What is the difference between a metric and a norm?

Answers

Answer 1

Answer:

A norm and a metric are two different things.  .

Step-by-step explanation:

The norm is measuring the size of something, and the metric is measuring the distance between two things. A metric can be defined on any set . It is simply a function which assigns a distance (i.e. a non-negative real number) to any two elements .

Answer 2

The major difference between the matric and norms is that metric is a unit of measurement that measures the distance between two objects. The size of a single thing is measured by a norm.

What is measurement?

It is defined as the numerical quantity that gives an idea about an object's size, length, width, and many more. It can be used to compare two objects.

The major difference between metrics and norms is as follows:

A metric is a unit of measurement that measures the distance between two objects. The size of a single thing is measured by a norm.Metrics may be expressed on almost anything, however, a norm can only be defined on vector spaces but since the definition of a norm requires that the things measured by the norm be added and scaled.

Thus, the major difference between the matric and norms is that metric is a unit of measurement that measures the distance between two objects. The size of a single thing is measured by a norm.

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Related Questions

On Monday, Payton rode 7 miles on a bike. On Tuesday, she rode 23
miles. On Wednesday, she rode 3 times as much as she did Monday
and Tuesday combined. What equation could you use to find how
many miles Payton rode on Wednesday, r?

Answers

Answer:

483

Step-by-step explanation:

I really really pray and hope this helpss.

Answer:

X=3(7+23)

Step-by-step explanation:

what is 60 divided by 4?

Answers

Answer:

The answer is 15

Step-by-step explanation:

can someone explain how to do "interquartile range"

Answers

What is it?

The IQR describes the middle 50% of values when ordered from lowest to highest. To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

How do you find IQR?

Step 1: Put the numbers in order. ...

Step 2: Find the median. ...

Step 3: Place parentheses around the numbers above and below the median. Not necessary statistically, but it makes Q1 and Q3 easier to spot. ...

Step 4: Find Q1 and Q3. ...

Step 5: Subtract Q1 from Q3 to find the interquartile range.

Answer:

The answer to this quesion is a measure of statistical dispersion, the spread of data or observations, first you need to get the data find the median calculate the median from both lower and upper half of the data and the iqr is the diffrence between the lower and upper.

Step-by-step explanation:

I Hope This Helps You!

-Justin:)

Can I have help on this?


Answers

Answer:

25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

Answer: 25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

The half-life of sr-85, which may be used in bone scans, is 64. 8 days. How many milligrams of a 7 mg sample will be left after 127 days? round to the hundredths place

Answers

[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &7\\ t=\textit{elapsed time}\dotfill &127\\ h=\textit{half-life}\dotfill &64.8 \end{cases} \\\\\\ A=7\left( \frac{1}{2} \right)^{\frac{127}{64.8}}\implies A=7\left( \frac{1}{2} \right)^{\frac{635}{324}}\implies A\approx 1.80[/tex]

The half-life of sr-85, which may be used in bone scans, is 64.8 days. 1.80 milligrams of a 7 mg sample will be left after 127 days.

What is half-life?

Half-life is defined as the time required for a quantity to reduce to half of its initial value.

The half-life of sr-85, which may be used in bone scans, is 64. 8 days.

We need to find how many milligrams of a 7 mg sample will be left after 127 days.

[tex]\rm A = P\frac{1}{2} ^{t/h}[/tex]

here A = current amount

P = inital amount

t = time

h = half life

So,

[tex]\rm A = 7\frac{1}{2} ^{127/64.8}[/tex]

[tex]\rm A = 7\frac{1}{2} ^{635/324}\\A = 1.80[/tex]

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The numbers in the triangles below go together following the
4
9
8
7
3
2
6
Find the missing number.
A 1
B 3

Answers

Answer:

1

by looking only 1 is missing

What is the volume of the square pyramid?

Answers

Answer:

v = 118.333333333

Step-by-step explanation:

formula: V=a^2h/3

The area is the base edge (so 5)

The height is the line going up the triangle (14.2)

Fill in:

v = 5^2(14.2/3)

Solve:

exponent first: 5^2 = 25

v = 25 (14.2/3)

divide/find out fraction: 14.2/3 = 4.73333333333

v = 23 x 4.73333333333

multiply: 23 x 4.73333333333 = 118.333333333

v = 118.333333333

you can also write as v = 118.3 with a line like “-“ over 3 to show the 3 is repeating:)

15.22 and add the point at the end

pls help me thank you ​

Answers

answer: B) CAD

Explanation;
The red marked region is CAD

Which graph represents the function f(x) = - |x - 2| - 1?

