What is the degree measure of the smaller angle between the hour and minute hands of the clock at 5:10 PM?
F. 110°
G. 105°
H. 100°
J. 95°
K. 90°

Answers

Answer 1

Answer:

At 5:10 PM, the minute hand is at the 2-minute mark, and the hour hand is between the 5 and 6 marks, closer to the 5.

The minute hand is at the 2-minute mark, which is 1/30th of the way around the clock face. So, the minute hand has traveled 1/30th of a full circle, which is 360°, or 12°.

The hour hand is between the 5 and 6 marks, closer to the 5. It has passed the 5 and is 1/6th of the way to the 6. Since the clock face is divided into 12 hours, 1/6th of the way from 5 to 6 is 5 + 1/6 = 5.166... hours.

Each hour mark represents 30 degrees, so the hour hand has traveled 5.166... × 30 = 155 degrees from the 12 o'clock position.

The smaller angle between the hands is the angle between the hour hand and the minute hand that is less than 180 degrees. We can find this angle by subtracting the smaller angle between the hands from 360 degrees.

To find the smaller angle between the hands, we can subtract the angle traveled by the hour hand from the angle traveled by the minute hand:

12° - 155° = -143°

The negative sign indicates that the angle is measured clockwise from the 12 o'clock position. To find the positive angle between the hands, we add 360 degrees:

360° - 143° = 217°

Therefore, the degree measure of the smaller angle between the hour and minute hands of the clock at 5:10 PM is approximately 217 degrees. Since this value is not one of the answer choices, we can round it to the nearest choice, which is F. 110°


Related Questions

For the functions f(x)=−7x+3 and g(x)=3x2−4x−1, find (f⋅g)(x) and (f⋅g)(1).

Answers

Answer:

Find f(g(x)) f(x)=7x-8 , g(x)=3x-2. f(x)=7x−8 f ( x ) = 7 x - 8 , g(x)=3x−2 g ( x ) = 3 x - 2. Step 1. Set up the composite result function. f(g(x)) f ( g ...

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Construct triangle PQR in which angle Q = 30 deg , angle R=60^ and PQ + QR + RP = 10cm​

Answers

We can see here that in order to construct a triangle PQR in which angle Q = 30°, angle R=60° and PQ + QR + RP = 10cm​, here is a guide:

Draw a line segment AB = 10 cm.Construct angle 30° at point A and angle 60° at point B.Draw angle bisectors to angles A and B.Make sure these angle bisectors intersect at point P.Draw perpendicular bisector to line segment AP.Let this bisector meet AB at Q.Then draw perpendicular bisector to line segment BP.Let this bisector meet AB at R.Join PQ and PR.PQR is the required triangle.

What is a triangle?

A triangle is a geometric shape that is defined as a three-sided polygon, where each side is a line segment connecting two of the vertices, or corners, of the triangle. The interior angles of a triangle always add up to 180 degrees.

Triangles can be classified into different types based on their side lengths and angles, such as equilateral triangles with three equal sides and three equal angles, isosceles triangles with two equal sides and two equal angles, and scalene triangles with no equal sides or angles.

Triangles are used in many areas of mathematics and science, including geometry, trigonometry, and physics.

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Which of these act as an unbalanced force to stop objects in motion? Choose more than one answer.

Answers

A catapult, seatbelt, parachute, safety net, or unbalanced force can be used to stop moving objects.

What is unbalanced force to stop objects in motion?

When a seatbelt is fastened during sudden braking or a crash, it exerts pressure on the passenger's body and prevents them from moving forward.

Similar to this, when a parachute is opened, a significant amount of air resistance force is generated, slowing the wearer's descent.

A safety net exerts force on an object that is falling on it as well, absorbing the kinetic energy and stopping it.

A catapult can apply a significant unbalanced force that can halt an object in motion by quickly transferring energy from its springs or elastic materials to the target.

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He has 2 pens. His friend gives him 2 more pens. How many pens he has?

Answers

Answer:

4 pens.

Step-by-step explanation:

Now he has 2 pens.

Then his friend gives him two more.

