Use the three steps to solve the problem.

Betty has 10 more dimes than quarters. If she has $3.45, how many quarters and dimes does she have?

Answer:

25

Step-by-step explanation:

First number      = 1

Second number = 2

Third number     = 5

Fourth number   = 10

Fifth number      = 25

Sixth number     = 50

Seventh number = 100

Again 14th number will be = 100

Again 21st number will be = 100

Continuing 70 th number will be = 100

71st number= 1

72nd number = 2

73rd number = 5

74th number = 10

75th number = 25

OR

[tex]\frac{75}{7} = 10 \times 7 + 5\\[/tex]

So, after repeating 10 times up to 100, then the 5 number will be the 75th number , which is 25

Answer:

Decompose each number:

\begin{gathered}6) 90 = 9 \times 10\\\\7) 40 = 4 \times 10\\\\8)890 = 89 \times 10\\\\9) 300 = 3 \times 100\\\\10) 7000 = 7 \times 1000\\\\11)3700 = 37 \times 100\\\\\end{gathered}

6)90=9×10

7)40=4×10

8)890=89×10

9)300=3×100

10)7000=7×1000

11)3700=37×100

Correct the error. Write the correct decomposition:

\begin{gathered}12) 560 = 56 \times 10\\\\13) 4300 = 43 \times 100\\\\14) 6000 = 60 \times 100 \ \ or \ \ 6 \times 1000\end{gathered}

12)560=56×10

13)4300=43×100

14)6000=60×100 or 6×1000

1) angle DCB

2) angle BCD

Step-by-step explanation:

the asymptotes of f(x) :

(4x-π) = π/2

4x = 3π/2 => x = 3π/8

(4x-π) = 3π/2

4x=5π/2 => x = 5π/8

the answer is

D. X= 3pi/8, x=5pi/8

Answer:

3

Step-by-step explanation:

A'B'C'D' is 3 times bigger than ABCD, so to get back to the original we gotta count the length of B'C' and devide by 3

[tex]9 \div 3 = 3[/tex]

The length of the segment BC or preimage of BC was 3 units.

Two-dimensional figures can be transformed mathematically in order to travel about a plane or coordinate system.

Dilation: The preimage is scaled up or down to create the image.

Reflection: The picture is a preimage that has been reversed.

Rotation: Around a given point, the preimage is rotated to create the final image.

Translation: The image is translated and moved a fixed amount from the preimage.

Given, A Quadrilateral A' B'C'D' is the image of quadrilateral ABCD under a dilation with a scale factor of 3.

From the graph diagram the length of segment B'C' is 9 units.

Therefore, Before the dilation, the length of the segment BC would be

(1/3)×9.

= 3 units.

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Answer:

500ml orange juice is the most cost effective

Answer:

Step-by-step explanation:

17/60 = 0.2833333333.....  3 repeating

25/60 = .025  terminating

31/44 = 0.7045454545.....   45 repeating

54/72 = 0.75    terminating

Answer:

568 in 2 boxes

Step-by-step explanation:

852 = total of grapes

852 ÷ 3 = 284 per box

To find 2 boxes:

284 + 284= 568

Answer:

D

Step-by-step explanation:

Total ribbon left is 28 1/3 - 10 2/3= 86/3-32/3=54/3=18

Answer:

a+b+c+d+e+f = 360º

Step-by-step explanation:

Each side of the outer triangle

is a straight line segment which is 180º

Since there are three sides

180 * 3 = 540º

therefor a+b+c+d+e+f + inside triangle = 540

The angles of the inside triangle total 180º

a+b+c+d+e+f = 540 - 180

a+b+c+d+e+f = 360º

Answer:

y=40°

Z + Y = 70°

z. = 70°-40°

z. = 30°

POH=X

=180-70

=110°

Answer:

line n

Step-by-step explanation:

Line n goes through points A and G on the diagram.

