Volt Electronics sells a Y-Box game console for $207. The store markup on thr Y-Box is 38%. What was the wholesale price that the store paid for it?​

Answer: Parallel

Step-by-step explanation:

Answer:

r≈12mi

Step-by-step explanation:

mark brainiest and Im 100% correct

Answer:

[tex]surface \: area \: ofa \: cube \: \\ area = \: 6 {a}^{2} \\ 6( {3}^{2} ) \\ 6(9) = 54[/tex]

An asymptote is a straight line that approaches a curve indefinitely but does not intersect at any point. There are asymptotes at t [tex]\dfrac{3}{2}\rm\ and\ \dfrac{-1}{3}[/tex].

An asymptote is a straight line that approaches a curve indefinitely but does not intersect at any point. In other words, when a curve approaches infinity, it approaches an asymptote line.

The function that is given to us is:

[tex]f(x)=\dfrac{x+1}{6x^2-7x-3}[/tex]

As in the function, there is a fraction therefore, the denominator should not be zero in order for the function to be defined. Therefore, there are asymptotes at

[tex]6x^2-7x-3 = 0\\[/tex]

Substituting the value in the formula of the quadratic equation we will get,

[tex]D=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\D = \dfrac{-(-7)\pm\sqrt{(-7)^2-4(6)(-3)}}{2(6)}\\\\D =\dfrac{-(-7)\pm\sqrt{11}}{12} = \dfrac{3}{2}, \dfrac{-1}{3}[/tex]

Thus, there are asymptotes at  [tex]\dfrac{3}{2}\rm\ and\ \dfrac{-1}{3}[/tex].

Learn more about Asymptotes:

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Answer:

Step-by-step explanation:

A "shaded area" problem can be worked by directly computing the area of the shaded shape, or by decomposing the figure in a convenient way. Here the overall square can be decomposed into unshaded triangles and a shaded square. The triangles have dimensions given, but the smaller square does not. Work must necessarily proceed from given dimensions to arrive at the values associated with dimensions not given.

For a problem like this, working the last question first can make it easier.

The total area is the area of a square 6+3 = 9 units on a side. Its area is ...

  Total area = s² = (9 units)² = 81 units²

__

The area of each of the four non-shaded triangles is ...

  A = 1/2bh = 1/2(6 units)(3 units) = 9 units²

There are 4 triangles with that area that are not shaded, so ...

  Non-shaded region = 4 × (9 units²) = 36 units²

__

The shaded region is that portion of the total area that is not Non-shaded. Its area will be the difference ...

  Shaded area = Total area - Non-shaded area

  Shaded area = 81 units² -36 units² = 45 units²

Answer:

C

Step-by-step explanation:

Volume = bhd

Volume = (x + 3)(x + 8)(x²)

start with (x + 3) and (x + 8), factor:

x² + 8x + 3x + 24

x² + 11x + 24

now bring x² back:

(x² + 11x + 24)(x²)

x⁴ + 11x³ + 24x²

Answer:

Maurico started with more :)

Step-by-step explanation:

Mariah started with 150 while Maurico started with around 190 so he has more to start with :)

Have a great day!

Please rate and mark brainliest!

Answer:

Mauricio

Step-by-step explanation:

To find who started with more money in their savings account, we want to observe the savings in $ when time=0 years

So by looking at the table of Mariah's savings, we see that when t=0 she had S=150$

By looking at the graph which describes Muaricio's savings as a function of time, we can see that when time=0 or x=0, y=S=190$

In other words, the y-intercept is the initial amount of savings.

190>150

:P

Hope this helps, it would be appreciated if you made me brainliest.

Answer:

J

Step-by-step explanation:

Start by labelling the sides of the triangle. The length of the ramp is the hypotenuse side, while the height of the ramp is the opposite side.

[tex]\textcolor{steelblue}{ \sinθ = \frac{opp}{hyp} }[/tex]

Let the length of the ramp be x.

[tex] \sin5° = \frac{3}{x} [/tex]

Multiply x on both sides:

x(sin5°)= 3

[tex]x = \frac{3}{ \sin5°} [/tex]

x= 34.4 (3 s.f.)

Thus, the length of the ramp is 34 ft. (nearest foot)

Answer:

C

Step-by-step explanation:

4

_

2 can be multiple by 3 and that will be same as 12

_

6

Answer:

ezz multiply and see what it s if its wrong then txt me

Step-by-step explanation:

Given A room is half as long again as it is broad

Let the breadth of the room x m

length of the room x + x/2 = 3x/2m

Area of the room , x × 3x/2 = 3x²/2m

Given , cost of carpeting the room at Rs. 3.25m⁻²

So , total cost , 3x²/2 × 3.25

But , Total cost of carpeting is given as 175.50 so ,

let the height of the room H m

Area of the four wall = 2(L+ b)× h 2(6+9)× H

= 30H m²

Area of the of the one door and two window is 8m²

8m² Area to be prepared = Area of four wall - area of two window and 1 door = (30H - 8) m²

Given cost of preparing wall is Rs. 1.40m²

total cost of preparing wall is (30H - 8) × 1.40

Total cost of preparing wall is given as 240.80

comparing , (30H - 8 ) × 1.40 = 240.80

Hence, Dimensions of the room are lengths 9m , breadth 6m and height 6m

Answer:

Myra swims for 3 miles.

Step-by-step explanation:

3/5 = 6/10

2 4/10 + 6/10 = 3

Answer:

diameter is twice the radius ( when given)

Answer:

6/19

Step-by-step explanation:

2+4+7+6=19

dose not have an a=6

6/19

Percentage discount

[tex]\\ \rm\rightarrowtail \dfrac{2}{86.25}{100}[/tex]

[tex]\\ \rm\rightarrowtail 0.0232(100)[/tex]

[tex]\\ \rm\rightarrowtail 2.32\%[/tex]

Answer:

2.3% (nearest tenth)

Step-by-step explanation:

[tex]\sf percentage \ change =\dfrac{|final \ value - initial \ value|}{initial \ value} \times 100\%[/tex]

Given:

[tex]\sf \implies percentage \ change =\dfrac{|84.25-86.25|}{86.25} \times 100\%[/tex]

[tex]\sf \implies percentage \ change =\dfrac{2}{86.25} \times 100\%[/tex]

[tex]\sf \implies percentage \ change =2.3\% \ (nearest \ tenth)[/tex]

Answer:

Option 2 hope it helps pls mark as the brainliest

Answer:

Domain: input values (x-values)

Range: output values (y-values)

Absolute value: remove negative sign → output becomes positive
eg. |-2| = 2

Squaring a number → output is always positive

[tex]a(x)=3|x|[/tex]

Domain = all real numbers

Range = all positive numbers and zero

[tex]b(x)=3x^2[/tex]

Domain = all real numbers

Range = all positive numbers and zero

Answer:

k= -5

Step-by-step explanation:

The equation for slope is rise over run which is also (y2-y1)/(x2-x1)

with the given coordinate being (x,y)

So, we just plug the given values into the equation in order to solve for k.

(9-k)/(-6-1)= -2

First let's simplify the denominator:

(9-k)/(-7)= -2

then we get rid of the denominator by multiplying it on both sides:

(9-k)= (-7)*(-2)

(9-k) = 14

-k = 5

k=-5

Answer:

Step-by-step explanation:

4+(7-5)2= 8 I guess

If Mr. Goldsman runs for one and a half hours, Kirby runs for 37 minutes 30 seconds.

The first step is to determine how many minutes kirby would run for every minute Mr Goldsman runs

Rate = 5/12

The second step is to multiply the rate by the minutes run by Mr Goldsman.

5/12 x 90 = 37.5

= 37 minutes 30 seconds

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Answer:

  -5 = log₄(0.0009765625)

  4 = log₄(256)

Step-by-step explanation:

Apparently, you want to express a number as a logarithm. That is, you want to find y for some value of x such that ...

  x = log₄(y)

Taking antilogs, this is ...

  y = 4^x

__

For x =-5, the log expression would be ...

  y = 4^-5 = 0.0009765625

  log₄(0.0009765625) = -5

__

For x = 4, the log expression would be ...

  y = 4^4 = 256

  log₄(256) = 4

Answer:

Step-by-step explanation:

(1,-4) m=2

first find c

-4=2×1+c

c=-6

y=2x+-6

Answer:

f(5)=26

Step-by-step explanation:

hello :

f(n)=f(n-1)+4   means :  f(n)-f(n-1)=4  (comon diference for arithm - sequence)

so : f(n) =f(1)+(n-1)×4

f(n) =10+(n-1)×4

f(n) = 4n+6

f(5) = 4(5)+6 =26

Based on the formula given of 27π = πn, we can find the value of n after substitution in an equation to be 27.

The value of n can be found by making n the subject of the formula as shown below;

27π = πn

n = 27π / π

Solving of n therefore gives:

n = 27π/π

n = 27

In conclusion, n is 27.

Find out more on finding terms at https://brainly.com/question/25827678.

Answer:

$1,689.

Step-by-step explanation:

Answer:

If this is compound interest and it is compouned annually,the answer is $1,685.91

If this is simple interest, the answer is $1,632.00

Step-by-step explanation:

Equation for compound interest.

[tex]A=P(1+\frac{r}{n})^{n*t}[/tex]

[tex]A=1200(1+\frac{0.12}{1})^{1*3}[/tex]

[tex]A=1685.91[/tex]

Equation for simple interest.

[tex]A=P(1+r*t)[/tex]

[tex]A=1200(1+0.08*3)[/tex]

[tex]A=1632.00[/tex]

The number of cubes that will fit into the shoebox is 40 cubes

Volume is the measure of a substance an object contains

Volume of the box = length * width * height

Volume of the box = 5/4 * 1 * 1/2
Volume of the box = 5/8cubic unit

Determine the volume of the box

Volume of the box = l³

Volume of the box = (1/4)³ = 1/64 cubic units

Number of cubes = (5/8)/(1/64)
Number of cubes = 5/8 * 64/1
Number of cubes = 5 * 8
Number of cubes = 40 cubes

Hence the number of cubes that will fit into the shoebox is 40 cubes

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[tex]\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\stackrel{\textit{"z" inversely proportional to "t"}}{z=\cfrac{k}{t}}\qquad \textit{we also know that} \begin{cases} t=9\\ z=28 \end{cases} \\\\\\ 28=\cfrac{k}{9}\implies 252=k~\hfill \boxed{z=\cfrac{252}{t}} \\\\\\ \textit{when t = 12, what is "z"?}\qquad z=\cfrac{252}{12}\implies z=21 \\\\\\ \textit{when z = 36, what is "t"?}\qquad 36=\cfrac{252}{t}\implies t=\cfrac{252}{36}\implies t=7[/tex]