What is enthalpy?
A. Enthalpy is the heat involved in a reaction.
B. Enthalpy is the temperature of a reaction.
C. Enthalpy is the mass involved in a reaction.
D. Enthalpy is the kinetic energy of a system.

Answer: pH :1-2 / acid

pH:7/neutral

pH:8-9/basic

Your welcome

Answer:1-2,7, 8-9

Explanation:

Acidic, neutral, basic

Answer:

a. Manganese(IV) oxide

b. Mercury(I) chloride

c.  Iron(III) nitrate

d. Titanium(IV) chloride

e. Copper(II) bromide

Explanation:

The IUPAC nomenclature is regulated by International Union of Pure and Applied Chemistry which is used in organic chemistry for naming of the organic chemical compounds.

a. Manganese(IV) oxide is IUPAC name of manganesse dioxed . It is an inorganic compound having the formula MnO2.

b. Mercury(I) chloride is IUPAC name of mercurous chloride . It is also known as the mineral calomel and have a chemical formula Hg2Cl2.

c. Iron(III) nitrate is IUPAC name of ferric nitrate . It have a chemical formula Fe(NO₃)₃.

d. Titanium(IV) chloride is IUPAC name of titanium tetrachloride - .  It have a chemical formula TiCl4.

e. Copper(II) bromide is IUPAC name of cupric bromide with chemical formula CuBr2 or Br2Cu.

Answer:

Explanation:

Compared to an enzyme with a Km of 10-6 mM, an enzyme having a Km of 10-8 mM

The correct answer is option B - would be described as having binding more tightly to the substrate

Reason:

Km is the measure of substrate affinity. It is inversely proportional. Higher the Km, lower is the binding affinity of the enzyme and lower the Km, higher binding affinity of the enzyme to the substrate.

Therfore, Km of 10⁻⁸ will have higher substrate binding affinity than the 10⁻⁶ enzyme.

Answer: [tex]\Delta G_{rxn}=130.19J[/tex]

Explanation:

The balanced chemical reaction is,

[tex]CaCO_3(s)\rightarrow CaO(s)+CO_2(g)[/tex]

The expression for Gibbs free energy change is,

[tex]\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)][/tex]

[tex]\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})][/tex]

where,

n = number of moles

Now put all the given values in this expression, we get

[tex]\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)][/tex]

[tex]\Delta G_{rxn}=130.19J[/tex]

Therefore, the gibbs free energy for this reaction is, +130.19 kJ

Answer: 130 kJ

Explanation:

Answer:

Explanation:

Oxiding agent act as "Reduction" which loses oxygen in the product side.

Reducing agent act as "Oxidation" which gains oxygen.

Answer:

Volume of flask = 29.134 cm³

Explanation:

Mass of water = mass of filled stoppered flask - mass of empty stoppered flask.

Mass of water = 65.858 - 36.724 = 29.134 g

Density of water = 1 g/cm³

Volume = mass/ density

Volumeof water = 29.134 g/ 1g/cm³ = 29.134cm³

Therefore, volume of flask = 29.134 cm³

Answer:

The volume of the flask is 103.6 g

Explanation:

We know that density is equals to mass per unit volume. So for finding the volume, we have to put the values of masses of water and flask and density of water in the formula.

First the masses of both water and flask is added which is 102.6 g and the density of water is 0.997 g/cm3. So by puting these values in the formula of volume i. e. volume = mass/ density, so we get 103.6 cm3 volume.

Answer:

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Explanation:

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According to molar concentration, 3 moles are  needed to be dissolved in 1 dm³ to get a 3 M solution,and 0.3 moles would be needed if only 0.1 dm³were used.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.Substituting the values in given  formula, number of moles=molar concentration×volume in liters=3×1=3 moles and for 0.1 dm³ it is 3×0.1=0.3 dm³.

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Answer:

The thermal energy, orheat, of an object is obtained by adding up the kinetic energy of all the molecules within it.Temperature is the average kineticenergy of the molecules. 

Answer: The volume occupied by 2.50 moles of [tex]N_2[/tex] gas at STP is 56.0L

Explanation:

According to ideal gas equation:

[tex]PV=nRT[/tex]

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 2.50

R = gas constant =[tex]0.0821Latm/Kmol[/tex]

T =temperature =[tex]273K[/tex]  (at STP)

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{2.50mol\times 0.0821Latm/K mol\times 273K}{1atm}=56.0L[/tex]

Thus the volume occupied by 2.50 moles of [tex]N_2[/tex] gas at STP is 56.0L

Answer:

Metamorphic rock

Explanation:

Answer:

metamorphic

Explanation:

just took the test

Answer:

[tex]S^0 \rightarrow S^{+4}+4e^-[/tex]

Explanation:

Hello,

In this case, for the reaction:

[tex]K_2Cr_2O_7 + H_2O + S \rightarrow SO_2 + KOH + Cr_2O_3[/tex]

We first must assign the oxidation state of each element:

[tex]K^{+1}_2Cr^{+6}_2O_7^{+2} + H_2^{+1}O^{-2} + S^0 \rightarrow S^{+4}O_2^{-2} + K^{+1}O^{-2}H^{+1} + Cr_2^{+3}O_3^{-2}[/tex]

Thus, we should remember that the oxidation half-reaction applies for the element undergoing an increase in its oxidation state, such case is sulfur, for which passes from 0 to +4 as shown below:

[tex]S^0 \rightarrow S^{+4}+4e^-[/tex]

It means, that four electrons were lost due to the effect of the strong oxidizing agent, potassium dichromate.

Best regards.

Answer:

2 K + 1 CrBr2 yield 2 KBr + 1 Cr

Explanation:

Answer:

1. a, 1.66

2. c, 1.69

Explanation:

-log(H+)=pH

pH+pOH=14

Answer:

D & E

Explanation:

I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.

Uniform cooling of a pure substance sample that began as a gas. Between points D and E, solid and liquid phases can coexist.

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Answer:

The new pressure is 21.19 atm.

Explanation:

Original volume of the gas was 21 L at 11.1 atm

Neon in a piston is compressed to a volume of 11 L.

It is required to find the new pressure in atm. Boyle's law gives the relationship between volume and pressure. Its mathematical form is given by :

[tex]P_1V_1=P_2V_2[/tex]

We have,

[tex]P_1=11.1\ atm\\\\V_1=21\ L\\\\V_2=11\ L\\\\P_2=?[/tex]

Using above equation,

[tex]P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{11.1\times 21}{11}\\\\P_2=21.19\ atm[/tex]

So, the new pressure is 21.19 atm.

Answer:

26.2 atm

Explanation:

P1=P2V2/V1

P1=(1.05 x .980)/.0393

Answer: 26.2 atm

You can check this by knowing that P and V at constant T have an inverse relationship. Hence, this is correct.

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The remains or traces of ancient living organisms that have been preserved by natural processes, known as Fossils. These are of many types of parts and some are whole preserved organisms, some are impressions, while others are mold.

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Answer: 1.87 atm

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 2.50 atm

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = 26.4 ml

[tex]V_2[/tex] = final volume of gas = 36.2 ml

[tex]T_1[/tex] = initial temperature of gas = [tex]2.5^oC=273+2.5=275.5K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]10^oC=273+10=283K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{2.50\times 26.4}{275.5}=\frac{P_2\times 36.2}{283}[/tex]

[tex]P_2=1.87atm[/tex]

The new pressure is 1.87 atm by using combined gas law.

Answer:

THE TRUE STATEMENTS REGARDING REACTION RATE IS "INCREASING TEMPERATURE OR ADDING A CATALYST WILL INCREASE THE REACTION RATE".

Explanation:

The rate of a chemical reaction is the number of moles of reactant converted or product formed per unit time. There are various factors that affect reaction rate and they include;

1. Nature of the reactant

2. concentration and pressure of reactants. pressure is for gases.

3. temperature of the reactants.

4. surface areas of the reactants

5. presence of light

6. presence of catalyst.

I will talk about the role of temperature and catalyst in reaction rate.

TEMPERATURE:

The rate of virtually all reactions (chemical) increase when the temperature is increased. increasing the temperature of a system both exothermic and endothermic reactions, energy in the form of heat is supplied to the system which thus increases the number of particles with energies equal to or more than the activation energy of the system. This increase in particles leads to increase in collision and thus the reaction proceed faster.

