what can you infer about angles w and z based on the information in the other triangles?

Answer:

a = 3

Step-by-step explanation:

(a, -1) is (x, y)

Plug in the value of y into the given equation to solve for a (x):

4x - 3(-1) = 15

4x + 3 = 15

4x = 12

x = 3

(x, y) is (a, -1) so (a, -1) = (3, -1)

Answer: a=3

Step-by-step explanation:

We are given a point and an equation. To see what "a" is, we can plug in the coordinate into the equation and solve for x.

4a-3(-1)=15       [multiply]

4a+3=15           [subtract both sides by 3]

4a=12               [divide both sides by 4]

a=3

Now, we know that a=3.

Answer:

x= -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^{2}[/tex]+6x=12

We add 9 [[tex](6/2)^{2}[/tex]] to both sides to complete the square as [tex]x^{2}[/tex]+6x+9 = [tex](x+3)^{2}[/tex].

[tex](x+3)^{2}[/tex]=21

Now we take the square root of both sides:

x+3=±[tex]\sqrt{21}[/tex]

x= -3 ± [tex]\sqrt{21}[/tex]

Answer:

x = -3 ± [tex]\sqrt{21}[/tex]

Step-by-step explanation:

[tex]x^2+6x=12[/tex]

[tex](\frac{b}{2} )^{2}[/tex] = 9

[tex]x^2+6x + 9 =12 + 9[/tex]

[tex](x+3)^{2} =21[/tex]

x + 3 = [tex]\sqrt{21}[/tex]

x = -3 ± [tex]\sqrt{21}[/tex]

Answer:

A

Step-by-step explanation:

180 - 75 = 105

9514 1404 393

Answer:

Step-by-step explanation:

We assume ...

The wall area is the wall height times the perimeter of the room.

  wall area = (25')(2(100' +65')) = 8250 ft²

The ceiling area is the product of length and width.

  ceiling area = (100')(65') = 6500 ft²

Then the area to be painted with each coat is ...

  painted area = wall area + ceiling area = (8250 +6500) ft² = 14750 ft²

Then two coats of paint will require sufficient paint to cover ...

  (2 coats)×(14750 ft²/coat) = 29,500 ft²

__

If each can of paint covers 1750 ft², the number of cans required is ...

  (29,500 ft²)/(1750 ft²/can) = 16.86 cans

  17 cans must be purchased

__

The cost of 17 cans of paint with sales tax will be ...

  (17 cans)($151.99/can)(1 +15%) = $2971.40

Answer:

4 + 5i

Step-by-step explanation:

To calculate this you have to combine the like terms until they cannot be combined any further:

7 + 10i + 4 - 10i - (7 - 5i)

11 + 0i - 7 - 5i

7 & 4 are liked terms so add them together + subtract 10i and 10i

4 + 5i  <--- Final answer

Hope this helps!

Answer:

4 + 5i

Step-by-step explanation:

(7 + 10i) + (4 - 10i) - (7 - 5i)

7 + 10i + 4 - 10i - (7 - 5i)

11 - 7 + 5i

4 + 51

Answer:

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

95°=6r°+47(being vertically opposite angle)

or,48°=6r

or,48=/6=r°

or,r=8°

Answer:

2

Step-by-step explanation:

Since x=0, and it's not <0, the "else statement" is executed making y=0+2

There is a category called "computer and technology", maybe you can get better answers if you select that instead of "mathematics"

Answer:

3x

Step-by-step explanation:

Answer:

Joel wants to find the quotient of a number and 4, minus thirteen

Step-by-step explanation:

Given the expression :

n/4 - 13

The options B and D cannot be possible answers as they are referring to products and sums which is not a part of the operation used in the expression.

However, the most appropriate option would be A because,

13 is subtracted from the quotient of n/4 which is what the first option expresses.

What is meant by option C however is :

13 - n/4

Hence. Option A is the correct choice.

Answer:

Joel wants to find the quotient of a number and 4, minus thirteen

Step-by-step explanation:

Answer:2x + 50 > 68

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

because is you skip count on two you will count on to 68 so that is why the answer is 7.

Answer:

3 units

Step-by-step explanation:

(4,2) (7,2)

Subtract 4 from 7 = 3

Subtract 2 from 2 = 0

This means that (7,2) is 3 units up from (4,2).

:) ur welcome

Answer:

Step-by-step explanation:

D=√(x2-x1)²+(y2-y1)²

D=√(7-4)²+(2-2)²

D=√(3)²+0

D=3²*½

D=3

Answer:

B. -infinity < x < infinity

Step-by-step explanation:

Since it's linear and kind of horizontal, it stretches to infinity on both sides (indicated by arrows on both sides of the line.

The tangent to the curve at a point P (x, y) has slope dy/dx at that point. By the chain rule,

dy/dx = (dy/dθ) / (dx/dθ)

We're in polar coordinates, so

y (θ) = r (θ) sin(θ)   ==>   dy/dθ = dr/dθ sin(θ) + r (θ) cos(θ)

x (θ) = r (θ) cos(θ)   ==>   dx/dθ = dr/dθ cos(θ) - r (θ) sin(θ)

We're given r (θ) = 1 - sin(θ), so that

dr/dθ = -cos(θ)

Then the slope of the tangent to the curve at P is

dy/dx = (dr/dθ sin(θ) + r (θ) cos(θ)) / (dr/dθ cos(θ) - r (θ) sin(θ))

dy/dx = (-cos(θ) sin(θ) + (1 - sin(θ)) cos(θ)) / (-cos²(θ) - (1 - sin(θ)) sin(θ))

dy/dx = - (cos(θ) - sin(2θ)) / (sin(θ) + cos(2θ))

The tangent is horizontal if dy/dx = 0 (or when the numerator vanishes):

cos(θ) - sin(2θ) = 0

cos(θ) - 2 sin(θ) cos(θ) = 0

cos(θ) (1 - 2 sin(θ)) = 0

cos(θ) = 0   or   1 - 2 sin(θ) = 0

cos(θ) = 0   or   sin(θ) = 1/2

[θ = π/2 + 2nπ   or   θ = 3π/2 + 2nπ]   or   [θ = π/6 + 2nπ   or   θ = 5π/6 + 2nπ]

where n is any integer.

In the interval 0 ≤ θ ≤ 2π, we get solutions of θ = π/6, θ = 5π/6, and θ = 3π/2. (We omit π/2 because the denominator is zero at that point and makes dy/dx undefined.) So the points where the tangent is horizontal are themselves (√3/4, 1/4), (-√3/4, 1/4), and (0, -2), respectively.

The tangent is vertical if 1/(dy/dx) = 0 (or when the denominator vanishes):

sin(θ) + cos(2θ) = 0

sin(θ) + (1 - 2 sin²(θ)) = 0

2 sin²(θ) - sin(θ) - 1 = 0

(2 sin(θ) + 1) (sin(θ) - 1) = 0

2 sin(θ) + 1 = 0   or   sin(θ) - 1 = 0

sin(θ) = -1/2   or   sin(θ) = 1

[θ = 7π/6 + 2nπ   or   θ = 11π/6 + 2nπ]   or   [θ = π/2 + 2nπ]

Then for 0 ≤ θ ≤ 2π, the tangent will be vertical for θ = 7π/6 and θ = 11π/6, which correspond respectively to the points (-3√3/4, -3/4) and (3√3/4, -3/4). (Again, we omit π/2 because this makes dy/dx non-existent.)

Answer:

C

Step-by-step explanation:

tracing paper is your friend

Answer: About 6.71 units

Step-by-step explanation:

You use the distance formula: [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} }[/tex].

