The types of stakeholders are internal, external, Primary and secondary
Stakeholders are a group that expresses interest in the firm and whose activities, whether professional or personal, have an impact on its operations. The four types of stakeholders can be noted as -
Internal stakeholders: These are the people or organisations within a company, such as the staff, management, or shareholders.External stakeholders: These are people or members that are not a part of the organisation, such as clients, vendors, or the neighborhood.Primary stakeholders: Customers, employees, and shareholders are examples of this type since they have a direct and substantial interest in the firm and its operations.Secondary stakeholders: It includes groups like the media, governmental organisations, and advocacy organisations that may have a tangential or potential interest in the organisation and its actions.Read more about stakeholders on:
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If f(x) and ¹(x) are inverse functions of each other and f(x) = 2x+5, what is f¹ (8)?
-1
T MIN 700
3
8
23
Answer: 3/2
Step-by-step explanation:
[tex]f^{-1}(8)=k \implies f(k)=8\\\\\therefore 2k+5=8\\\\2k=3\\\\k=\frac{3}{2}[/tex]
From the top of a 16 m tall building, the angle of depression to a car on the road is 35°. To the nearest metre, how far is the car from the base of the building?
The distance of the car to the base of the building is 23 metres.
How to find the distance of the car from the building using angle of depression?The situation will form a right angle triangle.
Therefore, the distance of the car to the base of the building is the adjacent side of the right angle triangle formed.
Therefore,
tan 35 = opposite / adjacent
tan 35 = 16 / x
x tan 35 = 16
x = 16 / tan 35
Therefore,
x = 16 / 0.70020753821
x = 22.8506141103
x = 23 meters
Therefore, the distance of the car to the base of the building is 23 metres.
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Help please you don’t know how much this means to me
[tex]a(0) = 1 \: \: \: \: \: \: b(0) = 2 \: \: \: \: \: c(0) = 3 \\ a(1) = b(0) + c(0) = 2 + 3 = 5 \\ b(1) = a(0) + c(0) = 1 + 3 = 4 \\ c(1) = a(0) + b(0) = 1 + 2 = 3 \\ \\ a(2) = b(1) + c(1) = 4 + 3 = 7 \\ b(2) = a(1) + c(1) = 5 + 3 = 8 \\ c(2) = a(1) + b(1) = 5 + 4 = 9[/tex]
[tex]a(3) = b(2) + c(2) = 8 + 9 = 17\\ b(3) = a(2) + c(2) =7 + 9 = 16 \\ c(3) = a(2) + b(2) = 7 + 8 = 15 \\ \\ a(4) = b(3) + c(3) = 16 + 15 = 31 \\ b(4) = a(3) + c(3) = 17 + 15 = 32 \\ c(4) = a(3) + b(3) = 17 + 16 = 33[/tex]
[tex]a(5) = 32 + 33 = 65 \\ b(5) = 31 + 33 = 64 \\ c(5) =31 + 32 = 63 \\ \\ a(6) = 64 + 63 = 127 \\ b(6) = 65 + 63 = 128 \\ c(6) = 65 + 64 = 129 \\ [/tex]
[tex]a(7) = 128 + 129 = 257 \\ b(7) = 127 + 129 = 256 \\c (7) = 127 + 128 = 255 \\ \\ a(8) = 256 + 255 = 511 \\ b(8) = 257 + 255 = 512 \\ c(8) = 257 + 256 = 513[/tex]
[tex]a(9) = 512 + 513 = 1025 \\ b(9) = 511 + 513 = 1024 \\ c(9) = 511 + 512 = 1023 \\ \\ a(10) = 1024 + 1023 = 2047 \\ b(10) = 1025 + 1023 = 2048 \\ c(10) = 1025 + 1024 = 2049[/tex]
b)[tex]a(n) + b(n) + c(n) = \\ 2(a(n - 1) + b(n - 1) + c(n - 1)) \\ 6 \times 2 {}^{n } [/tex]
c)[tex]6 \times 2 {}^{n} > 100 \: 000 \\ 2 {}^{n} > \frac{100 \: 000}{6} \\ n > log {}^{2} ( \frac{100 \: 000}{6} ) \\ n > 14.02468 \\ n = 15[/tex]
PLS HELP FAST
Kryton -85 is a radioisotope of krypton that has a half-life of about 10.75years. This isotope is produced by the nuclear fission of uranium and plutonium in nuclear weapons and in nuclear reactors, as well as cosmic rays. An important goal of the Limited Nuclear Test Ban Treaty of 1963 was to eliminate the release of such radioisotopes into the atmosphere. At present, the activity of Krypton -85 in the atmosphere is about 135 mCi.
