Answer:
916.9C
Explanation:
Using Q= It
Q= 0.54A x 1698s
= 916.9C
The charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.
What is Electric Charge?Electric charge is defined as the physical property of matter that causes that matter to experience a force when placed in an electromagnetic field that may be positive or negative such that charges repel each other and unlike charges attract each other. An object with the absence of net charge is said to be neutral.
The SI unit of electric charge is the coulomb which is a derived SI unit and is represented by the symbol C.
Electric Charge is represented as
Q= It
where, Q= Electric charge
I= Electric current
t= time
Q= 0.54A x 1698s
= 916.9C
Thus, the charge delivered by a current with an average of 0.54 A over 28.3 minutes is 916.9C.
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A grating has 320 lines/mm. How many orders of the visible wavelength 551 nm can it produce in addition to the m = 0 order
Answer:
6
Explanation:
Given that
dsinθ = mλ,
now, if sinθ = 1, then
m = d / λ, where
m = order of interference
d = distance between the slits
λ = wavelength of light
this is the formula we would use to solve the question
d = 1 / 320 lines/mm
d = 1 / 320*10^3
d = 3.125*10^-6 m
At λ = 551 nm, we have
m = 3.125*10^-6 / 551*10^-9
m = 5.67
5.67 ~ 6
thus, we can say that the orders of visible wavelength 551 nm, can produce is 6
A round pipe of varying diameter carries petroleum from a wellhead to a refinery. At the wellhead, the pipe's diameter is 58.9 cm ( 0.589 m) and the flow speed of the petroleum is 12.1 m/s. At the refinery, the petroleum flows at 6.29 m/s. What is the volume flow rate of the petroleum along the pipe and what is the pipe's diameter at the refinery?
Answer:
Explanation:
The volume rate of flow = a x v where a is cross sectional area of pipe and v is velocity of flow
putting the values
π x .2945² x 12.1
= 3.3 m³ /s
To know the pipe's diameter at the refinery we shall apply the following formula
a₁ v₁ = a₂ v₂
a₁ v₁ and a₂ v₂ are volume rate of flow of liquid which will be constant .
3.3 = a₂ x 6.29
a₂ = .5246 m³
π x r² = .5246
r = .4087 m
= 40.87 cm
diameter
= 81.74 cm
Which statement about the ocean is true? A. No evaporation or precipitation in the water cycle occurs over the ocean. B. Most evaporation and precipitation in the water cycle occur over the ocean. C. All evaporation and precipitation in the water cycle occur over the ocean. D. Evaporation, but not precipitation, in the water cycle occurs over the ocean.
Answer:
A
Explanation:
Answer:
A
Explanation:
No evaporation or precipitation in the water cycle occurs over the ocean.
The mass of the crate can also be adjusted by clicking on the More Features tab and then using the slider bar in the right panel. How does the maximum angle for which the crate can remain at rest on the ramp depend on the mass of the crate
Answer:
The maximum angle does not depend on the mass
Explanation:
This is because In as much as the force acting on the normal which is the the maximum force of static friction increases as the mass increases, the component of the force of gravity parallel to the ramp increases at the same rate. Thus The maximum angle is independent of the mass.
The velocity of any point on a rigid body is _________ to the relative position vector extending from the IC to the point. Group of answer choices
Answer:
The velocity of any point on a rigid body is ___Always perpendicular______ to the relative position vector extending from the IC to the point
Explanation:
This is because The instantaneous center (IC) of zero velocity for the rigid body is at the point in contact with ground. The velocity direction at any point on the body is always perpendicular to the line connecting the point to the IC.
The velocity of any point on a rigid body is : Perpendicular to the relative position vector extending from the IC to the point.
The IC ( instantaneous center ) is the point of the rigid body in contact with the ground when the rigid body is at zero velocity.
The velocity direction from any point of the rigid body will always be perpendicular to the ( IC ) since the IC is the reference point of the rigid body when the body is at rest ( zero velocity ).
Hence we can conclude that the velocity of any point on a rigid body will be perpendicular.
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Although the options related to your question is missing an accurate answer is provided within the scope of your question
Simple Harmonic Motion: The quartz crystal in a digital watch has a frequency of 32.8 kHz. What is its period of oscillation
Answer:
Time Period of Oscillation = 3.04 x 10⁻⁵ s
Explanation:
The time period of oscillation and the the frequency of oscillation are two inter linked quantities. They are actually the reciprocals of each other. So, the time period of oscillation of quartz crystal is given by the following formula:
Time Period of Oscillation = 1/Frequency of Oscillation
where,
Frequency of Oscillation = 32.8 KHz
Frequency of Oscillation = 32800 Hz
Therefore,
Time Period of Oscillation = 1/32800 Hz
Time Period of Oscillation = 3.04 x 10⁻⁵ s
Which describes the amplitude of a wave when it carries more ene
O It is higher.
O It is lower.
It is darker.
Oli is lighter
Answer:
It is higher.
Explanation:
Hello,
In this case, the quantity of energy that a wave is able to transfer is directly related its amplitude exhibiting that the higher the carried energy, the higher its amplitude and on the flip side, the lower the energy the lower the amplitude, therefore, the answer is it is higher. You can verify this on the attached picture.
Regards.
Answer:
It is higher.
Explanation:
The pressure at the bottom of a full barrel of water is Poriginal . Determine what happens to the pressure when the radius or height of the barrel is changed and water is added to make the barrel full again.
Answer:
a) P' = P_original, b) P ’= P_original + ρ g Δh
Explanation:
The expression for nanometric pressure is
P = ρ g h
where ρ is the density of the liquid and h is the height
a) we change the radius of the barrel, but keeping the same height
as the pressure does not depend on the radius it remains the same
P' = P_original
b) We change the barrel height
h ’≠ h
we substitute in the equation
P ’= ρ g h’
h ’= h + Δh
P ’= ρ g (h + Δh)
P ’= (ρ g h) + ρ g Δh
P ’= P_original + ΔP
In this case, the pressure changes due to the new height,
*if it is higher than the initial one, the pressure increases
*if the height is less than the initial one, the pressure is less
You drive 6.00 km at 50.0 km/h and then another 6.00kmat 900 km/h Your average speed over
the 12.0 km drive will be
Explanation:
average speed = total distance travelled / total time travelled
time to travel the first 6km: 6 / 50 = 3/25 (h)
time to travel the next 6km: 6 / 90 = 1/15 (h)
[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]
The total time: 3/25 + 1/15 = 14/75 (h)
Average speed over the 12 km drive will be:
[tex] \frac{12}{ \frac{14}{75} } = \frac{450}{7} = 64.3 \: km{h}^{ - 1} [/tex]
A parachuter, falling with a constant speed, drops 456m in 14.4s.
Determine all unknowns.
S =
51
m/s
d =
456
m
t =
14.4
S
Answer:
The parachuter is falling at a speed of 31.667 meters per second.
Explanation:
Given that parachuter falls at constant speed and travelled distance and time are known, the unknown is speed, measured in meters per second, which is obtained by the following kinematic expression:
[tex]s = \frac{d}{t}[/tex]
Where:
[tex]d[/tex] - Travelled distance, measured in meters.
[tex]t[/tex] - Time, measured in seconds.
If [tex]d = 456\,m[/tex] and [tex]t = 14.4\,s[/tex], the speed of the parachuter is:
[tex]s = \frac{456\,m}{14.4\,s}[/tex]
[tex]s = 31.667\,\frac{m}{s}[/tex]
The parachuter is falling at a speed of 31.667 meters per second.
For a conductor in electrostatic equilibrium, which of the following properties are true?
a) Any excess charge is uniformly spread throughout the volume of the conductor.
b) The electric field inside is zero.
c) The entire conductor is at the same potential.
Answer:
b) The electric field inside is zero.
Explanation:
This is simply because the charges in the field will be in motion, thus this charges kind of spread around to make the conductor field zero.
The spaceship Intergalactic landed on the surface of the uninhabited Pink Planet, which orbits a rather average star in the distant Garbanzo Galaxy. A scouting party sets out to explore. The party's leader–a physicist, naturally–immediately makes a determination of the acceleration due to gravity on the Pink Planet's surface by means of a simple pendulum of length 1.44 m. She sets the pendulum swinging, and her collaborators carefully count 1.10×102 complete cycles of oscillation during 2.00×102 s. What is the result
Answer:
18808.7 m/s^2
Explanation:
Given
Length of the pendulum L = 1.44 m
Number of complete cycles of oscillation n = 1.10 x 10^2
total time of oscillation t = 2.00 x 10^2 s
The period of the T = n/t
T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s
The period of a pendulum is gotten as
T = [tex]2\pi \sqrt{\frac{L}{g} }[/tex]
where g is the acceleration due to gravity
substituting values, we have
0.55 = [tex]2\pi \sqrt{\frac{1.44}{g} }[/tex]
0.0875 = [tex]\sqrt{\frac{1.44}{g} }[/tex]
squaring both sides of the equation, we have
7.656 x 10^-3 = 144/g
g = 144/(7.656 x 10^-3) = 18808.7 m/s^2
What does this picture show?