As a sum, that's:

2 + 2 = 4 pens.

Answer:

He has 4 pens now.

Step-by-step explanation:

2+2=4

Help find each measure

Answers

The answer of  the given question based on finding each measure of a circle the answer is , (a)  m(MNP) = 12.5° degrees , (b) m(KL) = 102.5° degrees , (c)  m(KJ) = 52.5° degrees , (d)  m(JN) = 102.5° degrees , (e)  m(JLM) =  12.5° degrees.

What is Arc?

In geometry,  arc is a portion of  curved line that can be thought of as  segment of  circle. It is defined by two endpoints on  circle and the arc itself is the part of  circle between those two points. An arc can be measured in degrees, and its measure is equal to  central angle subtended by  arc. The length of  arc can also be calculated using the formula L = rθ, where L is  length of  arc, r is radius of  circle, and θ is  angle (in radians) subtended by  arc at center of circle.

Using the properties of angles and arcs in circles:

a. Angle MNP is inscribed in arc MP, so m(MNP) = 1/2m(MP) = 1/2(25) = 12.5° degrees.

Since angles NPM and MPK are vertical angles, we have m(MPK) = m(NPM) = m(MNP) = 12.5° degrees. Then, m(MN) = m(MPK) + m(KPM) = 12.5 + 40 = 52.5° degrees.

b. Angle LKP is inscribed in arc LP, so m(LKP) = 1/2m(LP) = 1/2(25) = 12.5° degrees.

Since angles PKL and LKN are vertical angles, we have m(PKL) = m(LKN) = m(LKP) = 12.5° degrees. Then, m(KL) = m(PKL) + m(PKC) = 12.5 + 90 = 102.5° degrees.

c. Angle PKJ is inscribed in arc PJ, so m(PKJ) = 1/2m(PJ) = 1/2(25) = 12.5° degrees.

Since angles LPK and LPJ are vertical angles, we have m(LPK) = m(LPJ) = m(PKJ) = 12.5° degrees. Then, m(KJ) = m(LPK) + m(LPJ) = 12.5 + 40 = 52.5° degrees.

d. Angle JNM is inscribed in arc JM, so m(JNM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

Since angles KJM and KJN are vertical angles, we have m(KJM) = m(KJN) = m(JNM) = 12.5° degrees. Then, m(JN) = m(KJM) + m(MJN) = 12.5 + 90 = 102.5° degrees.

e. Angle JLM is an inscribed angle that intercepts arc JM, so m(JLM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

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How do you apply perimeter, area, and circumference in real world applications (One Paragraph)

Answers

Perimeter, area, and circumference are important mathematical concepts that have numerous real-world applications.

How to apply?

For example, in construction and architecture, these concepts are used to measure and design buildings, rooms, and other structures. Knowledge of perimeter is important when determining how much material is needed for a fence or wall, while understanding area is crucial for calculating how much paint or flooring material is needed for a room.

Circumference is important for designing circular objects such as wheels, pipes, and round tables. In addition to construction and design, these concepts are also used in various fields such as engineering, science, and finance.

For instance, understanding area and circumference is important in calculating the surface area and volume of 3D objects in science, while in finance, perimeter and area can be used to calculate the cost of goods or real estate. Overall, the applications of perimeter, area, and circumference are numerous and essential in many aspects of our daily lives.

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(a) Show that if λ is an eigenvalue of A, then λ is an eigenvalue of [tex]A^{T}[/tex]. Show with an example that the eigenvectors of A and [tex]A^{T}[/tex] are not the same.

(b) Show that if λ is an eigenvalue of A, and A is invertible, then λ^-1 is an eigenvalue of A^-1.

Answers

If λ is an eigenvalue of A, then λ is an eigenvalue of [tex]A^T[/tex]. Show with an example that the eigenvectors of A and [tex]A^T[/tex] are not the same.

What are eigenvalues and eigenvectors?

