Answer:
B
Explanation:
A soil test recommends applying 193 lbs N per acre. Using a 36-6-18 fertilizer, how much fertilizer is needed to meet the recommendation? Round your answer to nearest whole number.
The mass of 36-6-18 fertilizer fertilizer required is 536 lb.
What mass of nitrogen fertilizer is required for the acre of land?The mass of nitrogen fertilizer required for the acre of land is determined as follows:
Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.
Mass of Nitrogen required per acre = 193 lbs
Mass of fertilizer required = 193 * 100/36
Mass of fertilizer required = 536 lb of fertilizer.
In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.
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Baking soda (NaHCO3) can be added to a fruit mix solution to create a carbonated drink. An example is the reaction between baking soda and citric acid below.
C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2
a. What is the molar mass of citric acid (C6H8O7) and baking soda (NaHCO3)?
b. How many milliliters of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda?
I already have a done I just need b.
74.4 mL of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda.
Equation that demonstrates reaction;
C6H8O7 + 3NaHCO3 → Na3C6H5O7 + 3H2O + 3CO2
Molar mass of citric acid (C6H8O7) = 12×6 + 1.008×8 + 16×7
= 192.064 g/mol
Molar mass of baking soda (NaHCO3) = 23 + 1 + 12 + 3×16
= 84 g/mol
[tex]^c C_6H_8O_7 = 0.8 M = 0.8 mol/L\\^m NaHCO_3 =15g[/tex]
From the reaction equation:
[tex]3[/tex] × [tex]^n C_6H_8O_7 = ^n NaHCO_3[/tex]
Molar mass of baking soda (NaHCO3) = 84 g/mol
So,
[tex]^n NaHCO_3 = ^m NaHCO_3/ ^MNaHCO_3[/tex]
And;
[tex]^n C_6H_8O_7 = ^nNaHCO_3/ 3[/tex]
From the definition of Molarity,
[tex]^V C_6H_8O_7 =\frac{^n C_6H_8O_7}{^cC_6H_8O_7 } =\frac{^n NaHCO_3}{^3*n^cC_6H_8O_7 } = \frac{^m NaHCO_3 / ^M NaHCO^3}{3*^cC_6H_8O_7 }[/tex]
Calculating;
[tex]^V C_6H_8O_7 = \frac{15/84}{3*0.8} \\[/tex]
[tex]= 0.0744L\\= 74.4 mL[/tex]
Therefore, 74.4 mL of a 0.8 M solution of citric acid would be needed to react with 15 grams of baking soda.
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27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
How to find the mass of solute ?Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]
= [tex]\frac{508.64}{100}[/tex]
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
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What is the molar mass of an unknown gas
with a density of 4.95 g/L at 1.00 atm and
25.0 °C?
Answer:
121 g/mol
Explanation:
To find the molar mass, you first need to calculate the number of moles. For this, you need to use the Ideal Gas Law. The equation looks like this:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = constant (0.0821 L*atm/mol*K)
-----> T = temperature (K)
Because density is comparing the mass per 1 liter, I am assuming that the system has a volume of 1 L. Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.
P = 1.00 atm R = 0.0821 L*atm/mol*K
V = 1.00 L T = 25.0. °C + 273.15 = 298.15 K
n = ? moles
PV = nRT
(1.00 atm)(1.00L) = n(0.0821 L*atm/mol*K)(298.15 K)
1.00 = n(0.0821 L*atm/mol*K)(298.15 K)
1.00 = (24.478115)n
0.0409 = n
Now, we need to find the molar mass using the number of moles per liter (calculated) and the density.
0.0409 moles ? grams 4.95 grams
---------------------- x ------------------ = ------------------
1 L 1 mole 1 L
? g/mol = 121 g/mol
**note: I am not 100% confident on this answer
which best describes the source of radiation heat
A.two molecules colliding with each other
B.Objects having kinetic energy because of their motion
C.Liquid or gas circulating to move the heat
D.The Sun sending out electromagnetic waves
The sun sending out electromagnetic waves is best describes the source of radiation heat.
