What impulse must be applied to a 1.08 kg cart to cause a velocity change of 12.0 m/s

1. The spring force constant that attach a block with a mass of 0.3 kg = 15 N/m

2. The amplitude of the motion = 1.85 m

3. The maximum speed of the block during its motion = 6.9 m/s

4. The maximum magnitude acceleration of the block's acceleration during its motion = 92.5 m/s²

The force a spring applies to objects fastened to its ends is proportional to the distance the spring travels from its equilibrium length and is always pointed in the direction of equilibrium. F = -kx. The term "spring constant" refers to the proportional constant k.

The block's weight and the spring's force are equal:

F = -kx

ma = -kx

Hence,

1.

The spring force constant (k) = - (ma) / x

= - (0.3 x (-12) / 0.24

= 15 N/m

The total energy system:

E = [tex]\frac{1}{2}[/tex] (mv² + kx²)

= [tex]\frac{1}{2}[/tex] {(0.3 x 4)² + (15 x 0.24)²}

= 7.2 J

2.

The amplitude of the motion =

E = [tex]\frac{1}{2}[/tex] (mv² + kA²)

A = [tex]\sqrt{E^{2}/k }[/tex]

= [tex]\sqrt{\frac{(7.2)^{2} }{15} }[/tex]

= 1.85 m

3. The maximum speed of the block during its motion

E =  [tex]\frac{1}{2}[/tex] mv² + 0

v = [tex]\sqrt{\frac{2E}{m} }[/tex]

= [tex]\sqrt{\frac{2(7.2)}{0.3} }[/tex]

= 6.9 m/s

4. The maximum magnitude acceleration of the block's acceleration during its motion =

ma = kA

a = kA/m

= (15 x 1.85) / 0.3

= 92.5 m/s²

The question is incomplete, it should be:

A block with a mass of 0.3 kg is attached to one end of an ideal spring the other end is attached to a wall. when the block is at 0.24m, its acceleration is -12 m/s2 and its velocity is 4 m/s. find:

1. What is the spring's force constant k?2. What is the amplitude of the motion?3. What is the maximum speed of the block during its motion?4. What is the maximum magnitude of the block's acceleration during its motion?

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In  an open system, Matter, heat and work are able to freely enter or exit the system. Hence, option (A) is correct.

A system that interacts with the outside world is an open system. Depending on the field that defines the term, these interactions can involve the transfer of information, energy, or materials into or out of the system border.

An isolated system, which does not exchange energy, matter, or information with its surroundings, is contrasted with an open system. A flow system is another name for an open system. Hence, option (A) is correct.

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The potential energy stored in the spring when it is displaced a distance "x" from the equilibrium position is [tex]U = (k/4)x^4.[/tex]

The potential energy stored in a spring can be calculated using the work-energy theorem, which states that the work done on an object is equal to the change in its potential energy. If the spring is displaced a distance "x" from the equilibrium position, the force exerted by the spring is given by the equation[tex]f = kx^3[/tex], where "k" is a constant of proportionality. The work done on the spring as it is displaced a distance "x" is given by the equation [tex]W = ∫f dx = ∫kx^3 dx.[/tex]

To find the potential energy stored in the spring, we can evaluate the definite integral:

U =[tex]∫kx^3 dx = (k/4)x^4 + C,[/tex]

where "C" is a constant of integration. The constant "C" can be determined by specifying the potential energy to be zero when the spring is at its equilibrium position, so that U = 0 when x = 0. This gives us:

[tex]C = -(k/4) * 0^4 = 0[/tex],

So the potential energy stored in the spring when it is displaced a distance "x" from the equilibrium position is:

[tex]U = (k/4)x^4.[/tex]

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Answer:

D

Explanation:

I believe it is D, which is the resultant of the vector addition of B and E

Whenever two massless springs that obey Hooke's Law are joined by a thin, vertical rod, they are linked in parallel. The spring constants for springs  and  were indeed denoted by 1 and 2 . A steady force F is applied to the rod, keeping it perpendicular to the force's orientation. If the force was reciprocated, the springs may likewise be squeezed.

Such a system of two parallel springs is equal to a single Hookean spring with spring constant k.

What is spring constant?

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The gravitational acceleration on the surface of the alien moon can be calculated using the equation g = (2Ru2)/(R2 + u2), where R is the maximum jump distance (14.5 m), and u is the initial speed (3.10 m/s). Plugging these values in, we get g = 0.5137 m/s2.

Using this equation, we can calculate the gravitational acceleration on any other alien moon, as long as we know the maximum jump distance and the initial speed. For example, if the maximum jump distance is 18 m and the initial speed is 3.50 m/s, then the gravitational acceleration would be 0.6115 m/s2.

Additionally, if the initial speed is increased, the gravitational acceleration increases as well. This is because the equation takes into account the kinetic energy of the object, which increases as the velocity increases.

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Answer:

Explanation:

We know that distance can be calculated using the formula:

d = v0 * t + 0.5 * g * t^2

where v0= intial velocity

t=fall time

g= free fall acceleration

Now as per the question:

initial velocity v0 = 2.30 m/s

time t = 1.50 s

Free fall acceleration g = 9.8 m/s^2

d= v0 * t + 0.5 * g * t^2

distance = 2.30 * 1.50 + 0.5 * 9.8 * 1.50^2

distance = 3.45 + 14.7

d = 18.15 m

Therefore, the swimmer lands 18.15 meters from the base of the starting block.

They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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The density of the block can be calculated using the equation density = mass / volume.

In this case, the mass is 887.6 g and the volume is 7.31 cm x 4.24 cm x 2.15 cm, which results in a density of 89.9 g/cm3.

The density of a material can be used to identify what it is made of, and can also be used to estimate its strength and other properties. It is an important factor to consider when designing and constructing objects, as the density of a material affects how much it weighs, how much it can support, and how much it will cost. The density of a material varies depending on factors such as temperature, pressure, and composition.

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The speed of the released particle at an infinite distance from the other fixed charge is 8.07 * 10^3 m/s.

The speed of a particle at an infinite distance from another fixed charge can be calculated using the concept of electrostatic energy.

The initial electrostatic energy of the two particles is given by:

U = k * q1 * q2 / r

where k is Coulomb's constant (8.98 * 10^9 Nm^2/C^2), q1 and q2 are the charges of the particles (1.6 * 10^-6 C), and r is the distance between them (5 m).

The initial potential energy of the released particle is equal to its initial electrostatic energy:

U = (1/2) * m * v^2

where m is the mass of the particle (37 g) and v is its speed.

Solving for v, we have:

v = √(2 * U / m) = √(2 * k * q1 * q2 / (m * r)) = √(2 * 8.98 * 10^9 * 1.6 * 10^-6 * 1.6 * 10^-6 / (37 * 10^-3 * 5)) = 8.07 * 10^3 m/s

Therefore, the speed of the released particle at an infinite distance from the other fixed charge is 8.07 * 10^3 m/s.

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Revolving doors have three or four leaves (or wings) that are centered on a vertically oriented central pivoting shaft. These are contained in a spherical enclosure having openings on the interior and outside to permit movement when the door rotates within the enclosure.

Revolving doors can be run either manually or mechanically.If something is a "revolving door," it means that people or other items are constantly coming and going rather than remaining in one place: Ten directors came and departed over a twelve-year period, making the department a revolving door for senior executives.

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It is not speeding up. It will therefore move 6 meters per second. The speed would have increased by 6 m/s per second if the item had been accelerating and the speed had been in the plane of the speed.

an object is moving at a constant speed, can it accelerate Yup Many individuals initially find this counter-intuitive because they overlook the fact that acceleration can still occur even when an object maintains a constant speed.

A motion of an object that does not alter over time is referred to as a constant acceleration. A car's average speed increases if it goes from 20 mph to another 20 mph in a minute.

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Fermat's Theorem states that the path taken by a wave traveling from one point to another in a medium is the path that takes the least time, which is applicable in fluid dynamics to explain why fluids tend to follow the path of least resistance.

Fermat's theorem, also known as the "principle of least time," states that the path taken by a wave traveling from one point to another in a medium is the path that takes the least time.

In fluid dynamics, this principle is used to explain why fluids tend to follow the path of least resistance, as they seek to minimize the time it takes to move from one point to another. This results in the fluid flowing along the path of least energy, which is also known as the path of least resistance. The principle of least time is used to predict the behavior of fluids under different conditions, and it is an important concept in the field of fluid dynamics.

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As the volume rises, the equilibrium shifts to the left, favoring the reactants. As the volume is decreased, the equilibrium will shift toward the component of the reaction in which there are fewer moles.

An object is considered to be operating in unstable equilibrium when ever a destructive force is applied if the center of mass is lowered and the object moves from its starting position.

Equilibrium is important for understanding chemical processes since it tells us how the reaction will proceed. We can control the reaction's parameters to help the creation of desirable products while it is in equilibrium. It is also used to calculate the final reaction mixture's composition.

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(a) The number of waves on the diagram is 2.

(b) The period of the of the oscillation of the wave is 0.4 second.

(c) The frequency of the wave is 2.5 Hz.

The number of waves on the diagram is determined by calculating the number of cycles.

number of waves = 2

The period of the of the oscillation of the wave or the time taken to make a complete cycle is calculated as;

T = 0.4 seconds

The frequency of the wave is the reciprocal of the period of the wave and it is calculated as follows;

f = 1/T

f = 1 / 0.4

f = 2.5 H

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The required force between the two charges, when the distance between them is specified is calculated to be 416.67 N.

The charge q₁ is given as 0. 00005 C.

The charge q₂ is given as 0. 00003 C.

The separation (r) between the two charges is given as, 1.8 m.

The expression to find out the force between two charges is given as,

F = k q₁ q₂/r²

where,

k is relative permittivity (9 × 10⁹N)

q₁, q₂ are charges

r is separation between charges

Substituting the known values,

F = k q₁ q₂/r² = (9 × 10⁹× 5 × 10⁻⁴ × 3 × 10⁻⁴)/1.8² = 1350/1.8² = 416.67 N

Thus, the required force is calculated to be 416.67 N.

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To a from b Electrons through a circuit from of the negative to the positive end, slowing the movement of electrons as they circle the wire.

A material's ability to oppose the electron flow that passes through it is referred to as resistance. It limits how much electrons may go through the substance. It is measured by ohms () and indicated by the symbol (R). Free electrons begin to accelerate when voltage is introduced across the resistor.

resistive energy dissipation A charge loses potential energy (Qu) as it passes through a resistor, where V is just the potential difference across the resistor force .

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Thermionic emission is the thermally convinced inflow of charge carriers and vaporization is the process in which the liquid state changes into the vapor state.

Thermionic emission is the thermally convinced inflow of charge carriers from a face or over an implicit- energy barrier. This occurs as we know that the thermal energy which is given to the carrier overcomes the work function of the material.

Vaporization is the process in which the liquid state changes into the vapor state. Also when the temperature increases, the kinetic energy of the molecules increases. Due to this increase in kinetic energy, the force of attraction between the molecules reduces, which in turn escape into the surrounding in the form of vapors.

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Answer:

0

Explanation:

The linear expansivity of a material is the fractional increase in length for a unit increase in temperature. To calculate linear expansivity for a length of 120m that assumed a new length of 120.0 when heated through a temperature of 100°C, you would use the following formula:

Linear Expansivity = (New Length - Original Length) / (100°C - 0°C)

Therefore, the linear expansivity of the material in this example would be:

Linear Expansivity = (120.0 - 120.0) / (100°C - 0°C)

Linear Expansivity = 0.

Answer:

The linear expansivity of length 120m when heated through a temperature of 100°C can be calculated by using the following equation: ΔL/L × (1 / T) = α, where ΔL is the change in length, L is the original length, T is the temperature and α is the linear expansivity. In this case, ΔL would be 0, as the original and new length are the same. Therefore, the linear expansivity of length 120m when heated through a temperature of 100°C is 0. Here is a Brainly link that can provide you with more information on linear expansivity: https://brainly.com/question/5861312.

The required maximum mass that the beam can bear without slipping is 14.163 kg.

The maximum mass that a 4.0 m long steel beam with a cross-sectional area of 1.0 × 10²m² and a Young's modulus of 2.0 × 10' N/m² can bear without slipping when wedged horizontally between two vertical walls and compressed by 0.020 mm, assuming a coefficient of static friction of 0.70, is calculated as follows,

Force of friction = coefficient of static friction × normal force = Area of beam × Young's modulus × compression

Therefore, the force of friction = 0.70 × (1.0 × 10² m²) × (2.0 x10' N/m²) × 0.020 mm

Maximum mass = (force of friction) / (acceleration due to gravity)

Therefore, the maximum mass that the beam can bear without slipping is (0.70 × (1.0 × 10² m²) × (2.0 × 10' N/m²) × 0.020 mm) / (9.81 m/s²) = 14.163 kg.

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Coulomb's Law states that the force exerted between two electric charges is negatively correlated to their square of distance. As a result, if the range is doubled, its force will be nine times weaker.

Distance can be defined as the amount of space an object has covered, regardless of its start or ending position.

 Keep in mind that distance between two points and the distance travelled between them are not the same.

A pressure is the modification of an object's state brought on by its surroundings. Forces will cause an object.

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The energy that is removed from the system as heat is  139.8 J.

Internal energy is the total energy of a thermodynamic system, including the kinetic energy of its constituent particles and their potential energy due to their relative positions and interactions. It is a measure of the total thermal energy of a system and is a function of temperature, pressure, and volume.

We know that the work done can be obtained by the use of the equation;

w = PΔV

Then

w = 7.07 × 10^5 * 1.1 × 10^−4

w = 77.8 J

Then we have that;

E = q + w

-62 J = q + 77.8

q = 77.8 + 62

= 139.8 J

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Therefore the speed at the ground is 185. 3 m/s.

horizontal speed = 485 km/hr

= 485 * (5/18)

= 134.72m/s

h = 875 m

g = 9.8 m/s^2

a) Using formula,

h = (1/2) gt^2

875 = (9.8/2) t^2

t = 13.36 seconds

b)

D = u * t

D = 131.11 * 13.36

D = 1751.64 m

D = 1.75 km

c) when it lands on the ground

Vx = 131.11 m/s

Vy = gt

= 9.8 * 13.36

= 130.9 m/s

Therefore the speed at ground = [ 131.11^2 + 130.9^2]^(1/2)

= 185. 3 m/s

The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.

Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.

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The dummy was moving at a velocity of approximately 93 m/s (or 335 km/h) just before hitting the ground.

Find the velocity of the dummy when the jetpack fails,

v = u + at

where v is final velocity, u is initial velocity (which is 0 m/s in this case), a is acceleration (which is 3 m/s^2 in the upward direction), and t is time (which is 9 seconds).

v = 0 + (3 m/s^2)(9 s) = 27 m/s

Distance traveled,

s = (1/2)at^2

s = (1/2)(-9.8 m/s^2)(9 s)^2

s = -441 m (taking upward direction as positive)

Here, we have taken the upward direction as positive and the negative value of s indicates that the dummy fell a total distance of 441 meters after the jetpack failed.

v^2 = 0 + 2(-9.8 m/s^2)(-441 m)

v^2 = 8623.6 m^2/s^2

v = 93 m/s (approx)

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Answer:

Explanation:

Momentum (p) = mass(m) x velocity(v)

v = 12m/sec , m= 20kg

p=20*12 = 240 kg m s−1 or 240 Ns

The radiation radiated from an area A on a black body at actual temperature T is directly in proportion to the fourth power of a temperature, according to Stefan Boltzmann's law.

What significance do ratio and proportion have?

The ratio and ratio are important building blocks for understanding the numerous ideas in science and mathematics. Several challenges in daily life can be solved with proportion, including those in business when handling transactions or in the kitchen, among other situations. It creates a relationship among two or more numbers and aids in comparing them.

What would a proportional statement look like in practice?

For instance, the proportion statement for the ratio 45 is 20/25 = 45. This proportional statement can be solved to yield: The relationship between two quantities, such as a:b, when b is not equal to 0, is thus defined by the ratio. Example: 2:4 = 1:2 is used to show the proportion of 2 to 4. Here, it is claimed that the statement is in proportion.

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Answer:

D) πR/7,200 m/s

Explanation:

Let's call the speed of the moon "v".

We know that the period (T) of the moon is given by: T = 20 hours = 20 hours * 3600 seconds/hour = 72000 seconds

We can relate the speed of the moon to its period and distance using the formula:

v = 2πR/T, where R is the distance of the moon from the center of the planet.

In this case, the distance is 5R, so:

v = 2π(5R)/T

= 2π(5R)/72000 seconds

= (πR)/7,200 seconds

So the speed of the moon is (πR)/7,200 m/s.

Therefore, the answer is D) πR/7,200 m/s.

The velocity needed to have the trainee experience 5 g's of acceleration is approximately 15.74 m/s.

What is the acceleration ?

Acceleration is the rate of change of velocity of an object over time. The SI unit of acceleration is meters per second squared (m/s2). Acceleration can be positive, negative, or zero. Positive acceleration means the object is speeding up, negative acceleration indicates the object is slowing down, and zero acceleration indicates the object is not changing speed or direction.

The acceleration experienced by an object moving in uniform circular motion is given by:

[tex]\mathbf{a = v^2 / r}[/tex]

where a is the acceleration, v is the velocity, and r is the radius of the circular path.

In this case, we want the trainee to experience an acceleration of 5 g's, which is 5 times the acceleration due to gravity

(g) = 5 × 9.81 m/s²

= 49.05 m/s²

The radius of the circular path is half the length of the horizontal arm, or

r = 5.00m/2

= 2.50 m.

Substituting these values into the equation for acceleration, we get:

49.05 m/s² = v² / 2.50 m

Solving for v, we get:

[tex]\mathrm{v = \sqrt{49.05 m/s^2 \times 2.50 m} }[/tex]

v = 15.74 m/s

Therefore, the velocity needed to have the trainee experience 5 g's of acceleration is approximately 15.74 m/s.

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According to the solving using gravitational law the earths  its orbital period = 5.6 hours.

Every particle in the universe is drawn to every other component with a force that is directly related to the product between their masses and inversely proportional to their separation from one another, according to Newton's Law of Universal Gravitation. As a result, the general gravitation equation takes shape. F ∝ m 1 m 2 r 2.

Newton's first law asserts that an object at rest will stay at rest and also an object in motion will keep moving at a fixed pace unless they are both subject to a net external force.

The strength of attraction between two particles can be expressed as follows, according to Newton's gravitational law:

F = [tex]G\frac{M_1M_2}{R^2}[/tex]

speed of satellite = v = 5000 m/s

mass of earth = M = 6 × 10²⁴ kg

orbital period = T = ?

∑F = ma

[tex]G\frac{mm_2}{R^2}[/tex] = M[tex]\frac{v^2}{r}[/tex]

Substituting the value we get:

T = 2πG[tex]\frac{M}{v^3}[/tex]

T = 2π ×  6.67 × 10⁻¹¹ [tex]\frac{ 6 * 10^2^4}{5000^3}[/tex]

T = 20116s

T = 5.6 hours.

According to the solving the earths  its orbital period = 5.6 hours.

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The ball was thrown a total distance of 52.7 meters. The maximum height of the ball is 8.8 meters.

The distance refers to the amount of space between two points. It is typically measured in units of length such as meters, kilometers, or miles. Distance can also be measured in terms of time, as in the distance between two points in terms of the amount of time it takes to travel between them. Distance is an important concept in mathematics and can be used to calculate the length of a line, the area of a shape, or the volume of an object.

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