How much Krypton -85 will be present in the atmosphere after 12,532days?
Using an exponential function, it is found that 14.75 mCi of Krypton -85 will be present in the atmosphere after 12,532 days.
What is an exponential function?A decaying exponential function is modeled by:
[tex]A(t) = A(0)(0.5)^\frac{t}{h}[/tex]
In which:
A(0) is the initial value.h is the half life, in years.t is the time, in years.In this problem, the parameters are:
A(0) = 135, h = 10.75, t = 12532/365 = 34.334.
Hence the amount is:
[tex]A(t) = A(0)(0.5)^\frac{t}{h}[/tex]
[tex]A(t) = 135(0.5)^\frac{34.334}{10.75}[/tex]
A(t) = 14.75.
14.75 mCi of Krypton -85 will be present in the atmosphere after 12,532 days.
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3) angle of an isosceles triangle is 70°, find the value of If one remaining angles. a) 40°, 40° b) 45°, 45° c) 40°70° d)50⁰, 50⁰
The remaining two angles of the given isosceles triangle is Option(C) 40°,70° .
What are the remaining two angles in the isosceles triangle ?For an isosceles triangle, the two sides of the triangle are congruent and equal in length . Also the angles subtending the adjacent equal sides of the isosceles triangle are of same measure.
We also know that the sum of the three interior angles of any triangle is always equal to 180° .
In the options given, in Option(C) the angles measure 40° and 70° .
Thus as one angle of the isosceles triangle is given to be 70°, the other angle of its adjacent side is also 70° .
The sum of the interior angles of the triangle is equal to -
70° + 40° + 70° = 180° which satisfies the property.
Therefore, the remaining two angles of the given isosceles triangle is Option(C) 40°,70° .
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Quick algebra 1 question for 15 points!
Only answer if you know the answer, quick shout-out to Yeony2202, tysm for the help!
The cost per person if number of students is 100 given the inverse variation is $46.75
Inverse variationCost per person = CNumber of students = nC = k / n
where,
k = constant of proportionalityIf n = 55 and C = $85
C = k / n
85 = k / 55
85 × 55 = k
4,675 = k
Find C if n = 100
C = k / n
= 4,675 / 100
C = $46.75
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Half of a set of the parts are manufactured by machine A and half by machine B. Eight percent of all the parts are defective. Two percent of the parts manufactured on machine A are defective. Find the probability that a part was manufactured on machine A, given that the part is defective. (Round your answer to 4 decimal places.)
The probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.
What is probability?Probability is the branch of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely it is that a claim is true. The probability of an event is a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty.To find the probability that a part was manufactured on machine A, given that the part is defective:
The probability that a part was manufactured on machine A given that part is defective:
P ( A | D )
P ( A | D ) = [P (A) * P ( D | A )]/ P ( D )
Where: P (A) is the probability that the part is manufactured in machine A which is 0.2 (half of the parts are manufactured in machine A)
P (D/A) is the probability of a defective part given that the part was manufactured in machine A which is 2% or 0.02
And finally, the probability of defective part in the production is 8% or 0.08 hence :
P ( A | D ) = [ ( 0.2 ) * 0.02 ] / 0.08
P ( A | D ) = 0.024
Therefore, the probability that a part was manufactured on machine A, given that the part is defective is P ( A | D ) = 0.024.
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When you roll two number cubes, what are the odds in simplest form against getting two numbers greater than 4?
A. 4:1
B. 1:4
C. 1:8
D. 8:1
The odds in simplest form against getting two numbers greater than 4 is 1 : 4.
What are the odds?Probability determines the odds that a random event would happen. The odds the event occurs is 1 and the probability that the event does not occur is 0.
The odds of getting two numbers greater than 4 = 2 x (numbers greater than 3 in a cube / total number of sides in a cube)
2(3/6)
2 x 1/2 = 1 : 4
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Can someone please help me with this? I'll give brainliest :)
Based on the information given find the slope from [2,5] Is interval notation and means from x=2 to x=5.