Answer:
d poor accuracy,poor precision
The diagram represents how much accurate and precise the result data is. It is clear from the image that, the data points have poor accuracy and good precision.
What is accuracy ?Accuracy of a result is the measure of the closeness of the experimental or calculated value to the true value or absolute value of a measurement. For a reproducible experiment, the results for each trials can be differ or close.
The closeness between values of a set of experiments is called precision of the results. Not all accurate value be can be precise. Similarly precision of values does not need to meet accuracy.
Here, the central dot indicates the true value. The green points are a set of experimental values. They are not so close to the true value and hence it is less accurate. However, all the points and closer together. Hence, they are precise. Therefore, option B is correct.
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Suppose no stars more massive than about 2 solar masses had ever formed. Would life as we know it have been able to develop
Answer:
No, life would not be to develop
Explanation:
Stars less massive than about 2 solar masses can only produce natural element up to carbon and oxygen, which are the basic elements for building life. However, other more massive elements are needed by life to thrive and function properly, more massive elements like phosphorus, iron necessary for oxygen circulation, calcium for a strong support system, and silicon are essential for for life to form and be sustained here on Earth.
A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?
Answer:
Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
I would appreciate it!
Answer:
[tex]R\approx12.43 \,\, \Omega[/tex]
Explanation:
We can use Ohm's Law to find the resistance R of a wire that carries a current I under a given potential difference:
[tex]V=I\,\,R\\R = \frac{V}{I} \\R=\frac{87}{7} \\R\approx12.43 \,\, \Omega[/tex]
Where are the most reactive elements located on the periodic table.
Answer:
The most reactive elements are at the bottom left corner of the periodic table. Those are the elements that have the most active/most reactive. For example, lithium, sodium, and potassium all react with water!
Explanation:
Don't know what to explain :v
The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to
Answer:
F = 10.86 units
Explanation:
The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:
F = √(Fₓ² + Fy²)
where,
F = Magnitude of the Vector = ?
Fₓ = magnitude of the x-component of vector = 8.7 units
Fy = magnitude of y component of vector = - 6.5 units
Therefore, using these values in the equation, we get:
F = √[(8.7 units)² + (- 6.5 units)²]
F = √(117.94 units²)
F = 10.86 units
A person whose near-point distance is 45.5 cm wears a pair of glasses that are 2.1 cm from her eyes. With the aid of these glasses, she can now focus on objects 25 cm away from her eyes.
Required:
a. Find the focal length of her glasses.
b. Find the refractive power of her glasses.
Answer:
a
[tex]f = 0.4848 \ m[/tex]
b
[tex]p = 2.063 D[/tex]
Explanation:
From the question we are told that
The near point distance is [tex]k = 45.5 \ cm[/tex]
The distance of the glasses from the eye is [tex]y = 2.1 \ cm[/tex]
The distance of an object she can focus with the glass is [tex]i= 25 \ cm[/tex]
Generally the image distance is mathematically evaluated as
[tex]v = -(45.5 - 2.1)[/tex]
[tex]v = -43.4 \ cm[/tex]
Generally the object distance is mathematically represented as
[tex]u = (25 -2.1)[/tex]
[tex]u = 22.9 \ cm[/tex]
The negative sign tells us that the image was formed behind the eye
Generally the lens formula is mathematically represented as
[tex]\frac{1}{f} = \frac{1}{u} + \frac{1}{v}[/tex]
=> [tex]\frac{1}{f} = \frac{1}{22.9} + \frac{1}{ - 43.4}[/tex]
=> [tex]f = 48.48 \ cm[/tex]
converting to meters
[tex]f = 0.4848 \ m[/tex]
Thus the refractive power is mathematically represented as
[tex]p = \frac{1}{f}[/tex]
=> [tex]p = \frac{1}{0.4848 }[/tex]
=> [tex]p = 2.063 D[/tex]
A tire swing hanging from a branch reaches nearly to the ground. How could you estimate the height of the branch using only a stopwatch?