CATALYST

A catalyst is a substance which alters the rate of a chemical reaction but remains unchanged at the end of the reaction. Catalyst operates by providing an alternative route for the reaction to occur. So adding a catalyst and has a lower activation energy when added increases the rate of reaction as more particles can collide with each other. This kind of catalyst is called positive catalyst. A catalyst that provides an alternative route with a higher activation energy is called negative catalyst.

Answer:

1.2x10^9

Explanation:

You have to use a decimal point to count the zeros until you get to the one.

Answer:

[tex]\large \boxed{\text{220 J}}[/tex]

Explanation:

1. Convert the pressure to atmospheres

[tex]p = \text{825 Torr} \times \dfrac{\text{1 atm}}{\text{760 Torr}} = \text{1.086 atm}[/tex]

2. Calculate the work done

[tex]w = -p\Delta V = -p(V_{f} - V_{i}) = -\text{(1.086 atm)}(\text{2.0 L - 4.0 L})\\\\ = -\text{1.086 atm} \times \text{(-2.0 L)} = \text{2.17 L$\cdot$atm}[/tex]

3. Convert litre atmospheres to joules

[tex]w = \text{2.17 L$\cdot$atm} \times \dfrac{\text{101.3 J}}{\text{1 L$\cdot$atm}} = \textbf{220 J}\\\\\text{The work done is $\large \boxed{\textbf{220 J}}$}[/tex]

Note that the volume is decreasing, so work is being done on the system.

Answer:

True

Explanation:

In 1909 Ernest Rutherford proposed to Geiger and Marsden to conduct an experiment in which they would have to launch alpha particles from a radioactive source against a gold foil a few atoms thick.

The aim of the experiment was to corroborate Rutherford's idea that the particles would pass through the metal foil with little deviation.

Rutherford's interpretation of the experimental results gave rise to a new atomic model, and concluded that the mass of the atom was concentrated in a small region of positive charges that impeded the passage of alpha particles. He suggested a new model in which the atom had a nucleus or center in which the mass and the positive charge are concentrated, and that in the extra nuclear zone are the negatively charged electrons.

Answer:

10.35 M

Explanation:

Molarity = moles solute/ L solution

18.5 mL = 0.0185 L solution

11.5 mL (1g/1mL)= 11.5 grams vinegar (1 mol / 60.052 grams) = 0.1915 mol vinegar

M = 0.1915 mol vinegar/ 0.0185 L solution = 10.35M

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Answer:

Fatty foods become rancid due to the process of rancidity

Answer:The answer is C melting.

Explanation:

Answer:melting

Explanation:

Answer:

2,4–dimethylhexane.

Explanation:

To name the above compound, we must do the following:

1. Locate the longest continuous carbon chain. This gives the parent name. In this case, the longest chain is carbon 6 i.e Hexane.

2. Identify and Locate the position of the substituent group attached. In this case, the substituent group attached is methyl i.e CH3 and it is at carbon 2 and 4.

3. Combine the above to get the name.

Therefore, the name of the compound is:

2,4–dimethylhexane.

Answer:

Explanation:

1060 grams / 1.0 ml = 1060 g/ml ≅ 1100 g/ml (final answer has 2 sig. figs.    

Answer:

                      Final answer => 1100 (2 sig. figs.)

Explanation:

1060 grams / 1.0 ml = 1060 g/ml ≅ 1100 g/ml (final answer).  

The rule is, the final answer of the calculation should have answer rounded to the data value having the least number of significant figures of the data used in the calculation. That is to the data value having the least number of significant figures.  

Counting Significant Figures (a method of determining no. of  sig. figs.).

For data values without decimal in data value, count left to right until reaching 1st nonzero digit. Begin count, include all zeros after 1st zero as enclosed zeros as significant figures.  

Present final results with the least number of sig. figs. as defined by data of computations.  

Examples: data values without decimal.  Count right to left.

12000 => 2 sig. figs. (trailing zeros are not sig. figs)  

2051000 => 4 sig. figs.

300 => 1 sig. fig.  

93000000 => 2 sig. fig.  

Examples: data values containing decimal. Count left to right.

0.0012 => 4 sig. figs.  (leading zeros are sig. figs.)

12.0035 => 6 sig. figs. (enclosed zeros are sig. figs.)

0.000001 => 6 sig. figs. (leading zeros are sig. figs.)

13.010 => 5 sig. figs. (enclosed zeros are sig. figs.)

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