16. y = 3x - 4
17. y = 2x^2-4x - 2
The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
How to determine the slope?The interval is given as:
x = 2 to x = 5
The slope is calculated as:
[tex]m = \frac{y_2 -y_1}{x_2-x_1}[/tex]
16. y = 3x - 4
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
[tex]m = \frac{11 - 2}{5 - 2}[/tex]
[tex]m = \frac{9}{3}[/tex]
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
17. y = 2x^2-4x - 2
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
[tex]m = \frac{28 + 2}{5 - 2}[/tex]
[tex]m = \frac{30}{3}[/tex]
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
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Can u guys pls help me with this homework
The value of √(7 * 23 - 1)/8 is 4.47, the values of a, b and c are -14/11, -10/11 and 3, respectively and the area of the shape is 5√5 + 5 square meters
How to evaluate the radical expression?The question goes thus:
If √5 = 2.236, evaluate √(7 * 23 - 1)/8
We have:
√(7 * 23 - 1)/8
Evaluate the product of 7 and 23
√(7 * 23 - 1)/8 = √(161 - 1)/8
Evaluate the difference of 161 and 1
√(7 * 23 - 1)/8 = √160/8
Evaluate the quotient of 160 and 8
√(7 * 23 - 1)/8 = √20
Express 20 as the product 4 and 5
√(7 * 23 - 1)/8 = √(4 * 5)
Expand the product
√(7 * 23 - 1)/8 = √4 * √5
Express √4 as 2
√(7 * 23 - 1)/8 = 2 * √5
Substitute √5 = 2.236
√(7 * 23 - 1)/8 = 2 * 2.236
Evaluate the product
√(7 * 23 - 1)/8 = 4.472
Approximate
√(7 * 23 - 1)/8 = 4.47
Hence, the value of √(7 * 23 - 1)/8 is 4.47
How to simplify the radical expression?The expression is given as:
(3√2 + 5√6)/(3√2 - 5√6)
Rationalize the above expression
(3√2 + 5√6)/(3√2 - 5√6) * (3√2 + 5√6)/(3√2 + 5√6)
Evaluate the product
(3√2 + 5√6)²/((3√2)² - (5√6)²)
Simplify the denominator
(3√2 + 5√6)²/(18 - 150)
This gives
[(3√2)² + (5√6)² + 2 *(3√2) * (5√6)]/(-132)
Simplify the numerator
[168 + 120√3]/(-132)
Simplify the fraction
-14/11 - 10√3/11
Hence, the values of a, b and c are -14/11, -10/11 and 3, respectively
How to determine the area?The area is calculated as:
A = 1/2 * (Sum of parallel bases) * Height
So, we have:
A = 1/2 * (4 + 3√5 + 6 - √5) * √5
Evaluate the like terms
A = 1/2 * (10 + 2√5) * √5
Evaluate the product
A = (5 + √5) * √5
Evaluate the product
A = 5√5 + 5
Hence, the area of the shape is 5√5 + 5 square meters
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How many solutions does this nonlinear system of equations have? NEED HELP ASAP!
Answer:
Step-by-step explanation:
two
PLEASE HELP QUICKLY️️️
Answer:
first option x = 7
Step-by-step explanation:
"x" is the cathetus opposite the angle of 30°
14 is the hypotenuse
use the sine function
[tex]sin30^{0} =\frac{x}{14}[/tex]
[tex]x=14sen30^{0} =14(0.5)=7[/tex]
Hope this helps
Which is a function?
look at pic
Answer:
option 2 {(12, 3), (11,2), ...}
Step-by-step explanation:
For functions, multiple x-values can have the same y-value but each y-value must have a unique x-value. The second option matches this criterion.
Which point is the solution to the inequality shown in this graph?? Help pls
a.(0,5)
b.(-3,-1)
c.(0,0)
d.(3,3).
Answer:
only (0,5)
Step-by-step explanation:
(0,5) is in the shaded region on the graph, so it is a solution.
One other point is in the unshaded region so it is NOT a solution. The other two points are on the dashed line, so they are NOT solutions. If the line was solid (not dashed) they would work, but since the line is dashed they are NOT solutions.
Answer:
A. (0,5)
Step-by-step explanation:
Write the equation of the sinusoidal function shown.