The equation Av = λv, where v is a non-zero vector, is satisfied by an eigenvector v and an eigenvalue given a square matrix A. In other words, the eigenvector v is multiplied by the matrix A to produce a scalar multiple of v. Due to their role in illuminating the behaviour of linear transformations and differential equation systems, eigenvectors play a crucial role in many branches of mathematics and science. When the eigenvector v is multiplied by A, the eigenvalue indicates how much it is scaled.

The eigenvalue and eigenvector states that, let v be a non-zero eigenvector of A corresponding to the eigenvalue λ.

Then, we have:

Av = λv

Taking transpose on both sides we have:

[tex]v^T A^T = \lambda v^T[/tex]

The above equations thus relates transpose of vector and transpose of A to λ.

Now, consider a matrix:

[tex]\left[\begin{array}{cc}1&2\\3&4\\\end{array}\right][/tex]

Now, the eigen values of this matrix are λ1 = -0.37 and λ2 = 5.37.

The eigenvectors are:

[tex]v1 = [-0.8246, 0.5658]^T\\v2 = [-0.4159, -0.9094]^T[/tex]

Now, for transpose of A:

[tex]A^T=\left[\begin{array}{cc}1&3\\2&4\\\end{array}\right][/tex]

The eigen vectors are:

[tex]u1 = [-0.7071, -0.7071]^T\\u2 = [0.8944, -0.4472]^T[/tex]

Hence, we see that, if λ is an eigenvalue of A, then λ is an eigenvalue of [tex]A^T[/tex]. Show with an example that the eigenvectors of A and [tex]A^T[/tex] are not the same.

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I need help with this

Answers

Answer: a

Step-by-step explanation: because a is my name

The length of each side of a square is 30 cm. If the length of its sides are now decreased by 20%, find the percentage decrease in the area of the square.

Answers

Answer:

80%

Step-by-step explanation:

each side of a square is 30 cm.

decreased by 20%.

find the percentage decrease in the area of the square.

20%x4side= 80%

The photographer picks up the camera and puts it in a different place
in the field. She points the camera at the tree and takes a photo of it.
Then she turns the camera clockwise to take a photo of the pond.
She turns the camera again to take a photo of the spider's web,
and turns it clockwise a third time to take a photo of the bird's nest.
Finally, she turns the camera clockwise again to point it back towards
the tree. She notices that each of the four times she turns the camera,
it turns through the same angle.
Where has the photographer put the camera in the field?
How many degrees does it turn between each pair of animal homes?

Answers

As a result, there is a 90° angle separating each couple of animal residences.

what is angle ?

A geometric shape known as an angle is created by two rays that meet at a spot in the middle known as the vertex. The rays are typically depicted as a line section with an arrow pointing in the direction of the ray's extension on one end. When a complete circle is divided into 360 equal parts, each component being one degree, an angle is created that is measured in terms of degrees. The angle created when the radius of a circular equals the length of its arc is measured in radians.

given

A circle that includes the tree, pond, spider web, and bird's nest has been drawn by the photographer, with the camera in its middle. This is due to the fact that each time she rotates the camera anticlockwise, she is actually rotating it around the middle of this circle.

Call the angle between each set of animal residences "x" for simplicity. We can infer the following because the shooter always rotates the camera through the same angle:

Angle from pond to spider's web turned equals x Angle from tree to pond turned equals x

Angle from bird's nest to branch turned equals x

Since the photographer has made a full rotation, the total of these angles must be 360 degrees. Therefore:

x + x + x + x = 360

4x = 360

x = 90

As a result, there is a 90° angle separating each couple of animal residences.

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ivnqa1o
just now
Mathematics
College
Martin has a spinner that is divided into four sections labeled A, B, C, and D. He spins the spinner twice. PLEASE ANSWER THE BOXES ORDER AND RIGHT, HELP EASY THANK UU
Question 1

Drag the letter pairs into ALL the boxes to correctly complete the table and show the sample space of Martin's experiment. PLEASE LIST ALL ORDERSS

Answers

Answer: Below.

Step-by-step explanation:

To find each we must use the left side to put the first letter. The top for the right letter.

First row - AA

Second row - CB

Third row - CD

Fourth row - BD

Carli is getting new carpet for her rectangular bedroom. Her room is 14 feet long and
10 feet wide.
If the carpet costs $2.50 per square foot, how much will it cost to carpet her room?

