What is the area, in square centimeters, of the trapezoid below?

What Is The Area, In Square Centimeters, Of The Trapezoid Below?

Answers

Answer 1

Answer:

36 cm²

Step-by-step explanation:

1/2 × (8.9+5.5) ×5.5

1/2×14.4×5.5

1/2×72

36 cm²


Related Questions

what is the answer in simplest form?

Answers

[tex]\\ \sf\longmapsto 2m^2=-200[/tex]

[tex]\\ \sf\longmapsto m^2=-100[/tex]

[tex]\\ \sf\longmapsto m=√-100[/tex]

[tex]\\ \sf\longmapsto m=√100i[/tex]

[tex]\\ \sf\longmapsto m=10i[/tex]

NEED HELP PRONTOOO!!!!!!!!!!!!!!!!!!

Answers

Answer:

(x + 5)² - 25

Step-by-step explanation:

Given below, if Xy and are congruent, what is the measure of A. 140°
B. 280°
C. 100°
D. 80°
(it’s A. 140°)

Answers

Answer:

holi , cómo estás espero que bien bueno déjame te digo que está facil soy de México pero voy a clases de inglés y ya me la hicieron esa pregunta y es la D hojala te ayude mucho

i really need your help on this

Answers

Answer:

That is an improper fraction

Step-by-step explanation:

When the numerator (the top) is greater than the denominator (The bottom) then the fraction is improper

Hope this helps!

Answer:

Improper fraction

Step-by-step explanation:

Find the length of the second base of a trapezoid with one base measuring 18 feet, a height of 5.3 feet, and an area of 125.4 square feet.​

Answers

Answer:

29.32 feet

Step-by-step explanation:

area of a trapezoid = height/2 * (first base + second base)

125.4 = 5.3 / 2 * (18 + second base)

125.4 = 2.65 * (18 + second base)

We want to solve for the second base. To do this, we can start by isolating the (18+second base) by dividing each side by 2.65

47.32 = 18 + second base

subtract 18 from both sides to solve for the second base

29.32 = second base

what is the factor of this 3x - 12

Answers

Answer:

3 (x - 4)

Step-by-step explanation:

Can someone help me, please? :((((

Answers

Answer:

C 132 square units

Step-by-step explanation:

. Happy Friday

PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKS

Answers

Answer: y= (1/4)x

Step-by-step explanation: Best guess given screenshot, matched with desmos.

Prove the following ​

Answers

Step-by-step explanation:

Start by multiplying both sides by cosα:

1 + sinα + (cos²α)/(1+sinα) = 2

sinα + (cos²α)/(1+sinα) = 1

Now multiply both sides by 1+sinα:

sinα + sin²α + cos²α = 1 + sinα

sin²α + cos²α = 1 Q.E.D.

Thats the answer and method i used

1/2 + (-7) – 2 1/2 - (-2)​

Answers

The answer is -7

Explanation:

Dont know how to calculate it

Answers

Answer:

AB = 105

Step-by-step explanation:

Since ∠ A and ∠ B  are equal then Δ ABC is isosceles with 2 congruent legs.

AC = BC , substitute values

6x - 7 = 5x + 7 ( subtract 5x from both sides )

x - 7 = 7 ( add 7 to both sides )

x = 14

Then

AB = 7x + 7 = 7(14) + 7 = 98 + 7 = 105

the triangle has a right angle at the middle letter.
In AABC, Ĉ = 40°, BC = 4 cm. Find AB.

Answers

Tan 40 degree= opposite (ab)/adjacent (4)
.839=ab/4
Ab=3.36cm

find the length of the rectangular plot of land whose weight is 10 M and perimeter is 44 m

Answers

Step-by-step explanation:

Area of this plot =(84×84) m

2

=7056 m

2

length of rectangular plot =144 m.

We know that the area of the square plot is same as the area of the rectangular plot

Let breadth of rectangular plot be x.

then, 144x=7056 [∵ Area of a rectangle =l×b ]

⟹x=

144

7056

=49 m

∴ The width of rectangular plot is 49 m.

Pleas help me for B and C

Answers

Answer:

In no b 7 people has represented □

In no c 2 people referred giraffe than dogs

Answer:

(b)Total 8 complete square in given pictogram represented 64 people.

(c) 6 more people preferred giraffes than dogs.

Cliek an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan click the trashcan to clear all your answers
Factor completely, then place the answer in the proper location on the grid
2107.57a+ 30
123456789

Answers

Answer:    3(7a-5)(a-2)

===============================================================

Explanation:

I'll use the variable x in place of 'a'

The expression we need to factor is [tex]21x^2-57x+30[/tex] which is in the form [tex]ax^2+bx+c[/tex]

So,

a = 21b = -57c = 30

We'll plug those three values into the quadratic formula

[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-57)\pm\sqrt{(-57)^2-4(21)(30)}}{2(21)}\\\\x = \frac{57\pm\sqrt{729}}{42}\\\\x = \frac{57\pm27}{42}\\\\x = \frac{57+27}{42} \ \text{ or } \ x = \frac{57-27}{42}\\\\x = \frac{84}{42} \ \text{ or } \ x = \frac{30}{42}\\\\x = 2 \ \text{ or } \ x = \frac{5}{7}\\\\[/tex]

The two roots of [tex]21x^2-57x+30 =0[/tex] are [tex]x = 2 \text{ and } x = \frac{5}{7}[/tex]

The root x = 2 leads to the factor (x-2) after subtracting 2 from both sides.

