What is the average momentum of Cart 1 during the entire time shown before
kg-m
the collision, in units .?
$
Note that the collision appears to take place somewhere between 0.5 s and 0.6
s (perhaps at 0.6 s exactly, but we cannot be sure), so we can safely say that
data up to and including 0.5 s is "before the collision."
Answers
The average momentum of Cart 1 during the entire time shown before the collision is 0.24 kgm/s.
The given parameters:
Mass of the cart 1 = 500 g = 0.5 kgThe average velocity of the cart 1 before collision is calculated as follows;
[tex]v = \frac{\Delta x}{\Delta t} \\\\v = \frac{0.55 - 0.31}{0.5 - 0} \\\\v = 0.48 \ m/s\\\\[/tex]
The average momentum of Cart 1 during the entire time shown before the collision is calculated as follows;
[tex]P = mv\\\\P = 0.5 \times 0.48\\\\P = 0.24 \ kgm/s[/tex]
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Related Questions
Model how solutes dissolve into solvents. Describe how different types of solutes and solvents might attract or repel each other.
Answers
A solvent is any substance which is able to interact with a solute and dissolve it.
A solute is any substance that is able to interact with a solvent and dissolve in it. Usually, the solute must posses similar intermolecular forces as the solvent.
For this reason, polar solutes dissolve in polar solvents while nonpolar solutes dissolve in nonpolar solvents. In polar solutes, the ions or dipoles of the solute are able to interact with the dipoles of the solvent thereby pulling the solute particles apart in order to have solvent - solute interaction.
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Which phrase describes the energy transformation that happens in a
generator?
A. Electrical energy into chemical energy
ООО
B. Electrical energy into mechanical energy
C. Chemical energy into electrical energy
O
D. Mechanical energy into electrical energy
SI
Answers
Answer:
Mechanical energy into electrical energy
Explanation:
Answer:
ExplanMechanical energy into electrical energy
SIation:
2. Where do hyperbolic comets originate?
A.the Oort cloud
B.the asteroid belt
B.the Kuiper belt
C.interstellar space
Answers
Answer:
Hyperbolic comets originate from the Kuiper Belt.
when the tides are especially weak it is called a _____ tide
Answers
Answer:
When the tides are especially weak, it is called a NEAP tide.
Explanation:
Hope this helps :)
Answer:
Neap
Explanation:
Answered!
16. The K-T boundary is a layer of rock that separates the time of the dinosaurs from
their extinction. According to the law of superposition which of the following is true?
A. Paleontologists would expect to find dinosaur bones below the K-T boundary but
not above.
B. Paleontologists would expect to find dinosaur bones far away from tectonic plate
boundaries where new crust is being created
C. Paleontologists would expect to find dinosaur bones above the K-T boundary but
not below.
D. Paleontologists would expect to find dinosaur bones close to tectonic plate
boundaries where new crust is being created
Answers
According to the law of superposition, the statement 'it is expected to find dinosaur bones below the K-T boundary but not above'' is TRUE. This boundary separates the Cretaceous and Tertiary periods.
The law of superposition is used by paleontologists to explain a sequence of sedimentary rock layers from the oldest layer at the base to reach the surface (newer).
Moreover, the K-T boundary is a boundary that separates sediments of the Cretaceous period from the Tertiary period.
This boundary (K-T boundary) dates approximately 65 million years (Mya) ago, i.e., the period in which dinosaurs became extinct.
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plz help ASAP I'll mark as brainliest
Answers
Hi there!
1.
Hooke's law states that:
F = -kx
k = Spring constant (N/m)
x = DISPLACEMENT from equilibrium (m)
Essentially, the force of a spring is PROPORTIONAL to its spring constant and its displacement from its equilibrium point.
2.
The force of the spring (T) is not proportional to the spring's length (l), but rather its DISPLACEMENT from its equilibrium length. (Δl)
3.
The equilibrium length is where the force of the spring (T) = 0N. Looking at the graph, the line intersects this value at l = 30cm.
4.
We can begin by looking at the given graph.
When the spring force = 4N, the total length of the spring is 35 cm.