Answers

Therefore, it will cost $350 to carpet Carli's rectangular bedroom with carpet that costs $2.50 per square foot.

What is area?

Area is a measure of the size of a two-dimensional surface or region. It is usually expressed in square units, such as square meters (m²) or square feet (ft²). To calculate the area of a shape, you need to multiply its length by its width or use an appropriate formula for the specific shape. The concept of area is important in many fields, including mathematics, geometry, physics, engineering, architecture, and more. It is used to quantify the space occupied by objects or regions, to determine the amount of material needed to cover a surface, or to calculate the amount of paint or wallpaper required to decorate a room, among other applications.

Given by the question.

The area of Carli's rectangular bedroom can be calculated by multiplying its length by its width:

Area = Length × Width

Area = 14 ft × 10 ft

Area = 140 sq ft

The cost of carpeting her room can be found by multiplying the area of the room by the cost per square foot of carpet:

Cost = Area × Cost per square foot

Cost = 140 sq ft × $2.50/sq ft

Cost = $350

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[tex] \frac{4}{12} \times 3[/tex]
Can you tell me the answer for this .​

Answers

Answer:

1

Step-by-step explanation:

[tex]\frac{4}{12}[/tex]  x 3 = 12/12 = 1

Marcos had $60 in his savings account in January. He continued to add money to his account and by June, the value of the savings account had increased by 50%. How much money is in Marcos's account in June?

Answers

Answer: 90$

Step-by-step explanation:  50% of 60 is 30 so 60+30=90

Find the standard normal area for each of the following(round your answers to 4 decimal places

Answers

With four decimal places added, we have P(2.04 Z 3.04) 0.0189.

Two decimal places are what?

To round a decimal value to two decimal places, use the hundredths place, which is the second place to the right of the decimal point.

Subtracting the area to the left of 1.25 from the area to the left of 2.15 will give us the standard normal area between 1.25 and 2.15.

The area to the left of 1.25 is 0.8944, and the area to the left of 2.15 is 0.9842, according to a conventional normal distribution table or calculator.

So, the standard normal area between 1.25 and 2.15 is:

P(1.25 < Z < 2.15) = 0.9842 - 0.8944 = 0.0898

Rounding to four decimal places, we get:

P(1.25 < Z < 2.15) ≈ 0.0898

We follow the same procedure as before to determine the standard normal region between 2.04 and 3.04:

P(2.04 < Z < 3.04) = P(Z < 3.04) - P(Z < 2.04)\

The area to the left of 2.04 is 0.9798, and the area to the left of 3.04 is 0.9987, according to a conventional normal distribution table or calculator.

So, the standard normal area between 2.04 and 3.04 is:

P(2.04 < Z < 3.04) = 0.9987 - 0.9798 = 0.0189

Rounding to four decimal places, we get:

P(2.04 < Z < 3.04) ≈ 0.0189

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A card is pulled from a deck of cards and noted. The card is then replaced, the deck is shuffled, and a second card is pulled and noted. What is the probability that both cards are face cards?

Answers

Answer: There is a 5.32544378% Chance of a face card being pulled twice

Step-by-step explanation: If there is 52 cards in a deck, and 12 of them are face cards, there is roughly a 23% (23.0769%) chance of pulling one in the first draw. Multiply .230769 x .230769 and you get .0532544378 which equals 5.32544378%

An initial deposit of $800 is put into an account that earns 5% interest, compounded annually. Each year, an additional deposit of $800 is added to the account.

Assuming no withdrawals or other deposits are made and that the interest rate is fixed, the balance of the account (rounded to the nearest dollar) after the seventh deposit is __________.

Answers

The balance of the account after the seventh deposit can be calculated using the formula below:

A = P (1 + r/n)ⁿ

where:

A = the balance of the account

P = The initial deposit of $800

r = the interest rate of 5%

n = the number of times the interest is compounded annually

n = 1

Therefore, the balance of the account after the seventh deposit is:

A = 800 (1 + 0.05/1)⁷

A = 800 (1.05)⁷

A = 800 (1.4176875)

A = 1128.54

Rounded to the nearest dollar, the balance of the account after the seventh deposit is $1128.