Answers

Answer:

nsgs6

68÷9

02_3

73929

Step-by-step explanation:

8282×627=628373

Answer:

i hope this helps you!

Step-by-step explanation:

If the point (x,square root 3/2) is on the unit circle, what. is x?

Answers

Answer:

[tex]x=\pm\frac{1}{2}[/tex]

Step-by-step explanation:

On a unit circle, [tex](x,y)=(\cos\theta,\sin\theta)[/tex], so [tex]\sin\theta=\frac{\sqrt{3}}{2}[/tex] in this case. If you look at the attached circle, the only time that the y-coordinate is [tex]\frac{\sqrt{3}}{2}[/tex] is when [tex]x=-\frac{1}{2}[/tex] and [tex]x=\frac{1}{2}[/tex], which correspond to angles of [tex]\theta=\frac{2\pi}{3}[/tex] and [tex]\theta=\frac{\pi}{3}[/tex] respectively

A person places $81200 in an investment account earning an annual rate of 3. 6%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 13 years

Answers

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$81200\\ r=rate\to 3.6\%\to \frac{3.6}{100}\dotfill &0.036\\ t=years\dotfill &13 \end{cases} \\\\\\ A=81200e^{0.036\cdot 13}\implies A=81200e^{0.468}\implies A\approx 129659.95[/tex]

Please help!


Find the value of x. Round to the nearest tenth for numbers #19.


Find the value of x. Round to the nearest degree # 23 & #27.


-Answer the last question :)

LAST QUESTION: The lengths of the diagonals of a rhombus are 2in. and 5in. Find the measures of the angles of the rhombus to the nearest degree.

Answers

The values of x in the triangles and the angles in the rhombus are illustrations of tangent ratios

The values of x in the triangles are 21.4 units, 58 degrees and 66 degreesThe angles in the rhombus are 44 and 46 degrees, respectively

How to determine the values of x?

Triangle 1

The value of x is calculated using the following tangent ratio

tan(25) = 10/x

Make x the subject

x = 10/tan(25)

Evaluate

x = 21.4

Triangle 2

The value of x is calculated using the following tangent ratio

tan(x) = 8/5

Evaluate the quotient

tan(x) = 1.6

Take the arc tan of both sides

x = arctan(1.6)

Evaluate

x = 58

Triangle 3

The value of x is calculated using the following tangent ratio

tan(x) = 0.34/0.15

Evaluate the quotient

tan(x) = 2.27

Take the arc tan of both sides

x = arctan(2.27)

Evaluate

x = 66

How to calculate the angles of the rhombus?

The lengths of the diagonals are:

L1 = 2 in

L2 = 5 in

Represent the angles with x and y.

The measures of the angles are calculated using the following tangent ratios

tan(0.5x) = 2/5 and y = 90 - x

Evaluate the quotient

tan(0.5x) = 0.4

Take the arc tan of both sides

0.5x = arctan(0.4)

Evaluate

0.5x = 22

Divide by 0.5

x = 44

Recall that:

y = 90 - x

This gives

y = 90 - 44

Evaluate

y = 46

Hence, the angles in the rhombus are 44 and 46 degrees, respectively

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Answers

Answer:

d=8

e=11.31

Step-by-step explanation:

side8 and side(d) are the same length

8squared+8squared=128

[tex]\sqrt{128}[/tex]=11.31

hope this helps!

Answer:

d = 8 and e = 8√2   ( e = 11.31 do the nearest hundredth)

Step-by-step explanation:

This is a 45-45-90 triangle so the sides are in the ratio 1:1:√2

So d = 8

and

e = 8√2.

A university class has had 8 graduate students enroll so far, as well as 8 other students. Considering this data, how many of the next 12 students to enroll should you expect to be graduate students?

Answers

[tex]\bold{ANSWER:}[/tex]

6 Students

[tex]\bold{EXPLANATIONS:}[/tex]

3 kitchen assistants can prepare 10 kg of vegetables in 60 minutes. How long would it take 25 assistants to prepare the same amount?

Answers

Answer:

App. 83.33 kg

Step-by-step explanation:

10/60=0.167 kg/minute

0.167/3=0.056 kg/minute/person

0.056 x 25 x 60= 83.33...6

Describe how to find the sale price of an item that has been discounted 15%.

