Answer: hello the complete question is attached below
answer:
Histogram B is the right histogram
Yes it approximately depict data that have a normal distribution
Step-by-step explanation:
The histogram when plotted is symmetric which means/depicts that the data provided have a normal distribution ( approximately )
A histogram is one of the graphical ways of representing data for easy reading and interpretation.
13 multiplied by the sum of 4 and11. Now reverse the result and add it to the earliest result and then multiplied it by 13
Step-by-step explanation:
I am not critically certain but the ways you have jotted down your enquiry..
I assume is13 × (4×11)
13 × 44
=572 - 44= 528
528+13 =541
541 ×13=7033
Julie borrowed 3500 for 3years at a seven and a half simple interest rate how much interest rate is that
Answer:
787.50
Step-by-step explanation:
interest=3500*7.5*3/100
interest=35*7.5*3
interest=787.50
If 5(y-2) - 3(y + 4) = 0, then y
IS
A. -1
B. 3
C. 7
D. 11
Answer:
Y is -1.
Step-by-step explanation:
If you substitute the values, you find that that's the correct answer.
hi pls help me now i'll gibe you brainest,thank you
Answer:
64 cm^3
Step-by-step explanation:
answer for question no 5
length , breadth and height of the cube are always equal .So
here length = 4 cm
volume of a cube = l^3
=4^3
=64 m^2
On a
paper, graph y < -2x Then determine which answer matches
the graph you drew.
Answer:
theres the graph
Step-by-step explanation:
An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten weeks off per year (52 weeks in a year) for studying, vacation, and sick days. A non-student actuary is given four weeks off a year. It is assumed that all actuaries use all of the weeks off allocated to them. The actuary Mr. Taylor is at work today. What is the probability that he is a student?
Answer:
0.1111
Step-by-step explanation:
From the given information;
Number of staffs in the actuary = 80
Out of the 80, 10 are students.
i.e.
P(student actuary) = 10/80 = 0.125
number of weeks in a year = 52
off time per year = 10/52 = 0.1923
P(at work || student actuary) = (50 -10/52)
= 42/52
= 0.8077
P(non student actuary) = (80 -10)/80
= 70 / 80
= 0.875
For a non-student, they are only eligible to 4 weeks off in a year
i.e.
P(at work | non student) = (52-4)/52
= 48/52
= 0.9231
∴
P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)
P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)
P(at work) = 0.1009625 + 0.8077125
P(at work) = 0.90868
Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)
P(he is a student) = (0.125 × 0.8077) ÷ 0.90868
P(he is a student) = 0.1009625 ÷ 0.90868
P(he is a student) = 0.1111
х
f(x)
What is the initial value of the exponential function
represented by the table?
-2
1
8
e
8
-1
1
4
0
1
2
1
1
1
2
2
2
Answer:
the answer will be table -1
Step-by-step explanation:
Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample of American adults. If necessary, round to one more decimal place than the largest number of decimal places given in the data.
Lower Bound Upper Bound Frequency
56 64 11
65 73 15
74 82 14
83 91 4
92 100 11
Required:
a. What is the sample standard deviation?
b. What is the sample variance?
Answer:
[tex]\sigma = 12.5[/tex] ---- sample standard deviation
[tex]\sigma^2 = 157.2[/tex] ---- sample variance
Step-by-step explanation:
Solving (a): The sample variance
First, we calculate the midpoint of each class (this is the average of the limits)
So, we have:
[tex]x_1 = \frac{56 + 64}{2} = 60[/tex]
[tex]x_2 = \frac{65 + 73}{2} = 69[/tex]
And so on
So, the table becomes:
[tex]\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}[/tex]
Calculate the mean
[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]
[tex]\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}[/tex]
[tex]\bar x = \frac{4191}{55}[/tex]
[tex]\bar x = 76.2[/tex]
The variance is:
[tex]\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}[/tex]
So, we have:
[tex]\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}[/tex]
[tex]\sigma^2 = \frac{8488.8}{54}[/tex]
[tex]\sigma^2 = 157.2[/tex]
The sample standard deviation is:
[tex]\sigma = \sqrt{\sigma^2[/tex]
[tex]\sigma = \sqrt{157.2[/tex]
[tex]\sigma = 12.5[/tex]
Solving (b): The sample variance
In (a), we calculate the sample variance to be:
[tex]\sigma^2 = 157.2[/tex]
factor x^2-8x-48 completely
Answer: (X-12)(x+4)
The middle number is -8 and the last number is -48.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -8
Multiply together to get -48
Can you think of the two numbers?
Try 4 and -12:
4+-12 = -8
4*-12 = -48
Fill in the blanks in
(x+_)(x+_)
with 4 and -12 to get...
(x+4)(x-12)
Answer:
(x+4)(x−12)
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { (x - 12)(x + 4 )}}}}}}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex] {x}^{2} - 8x - 48[/tex]
[tex] = {x}^{2} + 4x - 12x - 48[/tex]
Taking [tex]x[/tex] as common from first two terms and [tex]12[/tex] from last two terms, we have
[tex] = x \: (x + 4) - 12 \: (x + 4)[/tex]
Taking the factor [tex](x+4)[/tex] as common,
[tex] = (x - 12)(x + 4)[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]
Find cos 0, tan 0, and csc0 where 0 is the angle shown in the figure. Give exact values, not decimal approximations. (plz help!)
Step-by-step explanation:
everything can be found in the picture
Write down in terms of n, an expression for the nth term
of the following sequences:
a) 6 2 -2 -6 -10
b) -8 -15 -22 -29 -36
Answer:
[tex]{ \bf{(a).}} \\ { \tt{ {n}^{th} = a + (n - 1)d }} \\ { \tt{ {n}^{th} = 6 + (n - 1) \times - 4 }} \\ {n}^{th} = 10 - 4n \\ \\ { \bf{(b).}} \\ { \tt{ {n}^{th} = - 8 + (n- 1) \times - 7 }} \\ { \tt{ {n}^{th} = -1 - 7n}}[/tex]
If the length of a rectangle is four times its width and the perimeter of the rectangle is 90 yd, whats its area?
Answer:
324 yds ^2
Step-by-step explanation:
If length=l and width=w, you could write an equation to find the length and width. Then use that to find the area. L=4w. There are two of each side in the rectangle. 4w+4w+w+w=10w. 10w=90. w=9. 4w=36. L=36. 36*9=324yds^2
A true false test contains 24 questions. In how many different ways can this test be completed. (Assume we
don't care about our scores.)
Answer:
The total number of ways to give the answer of the question is 16777216.
Step-by-step explanation:
Total number of questions = 24
The number of possibilities so that the answer is given is only 2. It is either true or false.
So, the total number of ways to complete the test is
[tex]2^{24} = 16777216[/tex]
A minority representation group accuses a major bank of racial discrimination in its recent hires for financial analysts. Exactly 16% of all applications were from minority members, and exactly 15% of the 2100 open positions were filled by members of the minority.
Required:
a. Find the mean of p, where p is the proportion of minority member applications in a random sample of 2100 that is drawn from all applications.
b. Find the standard deviation of p.
Answer:
a) The mean is of [tex]\mu = 0.16[/tex]
b) The standard deviation is of [tex]s = 0.008[/tex]
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Question a:
Exactly 16% of all applications were from minority members
This means [tex]p = 0.16[/tex], and thus, the mean is of [tex]\mu = p = 0.16[/tex]
b. Find the standard deviation of p.
2100 open positions, thus [tex]n = 2100[/tex].
[tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
[tex]s = \sqrt{\frac{0.16*0.84}{2100}}[/tex]
[tex]s = 0.008[/tex]
The standard deviation is of [tex]s = 0.008[/tex]
Which of the following will have 6 at unit place? a.19² b.11² c.24² d.13²
What is the mean absolute deviation of Warren’s data?
Warren's Scores Absolute Deviation from Mean Score – individual score
0
25
15
10
20
30
10
15
5
25
20
15
20
5
10
sum of absolute deviations =
Answer:
6.667
Step-by-step explanation:
I just did the calculations
Am I correct? If not which of the answers is correct?
Answer:
Yea you are right.
Step-by-step explanation:
Which is an x-intercept of the continuous function in the
table?
-2
-1
0
1
2
3
f(x)
-10
48
46
44
-2
0
(0, -6)
(3.0)
O (-6.0)
(0, 3)
Answer:
The x-intercept is the value of the variable x when the value of the function is equal to zero
so
In the table we have
(-1, 0)(−1,0) is a x-intercept, because
For x=-1x=−1 the value of the function is equal to zero
(-6, 0)(−6,0) is a x-intercept, because
For x=-6x=−6 the value of the function is equal to zero
therefore
the answer is
the continuous function in the table has two x-intercepts
(-1, 0)(−1,0)
(-6, 0)(−6,0)
c+12<16
what will be the answer
Answer:
[tex]c < 4[/tex]
Step-by-step explanation:
Move the constant to the right-hand side and change its signs:
[tex]c < 16 - 12[/tex]
Subtract the numbers:
[tex]c < 16 - 12 = c < 4[/tex]
I am not sure how to approach this problem or where to start? How would I be able to solve this problem?
Answer:
5.7
Step-by-step explanation:
We can use a proportion to solve the problem:
24 : 100 = 1.37 : x
x = (100 * 1.37)/24 = 137/24 = 5.7
What is the product of the rational expressions shown below? Make sure your
answer is in reduced form. X+1/x-4 • 5x/x+1?
Answer:
5x / (x - 4)
Step-by-step explanation:
(x + 1)/(x - 4) • 5x/(x + 1)
Method 1:
Cancel out x + 1
Leaving 5x/(x - 4)
Method 2:
(x + 1)/(x - 4) • 5x/(x + 1)
Multiply numerator and denominator separately
= 5x(x + 1) / (x - 4)(x + 1)
Cancel out (x + 1) in the numerator and (x + 1) in the denominator
= 5x / (x - 4)
Therefore,
(x + 1)/(x - 4) • 5x/(x + 1) = 5x / (x - 4)
Find the area of the composite area
PLEASE HELP ASAP!!!
Describe the graph of the function g by transformations of the base function f.
(Graph and Answers pictured!)
Answer:
Option (3)
Step-by-step explanation:
Base function in the graph is 'f' and the transformed form of the function 'f' is function 'g'.
Since, the base function 'f' is reflected across the x-axis,
h(x) = -f(x)
Followed by the translation by 3 units downwards,
g(x) = h(x) - 3
= -f(x) - 3
Therefore, function in the form of g(x) = -f(x) - 3 will be the answer.
Option (3) is the correct option.
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is
the solution set of this problem?
0 (-0, -21)
O (-0, -21]
o [-21, +00)
O (21, +00)
Answer:
5 × (x + 27) ≥ 6 × (x + 26).
Step-by-step explanation:
The solution set of " Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26" is (-∞, -21]
What is a solution set to an inequality or an equation?If the equation or inequality contains variable terms, then there might be some values of those variables for which that equation or inequality might be true. Such values are called solution to that equation or inequality. Set of such values is called solution set to the considered equation or inequality.
For this case, let the number in consideration be 'x', then according to the condition specified, we get:
The sum of a number and 27 = x+27Five times the sum of a number and 27 = [tex]5(x+27)[/tex]The sum of that number and 26 = x + 26Six times the sum of that number and 26 = [tex]6(x+26)[/tex]Also, we get:
Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26 as:
[tex]5(x+27) \geq 6(x+26)[/tex]
Expanding and taking x on one side:
[tex]5x+135 \geq 6x+156\\135-156 \geq x \\\\x \leq -21[/tex]
Thus, the considered statement is true for all the numbers which is smaller or equal to -21. Symbolically, the solution set is: (-∞, -21]
The square bracket shows that the -21 is included in the interval. And the interval (-∞, -21] is set of all real numbers smaller or equal to -21.
Thus, the solution set of " Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26" is (-∞, -21]
Learn more about inequalities here:
https://brainly.com/question/27425770
Complete each congruency statement and name the rule used. If you cannot show the triangles are congruent from the given information, leave the triangle's name blank and write CNBD for "Cannot be determined" in place of the rule. ∆ARE ≅ ∆_____ by _____
Answer:
add a picture so i can see .
Step-by-step explanation:
Answer the following questions using what you've learned from this unit. Write your
answers in the space provided. Be sure to show all work.
CLASSIFY and MEASURE TRIANGLES
1. Find angle measures and use angles to classify triangles.
Part I: Find the missing angle measure in each triangle. Show your work.
(3 points, 1 point each)
AAN
50"
В
A
mC
m B
mA
Answer:
50"
В
A
mC
m B
mA
Step-by-step explanation:
In a recent year, 31.6% of all registered doctors were female. If there were 53,000 female registered doctors that year, what was the total number of registered doctors?
Answer:
The total number of registered doctors was 167,722.
Step-by-step explanation:
Total number of doctors:
The total number of doctors is given by x.
31.6% of all registered doctors were female. 53,000 female doctors.
This means that:
[tex]0.316x = 53000[/tex]
What was the total number of registered doctors?
We have to solve the above equation for x. So
[tex]x = \frac{53000}{0.316}[/tex]
[tex]x = 167722[/tex]
The total number of registered doctors was 167,722.
please help. question in picture
Answer:
Step-by-step explanation:
Use the limit definition of the derivative to find the instantaneous rate of change of
f(x)=5x^2+3x+3 at x=4
[tex]f'(4) = 43[/tex]
Explanation:
Given: [tex]f(x)=5x^2 + 3x + 3[/tex]
[tex]\displaystyle f'(x)= \lim_{h \to 0} \dfrac{f(x+h) - f(x)}{h}[/tex]
Note that
[tex]f(x+h) = 5(x+h)^2 + 3(x+h) + 3[/tex]
[tex]\:\:\;\:\:\:\:= 5(x^2 + 2hx + h^2) + 3x + 3h +3[/tex]
[tex]\:\:\;\:\:\:\:= 5x^2 + 10hx + 5h^2 + 3x + 3h +3[/tex]
Substituting the above equation into the expression for f'(x), we can then write f'(x) as
[tex]\displaystyle f'(x) = \lim_{h \to 0} \dfrac{10hx + 3h + 5h^2}{h}[/tex]
[tex]\displaystyle\:\:\;\:\:\:\:= \lim_{h \to 0} (10x +3 +5h)[/tex]
[tex]\:\:\;\:\:\:\:= 10x + 3[/tex]
Therefore,
[tex]f'(4) = 10(4) + 3 = 43[/tex]
find the equation of line parallel to y=-2x+1 and passing through the point (2,4)
Answer:
[tex]y=-2x+8[/tex]
Step-by-step explanation:
Hi there!
What we need to know:
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)Parallel lines always have the same slopes1) Determine the slope (m)
[tex]y=-2x+1[/tex]
The given line has a slope of -2. Because parallel lines always have equal slopes, we know that the line parallel to this would also have a slope of -2. Plug this into [tex]y=mx+b[/tex]:
[tex]y=-2x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=-2x+b[/tex]
Plug in the given point (2,4) to solve for b
[tex]4=-2(2)+b\\4=-4+b[/tex]
Add 4 to both sides to isolate b
[tex]4+4=-4+b+4\\8=b[/tex]
Therefore, the y-intercept of the line is 8. Plug this back into [tex]y=-2x+b[/tex]:
[tex]y=-2x+8[/tex]
I hope this helps!