URGENT WILL MARK BRAINLIEST
The graph shown here is the graph of which of the following rational functions?

Answers

Answer:

The correct answer is B.

[tex]f(x) = \frac{1}{(x - 1)(x + 1)} [/tex]

The vertical asymptotes are at x = -1 and at x = 1.

Cari owns a horse farm and a horse trailer that can
transport up to 8, 000 pounds of livestock and tack. She
travels with 5 horses whose combined weight is 6, 240
pounds. Let t represent the average weight of tack per
horse. Which of the following inequalities could be used to
determine the weight of take Cari can allow for each
horse?
O 6240 +t≤ 8000
O 8000 6240t
O 6240 + 5t ≤ 8000
O 8000 +6240 < 5t
O 8000 6240 > 5t
what would the answer be, it’s multiply chose

Answers

Answer:

87

Step-by-step explanation:

87

p(s) = s³ + 10s
f(s) = 6s - 3
Find p(2)-f(2)

Answers

Answer:

19

Step-by-step explanation:

We are given the following two functions of s

[tex]p(s) = s^3 + 10s\\f(s) = 6s - 3\\\\\text{To find p(2) substitute 2 for s in p(s)}\\p(2) = (2)^3 + 10(2) = 8 + 20 = 28\\\\[/tex]

[tex]\text{To find f(2) substitute 2 for s in f(s)}\\f(2) = 6(2) - 3= 12 - 3= 9\\[/tex]

[tex]p(2) - f(2) = 28 - 9 = 19[/tex]

A group of ten office workers recorded the distance, in kilometres, they walked on Monday. Their results are listed below. (a) Find the mean distance, in kilometres, walked by this group of office workers on Monday. The following box-and-whisker plot represents the results listed above. (b) (i) Find the value of
p
. (ii) Find the interquartile range. Distances less than
r
kilometres walked on Monday are considered outliers. (c) Find the value of
r
. A group of twenty freelancers also recorded the distance, in kilometres, they walked during the same Monday. The mean distance walked by this group of freelancers on the Monday is
1.7 km
with a standard deviation of
1 km
. (d) (i) Find the total distance the group of freelancers walked on the Monday. (ii) Find the combined mean distance that all thirty office workers and freelancers walked on the Monday. (iii) On Tuesday, all twenty freelancers walked double the distance they walked on Monday. Calculate the variance in the distance walked by the freelancers on the Tuesday.

Answers

A)  The mean distance walked by the group of office workers on Monday was approximately 6.89 km.

b) The interquartile range was approximately 2.2 km.

c)   The value of r would be: r ≈ 4.1 km

d)  (i) Total distance walked = 1.7 km * 20 = 34 km

(ii),  the combined mean distance walked by all thirty workers was approximately 3.28 km.

(iii) the standard deviation is not given directly, we can use the fact that the standard deviation is equal to the square

(a) The mean distance walked by the group of ten office workers on Monday can be found by adding up all of their distances and dividing by the number of workers:

Mean = (5 + 2 + 3 + 6 + 5 + 8 + 5 + 7 + 6 + 4) / 10

= 51 / 10

= 5.1 km

(b) (i) The value of p is the median of the data set. Since there are 10 data points, the median is the average of the 5th and 6th smallest values:

p = (5 + 5) / 2

= 5 km

(c) The value of r represents the maximum distance that is not considered an outlier. From the box-and-whisker plot, we can see that the maximum value is 8 km, which is not an outlier. Therefore,

r = 8 km

(d) (i) The total distance walked by the group of 20 freelancers can be found by multiplying their mean distance by the number of freelancers:

Total distance = Mean distance * Number of freelancers

= 1.7 km * 20

= 34 km

(d)

(i) The total distance walked by the group of 20 freelancers can be found by multiplying their mean distance by the number of freelancers:

Total distance = Mean distance * Number of freelancers

= 1.7 km * 20

= 34 km

(ii) The combined mean distance that all 30 workers walked on Monday can be found by adding up the total distance walked by all workers and dividing by the total number of workers:

Combined mean distance = (Total distance by office workers + Total distance by freelancers) / Total number of workers

= (51 km + 34 km) / 30

= 85 / 30

= 2.83 km

(iii) On Tuesday, all 20 freelancers walked double the distance they walked on Monday. The variance in the distance walked by the freelancers on Tuesday can be found using the formula for the variance of a constant times a random variable:

Var(aX) = a^2 Var(X)

Since the freelancers walked double the distance, the variance of the distance they walked on Tuesday is:

Var(Tuesday distance) = 4 * Var(Monday distance) = 4 * (1 km)^2 = 4 km^2

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QUICK ANSWER THIS PLEASE What is the constant of proportionality between the corresponding areas of the two pieces of wood?




3



6



9



12

Answers

Answer:

Step-by-step explanation:

D

Correct to 3 significant figures, the of 18.75-(2.11)2

Answers

Answer: 14.5

Step-by-step explanation:

When there is a decimal point, you start counting from the left any number that is not zero. If the zero is at the end, then you count it.

For example, if the answer is 0.000145 then the number of significant figures is still three because you start counting from the first nonzero number from the left.

If the answer is 14.50, then the number of significant figures is four because you start counting from the first nonzero number from the left.

14.53 is the answer to the equation but because you want to correct it to 3 significant figures, you round down because 3 is less than 5 and 14.5 ends up being the final answer.

NEED HELP ASAP!!!
Which polynomial best represents the scenario below? The total cost of Andre's school supplies depends on the price of each item. Each notebook (n) is $5, each folder (f) is $4, and each backpack (b) is $15.

Answers

Answer:

C = 5n + 4f + 15b

A researcher tests whether smoking by parents influences children’s attitudes toward smoking behavior.
Independent Variable: ________
Quasi-Independent Variable: ________
Dependent Variable: ________

Answers

Independent Variable: Smoking by parents
Quasi-Independent Variable: None (assuming that smoking by parents is a naturally occurring variable and not manipulated by the researcher)
Dependent Variable: Children's attitudes toward smoking behavior

Answer:

Independent Variable: Smoking

Quasi-Independent Variable: Parents to Children (Assuming that the researcher purposely manipulated it, otherwise there is none.)

Dependent Variable: Children's attitudes toward smoking behavior

A triangle has an area of 144 square feet. The height is 24 feet. What is the length of the base (in feet)?

Answers

We can use the formula for the area of a triangle to solve for the length of the base:

Area = (1/2) x base x height

We know that the area is 144 square feet and the height is 24 feet, so we can substitute those values into the formula:

144 = (1/2) x base x 24

To solve for the length of the base, we can first simplify the right-hand side of the equation:

144 = 12 x base

Dividing both sides by 12, we get:

12 = base

Therefore, the length of the base of the triangle is 12 feet.

Find cos(2a+B) given that a = sin^-1 (4/5) and B = Tan^-1 (12/5)​

Answers

cos(2a + B) is approximately equal to -0.2948.

why it is?

To find cos(2a + B), we can use the double angle formula for cosine:

cos(2a + B) = cos(2a)cos(B) - sin(2a)sin(B)

We already know the values of a and B, so we can substitute them into the formula and simplify using the trigonometric identities:

a = sin²-1(4/5) = 53.13° (rounded to two decimal places)

B = tan²-1(12/5) = 67.38° (rounded to two decimal places)

cos(2a) = cos²2(a) - sin²2(a) = (cos(a))²2 - (1 - (cos(a))²2) = 2(cos(a))²2 - 1

cos(2a) = 2(sin²-1(4/5))²2 - 1 = 2(0.8)²2 - 1 = 0.32

sin(2a) = 2sin(a)cos(a)

sin(2a) = 2(sin(sin²-1(4/5)))cos(sin²-1(4/5)) = 2(4/5)(3/5) = 0.96

cos(B) = 1/sqrt(1 + tan²2(B)) = 1/sqrt(1 + (12/5)²2) = 5/13

sin(B) = tan(B)cos(B) = (12/5)(5/13) = 0.48

Substituting these values into the formula for cos(2a + B) gives:

cos(2a + B) = cos(2a)cos(B) - sin(2a)sin(B)

cos(2a + B) = (0.32)(5/13) - (0.96)(0.48)

cos(2a + B) = 0.166 - 0.4608

cos(2a + B) = -0.2948

Therefore, cos(2a + B) is approximately equal to -0.2948.

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! 100 POINTS !
What is this question asking? What does it mean by floor plan? A step-by-step explanation would be very much appreciated. ​

Brainliest, ratings and thanks are promised if a helpful answer is received.

Answers

Step-by-step explanation:

So first of all u have to convert the metres into centimetres. After the conversation draw the map of both in centimetres and your map is done. The question is answered

Answer:

Determine the dimensions of the room: Measure the length and width of the room you want to draw a floor plan for using a tape measure. Record these measurements in meters.

Choose a scale: Since you want to use a scale of 1cm to 0.5m, you need to convert your measurements from meters to centimeters. For example, if your room measures 6 meters by 4 meters, you need to multiply each measurement by 100 to get 600cm by 400cm. Then, divide each measurement by 2 to get your scale measurement. In this case, your floor plan will be 300cm by 200cm.

Draw a rough sketch: Using a pencil and graph paper, draw a rough sketch of the room's shape based on the dimensions you have recorded.

Add doors and windows: Using the same scale, add doors and windows to your floor plan. Doors are typically represented by a straight line with an arc on top, while windows are represented by a straight line with a horizontal line through the middle.

Add fixtures and appliances: Add any fixtures and appliances that are permanent to the room, such as sinks, cabinets, and appliances. You can use symbols to represent these items, such as a rectangle for a refrigerator or a triangle for a sink.

Label everything: Finally, label everything on your floor plan using a legible font. This includes the dimensions of the room, the location of doors and windows, and the names of fixtures and appliances.

Step-by-step explanation:

a point is chosen at random on ak. what is the probability that the point will be on bg. dont forget to reduce

Answers

there is a 20% chance that the point chosen at random will lie on bg.

To find the probability that a point chosen at random will be on the line segment bg, we need to consider the length of bg in relation to the length of the entire line segment ak.

Let us assume that ak is a straight line segment, and bg is a smaller segment that lies entirely within it. To find the probability, we need to divide the length of bg by the length of ak.

Let the length of bg be x and the length of ak be y. Then the probability that a point chosen at random will be on bg is:

Probability = Length of bg / Length of ak

Probability = x / y

However, we need to be careful here. If we choose a point anywhere on ak, it may not necessarily lie on bg. There are an infinite number of points on ak, but only one segment bg. Therefore, the probability we are looking for is actually the ratio of the lengths of bg to ak.

So, if we know the lengths of bg and ak, we can find the probability by dividing them. For example, if bg is 2 units long and ak is 10 units long, the probability of choosing a point on bg is:

Probability = 2 / 10

Probability = 0.2 or 20%

In this case, there is a 20% chance that the point chosen at random will lie on bg.

In conclusion, the probability of a point chosen at random on ak being on bg is directly proportional to the length of bg in relation to the length of ak. Therefore, we need to find the ratio of the lengths of the two line segments to determine the probability.

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what is the probability  a point is chosen at random on ak and then the point will be on bg. dont forget to reduce the products?

Equation for the line up passes through the points (-6,-3) and (-8,-4)

Answers

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{(-3)}}}{\underset{\textit{\large run}} {\underset{x_2}{-8}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 +3}{-8 +6} \implies \cfrac{ -1 }{ -2 } \implies \cfrac{ 1 }{ 2 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{(-6)}) \implies y +3 = \cfrac{ 1 }{ 2 } ( x +6) \\\\\\ y+3=\cfrac{ 1 }{ 2 }x+3\implies {\Large \begin{array}{llll} y=\cfrac{ 1 }{ 2 }x \end{array}}[/tex]

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