Answer:
Explanation:El ejercicio vigoroso previene en mayor medida el síndrome metabólico (un conjunto de enfermedades que aumentan el riesgo cardiovascular )
mientras que una reacción vigorosa se produce entre el aluminio y el gas cloro. Como consecuencia de la gran cantidad de energía liberada se producen luz y calor
If a current of 2.5 Ampere flow through a circuit in 15 minutes calculate amount of charge through a crcuit
Answer:
Q = 2250 Coulombs
Explanation:
We are given;
Current: I = 2.5 A
Time: t = 15 minutes = 15 × 60 seconds = 900 s
Now formula for the amount of charge through the circuit is given by:
Q = It
Thus;
Q = 2.5 × 900
Q = 2250 Coulombs
The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat's average kinetic energy? (1 kJ = 1000 J)
Answer:
69.44kJ
Explanation:
Kinetic energy is expressed as;
KE = 1/2mv^2
m is the mass = 500kg
v is the velocity
Get the velocity;
v = displacement/time
velocity = 2000/120
velcoity = 16.7m/s
Gt the kinetic energy
KE = 1/2 * 500 * 16.7²
KE = 250*277.78
KE = 69,444.4Joules
Since 1000J = 1kJ
69,444.4Joules = 69,444.4/1000
69,444.4Joules = 69.44kJ
Hence the Secretariat's average kinetic energy is 69.44kJ
Answer:C 69.0kJ
Explanation:
Find the weight of a 4.2 kg backpack,
A) 41.16 N
B) 0.42 kg
C) 41.16 kg
D) 0.42 N
Answer:
Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.
If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.
If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.
A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work to stop the car. Which of the following was the car's velocity when the brakes were initially applied?
Answer:
10m/s
Explanation:
What is a gravitational field, and how does it apply to Earth? what is its formula. and what is an example of how you can use it?
Answer:
Explanation:
a gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.
The formula is: weight/mass = gravitational field strength. On Earth the gravitational field strength is 10 N/kg.
an example of how you can use it if you need to find the gravitational force from earth.
I really need help on this I don’t understand it
1: 15m
2: 56m/s
3: 34.5m
Sorry if these are incorrect.
If constants aren't given in an experiment, what can be constant in the experiment?
Answer:
Anything in an experiment that remains unchanged.
Explanation:
An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.
How long does it take the lava bomb to reach its maximum height? Answer with three significant digits and the correct unit. A small volcano's steam pressure belches vertically upward a lava bomb from an initial height of 64.4 m and with an initial upward velocity of 31.4 m/s. Remember gravity's acceleration near earth is g = 9.8 m/s2 down.
Answer:
The time taken to reach the maximum height is 3.20 seconds
Explanation:
The given parameters are;
The initial height from which the volcano erupts the lava bomb = 64.4 m
The initial upward velocity of the lava bomb = 31.4 m/s
The acceleration due to gravity, g = 9.8 m/s²
The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;
v = u - g·t
Where;
v = The final velocity = 0 m/s at maximum height
u = The initial velocity = 31.4 m/s
g = The acceleration due to gravity = 9.8 m/s²
t = The time taken to reach the maximum height
Substituting the values gives;
0 = 31.4 - 9.8 × t
∴ 31.4 = 9.8 × t
t = 31.4/9.8 ≈ 3.204
The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds
Which term best matches the description of an earthquake?
Where all mass movements occur
Acts as a lubricant to reduce friction between soil grains
Determines how much material is available for mass movement
Occurs when a sheet of rock moves downhill on a sliding surface
Can trigger a sudden mass movement
A force that works to pull material downslope
can tigger sudden mass movement
What is a joule? Pls only answer if you know the answer.
Answer:
the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.
Explanation:
Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.
1. The lamp in your room is marked (100
W, 220 V). What do these readings mean?
