Answer:
1. the study of the structure, properties, and interactions of materials and the changes they undergo
2. the study of matter and energy and how they interact
3. the systematic study and analysis of facts
4. a process to test a proposed solution to a problem
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Until the 1600s, people who investigated problems related to our understanding of the natural world were called _____.
Click ca
Explanation:
The umbilicus in on the __ surface of the hand
Answer:
Umbilicus can't be on the hand....it is located in the abdomen....
Determine whether each of the following salts will form a solution that is acidic, basic, or pH-neutral.
a. KCl
b. NaClO
Answer:
a. Neutral
b. Basic
Explanation:
To determine which of the salts are acidic, neutral or basci we should dissociate them and determine if the ions, can make hydrolysis to water.
KCl → K⁺ + Cl⁻
We need to know, where do the ions come from. In this case, K⁺ comes from the KOH which is a strong base and Cl⁻ comes from the HCl, a strong acid. In conclussion, both are the conjugate weak acid and base, respectively. They do not make hydrolysis, so this salt is neutral. No protons or hydroxides are given.
NaClO → Na⁺ + ClO⁻
The Na⁺ comes from the NaOH, it is the conjugate weak acid from a strong base, while the ClO⁻ comes from the HClO, a weak acid. This means that the ClO⁻ can react to water, to make hydrolysis. The equilibrium will be:
ClO⁻ + H₂O ⇄ HClO + OH⁻
We are giving hydroxides to medium, so the salt is basic.
Identify the product of radioactive decay and classify the given nuclear reactions accordingly.
a) 23488Ra â 23086Rn + _____
b) 23892U â 23893Np + _______
c) 24294Pu â 23892U + ______
d) 146C â 147N + ______
e) 2412Mg â 2412Mg + ________
Answer: a) [tex]_{88}^{234}\textrm{Ra}\rightarrow _{86}^{230}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]
b) [tex]_{92}^{238}\textrm{Ra}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]
c) [tex]_{92}^{238}\textrm{Ra}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]
d) [tex]_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^{0}{\beta}[/tex]
e) [tex]_{12}^{24}\textrm{Mg}\rightarrow _{12}^{24}\textrm{Mg}+_{0}^{0}{\gamma}[/tex]
Explanation:
A balanced nuclear equation is one in which the atomic number and mass number remains same on both sides of the equation i.e the number of protons and neutrons remain same.
General representation of an element is given as:
Z represents Atomic number
A represents Mass number
X represents the symbol of an element
a) [tex]_{88}^{234}\textrm{Ra}\rightarrow _{86}^{230}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]
b) [tex]_{92}^{238}\textrm{U}\rightarrow _{93}^{238}\textrm{Np}+_{-1}^{0}{\beta}[/tex]
c) [tex]_{94}^{242}\textrm{Pu}\rightarrow _{92}^{238}\textrm{Ra}+_{2}^{4}\textrm{He}[/tex]
d) [tex]_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^{0}{\beta}[/tex]
e) [tex]_{12}^{24}\textrm{Mg}\rightarrow _{12}^{24}\textrm{Mg}+_{0}^{0}{\gamma}[/tex]
The following initial rate data are for the reaction of hypochlorite ion with iodide ion in 1M aqueous hydroxide solution: OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
What is the rate law for this reaction?
a. Rate = [1-1
b. Rate = K[OCI-11-2
c. Rate = K[OCI,20-1
d. Rate = K[OCH
e. Rate = K[OC1-20-1
Answer:
Rate = k [OCl] [I]
Explanation:
OCI+r → or +CI
Experiment [OCI] M I(-M) Rate (M/s)2
1 3.48 x 10-3 5.05 x 10-3 1.34 x 10-3
2 3.48 x 10-3 1.01 x 10-2 2.68 x 10-3
3 6.97 x 10-3 5.05 x 10-3 2.68 x 10-3
4 6.97 x 10-3 1.01 x 10-2 5.36 x 10-3
The table above able shows how the rate of the reaction is affected by changes in concentrations of the reactants.
In experiments 1 and 3, the conc of iodine is constant, however the rate is doubled and so is the conc of OCl. This means that the reaction is in first order with OCl.
In experiments 3 and 4, the conc of OCl is constant, however the rate is doubled and so is the conc of lodine. This means that the reaction is in first order with I.
The rate law is given as;
Rate = k [OCl] [I]
Which of these is the basic unit of mass?
L
kg
cm
ml
your friend makes the statement that " I think water boils at a higher temperature than ethanol," to which step of scientific method does this statement belong? scientific law hypothesis experiment observation
hypothesis
need 20 characters hope this helps
I WILL GIVE BRAINLYEST 40+ POINTS
A is correct because the atomic number determines that there are two protons and electrons. The atomic mass minus the atomic number determines that there are two neutrons.
B is correct because the atomic number determines that there are two protons and neutrons. The atomic mass determines that there are four electrons in the electron shell.
D is correct because the atomic number determines that there are two protons and electrons. The atomic mass minus the atomic number determines the number of neutrons.
C is correct because the atomic number determines that there are two protons and electrons. The atomic mass determines that there are four neutrons in the nucleus.
Answer:
The correct answer is A.
Explanation:
Helium's Atomic Model has 2 Protons and 2 Neutrons, and on the outside it has 2 electrons circling around it.
Answer:
is A
Explanation:
calculate the number of neutrons in the chlorine 17Cl35 and 17Cl37 ?
Answer: chlorine 17Cl35 has 18 neutrons, and 17Cl37 has 20 neutrons
Explanation: 17 is the atomic number of chlorine which tells us what is the number of protons in chlorine nucleus. 35 and 37 is the mass number of two isotopes of chlorine, it tells us what is the total number of protons and neutrons in atomic nucleus of two chlorine isotopes .
Now to know how many neutrons are in both isotopes we have to substract the number of protons from the mass number of each isotope
For 17Cl35 it will be 35- 17 what makes 18 and for 17 Cl 37 it will be 20 neutrons
Explain how passive and active transport are similar and how they are different.
Answer:
Sample Response: Both passive and active transport move substances into and out of the cell across the cell membrane. However, passive transport does not require the use of energy because molecules move from an area of high concentration to an area of low concentration. Active transport does require the use of energy because molecules move from an area of low concentration to an area of high concentration.
Explanation:
Active and passive transport are the two main biological processes which play an important role in providing the nutrients, oxygen, water and other essential molecules to the cells along with removing waste materials.
What are active and passive transport?The active transport involves the movement of molecules across a membrane against a concentration gradient which requires energy. The passive transport is the movement of molecules or ions across the cell membrane without using energy.
The differences between active and passive transport are: Active transport is a rapid process, passive transport is a slow process. Active transport transpires in one direction whereas passive one transpires bidirectionally. Active transport requires carrier proteins and energy whereas passive one does not require both.
The similarities among them are: both transport system require concentration gradient, both helps in homeostatic regulation and allow entry and exit of ions.
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Write the Ksp expression for the sparingly soluble compound chromium(III) hydroxide, Cr(OH)3.
Ksp =________
Answer and Explanation: Ksp is the Solubility Product Constant and is the equilibrium constant that happens when a solid is dissolved in an aqueous solution.
The dissolution of chromium (III) hydroxide:
[tex]Cr(OH)_{3}_{(s)}[/tex] ⇄ [tex]Cr^{3+}_{(aq)} + 3OH^{-}_{(aq0)}[/tex]
Every equilibrium constant is of the form:
[tex]K = \frac{[products]^{coefficient}}{[reagents]^{coefficient}}[/tex]
Then,
[tex]K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}[/tex]
The reagent is not included because solids don't take part in euqilibrium constants.
So, Ksp of chromium (III) hydroxide is [tex]K_{sp} = [Cr^{3+}_{(aq)}][OH^{-}_{aq}]^{3}[/tex]
Perform the following calculations and round according to the rules for significant figures. Just type in the number as a number (ex: 44)
8.20cm + 2cm (assume that the number is already labelled with the unit of cm)=
PLEASE HELP
Answer:
10 cm (Approx)
Explanation:
Given:
8.20 cm + 2 cm
Find:
Round of the following number
Computation:
⇒ 8.20 cm + 2 cm
⇒ 10.20 cm
We know that 0.20 < 0.50
So,
⇒ 10.20 cm = 10 cm (Approx)
The molecular formula of benzene is C6H6. what is the empirical formula of benzene?
What is the density if the mass of your object is 54.6g and the volume is 15.30 mL?
Answer:
5ml
Explanation:not sure why
A molecule of sugar has 45 atoms to make up the substance. If a sugar crystal has 1000 molecules, how many atoms are present?
Answer:
45000 atoms
Explanation:
a molecule has 45 atoms
1000 molecules have how many atoms??
by mathematical cress cross calculation we get that:
45 X 1000 = 45000 atoms
Which of the following methods can be used to competely separate a solution containing alcohol and water?
Answer:
separating funnel method
How many moles are present 560.0 g of iron (lll) sulfate
Answer:
1.400 mol
Explanation:
To convert grams to moles, you will need the molar mass. The molar mass of iron(iii) sulfate is 399.88 g/mol. Divide grams by the molar mass to find moles.
(560.0 g)/(399.88 g/mol) = 1.400 mol
There are 1.400 mol present in 560.0 g of iron(iii) sulfate.
Which of the following characteristics is common to both acids and bases? They produce ions when dissolved in water They absorb oxygen ions when dissolved in water They increase hydrogen ions when dissolved in a solution They increase the hydroxide ions when dissolved in a solution
Answer:
They produce ions when dissolved in water.
Explanation:
Acids and bases have the characteristic in common to each other. Both of them have the property of reacting and dissolving in the water. Both acids and bases lead to the production of the ions when they are placed in a water solution. Acids produce Hydrogen ions when they are dissolved in water. Bases produce hydroxide ion when they are dissolved in water.
Answer:
A
Explanation:
Lab safety is not only important in the classroom, but it is also important to follow
the rules at home, or on the bus. Accidents can happen anywhere and if proper safety
precautions aren't followed, someone can get hurt.
Last year in New York, students were burned when they were showing off their
science project at the bus stop.
In Rhode Island, a student kept chemicals in his locker for a later experiment, the
chemicals combined and exploded hurting students in the hallway.
In Brazil, students were practicing their experiment in a friend's garage, without
adult supervision, when there was an explosion. The explosion killed all 4 students.
Science can be a lot of fun but it is also dangerous if you aren't following safety
precautions.
Questions: Answer on the following slide.
1. What is needed from adults when conducting experiments at home?
2. What should always be followed when conducting experiments?
3. Why are chemicals so dangerous?
4. What is science?
YO
Answer:
Follow safety measures and safety rules to avoid any accident.
Explanation:
1. Follow all safety measures is needed from adults when they conducting any experiment at home in order to prevent any damage occurs due to that experiment.
2. Safety rules should always be followed when conducting an experiment at any place such as at home, class room and laboratory etc in order to avoid any accident.
3. Some chemicals are very dangerous because they are flammable and catch fire when allow it to the heat source. Some chemicals also cause suffocation by absorbing all the oxygen from the environment and as a result death occurs.
4. Science is a systematic study of physical objects through observation and experiments. Science is a knowledge gain from experiments.
True or false 12,785.000 has five significant digits.
Answer:
True
Explanation:
Significant digits include non-zero digits (unless the zero is between two non-zero numbers)
In 12,785.000, there are 5 non-zero digits:
1 2 7 8 5
ANSWER: the answer is true.
If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.45 J/g･°C) that can be heated from 22.5°C to 120.0°C?
Answer:
The correct answer will be "18.25 g".
Explanation:
The given values are:
Specific heat,
C = 0.45 J/g･°C
Heat involved,
q = 801 J
Temperature,
ΔT = 120.0°C-22.5°C
= 97.5°C
As we know,
⇒ [tex]C = \frac{q}{m \Delta T}[/tex]
On substituting the given values, we get
⇒ [tex]0.45=\frac{801}{m(97.5)}[/tex]
⇒ [tex]m = 18.25 \ g[/tex]
The mass in grams of iron heated during the change in temperature is 18.26 grams.
Given the following data:
Initial temperature = 22.5°CFinal temperature = 120.0°CQuantity of heat = 801 JoulesSpecific heat capacity of iron = 0.45 J/g°C.To find the mass in grams of iron heated during the change in temperature:
Mathematically, quantity of heat is given by the formula;
[tex]Q = mc\theta[/tex]
Where:
Q represents the heat capacity or quantity of heat. m represents the mass of an object. c represents the specific heat capacity. ∅ represents the change in temperature.Making mass (m) the subject of formula, we have:
[tex]Mass = \frac{Q}{c \theta}[/tex]
Substituting into the formula, we have:
[tex]Mass = \frac{801}{0.45(120\;-\;22.5)} \\\\Mass = \frac{801}{0.45(97.5)} \\\\Mass = \frac{801}{43.875}[/tex]
Mass, m = 18.26 grams.
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If salt and water mixed together which is a solvent and which is the solute
Answer:
Solvent = Water
Solute = Salt
The structure shown is represented of which sub
Answer:
Option B. pentan-1-ol
Explanation:
We'll begin by writing the name of the compound.
The name of the compound above is pentylpropanoate.
From the name of the compound and the structure, we can suggest the following equation:
CH3CH2COOH + HOCH2CH2CH2CH2CH3 —> CH3CH2COOCH2CH2CH2CH2CH3 + H2O
Thus,
Propanoic acid + pentan-1-ol —> pentylpropanoate + water.
Therefore, the alcohol used in the reaction is pentan-1-ol
Calculate the standard cell potential given the following standard reduction potentials: Al3++3e−→Al;E∘=−1.66 VAl3++3e−→Al;E∘=−1.66 V Ag++e−→Ag;E∘=0.799 V
Answer:
2.459 V
Explanation:
If we look at the data we have from the question closely, we will discover that aluminum has a very negative reduction potential. Recall that very negative reduction potentials are associated with strong reducing agents.
Similarly, silver has a positive reduction potential signifying that it is an oxidizing agent. Since the reducing agent is oxidized in a redox reaction and the oxidizing agent is reduced.
Hence;
E°cell= E°reduction process - E°oxidation process
E°cell= 0.799 -(-1.66)
E°cell= 2.459 V
The standard cell potential is 2.459 V
Standard cell potential:The standard cell potential is the potential difference between the cathode and anode.
The overall cell potential can be calculated by using the equation: [tex]E_0cell=E_0red-E_0oxid[/tex].
Aluminum has a very negative reduction potential. The negative reduction potentials are associated with strong reducing agents and Silver has a positive reduction potential signifying that it is an oxidizing agent. Since the reducing agent is oxidized in a redox reaction and the oxidizing agent is reduced.
Hence;
E°cell= E°reduction process - E°oxidation process
E°cell= 0.799 -(-1.66)
E°cell= 2.459 V
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consider a 1000-ml graduated cylinder with marks every 100 ml. a student records the volume of liquid in the cylinder as 750 ml. is this the correct measurement? explain
Answer:
Explanation:
The 1000-ml graduated cylinder with marks every 100 ml has least count of 100 ml . It means it can not measure a volume less than 100 ml . It can also measure volume in the integral multiple of 100 ml like 200 ml , 300 ml , 400 ml etc perfectly . All these have significant figure of one .
It can not measure volume like 150 , 250 , 255 , 760 etc because these measurements are not the integral multiple of 100 . 750 is not a integral multiple of 100 so it can not measure volume of 750 ml.
Which of the following liquids would have the highest viscosity at room temperature?
1) CH3OCH3
2)CH2Cl2
3) C2H5OH
4) CH3Br
5)HOCH2CH2OH
Answer:
5)HOCH2CH2OH
Explanation:
This is also known as ethylene glycol. An increase in hydrogen bonds of a compound means an increase in the viscosity. Hydrogen bonds occur as a result of bonding with electronegative elements such as Oxygen, Nitrogen etc.
The compounds with the highest amount of Hydrogen bond represents the one with the highest viscosity which is B) HOCH2CH2OH
The liquid which would have the highest viscosity at room temperature is: Choice 5): HOCH2CH2OH.
Discussion:
The compound HOCH2CH2OH, named ethylene glycol relative to the other compounds has more hydrogen bonding.
By convention, an increase in the number of hydrogen bonds of a compound means an increase in the viscosity.
Hydrogen bonds are characterized by the of hydrogen with electronegative elements such as Oxygen, Nitrogen etc.
The compounds with the highest amount of Hydrogen bond is therefore; HOCH2CH2OH.
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If we add a catalyst to the following equation, CO + H2O + heat CO2 + H2, which way will the equilibrium shift?
Answer:
No effect.
Explanation:
Hello,
In this case, considering the widely studied Le Chatelier's principle, we can realize that the factors affecting equilibrium are concentration, temperature and pressure and volume if the reaction is in gaseous phase and with non-zero change in the number of moles. In such a way, by adding a catalyst to given reaction will have no effect on the equilibrium direction.
Best regards.
When determining the standard reduction potential of a substance by using a standard hydrogen electrode as a reference, the standard reduction potential will always be equal to:______.
ta. he reduction potential for the standard hydrogen electrode.
b. one-half the cell potential.
c. the overall cell potential.
d. impossible to predict.
Answer:
the overall cell potential
Explanation:
We must bear in mind that the standard hydrogen electrode is a reference electrode whose electrode potential has been arbitrarily set at 0 V.
The standard hydrogen electrode consists of hydrogen ion solution and hydrogen gas together with a platinum electrode.
The overall cell potential is the reduction potential of the substance being determined using the standard hydrogen electrode as a reference electrode since its electrode potential is set at zero volts.
The solubility of gold (V) oxalate, Au2(C2O4)5 is 2.58 g/L. Calculate Ksp from this information.
Answer:
[tex]Ksp=3.39x10^{-14}[/tex]
Explanation:
Hello,
In this case, since the dissociation of gold (V) oxalate is:
[tex]Au_2(C_2O_4)_5(s)\rightleftharpoons 2Au^{5+}(aq)+5(C_2O_4)^{2-}(aq)[/tex]
In such a way, the equilibrium expression is:
[tex]Ksp=[Au^{5+}]^2[(C_2O_4)^{2-}]^5[/tex]
Thus, since the molar solubility of the gold (V) oxalate is computed by considering its molar mass (834 g/mol):
[tex][Au_2(C_2O_4)_5]=2.58\frac{g}{L} *\frac{1mol}{834g} =3.09M[/tex]
In such a way, since gold (V) is in a 2:1 molar ratio with the salt and the oxalate in a 5:1 in the chemical reaction, the corresponding concentrations at equilibrium are:
[tex][Au^{5+}]=3.09x10^{-3}\frac{mol}{L} *\frac{2molAu^{5+}}{1mol} =6.19x10^{-3}M[/tex]
[tex][(C_2O_4)^{2-}]=3.09x10^{-3}\frac{mol}{L} *\frac{5mol(C_2O_4)^{2-}}{1mol} =0.0155M[/tex]
Therefore, the solubility product turns out:
[tex]Ksp=(6.19x10^{-3})^2*(0.0155)^5\\\\Ksp=3.39x10^{-14}[/tex]
Regards.
Which of the following pairs of aqueous solutions would not produce a reaction when mixed? Select one: a. NaNO3 and CuCl2 b. Ba(OH)2 and HNO3 c. CaCl2 and Na3PO4 d. AgNO3 and HCl
Answer:
a. NaNO3 and CuCl2
Explanation:
The other 3 react as follows:
Ba(OH)2 and HNO3 ---> BaNO3 + H2O
CaCl2 + Na3PO4 ---> CaPO4 + NaCl
AgNO3 + HCl ---> AgCl + HNO3
The methane (CH4) molecule is tetrahedral, with each of the hydrogen atoms connected by a single bond to the central C atom. What type of orbital hybridization exists around the C atom
Answer:
The type of orbital hybridization around the C atom is sp3 hybridization.
Explanation:
The electron configuration of carbon is 1s² 2s² 2p². According to this configuration, carbon only has two semi-occupied orbitals that can form a covalent bond.
But a process called hybridization occurs, where the "s" and "p" orbitals at the (2s² 2p²) level combine and generate new orbitals. So this hybridization process where one "s" orbital is combined with three "p" orbitals forms four new sp³ hybrid orbitals (remember that there is 1 s orbital and 3 p orbitals for each layer or energy level). These four hybrid orbitals are half full, having only one electron and being capable of forming four covalent bonds.
So, the type of orbital hybridization around the C atom is sp³ hybridization.