Answer:

0.75

Step-by-step explanation:

Answer:

3/4

Step-by-step explanation:

Use x for the equation: (x - 1/2)*1/2 = 1/8

Just go backwards

1/8 is the result, and to get it, you multiply by 1/2, so instead of that, you divide 1/8 by 1/2 instead (Dividing a number by a fraction is the same as multiplying it by its reciprocal. The reciprocal of 1/2 is 2): (1/8)/(1/2) = 1/8 * 2 = 2/8 = 1/4, now since we subtracted 1/2, we add instead: 1/4 + 1/2 = 1/4 + 2/4 = 3/4

Answer:

Yes, I agree

Step-by-step explanation:

See attachments for cone

Cone A

[tex]h = 2r[/tex]

Cone B

R = 2r

[tex]h=r[/tex]

The volume of a cone is

[tex]V = \frac{1}{3}\pi r^2h[/tex]

For cone A, we have:

[tex]V = \frac{1}{3}\pi r^2*2r[/tex]

[tex]V_A = \frac{2}{3}\pi r^3[/tex]

For cone B, we have:

[tex]V = \frac{1}{3}\pi *(2r)^2 * r[/tex]

[tex]V = \frac{1}{3}\pi *4r^2 * r[/tex]

[tex]V_B = \frac{4}{3}\pi r^3[/tex]

So, we have:

[tex]V_B = 2 * \frac{2}{3}\pi r^3[/tex]

Substitute [tex]V_A = \frac{2}{3}\pi r^3[/tex]

[tex]V_B = 2 * V_A[/tex]

Make VA the subject

[tex]V_A = \frac{1}{2}V_B[/tex]

Hence, I agree with Ahmad

Answer:

Option C.

Step-by-step explanation:

First, let's define the transformations used here:

We can see that the red graph is shifted horizontally to the right, and that is reflected across the x-axis:

Horizontal shift:

For a general function f(x) an horizontal shift of N units is written as:

g(x) = f(x + N)

where:

If N > 0, the shift is to the left

if N < 0 , the shift is to the right.

Reflection across the x-axis.

For a function f(x), a reflection across the x-axis is just written as:

g(x) = -f(x)

So, if here we have a reflection across the x-axis and a horizontal shift of one unit to the right, we would write the equation for the red graph as:

g(x) = -f(x)     (only for the reflection)

g(x) = -f(x - 1)    (for the reflection and the shift)

Then the graph of the red function is:

y = -f(x - 1)

We can rewrite this as:

y = -1*f(x - 1)

dividing both sides by -1 we get:

y/-1 = f(x - 1)

This is what we can see in option C, so the correct option is C.

Answer:

is B. 75

Step-by-step explanation:

x+26=101

x=101-26

:. x=75

[tex]\huge\boxed{\fcolorbox{lime}{yellow}{ B. \:75}}[/tex]

[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]

[tex]x + 26 = 101[/tex]

[tex]➺ \: x = 101 - 26[/tex]

[tex]➺ \: x = 75[/tex]

Therefore, the value of [tex]x[/tex] is 75.

[tex]\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}[/tex]

[tex]➺ \: x + 26 = 101[/tex]

[tex]➺ \: 75 + 26 = 101[/tex]

[tex]➺ \: 101 = 101[/tex]

➺ L. H. S. = R. H. S.

Hence verified.

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

Given:

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

To find:

The quadrant in which [tex]\theta[/tex] lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only [tex]\sin\theta[/tex] and [tex]\csc\theta[/tex] are positive.

In Quadrant III, only [tex]\tan\theta[/tex] and [tex]\cot\theta[/tex] are positive.

In Quadrant IV, only [tex]\cos\theta[/tex] and [tex]\sec\theta[/tex] are positive.

We have,

[tex]\sin \theta <0[/tex]

[tex]\tan \theta <0[/tex]

Here, [tex]\sin\theta[/tex] is negative and [tex]\tan\theta[/tex] is also negative. It is possible, if [tex]\theta [/tex] lies in the Quadrant IV.

Therefore, the correct option is D.

Answer:

n=0.05

0.00036km

Step-by-step explanation:

a)

20:1

1:0.05

n=0.05

b)

1:25000

0.00036:9

0.00036km

Answer:

a+b

Step-by-step explanation:

you have to multiply

7(3a-2b)                  5(3b-4a)

7x3=21                     5x3=15

7x2=14                      5x4=20

(21a-14b)                   (15b-20a)

add them

21a-14b+15b-20a

21a-20a=1a

-14b+15b=1b

1a+1b

i dont understand ur question pls make it more clear!

Answer: (a)

Step-by-step explanation:

Suppose the original function is [tex]y=\left | x \right |[/tex]

To shift it 2 units right, replace x by x-2 such that

[tex]\Rightarrow x-2=0\\\Rightarrow x=2[/tex]

So, the function becomes [tex]y=\left | x -2\right |[/tex]

Answer:

shhsksbsvsvdbdhsbs. c

9514 1404 393

Answer:

  (d)  -3

Step-by-step explanation:

Put the number into the expression and do the arithmetic.

  f(g(-2)) = f(-2-3) = f(-5) = 2(-5) +7 = -10 +7

  f(g(-2)) = -3

Answer:

Simple random sampling

Step-by-step explanation:

From the sampling description explained above, the sampling method used is a simple random sampling method whereby a small subset or group is chosen from a larger set or population with all individuals in the population having exactly equal chance. The entire sample during a simple random sampling does not have to partitioned or subdivided into groups or subgroups. All individual samples are entirely sampled together with all having the sample probability of being chosen. This way the samples are representative of the entire population. All students in the scenario were sampled with any subdivision. Hence, we have a simple random sampling method.

Answer:

800 = 1/3(B)(46)

Step-by-step explanation:

Volume of a cone is [tex]1/3pir^2h[/tex]

we can set up an equation where V = 1/3pir^2h

Knowns :

V = 800

h = 46

Plug the knowns into the equation

800 = 1/3(pir^2)(46)

pir^2 is the area of a circle, which in this case is B

hope this helps

The equation which can be used  to find the area of the circular base is 800 = 1/3(πr²)(46)

a three dimensional shape can be defined as a solid figure or an object or shape that has three dimensions—length, width, and height.

Given that  circular cardboard piece is needed for the base of a volcano model.

The volcano is 46 centimeters tall and has a volume of 800 cubic centimeters.

We have to find the equation which can be used to find the area of the circular base.

Volume of a cone is 1/3πr²h

V= 1/3πr²h

Plug in the values of volume and height in the above formula

V = 800

h = 46

800 = 1/3(πr²)(46)

Hence, the equation which can be used  to find the area of the circular base is 800 = 1/3(πr²)(46)

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Answer: (C) 308 cm^2

Step-by-step explanation: Flat surface area is the surface area that is not curved; in this case, it would be the two circular bases. The height is arbitrary as the height is not needed to calculate the area of the bases. The formula for the area of circular bases is πr^2. Let's plug the given values into the formula. (22/7)(7)^2=(22/7)(49)=154. 154 cm^2 is the area of one base. To find the area of both bases, simply multiply the area of one base by two. 154*2 is 308, therefore the answer is (C) 308 cm^2.

Given:  The length of the chords are given.

To find: Here we need to identify which of the chord is having shorter length,

Solution: By the given option it is clear that the 13 units is the answer.

Therefore, the shorter of the two chords shown are 13 units.

Answer:

The person above is 13 13 13 13

Step-by-step explanation:

13 13 13 13 13 13 13 13 13 13 13 13 13 13 its right on edge

13 13 13 13 13 13 13 13 13 13 13 13 13 13 its right on edge

13 13 13 13 13 13 13 13 13 13 13 13 13 13 its right on edge

13 13 13 13 13 13 13 13 13 13 13 13 13 13 its right on edge

Given:

The endpoints of a line segment QS are Q(-6,2) and S(5,6).

Point R divides the line segment QS in 1:2.

To find:

The coordinates of point R.

Solution:

Section formula: If a point divides a line segment in m:n, then the coordinates of that point are:

[tex]Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)[/tex]

It is given that the endpoints of a line segment QS are Q(-6,2), S(5,6) and point R divides the line segment QS in 1:2. So, the coordinate of point R are:

[tex]R=\left(\dfrac{1(5)+2(-6)}{1+2},\dfrac{1(6)+2(2)}{1+2}\right)[/tex]

[tex]R=\left(\dfrac{5-12}{3},\dfrac{6+4}{3}\right)[/tex]

[tex]R=\left(\dfrac{-7}{3},\dfrac{10}{3}\right)[/tex]

Therefore, the coordinates of point R are [tex]\left(\dfrac{-7}{3},\dfrac{10}{3}\right)[/tex].