Radiation heat is the form of electromagnetic waves.
Radiation heat, commonly referred to as thermal radiation, is the electromagnetic radiation that defines how photons exchange heat. The technique of heat transfer known as radiant heat does not require a medium to be propagated in.
Two molecules colliding with each other produce kinetic energy, moving objects have kinetic energy. Radiation heat is thermal energy. Sun directly sends thermal radiation through electromagnetic waves.
Hence , The sun sends out electromagnetic waves directly is best describes the source of radiation heat.
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The solubility of the ionic compound MX3, having a molar mass of 288 g/mol, is 3.60 x 10-2 g/L. Calculate the KSP of the compound.
[tex]K_{sp}[/tex] of the compound is found to be 5.04 ×[tex]10^{-10}[/tex].
Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.
Solubility equilibrium
Ksp = [tex][A^{+} ]^{a}[/tex] [tex][B^{-} ]^{b}[/tex]
Ksp = solubility product constant
A+ = cation in an aquious solution
B- = anion in an aqueous solution
a, b = relative concentrations of a and b
Given,
Solubility = s = 3.60 × [tex]10^{-2}[/tex] g/L
molar mass = 288 g/ mol
∴ s= 3.60 × [tex]10^{-2}[/tex] g/L ÷ 288 g/ mol = 1.25 ×[tex]10^{-4}[/tex] mol/ L
Reaction:
MX3 ⇄ M + 3X
s 3s
[tex]K_{sp}[/tex] =[ [tex]M^{+3}[/tex]] [ [tex]X^{-1}[/tex][tex]]^{3}[/tex] = solubility product
∴ [tex]K_{sp}[/tex] =[tex][s]^{} [3s]^{3}[/tex]
∴ [tex]K_{sp}[/tex] = 3 [tex]s^{4}[/tex]
∴ [tex]K_{sp}[/tex] = 3 × (3.60 × [tex]10^{-2}[/tex] [tex])^{4}[/tex]
∴ [tex]K_{sp}[/tex] = 503.8848 ×[tex]10^{-8}[/tex] = 5.04 ×[tex]10^{-10}[/tex]
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I need help with my work
Answer:
2 the mass is greater than 10.0gram
Explanation:
2 the mass is greater than 10.0gram
What is the [H3O+] if the [OH-] is 1 x 10 -8?
From the calculation, the concentration of the oxonium ions is 1 * 10^-6 M
What is concentration?The term concentration refers to the amount of substances present in the solution. There are several units that can be used to show the concertation of a substances such as moles/liter, gram per liter, parts per billion, parts per billion, percentage etc.
Now we know that water is composed of the hydrogen and the hydroxide ions and the product of the both is generally known as the ion product of water and have a value of 1 * 10^-14.
If that be the case, we are in order to write the expression;
[H3O+] [OH-] = 1 * 10^-14
[H3O+] = 1 * 10^-14/ [OH-]
[H3O+] = 1 * 10^-14/ 1 x 10^ -8
[H3O+] = 1 * 10^-6 M
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A sample of flammable liquid is placed into an enclosed cylinder which is then fitted with a movable piston. Initially the cylinder maintains a volume of 1.7 L. The sample is ignited producing gas and releasing 439.6 J of energy. To what volume will the cylinder expand to if it must expand against a pressure of 738.52 mmHg. Assume all the energy released is converted to work used to push the piston? Answer to 1 decimal space.
Cylinder will expand to 6.08 Lit by assuming that all the energy released is converted to work used to push the piston.
Concept of work :If we apply force on an object and if the object moves and changes it's position, then product of the force and the displacement of an object in the direction of applied force is called work.
