mr.easton is 80 , and he thinks that all young people with longer hair use drugs .this is an example of:
Will mark brainliest pls help
Answer: Use the x/t = v formula!!! x is distance, t is time, and v is velocity. you just need to do 40 / 5 = 8 and 100 / 15 = 6.66
A daredevil on a motorcyclo attempts to clear a 420-meter-wide river from a 210-meter-high cliff. What must his initial horizontal velocity
be?
Answer:
His initial velocity (speed) must be 64.16 m/s.
Explanation:
Horizontal Motion
When an object is horizontally launched at a speed v from a height h, the maximum horizontal distance (also called Range) traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
Our daredevil is attempting to clear a river d=420 m wide with his motorcycle from a cliff h=210 m high. We need to find the speed needed to safely reach the opposite edge of the river.
From the above equation, we solve for v:
Speed:
[tex]\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}[/tex]
[tex]\displaystyle v=420\cdot\sqrt{\frac {9.8}{2\cdot 210}}[/tex]
[tex]\displaystyle v=420\cdot\sqrt{\frac {9.8}{420}}[/tex]
v = 64.16 m/s
His initial velocity (speed) must be 64.16 m/s.
A certain sound wave has a wavelength of 2 m and a frequency of 170 hertz. calculate the velocity of this wave.
Answer:
340m/s
Explanation:
Given parameters:
Wavelength = 2m
Frequency = 170Hz
Unknown:
Velocity of the wave = ?
Solution:
The velocity of the wave is the product of frequency and wavelength of the wave;
V = F λ
V is the velocity
F is the frequency
λ is the wavelength
Insert the parameters and solve;
V = 2 x 170 = 340m/s
The velocity of the wave with the given wavelength and frequency is 340m/s.
Given the data in the question;
Wavelength; [tex]\lambda = 2m[/tex]Frequency; [tex]f = 170Hz = 170 s^{-1}[/tex]Velocity; [tex]v =\ ?[/tex]
To determine the velocity of the wave, we use the expression for the relations between wavelength, frequency and speed.
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed.
We substitute our given values into the equation
[tex]2m = \frac{v}{170s^{-1}}\\\\v = 2m * 170s^{-1}\\\\v = 340m/s[/tex]
Therefore, the velocity of the wave with the given wavelength and frequency is 340m/s.
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how (and why) does a planet change its speed while in orbit?
please help asap!!!
Answer:
A planet's orbital speed changes, depending on how far it is from the Sun. The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.
Explanation: hope that helps :)
compared to a maritime tropical air mass, a maritime polar air mass has?
A maritime polar air mass has relatively higher moisture and is relatively cooler than the tropical air mass.
Air masses:Maritime polar (mP) is cold but moist due to its origination over the oceans. The desert region air masses (hot and dry) are designated by ‘cT’ for ‘continental tropical’. As these air masses move around the earth they can begin to acquire additional attributes.
The continental Tropical (cT) air mass originates in arid or desert regions in the middle or lower latitudes, principally during the summer season. It is strongly heated in general, but its moisture content is very low.
Continental tropical air masses are extremely hot and dry. Arctic, Antarctic, and polar air masses are cold. The qualities of arctic air are developed over ice and snow-covered ground. Arctic air is deeply cold, colder than polar air masses
Maritime Polar (mP) air masses develop over the polar areas of both the Northern and the Southern hemispheres. They generally contain considerably more moisture than the cP air masses. As they move inland in middle and high latitudes, heavy precipitation may occur.
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I WILL GIVE BRAINLIEST!!!!!!
An inclined plane makes work easier by decreasing force. This means, it must also _____.
decrease work
increase weight
increase distance
decrease distance
Answer:
increase distance
Explanation:
Inclined planes make it easier to move objects to a higher elevation. The sloping surface of the inclined plane supports part of the weight of the object as it moves up the slope. As a result, it takes less force to move the object uphill.