Answers

Answer:

Convert 15% to a regular number by moving the decimal 2 times to the left so 15.0 becomes 0.15 then do 0.15 × the original price, then take the original price and subtract the amount you got from doing 0.15 × the original price

The points 4,0 and 7,6 lie on a particular line, what is its equation in slope - intercept form?

Answers

[tex](\stackrel{x_1}{4}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{4}}}\implies \cfrac{6}{3}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{2}(x-\stackrel{x_1}{4})\implies y = 2x-8[/tex]

Will give Brainly Fivue starts and a tThanks

Answers

Answer:

y = x + 9

Step-by-step explanation:

Since each x input can be added by 9 to get the y outputs, the equation is y=x+9
Hope this helps :)

A rock is dropped from a height of 100 feet. Calculate the time between when the rock was dropped and when it landed. If we choose "down" as positive and ignore air friction, the
function is h(t) = 16t^2 – 100.

A)t = 2.5 seconds

B)t = 6.25 seconds

C)t = 10 seconds

D)t = 12.5

Answers

Answer:

A

Step-by-step explanation:

the rock lands when it reaches height 0.

so, for what t is h(t) = 0 ?

16t² - 100 = 0

16t² = 100

now we pull the square root on both sides (we can ignore the negative solutions, as negative seconds don't make any sense in our scenario)

4t = 10

t = 10/4 = 5/2 = 2.5 seconds

so, A is correct.

a locker requires a three-digit code to open the lock. the code must contain one letter and two numbers, and no letter or number can be repeated. you can choose from among four letters, a,b,c and d and two numbers, 5 and 6

Answers

Answer:

4 ways

Step-by-step explanation:

Given

Code consists of 3 digits1 letter and 2 numbersNo number/letter should be repeated

Possible combinations

a56b56c56d564 ways

Use the equation from the previous problem to predict the price of bzg stock on day 30.

Answers

Answer:

925.798

Step-by-step explanation:

1.65(x) x 18.703 = 925.798

What is the answer to this equation
3 1/2 - 27/8

Answers

Answer:

1/8

Change 27/8 into a mixed number 3 3/8

Answer: 1/8

Step-by-step explanation: I explain in the photo ! have a good day


13. What is the equation in standard form of the circle
represented by
x2 + y2 - 10x - 6y = 23?
A (x+5)2+(y + 3)2 = 23
B. (x + 5)2+(y + 3)2 = 57
C. (x-5)+(y - 3)2 = 23
D. (x - 5)2+(y - 3)2 = 57

Answers

The standard form of a circle shows the center and the radius

The equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

How to determine the equation?

The standard equation of a circle is:

(x - a)^2 + (y - b)^2 = r^2

Where:

Center= (a,b)

Radius = r

Assume that:

(a,b) = (-5,3)

r = [tex]\sqrt{[/tex]57

The equation of the circle would be:

(x + 5)^2 + (y - 4)^2 = ([tex]\sqrt{57[/tex])^2

Evaluate the exponent

(x + 5)^2 + (y - 4)^2 = 57

Hence, the equation of the circle in standard form is (x + 5)^2 + (y - 4)^2 = 57

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solve pls brainliest

Answers

Answer:

2/5 > 1/4

Step-by-step explanation:

First convert the denominators to the LCM which will be 20

2/5 will convert to 8/20 because 5 x 4 = 20 so 2 x 4 = 8 and 1/4 will convert to 5/20 because 4 x 5 = 20 so 1 x 5 = 5

Please Help! will Give Brainlest!

Answers

Answer:

tan ¤ = opp/adj

tan ¤ = 20/50

since opposite of the angle is 20, height of the tree is 20 feet.

Ans : D

Answer:

height : 20distance : 50

Explanation:

[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

[tex]\hookrightarrow \sf tan(x)= \dfrac{20}{50}[/tex]

using the equation, we can identify that ↓opposite ( the height of the tree ) is 20adjacent ( the distance ) is 50

Write the equation for the cosine function for the ferris wheel ride, with where h, is the height in meters, and t, is the time in minutes.

Answers

The cosine function for the ferris wheel ride is an illustration of a sinusoidial function

The equation of the Ferris wheel is y = -190cos(π / 120 t) + 195

How to determine the cosine function?

A cosine function is represented as:

y = Acos(Bt - C) + D

From the complete question, the diameter of the ferris wheel is 380 feet.

The amplitude represents the radius, and this is calculated as:

A = 380/2

A = 190

The function becomes:

y = 190cos(Bt - C) + D

The period of the function is:

T = 2π / B

From the complete question, one full rotation is completed in 4 minutes.

Convert the time to seconds

T = 4 * 60

T = 240.

So, we have:

240 = 2π / B

Divide both sides by 2

120 = π / B

Make B the subject

B = π / 120

The function becomes

y = 190cos(π / 120 t - C) + D

From the question, the ferris wheel is 195 feet above the ground.

This represents the vertical shift.

So, we have:

D = 195

The function becomes

y = 190cos(π / 120 t - C) + 195

Also, we have:

The lowest point is at t = 0 and the function is a negative cosine function

So, we have:

C = 0

The function becomes

y = -190cos(π / 120 t) + 195

Hence, the cosine function is y = -190cos(π / 120 t) + 195

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Which of the following statements is equivalent to P (z greater-than-or-equal-to 1. 7)? P (z greater-than-or-equal-to negative 1. 7) 1 minus P (z greater-than-or-equal-to negative 1. 7) P (z less-than-or-equal-to 1. 7) 1 minus P (z less-than-or-equal-to 1. 7).

Answers

This [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

It is given that the  [tex]\rm P(Z\geq 1.7)[/tex]

It is required to find which statement is equivalent to [tex]\rm P(Z\geq 1.7)[/tex]

The statements are:

[tex]a) \ \rm P(Z\geq -1.7)\\b) \ \rm 1-P(Z\geq -1.7)\\c) \ \rm P(Z\leq 1.7)\\d) \ \rm 1-P(Z\leq 1.7)[/tex]

What is a normal distribution?

It is defined as the continuous distribution probability curve which is most likely symmetric around the mean. At Z=0, the probability is 50-50% on the Z curve. It is also called a bell-shaped curve.

We have the [tex]\rm P(Z\geq 1.7)[/tex]

We know that:

[tex]\rm P(Z\leq a)=P(Z\geq -a)\\\rm P(Z\geq a)=P(Z\leq -a)[/tex]

If we compare statement (a) and statement (c), we will see these options are not equivalent to  [tex]\rm P(Z\geq 1.7)[/tex]

For statement (b) if we plot the graph for the given statement we will get the negative area of the bell curve hence it is also incorrect.

For statement (d) if we plot the graph for the given statement we will get the positive area which is equivalent to the [tex]\rm P(Z\geq 1.7)[/tex]

Thus, the [tex]\rm P(Z\geq 1.7)[/tex]  is equivalent to  [tex]\rm 1-P(Z\leq 1.7)[/tex]

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find the value of (0.81÷0.09)+(0.81÷9)

Answers

Answer:

9.09

Step-by-step explanation:

[tex]\frac{0.81}{0.09} + \frac{0.81}{9}[/tex]

= 9 + [tex]\frac{0.81}{9}[/tex]

= 9+ 0.09

= 9.09

I hope this helped!! If so please rate and mark brainliest <3!!

Fill in the table using this function rule.
-
y=6x-1
х
у
1
4
5
10
0

Answers

Answer:

Below

Step-by-step explanation:

According to a website, ebra

Solve for

N

by cross multiplying.

N

=

5

Tap to view steps...

Solve for s

Isolate the variable by dividing each side by factors that don't contain the variable.

s

=

8

r

5

t

Tap to view steps...

Solve for x

Isolate the variable by dividing each side by factors that don't contain the variable.

Inequality Form:

x

>

6

Interval Notation:

(

6

,

)

Tap to view steps...

Solve by Substitution

Move all terms that don't contain

x

to the right side and solve.

x

=

9

2

y

2

Tap to view steps...

3/31/2022 4:07 PM

How can I help you?

Tap to view tutorial...

Find the Function

Find the function by taking the integral of the derivative.

G

(

x

)

=

5

2

x

2

x

+

C

Tap to view steps...

How was this solution?

Tap to rate...

Find the Function

I am unable to solve this problem.

Tap for examples...

Tired of typing? Download the app to take a picture of your problems!

Find the Function Rule

The chosen topic is not meant for use with this type of problem. Try the examples below.

x

q

(

x

)

1

1

2

2

3

3

4

4

x

q

(

x

)

1

3

2

6

3

11

4

18

x

q

(

x

)

1

2

9

162

2

8

8

128

3

18

If VZ=p–7 and WY=p–21, what is the value of p?

Answers

Using the midline property;

[tex]2wy = vz[/tex]

[tex]2(p - 21) = p - 7[/tex]

[tex]2p - 42 = p - 7[/tex]

[tex]2p - p = - 7 + 42[/tex]

[tex]p = 35[/tex]

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