Now, the EQUILIBRIUM length is 30 cm, so the total elongation is:
35 - 30 = 5 cm.
5.1.
If the spring elongates by 10 cm, the total length of the spring is:
30 + 10 = 40 cm
According to the graph, a length of 40 cm corresponds to a force of 8N.
5.2.
We can solve for the weight of the ball using the following:
W (weight) = m (mass) · acceleration due to gravity (10N/kg)
Using a summation of forces:
∑F = T - W
The elongation that we are solving for occurs at the equilibrium point (net force = 0 N), so:
0 = T - W
T = W = 8 N
5.3.
0 = T - Mg
T = Mg
Use the prior value of T and gravity to solve:
8 = 10M
m = 0.8 kg
A body with a uniform acceleration travels distances of 24m and 64m during the first two equal consecutive intervals of time, each of duration 4s. Determine the initial velocity and acceleration of the moving body.
Answers
Answer:
Explanation:
Average velocity in the 24 m interval is 24 / 4 = 6 m/s
Average velocity in the 64 m interval is 64 / 4 = 16 m/s
There is a 4 second interval between the two points where average velocity equals actual velocity
a = Δv/t = (vf - vi) / t = (16 - 6) / 4 = 2.5 m/s²
s = v₀t + ½at²
24 = v₀(4) + ½(2.5)4²
4v₀ = 24 - 20
v₀ = 1 m/s
Not asked for but the velocity at the end of the first segment and beginning of the second segment is 11 m/s and final velocity is 21 m/s
A jet is flying at a speed of 700 kilometers per hour. The pilot encounters turbulence due to a 50-kilometer- per-hour wind blowing at an angle of 47°. Find the resultant force on the plane.
Answers
Answer:
F = 0 N
Explanation:
The problem does not talk about any acceleration. We can just assume it always moves at a constant speed so the resultant force will be 0 newtons. Of course you could say that it accelerates for a certain amount of time, as the wind blows, but the problem doesn't tell us when to calculate the resultant force (if during the acceleration or after) + we don't have the mass of the jet.
A 1500 kg car has the same momentum as a 2500 kg truck moving at 25 m/s. How fast is the car moving in m/s
Answers
Answer:
41.6m/s
Explanation:
P=mv
2500kg × 25m/s = 62500kgm/s
62500kgm/s ÷ 1500 kg = 41.6m/s
Two students run a race. Student A is 50 kg and runs at 5 m/s. Student B is 30 kg and runs at 2 m/s. Which
student has more Kinetic energy?
Answers
Answer:
Explanation:
KEA = ½(50)5² = 625 J
KEB = ½(30)2² = 60 J
Student A has more kinetic energy.
More than ten times more kinetic energy due to both larger mass and higher velocity.
What do these weapon stats mean?
Idle sway control is measured in Fc???
Flinch resistance is measured in N.
Answers
Answer:
its sort of like how Pounds are measured in lbs
Explanation:
Pounds are measured in lbs when they dont sound anything similar, same thing applies to gun technology.
Determine the rTo understand the concept of nodes of a standing wave.
The nodes of a standing wave are points where the displacement of the wave is zero at all times. Nodes are important for matching boundary conditions, for example that the point at which a string is tied to a support has zero displacement at all times (i.e., the point of attachment does not move).
Consider a standing wave, where y represents the transverse displacement of a string that extends along the x direction. Here is a common mathematical form for such a wave:
y(x,t)=Acos(kx)sin(ωt),
where A is the maximum transverse displacement of the string (the amplitude of the wave), which is assumed to be nonzero, k is the wavenumber, ω is the angular frequency of the wave, and t is time.
Part A
Which one of the following statements about wave y(x,t) is correct?
adius of the 236U nucleus.
Answers
Answer:
The nodes of a standing wave are points where the displacement of the wave is zero at all times nodes are important for matching boundary conditions for example that the point at which a string is tied to a support has zero displacement at all times ie the point of attachment does not move consider a standing
A 25.0kg boy is sliding on a frictionless frozen lake at 5.00m/s to the north when he is struck by a 1.00kg
snowball moving at 15.0m/s from the west. If the snowball sticks to him, how fast, and in what direction,
does the boy move after the collision?
Answers
The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east
The given parameters;
Mass of the boy, m₁ = 25 kgSpeed of the boy, u₁ = 5 m/sMass of the snowball, m₂ = 1.0 kgSpeed of the snow ball, u₂ = 15 m/sThe initial momentum of the boy is calculated as follows;
[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]
The initial momentum of the snowball is calculated as follows;
[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]
The resultant momentum of the boy and the snowball after collision is calculate as follows;
[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]
The final velocity of the system boy-snowball system is calculated as;
[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]
The direction of the boy after the collision is calculated as follows;
[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]
Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east
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This is the question I need help with
Answers
Answer:
Explanation:
If we ASSUME that a CCW torque is positive
τ = 10sin135[8.0] - 16sin90[4.0] + 19sin160[3.0] = 12 N•m
as the result is positive, the net torque is CCW.
A boy weighing 445 N swings on a 2-m long swing. If his horizontal speed at the lowest point is 3 m/s, what total force must the ropes holding the swing be able to withstand?
Answers
Explanation:
We need to calculate the centripetal force:
Fc = W + F
With Fc being the centripetal force, W the weight of the boy, F the centrifugal force (apparent).
We know that we can calculate the apparent centrifugal force thank to the formula:
F = (m·v²)/r = 204N
So we can write:
Fc = W + F = 445N + 204N = 649N
refers to a fear of being trapped in a crowded, public place.
Answers
Answer:
Agrophobia
Explanation:
an anxiety disorder in which someone feals anxious and scared in a public place
The earth has a mass of 5.972 x 1024 Kg. You decide to
put the satellite in an orbit 400 Km above the surface of the earth which has a radius of 6,371 Km, so the total
distance from the center of the earth to the satellite is 6,771,000 m. What will you need the velocity of the
satellite to be to stay in orbit? Show your work
Answers
Answer:
Explanation:
You want the required centripetal force to equal gravity force
if m is the mass of the satellite
ma = mv²/R
a = v²/R
F = ma = GMm/R²
a = GM/R²
v²/R = GM/R²
v² = GM/R
v = √(GM/R)
v = √(6.674 x 10⁻¹¹(5.972 x 10²⁴)/6.771 x 10⁶)
v = 7.672 x 10³ m/s
You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1 radian/sec. The pivot breaks. Though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. The new oscillation frequency is:
A. 0.88 rad/sec
B. 1.13 rad/sec
C. 1.07 rad/sec
D. 0.92 rad/sec
Answers
The new oscillation frequency of the pendulum clock is 1.14 rad/s.
The given parameters;
Mass of the pendulum, = M Length of the pendulum, = LInitial angular speed, [tex]\omega _i[/tex] = 1 rad/sThe moment of inertia of the rod about the end is given as;
[tex]I_i = \frac{1}{3} ML^2[/tex]
The moment of inertia of the rod between the middle and the end is calculated as;
[tex]I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} = \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}[/tex]
Apply the principle of conservation of angular momentum as shown below;
[tex]I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f[/tex]
Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.
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A car accelerating from rest for 20s to reach velocity of 15 m/s and it keeps on. moving with this velocity for 50s an then it applied the break
Stop in 30s what is the displacement?
WILL GIVE BRAINLY best answer with steps
Answers
Answer:
1125m
Explanation:
The car moves with a uniformly accelerated motion for 20s:
s = 1/2·a·t² + v0·t + s0 (note that vo = 0 and s0 = 0, with v0 being the initial velocity and s0 the initial displacement).
So: s = 1/2·a·t²
The acceleration will be: Δv/Δt = 15m/s / 20s = 0.75 m/s²
s1 = 1/2·0.75 m/s² · (20 s)^2 = 150m
Then it continues with the velocity he acquired (v = a·t = 0.75 m/s²·20s = 15 m/s):
s2 = vt = 15m/s·50s = 750m
The final acceleration, when stopping, will be:
a = Δv/Δt = -15m/s / 30s = -1/2 m/s²
s3 = 1/2·(1/2m/s²)·(30s)² = 225m.
Now we sum s1 with s2 and s3:
s1 + s2 + s3 = 150m + 225m + 750m = 1125m
Which is the independent variable in the graph of the U.S. population 1800-1900?
1. United States
2. straight lines
3. years
4. population
Answers
Answer:
3. years
Explanation:
The independent variable is the x axis of graph
A thin stream of water flows smoothly from a faucet and falls straight down. At one point, the water is flowing at a speed of 1=1.31 m/s . At a lower point, the diameter of the stream has decreased by a factor of 0.805 . What is the vertical distance ℎ between these two points?
Answers
Answer:
Explanation:
as the mass cannot change, the volume per unit time is also constant so the area of the stream times the velocity is constant
If the diameter is 1 where velocity is 1.31 m/s
area is proportional to the square of the diameter A = (π/4)d²
1²(1.31) = 0.805²(v)
v = 1.31/0.805² = 2.02 m/s
v² = u² + 2as
2.02² = 1.31² + 2(9.81)h
h = 0.120819... m
h = 12.0 cm
Wtz the answer to this question? I need to get it right
Answers
Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?
Select the correct answer.
What is the force that can cause two pieces of iron to attract each other?
A.
gravitational force
B.
magnetic force
C.
elastic force
D.
electrostatic force
Answers
Answer:
A. gravitational force always true.
B, C and D could be true under the correct conditions
If a force of 50 Newton's was applied to an object with a mass of 5 kilograms, what will the object's acceleration be?
Answers
Force = mass * acceleration
A force of 50 N was applied to an object with a mass of 5 kg, then the acceleration of the object will be 10 m/s².
What is Acceleration?The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
There are several types of acceleration :
Uniform AccelerationNon-Uniform AccelerationAverage AccelerationAccording to the question, the given values are :
Force, F = 50 N
Mass, m = 5 kg
Force = m × a
a = 50 / 5
a = 10 m/s².
Hence, the acceleration of the object will be 10 m/s².
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9. If the force acting on a mass of 4kg accelerates it at a rate of 2m/s2, what will be the acceleration of the body when the force is doubled?
Answers
Explanation:
Force= mass× acceleration
Force= 4×2
= 8N
Doubling the force, 8×2= 16N
16= 4 × a
a= 16/4
= 4m/s²
The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?
Answers
The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].
Given the following data:
Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 VoltsTo determine the charge:
Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:
[tex]W = PQ[/tex]
Where:
W is the work done.P is the electric potential difference.Q is the charge.Making Q the subject of formula, we have:
[tex]Q =\frac{W}{P}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]
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Energy can be changed from one form to another. Which terms can be used to describe these changes? Check all
that apply.
energy conversion
energy conservation
energy correlation
energy transformation
energy transference
Answers
Answer:
energy transformation
Answer: Energy Transformation & Energy Conversion.
In three to five sentences, identify the acid, base, conjugate acid, and conjugate base. Use patterns in the periodic table to explain why the substances you identified acted as the acid and the base in this reaction.
Answers
A conjugate acid is formed from the base by accepting a proton from the acid .
A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.
Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie :B is the Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the Brownstead - Lowry acid.
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An airplane accelerates from rest down a runway at 9.50 m/s2 for 29.3 seconds when it
takes off. What is the distance traveled while taking off?
Answers
Answer:
Explanation:
s = ½at²
s = ½(9.50)(29.3²) = 4,077.8275
s = 4080 m
when rounded to the three significant digits of the question numerals.
The force as a function of displacement of a moving object is presented by the graph. How much work is done when the object moves from 5 m to 8 m? *
Answers
Answer:
Explanation:
Work is the area under the curve between the limits
W = ½(5)(8 - 5) = 7.5 J
The work done when an object moves from 5 m to 8 m is 7.5 J.
Work done
The work done in moving an object from one point to another is equal to the product of force and displacement of the object.
W = Fs
Area under a curveThe work done on an object is equal to area under the curve
The area between point 5 m and 8 m = ¹/₂ x (8 - 5) x 5 = 7.5 J
Thus, the work done when an object moves from 5 m to 8 m is 7.5 J.
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