Answer:
Hello your answer would be increase of distance
Explanation:
I know that because than you would have to go upward with the object.
A paper airplane moves at a constant velocity of 10 m/s to the east when there is no wind of 19 m/s begins to blow?
Answer: So if the steady easterly wind of 19 m/s begins to blow more than the 10 m/s it just needs more wind and direction So the resultant has to be 29 m/s east.
A 0.145 kg baseball is flying at a height of 2.50 m. How much potential energy
does the ball have?
Gravitational potential energy is the energy stored in an object as the result of its vertical position or height. It can be calculated as its weight times the height. This is:
[tex]\boxed{U_g=W\cdot h=mgh}[/tex]
Where:
W is the weight of the object m is the mass g is gravitational acceleration h is the heightEvaluating:
[tex]U_g = (0.145\;kg)(9.8\;m/s^2)(2.50\;m)\\\\\boxed{U_g=3.5525\;J}[/tex]
R/ The ball has 3.5525 J of potential energy.
A rifle recoils from firing a bullet. The speed of the rifle’s recoil is small compared to the speed of the bullet because the rifle has a great deal more ____ than the bullet.
a. force
b. speed
c. distance
d. mass
Answer: mass
Explanation:
i remember my teacher saying it lol
A rifle recoils from firing a bullet. The speed of the rifle’s recoil is small compared to the speed of the bullet because the rifle has a great deal more mass than the bullet.
What is mass?Mass is a numerical measure of inertia, which is a basic feature of all matter. It is, in effect, a body of matter's resistance to a change in speed or position caused by the application of a force.
In the International System of Units (SI), the kilogram is the unit of mass.
A rifle recoils from firing a bullet. The speed of the rifle’s recoil is small compared to the speed of the bullet because the rifle has a great deal more mass than the bullet.
Hence d is the correct option.
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A +4.0 uC charge is placed on the x axis at x= +3.0 m, and a -2.0 uC is located on the y-axis at y= -1.0 m. Point A is on the y axis at y= +4.0 m. Determine the electric potential at point A (relative to zero at the origin).
Answer:
The potential is [tex]V_A = 9600 \ V[/tex]
Explanation:
From the question we are told that
The magnitude of the charge is [tex]q_1 = 4 \mu C = 4*10^{-6} \ C[/tex]
The position of the charge is [tex]x = + 3.0 \ m[/tex]
The magnitude of the second charge is [tex]q_2 = -2.0 \mu C = -2.0 *10^{-6} \ C[/tex]
The position is [tex]y_1 = - 1.0 \ m[/tex]
The position of point A is [tex]y_2 = + 4.0 \ m[/tex]
Generally the electric potential at A due to the first charge is mathematically represented as
[tex]V_a = \frac{k * q_1 }{r_1 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_1[/tex] is the distance between first charge and a which is mathematically represented as
[tex]r_1 = \sqrt{x^2 + y_2 ^2 }[/tex]
=> [tex]r_1 = \sqrt{3^2 + 4 ^2 }[/tex]
=> [tex]r_1 = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * 4*10^{-6} }{5 }[/tex]
[tex]V_a = 7200 \ V[/tex]
Generally the electric potential at A due to the second charge is mathematically represented as
[tex]V_b = \frac{k * q_2 }{r_2 }[/tex]
Here k is the coulombs constant with value [tex]k = 9*10^{9} \ \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}[/tex]
[tex]r_2[/tex] is the distance between second charge and a which is mathematically represented as
[tex]r_2 = y_2 - y[/tex]
=> [tex]r _2 = 4.0 - (-1.0)[/tex]
=> [tex]r = 5 \ m[/tex]
So
[tex]V_a = \frac{9*10^9 * -2*10^{-6} }{5 }[/tex]
[tex]V_a = -3600 \ V[/tex]
So the net potential difference at point A due to the charges is mathematically represented as
[tex]V_n = V_a + V_b[/tex]
=> [tex]V_n = 7200 - 3600[/tex]
=> [tex]V_n = 3600 V[/tex]
Generally the net potential difference at the origin due to both charges is mathematically represented as
[tex]V_N = V_c + V_d[/tex]
Here
[tex]V_c = \frac{k * q_1 }{x}[/tex]
=> [tex]V_c = \frac{9*10^9 * 4*10^{-6} }{3}[/tex]
=> [tex]V_c = 12000 V[/tex]
and
[tex]V_d= \frac{k * q_2 }{y}[/tex]
=> [tex]V_c = \frac{9*10^9 * -2*10^{-6} }{1}[/tex]
=> [tex]V_c =- 18000 V[/tex]
Generally the net potential difference at the origin is
[tex]V_N = 12000 - 18000[/tex]
=> [tex]V_N = -6000[/tex]
Generally the potential difference at A relative to zero at the origin is mathematically evaluated as
[tex]V_A = V_n - V_N[/tex]
=> [tex]V_A = 3600 - (-6000)[/tex]
=> [tex]V_A = 9600 \ V[/tex]
What is the x component of this vector: 8 N [North 50 degrees East]?
