What can we conclude from observing an attractive force between a positively charged rod and some object

Answer:

My youngins heartless, so they ain't playin' no games

We really want 'em dead, he got hit up close range

He fuc__ked up in the head, he wanna see some more brains

On that corner, I couldn't stay up out that do_0pe game

My cousin got indicted dealin' coc__aine

She an Insta>:gram addict, she want more fame

I used to starve, now I'm blowing up like pro__pane

Told my inner self, "I promise you I won't change"

Explanation:

Answer:

6g/cm³

Explanation:

Given parameters;

Mass  = 600g

Dimension  = 2cm wide, 2cm tall and 25cm long

Unknown:

Density  = ?

Solution

Density is the mass per unit volume of any substance. To solve this problem:

   Density  = [tex]\frac{mass}{volume}[/tex]  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = [tex]\frac{600}{100}[/tex]    = 6g/cm³

Answer:

26.17

1.17

30.86

5.86

Explanation:

said they were correct on my assignment

Given :

Initial speed, u = 0 m/s.

Final speed, v = 9 m/s.

Time taken to reach that speed, t = 2 sec.

To Find :

The acceleration of the athlete.

Solution :

We know, in uniform acceleration motion :

[tex]v= u+at\\\\a = \dfrac{v-u}{t}\\\\a = \dfrac{9-0}{2}\ m/s\\\\a = 4.5 \ m/s^2[/tex]

Therefore, acceleration of the athlete is 4.5 m/s².

Answer:

15.106 N

Explanation:

From the given information,

The weight of the bucket can be calculated as:

[tex]W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N[/tex]

The mass of the water accumulated in the bucket after 3.20s is:

[tex]m_w= (0.20 \ L/s) ( 3.20)s[/tex]

[tex]m _w=0.64 \ kg[/tex]

To determine the weight of the water accumulated in the bucket, we have:

[tex]W_w = m_w g[/tex]

[tex]W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)[/tex]

[tex]W_w = 6.272 \ N[/tex]

For the speed of the water before hitting the bucket; we have:

[tex]v = \sqrt{2gh}[/tex]

[tex]v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}[/tex]

v = 8.4 m/s

Now, the force required to stop the water later when it already hit the bucket is:

[tex]F = v ( \dfrac {dm}{dt} )[/tex]

[tex]F = (8.4 \ m/s)( 0.200 \ L/s)[/tex]

F = 1.68 N

Finally, the reading scale is:

[tex]F_{scale[/tex] = 7.154 N + 6.272 N + 1.68 N

= 15.106 N

Answer:

F_scale ≈ 15.12 N

Explanation:

We are given;

Mass flow rate; m' = 0.2 l/s

Time; t = 3.2 s

Mass of bucket; m_b = 0.730 kg

Height; h = 3.6 m

Now, mass of water is;

m_w = 0.2 l/s × 3.2 s

m_w = 0.64 l

From conversion, 1 litre = 1 kg

Thus: m_w = 0.64 kg

Now, let's calculate final velocity from Newton's third equation of motion.

v² = u² + 2gh

Initial velocity is 0. Thus;

v² = 0 + 2(9.8 × 3.6)

v² = 70.56

v = √70.56

v = 8.4 m/s

Now, total mass of water and bucket is;

m_t = m_w + m_b = 0.64 + 0.73

m_t = 1.37 kg

Force on the scale is calculated from;

F_scale = (m_t)g + (m_w)v/t

F_scale = (1.37 × 9.81) + (0.64 × 8.4/3.2)

F_scale ≈ 15.12 N

Answer:

A circle.

Explanation:

When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory is a circle.

This ultimately implies that, a charged particle moving perpendicularly to a uniform magnetic field would undergo or experience a uniform circular motion and this simply, describes its trajectory.

Additionally, the frequency would be directly proportional to the mass of the charged particle.

Answer:

100m/s²

Explanation:

F=ma

50=0.5a

a=50/0.5

a=100

Answer: 0

Explanation: because when it return total displacement is 0

This question is not complete, the complete question is;

Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 20 m . Calculate the frequency of these radio waves.

Answer: frequency of the radio waves is 15 MHz

Explanation:

Given that;

wavelength λ = 20 m

we know that; Speed of light C = 3 × 10⁸ m/s

frequency f = ?

we know that;

frequency f = Speed of light C / wavelength λ

so we substitute

frequency f = (3 × 10⁸m/s) / (20m)

frequency f = 15 × 10⁶ Hz

we also know that 1 Hertz = 0.000001 Megahertz

so

frequency f = 15 × 10⁶ Hz × 0.000001

frequency f = 15 MHz

Therefore frequency of the radio waves is 15 MHz

Answer:

Spaceship Vibes

Explanation:

Song written by NoCap

Answer:

force; distance; energy.

Explanation:

An impulse can be defined as the net force acting an object for a very short period of time.

Mathematically, impulse is given by the formula;

[tex] Impulse = force * time[/tex]

An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.

Mathematically, work done is given by the formula;

[tex] Work done = force * distance [/tex]

Answer:

T on edge

Explanation:

Answer:

true

Explanation:

Answer:

Magnetism is the force exerted by magnets when they attract or repel each other

hope it helps you:)

Squamous cells, which are tiny, flat cells that resemble fish scales, are present in the tissue that makes up the skin's surface, and the lining of the digestive and respiratory systems.

Simple squamous epithelial cells serve as filtration and diffusion mediators. They enable facile transmembrane transit of tiny molecules (i.e., across the membrane and through the cell) because of their straightforward and thin construction.

