What evidence supports the claim that social media
had more of an influence outside of the Arab world than
inside it?
Sixty five percent of Egyptians do not use the
internet at all
Eighty four percent of internet users visit social
networking sites for political news,
College educated people are more likely to use the
internet
Social media sites use bitly links to help spread
information

Answer:

d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.

Explanation:

The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and  a single bond between each nitrogen to it respective hydrogen.

Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).

The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.

Answer:

d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.

Explanation:

The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and  a single bond between each nitrogen to it respective hydrogen.

Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).

The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.

After 3 half-life, 12 of the 14 of the C-14 = 18 of the C-14 would remain.

Explanation:

Molarity = mol/liter

Solution 240 mL = NaCl 9.0 g

Solution 1000 mL = NaCl 9.0/240 × 1000 = ..... g

mol NaCl = g/MW

MW NaCl = ?....

...........

Molarity = ......... Molar

Answer:

Explanation:

Fe₂O₃(s) + 3H₂(g)  =  2Fe (s) + 3H₂O - 98.8 kJ .

one mole of ferric oxide reacts with 3 mole of hydrogen to give 2 mole of iron and 3 mole of water .   98.8 kJ of heat is absorbed .

Answer:

The percentage is   k  [tex]= 20.8[/tex]%

Explanation:

From the question we are told that

    The mass of the stibnite is  [tex]m_s = 5.86 \ g[/tex]

   The volume of   KBrO3(aq) is  [tex]V = 26.6 mL = 26.6 *10^{-3} \ L[/tex]

     The concentration  of   KBrO3(aq) is  [tex]C = 0.125 M[/tex]

Now the balanced ionic  equation for this reaction is

        [tex]BrO_3 ^{-}+ 3Sb^{3+} + 6H^{+} \to Br^{1-} + 3Sb^{5+} + 3H_2O[/tex]

The number of moles of   [tex]BrO_3 ^{-}[/tex] is  

     [tex]n = C *V[/tex]

substituting values

     [tex]n = 26.6*10^{-3} * 0.125[/tex]

     [tex]n = 0.003325 \ mols[/tex]

from the reaction we see that 1 mole of [tex]BrO_3 ^{-}[/tex]  reacts with 3 moles of  [tex]Sb^{3+}[/tex]

so 0.003325 moles will react with x moles of  [tex]Sb^{3+}[/tex]

Therefore

               [tex]x = \frac{0.003325 * 3}{1}[/tex]

              [tex]x = 0.009975 \ mols[/tex]

Now the molar mass of [tex]Sb^{3+}[/tex] is a constant with a values of  [tex]Z = 121.76 \ g/mol[/tex]

Generally the mass of  [tex]Sb^{3+}[/tex] is mathematically represented as

        [tex]m = x * Z[/tex]

substituting values

        [tex]m = 1.215 \ g[/tex]

The percentage of  Sb(antimony) in the overall mass of the stibnite is mathematically evaluated as

            k  [tex]= \frac{1.215}{5.85 } * 100[/tex]

           k  [tex]= 20.8[/tex]%

Answer:

Explanation:

Step 1: Data given

Mass of stibnite (Sb2S3) = 5.85 grams

The Sb3+(aq) is completely oxidized by 26.6 mL of a  0.125 M aqueous solution of KBrO3(aq).

Step 2: The balanced equation

BrO3-(aq)+ 3Sb^3+(aq) + 6 H+ → Br-(aq) + 3Sb^5+(aq) + 3H2O (l)

Step 3: Calculate moles KBrO3

Moles KBrO3 = molarity * volume

Moles KBrO3 = 0.125 M *0.0266 L

Moles KBrO3 = 0.003325 moles

Step 4: Calculate moles Bro3-

in 1 mol KBrO3 we have 1 mol K+ and 1 mol BrO3-

In 0.003325 moles KBrO3 we have 0.003325 moles BrO3-

Step 5: Calculate moles Sb

For 1 mol BrO3- we need 3 mol Sb^3+ to produce 1 mol Br- and 3 mol Sb^5+

For 0.029085 moles BrO3- we need 3*0.003325 = 0.009975 moles Sb

Step 6: Calculate mass Sb

Mass Sb = moles Sb * molar mass Sb

Mass Sb = 0.009975 moles * 121.76 g/mol

Mass Sb = 1.21 grams

Step 7: Calculate the percentage of Sb in the ore

% Sb = (mass Sb / total mass) * 100%

% Sb = (1.21 grams / 5.85 grams) * 100 %

% Sb = 20.76 %

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

Answer:

The solid phase has the lowest entropy.

