The probability of having exactly 10 samples succeed from a binomial random variable, given a sample size of 20 and a probability of success of 51%, is 0.1011.
To calculate this, we can use the Binomial Probability formula:
P(x;n,p) = (n!/(x!*(n-x)!) * px * qn-x)
where P(x;n,p) is the probability of x successes in n trials with probability p, and q is the probability of failure, equal to 1-p.
In this case, x = 10, n = 20, and p = 0.51, so q = 0.49. Plugging these values into the formula, we get:
P(10;20,0.51) = (20!/(10!*10!) * 0.5110 * 0.4910) = 0.1011
Therefore, the probability of having exactly 10 successes is 0.1011.
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Two students record the distance they each traveled in 60 seconds in the data table shown.
The correct statement is: Student 1 traveled 60 meters, and student 2 traveled 30 meters.
Calculate the speed of each student:
Student 1: 40 meters / 60 seconds = 0.67 meters per second
Student 2: 20 meters / 60 seconds = 0.33 meters per second
Use the speed to calculate the distance each student would travel in 90 seconds:
Student 1: 0.67 meters per second × 90 seconds = 60 meters
Student 2: 0.33 meters per second × 90 seconds = 30 meters
Therefore, the correct statement is: Student 1 traveled 60 meters, and student 2 traveled 30 meters.
What is speed?
Speed is a measure of how fast an object is moving. It is defined as the distance traveled by an object per unit of time, usually expressed in meters per second (m/s) or kilometers per hour (km/h).
The formula for calculating speed is:
Speed = Distance / Time
Where distance is the distance traveled by the object, and time is the duration of the travel.
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you should change lanes only when there is sufficient space between vehicles in the next lane and by allowing a gap of at least how many seconds?
When changing lanes, it is recommended to allow a gap of at least 3 seconds between your vehicle and the vehicle in front of you before merging into the next lane.
A gap refers to a region of space or energy where there is a discontinuity or absence of a physical quantity. This can manifest in several ways, depending on the context in which the term is used. In general, gaps in physics can represent areas of uncertainty or incompleteness in our understanding of the natural world and can provide important clues for future research and discovery.
One common example of a gap in physics is the band gap in solid-state materials, which refers to the range of energies where electrons cannot exist due to the nature of the material's electronic structure. This gap affects the electrical conductivity and optical properties of the material and is important in the design of electronic devices like solar cells and transistors.
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write an expression for the focal length of the glasses which will allow her to see distant objects clearly.
A. The expression for the focal length of the glasses is 1/f = 1/do + 1/di. B. The focal length of the glasses that will allow the nearsighted person to see distant objects is 46 meters.
How did we get the value?(a) To find the focal length of the glasses that will allow the nearsighted person to see distant objects clearly, we can use the formula:
1/f = 1/do + 1/di
where f is the focal length, do is the distance of the far point (in meters), and di is the distance of the image formed by the glasses (in meters). We want the person to be able to see distant objects clearly, so di should be at infinity. Therefore, the equation becomes:
1/f = 1/do + 1/infinity
1/f = 1/do
Solving for f, we get:
f = do
Substituting the given value of do, we get:
f = -46 m
However, the focal length should be a positive value, so we take the absolute value of f, which gives:
f = 46 m
(b) Numerically, the focal length of the glasses is 46 meters.
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The complete question goes thus:
A person who is nearsighted has a far point of do-46 m. She wears glasses that are designed to sit d = 2.7 cm rom her eyes Randomized Variables do-4.6 m d-2.7 cm > 50% Part (a) Write an expression for the focal length of the glasses which will allow her to see distant objects clearly Grade Summa Deductions Potential ry 0% 100% Submissions Attempts remaining: 35 (5% per attempt) detailed view END DELI CLEAR Submit Hint I give up! Hints: 200 deduction per hint. Hints remaining: 5 Feedback: 296 deduction per feedback. là 50% Part (b) Numerically, what is the focal length in m?
A truck is moving at constant velocity. Inside the storage compartment, a rock is dropped from the midpoint of the ceiling and strikes the floor below.
The rock hits the floor
A) exactly below the midpoint of the ceiling.
B) ahead of the midpoint of the ceiling.
C) behind the midpoint of the ceiling.
D) More information is needed to solve this problem.
E) none of these
When a truck is moving at constant velocity, and a rock is dropped from the midpoint of the ceiling and strikes the floor below, the rock hits the floor at exactly below the midpoint of the ceiling. The correct option is (A) exactly below the midpoint of the ceiling.