Calculate, in J and in kWh, the electric ener-
gy consumed for 5 hours of lighting. Deduce
the monthly cost if the price of one kWh is
55 L.L.
Answer:
See the answers below
Explanation:
The data of 100W means power, and the other data of 220V means voltage, that is to say that bulb serves to work at a voltage of 220V100W datum means power.
J means work that is given in Joules [J], we must remember that power is defined as the relationship between work at a certain time, therefore we can determine work by means of the following expression.
[tex]P=W/t\\[/tex]
where:
P = power [Watt]
W = work [J]
t = time [s]
[tex]W=P*t\\W=100*5[hr]*[\frac{3600s}{1hr} ]\\W=1800000[J] = 1.8[MJ][/tex]
Now the electric cost.
[tex]0.1[kW]*5[hr]*55\frac{LL}{1kwhr} =27.5[LL][/tex]
Which of the four spheres is this pictures/scene?
A) hydrosphere
B) biosphere
C) geosphere
D) atmosphere
I believe the correct answer is atmosphere (D).
Answer:
D) atmosphere
Explanation:
but the correct answer is troposhare
A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog
Answer:
25J
Explanation:
Given parameters:
Mass of the dog = 10kg
Speed of the dog = 5m/s
Unknown:
The minimum energy required to stop the dog = ?
Solution:
The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.
To find the kinetic energy;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass
v is the velocity
Now insert the parameters and solve;
K.E = [tex]\frac{1}{2}[/tex] x 10 x 5 = 25J
how high above the ground is a 3 kg object that has 147 J (joules) of potential energy
Answer:
4.9949
Explanation:
M = 3 kg
P.E = 147 joules
G = 9.81 ms^-2
H = ?
P.E = MGH
147 = 3 x 9.81 x H
147 = 29.43H
147/29.43 = 29.43H/29.43
4.9949 = H
:. H = 4.9949
A hunter shoots a tranquilizer dart straight at a monkey who is
hanging on a tree branch that is 1.5 meters high. The tree is 16 meters
away from the hunter. The man shot the dart at the monkey with an
initial sideways velocity of 40 m/s, and at the same time, the monkey
let go of the branch. what time will the monkey reach the same height
of the arrow?
t= _S
Answer:
The donkey might be dead
A sea turtle must crawl up a beach to lay eggs. Ignoring friction, what work must a 140-kg turtle do in lifting herself 2.5 m above the level of the sea?
Answer:
3500joules of work
Explanation:
Work done = Force×,distance
Given
Focrce= mass ,× acceleration = 140×10 = 1400N
Distance moved = 2.5m
Workdone = 1400×2.5
Work done = 140×25
Workdone = 3500Joules
On an air track, a 4-kg cart moving at 3 m/s collides with a 2-kg cart that is
initially at rest. If the two carts stick together, what will be their velocity
after the collision? Show all calculations, including any equation(s) used,
and include correct measurement units. *
Your answer
Answer:
v₃ = 2 [m/s]
Explanation:
To solve such problems we must use the principle of conservation of momentum. That is, the linear momentum is conserved before and after the collision.
P = m*v
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
The momentum is conserved before and after the collision, in this way we can obtain the following equation.
[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]
where:
m₁ = mass of the cart moving = 4 [kg]
v₁ = velocity of the cart moving before the collision = 3 [m/s]
m₂ = mass of the cart initially at rest = 2 [kg]
v₂ = velocity of the cart at rest = 0
v₃ = velocity of the two carts combined (carts stick together) after the collision [m/s]
[tex](4*3)+(2*0)=(4+2)*v_{3}\\v_{3}=12/6\\v_{3}=2[m/s][/tex]
A man pushes a crate along a factory floor by exerting a force of 55 N. If
the crate moves a distance of 4.0 m, how much work does the man
perform?
