Answer:
K = 4 ; N = 106
Step-by-step explanation:
Given the following :
Source of VARIATION - SS - df - - MS - - - - - F
Between groups - 1,959.79 - 3 - - 653.26 - 21.16*
Error - - - - - - - - 3,148.61 - - - - 102 - - 30.86
Total - - - - - - - - - - - 5,108.41 - 105
The degree of freedom between group (treatment) (DFT) is obtained using the formula ;
K - 1, where k = number of groups observed
DFT = K - 1 ; From the ANOVA table, DFT = 3
3 = K - 1
3 + 1 = K
K = 4
To obtain sample size (N) :
Degree of freedom of Error (DFE) is the difference between the sample size and the number of groups observed.
DFE = N - K ; From. The table DFE = 102 ; K = 4
102 = N - 4
102 + 4 = N
N = 106
I=prt,for p please show step by step for this variable
Answer:
[tex] p = \dfrac{I}{rt} [/tex]
Step-by-step explanation:
I = prt
Switch sides.
prt = I
We are solving for p. We want p alone on the left side. p is being multiplied by r and t, so we divide both sides by r and t.
[tex] \dfrac{prt}{rt} = \dfrac{I}{rt} [/tex]
[tex] p = \dfrac{I}{rt} [/tex]
Find an equation for the nth term of a geometric sequence where the second and fifth terms are -21 and 567, respectively
Answer:
[tex]x_n=7(-3)^{n-1}[/tex]
Step-by-step explanation:
First, write some equations so we can figure out the common ratio and the initial term. The standard explicit formula for a geometric sequence is:
[tex]x_n=ar^{n-1}[/tex]
Where xₙ is the nth term, a is the initial value, and r is the common ratio.
We know that the second and fifth terms are -21 and 567, respectively. Thus:
[tex]a_2=-21\\a_5=567[/tex]
Substitute them into the equations:
[tex]x_2=ar^{(2)-1}\\-21=ar[/tex]
And:
[tex]a^5=ar^{(5)-1}\\567=ar^4[/tex]
To find a and r, divide both sides by a in the first equation:
[tex]r=-\frac{21}{a}[/tex]
And substitute this into the second equation:
[tex]567=a(\frac{-21}{a} )^4[/tex]
Simplify:
[tex]567=a(\frac{(-21)^4}{a^4})[/tex]
The as cancel out. (-21)^4 is 194481:
[tex]\frac{567}{1}=\frac{194481}{a^3}[/tex]
Cross multiply:
[tex]194481=567a^3\\a^3=194481/567=343[/tex]
Take the cube root of both sides:
[tex]a=\sqrt[3]{343} =7[/tex]
Therefore, the initial value is 7.
And the common ratio is (going back to the equation previously):
[tex]r=-21/a\\r=-21/(7)\\r=-3[/tex]
Thus, the common ratio is -3.
Therefore, the equation is:
[tex]x_n=7(-3)^{n-1}[/tex]
The overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8.6 cm
a. Find the probability that an individual distance is greater than 214.80 cm.
b. Find the probability that the mean for 1515 randomly selected distances is greater than 204.00 cm
c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?
a. The probability is
(Round to four decimal places as needed.)
b. The probability is
(Round to four decimal places as needed.)
c. Choose the correct answer below.
A. The normal distribution can be used because the original population has a normal distribution.
B. The normal distribution can be used because the probability is less than 0.5
C. The normal distribution can be used because the mean is large.
D. The normal distribution can be used because the finite population correction factor is small
Answer:
(a) the probability that an individual distance is greater than 214.80 cm is 0.1401.
(b) The probability that the mean for 15 randomly selected distances is greater than 204.00 cm is 0.2482.
(c) The normal distribution can be used because the original population has a normal distribution.
Step-by-step explanation:
We are given that the overhead reach distances of adult females are normally distributed with a mean of 205.5 cm and a standard deviation of 8.6 cm.
(a) Let X = the overhead reach distances of adult females.