When a rock is dropped from the midpoint of the ceiling of a moving truck, the rock strikes the ground at exactly below the midpoint of the ceiling of the moving truck. This is because of the following reason:
When a truck is moving at constant velocity, everything in it is also moving at a constant velocity relative to the earth, including the rock. Hence, the rock will continue to move forward at the same velocity as the truck. It is said that the rock has the same horizontal velocity as that of the truck.
Now when the rock is dropped, the force of gravity pulls the rock towards the earth. Due to this force of gravity, the rock falls vertically towards the earth. Since the rock has the same horizontal velocity as that of the truck, it falls vertically downwards but continues to move forward along with the truck.
Hence, the rock strikes the ground at exactly below the midpoint of the ceiling of the moving truck. Therefore, the correct answer is option (A).
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Given the information you have learned in class and the material in your lab manual, answer the following question: Which of these investigations could NOT be addressed using gel electophoresis? Checking for genomic DNA contamination and purity of samples Examining the expression of genes in different individuals. Determining the DNA fingerprint of the suspect of a crime. Determining the paternity of a child.
There is no investigation among the given options that cannot be addressed using gel electrophoresis.
Gel electrophoresis is a common laboratory technique used to separate and analyze DNA, RNA, and proteins based on their size, charge, and other properties. It is widely used in various fields of research, including forensic science, genetics, and biotechnology. Gel electrophoresis can be used to detect DNA contamination, analyze gene expression, determine DNA fingerprinting, and establish paternity testing. Therefore, all the investigations listed, including checking for genomic DNA contamination and purity of samples, examining gene expression, determining DNA fingerprint, and paternity testing can be addressed using gel electrophoresis.
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What is the speed of the elevator after it has moved downward 1.00 from the point where it first contacts a spring?
When the elevator is 1.00 below point where it first contacts a spring, what is its acceleration?
The speed of the elevator after it has moved downward 1.00 from the point where it first contacts a spring is 2.23 m/s.
The acceleration of the elevator when it is 1.00 below the point where it first contacts a spring is -9.8 m/s².
The speed of the elevator after it has moved downward 1.00 from the point where it first contacts a spring is 2.23 m/s. When the elevator is 1.00 below the point where it first contacts a spring, its acceleration is -9.8 m/s². This is because the elevator is moving downwards and accelerating due to gravity.
To solve for the speed of the elevator after it has moved downward 1.00 from the point where it first contacts a spring, we need to use the formula for potential energy and kinetic energy:
Potential Energy (PE) = Kinetic Energy (KE)
mgh = 1/2 mv²
where m is the mass of the elevator, g is the acceleration due to gravity, h is the height, and v is the velocity.
Rearranging the formula, we get:
v = √(2gh)
Substituting the given values, we get:
v = √(2 × 9.8 × 1) = 2.23 m/s
To solve for the acceleration of the elevator when it is 1.00 below the point where it first contacts a spring, we simply use the acceleration due to gravity which is -9.8 m/s². The negative sign indicates that the acceleration is directed downwards.
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The planet Earth orbits around the Sun and also spins around its own axis 33% Part (a) Calculate the angular momentum of the Earth in its orbit around the Sun in kg m?/s Lorb 2.76 1040 Lorb 2.76E-40 X Attempts Remain 33% Part (b) Calculate the angular momentum of the Earth spining On its axs kg"m /s 33% Part (c) How many times larger is the angular momentum of the Earth in its orbit than the angular momentum of the Earth around its axis? Grade Summary Lorb Deductions 000
To calculate the angular momentum of the Earth in its orbit around the Sun, we use the formula:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
The moment of inertia of the Earth in its orbit around the Sun can be approximated as a point mass at the center of the orbit, so we have:
I = mr^2
where m is the mass of the Earth, and r is the radius of its orbit around the Sun.
The angular velocity of the Earth in its orbit around the Sun can be calculated as:
ω = v/r
where v is the velocity of the Earth in its orbit around the Sun.
Using the values of the mass of the Earth (m = 5.97 × 10^24 kg), the radius of its orbit around the Sun (r = 1.50 × 10^11 m), and the velocity of the Earth in its orbit around the Sun (v = 2.98 × 10^4 m/s), we have:
I = (5.97 × 10^24 kg) (1.50 × 10^11 m)^2 = 1.08 × 10^40 kg m^2
ω = (2.98 × 10^4 m/s) / (1.50 × 10^11 m) = 1.99 × 10^-7 rad/s
Therefore, the angular momentum of the Earth in its orbit around the Sun is:
L = Iω = (1.08 × 10^40 kg m^2) (1.99 × 10^-7 rad/s) = 2.15 × 10^33 kg m^2/s
What is the angular momentum of the Earth spining On its axs kg"m /s 33% Part?To calculate the angular momentum of the Earth spinning on its own axis, we use the same formula:
L = Iω
where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
The moment of inertia of the Earth spinning on its own axis can be approximated as a solid sphere, so we have:
I = (2/5)mr^2
where m is the mass of the Earth, and r is the radius of the Earth.
