What details show that this illustration is a scene of life during the Neolithic Age and not the Paleolithic Age? Select all that apply.
1. animal skin shoes
2. cooking fire
3. domesticated animals
4. small houses
5. stone axe

Answer:

awnser in C i took the test earlier today ! :)

Explanation:

Hope it helps !

Answer:

Plot. In 1963 Brighton, out-of-work skiffle player Francis Henshall becomes separately employed by two men – Roscoe Crabbe, a gangster, and Stanley Stubbers, an upper class twit. Francis tries to keep the two from meeting, in order to avoid each of them learning that Francis is also working for someone else.

Adapted from: The Servant of Two Masters

Playwright: Richard Bean

Don't forget to leave a like or a rate

Answer:

Chinese issue paper money

Explanation:

1042 ce is after 476 ce and before 1492 ce so its between both which is c

Answer:

No. Two bits are not enough to assign a unique binary number to each vowel in the English language.

Explanation:

The vowel in the English language is made up of 5 lowercase letters (a, e, i, o, u) and their corresponding 5 uppercase letters (A, E, I, O, U). All together, there are 10 unique vowel letters.

The number, x, of unique characters that can be stored by n bits is given by:

x = 2ⁿ

So if we have 2 bits, it implies that, the number of different characters that can be stored is:

2² = 4

Therefore, with 2 bits, there are 4 unique characters that can be stored.

But then, we need to store a total of 10 characters representing the English Language vowels. Therefore, two bits will not be enough to assign a unique binary number to each vowel.

It can also be seen this way

For two bits, we have the following possibilities:

00

01

10

11

Now, let's assume we have assigned the vowels as follows:

00 = a

01 = e

10 = i

11 = o

Then, only four of the vowel letters can be assigned a unique binary number.

Therefore, two bits are not enough to assign a unique binary number to each vowel of the English language.

We need at least 4 bits which will yield 2⁴ = 16 different combinations. And from that, we are able to assign each vowel a unique binary number like so:

Used

0000 = a

0001 = e

0010 = i

0011 = o

0100 = u

0101 = A

0110 = E

0111 = I

1000 = 0

1001 = U

Remaining:

1010

1011

1100

1101

1110

1111

10 out of 16 different combinations of binary numbers have been used by the 10 vowel characters. We will be left with 6 binary numbers. Better being surplus than being deficit.

Bits simply means binary digits

Two bits would not be enough to assign a unique binary number to each vowel in the English language.

The number of bits in a system is:

[tex]\mathbf{2^n = N}[/tex]

In this case:

n represents the number of bits i.e. 2

N represents the number of vowels i.e. 5

So, we have:

[tex]\mathbf{2^2 = 5}[/tex]

Express 2^2 as 4

[tex]\mathbf{4 = 5}[/tex]

The above equation is false, because 4 is not equal to 5

Hence, two bits would not be enough to assign a unique binary number to each vowel in the English language.

Read more about bits at:

https://brainly.com/question/13188094