The root [tex]x = \frac{5}{7}[/tex] leads to the factor (7x-5) after first multiplying both sides by 7, and then subtract 5 from both sides.

So we have this set of steps:

[tex]x = \frac{5}{7}\\\\7x = 5\\\\7x-5=0\\\\[/tex]

The two factors are (x-2) and (7x-5).

This leads to (x-2)(7x-5)

The last step is to replace x with 'a' so that the variables match up.

We arrive at  (a-2)(7a-5)

However, as the next section shows, we have a bit of a problem. Don't worry, it can be easily fixed.

---------------------

Let's expand out that factored expression we found earlier.

[tex](a-2)(7a-5)\\\\b(7a-5)\ \text{ ..... let b = a-2}\\\\7ab - 5b\\\\7a(b) - 5(b)\\\\7a(a-2) - 5(a-2)\ \text{ ..... plug in b = a-2}\\\\7a^2-14a - 5a+10\\\\7a^2-19a+10\\\\[/tex]

That's not good. We should have arrived at the original expression [tex]21a^2-57a+30[/tex]. To fix this discrepancy, we can stick a 3 out front and then notice that:

[tex]3(a-2)(7a-5) = 3(7a^2-19a+10) = 21a^2-57a+30[/tex]

The error has been fixed.

We have the full factorization of 3(a-2)(7a-5)

The order of the factors doesn't matter, so we could have written the answer as 3(7a-5)(a-2). Usually the factor without any variables will be listed first.

Based on the screenshot you posted, if that '7' is locked in place, then the only possible answer is 3(7a-5)(a-2) since you'll have 3 in the first slot, then a ( in the next slot. The other slots are filled out in a similar manner. There are no spaces between any symbol or letter.

6. If the pattern continues, what would be the ninth number in the pattern?

4 8, 12, 16___

( full question on pic )

Hi! can someone help me please, thank u!

Answers

20 would be the answer. Your counting by 4s

Answer:

20

Step-by-step explanation:

You're counting by 4's. Which are the following 4,8,12,16,20 and so on. Hope this helps :D

YOU guys can write a story or a situation that can be represented by the given equation.

4a + 5 = 12a - 11

Thank you :)​

Answers

Answer:

If you have a party and your pizza was split up into 16 pieces, 8 people should be able to have 2 pieces.

Step-by-step explanation:

A t-shirt shop bought a total of 24 t-shirts (t) and hats (h) combined. They bought t-shirts for $12.50 each and hats for $8 each. The store spent a total of $259.50, which system of equations could be used to find the number of hats and t-shirts bought?

Answers

Answer:

12.5t + 8h = 259.5

t + h = 24

Step-by-step explanation:

Write one equation to deal with the costs and one equation to deal with the numbers of shirts and hats.

12.5t + 8h = 259.5

t + h = 24

greg drove 300 miles at a constant speed for 5 hours. the speed limit is 70 miles per hour. was his rate grater than the speed limit?

Answers

Answer:

No.

Step-by-step explanation:

To find the rate for how many miles Greg drove for 5 hours, we need to divide 300 by 5:

300 / 5 = 60.

60 miles represents the speed for 1 hour.

60<70.

The inequality indicates that his rate (60 miles per hour) is less than the speed limit.

what are some expressions that are equivalent to

2(5n).

Answers

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\large\text{Gu\textbf{id}\textsf{e}}\bf\downarrow[/tex]

[tex]\large\textbf{2 negatives = positive}\\\large\textbf{2 positives = positive}\\\large\textbf{1 negative \& 1 positive = negative}\\\large\textbf{1 positive \& 1 negative = negative}\\\\\large\text{Negatives are BELOW 0}\\\large\text{Positives are ABOVE 0}\\\\\large\textsf{Negatives are on the LEFT side of zero.}\\\large\textsf{Positives are on the RIGHT side of zero.}[/tex]

[tex]\huge\textsf{-2(5n) \boxed{\rightarrow} \bf -10n}\\\\\\\\\huge\boxed{\rightarrow\text{-2n + (-2n) + (-2n) + (-2n) + (-2n)}}\\\huge\boxed{\rightarrow \text{\bf -2n - 2n - 2n - 2n - 2n}}\\\huge\boxed{\rightarrow{\text{-4n - 2n - 2n - 2n}}}\\\huge\boxed{\rightarrow \text{-6n - 2n - 2n}}\\\huge\boxed{\rightarrow \text{\bf -8n - 2n}}\\\huge\boxed{\rightarrow \boxed{\text{ -10n}}}[/tex]

[tex]\huge\text{\bf -5(2n)}\\\huge\boxed{\rightarrow \text{-10n}}[/tex]