The angular velocity of the Earth spinning on its own axis is:
ω = 2π/T
where T is the period of rotation of the Earth.
Using the values of the mass of the Earth (m = 5.97 × 10^24 kg), the radius of the Earth (r = 6.37 × 10^6 m), and the period of rotation of the Earth (T = 24 hours = 8.64 × 10^4 s), we have:
I = (2/5) (5.97 × 10^24 kg) (6.37 × 10^6 m)^2 = 8.03 × 10^37 kg m^2
ω = 2π / (8.64 × 10^4 s) = 7.27 × 10^-5 rad/s
Therefore, the angular momentum of the Earth spinning on its own axis is:
L = Iω = (8.03 × 10^37 kg m^2) (7.27 × 10^-5 rad/s) = 5.84 × 10^33 kg m^2/s
The angular momentum of the Earth in its orbit around the Sun is approximately 2.76 × 10^40 kg m^2/s, and the angular momentum of the Earth spinning on its axis is approximately 7.06 × 10^33 kg m^2/s.
To find out how many times larger the angular momentum of the Earth in its orbit is compared to the angular momentum of the Earth spinning on its axis, we can simply divide the value obtained in part (a) by the value obtained in part (b):
2.76 × 10^40 kg m^2/s ÷ 7.06 × 10^33 kg m^2/s ≈ 3.91 × 10^6
Therefore, the angular momentum of the Earth in its orbit around the Sun is approximately 3.91 million times larger than the angular momentum of the Earth spinning on its axis.
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find the net force on a 30.0 nc charge located at the origin by two other charges. one is -50.0 nc located at (-4.0 m, 2.0 m) and 40.0 nc located at (3.0 m, 3.0 m).
The net force on a 30.0 NC charge located at the origin by two other charges is 43.72 N.
First, we need to calculate the force between the charge at the origin and the charge at (-4.0 m, 2.0 m)F₁ = k.q₁.q₂/r²
Here, q₁ = 30 NC, q₂ = -50 NC, and r = √(4² + 2²) = √20F₁ = k.q₁.q₂/r² = 9 × 10⁹.30.(-50)/(√20)² = -27.71 N
Since the charge at (-4.0 m, 2.0 m) is negative, the force is negative.
Next, we need to calculate the force between the charge at the origin and the charge at
(3.0 m, 3.0 m).F₂ = k.q₁.q₂/r²
Here, q₁ = 30 NC, q₂ = 40 NC, and r = √(3² + 3²) = √18F₂ = k.q₁.q₂/r² = 9 × 10⁹.30.40/(√18)² = 71.43 N
Since the charge at (3.0 m, 3.0 m) is positive, the force is positive.
The net force is given by the vector sum of the forces: F_net = F₁ + F₂ = -27.71 + 71.43 = 43.72 N
Therefore, the net force on a 30.0 NC charge located at the origin by two other charges, one is -50.0 NC located at (-4.0 m, 2.0 m) and 40.0 NC located at (3.0 m, 3.0 m) is 43.72 N.
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In the development of throwing, trunk rotation in which the lower trunk and upper trunk rotate together, as a unit, is called ____________ rotation.
In the development of throwing, trunk rotation in which the lower trunk and upper trunk rotate together, as a unit, is called blocked rotation.
Trunk rotation is a crucial part of body mechanics. Trunk rotation is a crucial element of many activities. It's crucial for sports that require rapid turning movements, such as baseball, golf, and soccer. The core muscles, including the lower back and abs, work together to rotate the torso to the right and left when you twist the trunk. When performing a throwing movement, trunk rotation is essential.
Blocked rotation is when the upper and lower trunk moves together as one unit during a throwing movement. The technique is known as a "block" because it appears as if the body is blocking the movement. This type of rotation, which is also known as linear or non-differentiated, is often used by beginners or athletes who haven't yet mastered the throwing motion. It's less common in seasoned athletes who have mastered throwing technique because it can reduce throwing distance and speed.
