The chemical produced by endothelial cells at the site of injury during the first step of platelet plug formation is von Willebrand factor (VWF). VWF is a glycoprotein that is released from endothelial cells when they are injured.
What is endothelial ?Endothelial cells are the cells that line the inside of the body's organs and vessels, such as the intestines, the heart, and the blood vessels. These cells are a type of epithelial cell, meaning that they form a single layer that serves as a barrier between the body's organs and the outside environment. Endothelial cells are particularly important in providing a barrier between the blood and the body's other organs and tissues. They are also important in regulating the movement of fluids and nutrients throughout the body, and in providing a barrier to stop any potentially harmful substances from entering the body. Endothelial cells also play an important role in regulating the body's inflammatory response, as well as its immune response. Endothelial cells are also important in regulating vascular tone, which helps to ensure that the blood vessels are working normally.
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Suppose that when you plot the masses of several samples of an unknown substance against the corresponding volumes of water displaced by the samples, the slope of the resulting straight line is 2.7 g/mL. What is the substance's density and probable identity?
Suppose that when you plot the masses of several samples. The density of the object is 2.7 g/mL and it is aluminum.
What is density?It is important to keep in mind that the material's density is the ratio of the object's mass to its volume. By plotting the masses of several samples of an unknown substance against the volumes of water displaced by the samples, the case's density was experimentally determined.
Why is the substance's density so high?The relationship between a substance's mass and the amount of space it occupies (volume) is its density. The density of a substance is determined by the mass, size, and arrangement of its atoms. Density is equal to the material's mass divided by its volume; D = m/v.
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Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:
Mg2+, Al3+, F−, O2−
Answer:
Explanation:
Here are four binary ionic compounds that could be formed from the given ions, along with their empirical formulas:
Magnesium fluoride: Mg2+ + 2F- → MgF2 (empirical formula: MF2)
Aluminum oxide: 2Al3+ + 3O2- → Al2O3 (empirical formula: Al2O3)
Magnesium oxide: Mg2+ + O2- → MgO (empirical formula: MO)
Aluminum fluoride: Al3+ + 3F- → AlF3 (empirical formula: AlF3)
In each case, the positive and negative charges balance to give a neutral compound. The empirical formula of each compound shows the simplest ratio of the elements present in the compound.
A chemist measures the amount of iodine solid produced during an experiment. She finds that of iodine solid is produced. Calculate the number of moles of iodine solid produced.
The number of moles of iodine solid produced is 1.6 g.
What are moles?Moles are a standard scientific unit for measuring large quantities of very small entities, such as atoms.
Mass of iodine solid produced = 1.6 g
Iodine solid has a molecular formula: I2
Atomic mass of iodine = 126.904 g/mol
Therefore, molar mass of I2 solid = 2 x 126.904 = 253.808 g/mol
The number of moles of a given substance is the ratio of its mass to the molar mass
moles of I2 solid = mass of I2 solid/molar mass = 1.6 g/253.808 = 0.00630 moles
Hence, the moles of iodine solid produced are 0.00630 moles.
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A major component of gasoline is octane (C3H18). When liquid octane is burned in air it reacts with oxygen (O₂) gas to produce carbon dioxide gas and water
vapor. Calculate the moles of octane needed to produce 2.10 mol of water. Be sure your answer has a unit symbol, if necessary, and round it to the correct
number of significant digits.
The amount of octane produced by a reaction involving 2.10 mole of water is 18.9 mole.
What is a mole?We'll start by writing the reaction's balanced equation. This is as follows:
2C8H18 + 25O2 → 16CO2 + 18H2O
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Using the above data, we can calculate the number of moles of octane produced by the reaction of 2.10 mole of water. This can be obtained by doing the following:
Based on the above-mentioned balanced equation,
2 moles of octane were converted into 18 moles of water.
Therefore,
When x mole of octane will react to produce 18 moles of water
x = 2x / 18 x 2.10
2x = 37.8
x = 37.8/2
x = 18.9
As a result, the number of moles of octane produced by the reaction is 18.9 mole.
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What happens when solid goes to liquid?
When solid goes to liquid, it is called melting. Think of a solid ice cube being melted into liquid water.
Now for particles, for solids, particles are arranged in regular, repeating patterns. For liquid, the molecules lose the arrangement and is now random, but close toward each other. The particles move freely and take the shape of the container.
An aqueous solution at 25°C has a H3O+ concentration of ×8.810−12M . Calculate the OH− concentration. Be sure your answer has the correct number of significant digits.
The OH⁻ concentration will be 10^2.9031
The amount of hydrogen ions present in a solution or substance is first and foremost indicated by the pH scale, which measures acidity or alkalinity.
The concentration of hydrogen ions, or H₃O⁺, is what is referred to as the pH, which is defined as the negative base 10 logarithm of the activity of hydrogen ions:
pH= - log [H⁺]= - log [H₃O⁺]
An aqueous solution at 25°C has a H₃O⁺ concentration of 8.8 x 10⁻¹²M
pH= - log [H⁺]= - log [H₃O⁺]
pH= - log [8.8 x 10⁻¹²M]
pH = 11.0969
The following relationship can be established between pH and pOH:
pOH + pH= 14
pOH = 14- pH
pOH = 14- 11.0969
pOH = 2.9031
pOH = - log [OH]
2.9031 = - log [OH]
[OH] = 10^2.9031
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Which of the following would not be helpful in separation a mixture of sand and salt? Select one: O Filter paper and funnel O Water O Glass cup O Magnet
The technique that would not be helpful in the separation of a mixture of sand and salt is O Magnet.
The combination of salt and sand may be separated via way of means of filtration observed via way of means of an evaporation process. Filtration can separate sand from a aggregate of sand and salt solution (salt dissolved in water). Sand remains at the clear out out paper as a residue after filtering. By boiling the filtrate, not unusualplace salt might also additionally now be produced. Probably the perfect approach to split the 2 materials is to dissolve salt in water, pour the liquid far from the sand, after which evaporate the water to get better the salt.
Thus, the correct option is magnet.
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Be sure to answer all parts.
Calculate the mass in grams of 16.8 mol of copper(I) carbonate. Enter your answer in scientific notation
with the correct number of significant figures.
Solving the Question
[tex]n=\dfrac{m}{M}[/tex]
m = massM = molar massRearrange for m:
[tex]m=nM[/tex]
Plug in given:
[tex]m=(16.8)M[/tex]
⇒ The molar mass of copper (1) carbonate is 187.1 g/mol:
[tex]m=(16.8)(187.1)\\m=3143.28[/tex]
Round to significant figures:
⇒ The given value has 3 significant figures:
[tex]m= 3140[/tex]
Convert to scientific notation:
3.14 × 10³ g
Answer3.14 × 10³ g
within atoms, there is an ongoing relationship between the nucleus and the electrons. categorize the characteristics by whether they describe the nucleus or electrons.
Within atoms, there is an ongoing relationship between the nucleus and the electrons. Characteristics describe the nucleus are:
Positively chargedAttracts the negatively charged particles into the space surrounding itCharacteristic describe electrons :
Negatively chargedCan gain or lose energyCan move from one atom to anotherCan bond two atoms into a molecule when shared between two atomsOn the basis of the 1909 Geiger-Marsden gold foil experiment, Ernest Rutherford identified the atomic nucleus in 1911, which is the compact, dense region made up of protons and neutrons at the heart of an atom. Positively charged nucleus draws negatively charged particles into the area around it.
The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically regarded to be elementary particles.
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Please help with the problem attached:
Answer:
the one with cars is false I think
need help i need it quick
Answer:
A
Explanation:
I would expect a sandwich to look like A
how do we open a business that is cheaper
Answer:dont sell as much stuff and name it something like the doller treestore LOL
Explanation:
S + 6 HNO3 --> H₂SO4 + 6 NO2 + 2H₂O
In the above equation how many grams of water can be made when 6 grams of HNO3 are
consumed?
Taking into account the reaction stoichiometry,50.57 grams of H₂O are formed when 6 grams of HNO₃ are consumed.
Reaction stoichiometryThe balanced reaction is:
S + 6 HNO₃ → H₂SO₄ + 6 NO₂ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
S: 1 moleHNO₃: 6 molesH₂SO₄: 1 moleNO₂: 6 molesH₂O: 2 molesThe molar mass of the compounds is:
S: 32 g/moleHNO₃: 63 g/moleH₂SO₄: 98 g/moleNO₂: 46 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
S: 1 mole ×32 g/mole= 32 gramsHNO₃: 6 moles ×63 g/mole= 378 gramsH₂SO₄: 1 mole ×98 g/mole= 98 gramsNO₂: 6 moles ×46 g/mole= 276 gramsH₂O: 2 moles× 18 g/mole= 36 gramsMass of H₂O formedThe following rule of three can be applied: if by reaction stoichiometry 378 grams of HNO₃ form 36 grams of H₂O, 6 grams of HNO₃ form how much mass of H₂O?
mass of H₂O= (6 grams of HNO₃×36 grams of H₂O)÷378 grams of HNO₃
mass of H₂O= 0.57 grams
Finally, 50.57 grams of H₂O are made.
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Which of the following options describe situations in which hydrogen bonding will be observed between the solute and solvent? Select all that apply.
A. Solvent contains OH or NH groups, solute contains N, O, or F atoms.
B. Solvent contains N, O, or F; solute contains OH or NH groups.
C. Solvent and solute both contain OH or NH groups.
D. As long as the solvent can form hydrogen bonds, hydrogen bonding is observed between solute and solvent.
E. Solvent and solute both contain O, N, or F.
The following options describe situations in which hydrogen bonding will be observed between the solute and solvent is Solvent contains OH or NH groups, solute contains N, O, or F atoms. The Solvent and solute both contain OH or NH groups in the process.
It contains the maximum amount of solute that will dissolve in that solvent at that temperature.
Solution= solute+ solvent
The solubility of a solute depends on temperature. A solution containing just the right (maximum) amount of solute that can normally dissolve at a given temperature is said to be saturated. Solvent contains N, O, or F; solute contains OH or NH groups in general.
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draw three glucose molecules joined by a,1, 4 linkages. you only need to show o's and the h's attached to o's. you may draw ring or chair forms of glucose?
Glucose (C6H12O6, molecular weight 180.18) is a hexose—a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains -CHO group).
Glucose is an aldehyde (contains -CHO group). Its five carbons and one oxygen form a ring called a "pyranose ring", the most stable form for six-carbon aldoses. In this ring, each carbon is attached to a hydroxyl and hydrogen side group except for the fifth atom, which is attached to the sixth carbon on the outside of the ring, forming the CH2OH group. This ring structure is in equilibrium with the more reactive form.
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A nutritionist suspected that her company's clients had below average cholesterol. They obtained a random sample of 8 clients of the same age and gender. These clients had a mean cholesterol level of xˉ=4.28 mmol/L (millimoles per liter).To see how likely a sample like this was to happen by random chance alone, the nutritionist performed a simulation. They simulated 60 samples of n=8 cholesterol levels from a normal population with a mean of 4.6 mmol/L and a standard deviation of 0.5 mmol/L (these are generally accepted values for people with the same age and gender of those in the sample). They recorded the mean of the cholesterol levels in each sample. Here are the sample means from their 60 samples:They want to test H0:μ=4.6 mmol/L vs. Ha:μ<4.6 mmol/L where μ is the mean cholesterol level for all clients like those sampled.Based on these simulated results, what is the approximate p-value of the test?Note: The sample result was xˉ=4.28 mmol/L.
The nutritionist can deduce that the mean cholesterol level for all clients is less than 4.6 mmol/L (Ha:4.6 mmol/L) because this p-value is less than 0.05, rejecting the null hypothesis.
Calculating the likelihood that a sample mean will be equally extreme or more extreme than the observed mean if the null hypothesis is correct will yield the p-value.