Explanation:

Entropy (S) is the measure of how  spread out or dispersed the energy of a system is among the different possible ways  that system can contain energy. The greater the dispersal, the greater is the entropy.

In a solid, the atoms or molecules  are confined to fixed positions, thus, the dispersal is minimal and the entropy is at its lowest.

Answer:

a: 1 amu

b: +1

c: neutron

d: 1 amu

Explanation:

Answer:

A. 4Ni(s) + 3O2(g) —> 2Ni2O3(s)

B. Synthesis reaction.

C. 18.31g of O2

Explanation:

A. The equation for the reaction.

Ni(s) + O2(g) —> Ni2O3(s)

The above equation can be balance as follow:

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by putting 2 in front Ni2O3 and 3 in front of O2 as shown below:

Ni(s) + 3O2(g) —> 2Ni2O3(s)

There are 4 atoms of Ni on the right side and 1 atom on the left it can be balance by putting 4 in front of Ni as shown below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Now the equation is balanced

B. From the equation, we can see that two reactants combined to form a single product. Therefore, the reaction is termed synthesis reaction.

C. We'll begin by calculating the mass of Ni and O2 that reacted from the balanced equation. This is illustrated below:

4Ni(s) + 3O2(g) —> 2Ni2O3(s)

Molar mass of Ni = 59g/mol

Mass of Ni from the balanced equation = 4 x 59 = 236g

Molar mass of O2 = 16x2 = 32g/mol

Mass of O2 from the balanced equation = 3 x 32 = 96g

Summary:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Now, we can obtain the mass of O2 needed to react with 45g of Ni as follow:

From the balanced equation above,

236g of Ni reacted with 96g of O2.

Therefore, 45g of Ni will react with = (45 x 96)/236 = 18.31g of O2.

Therefore, 18.31g of O2 is needed to react with 45g of Ni

Answer:

- 12.1

Explanation:

M(C3H8O3) = 3*12.0 + 8*1.0 + 3*16.0 = 92 g/mol

210.0 g C3H8O3 * 1 mol C3H8O3/92 g C3H8O3 = 210/92 mol C3H8O3

350.g = 0.350 kg H2O

Molality = mol soluty/ kg solvent = (210/92 mol C3H8O3) /(0.350 kg H2O) = =6. 522 molal

ΔT =i* Kf* m

(T2 - T1) = i* Kf* m

(T2 - 0°C) = 1*(-1.86°C/molal *6.522 molal)

T2= - 12.1°C

The change in freezing point and the new freeze point are -12.1°C and -12.1°C.

Given the following data:

We know that the temperature at which water freezes is 0°C.

To determine the change in freezing point and the new freeze point:

First of all, we would determine the molar mass of glycerol:

Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = [tex]12 \times (1 \times 8)\times (16 \times 3)[/tex]

Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = [tex]12 \times (8)\times (48)[/tex]

Molar mass of glycerol ([tex]C_3H_8O_3[/tex]) = 92 g/mol.

Next, we would find the number of moles of glycerol that is required:

[tex]Number\;of\;moles = \frac{mass}{molar\;mass}\\\\Number\;of\;moles = \frac{210.0}{92}[/tex]

Number of moles = 2.28 moles

To find the molality concentration:

[tex]Molality = \frac{moles\;of \;solute}{mass\;of \;solvent} \\\\Molality = \frac{2.28}{0.35}[/tex]

Molality = 6.51 molal.

Mathematically, the freezing point elevation of a liquid is given by the formula:

[tex]\Delta T = K_f m[/tex]

Where:

Substituting the parameters into the formula, we have;

[tex]\Delta T = -1.86 \times 6.51[/tex]

Change in temperature = -12.1°C.

Now, we can determine the new freeze point:

[tex]\Delta T = T_n - T_f\\\\T_n = \Delta T + T_f\\\\T_n = -12.1 + 0[/tex]

New freeze point = -12.1°C.