Given,
Pressure= P= 738.52 mm Hg = 0.97 atm. (∵ 760 mm Hg = 1 atm)
Initial volume =V1= 1.7 L
Work done = W = 439.6 J
As we need our answer in litters ..
let's convert the work done into suitable units
∴work done = W = 4.26 L-atm (∵ 1 J = 101.3 L-atm)
As given all the energy is assumed to converted into work so we need not to worry About heat loss or entropy.
work done = pressure * difference in volume
W = PΔV
ΔV = 4.26÷ 0.97
∴ΔV = 4.38 LIt
There for, the volume expanded = 4.38 Lit
So, total volume = 4.38+ 1.7 = 6.08 Lit.
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pls help i need this ASAP
Answer:
a. 54 calories burnt
b. multiplied by 9
1. A 4.0-g sample of glass was heated from 274K to 314 K. a temperature increase of 40 K, and was
found to have absorbed 32J of energy as heat.
a. What is the specific heat of this type of glass?
b. How much energy will the same glass sample gain when it is heated from 314 K to 344 K?
Answer:
See below
Explanation:
Q = m c T c = specific heat T = temp change Q = heat joules
32 = 4 c 40 c = .2 J/g-C
314 to 344 k is a change of 30 K
Q = m c T
= 4 * .2 * 30 = 24 Joules
Answer:
(a) 0.2 J/g°K
(b) 24 J
Explanation:
(a)
To find the specific heat capacity, you need to use the following equation:
Q = mcΔT
In this formula,
-----> Q = heat energy (J)
-----> m = mass (g)
-----> c = specific heat capacity (J/g°K)
-----> ΔT = change in temperature (K)
You can plug the given values into the equations and simplify to find the missing value.
Q = 32 J c = ? J/g°K
m = 4.0 g ΔT = 40 K
Q = mcΔT <----- Equation
32 J = (4.0 g) x c x (40 K) <----- Insert variables
32 J = (160) x c <----- Multiply 4.0 and 40
0.2 = c <----- Divide both sides by 160
(b)
To find the energy of the same sample, you can use the same equation. This time, you know the specific heat capacity, have a different change in temperature, and are solving for energy (Q).
Q = ? J c = 0.2 J/g°K
m = 4.0 g ΔT = 344 K - 314 K = 30 K
Q = mcΔT <----- Given equation
Q = (4.0 g)(0.2 J/g°K)(30 K) <----- Insert values
Q = 24 <----- Multiply
When ATP breaks down to ADP, potential energy stored in bonds is released. This energy stored in bonds is
What is the initial volume, in milliliters, needed to prepare each of the following diluted solutions? 330mL of 7.5% (m/v) HCl from 17% (m/v) HCl
Taking into account the definition of dilution, the initial volume needed to prepare each of the diluted solution is 145.59 mL.
DilutionWhen it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.
Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.
In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
A dilution is mathematically expressed as:
Ci×Vi = Cf×Vf
where
Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volumeFinal volumeIn this case, you know:
Ci= 17% (m/v)Vi= ?Cf= 7.5% (m/v)Vf= 330 mLReplacing in the definition of dilution:
17% (m/v)× Vi= 7.5% (m/v)× 330 mL
Solving:
Vi= (7.5% (m/v)× 330 mL)÷ 17% (m/v)
Vi= 145.59 mL
In summary, the initial volume needed to prepare each of the diluted solution is 145.59 mL.
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2NaN3 → 2Na + 3N2. Calculate the mass of sodium azide required to decompose and produce the number of moles of nitrogen you calculated to get 0.016
The mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.
How to calculate number of moles?The number of moles of a substance can be calculated stoichiometrically as follows:
According to this question, sodium azide decomposes to produce sodium and nitrogen gas as follows:
2NaN3 → 2Na + 3N2
2 moles of sodium azide produces 3 moles of N2
This means that 0.016 moles of N2 will be produced by 0.016 × 2/3 = 0.011moles of NaN3.
Therefore, the mass of sodium azide required to decompose and produce the number of moles of nitrogen calculated to get 0.016 is 0.011moles.
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PLEASE HELP!!!
A sample of xenon occupies a volume of 715 mL at 8.01 atm and 67 °C. If the volume is changed to 963 mL and the temperature is changed to 52 °C, what will
be the new pressure?
Answer:
4.62 atm
Explanation:
To find the missing pressure, you need to use the Combined Gas Law equation:
P₁V₁ / T₁ = P₂V₂ / T₂
In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the final pressure, volume, and temperature.
P₁ = 8.01 atm P₁ = ? atm
V₁ = 715 mL V₁ = 963 mL
T₁ = 67 °C T₁ = 52 °C
P₁V₁ / T₁ = P₂V₂ / T₂
(8.01 atm)(715 mL) / 67 °C = P₂(963 mL) / 52 °C
85.47985 = P₂(963 mL) / 52 °C
4444.952 = P₂(936 mL)
4.62 atm = P₂
The volume of a sample of gas (4.32 g) was 752 mL at 1.98 ATM and 62°C. The gas is
Answer:
Bromine
Explanation:
To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol *K)
-----> T = temperature (K)
After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.
P = 1.98 atm R = 0.08206 atm*L/mol *K
V = 752 mL / 1,000 = 0.752 L T = 62 °C + 273.15 = 335.15 K
n = ? moles
PV = nRT
(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)
1.48896 = n(27.5024)
0.0541 = n
You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.
Molar Mass = mass / moles
Molar Mass = 4.32 g / 0.0541 moles
Molar Mass = 79.8 g/mol
This molar mass is closest to the molar mass of bromine (79.904 g/mol).
Can someone please help me with this question also explain the answers I am so confused thank you.
The theoretical yield of H₂S is 13.5 g.
The percent yield is 75.5 %.
What is the theoretical yield of H₂S from the reaction?The equation of the reaction is given below:
FeS + 2 HCl → FeCl₂+ H₂SMoles of FeS reacting = mass/molar mass
Molar mass of FeS = 88 g/mol
Moles of FeS reacting = 35/88 = 0.398 moles
Moles of H₂S produced = 0.398 moles
Molar mass of H₂S = 34 g/mol
Mass of H₂S produced = 0.398 * 34 = 13.5 g
Theoretical yield of H₂S is 13.5 g.
Percent yield = actual yield/theoretical yield * 100%Actual yield of H₂S = 10.2 g
Percent yield = 10.2/13.5 * 100%
Percent yield = 75.5 %
In conclusion, the actual yield is less than the theoretical yield.
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You need to calculate the enthalpy change (AH) of the reaction A + 2B → C.
How can the enthalpies given for the reaction steps below be combined to
give the overall change in enthalpy?
D+B
D+3B
A. AH = AH2-A H₁
B. AH=2AH₁+AH²₂
OC. AH AH ₁ +AH²₂
D. AH = A H₁-AH₂
A
C
A
AH°,
A Hº
The enthalpy change of the reaction: A + 2B → C is determined as follows: ΔH = ΔH₁ + ΔH₂; option C
What is enthalpy change?Enthalpy change refers to the change in heat content as reactant molecules combine to form products.
The enthalpy change of a multistep reaction is calculated from by summing the enthalpy changes of the intermediate steps that leads to the overall reaction.
Thus, the enthalpy change of the reaction: A + 2B → C is determined as follows:
ΔH = ΔH₁ + ΔH₂
In conclusion, the enthalpy change of the reaction is determined from the summation of the enthalpy changes that occur in the intermediate steps.
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Fill in the chart below to identify the properties of shape and volume for each type of matter. Shape Volume Solid Liquid Gas
The properties are given below:
Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volumeWhat are the properties of solids, liquids and gases?The property of solids, liquids, and gases refers to those features which are used to identify solids, liquids and gases.
Some property of solids, liquids and gases are shape and volume.
