What is -2+(-4) I need help with it because id not understnad how to add integers

Answer:

[tex]7+w \ge 21[/tex]

remove the line under the arrow

Answer:

w>14

Step-by-step explanation:

"sum" means adding together. So, the sum of 7 and w would be 7+w. The equation states that this sum is greater than 21, so:

7+w>21

if you want a simplified version, subtract 7 from both sides to get w>14

Answer:

B

Step-by-step explanation:

The tangent of an angle is the ratio of the opposite side to the adjacent.

With respect to Angle A, the opposite side is 12.

And the adjacent side is 5.

Therefore:

[tex]\displaystyle\tan(A)=\frac{\text{opp}}{\text{adj}}=\frac{12}{5}[/tex]

The answer is B.

Answer:

20 times

Step-by-step explanation:

30/6 = $5 per time

100/5 = 20 times

Answer:b

Step-by-step explanation:

Answer:

X=2

Step-by-step explanation:

-2x+10=12-3x

-2x+3x=12-10

X=2

Answer:

Jahmya's Lunch cost more

Step-by-step explanation:

Stephen's Lunch

Jahmya's Lunch

Answer:

A

Step-by-step explanation:

155-22/155 equal around 86% who don't so meaning 14% do take lessons.

Answer:

The answer is A.

Step-by-step explanation:

Answer:

The answer is "confidence interval".

Step-by-step explanation:

The trust period is a set of values that may include confidence intervals unspecified. Whenever a representative selection is collected numerous times, its sample parameter would be a certain percentage of its confidence intervals. It shows how likely the position of a statistical parameter will be estimated.

Answer:

I'm going to answer in the comments so no one steals this answer

Step-by-step explanation:

Answer:

Choice A (0,2)

Step-by-step explanation:

Solve for y:

2x + 3y = 6

3y = -2x+6

y=-2/3x+2

Sub x as 0 to find y:

y=-2/3(0)+2

y=2

Answer:

a- (0,2)

Step-by-step explanation:

PLATO

Answer:

B. It will be the tens place because 6 is greater than 3.

Step-by-step explanation:

Since the question said "quotient," then I believe we have 362 ÷ 6 and not "362 + 6."

If we work on the quotient we have

[tex]60\frac{1}{3}[/tex]

Obviously, the first digit in the quotient is 6 and it takes the place of tens.

Looking at the options, option B fits the most because 6 is actually greater than 3.

Therefore, the answer is option B, It will be the tens place because 6 is greater than 3.

Answer:

"All integers are irrational numbers" False

"No whole numbers are irrational numbers" True

"Some rational numbers are not integers" True

"Some integers are not whole numbers" True

Step-by-step explanation:

I'm 100% sure of this.

Answer:

Step-by-step explanation:

CG = [tex]\frac{2}{3}[/tex] CF

8x = [tex]\frac{2}{3}[/tex] (9x + 6)

8x = 6x + 4

2x = 4

x = 2

Answer:

i think its c

Step-by-step explanation:

Open circle means that the solution cannot be the answer, closed circle means that the answer can be part of the solution. Therefore, option B is the correct answer.

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

The difference between an open and closed circle when graphing inequalities are  

A closed circle indicates "greater than or equal to" or "less than or equal to," while and open circle indicates "greater than" or "less than".

Therefore, option B is the correct answer.

To learn more about the inequalities visit:

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#SPJ2

Answer:

They each get 1/8 of the brownie

Step-by-step explanation:

Hurry up! don't want you getting a zero!

Multiply people per square km by total square km.

45 x 33 = 1,485 total people.

Answer:

x-(-1)=6

-x=6

-x/-1 6/-1

x=-6

Answer:

Therefore, the solution of the system of equations will be:

[tex]x=5,\:y=-1[/tex]

Step-by-step explanation:

Given the system of equations

[tex]x-y=6;\:y=-1[/tex]

solving

[tex]\begin{bmatrix}x-y=6\\ y=-1\end{bmatrix}[/tex]

[tex]\mathrm{Subsititute\:}y=-1[/tex]

[tex]\begin{bmatrix}x-\left(-1\right)=6\end{bmatrix}[/tex]

[tex]\begin{bmatrix}x+1=6\end{bmatrix}[/tex]

Isolate x for [tex]x+1=6[/tex]

[tex]x+1=6[/tex]

[tex]x=5[/tex]

Therefore, the solution of the system of equations will be:

[tex]x=5,\:y=-1[/tex]

Answer:

98.6607 pounds

Step-by-step explanation:

11.81 times 8.354 = 98.6607

Answer:

4 days

Step-by-step explanation

[tex]\frac{4}{1}[/tex] x [tex]\frac{4}{3}[/tex] = 5 [tex]\frac{1}{3}[/tex]

Answer:

B: (-4, 22)

Step-by-step explanation:

for these types of problems, you just need to plug in the values

A: y= -4(-4) + 6 = 22 — NOT 10

B: y= -4(-4) + 6 = 22 — CORRECT

C: y= -4(1) + 6 = 2 — NOT 10

D: y= -4(1) + 6 = 2 — NOT -2

Answer:

Step-by-step explanation:

Answer:

D. -2 ≤ y ≤ 2

Step-by-step explanation:

Range of a Relation

It's the set of values the relation takes when x moves into the relation's domain.

It can be graphically determined by placing imaginary horizontal lines from minus infinite to plus infinite. Where the line meets the relation's graph, that value of y belongs to the range.

If we place imaginary horizontal lines from -∞ up to y=-2, we won't meet the relation's graph. Exactly at y = -2, the line and the graph have one point in common.

Moving up the line will meet the graph until exactly y=2, from where there won't be any additional interceptions.

Thus, the range of the relation is [-2,2] or, written in inequality form:

D. -2 ≤ y ≤ 2

Based on the information given about the combination, the number of different parts of fruits that can be selected from the bowl will be 6.

Since the bowl contains an apple, a plum, a pear, and a banana, the different pairs of fruit that can be selected from the bowl will be 4C2.

We can solve this further which will be:

= 4C2

= 4! /2! (4 - 2)!

= 4! / 2!2!

= (4 × 3 × 2)/ 2 × 2

= 24/4

= 6

Therefore, 6 different pairs of fruit can be selected.

Learn more about combinations on:

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Answer:

im too dum

Step-by-step explanation:

dum dum dummy

Answer:

44.125 inches

Step-by-step explanation:

Given that:

Length of picture = 32 1/2 inches

Length of wall = 120 3/4 inches

Hence, to center picture horizontally ;

Distance from the edge of the wall in which the picture should be placed :

(Length of wall - length of picture) / 2

(120 3/4 - 32 1/2) / 2

(483/4 - 65/2) / 2

Take the L. C. M of 4 and 2 = 4

((483 - 130) / 4) ÷ 2

(353 / 4) ÷ 2

(353 / 4) * (1 / 2)

= 353 / 8

= 44 1/8

= 44 1/8

= 44.125 inches

The space that will be left in each side of the picture from the edge of the wall if Jon is to hang the picture at the center of the wall horizontally is: 44.125 inches.

The wall that Jon wants to hang the picture has been sketched in the diagram attached below (see attachment).

Given the following:

Therefore, the following equation can be derived as follows:

[tex]2x + 32.5 = 120.75[/tex]

[tex]2x = 120.75 - 32.5 \\\\2x = 88.25\\\\x = \frac{88.25}{2} \\\\\mathbf{x = 44.125 $ inches}[/tex]

Therefore, the space that will be left in each side of the picture from the edge of the wall if Jon is to hang the picture at the center of the wall horizontally is: 44.125 inches.

Learn more here:

https://brainly.com/question/9918022

Answer:

4.666 repeat robuxxx vegtebles hulk

Answer:

Step-by-step explanation:

1) For complex numbers addition, add the real parts and imaginary party separately.

(2 +5i) - (-6 + 3i) = 2 + 5i + 6 - 3i

                          = 2+ 6 + 5i - 3i

                          = 8 + 2i

2)Use FOIL method

(-4 +2i)(3 - 7i) = -4*3 + (-4)*(-7i) + 2i* 3  + (2i)*(-7i)

                    = -12 + 28i + 6i -14i²                 {i² = -1}

                   = -12 + 28i + 6i - 14*(-1)

                   = -12 + 28i + 6i + 14             {Combine like terms}

                 = -12 + 14 + 28i + 6i

                 = - 2 + 34i

3)Hint:

[tex]a^{mn} = (a^m)^{n}\\\\a^{m}*a^{n}= a^{m+n}[/tex]

[tex]\sqrt[4]{144x^{12}y^{7}} =\sqrt[4]{2*2*2*2*3*3*x^{3*4}*y^{4+3}} \\\\=\sqrt[4]{2^{4}*9*(x^{3})^{4}*y^{4}*y^{3}}\\\\=2*x^{3}*y\sqrt[4]{9y^{3}}\\\\ =2x^{3}y\sqrt[4]{9y^{3}}[/tex]

4)

[tex]\sqrt[3]{\frac{320a^{10}}{27b^{6}}}= \sqrt[3]{\frac{8*8*5a^{3+3+3+1}}{3*3*3b^{3+3}}}\\\\=\sqrt[3]{\frac{2^{3}*2^{3}*5a^{3}*a^{3}*a^{3}*a}{3^{3}b^{3}*b^{3}}}\\\\=\frac{2*2*a*a*a}{3b*b}\sqrt[3]{\frac{5a}{1}}\\\\=\frac{4a^{2}}{3b^{2}}\sqrt[3]{5a}[/tex]

5) 4x² + 28x + 49 = 4x² + 14x +14x + 7*7

                            = 2x(2x + 7) + 7(2x + 7)

                            =(2x+ 7)(2x + 7)

6) 2x² + 3x - 20 =  2x² +8x - 5x - 5 *4

                         =2x(x + 4) - 5(x + 4)

                       = (x + 4)(2x - 5)