A) y = cos x - 1
B)y=sin x - 1
C) y=2 sin x - 1
D) y = 2 cos x - 1
Answer:
A. y= cos x - 1
Step-by-step explanation:
short answer: this is basically the parent graph cos(x), just vertically shifted down 1 unit.
longer answer:
standard form is y = a cos(bx-c) +d
a = amplitude
b = 2pi/period
c = horizontal shift
d = vertical shift (also equal to midline)
for this graph
a=1
period is 2pi, so b=1
there is no horizontal shift so c=0
d= -1 because it is shifted down one unit from axis (midline is at -1)
The temperature was -20.5°F at 5 A.M. and rose 5 degrees per hour for the next 5 hours. Melissa says the temperature at 10 A.M. was -5.5°F. Which statement identifies Melissa’s error and the correct answer?A.Melissa multiplied incorrectly. The correct answer is -0.5°F.B.Melissa multiplied incorrectly. The correct answer is 9.5°F.C.Melissa added incorrectly. The correct answer is 4.5°F.D.Melissa added incorrectly. The correct answer is 5.5°F.
The statement which identifies Melissa’s error and the correct answer is; Melissa added incorrectly. The correct answer is 4.5°F
TemperatureInitial temperature = -20.5°FChange in temperature per hour = 5°FNumber of hours = 5New temperature = Initial temperature + (Change in temperature per × Number of hours)
= -20.5°F + (5°F × 5)
= -20.5°F + (25°F)
= 4.5°F
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Answer:
C
Step-by-step explanation:
35 POINTS please help asap
Type the correct answer in each box. Use numerals instead of words.
This graph represents a quadratic function. What is the function’s equation written in factored form and in vertex form?
f(x) = _x(x - _)
f(x) = _(x − _)^2 + _
i know for sure the first four blanks are 2, 4, 2, and 2 but the last is NOT 8.
The quadratic equation given in the graph can be represented in these two following ways:
Factored: f(x) = 2x(x - 4).Vertex form: y = 2(x - 2)² - 8.What is the Factor Theorem?The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:
[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]
In which a is the leading coefficient.
In this graph, the roots are [tex]x_1 = 0, x_2 = 4[/tex], hence the factored form of the polynomial is:
f(x) = ax(x - 4).
When x = 5, y = 10, hence the leading coefficient is found as follows:
10 = 5a(5 - 4)
5a = 10
a = 2.
Hence the factored form of the polynomial is:
f(x) = 2x(x - 4).
What is the equation of a parabola given it’s vertex?The equation of a quadratic function, of vertex (h,k), is given by:
y = a(x - h)² + k
In which a is the leading coefficient.
In this problem, the vertex is at point (2,-8), hence h = 2, k = -8 and:
y = a(x - 2)² - 8
When x = 5, y = 10, hence the leading coefficient is found as follows:
10 = a(5 - 2)² - 8
9a = 18
a = 2.
Hence the equation in vertex-form is:
y = 2(x - 2)² - 8
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Which systems of equations have no real number solutions? Check all that apply.
Oy=x² + 4x + 7 and y = 2
□ y=x²-2 and y=x+5
-Oy=-x²-3 and y = 9 + 2x
y=-3x-6 and y = 2x² - 7x
y=x² and y = 10 - 8x
Answer + Step-by-step explanation:
Recall That the number of solution
of a quadratic equation ax² + bx + c = 0
depends on the discriminant b² - 4ac :
if b² - 4ac > 0 , the equation has two distinct solutions.
if b² - 4ac = 0 , the equation has only one solution.
if b² - 4ac < 0 , the equation has no solutions.
=======================================
System 1 :
y = x² + 4x + 7 and y = 2
⇔ x² + 4x + 7 = 2
⇔ x² + 4x + 5 = 0
→ b² - 4ac = 4² - 4×1×5 = 16 - 20 = -4 < 0
Then the quadratic equation has no solutions
Therefore the system has no solutions.
System 2 :
y = x² - 2 and y = x + 5
⇔ x² - 2 = x + 5
⇔ x² - x - 7 = 0
→ b² - 4ac = (-1)² + 4×7 = 29 > 0
Then the quadratic equation has two solutions
Therefore the system has two solutions.
System 3 :
y = -x² - 3 and y = 9 + 2x
⇔ -x² - 3 = 9 + 2x
⇔ -x² - 2x - 12 = 0
→ b² - 4ac = (-2)² - 4×(-1)×(-12) = 4 - 48 = -44 < 0
Then the quadratic equation has no solutions
Therefore the system has two solutions.