Using the observed sample mean as a foundation, calculate the Z-score:
[tex]Z = \frac{4.28 - 4.6}{0.5 / \sqrt{8}}[/tex]
To ascertain the likelihood of encountering a Z-score, look up the Z-score in a typical normal table. The Z-score in this case is around -2.56, with a probability of 0.0039.
The p-value is the chance of encountering a sample mean that is as severe or more extreme than the observed mean, given that the null hypothesis is true. The p-value for this test is hence close to 0.0039.
There is a 0.0039 possibility of seeing a sample mean that is as high or more severe than the observed mean (4.28 mmol/L) if the average cholesterol level for all customers is 4.6 mmol/L.
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How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?
Answer:
To prepare 200.0 mL of 0.900% (m/v) KCl solution, 91.4 grams of KCl are required. [1] This can be calculated by first converting the molarity to moles, then using the atomic mass of KCl to convert the number of moles to grams. For example, 2.45 moles of KCl is required to make 0.5 L of 2.45 M solution. [2] This calculation can also be applied to other salts, such as CuSO4.6H2O, to find the required mass to make a given 0.300 M solution. [3]
Explanation:
In order to prepare a 200.0 mL solution of 0.900% (m/v) KCL, you will need 1.8 grams of KCL.
Explanation:To resolve the question of 'How many grams of KCL are needed to prepare 200.0mL of 0.900% (m/v) KCL solution?', first we need to understand that the %(m/v) here means grams of solute per 100 mL of solution. Hence, for a 0.900% (m/v) KCL solution, there would be 0.900 grams of KCL per 100 mL of solution.
For preparing 200.0mL (which is double of 100mL), simply double the amount of KCL needed. So, 0.900 grams x 2 = 1.8 grams.
So, you therefore need 1.8 grams of KCL to prepare 200.0mL of 0.900% (m/v) KCL solution.
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if the concentration of chloride is higher inside the cell what does that mean for the nernst potential
Inside the cell, the potassium concentration is higher than outside, whereas the sodium and chloride ion concentrations are lower.
How does chloride impact the potential of resting membranes?Since chloride is a negative ion, it must exit the cell in order for the membrane potential to change from -70 mV to -65 mV by making the cell more positive.
How does concentration affect the potential of the cell?The larger concentration enables the rise in voltage difference in an electrochemical cell. Increased voltage is seen as a result of the reaction moving more quickly in a forward direction due to the higher reactant concentration.
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1.Calculate the boiling point (in degrees C) of a solution made by dissolving 6.60 g of naphthalene {C10H8} in 47.1 g of CCl4. The Kbp of the solvent is 4.95 K/m and the normal boiling point is 76.5 degrees C. Enter your answer to 2 decimal places.
The boiling point ( in degree Celsius) of solution
of a solution made by dissolving 6.60 g of naphthalene {C₁₀H₈} in 47.1 g of CCl₄ is equals to the 81.91°C.
The naphthalene compound is dissolved in carbon tetrachloride, CCl₄. When naphthalene added to the carbon tetrachloride it will result in higher boiling point compared to the boiling point of a pure carbon tetrachloride (solvent). This is known as the boiling point elevation The equation for the boiling point elevation is:
ΔT= Kb × m
where: ΔT is the change in temperature
Kb is the boiling point elevation constant m is molality of the solutionFirst we calculate the molality of the solution
Moles of naphthalene = 6.60 g / 128.17 g per mol = 0.0515 mol
Mass of solvent = 47.1 g ×1 kg / 1000 g = 0.0471kg
Molality = moles / kg solvent
= 0.0515mol / 0.0471 kg
= 1.093 m
∆ Tb = kb ×m
= 4.95 °C per m × 1.093m
= 5.410°C
So the boiling point of the solution is = bp of pure CCl₄ + ∆Tb
= 76.5°C + 5.41°C
= 81.91°C
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Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released).AB+C --> AC+BA+ BC --> AB + CA2+C2 --> 2ACB2+C2 --> 2BCA2+B2 --> 2ABStrongest BondA-BA-AB-BC-CB-CA-CWeakest Bond
The answer is 1) Endothermic, 2) Exothermic, 3) Endothermic, 4) Endothermic, 5) Exothermic.