Shape: Solids have definite shape; liquids take the shape of their container; gases have no shape.
Volume: Solids have definite volume; liquids have definite volume; gases do not have a definite volume
In conclusion, solids, liquids and gases have unique properties in their shape and volume.
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Do the following statement describe physical or chemical property!
Uranium is a radioactive element
9. Predict the full Robinson Annulation product (including all intermediates) and 10. Show the stepwise mechanism for the following reaction.
4.50 moles of glucose in 3.50 L of a glucose solution
Answer:
Molarity = 1.28
Explanation:
[tex]m= n/v[/tex]
M = molar concentration
n = moles of solute
v = liters of solution
Molarity = moles of solute / litres of solution.
]
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Question 9
What pressure will be exerted by 15 g of carbon dioxide gas in a 20 L container at 0 °C?
Answer:
0.382 atm
Explanation:
In order to find the pressure, you need to know the moles of carbon dioxide (CO₂) gas. This can be found by multiplying the mass (g) by the molar mass (g/mol) of CO₂. It is important to arrange the conversion in a way that allows for the cancellation of units.
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
15 grams CO₂ 1 mole
---------------------- x ------------------------ = 0.341 moles CO₂
44.007 grams
To find the pressure, you need to use the Ideal Gas Law equation.
PV = nRT
In this equation,
-----> P = pressure (atm)
-----> V = volume (L)
-----> n = moles
-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)
-----> T = temperature (K)
After you convert Celsius to Kelvin, you can plug the given and calculated values into the equation and simplify to find the pressure.
P = ? atm R = 0.08206 atm*L/mol*K
V = 20 L T = 0 °C + 273.15 = 273.15 K
n = 0.341 moles
PV = nRT
P(20 L) = (0.341 moles)(0.08206 atm*L/mol*K)(273.15 K)
P(20 L) = 7.64016
P = 0.382 atm
For each pair of molecules given in the table below, identify the correct relationship.
For each pair of molecules given in the table below, the correct relationships are identified as follows.
The relationships between the molecules are given as?These are structural isomers. This is because, they have the same molecular formula (C₆H₁₂) but possess varying structures.The given pair of molecules posses similar formula (C₄H₁₀O) and can be superimposed on one another via rotation of the entire molecule, hence they are identical isomers.In this case the pair of molecules possess similar molecular formula (C₄H₁₀O) and similar arrangement of atoms. Hence, they are identical isomers.This case also features structural isomers. They both contain the same carbon chain with similar formula - C₃H₆BrClThese pair as identical isomers. They are also derived from C₃H₆BrCl.This pair are called stereoisomers isomers. This is because they contain the same about of molecules but are different in the position of the alcohol (-OH) group. But more importantly, the position of the bonding is the same.This set is a functional pair. This is because the composition of the molecules present in each case are different.This is also a functional pair.What is a molecules?A molecule is a bonded collection of atoms that represents the smallest fundamental unit of a chemical compound that may participate in a chemical process.
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which celsius temperature is equal to 298k
Answer:
298-273 = 25°C is correct answer!
6. Which of the following is an electrical hazard?
OA. A machine without guards in place
OB. A welding cylinder without a safety cap
OC. A broken ground post on a plug
O D. An ingoing nip point
+
Using the balanced equation below.
how many grams of cesium fluoride
would be required to make 73.1 g
of
cesium xenon heptafluoride?