System 4 :
y = -3x - 6 and y = 2x² - 7x
⇔ -3x - 6 = 2x² - 7x
⇔ 2x² - 4x + 6 = 0
→ b² - 4ac = (-4)² - 4×(2)×(6) = 16 - 48 = -32 < 0
Then the quadratic equation has no solutions
Therefore the system has two solutions.
System 5 :
y = x² and y = 10 - 8x
⇔ x² = 10 - 8x
⇔ x² + 8x - 10 = 0
→ b² - 4ac = 8² - 4×1×(-10) = 64 + 40 = 104 > 0
Then the quadratic equation has two solutions
Therefore the system has two solutions.
Find the area of the polygon with the coordinates (1, 2), (3, 2), (3, 0), and (1, 0)
The area of the polygon is 4 square units
How to determine the area of the polygon?The vertices are given as:
(1, 2), (3, 2), (3, 0), and (1, 0)
The area is then calculated as:
A = 0.5 * |x1y2 - x2y1 +x2y3 - x3y2 + ....... |
So, we have:
A = 0.5 * |1 * 2 - 3 * 2 + 3 * 0 - 2 * 3 + 3 * 0 - 0 * 1 + 1 * 2 - 0 * 1|
Evaluate
A = 0.5 * |-8|
Remove the absolute bracket
A = 0.5 * 8
This gives
A = 4
Hence, the area of the polygon is 4 square units
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In the 1980’s, a clinical trial was conducted to determine if taking an aspirin daily reduced the incidence of heart attacks. Of 22,071 medical doctors participating in the study, 11,037 were randomly assigned to take aspirin and 11,034 were randomly assigned to the placebo group. Doctors in this group were given a sugar pill disguised to look like aspirin. After six months, the proportion of heart attacks in the two groups was compared. Only 104 doctors who took aspirin had a heart attack, whereas 189 who received the placebo had a heart attack. Can we conclude from this study that taking aspirin reduced the chance of having a heart attack? the purpose of this study was to determine whether taking an aspirin daily reduces the proportion of heart attacks.
There is enough evidence to conclude that taking aspirin cannot reduces the chance of cancer.
Given sample size of patients take aspirin 11037, sample size of patients who have assigned placebo group be 11034. 104 doctors who take aspirin had a heart attack, 189 doctors had placebo had heart attacks.
First we have to form hypothesis.
[tex]H_{0} :p{1} -p_{2} =0[/tex]
[tex]H_{1}:p_{1} -p_{2} < 0[/tex]
We have to find the respective probabilities.
[tex]p_{1}[/tex]=104/11037
=0.0094
[tex]p_{2}[/tex]=189/11034
=0.0171
Now their respective margin of errors.
[tex]s_{1}[/tex]=[tex]\sqrt{ {(0.0094*0.9906)/11037}[/tex]
=0.0009
[tex]s_{2}[/tex]=[tex]\sqrt{0.0171*0.9829}[/tex]
=0.0011
Hence the distribution of the differences,they are given by:
p=[tex]p_{1} -p_{2}[/tex]
=0.0094-0.0171
=-0.0077
S=[tex]\sqrt{s_{1} ^{2}+s_{2} ^{2} }[/tex]
=[tex]\sqrt{(0.0009)^{2} +(0.0011)^{2} }[/tex]
=0.00305
z=(p -f)/S (In which f=0 is the value tested at the null hypothesis)
=(-0.0077-0)/0.00305
=-2.52
p value will be 0.005.
p value of 0.05 significance level.
z=1.96.
1.96>0.005
So we will reject the null hypothesis which means it cannot reduce the whole chance of becomming a heart attack.
Hence there is enough evidence to conclude that taking aspirin cannot reduces the chance of cancer.
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Find x such that the matrix is singular. A = 3 x −6 −4 x =
The matrix A becomes singular when x is equal to ±√8 (positive or negative square root of 8).
We have,
Matrix A becomes singular (i.e., its determinant is zero).
The given matrix A is:
A = | 3x -6 |
| -4 x |
Using the determinant formula for a 2x2 matrix, we have:
det(A) = (3x * x) - (-6 * -4)
Simplifying the expression:
det(A) = 3x^2 - 24
To find the value of x for which det(A) = 0, we set the determinant equal to zero:
3x^2 - 24 = 0
Now, we can solve this quadratic equation for x:
3x^2 = 24
x^2 = 8
x = ±√8
Therefore,
The matrix A becomes singular when x is equal to ±√8 (positive or negative square root of 8).
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Module 1: directions: respond to this question to demonstrate your understanding of the topic/content. be sure to provide adequate and relevant details learned in the module to support your response. pay close attention to organizing your response so it makes sense and uses correct grammar. your response should be at least 5-7 sentences at a minimum. question: given the two points (1,5) and (-2, -4), write a set of instructions for your younger cousin that determines the equation of the line in slope-intercept form (y=mx+b). be sure to write the equation.
The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.
Given two points of a line (1,5) and (-2,-4).
We have to form an equation in slop intercept form.
Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.
Point slope form of an equation is y=x+mc where m is slope of the line.
From two points the formula of equation is as under:
(y-[tex]y_{1}[/tex])=[tex](y_{2} -y_{1} )/(x_{2} -x_{1} )[/tex]*(x-[tex]x_{1}[/tex])
where [tex](x_{1} ,y_{1} ) and (x_{2} ,y_{2} )[/tex] are the points.
Putting the values of [tex]x_{1}[/tex]=1, [tex]x_{2}[/tex]=-2, [tex]y_{1}[/tex]=5 and [tex]y_{2}[/tex]=-4.
y-5=(-4-5/-2-1)*(x-1)
y-5=-9/-3*(x-1)
y-5=3(x-1)
y-5=3x-3
y=3x-3+5
y=3x+2
Hence the slope intercept form of the line having points (1,5)(-2,-4) is y=3x+2.
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PLEASE HELP ME AS SOON AS POSSIBLE
a) The linear function that models the population in t years after 2004 is: P(t) = -200t + 29600.
b) Using the function, the estimate for the population in 2020 is of 26,400.
What is a linear function?A linear function is modeled by:
y = mx + b
In which:
m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.The initial population in 2004, of 29600, is the y-intercept. In 12 years, the population decayed 2400, hence the slope is:
m = -2400/12 = -200.
Hence the equation is:
P(t) = -200t + 29600.
2020 is 16 years after 2004, hence the estimate is:
P(16) = -200(16) + 29600 = 26,400.
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Sa = 2(pi)(r)(h) + 2(pi)(r^2) v = (pi)(r^2)(h) find the surface area and the volume.
If Sa=2πrh+2π[tex]r^{2}[/tex]v=π[tex]r^{2}h[/tex] then the surface area is π[tex]r^{2} h[/tex] and volume is
(rh-2h)/2r.
Given Sa=2πrh+2π[tex]r^{2} v[/tex]=π[tex]r^{2}h[/tex].
We have to find surface area and volume from the given expression.
Volume is basically amount of substance a container can hold in its capacity.
First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.
2πrh+2π[tex]r^{2}[/tex]v=π[tex]r^{2}[/tex]h
Keeping the term containing v at left side and take all other to right side.
2π[tex]r^{2}[/tex]v=π[tex]r^{2}h[/tex]-2πrh
v=(π[tex]r^{2}[/tex]h-2πrh)/2π[tex]r^{2}[/tex]
v=π[tex]r^{2} h[/tex]/2π[tex]r^{2}[/tex]-2πrh/2π[tex]r^{2}[/tex]
v=h/2-h/r
v=h(r-2)/2r
Put the value of v in Sa=2πrh+2π[tex]r^{2} v[/tex]
Sa=2πrh+2π[tex]r^{2}[/tex]*h(r-2)/2r
=2πrh+2πrh(r-2)/2
=2πrh+πrh(r-2)
=2πrh+π[tex]r^{2}[/tex]h-2πrh
=π[tex]r^{2}[/tex]h
Hence surface area is π[tex]r^{2}[/tex]h and volume is h(r-2)/2.
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Using the quadratic formula, solve the
equation below to find the two possible
values of t.
6x^2-35=-11x
Give each value as a fraction in its
simplest form.
The two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2
What are the two possible solution to the equation?