The centre of squamous epithelial cells, which are big, flattened cells loaded with cytoplasm, is a small, spherical nucleus. They are spherical and unevenly flat.

Therefore, The lumen is a free area that is surrounded by simple squamous epithelium. Simple squamous cells join together to produce a layered structure.

Learn more about Squamous cells here:

https://brainly.com/question/3041690

#SPJ2

Answer:

tow a has the most power but tow b does the most work

Explanation:

Tow A with a heavier load pulls as fast as Tow B, Then A does The most work, and A also has more power.

It is defined as the Rate of work done or the ratio of work done and time.

If the amount of work(W) is down over a time interval of (t) then the power is given by,

P=W/t

Where W=is  work done by a force is known as a product of force and distance.

t= time interval in s.

Force

F= force which is known as the rate of momentum.=mv/t

where m= mass of the body in kg.

v= velocity in m/s.

Here in the question, given that A pulls heavier weight than B that means A applied more force which results in more work.

When more work is done by A than by B then the power of an also greater than B because they move at the same velocity.

Hence, The Work done as well as the power of A is more.

To find more on work done click:

https://brainly.com/question/28172139

#SPJ3

Answer:

its n

Explanation:

The acceleration of the boat is obtained as 1.6 ms-2.

We have to obtain the resultant force acting on the boat in order to obtain the acceleration of the boat.

Resultant force on the boat = √(25)^2 + (20)^2 = √625 + 400 = 32 N

Now recall that from Newton's laws; F = ma

m= mass of the body

a = acceleration of the body

32 N = 20Kg × a  

a =  32 N/20Kg

a = 1.6 ms-2

Learn more about force: https://brainly.com/question/1301963

Answer:

We need the question

Explanation:

The answer is the first choice.

Answer:

False, it is a fuse.

Explanation:

In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.

Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.

A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.

Source: https://en.wikipedia.org/wiki/Fuse_(electrical)

A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.

A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.

Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.

Source: https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html

Answer:

Statement B is the only true statement

"Decreasing the mass of an object increases its acceleration while force is  constant."

Explanation:

Recall that Newton's 2nd Law states:

F = m * a

Therefore, if the force (F) is constant, and the mass (m) decreases, the acceleration (a) of the object must increase.

This agrees with the statement labeled as B: "Decreasing the mass of an object increases its acceleration while force is  constant."

The true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.

NEWTON'S LAW:

Learn more at: https://brainly.com/question/25116504?referrer=searchResults

Answer:

Its mass increases and weight decreases. Its mass remains constant and weight decreases.

Answer:

A) Energy is tranferred from Joey to the water. The temperature of the water increases.

Explanation:

At first Joey jumps and gains a height above the water level of the pool, this way has an energy potential initial, as Joey falls into the water his speed is increased that is to say its energy potential is transformed into kinetic energy, and at the moment of impact with the water, this energy kinetic is transformed into heat which is transferred to the water. Therefore the temperature increment.

Note: This is one of the reasons why space agencies are studying  spatial asteroids that are directed toward the earth, as these come with great kinetic energy, and great potential energy, if these are of a considerable size can cause catastrophic damage, even if they fall into the ocean, due to the large amount of energy which can cause the instantaneous evaporation of large amounts of water and collateral damage in other areas.

Answer:

The total net momentum after the push is 0.

Explanation:

The total net momentum is given by:

[tex] p_{f} = p_{1_{f}} + p_{2_{f}} = m_{1}v_{1} + m_{2}v_{2} [/tex]

Where:

m₁: is the mass of 70 kg

m₂: is the mass of 60 kg

v₁: is the speed of 2.5 m/s

v₂:?

To find the final momentum first we need to find the speed v₂:

[tex]m_{1}v_{1} + m_{2}v_{2} = p_{i}[/tex]  

Where [tex]p_{i}[/tex] is the initial momentum = 0 (they are at rest)          

[tex] v_{2} = -\frac{m_{1}v_{1}}{m_{2}} = -\frac{70 kg*2.5 m/s}{60 kg} = -2.92 m/s [/tex]          

The minus sign is because the second person is moving in the opposite direction to the first person.

Now, the total net momentum is:

[tex] p_{f} = m_{1}v_{1} + m_{2}v_{2} = 70 kg*2.5 m/s + 60 kg*(-2.92 m/s) = 0 [/tex]

The final total momentum (after the push) should be zero because of momentum conservation.

Therefore, the total net momentum after the push is 0.

I hope it helps you!                

Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Answer:Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Answer:

Blank 1: 10

Blank 2: 4

Blank 3: 10

Blank 4: 5

Blank 5: 5

Answer:

[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]

Explanation:

From the question we  are told that

Voltage decreases at   [tex]\frac{dv}{dt} =-0.03volts/sec[/tex]

Resistance increase at [tex]\frac{dR}{dt}=0.02ohms /sec[/tex]

Resistance at [tex]R=100ohms[/tex]

Current at [tex]I=0.02amps[/tex]

Generally the equation for ohms law is mathematically represented as

       [tex]V=IR[/tex]

Therefore

       [tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

Generally making [tex]\frac{dI}{dt}[/tex] subject of the formula in the above equation mathematically gives

       [tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]

      [tex]R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}[/tex]

       [tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})[/tex]

Therefore

       [tex]\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))[/tex]

Generally it is given that the change in current is

       [tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]

Answer:

I think it's no. 3

Decrease the volume of the horizontal and vertical stabilizer material.

Explanation:

Lemme know if it's correct

Answer:

all of the above

Explanation: