What is an astronomical unit or AU

Answer:

Answer:

Im afraid i need to to know more on what your asking, are you asking what is momentum?

Explanation:

Because therefore it is the quantity of motion of a moving body, measured as a product of its mass and velocity to the state of motion

or

p = mv

I hope this helps and have a good day, or to best that you can make it <33

Answer:

Explanation:

Answer:

The radius is  [tex]r = 0.0170 \ m[/tex]  

Explanation:

From the question we are told that

      The speed at which the race car moves is [tex]v = 0.512 \ m/s[/tex]

       The centripetal acceleration is  [tex]a _r = 15.4 \ m/s[/tex]

Generally the centripetal acceleration is mathematically represented as

           [tex]a_r = \frac{v^2 }{r}[/tex]

=>        [tex]15.4 = \frac{0.512^2 }{ r}[/tex]

=>       [tex]r = 0.0170 \ m[/tex]  

Answer:

Explanation:

Pecan 1 and 4 seem the best answer

Answer:

a. Please find attached the diagram of the disc, having arrows that represent the velocity and the acceleration of the particle placed on it

b. The angular speed is approximately 4.488 rad/s

The linear speed is approximately 0.987 m/s

c. The largest distance from the center of the disc where the particle can be placed and still not move is approximately 0.399 m from the center of the disc

d. i The maximum angular speed of the disk so that the particle does not move relative to the disk is approximately 6.044 rad/sec

ii When the angular speed with which the disc rotates is more than the the answer of question d i  above, the particle slips on the disc, and the disc begins to rotate faster than the particle, while the particle is swung in an outward radial direction off the disc due to the centrifugal forces

Explanation:

The given parameters are;

The radius of the horizontal disc, r = 45 cm = 0.45 m

The time the disc makes one full revolution, T = 1.40 s

The mass of the particle placed on the disc = 0.054 kg

The location on the disc the particle is placed = 22 cm from the disc's center

a. Please find attached the diagram of the disc created with Microsoft Visio, with arrows representing the velocity and the acceleration of the particle placed on the disk

b. The angular speed, ω = 2·π/T = 2 × π/1.4 ≈ 4.488 rad/s

The linear speed, v = ω × r = 4.488 rad/s × 0.22 m ≈ 0.987 m/s

The linear speed, v ≈ 0.987 m/s

c. The given coefficient of static friction = 0.82

Therefore;

The frictional force that prevents motion = Weight of the particle × The coefficient of static friction

The frictional force that prevents motion is [tex]F_f[/tex] = 0.054 × 9.8 × 0.82 ≈ 0.434 N

[tex]F_f[/tex] ≈ 0.434 N

Therefore, for the largest distance from the center of the disc where the particle can be placed and still not move, r, is given by the formula for the centripetal force, [tex]F_c[/tex], acting on the particle as follows;

For static equilibrium, no movement of the particle relative to the disc, we have;

[tex]F_f[/tex] = [tex]F_c[/tex]

Where;

[tex]F_c = \dfrac{m \times v^2}{r} = m \times \omega ^2 \times r[/tex]

Which gives;

[tex]F_c = {0.054 \ kg \times (4.488 \ rad/s)^2} \times r = F_f = 0.434 \ N[/tex]

r = 0.434 N/(0.054 kg × (4.488 rad/s)²) ≈ 0.399 m

The largest distance from the center of the disc where the particle can be placed and still not move, r = 0.399 m from the center of the disc

d. i From the static equilibrium equation where r = 0.22 m, we have;

[tex]F_c = {0.054 \ kg \times \omega ^2} \times 0.22 \ m = F_f = 0.434 \ N[/tex]

ω =  √(0.434 N/(0.054 kg × (0.22 m))) ≈ 6.044 rad/sec

The maximum angular speed of the disk so that the particle does not move relative to the disk, ω ≈ 6.044 rad/sec

ii When the angular speed with which the disc rotates is more than the the answer of question d i  above, we have

The particle begins to slip on the disc such that the disc rotates faster than the particle and the particle tends to rotate slower than the speed pf the disc and is swung off the disc by centripetal force acting on the particle due to the rotational motion of the disc.

Answer:

128 m

Explanation:

From the question given above, the following data were obtained:

Horizontal velocity (u) = 40 m/s

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Horizontal distance (s) =?

Next, we shall determine the time taken for the package to get to the ground.