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a boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. the girl moves in a negative direction with a speed of 3 m/s. what is her momentum? a. 60 kgm/s b. -100 kgm/s c. -120 kgm/s d. 120 kgm/s
The momentum of the girl is -120 kgm/s in the direction opposite to the boy.
The momentum of an object is defined as the product of its mass and velocity. Since the girl moves in the negative direction, we can consider her velocity to be negative.
The momentum of the girl can be calculated as:
momentum = mass x velocity
momentum = 40 kg x (-3 m/s)
momentum = -120 kgm/s
Therefore, the momentum of the girl is -120 kgm/s.
Note that momentum is a vector quantity and has a direction, which in this case is negative because the girl moves in the opposite direction to the one considered positive.
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risks that can result in a system or process that will not work are known as
Risks that can result in a system or process that will not work are commonly known as "technical risks". These are risks that are related to the technical aspects of a system or process, such as hardware, software, or infrastructure.
Several things, including the following, can lead to technical risks: Complexity: Very complex systems and processes can be challenging to develop, implement, and maintain, as well as being more vulnerable to technical risks. Interdependencies: If one component fails or does not function properly, systems and processes that are extensively interconnected may be exposed to technical risks. Technical restrictions: Systems and procedures that must adhere to technical restrictions, such as those imposed by hardware or software, may be more vulnerable to technical risks. Technical hazards may be more likely to arise for systems and processes that must be integrated with other systems or processes if there are integration concerns.
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yoda is 500km above the surface of the earth. if yoda have a mass of 96kg, what speed must he have to stay in a circular orbit around the earth at that altitude.
Yoda must have a speed of approximately 7613.99 m/s to stay in a circular orbit around the Earth at an altitude of 500 km.
To stay in a circular orbit around the Earth at a certain altitude, an object must have a specific speed known as the orbital speed. The orbital speed is determined by the gravitational force between the object and the Earth, as well as the distance between them.
The formula for the orbital speed of an object in a circular orbit around the Earth is:
[tex]v = \sqrt{GM/r}[/tex]
where v is the orbital speed, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the object and the center of the Earth (in this case, the altitude of Yoda above the Earth's surface plus the radius of the Earth).
First, we need to convert the altitude of Yoda above the surface of the Earth to the distance between Yoda and the center of the Earth:
r = altitude + radius of Earth
r = 500 km + 6371 km
r = 6871 km
Now we can substitute the values into the formula:
[tex]v = \sqrt{GM/r}[/tex]
[tex]v = \sqrt{6.6743 \times 10^{-11} m^3 kg^{-1} s^{-2} \times 5.9722 \times 10^{24} kg / 6871000 m)[/tex]
v = 7613.99 m/s
Hence velocity should be 7613.99 m/s.
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A typical neutron star has a mass of about 1.5Msun and a radius of 10 kilometers Calculate the average density of a neutron star. Express your answer in kilograms per cubic centimeter to two significant figures.
The average density of the neutron star that has a mass of about 1.5Msun and a radius of 10 kilometers rounded off to two significant figures is 5.9 × 10¹⁴ kg/cm³
The average density of a neutron star can be calculated using the following formula;`d = (3M)/(4πr³)`where `d` is the average density of the neutron star, `M` is the mass of the neutron star, and `r` is the radius of the neutron star.Using the given values in the formula, we get;`d = (3 × 1.5 × 1.989 × 10³⁰)/(4π × (10 × 10³)³)` = 5.9 × 10¹⁷ kg/m³To convert kg/m³ to kg/cm³, we can use the following conversion factor;1 m³ = 10⁶ cm³Therefore,1 kg/m³ = 10⁻³ kg/cm³So, the average density of the neutron star in kg/cm³ is;`d = (5.9 × 10¹⁷) × (10⁻³)` = 5.9 × 10¹⁴ kg/cm³Therefore, the average density of the neutron star is 5.9 × 10¹⁴ kg/cm³ (rounded to two significant figures).Answer: 5.9 × 10¹⁴ kg/cm³.
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A within-subjects experiment with 30 volunteers is used to test the effect of light color on mood. The experiment has a single light bulb type with 3 different ambient color schemes. The experiment has 3 different rooms, each room with a different colored light bulb. Which of these is the factor in this experiment?
In this experiment, the factor is the ambient color schemes. In other words, the independent variable is the ambient color schemes.
What are ambient color Schemes?This means that the different colored light bulbs are the factor in the experiment. Three different rooms are used in the experiment and each room has a different colored light bulb.