Read more: https://brainly.com/question/13750908

Answer:

Percent yield for chemical reaction = 60%

Explanation:

Given:

Theoretical yield of chemical reaction = 20 gram

Actual yield of chemical reaction = 12 gram

Find:

Percent yield for chemical reaction = ?

Computation:

[tex]Percent\ yield \ for\ chemical\ reaction = [\frac{Actual yield}{Theoretical yield} ]100\\\\Percent\ yield \ for\ chemical\ reaction = [\frac{12}{20} ]100\\\\Percent\ yield \ for\ chemical\ reaction = [0.6 ]100\\\\Percent\ yield \ for\ chemical\ reaction = 60[/tex]

Percent yield for chemical reaction = 60%

Answer:

11

Explanation:

pH=-log(H+)

Answer:

The maximum mass of water produced is  [tex]m__{H_2O}} =116 \ g[/tex]

Explanation:

From the question we are told that

    The mass of  sucrose is [tex]m_s = 200 \ g[/tex]

    The chemical formula for  sucrose is  [tex]C_{12} H_{22} O_{11}[/tex]

The chemical equation for the dissociation of sucrose  is

          [tex]C_{12} H_{22}O_{4} \to 12C + 11H_2O[/tex]

The number of moles of  sucrose can be evaluated as

        [tex]n = \frac{m}{Z}[/tex]

Where Z is the molar mass of sucrose which has a constant value of

      [tex]Z = 342 \ g/mol[/tex]

So  

    [tex]n = \frac{200}{342}[/tex]

   [tex]n =0.585[/tex]

From the chemical equation one mole of sucrose produces 11 moles of water so  0.585 moles of sucrose will produce x moles of  water

Therefore

          [tex]x = \frac{0.585 * 11}{1}[/tex]

         [tex]x = 6.433 \ moles[/tex]

Now the mass of water produced is mathematically represented as

         [tex]m__{H_2O}} = x * Z__{H_2O}[/tex]

 Where  [tex]Z__{H_2O}[/tex] is the molar mass of water with a constant values of  [tex]Z__{H_2O}} = 18 \ g/mol[/tex]

  So  

        [tex]m__{H_2O}} = 6.43* 18[/tex]

       [tex]m__{H_2O}} =116 \ g[/tex]

Answer:

The description including its given problem is outlined in the following section on the clarification.

Explanation:

The given values are:

RBCC = 0.12584 nm

RFCC = 0.12894 nm

The unit cell edge length (ABCC) as well as the atomic radius (RBcc) respectively connected as measures for BCC (α-phase) structure:

√3 ABCC = 4RBCC

⇒  ABCC = [tex]\frac{4RBCC}{\sqrt{3} }[/tex]

⇒             = [tex]\frac{4\times 0.12584}{\sqrt{3}}[/tex]

⇒             = [tex]0.29062 \ nm[/tex]

Likewise AFCC as well as RFCC are interconnected by  

√2AFCC = 4RFCC

⇒  AFCC = [tex]\frac{4RFCC}{\sqrt{2}}[/tex]

⇒             = [tex]\frac{4\times 0.12894}{\sqrt{2} }[/tex]

⇒             = [tex]0.36470 \ nm[/tex]

Now,

The Change in Percent Volume,

= [tex]\frac{V \ final-V \ initial}{V \ initial}\times 100 \ percent[/tex]

= [tex]\frac{(VFCC)unit \ cell-(VBCC)unit \ cell}{(VBCC)unit \ cell}\times 100 \ percent[/tex]

= [tex]\frac{(aFCC)^3-(aBCC)^3}{(aBCC)^3}\times 100 \ percent[/tex]

= [tex]\frac{(0.36470)^3-(0.29062)^3}{(0.29062)^3}\times 100 \ percent[/tex]

= [tex]97.62 \ percent (approximately)[/tex]

Note: percent = %

Answer:

15.63.

Explanation:

So, from the question, we are given the following parameters or data or information for solving this particular Question and they are;

(1). "semi-permeable membrane from the extracellular space ([galactose] = 2 mM) to the cytosol ([galactose] = 10 mM) under biochemically standard conditions. (R = 0.08206 L atm/mol K = 8.314 J/mol  K) (15 pts.) "

(2). "If ATP hydrolysis liberates 30.5 kJ/mol at standard conditions".