Answer:
A stop watch measures time and the number of seconds making an osculation is the period T
Which is T = 2π√(L/g)........solving for L (the length of the pendulum),
Then the L = T²x g/( 4πr²) substitute and then u find length or height of the swing
1) A cyclist moves a distance of 2000 meters during a time of 20 minutes. How fast is the cyclist?
2) A car moves for 20 minutes on a road with constant speed. If he traveled 60 kilometers, what is his speed?
Answer:
1) speed of a cyclist = 100 m/min.
2) speed of a car moving = 3 km/min.
Explanation:
1) speed of a cyclist = distance over time
= 2000 m / 20 min
= 100 m/min.
2) speed of car moving = distance over time
= 60 km / 20 min
= 3 km/min.
The rotating loop in an AC generator is a square 12.0 cm on a side. It is rotated at 70.0 Hz in a uniform field of 0.800 T. Calculate the following quantities as functions of time t, where t is in seconds. I need help with d and e.
(a) the flux through the loop
11.52cos(140πt) mT·m2
(b) the emf induced in the loop
5.067sin(140πt) V
(c) the current induced in the loop for a loop resistance of 2.50 Ω
2.03sin(140πt) A
(d) the power delivered to the loop
4.12sin2(140πt) W (wrong)
(e) the torque that must be exerted to rotate the loop
mN·m
Answer:
Explanation:
d )
power in an electrical loop = volt x current
= 5.067sin(140πt) x 2.03sin(140πt)
= 10.286 sin²(140πt) .
10.286 ( 1 - cos 280πt ) / 2
= 5.143 ( 1 - cos 280πt )
e )
Torque on a current carrying loop in a magnetic field
= M B sinθ
M is magnetic moment of coil , B is magnetic field , θ is angle between area vector of coil and direction of B .
Here magnetic moment of coil
= A i where A is area of coil and i is current .
= .12² x 2.03sin(140πt)
= .029 sin(140πt)
B = .8 T
MB = .8 x .029 sin(140πt)
= .0232 sin(140πt) x sin(140πt)
=.0232 sin²(140πt).
Consider a vacuum-filled parallel plate capacitor (no dielectric material between the plates). What is the ratio of conduction current Jc to displacement current Jd at 10 MHz
Answer: 1798
Explanation:
Given that there is no dielectric material between the plates,
the permittivity of free space = 9 × 10^-12 f/m
The frequency F = 10 MHz
The ratio of conduction current JC to the displacement current Jd is also known as loss tangent.
Please find the attached file for the solution
A family made the observation that more expensive brands of popcorn seem to produce more popped kernels than cheaper brands of popcorn. In order to test this hypothesis, the family conducted an experiment in which they followed the procedures below: The family bought 2 differing brands of popcorn to test: Wilbur Bockenreder Popcorn and PopWhisper. They measured 1 cup of kernels and popped 5 bowls of each type of popcorn. They ensured they popped the popcorn for the same amount of time, used the same wattage microwave, and did not have any other ingredients added to the kernels (butter, etc). They counted and recorded the number of unpopped kernels in each of the 10 bowls. As they analyzed the data collected, they were able to conclude that their initial hypothesis was supported. They formed the conclusion that the more expensive brand of popcorn popped more kernels than the cheaper brand of popcorn. From this experiment, let's answer some questions. Identify the independent variable.
Answer:
The different types of corn used.
Explanation:
Independent variable: In research methods, the term "independent variable" is determined as a variable that is being manipulated, changed, or altered in an experiment by the experimenter in order to see its effect on the dependent variable. The changes in the dependent variable in an experiment depends on the independent variable directly.
The independent variable in the popcorn experiment is brand of popcorn used.
INDEPENDENT VARIABLE:Independent variable in an experiment is the variable that the experimenter changes or manipulates in order to bring about a response. According to this question, a family is conducting an experiment to test which brand of popcorn seem to produce more popped kernels. They used two brands of popcorn as follows: Wilbur Bockenreder Popcorn and PopWhisper.However, the brand of popcorn was changed in this experiment, hence, the brand of the popcorn is the independent variable.
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A monatomic gas is adiabatically compressed to 0.250 of its initial volume. Do each of the following quantities change?
A) What is rms speed?
B) What is the mean free path?