The stronger the bond, the more energy is required to break it, and the stronger the bond formed, the more energy is released.
AB is a strong bond and requires more energy to break it, forming a weak AC bond that releases very little energy, so the reaction is relatively endothermic since more energy is absorbed than given off. Similar logic can be applied to all 5.
Endothermic reactions consume energy in the form of heat. Endothermic reactions occur when molecules absorb energy from surroundings, causing them to break and form new bonds with other molecules.
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Part 1: Read the following information on elements, compounds and mixtures. Fill in the blanks where necessary Elements: A pure substance containing only one kind of • An element is always uniform all the way through (homogeneous). An element be separated into simpler materials (except during nuclear reactions). • Over 100 existing elements are listed and classified on the Compounds: A pure substance containing two or more kinds of The atoms are __combined in some way. Often times (but not always) they come together to form groups of atoms called molecules • A compound is always homogeneous (uniform). Compounds _ be separated by physical means. Separating a compound requires a chemical reaction The properties of a compound are usually different than the properties of the elements it contains. Mixtures: • Two or more NOT chemically combined. • No reaction between substances. • Mixtures can be uniform (called ) and are known as solutions. • Mixtures can also be non-uniform (called • Mixtures can be separated into their components by chemical or physical means. • The properties of a mixture are similar to the properties of its components. Part 2: Classify each of the following as elements (E), compounds (C) or Mixtures (M). Write the letter X if it is none of these. Diamond (C) Sugar (C.H.O.) Milk Air Sulfuric Acid (H:50.) Gasoline Krypton (K) Bismuth (B1) Uranium (U) Water (H20) Alcohol (CH,OH) Pail of Garbage Ammonia (NH3)_ Salt (NaCl) Energy Wood Bronze Dry Ice (CO) _Baking Soda (NaHCO)_Titanium (T1) Iron (Fe) Electricity Popcorn A dog Gold (Au) Pizza Concrete Ink CHEM 1101 AY 2019-2020 SEM 2
A pure substance containing two or more kinds of the atoms are elements combined in some way. Compounds can be separated by physical means.
A physical approach cannot separate the components of a substance. Chemical or electrochemical methods must be used to separate the elements from compounds because they are chemically bonded together.
A compound is anything created when two or more separate chemical elements are mixed together in a specific proportion. Chemical connections that are challenging to break are created when the elements interact with one another. These bonds develop as a result of atoms sharing or trading electrons.
A mixture is a substance composed of two or more unrelated chemical components. A mixture is a physical combination of two or more distinct substances that can take the form of solutions, suspensions, or colloids.
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How much volume of the above stock solution you will need to prepare the riboflavin solutions of following concentrations: (a) 0.059 mM in 25 ml (b) 14 uM in 25 ml
0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
To prepare a 0.059 mM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water.
First, we need to convert the concentration from mM to μM:
0.059 mM × 1000 μM/1 mM = 59 μM
Next, we need to calculate the amount of riboflavin required to prepare a 25 ml solution with a concentration of 59 μM:
59 μM × 25 ml = 1475 μmol
Finally, we need to convert μmol to milligrams:
1475 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.055 g
So, 0.055 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 0.059 mM solution.
To prepare a 14 μM riboflavin solution in 25 ml, we need to calculate the amount of riboflavin to add to 25 ml of water:
14 μM × 25 ml = 350 μmol
Finally, we need to convert μmol to milligrams:
350 μmol × (375.2 g/mol) / (10⁻⁶ μmol/mol) = 0.013 g
So, 0.013 g of the stock solution of riboflavin needs to be added to 25 ml of water to prepare a 14 μM solution.