Answer:
Explanation:
Given
Force = 8N
Direction = N50°E
Required
x component of the Force
Fx = F cos theta
Fx = 8cos 50°
Fx = 8(0.6428)
Fx = 5.1423N
Hence the x component of the force is 5.1423N
Ejercicio 1: Un cuerpo gira en un círculo de 8cm de diámetro con una rapidez constante
de 7km/h. ¿Cuál es la aceleración centrípeta expresada en m/s? Recordar que el radio es
la mitad del diámetro.
Ejercicio 2: Las cargas están interactuando en un medio desconocido con una fuerza de
-5N con una separación de 40cm teniendo sus respectivas cargas de 3.5 milicoulombs y
6 milicoulombs.
Answer:
Exercise 1;
The centripetal acceleration is approximately 94.52 m/s²
Explanation:
1) The given parameters are;
The diameter of the circle = 8 cm = 0.08 m
The radius of the circle = Diameter/2 = 0.08/2 = 0.04 m
The speed of motion = 7 km/h = 1.944444 m/s
The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²
The centripetal acceleration ≈ 94.52 m/s²
A sound source produces 85 sound wave compressions in 5 seconds. the wave length of the sound is 20m. calculate the
a)frequency of the sound waves
b)the speed of the wave
Answer: it would be 14.1 mm
Explanation: Sound is a wave. More specifically, sound is defined to be a disturbance of matter that is transmitted from its source outward. A disturbance is anything that is moved from its state of equilibrium. Some sound waves can be characterized as periodic waves, which means that the atoms that make up the matter experience simple harmonic motion.
A vibrating string produces a sound wave as illustrated in Figure 14.2, Figure 14.3, and Figure 14.4. As the string oscillates back and forth, part of the string’s energy goes into compressing and expanding the surrounding air. This creates slightly higher and lower pressures. The higher pressure... regions are compressions, and the low pressure regions are rarefactions. The pressure disturbance moves through the air as longitudinal waves with the same frequency as the string. Some of the energy is lost in the form of thermal energy transferred to the air. You may recall from the chapter on waves that areas of compression and rarefaction in longitudinal waves (such as sound) are analogous to crests and troughs in transverse waves.
The frequency of sound waves is 144.1 m.
What is Sound waves?More specifically, sound is defined to be a disturbance of matter that is transmitted from its source outward. A disturbance is anything that is moved from its state of equilibrium.
Some sound waves can be characterized as periodic waves, which means that the atoms that make up the matter experience simple harmonic motion.
This creates slightly higher and lower pressures. The higher pressure... regions are compressions, and the low pressure regions are rarefactions. The pressure disturbance moves through the air as longitudinal waves with the same frequency as the string.
Therefore, The frequency of sound waves is 144.1 m.
