Answer:
16m E
Explanation:
displacement=10m E-6m W+12m E=16m E
In case of parallel plate capacitor, if the place separation is doubled and plate area is halved, the capacitance becomes A)4 times B)one half C)one forth D)zero
Answer:
C)one forthExplanation:
The capacitance of a capacitor is defined as the charge stored per unit potential change.
using the expression for the capacitance
[tex]C= \frac{eA}{d}[/tex]
where e= electrostatic constant
A = the area of the plate
d = separation distance.
Given the problem statement
1. If the place separation is doubled
2. plate area is halved.
effecting the conditions in our expression for the capacitance we have
[tex]C= \frac{e\frac{A}{2} }{2d}\\\\2dC=e\frac{A}{2}[/tex]
cross multiplying we have
[tex]4dC=eA[/tex]
dividing both sides by 4d we have
[tex]C=\frac{eA}{4d}[/tex]
The capacitance is 1/4 the initial value
The capacitance should become C)one forth
The capacitance of a capacitor:It could be defined by the charge stored per unit with respect to the potential change.
Here the following expression should be used.
[tex]C = eA \div d[/tex]
Here e= electrostatic constant
A = the area of the plate
d = separation distance.
So in the case when place separation is doubled and plate area is halved
So,
[tex]C = \frac{e\frac{A}{2} }{2d}\\\\2Dc = e\frac{A}{2}\\\\ 4Dc = eA[/tex]
Now if we divide both the sides by 4d so
[tex]C = \frac{eA}{4D}[/tex]
Learn more about plate here: https://brainly.com/question/15612606
8. What is the kinetic energy of a car that has a mass of 1000 kg and is moving at a speed of 30 m/s?
Answer:
Hope it will help you :)
Explanation:
Recall the definition of a parsec.
Explanation:
One parsec is the distance to an object whose parallax angle is one arcsecond. The radius of the Earth's orbit equals one astronomical unit (AU), so an object that is one parsec distant is 206,265 AU (or 3.26 light-years) away
Answer:
Parsec is a unit of distance used in astronomy, equal to about 3.26 light years (3.086 × 10^13 kilometres). One parsec corresponds to the distance at which the mean radius of the earth's orbit subtends an angle of one second of arc.
Hope this helps!
For a body of Mass ‘m’ moving in a circle of radius ‘r’ if its velocity is halved, what will be the effect on the value of centripetal force?
Explanation:
F = mv²/r
If the velocity is halved:
F' = m(v/2)²/r
F' = ¼ mv²/r
F' = ¼ F
The centripetal force is reduced by a factor of 4.
which one is smaller a hectogram, dekagram, kilogram, centigram, or milligrams?
Tech A says that batteries should be charged as fast as possible. Tech B says that the ideal charging rate is the CCA divided by 70. Who is correct?
Answer:
Neither A nor B
Explanation:
The charge rate of a battery is the rate at which charge is added to the battery in a given time unit. The unit of charge rate is Coulombs/second or amps
The time to charge a battery, is given by the battery charging formula which is given as follows;
Battery charging time, t = Battery Ah(Ampere hour)/(Charging current, A)
T = Ah/A
Where;
T = Time (Hours)
Ah = The rating of the battery in Ampere Hour
A = The Current applied given in Amperes
The charging current should 10% of the Ah battery rating, such that a 120 Ah battery requires about 12 Amperes charging current
However, due to losses in the system, the current can be set at 13A
the time for charging will then be t = 120/13 = 9.23 hours
What is the distance of 0m and jogs 300m east
Question 51 pts Which of the following illustrates an increase in potential energy? Group of answer choices a wind-up toy winding down an apple dropping from a tree a person climbs a set of stairs a firecracker explodes
Answer:
a person climbs a set of stairs
Explanation:
A person climbing a set of stairs increases his height, which also increases his gravitopotential energy. Gravitopotential energy increases with height as you move further away from the surface of the Earth.
A wind up toy winding down is already expending its stored up potential energy. An apple falling from a tree is already losing its gravitipotential energy. A firecracker that explodes is already using up the potential energy stored in its chemical. All these are cases where the potential energy is decreasing.
A sack is pushed from rest , find the velocity after 6 m while moving at 10 m/s 2
Answer:
The velocity after 6 m while moving at 10 m/s² ≈ 10.95 m/s
Explanation:
The given parameters are;
The given distance of the sack movement = 6 m
The acceleration, a of the sack = 10 m/s²
The velocity of the is given from the relation;
v² = u² + 2×a×s
Where;
u =The initial velocity = 0
Which gives;
v² = 2×a×s
v² = 2×10×6 - 120
v = √120 = 2·√30 m/s
The velocity after 6 m while moving at 10 m/s² is 2·√30 m/s or approximately equal to 10.95 m/s.
which instrument is most easily used to measure the internal diameter of a pipe? a. manometer b. measuring cylinder c. micrometer d. vernier calipers
Answer:
vernier calipers....................
Answer:
d. vernier calipers
Explanation:
manometer is used for measuring pressure
measuring cylinder is for liquids
micrometer can only measure objects less than 2.5 cm (like a thin wire)
so the answer is vernier calipers, they have a measuring range of 1-15 cm.
A ball is pushed down a hill so that it starts with a velocity of 2.0 m/s. It accelerates at a rate of 0.50 m/s2 for the length of the hill, 10.0 m. What is the velocity of the ball at the bottom of the hill?
Answer:
3.7 m/s
Explanation:
Given:
Δx = 10.0 m
v₀ = 2.0 m/s
a = 0.50 m/s²
Find: v
v² = v₀² + 2aΔx
v² = (2.0 m/s)² + 2 (0.50 m/s²) (10.0 m)
v = 3.7 m/s
A running back with a mass of 70 kg travels down the field with a velocity of 5.0 ms . Calculate the kinetic energy of the football player.
convert 0.0079 cm to mm
Answer: 0.079mm
Explanation:
Hope this helps^^
PLEASE EXPLAIN AND YOU WILL GET BRAINLIST Ms. R is curious if the type of gasoline she uses in her car affects how many miles she can drive on a single tank of gas. (Fuel efficiency). Which of the following would be the BEST scientific question for her to test?
1) How does driving farther affect the type of gas used?
2) How does a Mazda compare to a Civic?
3) How does changing the type of fuel affect the number of miles a car can be driven on a single tank of gas?
4)How does the color of the car affect its internal temperature?
se the IUPAC nomenclature rules to give the name for this compound - CaS.
Answer:
Calcium sulphide
Explanation:
If we look at the compound, we will discover that it is an ionic compound. The compound is comprised of Ca^2+ and S^2-.
The cation Ca^2+ is the calcium ion while the anion S^2- is the sulphide ion hence the compound is rightly named calcium sulphide.
The diagram shows the layers formed when 10 mL each of corn starch, water, and vegetable oil were slowly poured into a glass cylinder. A tall cylinder with 3 layers is shown. The top layer is labeled Oil, the middle layer is labeled Water and the bottom layer is labeled Corn Starch. A paper clip released gently into the liquid settles at the bottom of the cylinder. What best compares the densities of the substances? Oil is denser than the other liquids, and all liquids are denser than the clip. The clip is denser than the three liquids, and water is denser than oil. Oil is denser than water but less dense than the clip. Corn starch is denser than the other liquids and the clip.
Answer:
The clip is denser than the three liquids, and water is denser than oil.
Explanation:
In this exercise, the Archimedes principle must be used, on the thrust that is equal to the weight of the dislodged liquid
B = ρ_liquid g V_body
when a body is placed on a liquid, the equilibrium equation must be fulfilled
W - B = 0
W = B
ρ_body g V_body = ρ _liquid g V’
from this expression we see that we have three possibilities
* the density of the body is less than the density of the liquid, therefore the body floats
* The density of the body is equal to the density of the liquid, the body is in equilibrium with the liquid, neither floats nor sinks
* the density of the body greater than that of the liquid, the body sinks.
Based on this, the liquids are arranged in the cylinder according to their density.
ρ_oil < ρ_water < ρ_starch
as the clip sinks
the density of the clip is higher than that of liquids
We review the final statements and the correct one is: Clip is denser than liquids and water is denser than oil
Answer: D
Explanation:
Which career do you think it would be most difficult to break into and why?
Answer:
Fashion and interior design.
I hope it will help you.
You are heating a substance in a test tube. Always point the open end of the tub
Answer:
Away from all ppl
Explanation:
A robin in flight has 20.8 J of PE when it is 27.6 m high. What is the mass of the robin? (Unit = kg)
Answer:
[tex] \boxed{ \bold{ \purple{0.0769 \: kg \: }}}[/tex]Explanation:
[tex] \sf{Potential Energy ( P.E ) \: = \: 20.8 \: joule}[/tex]
[tex] \sf{distance \: = 27.6 \: metre}[/tex]
[tex] \sf{mass = }[/tex] ?
[tex] \sf{acceleration \: due \: to \: gravity = 9.68 \: {metre \: per \: second}^{2} }[/tex]
Now, let's find the mass:
[tex] \sf{PE \: = mass \times gravity \: \times \: distance}[/tex]
plug the values
⇒[tex] \sf{20.8 = m \times 9.8 \times 27.6}[/tex]
Multiply the numbers
⇒[tex] \sf{20.8 = 270.48 \: m}[/tex]
Swap the sides of the equation
⇒[tex] \sf{270.48m = 20.8}[/tex]
Divide both sides of the equation by 270.48
⇒[tex] \sf{ \frac{270.48m}{270.48} = \frac{20.8}{270.48} }[/tex]
Calculate
⇒[tex] \sf{0.0769}[/tex] kg
Hope I helped!
Best regards!!
Answer:
[tex]\huge \boxed{\mathrm{0.0769 \ kg}}[/tex]
Explanation:
[tex]\displaystyle \sf Mass=\frac{Potential \ energy}{Acceleration \ of \ gravity \times Height}[/tex]
[tex]\displaystyle m=\frac{PE}{gh}[/tex]
[tex]\mathrm{We \ need \ to \ find \ the \ mass.}[/tex]
[tex]\displaystyle m=\frac{20.8}{9.8 \times 27.6}[/tex]
[tex]m= 0.0769[/tex]
Physics Homework
1. A swimmer is in Lake Lanier practicing a 100 m individual medley event. They swim East 25
m using butterfly, West 25 m using backstroke, East 25 m using breaststroke, and finally West
25 m using freestyle. This event takes them 70 seconds to complete.
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a. What was the swimmer's average speed?
b. What was the swimmer's average velocity?
Explanation:
a. Average speed = distance / time
= 100 m / 70 s
= 1.43 m/s
b. Average displacement = displacement / time
= 0 m / 70 s
= 0 m/s
Distance is the length of the path traveled. Displacement is the difference between the final position and initial position.
The escape velocity of a rocket from the earth is 11kms^-1. Taking the acceleration due to gravity as 9.8ms^-2, calculate the radius of the earth.
Answer:
6.37*10^6 m
Explanation:
We know that,
g = GM/R²
values given to us
acceleration due to gravity = g = 9.8 m/s²
Mass of the earth is= 6.4*10^24
G = 6.67*[tex]10^{-11}[/tex]
implementing
9.8 = 6.67*10^-11 * 6*10^24/R^2
9.8 = 40.02 * 10^13/ R^2
R^2 = 4002/98 * 10^12
R^2 = 40.83* 10^12
R= 6.37*10^6 m (approximately)
Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during their trip their velocity was -20 m/s? Explain, and give an example to justify your answer. PLEASE HELP
Answer: Yes. Please find the answer in the explanation.
Explanation:
Yes. Since velocity is a vector quantity, that is, it has both magnitude and direction.
If the displacements covered are not of the same direction, the velocity will not also of the same direction.
Take for instance, if the velocity in a positive is 40 m/s and velocity in the opposite direction is - 20 m/s . Then, the resultant velocity will be 40 - 20 = 20 m/s
Therefore, it is possible that at any time during their trip their velocity was -20 m/s.
a cheetah has a speed of 100 km/h. if the cheetah runs for 5 hours, then what’s it’s speed ?
Answer:
Explanation:
idk
The density of a certain type of glass is 25g/cm3. A piece of the glass has a mass of 125g. Calculate its volume
Given:-
Density = 25 g/cm³Mass = 125 gTo be calculated:-
Calculate its volume.
Formula used:-
Density = Mass/volume
=> 25 = 125/Volume
=> Volume = 125/25
=> Volume = 5 cm³
If a true heading of 135° results in a ground track of 130° and a true airspeed of 135 knots results in a groundspeed of 140 knots, the wind would be from
Answer:
245.1° and 13 knots
Explanation:
The given parameters are;
The true heading = 135°
The resultant ground track = 130°
The true airspeed = 135 knots
The ground speed = 140 knots
Given that the true airspeed the ground speed and the wind direction and magnitude form a triangle, we have;
From cosine rule, we have;
a² = b² + c² - 2×b×c×cos(A)
Where
a = The magnitude of the wind speed in knot
b = The true airspeed = 135 knots
c = The ground speed = 140 knots
A = The angle in between the true heading and the resultant ground track heading = 5°
Which gives;
a² = 135² + 140² - 2×135×140×cos(5 degrees) = 168.84 knots²
a = √168.84 = 12.9934 ≈ 13 knots
We have;
135 × sin(135 degrees) - 140× sin(130 degrees) = -11.7868
135 × cos(135 degrees) - 140× cos(130 degrees) = -5.469
Tan(θ) = -11.8/-5.5 = 2.155
θ = tan⁻¹(2.155) = 65.108°
Given that the wind is moving in opposite direction (slowing down the airplane, we add 180°, to get
Therefore, the angle direction = 180 + 65.108 = 245.1
Therefore, we have;
245.1° and 13 knots
How much time does a bike with an acceleration of 2ms-2 take to increase its velocity from 10ms-1 to 30ms-1?
Answer:
[tex] \boxed{\sf Time \ taken = 10 \ seconds} [/tex]
Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 30 m/s
Acceleration (a) = 2 m/s²
To Find:
Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s²
Explanation:
[tex]\sf From \ equation \ of \ motion:[/tex]
[tex] \boxed{ \bold{v = u + at}}[/tex]
Substituting values of v, u & a in the equation:
[tex] \sf \implies 30 = 10 + 2t[/tex]
Substract 10 from both sides:
[tex] \sf \implies 30 - 10 = (10 - 10) + 2t[/tex]
[tex] \sf \implies 20 = 2t[/tex]
20 = 2t is equivalent to 2t = 20:
[tex] \sf \implies 2t = 20[/tex]
Dividing both sides by 2:
[tex] \sf \implies \frac{ \cancel{2}t}{ \cancel{2}} = \frac{20}{2} [/tex]
[tex] \sf \implies t = \frac{10 \times \cancel{2}}{ \cancel{2}} [/tex]
[tex] \sf \implies t = 10 \: s[/tex]
So,
Time taken (t) by bike to increase its velocity from 10 m/s to 30 m/s with an acceleration of 2 m/s² = 10 seconds
I NEED HELP WITH 59-61
PLEASE HELP ME!!!!!
60. What value would the acceleration on the object above have now? Does it change anytime during its fall?
Describe the motion of its fall.
61. If there was no air resistance, which object falls faster: an unfolded piece of paper or an anvil?
Answer:
Explanation:
59 ) Graph has been given in the file attached .
60) Since the v- t graph is a straight line so the acceleration is constant . This acceleration does not change with time . It is also called acceleration due to gravity . Its value is 10 m /s²
61 ) If there is no resistance , both the objects will fall together and reach the earth simultaneously if fallen from same height . it is so because each and every object falls under gravity without any obstruction with equal acceleration which is equal to 10 m /s ² .
when a constant force acts upon an object the acceleration of the object varies inversely with its mass. when a certain constant force acts ipon an objec twith mass 21khm the accerlation of the object is 3 m/2^2. If the same force acts upon another object whose mass is 9kg. What would this object's acceleration be?
Explanation:
When a constant force acts upon an object the acceleration of the object varies inversely with its mass.
[tex]a\propto \dfrac{1}{m}[/tex]
or
[tex]\dfrac{a_1}{a_2}=\dfrac{m_2}{m_1}[/tex]
If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg
We need to find a₂
So,
[tex]a_2=\dfrac{m_1a_1}{m_2}\\\\a_2=\dfrac{21\times 3}{9}\\\\a_2=7\ m/s^2[/tex]
So, if mass is 9 kg, its acceleration is 7 m/s².
Answer:
A AND B
Explanation:
Explain Any Ten Forces Briefly.
Answer:
--->
Explanation:
1. Air Resistance- this is a type of frictional force that acts upon objects as they travel through air. It usually opposes the motion of an object and it is mathematically difficult to predict its value.
2. Gravity- the force of gravity is the force that the earth, and moon use to attract an object towards itself. The moon has far less gravity than earth. All objects on earth experience a force of gravity that pulls them downward, towards the center of the earth.
3. Tension- the tension force is the force that is transmitted through a string, rope, cable or wire when it is pulled from opposite ends. The tension force is directed along the length of the wire and pulls equally on the objects on the opposite ends of the wire
4. Friction- this is the force exerted by a surface when an object moves across it. Friction results from the two surfaces being pressed together closely.
5. Electromagnetic force- although they don't seem similar, electricity and magnetism are related. Flowing electrons produce magnetism, and a moving magnet produces electricity.
6. Upthrust- this is the upward force that a liquid or gas exerts on a body floating in it.
7. Spring force- The spring force is the force exerted by a compressed spring upon any object that is attached to it. This object is always acted upon by a force that restores the object to its rest or equilibrium position.
8. Applied force- An applied force is a force that is applied to an object by a person or another object.
9. Electrostatic force- The types of forces exerted by all electrically charged bodies on another charged bodies in the universe are ‘electrostatic forces’. They can be either positively or negatively charged.
10. Nuclear force- these are the forces that act between two or more nucleons. They bind protons and neutrons into atomic nuclei. The nuclear force is about 10 millions times stronger than the chemical binding that holds atoms together in molecules.
Assume each mark on the scale represented 1 g. Estimate how much a sheet of paper would mass. A sheet of paper is 28 cm by 21.7 cm.
Answer:
607.6g
Explanation:
Assume each mark on the scale represented 1 g. That is 1 cm = 1g
To estimate how much a sheet of paper would mass a sheet of paper is 28 cm by 21.7 cm, first calculate the area.
Area = 28 × 21.7 = 607.6 cm^2
Mass = 607.6 × 1g = 607.6 g
Therefore, the estimation will be 607.6g