what are subtomic particles

Answers

Answer 1

Answer:

In the physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles. Particle physics and nuclear physics study these particles and how they interact.

Explanation:

Answer 2

Answer:

In physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles.


Related Questions

All of the following choices are examples of commonly used assessment methods for body
composition EXCEPT

A. waist to hip ratio
B. bioelectrical impedance analysis
C. the spongy bob technique
D. skinfold measurements this is PE please help mee

Answers

Answer:

letter D

Explanation:

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I NEED HELP AS SOON AS POSSIBLE PLEASEEE!!
DO NOT ANSWER IF YOU DON'T KNOW IT PLEASE!



Use The Kinetic Theory To Explain:
•Boyle's Law
•Charles' Law
•Pressure Law​

Answers

Answer:

Kinetic theory is based on the kinetic energy of moving particles.  In Boyle's Law the temperature is helped constant, so the kinetic energy of the molecules is a constant. The pressure and the volume are inversely related in Boyle's Law. In Kinetic theory pressure is created by the collision of particles.

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Explanation:

A wire in a circuit carries a current of 0.9 A. Calculate the quantity of
charge that flows through the wire in 50 s. Choose the correct unit of
charge with your answer.
45 A
45C
45 J
O 0.018 A
O 0,018
0.018 J
O 55.6 A
55.6 C
55.6J

Answers

Answer:

We conclude that the quantity of  the charge that flows through the wire in 50 s will be 45 C.

Explanation:

Given

Current I = 0.9 ATime t = 50 s

To determine

We need to find the quantity of  the charge that flows through the wire in 50 s.

Important Tip:

A current of 1 Ampere = 1 Coulomb  of charge flowing in 1 second

Using the formula involving charge and current

[tex]I=\frac{Q}{t}[/tex]

where:

[tex]I[/tex] represents the current in amperes (A)[tex]Q[/tex] represents the charge in coulomb (C)[tex]t[/tex] represents the time in seconds (s)

now substituting I = 0.9 and t = 50 in the formula

[tex]I=\frac{Q}{t}[/tex]

[tex]0.9\:=\:\frac{Q}{50}[/tex]

switch sides

[tex]\frac{Q}{50}=0.9[/tex]

Multiply both sides by 50

[tex]\frac{50Q}{50}=0.9\cdot \:50[/tex]

Simplify

[tex]Q=45[/tex] C

Therefore, we conclude that the quantity of  the charge that flows through the wire in 50 s will be 45 C.

You can use _______________ to change a liquid into a gas.

Answers

Answer:

below

Explanation: When a liquid changes into a gas vaporization has occurred. The process can either occur due to boiling or evaporation. Boiling occurs when the vapor pressure of the liquid is raised (by heating) to the point where it is equal to the atmospheric pressure.

You can use thermal energy to change a liquid into a gas.

What is thermal energy?

By virtue of its temperature, a system in a condition of thermodynamic equilibrium has thermal energy, or internal energy. Unlike the energy of systems that are not in a state of thermodynamic equilibrium, thermal energy cannot be transformed into meaningful work as quickly.

For instance, the same fluid or solid in a thermodynamic equilibrium state with the same energy (as thermal energy) cannot do work unless it is combined with another substance at a different temperature, as in a heat engine. However, the same fluid or solid in a moving state with the same energy (as mechanical energy) can be converted to work in some mechanical device, such as a windmill or a waterwheel.

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What is the specific heat of water? A. 1.00 J/gºC
B. 4.18 J/gºC
C. 9.18 J/gºC
D. 8.36 J/gºC

Answers

Answer:

B 4.18J\g degree C is the specific heat of water

A box weighing 2.4 x 10^2 Newton's is lifted at a constant speed to a shelf 1.2 meters high in 4.0 seconds. What power is required to lift the box

Answers

Answer:

72Watts

Explanation:

Power = Force * distance/Time

Given the following

Force = 2.4 x 10^2 = 240N

distance = 1.2m

Time = 4.0secs

Substitute

Power = 240*1.2/4

Power = 60 * 1.2

Power = 72watts

Hence the power required to lift the box is 72Watts

Which wave property has the same value for all X-rays travelling in air?
A amplitude
B frequency
C speed
D wavelength
Which statement is correct?
A Gamma rays have a longer wavelength than ultra-violet waves.
B Infra-red waves have a lower frequency than radio waves
.C Microwaves have a longer wavelength than visible light.
D X-rays have a higher speed in air than visible light.

A star explodes in outer space. Which waves from the exploding star do not reach theEarth?
A infra-red
B light
C radio
D sound

Answers

Answer:

1. C speed

2. C Microwaves have a longer wavelength than visible light.

3. D sound

Explanation:

1. An X-ray is an electromagnetic wave. And these are waves that moves with the same speed in air. Thus all X-rays should travel with the same speed in air.

2. For electromagnetic waves, as the wavelength increases across the spectrum; the frequency of the wave decreases. Thus the correct statement is; microwaves have a longer wavelength than visible light.

3. Since electromagnetic waves moves with the same velocity (i.e the speed of light), then sound waves would not reach the earth. The correct option is D.

A 15kg object strikes the ground with 2000J of kinetic energy after freely falling from rest. How far above the ground was the object when it was released?

Answers

Answer:

Explanation:

Find the final velocity at which it struck the ground by using the kinetic energy formula.

[tex]KE=\frac{1}{2} mv^2[/tex]

[tex]2000=\frac{1}{2} (15)v^2\\v=16.33[/tex]

Now use kinematics to solve for the vertical displacement. We were given the initial velocity and acceleration can be assumed to be 9.8

[tex]V^2=V^2_i+2a(y_f-y_i)\\16.33^2=0^2+2(9.8)(y_f-y_i)[/tex]

Δy = 13.6 meters

A train travels 20,000km in 500h. What is the average speed of the train?

Answers

Answer:

40 mph

Explanation:

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Consider a point charge qqq in three-dimensional space. Symmetry requires the electric field to point directly away from the charge in all directions. To find E(r)E(r)E(r), the magnitude of the field at distance rrr from the charge, the logical Gaussian surface is a sphere centered at the charge. The electric field is normal to this surface, so the dot product of the electric field and an infinitesimal surface element involves cos(0)=1cos⁡(0)=1. The flux integral is therefore reduced to ∫E(r)dA=E(r)A(r)∫E(r)dA=E(r)A(r), where E(r)E(r)E(r) is the magnitude of the electric field on the Gaussian surface, and A(r)A(r)A(r) is the area of the surface.

Answers

Answer:

 E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]

Explanation:

For this exercise let's use Gauss's law. The Gaussian surface that follows the symmetry of the charges is a sphere

           Ф = ∫ E. dA = [tex]\frac{x_{int} }{\epsilon_o}[/tex]

the bold are vectors, the radii of the sphere and the electric field are parallel therefore the scalar product reduces to the algebraic product

           Ф = ∫ E dA = \frac{x_{int} }{\epsilon_o}

           E ∫ dA = \frac{x_{int} }{\epsilon_o}

           E A = \frac{x_{int} }{\epsilon_o}

the area of ​​a sphere is

            A = 4π r²

the charge inside the sphere is q = + q

           

we substitute

           E 4π r² = \frac{x }{\epsilon_o}

           E = [tex]\frac{1}{4\pi \epsilon_o } \ r^2[/tex]

During a contest that involved throwing a 7.0-kg bowling ball straight up in the air, one contestant exerted a force of 810 N on the ball. If the force was exerted through a distance of 2.0 m, how high did the ball go from the point of release?

Answers

Answer:

23.6 m

Explanation:

We are given that

Mass of ball, m=7.0 kg

Force, F=810 N

Distance, s=2.0 m

We have to find the height of ball from the point where it releases.

Work done=K.E

[tex]Fs=\frac{1}{2}mv^2[/tex]

[tex]v^2=\frac{2Fs}{m}[/tex]

Substitute the value

[tex]v^2=\frac{2\times 810\times 2}{7}[/tex]

[tex]v^2=\frac{3240}{7}[/tex]

K.E=P.E

[tex]\frac{1}{2}mv^2=mgh[/tex]

[tex]\frac{1}{2}v^2=gh[/tex]

Where g=[tex]9.8m/s^2[/tex]

[tex]\frac{1}{2}\times \frac{3240}{7}=9.8h[/tex]

[tex]h=\frac{3240}{7\times 2\times 9.8}[/tex]

[tex]h=23.6 m[/tex]

Calculate acceleration if net force acting on an object is 140N and mass
is 15 kg

Answers

Answer:

9.33333333 m / s2

Explanation:

140 N divided by 15 kg

can someone do this assignment for me about
force

Answers

Answer:

Newtons 3sd law

Force = mass × acceleration

3rd photo about momentum

If the small piston has an area of .004 square
meters and Bob pushes down on it with 225 N of
force, how much weight can he lift on the car
side of the system, if that piston's area is 3.5
square meters?

Answers

F₂ = 1.723 x 10⁸ N

Further explanation

Given

Area of small piston : 0.004 m²

Area of large piston : 3.5 m²

Force 225 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

225/0.004 m² = F₂/3.5² m²

F₂ = 1.723 x 10⁸ N

Why is thunder heard later after than the flash of light?​

Answers

Answer:

During a thunderstorm, lightning is seen first and thunder is heard later on because light travels faster than sound. If you see a lightning flash but cannot hear any thunder, the thunderstorm is most likely be quite far away from you.

Which two statements are true about the wave shown?​

Answers

Answer: The correct answers are C. and D.

Explanation:

One Newton is equivalent to
A. 1 kg/s2
B. 1 kg*m/s
C. 1 kg*m/s2
D. 1 kg/s

Answers

Answer:

C

Explanation:

A newton is defined as 1 kg⋅m/s2.

One newton is therefore the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in the direction of the applied force.

need some more help please

Answers

Answer:

Longitudinal wave

Explanation:

Mechanical longitudinal waves are also called compressional or compression waves, because they produce compression and rarefaction when traveling through a medium, and pressure waves, because they produce increases and decreases in pressure.

Consider the common measurement speed = 55 mph. What is the magnitude quantity?
Speed, mph, miles per hour, 55

Answers

Answer:

Magnitude = 55

Quantity = Speed

Explanation:

We are told that the speed is 55 mph. This implies that the magnitude is 55 while the unit is mph.

Also, physical quantities are usually things that can be measured such as distance, voltage, temperature e.t.c

Answer:

i think its speed

Explanation:

which
In describing the motion of an object it is often helpful to identify a
allows you to describe its motion relative to that of another object.
O acceleration
O average velocity
O frame of reference
O speed

Answers

Frame of reference

I think so

which of the following is an electromagnetic wave
A. Earthquake
B. light
C. Ocean
D. Sound

Answers

Answer:

The answer is D. Sound

Explanation:

Sound has an electromagnetic wave

I'm which direction does earth rotate

Answers

Answer:

Earth rotates eastward, in prograde motion.

Answer:

Earth rotates eastward, in prograde motion. As viewed from the North Pole, Earth turns counterclockwise.

Explanation:

Julieta kicks a 0.2 kg soccer ball already rolling in the same direction at 2.5 m/s. The ball leaves her foot at a speed of 20 m/s after the kick

Answers

Answer:

3.5kgm/s

Explanation:

We can calculate the momentum of Julieta

momentum = m(v-u)

Momentum = 0.2(20-2.5)

Momentum = 0.2(17.5)

Momentum = 3.5

Hence the momentum of Julieta is 3.5kgm/s

Write two daily life examples for each of the following:
- Specular Reflection - Diffuse Reflection

Answers

Answer:

Hey there here is your ans

Explanation:

Specular Reflection- bathroom mirror , glare on a pair of eyeglasses

Diffuse Reflection- reflection are the reading of a notebook

Tq

Specular reflection: glare on a pair of eyeglasses, bathroom mirror.

Diffuse reflection involves reading a notepad.

What is reflection?

The direction in which a wavefront travels at an interface between two distinct media changes during the process of reflection. This allows the wavefront to go back into the medium in which it was first generated. Light, music, and water waves are all examples of common phenomena that may be reflected.

The following is a list of the three most common forms of reflection:

Regular Reflection.Reflection that is DiffusedMultiple Reflection

Glare on a pair of eyeglasses or the mirror in the bathroom is an example of specular reflection. Reading from a notebook is an example of diffuse reflection.

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A 59.31 kg rock is sitting at the top of a cliff that is 300 m tall. What is the gravitational potential energy of that rock?

Answers

Answer:

The gravitational potential energy of that rock is 174371.4 J.

Explanation:

Given

Mass m = 59.31 kgHeight h = 300 m

To determine

We need to find the gravitational potential energy of the rock

We know that the potential energy of a body is termed as the stored energy due to its position.

One kind of energy comes from Earth's gravity — Gravitational potential energy (GPE).

Gravitational potential energy (GPE) can be determined using the formula

[tex]GPE = mgh[/tex]

where

[tex]m[/tex] is the mass[tex]g[/tex] is the gravitational acceleration which is equal to g = 9.8 m/s²[tex]h[/tex] is the heightGPE is the Gravitational potential energy

now substituting m = 59.31, h = 300 and g = 9.8

[tex]GPE = mgh[/tex]

         [tex]=59.31\times 9.8\times 300[/tex]

         [tex]=174371.4[/tex] J

Therefore, the gravitational potential energy of that rock is 174371.4 J.

Imagine you are standing on a bathroom scale inside an elevator. What would happen to your weight reading when the elevator accelerated upward.

Answers

Answer:

it would decrease i think

Explanation:

Answer:

HMMMMMM??????

Explanation:

PLS ANSWER FAST WILL GIVE BRANLEST!!!


Answer using mass m= F divided by a

And also use kilograms {kg}


A cannonball accelerates at 1000 m / s2 from an applied force of 5000 N. What is the mass of the cannonball?

Answers

Answer:

mass=force/acceleratio

m=5000/1000

m=5kg

[tex]\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}[/tex]

Given:-

acceleration = 1000 m/s²force = 5000 N

To find:-

Mass of the cannonball

Formula to be used:-

[tex]\longrightarrow[/tex] [tex]\underline{\boxed{\sf mass = \dfrac{force}{acceleration}}}[/tex]

Solution:-

:[tex]\implies[/tex] [tex]\sf mass = \dfrac{5000}{1000}[/tex]

:[tex]\implies[/tex] [tex]\sf mass = 5 kg [/tex]

hence, the required answer is 5kg.

______________________________

Can someone explain with the Answers pls?

Answers

Answer:

a) The frequency of the third harmonic is 786 Hz

b) The frequency of the first harmonic is 340 Hz

c) The frequency of the fifth harmonic is 1640 Hz

Explanation:

The rule is as follows:

If the first harmonic frequency (also called the fundamental frequency) is F, then:

The frequency of the second harmonic (also called the second overtone) is:

2*F

The frequency of the third harmonic (also called the third overtone) is:

3*F

And so on.

With this information, we can answer the questions:

a) We want to find the frequency of the third harmonic, such that the frequency of the first harmonic is 262 Hz.

Then we have F = 262Hz

And the frequency of the third harmonic will be:

3*F = 3*262Hz = 786 Hz

b) First harmonic for a string whose fifth harmonic frequency is 1700Hz.

Let's define F as the first frequency (the one we want to find)

Then the fifth harmonic frequency can be written as:

5*F = 1700Hz

With this equation we can find the value of F:

F = 1700Hz/5 = 340Hz

c) We want to find the fifth harmonic for a string whose third overtone (this is the same as the third harmonic) frequency is 984 Hz.

Then if the frequency of the first harmonic is F, we know that:

3*F = 984 Hz

With this we can find the value of F:

F = 984 Hz/3 =328 Hz

Now that we know the frequency of the first harmonic, we can find the frequency of the fifth harmonic:

5*F = 5*328 Hz = 1640 Hz

A spring has a spring constant k = 20N/cm. What load is needed to produce an extension of 2.5cm?



ASAP please !

Answers

Answer:

50 N

Explanation:

We are given;

Spring constant; K = 20N/cm

Extension; Δx = 2.5 cm

We want to find the load which is the force. This is gotten from the equation;

F = k•Δx

F = 20 × 2.5

F = 50 N

Therefore the load needed is 50 N.

En pocas palabras la utilidad que le darias al hecho de conocer los principios y leyes que rigen el movimiento de los cuerpos

Answers

Answer:

we can predict where they are in the future, know where they were in the past

can also build a device that generates a specific type of desired movement,

Explanation:

With the knowledge of the laws that govern the movement of bodies, we can predict where they are in the future and therefore know if there may be an accident, crash.

We can also know where they were in the past and therefore know if a fact is the result of these movements, craters, collapse of buildings, etc.

We can also build a device that generates a specific type of desired movement, for example pulleys that help us with work, etc.

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