Answer:
Margin of error = 0.17Sample mean = 1.88Step-by-step explanation:
Given:
Sample 1.71 , 2.05
Find:
Margin of error
Sample mean
Computation:
1. Margin of error = (2.05 - 1.71) / 2
Margin of error = 0.34 / 2
Margin of error = 0.17
2. Sample mean = (2.05 + 1.71) / 2
Sample mean = 3.76 / 2
Sample mean = 1.88
Solve for z.
5
y = ZW - ZC
Step-by-step explanation:
5y = ZW - ZC
5y = Z(W - C)
5y / W- C = Z(W -C) / W - C
Z = 5y / W - C
show that Lim lx-2l/x-2 does not exist
Answer:
Actually It Does Lx-21/x-2 you have to find out what the Letter x stands for and what the letter L stands For for you to be able to find the answer
Step-by-step explanation:
simplify the expression i^37
im pretty sure that it is
i
Answer:
i
Step-by-step explanation:
[tex] \huge {i}^{37} \\ \huge= {i}^{36} \times i \\ \huge = ( {i}^{2})^{18} \times i \\\huge = ( - 1) ^{18} \times i \\ \huge = 1 \times i \\ \huge = i \\ \\\huge \therefore {i}^{37} = i[/tex]
A fish bowl contains blue, green and red plastic fish.
Answer:
Please comment on this answer what the real question is.
Step-by-step explanation:
can someone plz help me!
Answer:
Step-by-step explanation:
from focus
[tex]\sqrt{(x+3)^2+(y-2)^2}[/tex]
from directrix
|y-4|
Write this number using words. 703,010,006
Answer:
Seven and three million ten thousand and six.
Step-by-step explanation:
703 is in the millions place.
010 is in the thousands place.
and 006 is in the hundredths place.
hope this helps you!
Which rational number could be graphed between -3 and -4
Answer:
-3.5
Step-by-step explanation:
An example is -3.5.
According to a poll taken last year, 45% of the cities' residents get most of their news from the Internet. To conduct a follow-up study that would provide 90% confidence that the point estimate is correct to within 0.04 of the population proportion, how large a sample size is required
Answer:
The sample size is [tex]n =419[/tex]
Step-by-step explanation:
From the question we are told that
The population proportion is [tex]p = 0.45[/tex]
The margin of error is [tex]E = 0.04[/tex]
Given that the confidence level is 90%
Then the level of significance can be mathematically represented as
[tex]\alpha = 100 -90[/tex]
[tex]\alpha = 10\%[/tex]
[tex]\alpha = 0.10[/tex]
Next we obtain the level of significance from the normal distribution table the value is
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
Generally the sample size is mathematically represented as
[tex]n = [ \frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * p(1- p )[/tex]
substituting values
[tex]n = [ \frac{1.645 }{0.04} ]^2 * 0.45(1- 0.45 )[/tex]
[tex]n =419[/tex]
doctor better than teacher debate
Answer:
Teachers are the one that teach the doctors how to do their profession. They are both critical parts of society and should both be respected. Though doctors work with patients and determine what problems they have and how to help solve them. They work on treatments and can reassure patients in tough situations. They only goal is to help others and keep everyone has happy and healthy as possible.
7x - 3y = 4
2x - 4y = 1
The solution to the system of equations is _____.
A:(13/34, -15/34)
B:(3/22, -7/22)
C:(13/22, 1/22)
Answer:
My answer is option C.
Step-by-step explanation:
Since you cannot eliminate it immediately then you will need to multiply it by each of the number to make them equal that means you will multiply the first equation by any number in the second equation that is you can use maybe -4 or 2 or 1. and then do the same to the other equation to make them equal...if you use 2 in the second equation for the first equation and you use 7 in the first equation for the second equation the you will make them equal which makes them easier to eliminate and then when you find y which is y=1/22 then you can substitute it into any of the equation and find your x which is x=13/11.
Answer: option c
Step-by-step explanation:
You want to buy a special handcrafted square box. Since each box is uniquely handcrafted and you did not bring you ruler, you are not sure of the exact dimensions. Let X be the length of one of the sides, and assume that X is uniformly distributed between 15 and 18 inches. a) What is the expected volume of the box that you buy
Answer:
[tex]Volume = 4492.125\ unit^3[/tex]
Step-by-step explanation:
Given
Uniform Distribution X
X: 15 to 18
Required
Determine the expected volume
Since, X is uniformly distributed; We have to first determine the expected value of X as follows;
[tex]Mean(X) = \frac{b + a}{2}[/tex]
Where b = 18 and a = 15
[tex]Mean(X) = \frac{18 + 15}{2}[/tex]
[tex]Mean(X) = \frac{33}{2}[/tex]
[tex]Mean(X) = 16.5[/tex]
Since the box is a square box, the volume is as follows;
[tex]Volume = 16.5 * 16.5 * 16.5[/tex]
[tex]Volume = 4492.125\ unit^3[/tex]
Hence, the expected volume is 4492.125 unit³
The sum of three numbers is 125. The first number is 7 more than the first. The third number is 4 times the second.What are the numbers
Answer:
15, 22, 88
Step-by-step explanation:
I assume you mean the second number is 7 more than the first. Write the system of equations:
x + y + z = 125
y = x + 7
z = 4y
Substitute the third equation into the first.
x + y + 4y = 125
x + 5y = 125
Substitute the second equation.
x + 5(x + 7) = 125
6x + 35 = 125
6x = 90
x = 15
Solve for the other variables.
y = 22
z = 88
According to Bureau of Labor Statistics, 22.1% of the total part-time workforce in the U.S. was between the ages of 25 and 34 during the 3 rd quarter of 2011. A random sample of 80 part-time employees was selected during this quarter. Using the normal approximation to the binomial distribution, what is the probability that fewer than 20 people from this sample were between the ages of 25 and 34?
Answer:
The probability is [tex]P(X < 20 ) = 0.68807[/tex]
Step-by-step explanation:
From the question we are told that
The proportion of total part-time workforce is [tex]\r p = 0.221[/tex]
The sample size is n = 80
Generally the mean is mathematically represented as
[tex]\mu = n* p[/tex]
[tex]\mu = 0.221 * 80[/tex]
[tex]\mu = 17.68[/tex]
The proportion of not part - time workforce
[tex]q = 1- p[/tex]
=> [tex]q = 1- 0.221[/tex]
=> [tex]q = 0.779[/tex]
The standard deviation is mathematically represented as
[tex]\sigma = \sqrt{ 80 * 0.221 * 0.779 }[/tex]
[tex]\sigma = 3.711[/tex]
Now applying the normal approximation,
Then the probability that fewer than 20 people from this sample were between the ages of 25 and 34 is mathematically represented as
[tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ 20 - 17.68 }{ 3.711} )[/tex]
Applying continuity correction
[tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ (20-0.5 ) - 17.68 }{ 3.711} )[/tex]
[tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < \frac{ (20-0.5 ) - 17.68 }{ 3.711} )[/tex]
[tex]P(X < 20 ) = P( \frac{X - \mu }{ \sigma } < 0.4904 )[/tex]
Generally
[tex]\frac{X - \mu }{ \sigma } = Z ( The \ standardized \ value \ of \ X )[/tex]
So
[tex]P(X < 20 ) = P( Z< 0.4904 )[/tex]
From the z-table
[tex]P( Z< 0.4904 ) = 0.68807[/tex]
The probability is
[tex]P(X < 20 ) = 0.68807[/tex]
Davon marks a 4-inch paper strip into equal parts as shown below. Label the whole and quarter inches on the paper strip.
Answer:
Step-by-step explanation:
Divide the length of the paper strip into four equal sections of 1 inch each.
Mark the left end of the strip '0' and the right end '4.' Label the '1,' '2,' '3' points.
Between these marks, label the strip as follows:
'1/4,' '1/2,' '3/4,' 1 (already marked), '1 1/4,' '1 1/2,' and so on.
Next time, please be sure to share ALL parts of the question with which you want help. Thank you.
Give an example of two 2×2 matrices A and B, neither of which is the zero matrix or the identity matrix, such that AB=BA.
Let
[tex]A=B=\begin{bmatrix}0&1\\1&0\end{bmatrix}[/tex]
Then
[tex]AB=BA=\begin{bmatrix}0&1\\1&0\end{bmatrix}^2=\begin{bmatrix}1&0\\0&1\end{bmatrix}[/tex]
Find the inverse of the radical function [tex]\sqrt[3]{x-2}[/tex]
Answer: y=x³+2 or f⁻¹(x)=x³+2
Step-by-step explanation:
To find the inverse of the radical function, we replace y with x and x with y. Then, you solve for y.
[tex]y=\sqrt[3]{x-2}[/tex] [replace y with x and x with y]
[tex]x=\sqrt[3]{y-2}[/tex] [cube both sides to cancel out the cubed root]
[tex]x^3=y-2[/tex] [add both sides by 2]
[tex]x^3+2=y[/tex]
Now that we have switched the variables and solved for y, we know that the inverse function is y=x³+2 or f⁻¹(x)=x³+2.
Answer:
f^-1(x)=x^3+2
Step-by-step explanation:
Pleaasee answer!!!!!!!!!!!!!!!!!!!!
Answer:
C Mark me as brainliest!!!
Step-by-step explanation:
what do you do when you simplify like variables with different exponents for example: I have 3x^(5)y^(8) + 2x^(5)y^(7) when I simplify 3x and 2x give me 5x^(5) but I don't know what to do with the different exponents in the y variables do I separate the variables and end with 5x^(5)y^(8)y^(7)?
Because both the x and y variables are associate with a value, you don’t just add 3x and 2x.
You have:
3x^5y^8 + 2x^5y^7
Apply the exponent rule a^b+c = a^ba^c
This means x^5y^8 = x^5y^7y
Now you have:
3x^5y^7y + 2x^5y^7
Since they both now have an x^5y^7 in them factor the out of both:
When you take that out it’d both numbers you are left with 3y + 2
The final answer is: X^5y^7(3y +2)
Use the number line below, where RS=7y+2, ST=5y+7, and RT=14y−3. a. What is the value of y? b. Find RS, ST, and RT.
Answer:
a. y = 6
b. RS = 44
ST = 37
RT = 81
Step-by-step explanation:
RS = 7y + 2
ST = 5y + 7
RT = 14y - 3
find:
a. y
b. RS, ST, RT
RS + ST = RT
7y + 2 + 5y + 7 = 14y - 3
group like terms
7y + 5y + 2 + 7 = 14y - 3
12y + 9 = 14y - 3
9 + 3 = 14y - 12y
12 = 2y
y = 12/2
y = 6
-----------------------------------
b.
RS = 7(6) + 2
RS = 44
ST = 5(6) + 7
ST = 37
RT = 14(6) - 3
RT = 81
Answer:
a. y = 6
b. RS = 44; ST = 37; RT = 81
Step-by-step explanation:
RS + ST = RT
7y + 2 + 5y + 7 = 14y - 3
group like terms
7y + 5y + 2 + 7 = 14y - 3
9 + 3 = 14y - 12y
12 = 2y
y = 12/2
y = 6
plug in values to solve RS, ST, RT
RS = 7(6) + 2 = 44
ST = 5(6) + 7 = 37
RT = 14(6) - 3 = 81
x = 3 / 5 (cb+k)
Solve for b
Answer:
(5/3 x - k)/c =b
Step-by-step explanation:
x = 3 / 5 (cb+k)
Multiply each side by 5/3
5/3x =5/3* 3 / 5 (cb+k)
5/3x = (cb+k)
Subtract k
5/3 x - k = cb +k-k
5/3 x - k = cb
Divide by c
(5/3 x - k)/c = cb/c
(5/3 x - k)/c =b
Can a vertical line be diagonal?
Answer:
No
Step-by-step explanation:
Assuming that the x- and y- axes are respectively horizontal and vertical, a vertical line has an undefined slope and cannot be diagonal.
Note that only a diagonal line can have a slope defined.
A train is traveling at a constant speed of 90 miles per hour. How many feet does it travel in 10 seconds? Remember that 1 mile is 5280 feet.
Hi
1 mile = 5280 feet
at 90 mile per hour, you have 5280 *90 = 475 200 feets
an hour is 60*60 = 3600 second
so in 1 second the train travel : 475 200 /3600 = 4752 /36 = 132 feets
so in 10 seconds : 132*10 = 1320 feets.
The feet train travel in 10 seconds is 1,320 feet .
What is unitary method?The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
According to the question
Train traveling at a constant speed = 90 miles per hour
1 mile = 5280 feet
By using unitary method:
feet does it travel in 1 seconds = [tex]\frac{90*5280}{60*60}[/tex]
feet does it travel in 10 seconds = [tex]\frac{90*5280}{60*60} * 10[/tex]
= 1,320 feet
Hence, the feet train travel in 10 seconds is 1,320 feet .
To know more about unitary method here:
https://brainly.com/question/22056199
#SPJ3
Expand and simplify the expression 6x-7(4 - 5) algabra btw
Answer:
[tex] \boxed{ \bold{ \red{6x + 7}}}[/tex]Step-by-step explanation:
[tex] \sf{6x - 7(4 - 5)}[/tex]
Distribute 7 through the parentheses
[tex] \sf{6x - 28 + 35}[/tex]
Calculate
[tex] \sf{6x + 7}[/tex]
Hope I helped!
Best regards!!
Solve the equation: x/4= 2
Answer:
[tex] \purple{ \boxed { \bold{\blue{x = 8}}}}[/tex]Step-by-step explanation:
[tex] \mathsf{ \frac{x}{4} = 2}[/tex]
Apply cross product property
[tex] \mathsf{x \times 1 = 2 \times 4}[/tex]
Calculate
[tex] \mathsf{x = 8}[/tex]
Hope I helped!
Best regards!
Answer:
[tex] \frac{x}{4} = 2[/tex]
X=2
Step-by-step explanation:
4•x/4=2•4
X=8
The mean height of women in a country (ages 2029) is inches. A random sample of women in this age group is selected. What is the probability that the mean height for the sample is greater than inches? Assume . The probability that the mean height for the sample is greater than inches is nothing.
Complete Question
The mean height of women in a country (ages 20-29) is 64.4 inches. A random sample of 75 women in this age ground is selected. what is the probability that the mean height for the sample is greater than 65 inches? assume [tex]\sigma = 2.97[/tex]
Answer:
The value is [tex]P(X > 65) = 0.039715[/tex]
Step-by-step explanation:
From question we are told that
The mean is [tex]\mu = 64.4 \ inches[/tex]
The sample size is [tex]n = 75[/tex]
The probability that the mean height for the sample is greater than 65 inches is mathematically represented as
[tex]P(X > 65) = P[\frac{X - \mu }{ \sigma_{\= x} } > \frac{65 - 64.4 }{ \sigma_{\= x} } ][/tex]
Where [tex]\sigma _{\= x }[/tex] is the standard error of mean which is evaluated as
[tex]\sigma_{\= x } = \frac{\sigma}{\sqrt{n} }[/tex]
=> [tex]\sigma_{\= x } = \frac{2.97}{\sqrt{75} }[/tex]
=> [tex]\sigma_{\= x } = 0.343[/tex]
Generally [tex]\frac{X - \mu }{ \sigma_{\= x } } = Z(The \ standardized \ value \ of \ X )[/tex]
[tex]P(X > 65) = P[Z> \frac{65 - 64.4 }{0.342 } ][/tex]
So
[tex]P(X > 65) = P[Z >1.754 ][/tex]
From the z-table the value of
[tex]P(X > 65) = P[Z >1.754 ] = 0.039715[/tex]
[tex]P(X > 65) = 0.039715[/tex]
what is the answer to 6y+21+7=4y−20+5y
Step-by-step explanation:
the answer for 6y+21+7=4y−20+5y is
y =16
HELP!! hOW DO YOU FIND FREQUENCY FROM CLASS LIMITS AND CLASS BOUNDARY???? I AM SO CONFUSED.
Data:
70 88 103 64 88 100 78 80 77 69
85 65 71 90 88 75 80 72 60 70
60 75 79
Class width: 7
Class limits
60-66
67-73
74-80
81-87
88-94
95-101
102-108
class boundaries
59.5-66.5
66.5- 73.5
73.5- 80.5
80.5- 87.5
87.5- 94.5
94.5-101.5
101.5-108.5
frequency
____
------
____
____
_____
___
_____
= Total frequency
Side Note: Format is off but it is three columns I need help figuring out this exact problem
JIM, Thank so you so much. How can I private message you?
The third column is optional/extra. It's to show which data values fit in what specific class limit interval.
===================================================
Explanation:
Imagine we had a bunch of cards. Each card will have a number that is from the data set {70, 88, 103, 64, ... etc}
The goal is to sort the cards into 7 boxes. The first box is labeled "60 through 66", the next is "67 through 73", etc.
The first box has 4 cards placed inside it because we have the values {64,65,60,60 } which fit the interval from 60 through 66. Therefore the frequency here is 4.
The next box has the cards labeled {70,69,71,72,70 } inside it. We have 5 cards here, so the frequency is 5.
This pattern is kept up until all of the cards have been sorted into the proper boxes.
What you'll end up with is what you see in the image below. It shows the table of class limits with their corresponding frequencies. I have added a third column to show which values go where, which is optional and likely something you wont put as your answer to the teacher. This third column is just something for you to help keep track of everything.
Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.
Answer:
z= 3.63
z for significance level = 0.05 is ± 1.645
Step-by-step explanation:
Here p = 42% = 0.42
n= 500
We formulate our null and alternative hypotheses as
H0: p= 0.42 against Ha : p> 0.42 One tailed test
From this we can find q which is equal to 1-p= 1-0.42 = 0.58
Taking p`= 0.5
Now using the z test
z= p`- p/ √p(1-p)/n
Putting the values
z= 0.5- 0.42/ √0.42*0.58/500
z= 0.5- 0.42/ 0.0220
z= 3.63
For one tailed test the value of z for significance level = 0.05 is ± 1.645
Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.
(5 points) The probability of rain on any day in the month of April is 34%. The probability that it will be windy on any day in the month of April is 38%, and the probability of both is 10%. What is the probability that a randomly selected day in April will be rainy or windy?
Answer:
0.62
Step-by-step explanation:
Probability of rain = 34% = 0.34
Probability of wind = 38% = 0.38
Probability of wind and rain = 10% = 0.1
P(wind U rain) = p(wind) + p(rain) - p(both)
= 0.34 + 0.38 -1
= 0.62
The probability that it would be rainy or sunny in any given day in April is 62%
can you please help me?
Step-by-step explanation:
1.
Point M is the bisector of AB
AM = 13...(given)
Therefore, AB = 2AM = 2* 13 = 26
2.
Ray MC is the bisector of AB
AM = 8...(given)
Therefore, AB = 2AM = 2* 8 = 16
3.
Line l is the bisector of angle AB.
BM = 26...(given)
Therefore, AB = 2BM = 2* 26 = 52