[tex]\huge\boxed{\text{\bf Therefore, your answers \underline{\underline{could}} be: }}\\\huge\boxed{\bullet \textsf{ -2n - 2n - 2n - 2n -2n}}\huge\checkmark\\\huge\boxed{\bullet \textsf{ -8n - 2n}}\huge\checkmark\\\huge\boxed{\bullet \textsf{ -5(2n)}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

(1)Pradnya had 5 dozen copies. She gave half of the copies to Anushka and 1/5 times of the copies to Prajwal. How many copies are remaining with her ?
(2) Shrikant bought a watch at Rs. 900. He gave equal number of notes of denomination Rs. 10, Rs. 20, Rs. 50 and Rs. 100. Find the number of notes of Rs. 20 that he gave to the shopkeeper.
(3) Mangalakaku purchased 6016 saplings of lemon. She planted 47 saplings in each row. How many rows will be formed of those saplings?​

Answers

Explanation:

(i)Total number of copies are at Pradnya = 5 dozen

We know that 1 dozen = 12

⇛5×12 = 60

Given copies to Anushka = half of 60

⇛60/2 = 30 copies

Given copies to Prajwala = 1/5 the copies

⇛ (1/5)×60

⇛60/5

⇛12 copies

Total number of given copies = 30+12 = 42

Remaining copies = 60-42 = 18

Answer: Remaining copies = 18

(ii)Let the number of Rs. 10 notes be X

So given that

all are equal in number

So, Number of Rs 20 notes = Number of Rs. 50 notes = Number of Rs. 100 = X

Total number of notes

= X+X+X+X = 4X

Value of Rs. 10 = 10X

Value of Rs. 20 = 20X

Value of Rs. 50 = 50X

Value of Rs. 100 = 100X

Total amount = Rs. 900

⇛10X +20X +50X+100X = 900

⇛180X = 900

⇛X = 900/180

⇛X = 5

Number of Rs. 10 notes = Number of Rs. 20 notes = Answer: number of Rs. 50 notes = Number of Rs. 100 = 5

(iii) Let the number of rows be X

Number of saplings per each row = 47

Total number of saplings of X rows = 47X

According to the given problem,

Total number of saplings purchased by Mangalakaku = 6016

⇛47X = 6016

⇛X = 6016/47

⇛X = 128

Answer: Total number of rows = 128

need help with this pls

Answers

Answer:

Hence y = (5k -3)/ (1 - k)

.... shown

alex is running in a clockwise direction around a circular track with radius 60 yards. he runs for 20 minutes at a speed of 4 yards per second. find the shortest distance between their starting point and their ending point measured along the track

Answers

Answer:

  100.9 yards

Step-by-step explanation:

One circuit of the track is a distance of ...

  C = 2πr = 2π(60 yd) = 120π yd.

At Alex's running rate, the distance covered in 20 minutes is ...

  (4 yd/s)(20 min)(60 s/min) = 4800 yd

The number of circuits will be ...

  (4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits

The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,

That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd

The shortest distance along the track to Alex's starting point is about 100.9 yards.

_____

Additional comment

The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.

In science class, the girl to boy ratio is 3 to 7.
If there are 50 students total in the class, how many are boys?

Answers

Answer:

There are 35 boys in the class.

Step-by-step explanation:

Girls to Boys ratio = 3:7

Total number of students in class = 50

Let total number of girls be '3x' and total number of boys be '7x'

Total number of girls + Total number of boys = Total number of students

3x + 7x = 50

10x = 50

x = 50/10

x = 5

[tex] \therefore [/tex]

Total number of girls = 3 × 5 = 15

Total number of boys = 7 × 5 = 35

8 less than the sum of u and 2

Answers

Answer: u < 6

Step-by-step explanation: 2 + u < 8

u < (8-2)

u < 6

if laura has a school loan of $420,a car loan of $300 and rent of $550,what must she budget just to pay those expenses?

Answers

Answer:

1270

Step-by-step explanation:

420+300+550

$420+300=720+550=1270

PLEASE HELP!!!!
ILL MARK AS BRAINIEST!!!!
ANSWER HOW MUCH U CAN!!!

Answers

Answer:

1) C

2) B

3) D

4) A

5) B

Step-by-step explanation:

Hope this helps

MAy I get braineist pls???????????

Answer:

MARK ME AS BRAINLIEST!!!

Step-by-step explanation:

1. A

2. B

3. D

4. A

5. B

HAVE A NICE DAY!!!

:)

The charge on an ion is
a.
always positive.
b.
always negative.
C.
either positive or negative.

Answers

Answer:

C. Either positive or negative

Please help question in pic

Answers

Answer:

7,3

Step-by-step explanation:

for every 5 it goes right it goes 4 up. 2,1+5,4=7,3

Determine if they are congruent. State how they are.

Answers

[tex]\huge \bf༆ Answer ༄[/tex]

The Correct choice is ~ D

[tex] \textsf{Not enough information }[/tex]

The given triangles are not congruent, because they they just have all their corresponding angles equal to one another, so we need more information ~

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