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You accelerate from 2m/s to 6m/s while traveling a distance of 2m; what was your acceleration?
A.4 m/s^2
B.8 m/s^2
C.12 m/s^2
D.16 m/s^2
Answer:
The acceleration is 8 m/s²
Explanation:
The given parameters are;
The initial velocity, u = 2 m/s
The final velocity, v = 6 m/s
The distance the acceleration took place, s = 2 m
The acceleration, a, can be found from the following kinematic equation;
v² = u² + 2·a·s
By substituting the values, we have;
6² = 2² + 2 × a × 2
6² - 2² = 2 × a × 2
32 = 4·a
a = 32/4 = 8 m/s²
The acceleration, a, of the given motion = 8 m/s².
The velocity of a vehicle is typically
expressed relative to which of the following?
Answer:
e
Explanation:
e
why is it, that no matter what we do in life, we die.
Answer:
the time comes eventually.
Explanation:
ur body just be giving up
Three hikers take three different paths to the top of a mountain, Paths 1, 2, and 3. The hikers are all the same height and weight.
When all of the hikers are at the finish point at the top of the mountain, which hiker will have the greatest amount of gravitational potential energy?
A)The gravitational potential energy is the same for all of the hikers.
B)The hiker who took Path 1
C)The hiker who took Path 2
D)The hiker who took Path 3
Answer: a
Explanation:
cause i took a test and that is what my science teacher said
Option A - The gravitational potential energy is the same for all of the hikers is correct.
We have three hikers who took three different paths to the top of a mountain labelled as paths 1, 2, and 3. The hikers are all the same height and weight.
We have to find which hiker will have the greatest amount of gravitational potential energy at the top.
What is the gravitational potential energy of the body of mass ' m ' at a height ' h ' above the surface of earth (h <<R)?The formula to calculate the gravitational potential energy is -
U (h) = mgh
In the question given to us -
Mass of each hiker is same = m kg
Height of each hiker at top is same = h meters
The gravitational Potential Energy of a body is independent of the path taken. Since the mass and height of each hiker is same, therefore -
U (h[1]) = U(h[2]) = U(h[3]) = mgh
Hence, Option A is correct.
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why is it more difficult to revolve a stone by tieing it in a longer string then by tieing it to a shorter string
A box with a mass of 100.0 kg slides down a ramp with
a 50 degree angle.
What is the weight of the box?
N
What is the value of the normal force? Round the
answer to the nearest whole number.
N
What is the acceleration of the box? (Disregard friction
and air resistance.) Round the answer to the nearest
tenth.
m/s2
Answer:
Weight of the box? 980 N
Value of the normal force? 630 N
Acceleration of the box? 7.5 m/s^2
Explanation:
I got the answer right
A 20 g bullet is shot from a 10 kg gun with a velocity of 400 m/s. What
is the speed of recoil of the gun?
Answer: -.80m/s
Explanation:
For a given radius, what happens to the angular acceleration as linear acceleration increases?
Linear acceleration and angular acceleration are directly proportional. The greater the linear acceleration, the larger the angular acceleration.
For example, the greater the angular acceleration of a bike's wheels, the greater the acceleration of the bike.
An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the time it takes the object to complete one horizontal circle?
P.S. : I know the answer is 1.18 seconds but I just don’t know how to get there. Can someone explain to me how to do it? Thanks
Answer:
The object takes approximately 1.180 seconds to complete one horizontal circle.
Explanation:
From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration ([tex]a[/tex]), measured in meters per square second, is entirely centripetal and is expressed as:
[tex]a = \frac{4\pi^{2}\cdot R}{T^{2}}[/tex] (1)
Where:
[tex]T[/tex] - Period of rotation, measured in seconds.
[tex]R[/tex] - Radius of rotation, measured in meters.