C) What is the thermal energy of gas?
D) What is the molar specific at a constant volume?
Answer:
Given that
V2/V1= 0.25
And we know that in adiabatic process
TV^န-1= constant
So
T1/T2=( V1 /V2)^ န-1
So = ( 1/0.25)^ 0.66= 2.5
Also PV^န= constant
So P1/P2= (V2/V1)^န
= (1/0.25)^1.66 = 9.98
A. RMS speed is
Vrms= √ 3RT/M
But this is also
Vrms 2/Vrms1= (√T2/T1)
Vrms2=√2.5= 1.6vrms1
B.
Lambda=V/4π√2πr²N
So
Lambda 2/lambda 1= V2/V1 = 0.25
So the mean free path can be inferred to be 0.25 times the first mean free path
C. Using
Eth= 3/2KT
So Eth2/Eth1= T2/T1
So
Eth2= 2.5Eth1
D.
Using CV= 3/2R
Cvf= Cvi
So molar specific heat constant does not change
The rms speed of the system is 1.6 while Mean free path is 0.25 times the first mean free path.
Given that
[tex]\bold{\dfrac {V_2}{V_1}= 0.25}[/tex]
In adiabatic process
[tex]\bold {TV^\gamma^-^1}[/tex]= constant
So
[tex]\bold {\dfrac {T1}{T2}=(\dfrac {V1 }{V2})^ \gamma^-^1}}\\[/tex]
So,
[tex]\bold {\dfrac {T_1} {T_2} = (\dfrac { 1}{0.25})^ 0^.^6^6= 2.5}[/tex]
for pressure,
[tex]\bold {PV^\gamma = \ Constant }[/tex]
So
[tex]\bold {\dfrac {P1}{P2}=(\dfrac {V1 }{V2})^ \gamma}}\\\\\bold {\dfrac {P1}{P2}=(\dfrac {1}{0.25})^ 0^.^6^6} = 9.98 } }[/tex]
A. rms speed can be calculated as
[tex]\bold {\dfrac {Vrms 2}{Vrms1}= \sqrt {T2T1})}\\\\\bold {Vrms2 =\sqrt {2.5} = 1.6\ Vrms1 }[/tex]
B. The mean free path can be calculated as
[tex]\bold {\dfrac {\lambda_1 }{\lambda_2} = \dfrac {V_1}{V_2} = 0.25 \\ }[/tex]
Mean free path is 0.25 times the first mean free path.
C.
[tex]\bold {Eth= \dfrac {3}{2}kT}}\\\\\bold {\dfrac {E_t2}{E_t1} = \dfrac {T_2}{T_1}}\\\\\bold {E_t2= 2.5\ E_t1}[/tex]
D. the molar specific at a constant volume can be calculated a using,
[tex]\bold {CV= \dfrac 3{2}R }[/tex]
[tex]\bold {Cv_f= Cv_i }[/tex]
So, molar specific heat constant will not change.
Therefore, the rms speed of the system is 1.6 while Mean free path is 0.25 times the first mean free path.
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How large an expansion gap should be left between steel railroad rails if they may reach a maximum temperature 36.0°C greater than when they were laid? Their original length is 26.0 m.
Answer:
11 mm
Explanation:
Original length L' = 26 m
Increase in temperature dT = 36.0°C
The gap l =?
The coefficient of linear expansion for steel & = 12 × 10^−6 per °C
The gap will be gotten from the equation of linear expansion.
l = L' x & x dT
substituting, we have
L = 26 x 12 × 10^−6 x 36
L = 0.011 m = 11 mm
How far can a person run in 0.25hr if he or she runs at a average speed of 16km/he?
Answer:
4km
Explanation:
d = st
d=0.25*16
d=4km
Two point charges totaling 8 μC exert a repulsive force of 0.15 N on one another when separated by 0.5 m. What is the charge on each? A. 4.0x10-6 C 4.0x10-6 C B. 7.4x10-6 C 0.6x10-6 C C. 6.6x10-6 C 1.4x10-6 C D. 5.0x10-6 C 3.0x10-6 C
Answer:
B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C
Explanation:
From Coulomb's Law the electrostatic repulsive force is given by the following formula:
F = kq₁q₂/r²
where,
F = Repulsive Force = 0.15 N
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = Magnitude of 1st Charge = ?
q₂ = Magnitude of 2nd Charge = ?