(3). " (507.2 g/mol) would be required to transport 260 g of galactose from the extracellular space to the cytosol"

Step one: determine the difference to transport of galactose from extracellular space to cytosol.

This can be done by using the formula below:

Ratio = intracellular/ extracellular.

=> 10/2 = 5 mM.

Step two: so, from statement (2) and (3), the if 507.2 g/mol ATP = 30.5 kJ/mol, then 260 g/mol = ???

Therefore, 260 × 30.5 / 507.2 = 15.63 is the energy required.

Answer:

Polar molecule.

Explanation:

Hello,

In this case, hydrogen sulfate has in its structure sulfur-oxygen and oxygen-hydrogen bonds which are both polar since the electronegativity difference is between 0.7 and 1.7 (0.86 and 1.24 respectively), for that reason, such quality makes hydrogen sulfate a polar molecule, for that reason it is largely soluble in water.

Best regards.

The given question is incomplete, the complete question is:

Given the balanced equation representing a redox reaction:

2Al + 3Cu2+ --> 2Al3+ + 3Cu

Which statement is true about this reaction?

(1) Each Al loses 2e- and each Cu2+ gains 3e-

(2) Each Al loses 3e- and each Cu2+ gains 2e-

(3) Each Al3+ gains 2e- and each Cu loses 3e-

(4) Each Al3+ gains 3e- and each Cu loses 2e-

Answer:

The correct answer is option 2, that is, in the given reaction each of Al loses three electrons and each of the Cu^2+ ion acquires two electrons.

Explanation:

To understand the concept, let us suppose that when an atom A loses an electron, it turns into an atom A^1+, and becomes A^2+ when it loses two electrons. On the other hand, when an atom A gains an electron, it turns into A^1- and becomes A^2- when it acquires two electrons.  

Therefore, in the given case, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu, each of the Al atom turns into Al^3+ when it loses three electrons, and when each of the Cu^2+ ions acquires two electrons, it turns into Cu (Cu^2+ ^2- = Cu).  

Answer:

global warming and destruction of the ozone layer

Explanation:

if Carbon dioxide are high in number , it will cause destruction of the ozone layer which will result to global warming

Answer:

This involves metric conversion and one can easily use dimensional analysis, assuming you know the conversion factors.  

1 ng = 10-9 g, or put another way 109 ng = 1 g

1 kg = 103 g

5.27x10-13 kg x 1 g/1x10-3 kg x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng

Looking at the individual steps and following the units, we have...

5.27x10-13 kg x 1 g/1x10-3 g = 5.27x10-10 g (kg cancel leaving g)

5.27x10-10 g x 1x109 ng/g = 5.27x10-1 ng = 0.527 ng (g cancel leaving ng)

Answer: 7.505

×

10

22

atoms. (rounded to third place of decimal)

Explanation:

Answer:

1.23 g/mL

-18.2%

Explanation:

We need to find the average, which is just the sum of the numbers divided by the number of numbers. Here, the sum will be 1.24 + 1.21 + 1.23 = 3.68 g/mL. There are 3 numbers, so divide 3.68 by 3: 3.68 / 3 ≈ 1.2266...

However, we need to round this and take into account significant figures. Each trial gave a number with 3 significant figures, so we round our number off to three: 1.22666... ≈ 1.23. So, circle the first number under the X column.

We now need to find the percent error, which is RE (%). To calculate this, we take the measured value (1.23 in this case) and subtract the exact value (1.50 here) from it, and then divide that by the exact value:

(1.23 - 1.50) / 1.50 ≈ -0.1822...

Again, we need to round to 3 significant figures, which would make it:

-0.1822... ≈ -0.182

Thus, circle the last number under the RE (%) column.