A within-subjects experiment with 30 volunteers is being used to evaluate the impact of light color on mood. There is a single light bulb form used in the experiment with three different ambient color schemes.
Each room has a different colored light bulb, and there are three different rooms in the experiment. The factor in this experiment is the ambient color scheme because it is the independent variable.
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hello how are u today? whats up!!!!!!!!!!!!1
Answer:
good
Explanation:
i need help with physical sciences
describe (facts) how p and s-wave velocities change as they travel through the interior of the earth from about 0 to 3,000 km, at approximately 3,000 km, and then afterwards
While p-waves are the fastest-moving seismic waves and the first to be felt or recorded during an earthquake, their velocities alter as they go through the interior of the earth.
How do P and S waves traverse the Earth's strata and describe their characteristics?P waves can travel through fluids, solids, and gases, whereas S waves can only travel through solids. Scientists use this information to determine the makeup of the Earth.
What can P and S waves tell us about the interior of the Earth?Detailed Description. P-wave and S-wave routes through the earth. By studying seismic vibrations, scientists learned that the Earth's outer core is liquid. P waves can pass through both solid and liquid materials.
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Suppose you watch a leaf bobbing up and down as ripples pass it by in a pond. You notice that it does two full up and down bobs each second. Which statement is true of the ripples on the pond?
They have a frequency of 2 hertz.
The correct statement of the ripples on the pond is that they have a frequency of 2 hertz.
In physics, the number of cycles of a periodic wave that occur in a unit of time is known as the frequency of that wave. Its unit is hertz (Hz), which indicates cycles per second.A hertz is a unit of frequency that indicates how many times per second a wave oscillates. The amount of time it takes for one complete cycle of the wave is inversely proportional to its frequency. A wave with a high frequency oscillates more frequently than one with a low frequency.What is hertz (Hz)?Hertz (Hz) is the standard unit of frequency. One hertz (Hz) is equal to one cycle per second, meaning that a wave with a frequency of 2 Hz repeats twice in one second. Therefore, the frequency of the ripples on the pond is 2 hertz.
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for each charge, determine the direction of the magnetic force. for the last one, determine the direction of the magnetic field. the sign of the charge is given for each part.
For each charge, the direction of the magnetic force can be determined using the right-hand rule. For the last one, the direction of the magnetic field can be determined by observing the direction of the current.
The right-hand formula can be used to calculate the direction of the magnetic field for each charge. According to the formula, if you aim your right thumb in the direction of the charged particle's velocity and your fingers in the direction of the magnetic field, the way your hand confronts is the magnetic force direction.
To identify the direction of the magnetic field for the final charge, examine the direction of the current. The magnetic field is perpendicular to the current and can also be calculated with the right-hand formula.
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Is lead is melted I’m into liquid to form pellets a physical change
Yes, melting lead into a liquid to form pellets is a physical change.
This is because the chemical composition of lead remains the same even after it has been melted and then solidified into pellets. In other words, the molecular structure of lead does not change during the melting process, but only the physical state of the material changes from a solid to a liquid and then back to a solid. This type of change is reversible and can be undone by cooling the lead pellets to their solid state. Therefore, melting lead to form pellets is an example of a physical change rather than a chemical change.
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--The complete Question is, Is lead melting into liquid to form pellets a physical change? --
a 0.27-kg mass attached to a spring is pulled back horizontally across a table so that the potential energy of the system is increased from zero to 165 j. ignoring friction, what is the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j?
The kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j, ignoring friction, can be calculated using the equation KE = PEinitial - PEfinal, which states that the change in kinetic energy is equal to the change in potential energy. Therefore, the kinetic energy of the system is 165 J - 75 J = 90 J.
The kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 J is 46.12 J.How to calculate the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j?