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Which of the following statements about subatomic particles are correct? (select all that apply)
A. Neutrons and protons are the only charges subatomic particles
B. The charge on a proton is equal in magnitude and opposite in sign to that of an electron
C. The mass of a proton is similar to that of a neutron
D. The mass of a neutron is slightly greater than that of an electron
The following statements about subatomic particles are correct:
B. The charge on a proton is equal in magnitude and opposite in sign to that of an electron
C. The mass of a proton is similar to that of a neutron
D. The mass of a neutron is slightly greater than that of an electron.
Subatomic particles refer to the basic building blocks of matter that make up atoms. The main subatomic particles are:
Protons: Positively charge particles found in the nucleus of an atom. The number of protons in an atom determines the atomic number, and thus the identity, of the element.
Neutrons: Neutral particles found in the nucleus of an atom. The number of neutrons in an atom can vary, resulting in isotopes of the same element.
Electrons: Negatively charged particles that orbit the nucleus of an atom. The number of electrons in an atom determines its chemical properties and reactivity.
These subatomic particles interact with each other through electromagnetic forces to form the atoms and molecules that make up matter. Understanding the behavior and interactions of subatomic particles is key to understanding the properties and behavior of matter on a macroscopic scale.
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the bjerrum plot shows the relative concentrations of each carbonate species in seawater at different ph's. please select the relative concentrations of carbonate species in seawater at ph of 7.
Relative concentrations of carbonate species in seawater at pH of 7 is [HCO3-]= 4.1 Mmol, [H2CO3]=0.91 Mmol-1, [CO3 2-]= 1.9x 10-3 Mmol.
Find attached Bjerrum plot shows the relative concentrations of each Carbonate species in seawater at different pHs.
The reactions between carbon dioxide, hydrogen ions, bicarbonate and Carbonate ions, all dissolved in water, are as follows:
CO2 + H2O ⇌ H+ + HCO−3
(1) HCO−3 ⇌ H+ + CO2−3
Reaction 1 is actually the combination of two elementary reactions:
CO2 + H2O ⇌ H2CO3 ⇌ H+ + HCO−3
Sea-water reactions.
H+ has very little final role in the seawater reactions. We can express Them as:
CO2 + CO3-- + H2O ⇌ 2HCO3-
Ca++ + CO3-- ⇌ CaCO3 (aragonite).
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A sample of oxygen gas initially at 0.760 atm is cooled from 27°C to −93°C at constant volume.
What is its final pressure (in atm)?
Answer:
0.38 atm
Explanation:
Gay-Lussac's Law states:
[tex]\frac{P_1}{T_1} =\frac{P_2}{T_2}[/tex]
p = pressure
T = temperature
Change temps from Celcus to Kelvin:
27+273 = 360
-93+273 = 180
plugging the information in we have:
[tex]\frac{0.760 atm}{360K} = \frac{x}{180K}[/tex]
Cross multiply:
136.8 = 360x
divide 136.8 by 360 = .38 atm
8. A cashier at Whole Foods measures the weight (mass) of fruit with an electronic scale at the register.
If the cashier accidentally leaves a pen on the scale for each measurement, would this contribute to
random error or systematic error? Explain.
Leaving a pen on the scale for each measurement would contribute to systematic error.
The term "systematic error" describes a predictable and repeatable deviation in measurement results that takes place in the same direction every time the measurement is taken. In this instance, each measurement is consistently and repeatedly deviated by the pen on the scale, systematically elevating all of the readings above the actual weight of the fruit.
What is a systematic error with an example?
A systematic error is one that consistently changes in the same manner. For instance, if something consistently or frequently raised the blood pressure right before the measurements, this might happen when taking blood pressure.
What is the random error?
Each measurement varies slightly from the next because of random error. Unexpected outcomes of an experiment are where it comes from.
What are 3 systematic errors?
Environmental Errors.
Observational Errors.
Instrumental Errors.
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Photoelectron spectroscopy typically measures the binding energy of electrons in units of
MJ/mol
. Use the value for the energy of an electron in a hydrogen atom in the ground state that you just calculated using the Bohr model to predict the binding energy for the electron in hydrogen in units of
MJ/mol
. Note: If you are not sure where to start to answer this question, click on the "Extra Info" button. Binding energy for the electron in hydrogen predicted by the Bohr model
=
MJ/mol
Check your calculated value. To answer this question, remember that
E binding =−E e−
​ . It can also be helpful to think of the units for the energy of the electron as J/electron, while the units for the binding energy are
MJ/mol
of electrons. You will need Avogadro's number and conversion factor for the prefix mega (M).