r = Distance between Charges = 0.5 m
Therefore,
0.15 N = (9 x 10⁹ N.m²/C²)q₁q₂/(0.5 m)²
q₁q₂ = (0.15 N)(0.5 m)²/(9 x 10⁹ N.m²/C²)
q₁q₂ = 4.17 x 10⁻¹²
q₁ = (4.17 x 10⁻¹²)/q₂ -------------------- equation (1)
The sum of charges is given as:
q₁ + q₂ = 8 μC
q₁ + q₂ = 8 x 10⁻⁶
using equation (1):
(4.17 x 10⁻¹²)/q₂ + q₂ = 8 x 10⁻⁶
(4.17 x 10⁻¹²) + q₂² = 8 x 10⁻⁶ q₂
q₂² - (8 x 10⁻⁶) q₂ + (4.17 x 10⁻¹²) = 0
Solving this quadratic equation:
q₂ = 7.4 x 10⁻⁶ C (OR) q₂ = 0.56 x 10⁻⁶ C
q₂ = 7.4 μC (OR) q₂ = 0.6 μC
Therefore,
q₁ = (4.17 x 10⁻¹² C)/(7.4 x 10⁻⁶ C)
q₁ = 0.6μC
Now, if we solve with q₂ = 0.6 μC, we will get q₁ = 7.4 μC.
Therefore, the correct option will be:
B. 7.4 x 10⁻⁶ C, 0.6 x 10⁻⁶ C
A particle with charge q and kinetic energy K travels in a uniform magnetic field of magnitude B. If the particle moves in a circular path of radius R, find expressions for:
a. its speed
b. its mass.
Answer:
Given that K.E is
1/2mv²
So to find speed v,
Make it subject
K.E= 1.2mv²
However radial force = magnetic force
So mv²/r= qvB
So v subject
V= 2K.E/ qBr that is speed
To find mass
K.E = 1/2mv²
Puy value of v
So KE= 1/2m(2K.E/qBr)
m= (qBr)/2K.E
That is mass
Answer:
m = qbr/v
v = 2k/qbr
Explanation:
When a charged particle enters a magnetic field, it experiences a force that is always perpendicular to the velocity. This force provides a centripetal force, and thus, we have
qvb = mv²/r
if we make m the subject of the formula, we will have
m = qbr/v
Recall that the kinetic energy, KE = ½mv²
Now, let's make v² the subject of formula, we have
v² = 2K/m
now, we substitute for m from the equation we got earlier
v² = 2K / (qbr/v)
v² = 2Kv / qbr, if we simplify further, we have
v = 2k / qbr
Therefore, we can say that the expression for the mass and speed is respectively,
m = qbr/v
v = 2k/qbr
Which is the property of mattter in which substance can transfer heat to electricity
Conductivity is the property of matter in which a substance can transfer heat or electricity.
Additional information:-Matter : Anything which occupies space and has mass is called matter.
Chemical classifications
Pure Substances ( made of one kind of substance )Impure Substances ( mixture )Physical classifications
Solid Liquid GasPlasma ( made of ions and free electrons )BEC ( Bose Einstein Condensate )Fermionic Condensate ( It discovered in 2003 )The floor of a railroad flatcar is loaded with loose crates having a coefficient of static friction of 0.420 with the floor. If the train is initially moving at a speed of 57.0 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor
Answer:
The distance is [tex]s= 30.3 \ m[/tex]
Explanation:
From the question we are told that
The coefficient of static friction is [tex]\mu_s = 0.42[/tex]
The initial speed of the train is [tex]u = 57 \ km /hr = 15.8 \ m/s[/tex]
For the crate not to slide the friction force must be equal to the force acting on the train i.e
[tex]-F_f = F[/tex]
The negative sign shows that the two forces are acting in opposite direction
=> [tex]mg * \mu_s = ma[/tex]
=> [tex]-g * \mu_s = a[/tex]
=> [tex]a = -9.8 * 0.420[/tex]
=> [tex]a = -4.116 m/s^2[/tex]
From equation of motion
[tex]v^2 = u^2 + 2as[/tex]
Here v = 0 m/s since it came to a stop
=> [tex]s= \frac{v^2 - u^2 }{ 2 a}[/tex]
=> [tex]s= \frac{0 -(15.8)^2 }{ - 2 * 4.116}[/tex]
=> [tex]s= 30.3 \ m[/tex]