If we know that [tex]a = 26.36\,\frac{m}{s^{2}}[/tex] and [tex]R = 0.93\,m[/tex], then the time taken by the object to complete one revolution is:
[tex]T^{2} = \frac{4\pi^{2}\cdot R}{a}[/tex]
[tex]T = 2\pi\cdot \sqrt{\frac{R}{a} }[/tex]
[tex]T = 2\pi\cdot \sqrt{\frac{0.93\,m}{26.36\,\frac{m}{s^{2}} } }[/tex]
[tex]T \approx 1.180\,s[/tex]
The object takes approximately 1.180 seconds to complete one horizontal circle.
if the velocity is at 0 and the accelerationis at 0 what is the motion
Given the following blackbody curve graph, what color will Star A be? Blue Red White Yellow
Answer:
I think white is the colour of star A.
Answer:
yellow
Explanation:
i don’t know what to put here but i just wanna leave
what can cause a magnetic domain to form?
A. iron atoms being closed together
B. magnetic material being placed close to a magnet
C. electric current flowing through iron
D. magnetic fields of atoms being aligned with each other
Answer:
D
Explanation:
Magnetic domains are always present in ferromagnetic materials due to the way the atoms bond to form the material. However, when a ferromagnetic material is in the unmagnetized condition, the magnetic domains are randomly oriented so that the magnetic field strength in the piece of material is zero.
Answer:
D. magnetic fields of atoms being aligned with each other
Explanation:
Which of the following provides evidence that there must be at least two types of electrical charge, but that there is only one type of mass?
A.) The magnitude of the Coulomb's law constant differs greatly from the magnitude of the universal gravitational constant.
B.) Contact forces such as friction are caused primarily by electrostatic forces and not by gravitational ones.
C.) The electric force has a relative strength that is much greater than the strength of the gravitational force.
D.)On the scale of the solar system, electric forces cancel out and gravitational forces dominate.
Answer:
Option D (On the...............dominate) would be the right approach.
Explanation:
The Gravitational constant (G) will be:
= [tex]6.67\times 10^{-11}[/tex]
The Coulomb's law constant (K) will be:
= [tex]9\times 10^9[/tex]
Throughout particular, these have been determined that among 2 substances with almost the similar form of charge, the combination of electromagnetic as well as the force does seem to be usually the following:⇒ [tex]\frac{f_e}{f_g}\sim 10^{42}[/tex]
By that same argument, the electrostatic force including its planet's atmosphere would have strongly influenced the effect, as well as maybe the planet's atmosphere, would have crashed, or perhaps the earth would have shifted at a much longer exposure from one another and.Throughout particular, astronomical distance statutory framework that gravity seems to be predominant, whereas electrostatic forces have been generally ignored. It is quite since there are so many categories of allegations throughout the planet's atmosphere that balance out someone else's effects, there's only yet another form of momentum, because although the forces are still cumulative, as well as therefore offering to help everything hold to the universe, encouraging the universe just to rotate across the sun.The latter three choices aren't connected to either the situation mentioned in the clarification segment elsewhere here.
The statement that provides evidence that there must be at least two types of electrical charge, but that there is only one type of mass is that on the scale of the solar system, electric forces cancel out and gravitational forces dominate.
The examples that provides conclusive evidence of is option d because the Gravitational constant is (G)=6.67*10-11 while the Coulomb's law constant(K)=9*109.
Coulomb's law often connotes that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.The interaction between charged objects is regarded as a non-contact force that acts over some distance of separation.
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Anyone can help me with this
Answer:
this is in the middle of the wheel and helps it rotate it is an axle
when analyzing a position time graph the direction of the slope positive or negative tells us:
Answer:
Explanation:
Positive values for position indicate that the object is in front of the starting point and negative values tell us that the object is behind the starting point. (time = 9.5, position = 0) the object is at the starting point.
Answer:
Positive values for position indicate that the object is in front of the starting point and negative values tell us that the object is behind the starting point. (time = 9.5, position = 0) the object is at the starting point.
Explanation: