Answer:
[tex]{ \tt{f(x) = 2 {x}^{2} + 3x - 3 }} \\ { \tt{g(x) = - {x}^{2} }} \\ f(x) + 2 \times g(x) : \\ 0 {x}^{2} + 3x - 3 = 0 \\ x = 1 [/tex]
point's (1, 0)
We know that the remainder Rn will satisfy |Rn| ⤠bn + 1 = 1 (n + 1)9n + 1. We must make n large enough so that this is less than 0.0001. Rounding to five decimal places, we have b2 = _________ , b3 =_________and b4 =__________
This question is incomplete, the complete question is;
We know that the remainder R[tex]_n[/tex] will satisfy | R[tex]_n[/tex] | ≤ b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex].
We must make n large enough so that this is less than 0.0001.
Rounding to five decimal places,
we have b₂ = _________ , b₃ =_________and b₄ =__________
Answer:
b₂ = 0.00617, b = 0.00046 and b₄ = 0.00004
Step-by-step explanation:
Given the data in the question;
| R[tex]_n[/tex] | ≤ b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex]
Now,
b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex]
b₂ = b[tex]_{ 1 + 1[/tex] = 1 / ( 1 + 1 )9[tex]^{ 1 + 1[/tex] = 1 / (2)9² = 1 / 162 = 0.00617 { 5 decimal places }
b₃ = b[tex]_{ 2 + 1[/tex] = 1 / ( 2 + 1 )9[tex]^{ 2 + 1[/tex] = 1 / (3)9³ = 1 / 2187 = 0.00046 { 5 decimal places }
b₄ = b[tex]_{ 3 + 1[/tex] = 1 / ( 3 + 1 )9[tex]^{ 3 + 1[/tex] = 1 / (4)9⁴ = 1 / 19683 = 0.00004 { 5 decimal places }
Therefore, b₂ = 0.00062, b = 0.00046 and b₄ = 0.00004
If p and q are whole numbers such that p×q=37, find the value of p+q
Answer:
6x6
Step-by-step explanation:
Find the value of y.
Please help :(
Which table represents a direct variation function?
9514 1404 393
Answer:
(b) the correct table is marked
Step-by-step explanation:
Direct variation is characterized by the ratio of y to x being a constant for all values in the table. That constant is the constant of proportionality. For the values in the second table (marked), the ratio is ...
y/x = 8/6 = 12/9 = 16/12 = 4/3
The constant of proportionality is 4/3.
Imagine a couple who is ready to start a family. They plan to have exactly four children. Assuming no multiple births (twins, triplets, etc.), use the information provided in Pascal's triangle to determine how many different ways they may have exactly three boys and one girl (regardless of birth order).
Answer:
4 different ways
Step-by-step explanation:
Total number of children = 4
Distribution of the 4 children :
Number of boys = 3 ; Number of girls = 1
Boy = B ; Girl = G
Possible combinations :
BBBG ; GBBB ; BBGB ; BGBB
From the pascal triangle number of e; number of outcomes = 2
Having exactly 3 boys and 1 girl
Hence, of any of the 4 four total children, 3 must be boys and 1 girl ;
(ar^b) ^4 = 16r^20 where a and b are positive integers work our a and b
Answer:
a = 2
b = 5
Step-by-step explanation:
Given :
(ar^b)^4 = 16r^20 ; a and b are positive integers :
Opening the bracket :
a^4r^4b = 16r^20
a^4 = 16 - - - - - (1)
r^4b = r^20 - - - (2)
a^4 = 16
Take the 4th root of both sides :
(a^4)^(1/4) = 16^1/4
a = 2
From (2)
r^4b = r^20
4b = 20
Divide both sides by 4
4b/4 = 20/4
b = 5
Hence ;
a = 2
b = 5
where is the location of the incenter of triangle abc is
Answer:
The point of intersection of angle bisectors of the 3 angles of triangle ABC is the incenter (denoted by I). The incircle (whose center is I) touches each side of the triangle.
Answer:
Step-by-step explanation:
we need a photo..
Solve the following differential equations using classical methods. Assume zero initial conditions.
a. dx/dy +7x = 5cos2t
b. d^2x/dt^2 + 6 dx/dt + 8x = 5sin3t
I'll use the integrating factor method for the first DE, and undetermined coefficients for the second one.
(a) Multiply both sides by exp(7t ):
exp(7t ) dx/dt + 7 exp(7t ) x = 5 exp(7t ) cos(2t )
The left side is now the derivative of a product:
d/dt [exp(7t ) x] = 5 exp(7t ) cos(2t )
Integrate both sides:
exp(7t ) x = 10/53 exp(7t ) sin(2t ) + 35/53 exp(7t ) cos(2t ) + C
Solve for x :
x = 10/53 sin(2t ) + 35/53 cos(2t ) + C exp(-7t )
(b) Solve the corresonding homogeneous DE:
d²x/dt ² + 6 dx/dt + 8x = 0
has characteristic equation
r ² + 6r + 8 = (r + 4) (r + 2) = 0
with roots at r = -4 and r = -2. So the characteristic solution is
x (char.) = C₁ exp(-4t ) + C₂ exp(-2t )
For the particular solution, assume an ansatz of the form
x (part.) = a cos(3t ) + b sin(3t )
with derivatives
dx/dt = -3a sin(3t ) + 3b cos(3t )
d²x/dt ² = -9a cos(3t ) - 9b sin(3t )
Substitute these into the non-homogeneous DE and solve for the coefficients:
(-9a cos(3t ) - 9b sin(3t ))
… + 6 (-3a sin(3t ) + 3b cos(3t ))
… + 8 (a cos(3t ) + b sin(3t ))
= (-a + 18b) cos(3t ) + (-18a - b) sin(3t ) = 5 sin(3t )
So we have
-a + 18b = 0
-18a - b = 5
==> a = -18/65 and b = -1/65
so that the particular solution is
x (part.) = -18/65 cos(3t ) - 1/65 sin(3t )
and thus the general solution is
x (gen.) = x (char.) + x (part.)
x = C₁ exp(-4t ) + C₂ exp(-2t ) - 18/65 cos(3t ) - 1/65 sin(3t )
The denominator of a fraction is three more than twice the numerator. if both numerator and denominator are degreased by seven, the simplified result is 4/13
orgnal fraction. (Don't simplify.)
Answer:
2/7
Step-by-step explanation:
d=2n+3
[tex]\frac{d-7}{2n-4} = \frac{4}{13}[/tex]
13(2n+3) -91 =8n - 16
26n+39 -91 = 8n-16
18n=36
n=2
d=7
HOW DO YOU SOLVE THIS PROBLEM
x = 100° (using definition of vertical angles)
Need a little help with this one
If I=square root-1 then i^2=
Answer:
i^−3 = i
i^−2 = −1
i^−1 = −i
i^0 = 1
i^1 = i
i^2 = −1
i^3 = −i
i^4 = 1
i^5 = i
i^ 6 = −1
See the pattern
Please help! I feel like I'm drowning :(
Answer:
1d = -3
2b = 2
2c = 1
3a = 3
3d = 4
Step-by-step explanation:
Polynomial 1: [tex]x^2-8x+15[/tex]
Multiply the leading coefficient, 1, and the last term, 15. You get: 15.
Then, list out the factors of 15 and the addends of -8 until you get two of numbers that are the same:
Factors of 15: -5 * -3
Addends of -8: -5 + -3
Replace the -8x with -5x - 3x:
[tex]x^2-5x-3x+15[/tex]
Put parentheses around the first 2 terms & last 2 terms and factor like so:
[tex](x^2-5x)-(3x+15)[/tex]
[tex]x(x-5)-3(x-5)[/tex]
[tex](x-5)(x-3)[/tex]
Looking at the answer (ax + b)(cx + d), d would correspond with -3.
Polynomial 2: [tex]2x^3-8x^2-24x[/tex]
First factor out the x:
[tex]x(2x^{2}-8x-24)[/tex]
Divide the polynomial inside by 2 and place the 2 outside with the x:
[tex]2x(x^2-4x-12)[/tex]
Then find the factors of 1*-12 and the addends of -4 and see which two numbers match:
Factors of -12: -6 * 2
Addends of -4: -6 + 2
Replace the -8x with -6x + 2x:
[tex]2x(x^2-6x+2x-12)[/tex]
Put parentheses around the first 2 terms & last 2 terms and factor like so:
[tex]2x((x^2-6x)+(2x-12))[/tex]
[tex]2x(x(x-6)+2(x-6))[/tex]
[tex]2x((x+2)(x-6))[/tex]
[tex]2x(x+2)(x-6)[/tex]
Looking at the answer (2x)(ax + b)(cx + d), b & c would correspond with 2 & 1.
Polynomial 3: [tex]6x^2+14x+4[/tex]
Divide the polynomial by 2:
[tex](2)(3x^2+7x+2)[/tex]
Find the factors of 3*2 and the addends of 7 and see which two numbers match:
Factors of 6: 6 * 1
Addends of 7: 6 + 1
Replace the 7x with 6x + x:
[tex](2)(3x^2+6x+x+2)[/tex]
Put parentheses around the first 2 terms & last 2 terms and factor like so:
[tex](2)((3x^2+6x)+(x+2))[/tex]
[tex](2)(3x(x+2)+(x+2))[/tex]
[tex](2)((3x+1)(x+2))[/tex]
[tex](2)(3x+1)(x+2)[/tex]
Then multiply the 2 with the (x+2) and here's your final answer:
[tex](3x+1)(2x+4))[/tex]
Looking at the answer (ax + b)(cx + d), a & d correspond with 3 & 4.
Hope that helps (●'◡'●)
(This took a while to write, sorry about that)
(3k + 5)(2k2 – 5k – 3)
Find the value of x in each case:
Visually demonstrate the decimal .3 in the hundred square below. Explain how you what to shade.
Use the coordinates of the labeled point to find a point-slope equation of the
line.
5
5
(-2,-5) 6.5
>
O A. y- 5 = -2(x - 2)
O B. y + 5 = 2(x + 2)
O C. y + 5 = -2(x + 2)
OD. y- 5 = 2(x - 2)
Answer:
B. [tex] y + 5 = 2(x + 2) [/tex]
Step-by-step explanation:
Point-slope equation is given as [tex] y - b = m(x - a) [/tex], where,
(a, b) = (-2, -5)
[tex] m = slope = \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Using two points on the line (-2, -5) and (0, -1),
Slope (m) = (-1 -(-5))/(0 -(-2)) = 4/2
m = 2
✔️To write the equation in point-slope form, substitute a = -2, b = -5, and m = 2 into [tex] y - b = m(x - a) [/tex]
Thus:
[tex] y - (-5) = 2(x - (-2)) [/tex]
[tex] y + 5 = 2(x + 2) [/tex]
Complete the angle addition postulate for the following angle
Answer:
measurement m<GEM+m<MEO=m<GEO
Bryan and his wife, Jane, can afford $2,273 a month for a monthly mortgage payment.
How much money would they be able to borrow for a 30-year fixed mortgage if the APR is 3.8%.
How much money would they make in payments over the life-time of the mortgage?
How much money would they pay in interest over the life-time of the mortgage if they borrowed as much money as they could on the mortgage?
Round your answer to the nearest cent.
9514 1404 393
Answer:
borrowed amount: $487,812.89total of payments: $818,280.00paid in interest: $380,467.11Step-by-step explanation:
The formula for figuring the amount that can be borrowed (P) is shown on the first line of the attachment. (The second line rounds it to the nearest cent.) In this formula, ...
a = monthly payment, r = annual interest rate, t = number of years
The amounts requested by the problem statement are shown in the attachment, and above. b is the amount that can be borrowed, p is the total of payments, and i is the interest paid. There are 360 monthly payments in 30 years, so the total paid is 360 times the monthly payment amount.
Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
Answer:
C. 15.6
Step-by-step explanation:
Perimeter of WXYZ = WX + XY + YZ + ZW
Use the distance formula, [tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex] to calculate the length of each segment.
✔️Distance between W(-1, 1) and X(1, 2):
Let,
[tex] W(-1, 1) = (x_1, y_1) [/tex]
[tex] X(1, 2) = (x_2, y_2) [/tex]
Plug in the values
[tex] WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2} [/tex]
[tex] WX = \sqrt{(2)^2 + (1)^2} [/tex]
[tex] WX = \sqrt{4 + 1} [/tex]
[tex] WX = \sqrt{5} [/tex]
[tex] WX = 2.24 [/tex]
✔️Distance between X(1, 2) and Y(2, -4)
Let,
[tex] X(1, 2) = (x_1, y_1) [/tex]
[tex] Y(2, -4) = (x_2, y_2) [/tex]
Plug in the values
[tex] XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2} [/tex]
[tex] XY = \sqrt{(1)^2 + (-6)^2} [/tex]
[tex] XY = \sqrt{1 + 36} [/tex]
[tex] XY = \sqrt{37} [/tex]
[tex] XY = 6.08 [/tex]
✔️Distance between Y(2, -4) and Z(-2, -1)
Let,
[tex] Y(2, -4) = (x_1, y_1) [/tex]
[tex] Z(-2, -1) = (x_2, y_2) [/tex]
Plug in the values
[tex] YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2} [/tex]
[tex] YZ = \sqrt{(-4)^2 + (3)^2} [/tex]
[tex] YZ = \sqrt{16 + 9} [/tex]
[tex] YZ = \sqrt{25} [/tex]
[tex] YZ = 5 [/tex]
✔️Distance between Z(-2, -1) and W(-1, 1)
Let,
[tex] Z(-2, -1) = (x_1, y_1) [/tex]
[tex] W(-1, 1) = (x_2, y_2) [/tex]
Plug in the values
[tex] ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2} [/tex]
[tex] ZW = \sqrt{(1)^2 + (2)^2} [/tex]
[tex] ZW = \sqrt{1 + 4} [/tex]
[tex] ZW = \sqrt{5} [/tex]
[tex] ZW = 2.24 [/tex]
✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56
≈ 15.6
Answer:CCCCCCCCCCCCCCCCC
Step-by-step explanation:
E. Engagement Time Frame: Dox2) Leaming Task 2: Mate lists of possible combinations of snacks in your notebook. Use O for Orange Juice, M for Mango Juice, B for Blue Lemonade, O for Oreo, s for Skyflakes and R for Rebisco. Juices Biscuit Orange Juice Oreo Mango Juice Skyflakes Blue Leronode Rebisco
Answer:
The maximum number of possible combinations are 9.
Step-by-step explanation:
There are three types of juices :
Orange, Mango and Blue lemonade
There are three types of biscuits:
Oreo, Skyflakes and Rebisco
So, the number of possible combinations are
= (3 C 1) x (3 C 1)
= 3 x 3 = 9
The maximum number of possible combinations are 9.
The population of a city this year is 200,000. The population is expected to increase by 2.5% per year over the next 10 years. Which exponential equation models this situation?
Answer:
[tex]A = 200,000(1+.025) ^{t}[/tex]
[tex]A = 200,000(1+.025) ^{10}[/tex]
Step-by-step explanation:
Which of these figures has rotational symmetry?
Hello!
The answer is a.
Good luck! :)
What is the simplest form of 0.0115
23/200
Hope this helps! :)
Answer:
23/2000
Step-by-step explanation:
0.0115 can be written as 115/10000
=23/2000
Please mark me as brainliest.
The time that it takes to fold 1,000 origami cranes varies inversely with the number of people folding the cranes. If a class of 25 students work together to fold the 1,000 cranes, it will take 3 hours. Write an equation to show the relationship between time (t) and the number of people (n) folding cranes.
ASAP!!!!
Answer:
t = [tex]\frac{75}{n}[/tex]
Step-by-step explanation:
Use the inverse variation equation, y = [tex]\frac{k}{x}[/tex]
Replace y with t, and replace x with n, since those are the variables in this situation:
t = [tex]\frac{k}{n}[/tex]
Plug in 3 as t and 25 as n, and solve for k:
3 = [tex]\frac{k}{25}[/tex]
75 = k
Create the equation by plugging in 75 as k:
t = [tex]\frac{75}{n}[/tex]
So, the equation is t = [tex]\frac{75}{n}[/tex]
help e please i’ll give brainliest
Answer:
363,000,000
..........
Solve x2 + 4x + 3 = 0 by completing the square.
options:
–6, –1
–3, –1
1, 3
–6, –2
Answer:
-3,-1
Step-by-step explanation:
x²+4x+3=0
x²+4x=-3
x²+4x+(2)²=-3+(2)²
(x+2)²=-3+4
(x+2)²=1
Take square root of both sides
x+2=±1
x=-2±1
x=-1 or-3
There are 10 students on the track team who compete in sprinting events. They make up 25% of the track team. How many students are on the track team?
Answer:
40
Step-by-step explanation:
10/x = 25/100
Cross multiply 10 and 100 = 1000.
Then, divide 1000 by 25 = 40.
10/40 = 0.25 = 25%
Solve each inequality. Graph the solution on a number line.
Answer:
n>2 2/3
Draw a filled dot at a little more than 2 1/2 and continue the line to the right.
Step-by-step explanation:
Subtract 1/3 from both sides to get
2 2/3
Flip the inequality
n> 2 2/3
I hope this helps!
19. Students at a certain school can enroll in one elective course: painting, theater, choir, or band. This two-way frequency
table gives the number of male and female students enrolled in each class.
Male Female Total
Painting 17 16 33
Theater 15
18
33
Choir 21 25 46
Band 28
25
53
Total 81
84
165
Determine the conditional relative frequency that a student in the sample is enrolled in painting given that the student is
female.
O A. 19.0%
O B. 48.5%
O C. 9.7%
O D. 19.8%
Answer:
19.0%
Step-by-step explanation:
The probability that a student in the sample data is enrolled in painting Given that the student is female is a conditional probability and can be defined as :
Let,
F = Female ; P = painting
P(Painting Given female) = P(P|F) = (PnF) / F
From the table :
(PnF) = 16
F = 84
Hence,
P(P|F) = 16 / 84 = 0.19047 = 0.19047 * 100%
P(P|F) = 19.0%