CSF + XeF6 - CsXeF7
A
Answer:
28.0 grams CsF
Explanation:
To find the mass of CsF, you need to (1) convert grams CsXeF₇ to moles CsXeF₇ (via molar mass), then (2) convert moles CsXeF₇ to moles CsF (via mole-to-mole ratio from equation coefficients), and then (3) convert moles CsF to grams CsF (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Molar Mass (CsF): 132.91 g/mol + 18.998 g/mol
Molar Mass (CsF): 151.908 g/mol
Molar Mass (CsXeF₇): 132.91 g/mol + 131.29 g/mol + 7(18.998 g/mol)
Molar Mass (CsXeF₇): 397.186 g/mol
1 CsF + XeF₆ -----> 1 CsXeF₇
73.1 g CsXeF₇ 1 mole 1 mole CsF 151.908 g
---------------------- x -------------------- x ------------------------ x ------------------ =
397.186 g 1 mole CsXeF₇ 1 mole
= 27.958 g CsF
= 28.0 g CsF
What is an orbital in chemistry
A mathematical function known as an orbital is used to describe the wave-like behavior of an electron, an electron pair, or (less frequently) nucleons.
Atomic orbitals outline the potential locations of electrons within an atom. In molecules, molecular orbitals play the same function.
Each atomic orbital has three quantum numbers, n, l, and ml, attached to it. The wave function was used to calculate these numbers.
The square of the wave function 2 can be used to calculate the size and form of an orbital.
All atomic orbitals are centered on the atomic nucleus and have unique forms.
The s, p, and d orbitals—orbitals that correspond to the s, p, and d subshells—are the orbitals that are most frequently encountered in introductory quantum chemistry.
F orbitals can be found in the ground states of heavier atoms as well.
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Answer:
In chemistry, an orbital is related to also a wave function. An Orbital is a practical region or part that is around the nucleus in a molecule and maybe an atom. It can contain up to two electrons, electrons form themselves around the nucleus.
Explanation:
No Explanation
1. Consider the unbalanced equation:
Mg (s) + HCl (aq) ---> MgCl2 (s) + H2 (g)
If 4.59 mol of Mg and 4.59 mol of HCl are reacted, how many moles of MgCl2 are produced?
Hint: Write the balanced equation first.
Answer:
2.30 moles MgCl₂
Explanation:
First, you need to balance the chemical equation. An equation is balanced when there is an equal amount of each element on both sides of the reaction. These values can be modified by adding coefficients in front of the molecules.
The unbalanced equation:
Mg (s) + HCl (aq) ---> MgCl₂ (s) + H₂ (g)
Reactants: 1 magnesium, 1 hydrogen, 1 chlorine
Products: 1 magnesium, 2 hydrogen, 2 chlorine
The balanced equation:
Mg (s) + 2 HCl (aq) ---> MgCl₂ (s) + H₂ (g)
Reactants: 1 magnesium, 2 hydrogen, 2 chlorine
Products: 1 magnesium, 2 hydrogen, 2 chlorine
Now, you need to use the mole-to-mole ratios from the balanced equation to convert between moles. Since we were not given a limiting reactant, the easiest way to find the actual moles of MgCl₂ is to start from both reactants.
4.59 moles Mg 1 mole MgCl₂
------------------------- x ------------------------ = 4.59 moles MgCl₂
1 mole Mg
4.59 moles HCl 1 mole MgCl₂
------------------------- x ------------------------ = 2.30 moles MgCl₂
2 moles HCl
Since HCl produces the smaller amount of product, it must be the limiting reactant. In other words, HCl runs out before all of the Mg is completely used up. Therefore, the actual amount of MgCl₂ produced in 2.30 moles.
27.2 kg of a solution containing 18.7 % KCl by mass
Express your answer in kilograms using three significant figures.
The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
How to find the mass of solute ?Mass of solute = Mass percent of solute x Mass of the solution
Here,
Mass percent of solute = 18.7 %
Mass of the solution = 27.2 kg
Now put the value in above formula we get
Mass of solute = Mass percent of solute x Mass of the solution
= [tex]\frac{18.7}{100} \times 27.2\ kg[/tex]
= [tex]\frac{508.64}{100}[/tex]
= 5.086
Thus from the above conclusion we can say that The amount of potassium chloride (KCl) in 27.2 kg of a solution containing 18.7% KCl by mass solution is 5.086 kg.
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