Answer:
it's 220 J
the second one
A child's first bicycle has 12-inch tires. These tires have a 6-inch radius. How fa r does the bicycle move forward each time the wheel makes one complete rotation? Give your answer in meters. (1 inch = 0.022 meters) b. A woman's ten-speed bicycle has 27-inch tires (13.5-inch radius). How far does this bicycle …
Answer:
a. s = 0.96 m
b. s = 2.15 m
Explanation:
a.
The relationship between the linear displacement and the angular displacement is given as follows:
[tex]s = r\theta[/tex]
where,
s = linear distance covered = ?
r = radius of wheel = (6 in)(0.0254 m/1 in) = 0.1524 m
θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad
Therefore,
[tex]s = (0.1524\ m) 2\pi[/tex]
s = 0.96 m
b.
Assuming, we have to find linear displacement here, as well:
[tex]s = r\theta[/tex]
where,
s = linear distance covered = ?
r = radius of wheel = (13.5 in)(0.0254 m/1 in) = 0.3429 m
θ = angular displacement = (1 rev)(2π rad/1 rev) = 2π rad
Therefore,
[tex]s = (0.3429 \ m) 2\pi[/tex]
s = 2.15 m
what are the uses of X-rays.
Explanation:
id : 237 514 2470
pass : frmCV5
Join in zoom!❤
I am boy :)
The dead sea has a very high salt content. Explain why it is easier for a swimmer to float in the dead sea than in a swimming pool containing fresh water
Answer:
Dead sea is full of salt.
Explanation:
The water of the Dead Sea is full of salt, which makes it much denser and heavier than freshwater. If you swim in it, you float very easily.
When salt is dissolved in water, for example sea water, dissolved salt adds to the mass of the water and makes the water denser than it would be without salt. Because objects float better on a dense surface, they float better on salt water than fresh water.
What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s
Answer:
0.5625 Joules
Explanation:
The equation to calculate kinetic energy is:
[tex]KE = \frac{1}{2}mv^2[/tex]
So, plug in all given info and calculate:
[tex]KE = \frac{1}{2}(0.5)(1.5)^2 = 0.5625J[/tex]
And that's your answer! :)
A long-jumper leaves the ground at an angle of 20.0° above the horizontal and at a speed of 11.0 m/s.How far does he jump in the horizontal direction?(Assume his motion is equivalent to that of a particle.).
a. 12m
b. 7.94m
c. 10m
d. 0.384m
Answer:
The correct option is;
b. 7.94 m
Explanation:
The given parameters of the jump of the long jumper are;
The angle above the horizontal with which the long jumper leaves the ground, θ = 20.0°
The speed with which the long jumper leaves the ground, u = 11.0 m/s
The furthest horizontal distance the long jumper jumps, given that the motion is equivalent to that of a particle, is given by the formula for the range, R, of a projectile motion as follows;
[tex]R = \dfrac{u^2 \times sin \left (2 \cdot \theta \right )}{g}[/tex]
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
u = The initial velocity of the long-jumper = 11.0 m/s
θ = The angle of the direction above the horizontal the long-jumper jumps = 20.0°
Plugging in the values, gives;
[tex]R = \dfrac{(11.0 \ m/s)^2 \times sin \left (2 \times 20.0 ^{\circ} \right )}{9.8} = \dfrac{121 \ m^2/s^2 \times sin \left (40.0 ^{\circ} \right )}{9.8 \ m/s^2} \approx 7.94 \ m[/tex]
How far the long-jumper goes = The range, R, of the projectile motion ≈ 7.94 m.
what do you notice about gravity in space?
Answer:
gravity is everywhere in space and objects in space are always falling: towards the earth, towards the sun, and towards the galactic center
Explanation:
1. Why do we need to travel?
Answer:
We're like children who move away from their parents - then back,
HUMANS LOVE to travel. Mentally or physically, they escape to other places. They crave adventure. They seek the unknown. They want to see new places, learn new things, enjoy new experiences and then return home to the familiar, the predictable, the secure, before taking off again on their travels.