Given the equation; 6x² - 35 = -11x
The quadratic formula is expressed as;
x = [ -b±√( b² - 4(ac) ]/2a
First, we re-arrange our equation in the form of ax² + bx + c = 0
6x² + 11x - 35 = 0
a = 6b = 11c = -35We substitute into the formula.
x = [ -b±√( b² - 4(ac) ]/2a
x = [ -11±√( 11² - 4( 6 × -35 ) ]/2×6
x = [ -11±√( 121 + 840 ]/12
x = [ -11±√961 ]/12
x = [ -11 ± 31 ]/12
x = (-11 + 31)/12, (-11 + 31 )/12
x = 20/12, -42/12
x = 5/3, -7/2
Therefore, the two possible solutions to the given equation ( 6x^2-35 = -11x ) are x = 5/3 and x = -7/2
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Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 8% each week. The following function represents the weekly weed growth: f(x) = 86(1.08)x. Rewrite the function to show how quickly the weeds grow each day.
f(x) = 86(1.08)7x; grows approximately at a rate of 5.6% daily
f(x) = 86(1.087)x; grows approximately at a rate of 0.56% daily
f(x) = 86(1.01)x; grows approximately at a rate of 0.1% daily
f(x) = 86(1.01)7x; grows approximately at a rate of 1% daily
The function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
How to rewrite the function?The function is given as:
f(x) = 86(1.08)^x
There are 7 days in a week.
This means that:
1 day = 1/7 week
So, x days is
x day = x/7 week
Substitute x/7 for x in
f(x) = 86(1.08)^(x/7)
Rewrite as:
f(x) = 86(1.08^1/7)^x
Evaluate
f(x) = 86(1.01)^x
In the above, we have:
r = 1.01 - 1
Evaluate
r = 0.01
Express as percentage
r = 1%
Hence, the function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily
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Answer: the answer is d
Step-by-step explanation:
What is the sum of the 12th square number and the 9th square number
Answer: 225
Step-by-step explanation:
What is a square number?
A square number is a product of a number times itself
So, the 12th square number would be 12 * 12, or 12²
The 9th square number would be 9 * 9, or 9²
The equation would be 12² + 9²
So:
12² + 9²
= 144 + 81
= 225
So, the answer is 225
Were the non-violent, civil disobedience tactics used by civil rights leaders like dr. king effective at creating change and ending injustice? why or why not
Yes, the non-violent, civil disobedience tactics used by civil right leaders were effective to a great extent at creating change and ending injustice.
How were the civil disobedience tactics effective?
Martin Luther King, Jr.'s and other civil right leaders' leadership and vision were shaped by their steadfast faith in the efficacy of nonviolence and civil disobedience. Although it permitted civil rights protesters to avoid harsher legal penalties, it also had a deeper significance. America only learned about the effectiveness of nonviolent protest as a result of the work of Martin Luther King, Jr. and his civil disobedience allies.
Civil Disobedience Tactics
The Civil Rights Act of 1964 and the Voting Rights Act of 1965 were primarily made possible thanks to King. The Civil Rights Act outlawed discrimination on the basis of "race, color, religion, or national origin" in the workplace and in public places. African Americans' right to vote is safeguarded by the Voting Rights Act.
Inspired by Gandhi, King and other non-violent leaders, utilized civil disobedience to pressure governments to change. It manifested as widespread, nonviolent defiance of official orders. Civil disobedience is the act of refusing to comply with governmental orders or demands and remaining unaffected by the arrest and punishment that may follow.
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In the diagram AB/BC = AD/DE
Substitute the known values into the proportion and solve for DE
Answer:
[tex]\huge\boxed{\sf DE = 9}[/tex]
Step-by-step explanation:
From the figure,
AB = 2
BC = 3
AD = 6
Substitute in the given formula
[tex]\displaystyle \frac{AB}{BC} =\frac{AD}{DE} \\\\\frac{2}{3} = \frac{6}{DE} \\\\Cross \ Multiply \\\\2 \times DE = 6 \times 3\\\\2DE = 18\\\\Divide \ 2 \ to \ both \ sides\\\\DE = 18/2\\\\DE = 9\\\\\rule[225]{225}{2}[/tex]
A firm offers routine physical examinations as part of a health service program for its employees. The exams showed that 16% of the employees needed corrective shoes, 23% needed major dental work, and 3% needed both corrective shoes and major dental work. What is the probability that an employee selected at random will need either corrective shoes or major dental work
Probability of people needing corrective shoes or dental work is 0.36.
What is probability?The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.
What are mutually exclusive events?A statistical term used to describe events that cannot occur concurrently is "mutually exclusive".
Here, the two events getting corrective shoes and getting dental work are not mutually exclusive events.
P(corrective shoes or dental work) = P(corrective shoes) + P(dental work) - P(corrective shoes and dental work)
P(corrective shoes or dental work) = 0.16 + 0.23 - 0.03
P(corrective shoes or dental work) = 0.36
Hence, the probability of people needing corrective shoes or dental work is 0.36.
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