What is the answer. I need it ASAP u have to choose 3 answers

Answer:

Domain = -6 < x < 3

range = -6 < x < -4

Step-by-step explanation:

The domain is the input values along the x-axis. According to the graph, the x values are within the interval;

Domain= -6 < x < 3

The range is the output values along the y-axis. According to the graph, the y values are within the interval;

range = -6 < x < -4

Answer:

8970

Step-by-step explanation:

In order to round 9272 so that it has only 1 nonzero digit, look at the hundred digit, If the number is greater or equal to 5, add 1 to the thousand figure. If this is not the case, add zero

The hundred digit is 2 which is less than 5, so 0 is added to 9. the number becomes 9000

In order to round 28 so that it has only 1 nonzero digit, look at the units digit, If the number is greater or equal to 5, add 1 to the tens figure. If this is not the case, add zero

The units digit is greater than 5, so 1 would be added to tens digit. the number becomes 30

9000 - 30 = 8970

Answer:

cosB = 7/25 = 0,28

tanB = 24/7 = 3,428571429

sinB = 24/25 = 0,96

Answer:

28 children and 7 adults

Equation 1: a + c = 35

Equation 2: 6a + c = 70

Step-by-step explanation:

If the total number of people at the movie was 35 people, one of the equations will be a + c = 35.

If $70 was collected in total, the other equation will be 6a + c = 70.

Now, solve this system of equations:

a + c = 35

6a + c = 70

Solve by elimination by multiplying the top equation by -1, then adding the equations together:

-a - c = -35

6a + c = 70

Add these together, and solve for a:

5a = 35

a = 7

Since there were 35 people in total, find how many children attended by subtracting 7 from 35:

35 - 7

= 28

So, there were 28 children and 7 adults.

The equations used were: a + c = 35 and 6a + c = 70

So, the correct answer is:

28 children and 7 adults

Equation 1: a + c = 35

Equation 2: 6a + c = 70

Answer:

a. 11900, 15875

b. 0.2052, 0.2175

Step-by-step explanation:

number of engineers in 2018 = 10

calls handled in 2018 = 119000

average salary in 2018 = 58000

number of engineers in 2019 = 8

calls handled = 127000

salary = 73000

a.) operational productivity = output/input

in year 2018 = 119000/10= 11900

in year 2019 = 127000/8 = 15875

b.) ratio for both years = output/amount spent

in year 2018 = 119000/10*58000 = 0.2052

in year 2019 = 127000/8*73000 = 0.2175

Answer:

42

Step-by-step explanation:

(adjacent straight angles sum up to 180)

3x+54=180

x=42

Answer:

Step-by-step explanation:

We need to first find out how much 400% of 170 is and then add that increase to the original 170 people.

4(170) = 680 and

680 + 170 = 850 people after 3 years.

Answer:

3. -3,0,|3|, (-3)^2

Step-by-step explanation:

Answer:

answer would be option 3

Step-by-step explanation:

help this helps

Answer:

a. 17.18

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

Identify

w = 17

x = 29

z = 8

w + (1/x) + (1/z)

Step 2: Evaluate

Anwer:$285

Explaination: Division method

$1995.00÷7=$285

Answer:

C.

Step-by-step explanation:

In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.

A.

9 + 9 = 18

18 < 22

No triangle

B.

7 + 3 = 10

10 = 10

No triangle

C.

5 + 6 = 11 and 11 > 9  good

5 + 9 = 14 and 14 > 6  good

9 + 6 = 15 and 15 > 5  good

There is a triangle.

Answer: C.

Answer:

find the quotient of 8 divided by one-third, multiply 8 by

A:1/8

B:1/3( true

C:3

D:8

are the possible answers

Answer:

z (max)  =  34500 $

x₁  =  2

x₂  = 3

Step-by-step explanation:

Hilltop College  

3 hours per week  preparing lessons and grading papers

Serra College

4  hours per week  preparing lessons and grading papers

Total hours to spend per week preparing lessons  18

Let´s call  x₁  numbers of class at Hilltop College

and  x₂ numbers of class at Serra College then:

Objective function

z  =  6000*x₁  +  7500*x₂

Constraints:

1.-     x₁  +  x₂  ≤ 5        the total number of class

2.-    3*x₁  +  4*x₂  ≤  18

3. General constraints   x₁  ≥ 0       x₂    ≥  0   integers

After 6 iteration optimal solution is:  From on-line solver

z (max)  =  34500 $

x₁  =  2

x₂  = 3

1 5

12 1 121

1

121

13

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OC. .

12

OD. ????????????????

Median of the given data is 8.5.

In statistics, the median is the middle value of the given list of data in order. Data or observations can be sorted in ascending or descending order.