This can be obtained as follow:

Height (h) = 50 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

50 = ½ × 9.8 × t²

50 = 4.9 × t²

Divide both side by 4.9

t² = 50 / 4.9

t² = 10.2

Take the square root of both side

t = √10.2

t = 3.2 s

Finally, we shall determine where the package lands by calculating the horizontal distance travelled by the package after being dropped from the plane. This can be obtained as follow:

Horizontal velocity (u) = 40 m/s

Time (t) = 3.2 s

Horizontal distance (s) =?

s = ut

s = 40 × 3.2

s = 128 m

Therefore, the package will land at 128 m relative to the plane

Answer:

Hi, thank you for posting your question here at Brainly.

To find the velocity of light or any electromagnetic wave, we use the equation: v = wavelength * frequency. Substituting,

v = 0.5 m * 930 1/s

v = 465 m/s

Brainiest please

Explanation:

Answer:

kilograms and grams

Explanation:

kilograms is the stadard unit for mass according to the SI system.

Grams is another unit for mass.

Answer:

The density of the liquid is 340.136 kg/m³

Explanation:

Given;

depth of liquid in the container, h = 60 cm = 0.6 m

pressure of the liquid, P = 2000 Pa = 2000 N/m²

The pressure of the liquid is calculated as ;

P = ρgh

where;

ρ is density of the liquid

g is acceleration due to gravity = 9.8 m/s²

h is depth of the liquid

Make the density (ρ) the subject of the formula;

[tex]\rho = \frac{P}{gh} \\\\\rho = \frac{2000}{9.8 \times 0.6}\\\\\rho = 340.136 \ kg/m^3[/tex]

Therefore, the density of the liquid is 340.136 kg/m³

Answer:

In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).

Explanation:

Answer:i think it's d

Explanation:

Answer:

Tension, Ft = 79.91 N

Explanation:

The tension in the string is the resultant force that exists in the string due to the centripetal effect of the swinging ball.

From conservation laws, the tension in the string will be equals to the centripetal force acting on the string.

The tension in a string can be obtained using the formula:

[tex]T=mv^2/R[/tex]

where v = linear velocity of the metal ball which equals to the angular velocity of the ball X the radius of the ball.

The radius of the ball is given as 72 cm = 0.72m and the angular velocity = 1.02 rad/second.

Therefore, linear velocity, [tex]v = 2\pi \times 1.02\times 0.72 =4.616m/s[/tex]

The tension in the string will now be equals to [tex]2.7 \times 4.616^2 /0.72 =79.91N[/tex]

Answer: It is b. a crystal

Explanation:

Answer:

B. A crystal

Explanation:

Answer:

sorry its impossible

Explanation:

Explanation:

Mass of iron = (7.9)(10) = 79g

Mass of wood = (115)(0.7) = 80.5g

Therefore iron has a smaller mass than the wood, which is true.

Answer:

1.92 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 200 Kg

Spring constant (K) = 10⁶ N/m

Workdone =?

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass (m) = 200 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = m × g

F = 200 × 9.8

F = 1960 N

Next we shall determine the extent to which the spring stretches. This can be obtained as follow:

Spring constant (K) = 10⁶ N/m

Force (F) = 1960 N

Extention (e) =?

F = Ke

1960 = 10⁶ × e

Divide both side by 10⁶

e = 1960 / 10⁶

e = 0.00196 m

Finally, we shall determine energy (Workdone) on the spring as follow:

Spring constant (K) = 10⁶ N/m

Extention (e) = 0.00196 m

Energy (E) =?

E = ½Ke²

E = ½ × 10⁶ × (0.00196)²

E = 1.92 J

Therefore, the Workdone on the spring is 1.92 J

Answer: I think its True

Answer:

416.667 m/s

Explanation:

divide the distance by the time

Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass in kg

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question

750 g = 0.75 kg

We have

PE = 0.75 × 9.8 × 3

We have the final answer as

Hope this helps you

Answer:

The mass of the object is 24.5 kg and weight of the object on Mars is 91.14 N.

Explanation:

Weight of the object on the surface of Earth, W = 245 N

On the surface of Earth, acceleration due to gravity, g = 10 m/s²

Weight of an object is given by :

W = mg

m is mass

[tex]m=\dfrac{W}{g}\\\\m=\dfrac{245\ N}{10\ m/s^2}\\\\=24.5\ kg[/tex]

So, the mass of the object is 24.5 kg

Acceleration due to gravity on Mars, g' = 3.72 m/s²

Weight of the object on Mars,

W' =mg'

W' = 24.5 kg × 3.72 m/s²

= 91.14 N

So, the weight of the object on Mars is 91.14 N.