Assign the the two points to the variables:

[tex](x_{1}, y_{1}) = (1, 3)\\(x_{2}, y_{2}) = (4, -3)[/tex]

Substitute them in the formula:

[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}[/tex]

And solve it:

[tex]\sqrt{(4-1)^{2}+(-3-3)^{2}}\\=\sqrt{(3)^{2}+(-6)^{2}}\\=\sqrt{9+36}\\=\sqrt{45}\\=6.71[/tex]

Answer:

I got the answer as 6.70 .here's how

Step-by-step explanation:

c= ( 1,3)

d=(4,-3)

Now , formula of distance

√(x2 - x1)^2 +(y2 - y1)^2

or, √(4-1)^2+(-3-3)^2

or, √(3)^2+(-6)^2

or,√9+36

or√45

√45 = 6.70 units approx

Answer:

3/4-1/2=1/4 4/5-3/15

Step-by-step explanation:

3/4-1/2

=3/4-2/4

=1/4

4/5-3/15

=4/5-1/5

=3/5

Answer:I’m pretty sure ( not 100% thou ) the awnser would be A) 4

Answer:

[tex]x^{2}[/tex] + 7x + 12

Step-by-step explanation:

The area of a parallelogram is A = bh, where the base is the length.

To solve this, you have to multiply 4 + x and x + 3.

(4 + x)(x + 3)

If you factor this more, it should be equal to:

[tex]x^{2}[/tex] + 3x + 4x + 12.

This simplified is equal to:

[tex]x^{2}[/tex] + 7x + 12.

Answer:

option d is correct one in which value of T lies

Answer:

Evaluación de expresiones y polinomios

Purplemath

"Evaluación" significa principalmente "simplificar una expresión a un solo valor numérico". A veces se le dará una expresión numérica, donde todo lo que tiene que hacer es simplificar; esa es más una cuestión de orden de operaciones. En esta lección, me concentraré en el aspecto de la evaluación de "conectar y tragar": introducir valores para las variables y "avanzar" hasta llegar a la respuesta simplificada.

(Por cierto, sí, "plug-n-chug" es una terminología bastante estándar. No es un término "técnico", por lo que probablemente no lo verá en su libro de texto, pero seguramente lo escuchará de otros estudiantes. , y quizás también su instructor.)

MathHelp.com

Evaluar expresiones en MathHelp.com

Evaluar expresiones

Por lo general, la única parte difícil de la evaluación es hacer un seguimiento de los signos "menos". Le recomiendo encarecidamente que utilice los paréntesis libremente, especialmente cuando recién está comenzando.

Evalúe a2b para a = –2, b = 3, c = –4 y d = 4.

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Para encontrar mi respuesta, simplemente conecto los valores dados, teniendo cuidado de usar paréntesis, particularmente alrededor de los signos "menos". Especialmente cuando recién estoy comenzando, dibujar los paréntesis primero puede ser útil:

a2 b

() 2 ()

(–2) 2 (3)

(4) (3)

12

Observe cómo el uso de paréntesis me ayudó a realizar un seguimiento del signo "menos" en el valor de a. Esto era importante, porque de otro modo podría haber elevado al cuadrado solo el 2, terminando con –4, lo que habría estado mal.

Por cierto, resultó que no necesitábamos los valores de las variables c y d. Cuando se le da un gran conjunto de expresiones para evaluar, debe esperar que a menudo haya una u otra de las variables que no se incluirán en ningún ejercicio en particular del conjunto.

Evalúe a - cd para a = –2, b = 3, c = –4 y d = 4.

En este ejercicio, me dieron información adicional. No hay una b en la expresión que quieren que evalúe, por lo que puedo ignorar este valor en mi trabajo:

(–2) - (–4) (4)

–2 - (–16)

–2 + 16

16 - 2

14

Step-by-step explanation:

hola

Answer - It’s 31.56

Step-by-step explanation: You just do regular multiplication and then add  the decimal point

Answer:

4x^2 + 12x + 8

Step-by-step explanation:

Won't go into it since some wonderful moderator will probably delete this because they feel like it.

But the answer is correct.

Answer:

the image is hard to read... this is the best that I can see

Step-by-step explanation:

[tex]\sqrt[3]{x^{3} } = x^{3/3} = x\\\sqrt[3]{x^{5} } = x^{5/3} \\\\\sqrt[5]{x } = x^{1/5} \\\\\sqrt[2]{x ^3 } = x^{3/2} \\[/tex]

~~~~~~~~~~~~~~~~~~~

Answer:

x = 4

y = 3

Step-by-step explanation:

Given equations :-

Second equation can be written as ,

Adding them :-

Put this in (ii) :-