Given data,

1 , 5, 12, 1, 121, 1, 121, 13

Arranging in ascending order

1, 1, 1, 5, 12, 13, 121, 121

Number of elements N = 8

When number of elements is odd

Median = (N/2 th term + (N/2)+1 th term)/2

Median = (8/2 th term + (8/2)+1 th term)/2

Median = (4th term + 5th term)/2

Median = (5+12)/2

Median = 17/2

Median = 8.5

Hence, 8.5 is the median of the given data.

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Answer:

x= - 18/7 - 1/7y, y

or if you are solving for y= -18-7x, x

( SEE OTHER IMAGE)

Step-by-step explanation:

See image below:)

Answer:

[tex]x= \frac{- 18 - y }{7}[/tex]

y = - 18 - 7x

Step-by-step explanation:

7x + y = - 18

7x + y - y = - 18 - y

7x = - 18 - y

[tex]\frac{7x}{7}= \frac{- 18 - y }{7}[/tex]

[tex]x= \frac{- 18 - y }{7}[/tex]

7x + y = - 18

7x - 7x + y = - 18 - 7x

y = - 18 - 7x

Answer:

We do not reject the Null Hypothesis

Step-by-step explanation:

From the question we are told that:

Sample size [tex]n=23[/tex]

Population mean [tex]\mu=9.02cm^3[/tex]

Sample mean [tex]\=x=8.16[/tex]

Standard deviation [tex]\sigma=0.7cm^3[/tex]

Significance level [tex]\alpha =0.01[/tex]

Generally the Null and and alternative Hypothesis are as follows

 [tex]H_0:\mu=9.02cm^3[/tex]

 [tex]H_a:\mu<9.02cm^3[/tex]

Therefore t critical Value is

 [tex]t\ critical\ Value=(\alpha,df)[/tex]

 [tex]t\ critical\ Value=(0.01,22)[/tex]

Where

  [tex]df=n-1\\\\df=23-1=>22[/tex]

Therefore

From t Table

 [tex]t value=-2.8[/tex]

Generally the equation for Z Critical is mathematically given by

 [tex]t=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex]

 [tex]t=\frac{8.16-9.02}{\frac{0.7}{\sqrt{23} } }[/tex]

 [tex]t=-5.89[/tex]

Therefore

Since the t test statistics is greater than the Critical value

Hence,we do not reject the Null Hypothesis

9514 1404 393

Answer:

  $386,857.14

Step-by-step explanation:

You have ...

  sold = 140% × paid

Dividing by 140% gives ...

  paid = sold/1.40 = $541,500/1.40 = $386,857.14

Derek paid $386,857.14 for the property.

Answer:

Wow sup Comment allez-vous, je suis là pour vous aider à essayer cette application, je ne suis pas vraiment sûr de ce que vous entendez par " Rubber Band App " Mais je pense que cela pourrait aider à l'essayer Exercices de bande de résistance

=========================================================

Explanation:

The set of natural numbers is {1,2,3,...} basically anything positive and a whole number.

Any multiple of 8 is of the form 8x. Since x is a natural number, the smallest it can be is x = 1 which corresponds to 8x = 8*1 = 8. So 8 is the first multiple of the set. Then 16 is next because 8x = 8*2 = 16, and so on.

That's how we end up with {8, 16, 24, 32, ...}

The three dots, or ellipses, tell the reader that the pattern goes on forever. This set is infinitely large. We wouldn't stop at 800 because we could plug in say x = 200 to get 8x = 8*200 = 1600 and that's a multiple of 8.

9514 1404 393

Answer:

  8√3 ≈ 13.86 ft

Step-by-step explanation:

The light source is usually placed at the focus, so the focus-vertex distance is p=3 ft. The equation for the parabola with its vertex at the origin is ...

  y = 1/(4p)x^2

  y = 1/12x^2

The opening for some y-value extends ±x from the axis of symmetry, so is a total of 2x in width.

For y=4, the corresponding value of x is ...

  4 = 1/12x^2

  48 = x^2

  √48 = x = 4√3

Then the width of the searchlight opening is ...

  2(4√3 ft) = 8√3 ft ≈ 13.86 ft

9514 1404 393

Answer:

  ∠15 = 97°

Step-by-step explanation:

At any given transversal of parallel lines, all obtuse angles are congruent, and all acute angles are congruent. Obtuse angle 15 is congruent to the one market 97°.

  ∠15 = 97°

Answer:

[tex]CV=0.2[/tex] ---- dataset 1

[tex]CV = 7.2[/tex] --- dataset 2

Step-by-step explanation:

Given

[tex]A: 30500, 27500, 31200, 24000, 27100,28600, 39100, 36900, 35000, 21400, 37900, 27900, 18700,[/tex][tex]33100[/tex]

[tex]B: 4.29, 4.88, 4.34, 4.17, 4.52, 4.80, 3.28, 3.79, 4.84, 4.77, 3.11[/tex]

Required

The coefficient of variation of each

Dataset A

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{30500+ 27500+31200+24000+ 27100+28600+ 39100+ 36900+ 35000+ 21400+ 37900+ 27900+ 18700+33100}{14}[/tex][tex]\mu = \frac{418900}{14}[/tex]

[tex]\mu = 29921.43[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

So, we have:

[tex]\sigma= \sqrt{\frac{(30500 - 29921.43)^2 +.................+ (18700- 29921.43)^2 + (33100- 29921.43)^2}{13}}[/tex]

[tex]\sigma= \sqrt{\frac{487723571.42857}{14}}[/tex]

[tex]\sigma= \sqrt{34837397.959184}[/tex]

[tex]\sigma= 5902.32[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV=\frac{5902.32}{29921.43}[/tex]

[tex]CV=0.2[/tex] --- approximated

Dataset B

Calculate the mean

[tex]\mu = \frac{\sum x}{n}[/tex]

[tex]\mu = \frac{4.29+ 4.88+ 4.34+ 4.17+ 4.52+ 4.80+ 3.28+ 3.79+ 4.84+ 4.77+ 3.11}{11}[/tex]

[tex]\mu = \frac{46.79}{11}[/tex]

[tex]\mu = 4.25[/tex]

Next, calculate the standard deviation using:

[tex]\sigma = \sqrt{\frac{\sum(x - \mu)^2}{n}}[/tex]

[tex]\sigma = \sqrt{\frac{(4.29 - 4.25)^2 + (4.88- 4.25)^2 +.........+ (3.11- 4.25)^2}{11}}[/tex]

[tex]\sigma = \sqrt{\frac{3.859}{11}}[/tex]

[tex]\sigma = \sqrt{0.35081818181}[/tex]

[tex]\sigma = 0.593[/tex]

So, the coefficient of variation is:

[tex]CV=\frac{\sigma}{\mu}[/tex]

[tex]CV = \frac{4.25}{0.5903}[/tex]

[tex]CV = 7.2[/tex] -- approximated

Step-by-step explanation:

[tex]\displaystyle \lim_{x \to 0} \left(\dfrac{\sqrt{x^2 + 3x + 1} - 1}{\arcsin 2x} \right)[/tex]

Note that as [tex]x \rightarrow 0[/tex], the ratio becomes undefined. Using L'Hopital's Rule, where

[tex]\displaystyle \lim_{x \to c} \dfrac{f(x)}{g(x)} = \lim_{x \to c} \dfrac{f'(x)}{g'(x)} [/tex]

where f'(x) and g'(x) are the derivatives of the functions f(x) and g(x), respectively. Note that

[tex]f(x) = \sqrt{x^2 + 3x + 1} \:\:\text{and}\:\: g(x) = \arcsin 2x[/tex]

[tex]f'(x) = \dfrac{2x + 3}{2(\sqrt{x^2 + 3x + 1})}[/tex]

[tex]g'(x) = \dfrac{2}{\sqrt{1 - 4x^2}}[/tex]

Therefore,

[tex]\displaystyle \lim_{x \to 0} \dfrac{f'(x)}{g'(x)} = \lim_{x \to 0} \dfrac{2x + 3}{2(\sqrt{x^2 + 3x + 1})} \times \left(\dfrac{\sqrt{1 - 4x^2}}{2} \right)[/tex]

or

[tex]\displaystyle \lim_{x \to 0} \left(\dfrac{\sqrt{x^2 + 3x + 1} - 1}{\arcsin 2x} \right) = \dfrac{3}{4}[/tex]

Answer:

Both (B) and (C) are correct

Step-by-step explanation:

Explaining in simple terms, The Simpson's paradox simply describes a phenomenon which occurs when observable trends in a relationship, which are obvious during singular evaluation of the variables disappears when each of this relationships are combined. This is what played out when hitmire appears to d well on both of natyraknamd artificial turf when separately compared, but isn't the same when the turf data was combined. Also, performance may actually not be related to the turf as turf may Just be. a lurking variable causing a spurious association in performance.

Answer:

6 rides

Step-by-step explanation:

3r+5<25

3r<20

r<6.67

rides=6

check answer

3r+5<25

3(6)+5<25

18+5<25

23<25

Answer:

A.-10 should be the answer to the question..

The rational expression is zero at x = -10.

The ratio of two polynomials is known as a rational expression.

The given rational expression can equate to zero

[tex]\frac{20+2X}{5-X} =0[/tex]

Then, 20+2x=0

Therefore, x = (-20/2) = -10.

At x = -10, the given rational expression is zero.

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Answer:

.50r + 2p

Step-by-step explanation:

cost of ruler * number of rules  + cost of pens * number of pens

.50 *r + 2 *p

.50r + 2p