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm
[tex]\sigma[/tex] = standard deviation = 8.6 cm
So, X ~ Normal([tex]\mu=205.5,\sigma^{2} =8.6^{2}[/tex])
Now, the probability that an individual distance is greater than 214.80 cm is given by = P(X > 214.80 cm)
P(X > 214.80 cm) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{214.80-205.5}{8.6}[/tex] ) = P(Z > 1.08) = 1 - P(Z [tex]\leq[/tex] 1.08)
= 1 - 0.8599 = 0.1401
The above probability is calculated by looking at the value of x = 1.08 in the z table which has an area of 0.8599.
(b) Let [tex]\bar X[/tex] = the sample mean selected distances.
The z-score probability distribution for the sample mean is given by;
Z = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean reach distance = 205.5 cm
[tex]\sigma[/tex] = standard deviation = 8.6 cm
n = sample size = 15
Now, the probability that the mean for 15 randomly selected distances is greater than 204.00 cm is given by = P([tex]\bar X[/tex] > 204.00 cm)
P([tex]\bar X[/tex] > 204 cm) = P( [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] > [tex]\frac{204-205.5}{\frac{8.6}{\sqrt{15} } }[/tex] ) = P(Z > -0.68) = 1 - P(Z [tex]\leq[/tex] 0.68)
= 1 - 0.7518 = 0.2482
The above probability is calculated by looking at the value of x = 0.68 in the z table which has an area of 0.7518.
(c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because the original population has a normal distribution and the sample of 15 randomly selected distances has been taken from the population itself.
A jar contains 100 ounces of lemonade. A spout at the bottom of the jar is opened and the lemonade pours out at a rate of 10 ounces per second. Which graph below represents the amount of lemonade in the jar for the first 15 seconds after the spout was opened?
Answer:
100 ounces(hope it help)
Step-by-step explanation:
because there is only 100 ounces in the jar.
Please help fast :) I really need the help thanks !!
Step-by-step explanation:
6 x 1/7 is Less than 1 since 6 x 1/7 is equal to 6/7 in decimal form is 0.8571429.
4 x 4/9 is greater than 1 since 4 x 4/9 is equal to 1 7/9 in decimal form is 1.777...
8 x 1/8 is equal to 1 since 8 x 1/8 is equal to 1.
7 x 1/5 is greater than 1 since 7 x 1/5 is equal to 1 2/5 in decimal form is 1.4
3 x 1/2 is greater than 1 since 3 x 12 is equal to 1 1/2 in decimal form is 1.5
1 x 3/4 is is less than 1 since 1 x 3/4 is equal to 3/4 in decimal form is 0.75
3 1/2 x 5 2/5 = Also explain how you got it
Answer:
Hello! Answer below.
Step-by-step explanation:
The answer to your question is:
18 9/10 or 18.9
Steps below...
You have to do this first.
1. Convert the mixed number to fraction.
2. [tex]7/2[/tex]
Multiplied by
[tex]27/5[/tex]
This will equal, 189/10
If you divide this the answer will be 18 9/10
So the answer is 18 9/10 or 18.9
Hope this helps!
By, BrainlyMagic
Use the quadratic formula to solve the equation: 0 = x2 + x - 20
Answer:
(x-4)*(x+5) : x =4,-5
Step-by-step explanation:
a= 1
b= 1
c= -20
x1,2 = (-1+-(1 - (4*1*-20))^0.5)/2
x1,2 = (-1+-(1+80)^0.5)/2
x1,2 = (-1+-(81^0.5))/2
x1,2 =(-1+-9)/2
x1 = 8/2 = 4 x2 = -10/2 = -5
A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
Answer: 82 sq. units .
Step-by-step explanation:
Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.
Then we plot them on graph ( as provided in attachment)
Length = AB [tex]=\sqrt{(9+1)^2+(-1-7)^2}[/tex] units [By distance formula : [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]]
[tex]=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41}[/tex] units
Width = BC = [tex]\sqrt{(-1+5)^2+(7-2)^2}[/tex] units
[tex]=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}[/tex]
Area = length x width
= [tex]2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}[/tex]
Hence, the area of the rectangle is 82 sq. units .
______ income is gross income minus taxes and deductions. fill in the blank
Answer:
Net
Step-by-step explanation:
The definition of "Net Income" is a person's income after deductions and taxes. Hence it is also sometimes know as the "Take-Home" income. i.e the amount of money that you actually take home.
need help asap!!will mark brainliest
Answer:
x = -1
Step-by-step explanation:
[tex]Midpoint =(1,2)= (x,y)\\J(3,-3)=(x_1,y_1) \:and\:K(x,7)= (x_2,y_2)\\\\x = \frac{x_1+x_2}{2} \\\\1 = \frac{3+x}{2}\\ \\Cross\:Multiply \\2\times 1 = 3+x\\2 =3+x\\2-3=x\\-1=x\\\\x =-1[/tex]
Use the diagram to answer the question.
P
Which of the following statements is true?
line s and line t intersect
line s and line t intersect at Point P
Point P is on line t and on line s
all of the above are true
Answer:
last option ie all of the above are true
Lines s and t are intersect at P. Therefor, option D is the correct answer.
What is intersection of line?In a plane, intersecting lines are any two or more lines that cross one another. The point of intersection, which can be found on all intersecting lines, is where the intersecting lines share a common point.
Straight lines s and t are intersect at P.
P is called point of intersection.
Therefor, option D is the correct answer.
Learn more about intersection of lines here:
brainly.com/question/11297403.
#SPJ2
Edward walks at a pace 2 1/4 miles in 2/3 hour. How many miles does Edward walk per hour
Divide distance walked by time:
2 1/4 miles / 2/3 hours = 3 3/8 miles per hour
Can someone please help me !❤️❤️
Find the horizontal asymptote (Show your work)
Answer:
[tex] y = 0 [/tex]
Step-by-step explanation:
To find the given asymptote of the given function, [tex] f(x) = \frac{x^2 - 2x + 1}{x^3 + x - 7} [/tex], first, compare the degrees of the lead term of the polynomial of the numerator and that of the denominator.
The numerator has a 2nd degree polynomial (x²).
The denominator has a 3rd degree polynomial (x³).
The polynomial of the numerator has a lower degree compared to the denominator, therefore, the horizontal asymptote is y = 0.
CAN SOMEONE PLEASE HELP ME WITH THIS?
Look it up then u get the answer
Answer:
hey mate!
kindly see attached picture
hope it helped you:)
The area of a rectangular parking lot is represented by A = 6x^2 − 19x − 7 If x represents 15 m, what are the length and width of the parking lot?
Answer:
The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.
Step-by-step explanation:
The surface formula ([tex]A[/tex]) for the rectangular parking lot is represented by:
[tex]A = w\cdot l[/tex]
Where:
[tex]w[/tex] - Width of the rectangle, measured in meters.
[tex]l[/tex] - Length of the rectangle, measured in meters.
Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If [tex]A = 6\cdot x^{2}-19\cdot x -7[/tex], the factorized form is:
[tex]A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)[/tex]
Now, let consider that [tex]w = \left(x-\frac{7}{2}\,m \right)[/tex] and [tex]l = \left(x+\frac{1}{3}\,m \right)[/tex], if [tex]x = 15\,m[/tex], the length and width of the parking lot are, respectively:
[tex]w =\left(15\,m-\frac{7}{2}\,m \right)[/tex]
[tex]w = \frac{23}{2}\,m[/tex]
[tex]l =\left(15\,m+\frac{1}{3}\,m \right)[/tex]
[tex]l = \frac{46}{3}\,m[/tex]
The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.
Fatoring Trinomials
x^2+2x=-1
Answer:
[tex]\Huge \boxed{x=-1}[/tex]
Step-by-step explanation:
[tex]x^2+2x=-1[/tex]
Adding 1 to both sides of the equation.
[tex]x^2+2x+1=-1+1[/tex]
[tex]x^2 +2x+1=0[/tex]
Factoring the left side of the equation.
[tex]x^2 +1x+1x+1=0[/tex]
[tex]x(x+1)+1(x+1)=0[/tex]
[tex](x+1)(x+1) = 0[/tex]
[tex](x+1)^2 =0[/tex]
Taking the square root of both sides of the equation.
[tex]\sqrt{(x+1)^2} =\sqrt{0}[/tex]
[tex]x+1=0[/tex]
Subtracting 1 from both sides of the equation.
[tex]x+1-1=0-1[/tex]
[tex]x=-1[/tex]
Answer:
x = -1
Step-by-step explanation:
[tex]x^2+2x = -1\\=0\\=x^2+2x+1 \\= (x+1)(x+1)\\=(x+1)^2\\\\0 = \sqrt{(x+1)^2} \\= x+1\\\\x+1=0\\x=-1[/tex]
(b-(a-a)) ÷ 3; use a = 6, and b = 3
Answer:
The answer is 1Step-by-step explanation:
(b-(a-a)) ÷ 3
a = 6 , b = 3
Substitute the values into the above formula
That's
[tex](3 - (6 - 6)) \div 3[/tex]
Using PEDMAS solve the terms in the bracket first
That's
[tex](3 - 0) \div 3[/tex]
We have
3 ÷ 3
The final answer is 1Hope this helps you
Answer this pleaseeeeeeeee
Answer:
.= 157
Step-by-step explanation:
There are three clock summing up to 21
One clock=21/3
One clock= 7
There are three calculator summing up to 30
One calculator= 30/3
One calculator= 10
There are three light bulb summing up to 15
One light bulb =15/3
One light bulb= 5
So the problem expression is
Clock +calculator *3bulb
= Clock +(calculator*3bulb)
= 7+(10*3(5))
= 7 +(10*15)
= 7 + 150
.= 157
NEED THIS AND HOW U GOT THE ANSWER find the value of X given that M is greater than PQS equals 119°
Answer:
4.7 =x
Step-by-step explanation:
PQS = PQR + RQS
119 = 72+ 10x
Subtract 72 from each side
119 - 72 = 72+10x -72
47 = 10x
Divide by 10
47/10 = 10x/10
4.7 =x
4-2(3+2)
2
How do you do this help me
Answer:
-46Step-by-step explanation:
[tex]4 - 2(3 + 2) ^{2} \\ 4 - 2( {5}^{2} ) \\ 4 - 2(25) \\ 4 - 50 = - 46[/tex]
[tex]f(x) = {x}^{2} + 4x - 5[/tex]
when [tex]x > - 2[/tex]
find[tex] \frac{d {f}^{ - 1} }{dx} at \: x = 16[/tex]
Answer:
[tex] \dfrac{df^{1}(16)}{dx} = \pm \dfrac{1}{10} [/tex]
Step-by-step explanation:
[tex] f(x) = x^2 + 4x - 5 [/tex]
First we find the inverse function.
[tex] y = x^2 + 4x - 5 [/tex]
[tex] x = y^2 + 4y - 5 [/tex]
[tex] y^2 + 4y - 5 = x [/tex]
[tex] y^2 + 4y = x + 5 [/tex]
[tex] y^2 + 4y + 4 = x + 5 + 4 [/tex]
[tex] (y + 2)^2 = x + 9 [/tex]
[tex] y + 2 = \pm\sqrt{x + 9} [/tex]
[tex] y = -2 \pm\sqrt{x + 9} [/tex]
[tex]f^{-1}(x) = -2 \pm\sqrt{x + 9}[/tex]
[tex]f^{-1}(x) = -2 \pm (x + 9)^{\frac{1}{2}}[/tex]
Now we find the derivative of the inverse function.
[tex]\dfrac{df^{-1}(x)}{dx} = \pm \dfrac{1}{2}(x + 9)^{-\frac{1}{2}}[/tex]
[tex]\dfrac{df^{-1}(x)}{dx} = \pm \dfrac{1}{2\sqrt{x + 9}}[/tex]
Now we evaluate the derivative of the inverse function at x = 16.
[tex]\dfrac{df^{-1}(16)}{dx} = \pm \dfrac{1}{2\sqrt{16 + 9}}[/tex]
[tex]\dfrac{df^{-1}(16)}{dx} = \pm \dfrac{1}{2\sqrt{25}}[/tex]
[tex]\dfrac{df^{-1}(16)}{dx} = \pm \dfrac{1}{2 \times 5 }[/tex]
[tex]\dfrac{df^{-1}(16)}{dx} = \pm \dfrac{1}{10}[/tex]
Help please urgent !!!!The students of a certain college were asked to choose which of six movie genres was their favorite. The pie chart below shows the distribution of the students’ answers. If there are 18,500 students at the college, how many chose Drama , Other, or Comedy ?
Answer:
12,950
Step-by-step explanation:
drama: 23%
other: 27%
comedy: 20%
23% + 27% + 20% = 70%
70% of 18,500 =
= 0.7 * 18,500
= 12,950
Johnny has 6 apples,12 bananas, and 14 strawberries. Write the ratio of apples:bananas: strawberries in its simplest form.
Please help
Answer:
apples:bananas: strawberries
3 : 6 : 7
Step-by-step explanation:
apples:bananas: strawberries
6 12 14
Divide each by 2
6/2 12/2 14/2
3 6 7
The ratio is
3 : 6 : 7
Answer:
3:6:7
Step-by-step explanation
The answer is 3:6:7 because if you divide the numbers by 2, you will get a answer of 3, 6, and 7, the simplest form of the ratio.
Hope this helped!
~Emilie Greene
Can someone help me solve the maze?
Answer:
see attached
Step-by-step explanation:
This is asking you to recognize the symbols used to designate a point, line segment, ray, angle, line, and plane.
The point is designated by its letter.
A line segment is designated by the letters of its endpoints, with an overline.
A ray is designated by the endpoint and a point on the ray. The endpoint is listed first. The letters have an arrow over them pointing in the direction from the endpoint.
An angle is designated using the symbol ∠. If three letters are used to identify the angle, the middle one is the vertex.
A line is designated using its name, or by the letters of two points on the line. If the letters are used, there may be a double-ended arrow over them.
A plane is designated by 3 non-collinear points, for example, "plane ABC". It may also be designated by the name of the plane.
In a triangle ABC, AB=AC and ˂A=70°, find the angles,˂B and ˂C
please help !!!!!!!!!!!!!
Answer:
Then angles [tex]\angle B[/tex] and [tex]\angle C[/tex] both measure [tex]55^o[/tex]
Step-by-step explanation:
Notice that if sides AB and AC are equal, then the angles opposed to them (that is angle [tex]\angle C[/tex] and angle [tex]\angle B[/tex] respectively) have to be equal since equal sides oppose equal angles in a triangle.
So you also know that the addition of the three angles in a triangle must equal [tex]180^o[/tex], then:
[tex]\angle A + \angle B+\angle C= 180^o\\70^o+\angle B + \angle B = 180^o\\2\,\angle B = 180^o-70^o\\2 \angle B=110^o\\\angle B=55^o\\\angle C = 55^o[/tex]
como dividir ? ? . . .. . . .. . . .. . .. . . .. .
Answer:
What
Step-by-step explanation:
What Do You Mean Bro
Tim and Nikko bought new computers. Tim spent $55 more than 2/3 of the amount that Nikko spent for his computer. The total amount that Tim and Nikko spent for their computers was $2,870. How much did Nikko spend for his computer?
A. $1,181.00
B. $1,407.50
C. $1,689.00
D. $1,755.00
Answer:
C. $1,689.00Step-by-step explanation:
Let the amount spent by Tim be x and the amount spent by Nikko be y
If Tim spent $55 more than 2/3 of the amount that Nikko spent for his computer, then amount spent by Tim will be x = 55+2/3 y
Since the total amount that Tim and Nikko spent for their computers was $2,870 then;
x+y = $2,870
Substituting x = 55+2/3y into the equation above, we will have;
55+2y/3 + y = 2,870
(165 + 2y)/3 + y = 2,870
(165 + 2y+3y)/3 = 2,870
cross multiply
165 + 2y+3y = 3*2870
165+5y = 8610
5y = 8610-165
5y = 8445
y = 8445/5
y = 1689
Hence Nikko spent a sum of $1,689.00 on his computer.
If m∠PQR=(12x−2)∘, and mPR=(20x−10)∘, what is m∠PQR?
a. 137.5
b. 70
c. 16
d. 81
Answer:
Step-by-step explanation:
12x - 2 + 20x - 10 = 180
32x - 12 = 180
32x = 192
x = 6
12*6 - 2
72 - 2 = 70
the solution is b
Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8
Answer:
Step-by-step explanation:
-7y = -10x - 8
y = 10/7x + 8/7