This departure-return behaviour has its origins, perhaps, in the early exploratory behaviour of the child. Research has shown that children who are "securely attached" to their parents, sure of their affection and protection, and who know that their parents will respond to their needs, are more independent, adventurous and exploratory in their play and behaviour.
Observations of infants show that from the safe base of having a parent present and available, the infant dares to move away a short distance and then return to the parent, to move a little further and return, until in incremental and amazingly measurable distances it explores the environment that surrounds it and has the courage to move beyond it.
This may be the first symbolic travel: the first departure, the first expedition and the possible beginning of the travel bug for those for whom their initial independent voyaging was successful.
With these first independent steps away from the parental presence lies the atavistic or recurring wish to reach out beyond the current confines of space and relationship
and see what is further away. And yet further again to see what is not visible, what is around the next corner, in the next room and eventually on
the other side of our geographical or psychological world. This is a human need. It is why we have uncovered our world, travelled its length, hiked to the top of its mountains and the depth of its oceans. It is why we became discontent with exploring our own plant but had to move beyond it into the unknown. It is why, as poet TS Eliot reminds us, we will "not cease from exploration".
It is our nature to travel. It is our joy to travel. It is our paradoxical psychological disposition to wish for the contradictory conditions of stability and change: to stay and to go, to be and to explore, to rest and to travel unceasingly.
Travel is more than going somewhere. It is a psychological event. It requires motivation and imagination. It begins in childhood with faltering first steps and with imagination fired by the tales of "long, long ago in a faraway land".
We emerge from these fantasies of childhood determined to cross the oceans, to find those faraway lands, the characters they containand the magic they hold. Determined to find the adventures they promise and the prospect of returning home triumphant with trophies having vanquished all fear, overcome all obstacles and live happily eve after.
Answer:
to see the world and experience new things. it opens your mind and you can meet more people. you have a new view on the world after seeing it from other places, not only new views on the world but new cultures, and languages.
Explanation:
A object with a mass of 1.5 kg is lifted from the ground to a height of 0.22 m what is the objects potential energy
Answer:
3.3 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 1.5 × 10 × 0.22
We have the final answer as
3.3 JHope this helps you
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Answer:
[tex]a=2.4\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]
So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].
HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
How are ribosomes different from other complex animal cell organelles?
Explanation:
Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing
If the magnitude of a vector is√8 .If it's x-component is 2 ,then it's y- component is
Answer:
The answer is below
Explanation:
A vector quantity is a quantity that has both magnitude and direction. The magnitude of a vector is the length of that vector.
The magnitude of a vector a with a x component of x and y component of y is given by the formula:
[tex]|a|=\sqrt{x^2+y^2}[/tex]
Given that the vector has a magnitude of √8, the x component is 2 and the y component = y. Hence:
[tex]\sqrt{8}=\sqrt{2^2+y^2}\\\\squaring\ both\ sides:\\\\8=4 + y^2\\\\y^2=8-4\\\\y^2=4\\\\square\ root\ of\ both\ sides:\\\\y=\sqrt{4} \\\\y=\pm 2\\\\y=+2\ or\ y=-2[/tex]
Two waves arrive at the same place at the same time exactly in step with each other. Each wave has an amplitude of 2.5 m. The resulting wave has an amplitude of
Answer:
5m
Explanation:
Whenever Two or more than two waves get to the same point/place, and they arrive at the same time, then there will be "superimposition" onto one another. Then there would be corresponding of each disturbance to a Amplitude or force, and since these disturbance maintain same line, "THEN THE RESULTING WAVE WILL BE THE ADDITION OF THE AMPLITUDE"
Superposition can be explained as the action that takes place as a result of two waves occupying same point.
To find the waves at this point, then " THE AMPLITUDE WILL BE ADDED TOGETHER"
Given:
Amplitude of first wave= 2.5m
Amplitude of second wave= 2.5m
The resulting wave will have an amplitude of(2.5m + 2.5m)=5.0m
Hence, The resulting wave has an amplitude of 5.0m