The potential energy of the system is given by: PE = 1/2 k x^2 ………. (1)where PE is the potential energy, k is the spring constant, and x is the extension of the spring. The kinetic energy of the system is given by: KE = 1/2 m v^2 ……… (2)where KE is the kinetic energy, m is the mass, v is the velocity of the object from equation (1), the spring constant k is given as: k = 2PE / x^2 ………. (3)The extension of the spring is given as: x = √ (2PE / k) ………. (4)From equation (2), the velocity of the object is given as v = √ (2KE / m) ………. (5)Initial Potential Energy = 0 JFinal Potential Energy = 165 JPE = 165 JPE = 1/2 k x^2 ………. (1)0.27 kg mass attached to a springThe mass of the object is given as: m = 0.27 kgFrom equation (3):k = 2PE / x^2 = 2 x 165 / x^2From equation (4):x = √ (2PE / k) = √ (2 x 165 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 165 / (2 x 165 / x^2))x = √ (2 x 165 x^2 / 2 x 165)x = √ x^2x = x Final Potential Energy = 75 JPE = 1/2 k x^2 ………. (1)From equation (3):k = 2PE / x^2 = 2 x 75 / x^2From equation (4):x = √ (2PE / k) = √ (2 x 75 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 75 / (2 x 75 / x^2))x = √ (2 x 75 x^2 / 2 x 75)x = √ x^2x = xThe velocity of the object is given as:v = √ (2KE / m)From equation (1):165 J = 1/2 k x^2From equation (3):k = 2PE / x^2Substituting the values of k and PE in the above equation, we get:165 J = 1/2 (2 x 165 / x^2) x^2165 J = 165 JFrom equation (2):KE = 1/2 m v^2Substituting the values of m and v in the above equation, we get:KE = 1/2 x (0.27 kg) x v^2KE = 0.135 v^2 JFrom equation (4):x = √ (2 x 75 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 75 / (2 x 75 / x^2))x = √ (2 x 75 x^2 / 2 x 75)x = √ x^2x = xFrom equation (2):KE = 1/2 m v^2Substituting the values of m and v in the above equation, we get:KE = 1/2 x (0.27 kg) x v^2KE = 0.135 v^2 JFrom equation (5):v = √ (2KE / m)Substituting the values of KE and m in the above equation, we get:v = √ (2 x 46.12 / 0.27)Therefore, the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j is 46.12 J.
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The symbol EF represents the magnitude of the electric field at location F, and the symbol Ep represents the magnitude of the electric field at location D. Which of the following equations is a correct energy conservation (loop) equation for this circuit, following a path that starts at the positive end of the battery and goes clockwise? O o- 1.5 V- Ef 0.25 m ED 0.063 m - Ef 0.25 m 0+1.5 V- EF 0.25 m ED 0.063 m-Ef 0.25 m 1.5 V- EF .0.25 m 0+1.5EF 0.25 mED -0.063 mEf 0.25 m 0-1.5 VEf 0.25 m ED 0.063 mEf-0.25 m 1.5V- ED-0.063 m The symbol i represents the electron current at location F, etc. Which of the following equations is a correct charge conservation (node) equation for this circuit? Use the appropriate equation(s), plus the equation relating electron current to electric field, to solve for the factor that goes in the blank below: *ED Use the appropriate equation(s) to calculate the magnitude of ED ED Use the appropriate equation(s) to calculate the electron current at location D in the steady state: V/m
The correct energy conservation (loop) equation for this circuit is 1.5V - EF 0.25m + ED 0.063m - EF 0.25m + 1.5V - EF 0.25m + ED 0.063m - EF 0.25m + 1.5V - ED 0.063m = 0.
The correct charge conservation (node) equation is i + EF 0.25m - ED 0.063m = 0. To solve for the factor that goes in the blank, we can solve the charge conservation equation for ED: ED = i + EF 0.25m. Therefore, ED = V/m. To calculate the magnitude of ED, substitute the known values into the equation: ED = V/m = (1,5V + 0,25m . EF)/0,063m.
To calculate the electron current at location D in the steady state, substitute the known values into the charge conservation equation: i = ED - EF 0.25m = (V/m - 0.25m*EF).
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If the change in internal energy = 1714J, specific
heat capacity = 49J/°C/kg, and mass = 38kg,
what is the temperature change experienced?
Give your answer to 2 decimal places.
Answer:
0.92°C
Explanation:
C = change in Q/m × change in T
so
change in T = change in Q/C ×m
C= 49
m= 38
change in Q= 1714
then
= 1714/49 × 38
= 1714/1862
= 0.92°C
rounded off to 2 d.p
The velocity function, in feet per second, is given for a particle moving along a straight line. v(t) = t3 − 9t2 + 23t − 15, 1 ≤ t ≤ 6 (a) find the displacement. (b) find the total distance that the particle travels over the given interval.
a) The displacement of the particle is 390.25 ft
b) the total distance traveled by the particle over the given interval is 136.5 ft.
To find displacement, integrate the velocity function from the lower limit of 1 to the upper limit of 6. Mathematically, we have that displacement of the particle is given by,
Displacement = ∫v(t) dt …(1), From the information, the velocity function is given as:
v(t) = t³ - 9t² + 23t - 15
Integrating the above function w.r.t t gives us the displacement function as: Displacement function,
s(t) = ¼ t⁴ - 3t³ + 11.5t² - 15t.
Now, substituting the upper and lower limits of integration to the above displacement function gives us the displacement of the particle as;
Displacement = s(6) - s(1)= 384.5 - (-5.75)= 390.25 ft.
Therefore, the displacement of the particle is 390.25 ft.
To find the total distance that the particle travels, we integrate the absolute value of velocity function from the lower limit of 1 to the upper limit of 6. Mathematically, we have that the total distance that the particle travels is given by,
Total distance = ∫|v(t)| dt …(2)
From the given information, the velocity function is given as:
v(t) = t³ - 9t² + 23t - 15
To get the absolute value of the above function, we have;
|v(t)| = |t³ - 9t² + 23t - 15|
The function v(t) cuts the x-axis at the points (1, 0), (2.205, 0), (3.795, 0), and (6, 0). Therefore, the total distance traveled by the particle over the given interval is given by;
Total distance = ∫|v(t)| dt=∫¹ⁿ|t³ - 9t² + 23t - 15| dt …(3)
Where n = 2.205, 3.795, and 6. Breaking the integration in equation (3) into smaller intervals where v(t) is positive and negative and finding the area under the curve using definite integration method, we have;
∫¹².²⁰⁵ (t³ - 9t² + 23t - 15) dt - ∫².²⁰⁵¹ ¹ (t³ - 9t² + 23t - 15) dt
= 53.85 + 28.80 + 53.85 = 136.5 ft
Therefore, the total distance traveled by the particle over the given interval is 136.5 ft.
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The theory of plate tectonics was created by this evidence.
Sea floor spreading
Ridges in the sea floor moving outward.
Due to the sea floor spreading the continental crust must be moving as well
The process through which tectonic plates—large slabs of Earth's lithosphere—split away from each other is known as seafloor spreading.
What is seafloor spreading?Mantle convection causes seafloor spreading and other tectonic activity processes. Divergent plates, a form of tectonic activity that results in plates moving away from each other, causing seafloor spreading. Diverge Seafloor spreading results in three major characteristics of the seafloor: the age of the seafloor becomes progressively older as one moves away from mid-ocean ridges, the elevation of the seafloor becomes progressively lower as one moves away from mid-ocean ridges, and the magnetic history of the seafloor bears the striped-pattern of the Earth's magnetic.
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a 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s. what is the angle of the pendulum?
A 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s then the angle of pendulum is 14.68°.
Given:
Mass of the object = 0.4kg
Length of string = 0.9m
Period of conical pendulum = 1.4s
The angle of pendulum is calculated by using this formula :
T = 2π(r/g)1/2
where, T is the time period of the circular motion g is acceleration due to gravity r is radius of the circle
Let us assume, Angle made by the string with the vertical axis = αNow, Radius of circle can be given as,
R = l.sinα
Given the period of the conical pendulum as 1.4s
we can find the acceleration due to gravity as follows = 2π(r/g)1/2r = l.sinα2π(r/g)1/2 = Tg = 4π2(l.sinα)2/T2g = 4π2(l2sin2α)/T2sinα = gT2/4π2l2Sinα = (9.8 m/s2× 1.4 s2)/(4π2 × (0.9 m)2)Sinα = 0.253α = sin-1(0.253)α = 14.68°
Hence, the angle made by the string with the vertical axis is 14.68°.
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Two coherent sources of intensity ratio 1 : 4 produce an interference pattern. The visibility of fringes will be a. 1
b. 0.6
c. 0.8
d. 0.4
Two coherent sources of intensity ratio 1: 4 produce an interference pattern. The visibility of fringes will be 0.6. Thus, the correct option is B.
What is Interference pattern?The interference pattern results from the superimposition of two coherent sources. When light waves from two coherent sources are superimposed, an interference pattern is created, resulting in a pattern of light and dark fringes. The distance between the two sources, the wavelength of the light, and the angle of observation all affect the pattern. This pattern is referred to as an interference pattern.
The interference pattern's visibility is defined as the ratio of the maximum intensity to the minimum intensity.
V = (Imax- Imin)/(Imax + Imin)
where, V is the visibility of the fringe, Imax is the maximum intensity, and Imin is the minimum intensity.
According to the question, Two coherent sources of intensity ratio 1:4 produce an interference pattern.
Using the above formula: V = (Imax - Imin)/(Imax + Imin)
We know that the two sources' intensity ratio is 1:4.
Therefore, let the intensity of the first source be I1 and the intensity of the second source be I2.I1/I2 = 1/4 = I2 = 4I1
Imax = I1 + I2 = I1 + 4I1 = 5I1
Imin = I1 - I2 = I1 - 4I1 = -3I1
Substitute the value of Imax and Imin in the visibility formula:
V = (Imax - Imin)/(Imax + Imin)= (5I1 - (-3I1))/(5I1 + (-3I1))= (5I1 + 3I1)/(5I1 - 3I1) = 8I1/2I1 = 4
Therefore, the visibility of fringes will be 0.6.
Therefore, the correct option is B.
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A small grinding wheel has a moment of inertia of 4. 0×10−5 kg⋅m2
k
g
⋅
m
2. What net torque must be applied to the wheel for its angular acceleration to be 150 rad/s2
r
a
d
/
s
2
?
A net torque of [tex]6.0×10^−3 N⋅m[/tex] is sufficient to produce the desired angular acceleration of [tex]150 rad/s^2[/tex].
The net torque required to produce an angular acceleration in a rotating object can be calculated using the formula: net torque = moment of inertia × angular acceleration In this case, the moment of inertia of the grinding wheel is given as 4.0×10^−5 kg⋅m^2 and the angular acceleration required is 150 rad/s^2.
Therefore, the net torque required can be calculated as: net torque = [tex](4.0×10^−5 kg⋅m^2) × (150 rad/s^2) = 6.0×10^−3 N⋅m[/tex]To explain this result, we need to understand the relationship between torque and angular acceleration. Torque is the rotational equivalent of force and it is defined as the product of force and the perpendicular distance between the line of action of the force and the axis of rotation.
When a torque is applied to a rotating object, it produces an angular acceleration in the object, which is a measure of how quickly the object's rotational speed changes.
The moment of inertia of an object is a measure of its resistance to changes in its rotational motion. It depends on the object's mass distribution and the distance of each element of mass from the axis of rotation. Objects with larger moments of inertia require more torque to produce a given angular acceleration than objects with smaller moments of inertia.
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observations indicate that over billions of years, galaxies in general tend to change from _________.
Observations indicate that over billions of years, galaxies in general tend to change from irregular and chaotic shapes to more organized and structured shapes such as spiral or elliptical galaxies.
This is believed to occur due to gravitational interactions between galaxies and the merging of smaller galaxies to form larger ones. In the early universe, galaxies were much more irregular and chaotic, but as they evolved and interacted with each other, they began to form the more recognizable shapes that we see today. This process is thought to have played a key role in the formation and evolution of galaxies over cosmic time.
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Metamorphism means "a change in form." How a rock may change during metamorphism?
Metamorphism is a geological process that involves the transformation of pre-existing rocks into new types of rocks through changes in temperature, pressure, and chemical composition.
During metamorphism, rocks undergo significant changes in their physical, mineralogical, and structural properties.
One common change that occurs during metamorphism is recrystallization, where the mineral grains in a rock grow larger or change shape, resulting in a coarser texture. This occurs due to high temperatures and pressures that cause the atoms in the minerals to rearrange themselves.
Another common change is foliation, which is the development of a layered or banded structure in a rock due to the alignment of mineral grains. Foliation occurs when rocks are subjected to differential stress, where the pressure is greater in one direction than in another. This can result in the development of slate, schist, or gneiss from previously existing sedimentary, igneous, or metamorphic rocks.
Metamorphism can also cause changes in the chemical composition of a rock, such as the addition or removal of certain minerals. This can occur due to the circulation of fluids, such as water or magma, which can react with the rock and alter its composition.
Overall, metamorphism is a complex process that can result in a wide range of changes in rocks. These changes can create new types of rocks with unique properties and structures, and can provide important insights into the geological history and evolution of the Earth.
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If all forces are equal and opposite how do things accelerate?
Answer:
It is true that in accordance with Newton's third law of motion, every action has an equal and opposite reaction, meaning that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object. However, this does not necessarily mean that the objects will not accelerate.
Acceleration depends on the net force acting on an object, which is the sum of all forces acting on the object. If the forces are balanced (i.e. they are equal and opposite), then there is no net force and the object will not accelerate. However, if the forces are unbalanced (i.e. they are not equal and opposite), then there is a net force and the object will accelerate in the direction of the net force.
For example, if you push a book across a table with a force of 5 N to the right, the book will experience a force of 5 N to the left due to friction. These two forces are equal and opposite, but they are not balanced because they act in opposite directions. The net force on the book is therefore 5 N to the right, which causes the book to accelerate in that direction.