Given the data in the question;

Weight of object; [tex]W = 245N[/tex]

Weight the measure of the force of gravity pulling down on a particle or object.

It is expressed as:

[tex]W = m* g[/tex]

Where m is mass of the object and g is acceleration due to gravity { Acceleration due gravity of Earth [tex]g_{earth} = 9.8m/s^2[/tex] }

We substitute our values into the equation

[tex]245N = m * 9.8m/s^2\\\\245kg.m/s^2 = m * 9.8m/s^2\\\\m = \frac{245kg.m/s^2}{9.8m/s^2} \\\\m = 25kg[/tex]

Therefore, mass of the object located near the Earth surface is 25kg

So on planet Mars; [tex]g = 3.72m/s^2[/tex], we know that mass of the object is [tex]25kg[/tex]

We substitute into our equation

[tex]W = m* g[/tex]

[tex]W = 25kg * 3.72m/s^2\\\\W = 93kg.m/s^2\\\\W = 93N[/tex]

Therefore, the weight of the object on Mars with the given gravity is 93 Newtons.

Learn more: https://brainly.com/question/23245710

Answer:

Michael's final velocity is 19.62 m/s.    

Explanation:            

We can find the final velocity of Michael by using the following kinematic equation:

[tex] v_{f} = v_{0} + at [/tex]   (1)    

Where:

[tex]v_{f}[/tex]: is the final velocity =?

[tex]v_{0}[/tex]: is the initial velocity = 1.62 m/s

a: is the acceleration = 1.2 m/s²

t: is the time = 15 s

By entering the above values into equation (1) we have:

[tex] v_{f} = 1.62 m/s + 1.2 m/s^{2}*15 s [/tex]

[tex] v_{f} = 19.62 m/s [/tex]

Therefore, Michael's final velocity is 19.62 m/s.

I hope it helps you!                                            

Answer:

Since cell division occurs twice during meiosis, one starting cell can produce four gametes (eggs or sperm). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase.

Answer:

here are six stages within each of the divisions, namely prophase, prometaphase, metaphase, anaphase, telophase and cytokinesis

Explanation:

Answer:

Explanation:

There are three states of matter; solid, liquid and gaseous states.

The solid state of matter has it's particles tightly packed with very restricted  or no movement within the molecule hence the reason for it's definite shape.

The liquid state of matter has it's particles with a free movement (better than solid but not as free as gases) within the molecule hence it's particles are loosely packed within the molecule. Hence, they (liquids) assume the shape of the container in which they are stored and they move freely when released from the container.

The gaseous state of matter has it's particles totally loosely packed as a result of it's particles moving freely and colliding against one another.

Thus, we can use the above descriptions to answer the statements from the question.

1) The atoms in a  ----- are closely packed, but able to slide past each other. Answer: From the description above, it can be deduced that the atoms here are in a solid because the particles within a solid are closely packed.

2) The atoms in a  -------- spread as far apart as possible.

Answer: The atoms here are in gaseous form because, as described earlier, they are loosely packed and  can thus be as far apart as possible.

3) A  ----- has a definite shape and volume.

Answer: As described earlier, a solid substance would have a definite shape and volume because it's particles are tightly packed.

4) The shape of a  ----- can change, but the volume is definite.

Answer: The substance here is a liquid because the particles are free (but not as free as gases) and would have a definite volume but will assume the shape of the any container they are placed in (hence they have an irregular shape).

Answer:

The atoms in a

✔ liquid

are closely packed, but able to slide past each other.

The atoms in a

✔ gas

spread as far apart as possible.

A

✔ solid

has a definite shape and volume.

The shape of a

✔ liquid

can change, but the volume is definite.

Explanation:

Examples of Newton's three law of motion.

First law of motion: A rocket being launched up in the atmosphere.

Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.

Third law of motion:when we jump off from the boat,the boat moves backward.

Hope,it will helpyouu!

Answer:

Mass of the melted wax

Explanation:

The mass of the original candle that has been burnt in the closed system is equal to the mass of the melted wax.

Answer:

Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line

Explanation:

:)

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT