What is a arithmetic fact ?

Answer:   512m³

Step-by-step explanation:

v = whl

The volume for left building:

v = w x h x l

v = 4 x 10 x 8

v = 320 m³

The volume for right and lower building:

v = w x h x l

v = 8 x 4 x 6

v = 192 m³

The total volume for the entire Charter School is: 320m³ + 192m³ = 512m³

Answer:

p,q,r

Step-by-step explanation:

Answer: x = -7

Step-by-step explanation:

7 (x + 4) = -21

7x + 28 = -21

Subtract 28 from both sides

7x = -49

Divide both sides by 7

x = -7

Answer:

x = -7

Step-by-step explanation:

first distribute he 7 to get 7x + 28 = -21

then subtract 28 from both sides to get 7x = -49

lastly divide 7 from both sides to get x = -7

Answer:

the graph on the bottom left

Step-by-step explanation:

outliers are points that are away from the cluster of points in the bottom left graph all of the points are grouped up therefor the bottom left graph is the correct answer

Answer: 7

Step-by-step explanation: because 45 divided by 6 is 7.5

Answer: 5040

Step-by-step explanation: There are 4 sides which is equal to 1260, 1260 x 4 = 5040

Answer:

nudaw HAHABSASASNA

Step-by-step explanation:[tex]x^{2} g[/tex]

hggggguuuuugs berte bhu jira yuwa

Answer:

Answer below

Step-by-step explanation:

right

acute

i believe this is correct :)

Answer:

1 simple

Step-by-step explanation:

Answer:

The points that fits the equation would be option D.

your answer would be 33.

step 1

2(+14)−1(2−5)

2+28−1(2−5)

step 2 distribute

2+28−1(2−5)

2+28−2+5

step 3 then add the numbers

2+28−2+5

2+33−2

combine

2+33−2

ANSWER IS

33

Answer:

x = 15

Step-by-step explanation:

use pythagorean theorem (a^2+b^2=c^2)

you have c^2 and one of the sides so you just reverse the equation and do

17^2-8^2

and that gives you 225

when you [tex]\sqrt{225}[/tex], you get 15 as your answer

Answer:

64

Step-by-step explanation:

Given :

h α 1 / sqrtk

h = k/sqrt(d)

Obtain the value of k, when. d = 4 and h = 20

20 = k / sqrt(4)

20 = k / 2

20 * 2 = k

k = 40

Therefore, the value of d when h = 5

h = k/sqrt(d)

5 = 40 / sqrt(d)

Square both sides

25 = 1600/d

25d = 1600

d = 1600 / 25

d = 64

d = 64

Answer:

x=9

Step-by-step explanation:

these are vertical angles, so they equal eachother!

12x-3=105

move three to the other side of the equals sign

12x=108

divide both sides by 108

x=9

Answer: x=9

Step-by-step explanation:

These angles are equal, so you can set 105 equal to 12x-3. Add 3 and divide by 12 to get x=9.

Answer:

3 ft

Step-by-step explanation:

Because 6 divided by 2 equals 3. And two 1s equal 2.

Answer:3ft

Step-by-step explanation:6/2

Answer:

9(2x-1)

Step-by-step explanation:

common factor of both 9 and 18 is 9

thus, you can take a 9 out

9(2x-1)

(to check if it is correct, you can expand it, and if it is the same as original then it is correct )

Answer:

9 (2x-1)

Step-by-step explanation:

Grouping

1. Common factor:

18x-9

Solution:

9 (2x-1)

Answer:

118

Step-by-step explanation:

a triangle is 180 degrease and two sides that are equal to each other which means the angles across from them have the same thing.

so. 180-31-31=118

Answer:

-8y° -7y

Step-by-step explanation:

Like terms:

13y-11y-9y= -7y

-8y°= -8y°

Simplified Expression:

-8y°-7y

Answer:

Slope = -1/2

Y-Intercept = 2

Equation: Y=-1/2x+2

Step-by-step explanation:

Graph goes 2 units up at y=2, that's your y-intercept. From there, plot your second point by moving 1 down and 2 to the right from the y-intercept, landing on the point (2,1) to get your slope, written as -1/2.

Given:

The pair of expressions in the options.

To find:

The pairs which show a pair of equivalent expressions.

Solution:

Property of exponent:

[tex](\sqrt[n]{x})^m=x^{\frac{m}{n}}[/tex]

In option A,

[tex](\sqrt[4]{81})^5=81^{\frac{5}{4}}[/tex]

So, option A is correct.

In option B,

[tex]6^{\frac{7}{2}}=(\sqrt[2]{6})^7[/tex]

[tex]6^{\frac{7}{2}}=(\sqrt{6})^7[/tex]

So, option B is correct.

In option C,

[tex]5^{\frac{2}{3}}=(\sqrt[3]{5})^2[/tex]

[tex]5^{\frac{2}{3}}\neq (\sqrt{5})^3[/tex]

So, option C is incorrect.

In option D,

[tex]7^{\frac{5}{7}}=(\sqrt[7]{7})^5[/tex]

[tex]7^{\frac{5}{7}}\neq (\sqrt{7})^5[/tex]

So, option D is incorrect.

Answer:it’s a and b

Step-by-step explanation:

did the test

Answer:

Trevor is right

Step-by-step explanation:

The solution of system of equations are [tex](4,0)[/tex]

Therefore, Trevor conclusion is true.

Given system of equations;

                 [tex]x- 2y = 4\\\\y=4-x[/tex]

Substitute value of y from equation (2) in equation (1).

           [tex]x-2(4-x)=4\\\\x-8+2x=4\\\\3x=12\\\\\\x=12/3=4[/tex]

Substitute value of x in second equation.

 [tex]y=4-x=4-4=0[/tex]

Hence, the solution of system of equations are [tex](4,0)[/tex]

Learn more about the system of equations here:

https://brainly.com/question/13729904

Answer:

100/ 651 , or 0.15361

Step-by-step explanation:

this took so long

Answer:

0.15360983102

.......

Answer:

8

Step-by-step explanation:

Given that

19 + 7 divided by 2 - 5

So if we solve this we have to apply proper brackets

= (19 + 7) ÷ 2 - 5

= 26 ÷ 2 - 5

= 13 - 5

= 8

After solving this the answer is 8

Answer:

there are not solutions because they never cross each other

The characteristics of the sinusoidal function can be found from the given

graph of the function.

The sinusoidal function is the sine function that has the following general equation;

a = The amplitude

b = Angular frequency

h = The horizontal shift

k = The vertical shift

The minimum value of the sinusoidal function.

From the given graph, we have;

The amplitude, a = 2

The period, T = 10 = 2·π/b

b = π/5

The vertical shift, k = 3

The horizontal shift = 0

The minimum value of the function = k - a

Therefore;

Learn more about sinusoidal functions here:

https://brainly.com/question/6666829

Answer:

[tex]\displaystyle 1[/tex]

Step-by-step explanation:

[tex]\displaystyle \boxed{y = 2cos\:(\frac{\pi}{5}x - \frac{\pi}{2}) + 3} \\ \\ y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{2\frac{1}{2}} \hookrightarrow \frac{\frac{\pi}{2}}{\frac{\pi}{5}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{10} \hookrightarrow \frac{2}{\frac{\pi}{5}}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle \boxed{y = 2sin\:\frac{\pi}{5}x + 3} \\ \\ y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 3 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{10} \hookrightarrow \frac{2}{\frac{\pi}{5}}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the sine graph, if you plan on writing your equation as a function of cosine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2cos\:\frac{\pi}{5}x + 3,[/tex] in which you need to replase "sine" with "cosine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the sine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the cosine graph [photograph on the right] is shifted [tex]\displaystyle 2\frac{1}{2}\:units[/tex]to the left, which means that in order to match the sine graph [photograph on the left], we need to shift the graph FORWARD [tex]\displaystyle 2\frac{1}{2}\:units,[/tex]which means the C-term will be positive, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{2\frac{1}{2}} = \frac{\frac{\pi}{2}}{\frac{\pi}{5}}.[/tex]So, the cosine graph of the sine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2cos\:(\frac{\pi}{5}x - \frac{\pi}{2}) + 3.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph approximately hits [tex]\displaystyle [-10, 3],[/tex]from there to the y-intercept of [tex]\displaystyle [0, 3],[/tex]they are obviously approximately [tex]\displaystyle 10\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle 10.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 3,[/tex]in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**Now, the minimum value is the lowest possible value the graph touches, and in this case, the graph's lowest peaks cycle around [tex]\displaystyle y = 1,[/tex]therefore the minimum of his sinusoidal function is [tex]\displaystyle 1.[/tex]

I am delighted to assist you at any time.