Previous question
The predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
Using the value for the energy of an electron in a hydrogen atom in the ground state calculated using the Bohr model, we have:
E_binding = -E_electron = -(13.6 eV) = -2.18 × 10²-18 J/electron
To convert from J/electron to MJ/mol, we can use the following conversions:
1 J/electron * (1 mol/6.022 x 10²23 electrons) = 1.66 x 10²-24 J/mol
1 MJ = 10²6 J
So, putting it all together:
E_binding = (-2.18 x 10²-18 J/electron) * (1 mol/6.022 x 10²23 electrons) * (10²-6 MJ/1 J) = -13.6 MJ/mol
Therefore, the predicted binding energy for the electron in hydrogen in units of MJ/mol is -13.6 MJ/mol.
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which of the following elements (p, na, o, n) is most likely to form a compound involving an expanded valence shell of electrons? explain.
The element most likely to form a compound involving an expanded valence shell of electrons is oxygen (O).
Oxygen has a valence shell of 6 electrons and it is able to form a variety of compounds with other elements by sharing its electrons with them. This gives oxygen the ability to form compounds with expanded valence shell, and is one of the reasons why it is such a versatile element.Oxygen is an essential element in the air that humans and other animals need to survive. It is the most abundant element on Earth and makes up 21% of the atmosphere. Oxygen is a colorless, odorless gas that is essential for the respiration of living organisms. It is also used in a variety of industrial processes, such as the production of steel, plastics
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Describe the situations when Greek prefixes are used:
a) To specify the number of hydrogen atoms in the formula of simple nonmetal hydrogen compounds.
b) To specify the number of water molecules in a hydrate.
c) To specify the number of atoms of each element in molecular compounds.
d) To specify the charge of elements in the names of polyatomic compounds.
e) To specify the number of atoms of each element in ionic
compounds.
**YOU CAN CHOOSE MULTIPLE
The situations when Greek prefixes are used to specify the charge of elements in the names of polyatomic compounds. Therefore, option D is correct.
When and why are prefixes used when naming compounds?Because molecular compounds can form compounds with different element ratios, prefixes are used to specify the number of atoms of each element in a compound molecule. SF₆, sulfur hexafluoride, and N₂O₄, dinitrogen tetroxide are two examples.
Greek prefixes are used to indicate the number of atoms of each nonmetal element in the compound's chemical formula. The prefix "mono-" is not used if the compound contains only one atom of the element listed first in the name.
Thus, option D is correct.
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Mathematical Representations Quick Check
How does the formation of water from hydrogen and oxygen demonstrate the conservation of mass? (1 point)
Storm
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same
number of atoms as the reactants.
The atomic number of the reactants equals the atomic number of the product, and the product has the same
number of atoms as the reactants
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
number of molecules as the reactants.
The atomic mass of the reactants equals the atomic mass of the product, and the product has the same.
What is the conservation of mass?The conservation of mass is a fundamental principle in physics and chemistry that states that the total mass of a system remains constant, regardless of any changes that take place within the system. In other words, mass cannot be created or destroyed, only transformed from one form to another.
This law applies to both physical and chemical processes, and is a key concept in fields such as thermodynamics, mechanics, and material science. It forms the basis for our understanding of the behavior of matter and energy in the universe, and is widely used in scientific and engineering calculations and experiments.
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Answer:
1. the reactants and the products have the same number of atoms of the same elements
2. the mass of one titanium atom is equal to the mass of four carbon atom
3. The atomic mass of the reactants equals the atomic mass of the product, and the product has the same number of atoms as the reactants.
4. 80amu
5. A molecule with two atoms combined with a molecule with three atoms to produce a molecule with a mass of 84 u.
Explanation: got 100% hope you get the same!