Use Taylor's method of order two to approximate the solution for the following initial-value problem: y =1+(t − y)2, 2 ≤ t ≤ 3, y(2)

Answers

Answer 1

By using Taylor's method of order two, we can approximate the solution for the initial-value problem y = 1 + (t - y)[tex]^2[/tex], 2 ≤ t ≤ 3, y(2).

How can we approximate the solution using Taylor's method of order two for the given initial-value problem?

To approximate the solution for the given initial-value problem using Taylor's method of order two, we need to follow a step-by-step process. Let's break it down:

1. Identify the function and its derivatives

The initial-value problem is defined as: y = 1 + (t - y)[tex]^2[/tex], 2 ≤ t ≤ 3, y(2). Here, y represents the unknown function, and t is the independent variable. We need to find an approximation for y within the given time interval.

2.Express the function as a Taylor series

Using Taylor's method, we express the function y as a Taylor series expansion. In this case, we'll use the second-order expansion, which involves the function's first and second derivatives:

y(t + h) ≈ y(t) + hy'(t) + (h[tex]^2[/tex])/2 * y''(t)

3.Calculate the derivatives

Next, we need to calculate the first and second derivatives of y(t). Taking the derivatives of the given equation, we have:

y'(t) = -2(t - y)

y''(t) = -2

4. Substitute the derivatives into the Taylor series

Now, we substitute the derivatives we calculated into the Taylor series equation from Step 2:

y(t + h) ≈ y(t) + h * (-2(t - y)) + (h[tex]^2[/tex])/2 * (-2)

Simplifying further:

y(t + h) ≈ y(t) - 2h(t - y) - hc[tex]^2[/tex]

5. Set up the iteration process

To obtain an approximation, we iterate the formula from Step 4. Starting with the initial condition y(2) = ?, we substitute t = 2 and y = ? into the formula:

y(2 + h) ≈ y(2) - 2h(2 - y(2)) - h[tex]^2[/tex]

6. Choose a step size and perform iterations

Choose a suitable step size, h, and perform the iterations. In this case, let's choose h = 0.1 and perform iterations from t = 2 to t = 3. We'll calculate the approximate values of y at each step using the formula from Step 5.

7. Perform the calculations and update the values

Starting with the initial condition, substitute the values into the formula and calculate the new approximations iteratively:

For t = 2:

y(2.1) ≈ y(2) - 2h(2 - y(2)) - h[tex]^2[/tex]

For t = 2.1:

y(2.2) ≈ y(2.1) - 2h(2.1 - y(2.1)) - h[tex]^2[/tex]

Repeat this process until you reach t = 3, updating the value of y at each iteration.

By following these steps, you can approximate the solution for the given initial-value problem using Taylor's method of order two. Remember to adjust the step size and number of iterations based on the desired accuracy of the approximation.

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6

Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Solve for X ​

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Answer:

Step-by-step explanation:

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----   ----

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

580 : 1120 : 104

Step-by-step explanation:

1.12 ml -> 1120 ml

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580 : 1120 : 104

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Answer:

125/6= 20.8 gallons

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Step-by-step explanation:


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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Options :

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c.) P=Po(0.02/4)

d.) P=Po(4.02/4)

e.) P=Po(1+ 0.02/4)

Answer:

a.) P=1.005Po

d.) e.) P=Po(1+ 0.02/4)

Step-by-step explanation:

From the compound interest formula:

P = P0(1 + r/n)^t

Rate = 2% = 2/100 = 0.02

n = Number of compounding times per period, quarterly ; n = (12 /3) months

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What is the surface area of the pyramid?

The total surface area is the summation of the areas of the base and the three other sides. A = B + ( 1/2 ) ( P x h ), where B is the area of the base of the pyramid, P is the perimeter of the base, and h is the slant height of the pyramid

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To learn more about surface area of pyramid click :

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If the mean of 5 numbers is 10 and the mean of other 15 numbers is 20 , what is the combined mean of both 20 numbers​

Answers

9514 1404 393

Answer:

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Step-by-step explanation:

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The sum of the 15 numbers is 15·20 = 300.

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Step-by-step explanation:

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PROOF

(1) ABCD is a rhombus //Given

(2) AB=AD                     //definition of rhombus

(3) AO=AO                    //Common side, reflexive property of equality

(4) BO=OD // A rhombus is a parallelogram, a parallelogram's diagonals bisect each other

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(6) ∠AOD ≅ ∠AOB     //Corresponding angles in congruent triangles (CPCTC)

(7) AC⊥DB     //Linear Pair Perpendicular Theorem

The converse of this is also true: if a parallelogram's diagonals are perpendicular, it is a rhombus.

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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