Answer:
la branche de la mécanique concernée par le mouvement des objets sans référence aux forces qui provoquent le mouvement
Answer:
the features or properties of motion in an object.
Which element(s) would you expect to behave similarly to Gadolinium? What properties of would you expect to be the same, what would be different?
The elements in the lanthanide series are similar to gadolinium.
The periodic table is arranged in groups and periods. Elements in the same group have similar properties. At the bottom row of the periodic table lies a group of elements that have unique properties called the lanthanides. This is where Gadolinium belongs.
The elements in the lanthanide series such as europium and terbium are similar to gadolinium. The lanthanides are similar in chemical reactivity and appearance. However, the density of the metals differ because it increases with increase in atomic number.
Learn more: https://brainly.com/question/1415109
what is the element found in all living matter.
Answer:
There are four elements that are found in all living animals, that are:
Oxygen (O)
Carbon (C)
Hydrogen (H)
Nitrogen (N).
How many moles are in 50 g of CO2
Answer:
1.1 mol
Explanation:
n=m/M, where n is moles, m is mass, and M is molar mass.
M of CO2 = 12.01+16.00+16.00 = 44.01g/mol
n=50g/44.01g/mol
n = 1.13610543 mol
n ≈ 1.1 mol
Hope that helps
I don’t wanna fail if you know the answer pls help me :(
Answer:
liquid and gas........................
When vectors are added or subtracted, the net force is called the _____.
will give brainliest to whoever gets it right
Answer:
resultant
Explanation:
Consider a box divided in half. One side is filled with 1 mol Ne at 300. Kelvin, and the other is filled with 1 mol Rn at 300. Kelvin. A small hole is opened in the divider between the sides, allowing the gases to mix. Suppose it takes 4.0 minutes for the Rn pressure to equilibrate between the two sides. How long (min) will it take the Ne pressure to equilibrate? Enter your answer to 1 decimal place.
It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.
We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;
t1 = time taken for Rn to equilibrate = 4.0 s
t2 = time taken for Ne to equilibrate = ?
M1 = molar mass of Rn = 222g/mol
M2 = molar mass of Ne = 20 g/mol
Using
t1/t2 = √M1/M2
4/t2 = √222/20
4/t2 = 3.33
t2 = 4/3.33
t2 = 1.2 seconds
Learn more about diffusion in gases: https://brainly.com/question/879602
does the following atomic model of a chemical reaction correctly demonstrate the law of conversation of matter why or why not
plzzz help
Answer:
Yes
Explanation:
You can tell because there are 2 moles of H2 on the reactants side and 1 mole of O2, and on the products side we see the same amount, meaning that no moles of H2 or O2 were added or destroyed, meaning that it follows the law of conservation of matter.
Which element is shown below? How do you know?
If I place an egg in carbonated water will the egg gain or lose mass?
Answer:
The egg will gain mass.
Explanation:
Eggs soaked in distilled water will gain mass and appear dramatically swollen.
Answer:
Gain mass
Explanation:
Carbonated water will create a reaction inside the egg making the fluid inside the egg becoming more solid thus gaining mass
Hope this helps!
Heart, 5 stars, Brainiest, and 40 coins if right! Answer needed ASAP
Which statement describes what happens when Bret runs up a flight of stairs?
A. His kinetic energy is destroyed.
B. His potential energy decreases.
C. His kinetic energy is converted into potential energy.
D. His potential energy is converted into kinetic energy.
Answer:
His kinetic energy is converted into potential energy.
Explanation:
Which statement describes a homogeneous catalyst?
It is in a gaseous phase only.
It is in the same phase as the reactants.
It is completely consumed by reactants.
It forms different products than the uncatalyzed reaction forms.
Answer:
it is in the same phase as the reactants
The statement describes a homogeneous catalyst is,
It is in the same as the reactants.So, option B is correct one.
What is homogeneous catalyst?The homogeneous catalyst is refer to catalytic system.In this, the phase of substrates for a reaction and catalytic components are same.Mainly it is in liquid phase.Example: Production of acetic acidWhat is catalyst?
The substance which increases the rate of the reaction without being itself change at the end of the reaction is called catalyst.
learn about homogeneous catalyst,
https://brainly.com/question/4249142
#SPJ2
write the conjugate bases of the following acids ? H₂S , HCOOH ,HSO₃¯ , HSO¯₄ , HS¯, HNO₂ ,HCN,?
Answer:
HS(-)
HCOO(-)
SO3(2-)
SO4(2-)
S(2-)
NO2(-)
CN(-)
Explanation:
The parenthesis are the charges of the compounds. When an acid is introduced in a base, it dissociates its Hydrogens giving protons to the base. In this case, if you remove one hydrogen of a compound, you will reduce the charge of a compound since basically you're removing a positive charge from a compound. If you need to, I can explain how the thing of the charges work.
In fact, the definition of a conjugate base is a compound created when the original (an acid) compound dissacioate an atom of hydrogen (a proton) in a base.
I need the skeleton equation for the following sentence!
Carbon dioxide gas and solid calcium oxide are produced in the decomposition of solid calcium carbonate.
Answer:
A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)
A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)
Make a atomic model of carbon-12 in mine craft
(If it's good I'll give a lot of points)
Here is the atomic model in the picture.
what are nanofluids and how they work?
Answer:
What is nanofluids?
Nanofluids are engineered suspensions of nanometer-sized solid particles in a base fluid. Suspending small solid particles in the energy transmission fluids can improve their thermal conductivity and provides an effective and innovative way to enhance their heat transfer characteristics significantly.
How nanofluids work?
Nanofluid refers to the dispersion of metal or non-metal nano-powder into traditional heat exchange media such as water, alcohol, and oil to prepare a uniform, stable and high thermal conductivity. The traditional heat exchange medium has a low thermal conductivity and has been unable to meet the growing demand for industrial engineering heat exchange. The thermal conductivity of some metal or non-metal nanoparticles is often hundreds of times higher than that of heat-conducting media. For example, common silicon carbide nanoparticles have a thermal conductivity of 170-270 W/m•K. The researchers found that if the nanoparticles can be uniformly and stably dispersed in the heat transfer medium, the thermal conductivity of the nanoparticles will be greatly improved.
Nitric oxide (NO) from car exhaust is a primary air pollutant. Calculate the equilibrium constant for the reaction
N2(g) + O2(g) equilibrium reaction arrow 2 NO(g)
at 25°C using the data listed in the supporting materials.
Calculate the equilibrium constant at 1496°C, which is a typical temperature inside the cylinders of a car's engine after it has been running for some time. (Assume that both ΔrH° and ΔrS° are temperature independent.)
This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:
N₂(g) + O₂(g) ⇄ 2 NO(g)
Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:
There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:
[tex]\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)[/tex]
Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:
[tex]\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K[/tex]
Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:
[tex]\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol[/tex]
And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:
[tex]K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}[/tex]
Learn more:
(Gibbs free energy) https://brainly.com/question/15213613How is a mixture different from a compound?
Answer:
A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.
Explanation:
How much heat must be added to a 8.21 g sample of gold to increase its temperature from the tempe
75.3°C to 83.1°C? The specific heat of gold is 0.13 J/gºC
Answer:
Q= ms∆T
Where, m is mass of substance
S is specific heat
∆T is temperature change
As in question , m=8.21 ,s=0.13 ,∆T =6.2
So, Q = 8.21×0.13×6.2=6.61 J
You already converted mass to moles for the reactants. Now convert mass to moles for the product, copper. 0.71 g Cu equals moles.
Answer: it wound'nt let me type the equations out so i did it on g.o.o.gl.e docs :')
Explanation:
hope this helps <3
have a great day/night/noon
:)
13. Which has the largest atomic radius?
A. fluorine B. chlorine C. bromine
D. a bromine anion with a charge of 1-
Answer:
bromine
Explanation:
How many moles in 44.7 kg of carbon dioxide
Answer:
What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.
Explanation:
What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.
Select True or False: The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol. Bloom's Level: Understand
True, the entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
The third law of thermodynamics states that, the entropy of a system approaches a constant value as the temperature of the system approaches absolute zero.
The entropy of any perfectly ordered, crystalline substance at absolute zero temperature is zero. That is, the entropy of a pure, perfect crystalline substance at 0 K is 0 J/K.
Thus, we can conclude that the given statement is true. The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
Learn more about third law of thermodynamics here: https://brainly.com/question/1156831
natural gas has been stored in an expandable tank that keeps a constant pressure as gas is added or removed. the tank has a volume of 4.50x 104 ft 3 when it contains 77.4 million mole natural gas at - 5 °c. what is the new volume of the tank if consumers use up 5.3 million mole and temperature increase to 7 °c?
Answer:
5-3. Ice water 0 "C. A steel tank contains carbon dioxide at 27 "C and a pressure of 12.0 atm.
Explanation:
What is the required mass to prepare a 0.5M potassium chloride solution using 250mL of water
if one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane
The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :
(i) The molecular formula of sulphur dioxide is [tex]SO_{2}[/tex]
So, [tex]1[/tex] mole of [tex]SO_{2}[/tex] = [tex]Mass[/tex] [tex]of[/tex] [tex]2'O'[/tex]
[tex]=32+2*16[/tex]
[tex]= 64[/tex] grams
Now, [tex]64g[/tex] of sulphur dioxide [tex]= 1[/tex] mole
So, [tex]1g[/tex] of sulphur dioxide = [tex]\frac{1}{64}[/tex] mole
Thus, we have [tex]\frac{1}{64}[/tex] mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, [tex]\frac{1}{64}[/tex] mole of methane will also contain x molecules of methane.
(ii) Molecular formula of methan is [tex]CH_{4}[/tex]
So, 1 mole of [tex]CH_{4}[/tex] = Mass of C + Mass of 4 H
[tex]=12+4*12[/tex]
Now, 16g of methane = 1 mole
So, 1 g of mathane = [tex]\frac{1}{16}[/tex] mole
We know that:
[tex]\frac{1}{64}[/tex] mole of methane contains = x molecules
So, [tex]\frac{1}{16}[/tex] mole of contains will contain =[tex]\frac{x*64}{16}[/tex] molecules
=[tex]4x[/tex] molecules
In which case would recalibrating a thermometer be an important next step in an experiment dealing with boiling points?
A) The results of several trials are all very close to each other, but they are noticeably different from the accepted value for the boiling point.
B) A small number of trials are conducted, with results quite different from each other, and with an average that is noticeably different from the accepted value.
C) A single trial is conducted, and the result is very close to the accepted value of the boiling point.
D) The results of several trials vary by a large amount, but the average is close to the accepted value for the boiling point.
I believe the answer would be D
An electrolysis reaction is
A) spontaneous
B) exothermic
C) non-spontaneous
D) hydrophobic
Answer:
it's non-spontaneous
Explanation:
I hope it helps you
A mixture of 0.384 M H2O, 0.384 M Cl2O, and 0.652 M HClO are placed in a vessel at 25 oC. Calculate the equilibrium concentration (in molarity) of HClO at the same temperature.
Equilibrium concentration of HOCl at 25°C is 0.140 M
The equation of the reaction at equilibrium is given below:
H₂O (g) + Cl₂O (g) ⇄ 2 HOCl (g)
Equilibrium constant, Kc = 0.0900 at 25°C
An ICE chart for the reaction is set up below
H₂O (g) + Cl₂O (g) ⇄ 2 HOCl (g)
I 0.384 0.384 0.652
C -x -x + 2x
E 0.384 - x 0.384 - x 0.652 + 2x
The equation of the equilibrium constant is given as;
Kc = [tex]\frac{[HOCl]^2}{[H_{2}O][Cl_{2}O]}[/tex]
substituting the values into the equation:
Kc = [tex]\frac{(0.652 + 2x)^2}{( 0.384 - x)( 0.384 - x)}[/tex] = 0.0900
4x² + 2.608x + 0.425 = 0.0900 (0.147 - 0.768x + x²)
4x² - 0.09x² + 2.677x - 0.069x + 0.425 - 0.013 = 0
3.910x² + 2.677x + 0.412 = 0
Solving using the quadratic formula:
a = 3.910, b = 2.677, c = 0.412
x = [tex]\frac{-2.677\±\sqrt{2.677^2 - 4*3.910*0.412}}{2*3.910}[/tex]
x = -0.256 or -0.431
The negative sign indicates that equilibrium is to the left of the reaction
Since x cannot be greater than 0.384, x = -0.256.
Equilibrium concentration of HOCl = 0.652 + 2(-0.256)
Equilibrium concentration of HOCl at 25°C is 0.140 M
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The diagram below shows the reaction between iron oxide and carbon that produces iron and carbon dioxide. The reaction takes place in a closed system. What is true about the carbon atoms in the reaction? A. The mass of carbon atoms in the reactants is the same as the mass of carbon atoms in the products. B. The total mass of the carbon atoms is the same as the total mass of the iron atoms. C. The mass of the carbon atoms increases between the reactants and the products of the reaction. D. The total mass of the carbon atoms is the same as the total mass of the oxygen atoms.
Answer:
A
Explanation:
The trick here is to know what the conservation of mass means.
It means that no matter what happens and how much change there is, the mass of the carbons on the reactants = the mass of the carbons on the products.
That's exactly what A says.
The valence electrons of a krypton (Kr) atom in the ground state are located in the
A. first energy level (shell).
B. second energy level (shell).
C. third energy level (shell).
D. fourth energy level (shell).
Answer:
D
Explanation:
The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.