What determines the type of air mass that forms in an area?

Answers

Answer 1

Answer:

Air masses are also identified based on whether they form over land or over water. Maritime air masses form over water and are humid. Continental air masses form over land and are dry. ... One that forms over the Indian Ocean is called a maritime tropical air mass and is warm and humid

Answer 2

The type of air mass that forms in an area is determined by the location and nature of the water and land.

What is meant by Air mass?

Air mass may be characterized as a huge volume of air that is present in the atmosphere which possesses a uniform temperature and moisture. This attribute is generally classified on the basis of latitude and continental or maritime source regions.

For example, Maritime air masses construct over water and are significantly humid. While continental air masses construct over land and are significantly dry. That is why air masses are characterized by the temperature and humidity of the given region.

Therefore, the type of air mass that forms in an area is determined by the location and nature of the water and land along with the temperature and humidity of the given region.

To learn more about Air masses, refer to the link:

https://brainly.com/question/18201898

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Related Questions

1) What is the mass of 6.2 mol of K2CO3?

Answers

Answer:

[tex]\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}[/tex]

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

K: 39.098 g/mol C: 12.011 g/mol O: 15.999 g/mol

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

2(39.098 g/mol) + 3(15.999 g/mol) + 12.011 g/mol= 138.204 g/mol

2. Convert Moles to Grams

Use the molar mass as a fraction.

[tex]\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

Multiply by the given number of moles: 6.2

[tex]6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}[/tex]

[tex]6.2 *\frac {138.204 \ g \ K_2CO_3}{1 }[/tex]

[tex]6.2 * {138.204 \ g \ K_2CO_3}[/tex]

[tex]856.8648 \ g \ K_2CO_3[/tex]

There are 856.8648 grams of potassium carbonate in 6.2 moles.

If today is October 7th and we observe a waxing gibbous, on what date will we observe the next waning crescent?

Answers

Answer:

14 days.

Explanation:

If today were October 7 and we observed a waxing gibbous moon, that is, a moon with an illumination greater than a first quarter but less than a full moon, we would have to wait 14 days to see a waning crescent moon, which would be a moon with a visibility less than the last quarter but greater than a new moon.

If a mixture contains 75% of one compound and 25% of its enantiomer, what is the e.e. of the mixture

Answers

Answer: The enantiomeric excess ee is 50%

Explanation:

Given that;

compound A = 75%, B = 25%

ee = ?

so

ee = [( A - B) / ( A + B)] × 100

= [( 75 - 25) / ( 75 + 25)] × 100

= [50 / 100] × 100

= 0.5 × 100

= 50%

Therefore enantiomeric excess ee is 50%

HELP I need these 2 questions answered

Answers

Answer:

1=a 2=d i think

Explanation:

What are the two types of alleles? A: Dominant and recessive B: genotype and phenotype C: Gene and chromosome or D: Gene and DNA

Answers

Answer:

dominant and recessive

Explanation:

The number of light waves that occur in one second is known as the wave's

Question 2 options:

amplitude

frequency

energy

movement

Answers

Answer:

b

Explanation:

I did this quiz and i think a got it right i also looked up my answer to make sure it was right good luck on quiz :)

How many molecules of malic acid (C4H6O5), an acid found in apples and other fruits, are there in 1.25 g

Answers

Answer:

5.61 * 10²¹ molecules

Explanation:

You have 1.25 g of malic acid, C4H.Os, an acid found in apples and other fruits. How many molecules of the acid do you have?

Solution:

A molecule is the group of two or more atoms held together by chemical bonds.

The number of molecules is calculated using the formula:

number of molecules in a substance = number of moles of substance * Avogadro constant

Avogadro constant = 6.02 * 10²³ mol⁻¹

number of moles = mass / molar mass

Given that mass = 1.25 g

molar mass of malic acid (C₄H₆O₅) = (12 * 4) + (1 * 6) + (16 * 5) = 48 + 6 + 80 = 134 g/mol

number of moles = mass / molar mass = 1.25 g / 134 g/mol = 0.0093 mol

Recall that: number of molecules in a substance = number of moles of substance * Avogadro constant

number of molecules in a substance = 0.0093 mol * 6.02 * 10²³ mol⁻¹ = 5.61 * 10²¹ molecules

For the element Lithium give the number of bonds it would like to form with other atoms.
A)1
B)2
C)3​

Answers

Answer: A) 1

Explanation:

Lithium is the third element of the periodic table with atomic number of 3. The atomic number is equal to the number of electrons for a neutral atom and thus there are 3 electrons in Lithium.

The electronic configuration of Lithium (Li) is [tex]1s^22s^1[/tex]. Thus it can gain one electron to complete its octet and attain stability. Thus it can form one bond with other atoms.

Example: Lithium can form one bond with flourine to form LiF by losing one electron to form [tex]Li^+[/tex].

In order to become stable in an ionic bond, oxygen needs to (A) gain 2 electrons (C) share 2 electrons B) lose 2 electrons​

Answers

Answer:

gains 2 electrons. In order for the new ionic compound to form a a neutral compound, the oxygens must gain 6 electrons

Answer:

C

Explanation:

because you got to share

How many moles of gold, Au, are in 3.60 x 10^-5 g of gold?

Answers

Answer:

1.83 × 10⁻⁷ mol Au

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisExplanation:

Step 1: Define

3.60 × 10⁻⁵ g Au (Gold)

Step 2: Identify Conversions

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Set up:                              [tex]\displaystyle 3.60 \cdot 10^{-5} \ g \ Au(\frac{1 \ mol \ Au}{196.97 \ g \ Au})[/tex]Multiply:                            [tex]\displaystyle 1.82769 \cdot 10^{-7} \ mol \ Au[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.82769 × 10⁻⁷ mol Au ≈ 1.83 × 10⁻⁷ mol Au

Helpppppp pleaseeeee with 16

Answers

Answer:

Neither accurate nor precise

Explanation:

The measurements shown on the table are neither accurate nor precise in value.

Accuracy is the nearness of the measured value to the true value.

Precision is the ability to reproduce a result.

From the given problem, we find that the true value is 1.52 and the average of the readings is not even close. So, it is not accurateAlso, there is no repeatability of the readings, so the work lacks precision. Therefore, this result is neither precise nor accurate.

CHEMISTRY!! Please help!!

Answers

Answer:

Yes, because it follows the octet rule.

Explanation:

The Lewis is correct

because it follows the octet rule.

And

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas.

Mass data for reaction of NaHCO3-Na2CO3 mixture with HCL:

Mass of crucible and cover (g) 28.8258
Mass of crucible, cover and mixture (g) 29.4948
Mass of crucible, cover and residue after reaction with HCL (g)

1st weighing... 29.4454
2nd weighing... 29.4455

Required:
Calculation of percent composition of NaHCO3 and Na2CO33 in an unknown mixture

Answers

Is there a graph? I need to see a graph in order to help
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