Answer:

- 622.5kJ

Explanation:

1)      2NH3 + 3N2O ----> 4N2 + 3H2O    ΔH° 1= - 1010kJ

-  3 (N2O  + 3H2     --->  N2H4 + H2O    ΔH° 2 = - 317 kJ)

2)      2NH3 + 3N2O ----> 4N2 + 3H2O        ΔH° 1= - 1010kJ

     - 3N2O   - 9 H2     ----> - 3N2H4 - 3H2O      - 3ΔH° 2 = 3*317 kJ

2NH3  + 3N2H4 --->4N2+9H2,     ΔH° 1 -  3*ΔH° 2

2NH3  + 3N2H4  --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

3) -(2NH3 +1/2O2 ---> N2H4 + H2O,     ΔH°3 = -143 kJ)

   -2NH3 - 1/2O2 ---> - N2H4 - H2O,    - ΔH°3 = 143 kJ

 2NH3  + 3N2H4 --->4N2+9H2,        ΔH° 1 -  3*ΔH° 2

 -2NH3 - 1/2O2              ---> - N2H4 - H2O,             - ΔH°3 = 143 kJ

 4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

4)

H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ

9*(H2 + 1/2O2 ---> H2O,    ΔH° 4 = - 286 kJ)

9H2+ 9/2 O2 ---> 9H2O,  9*ΔH° 4 = 9*(- 286) kJ

4N2H4 + H2O  ---> 4N2  + 9H2 + 1/2O2,    ΔH° 1 -  3*ΔH° 2 - ΔH°3

9H2+ 9/2 O2    ---> 9H2O,                             9*ΔH° 4 = 9*(- 286) kJ

4N2H4 +4O2 --->4N2+8H2O,         ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

5)

1/4*(4N2H4 +4O2 --->4N2+8H2O,    ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4

N2H4 +O2 --->N2+2H2O,        1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)

6)

N2H4 +O2 --->N2+2,        

1/4( ΔH° 1 -  3*ΔH° 2 - ΔH°3 + 9*ΔH° 4)=

=1/4(-1010kJ - 3*(-317kJ) - (-143kJ) + 9*(-286kJ))= - 622.5 kJ

Answer:

I'm glad you asked!

Explanation:

Gravity is a force which keeps people from floating around.

Density is usually used for mass or volume.

Weight is how heavy something is.

Acceleration is when something increases in height,speed etc.

The answer is Density.

Answer:

it makes it go faster

Explanation:

Answer:

It is an example of double displacement reaction.

4.8 g of NaCl is needed to react.

Explanation:

Balanced reaction: [tex]H_{2}SO_{4}(aq.)+2NaCl(s)\rightarrow 2HCl(g)+Na_{2}SO_{4}(aq.)[/tex]

Here, oxidation states of H, S, O, Na and Cl do not change during reaction. Hence it is not a redox reaction.

In this reaction, cations and anions of the reactants interchange their partners during reaction. Hence, it is an example of double displacement reaction.

As [tex]H_{2}SO_{4}(aq.)[/tex] remain in excess amount therefore NaCl (s) is the limiting reagent. Hence production of HCl entirely depends on amount of NaCl used.

Molar mass of HCl = 36.46 g/mol

So, 3.0 g of HCl = [tex]\frac{3.0}{36.46}[/tex] mol of HCl = 0.082 mol of HCl

According to balanced equation-

2 moles of HCl are produced from 2 moles of NaCl

So, 0.082 moles of HCl are produced from 0.082 moles of NaCl

Molar mass of NaCl = 58.44 g/mol

So, mass of 0.082 moles of NaCl = [tex](0.082\times 58.44)[/tex] g = 4.8 g

Hence 4.8 g of NaCl is needed to react.

Answer:

See explaination

Explanation:

No, the neurons don't use diffusion to transfer messages rather they employ the use of electrical impulses which are very fast for example, if we drop something accidentally on our foot we immediately move back to prevent ourselves from injury this quick reaction is possible because the signals are transferred in the form of electrical impulses.If diffusion was there to transfer the message then it would have taken very long time and our foot would have been bleeding too as diffusion process is relatively much slower.

This is due to collision of CO2 molecule with other molecules of CO2 and vander vals interaction between them which results in slow down of CO2 molecule and the CO2 molecules also collide with walls of leaf as well which also decreases the speed of CO2 molecule resulting it in taking more time.

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

Ionic compounds contain both cations and anions in a ratio that results in no net electrical charge

Answer:

4.35 mL

Explanation:

The water line falls halfway inbetween the 4.4 and 4.3 mark.

The number halfway between 4.3 and 4.4 is 4.35.

Therefore, the volume of the liquid in the graduated cylinder is 4.35 mL.