Unknown cultural affiliations and loss of identity at high elevations." These are words used to propose the hypothesis that archaeological sites tend to lose their identity as altitude extremes are reached. This idea is based on the notion that prehistoric people tended not to take trade wares to temporary settings and/or isolated areas. As elevation zones of prehistoric people (in what is now the state of New Mexico) increased, there seemed to be a loss of artifact identification. Consider the following information.Elevation Zone Number of Artifacts Number Unidentified7000-7500 ft 114 715000-5500 ft 142 23Let p1 be the population proportion of unidentified archaeological artifacts at the elevation zone 7000-7500 feet in the given archaeological area. Let p2 be the population proportion of unidentified archaeological artifacts at the elevation zone 5000-5500 feet in the given archaeological area.(a) Find a 95% confidence interval for p1 − p2. (Round your answers to three decimal places.)lower limit: upper limit:

Answer:

[tex]-2\dfrac{3}{8}[/tex]

Step-by-step explanation:

Given the expression:

[tex]3\dfrac78 - 6\dfrac14[/tex]

We are to simplify and obtain an equivalent expression.

Step 1: Change to Improper Fractions

[tex]3\dfrac78 - 6\dfrac14=\dfrac{31}{8}-\dfrac{25}{4}[/tex]

Step 2: Take the Lowest Common multiple of the denominators

LCM of 8 and 4 is 8.

Therefore:

[tex]\dfrac{31}{8}-\dfrac{25}{4}=\dfrac{31-2(25)}{8}\\\\\dfrac{31-50)}{8}\\\\=-\dfrac{19}{8}\\\\=-2\dfrac{3}{8}[/tex]

Therefore, an equivalent expression to [tex]3\dfrac78 - 6\dfrac14[/tex] is [tex]-2\dfrac{3}{8}[/tex].

Answer

3  7/8+ (-6  1/4)

Step-by-step explanation:

Answer: 3/4 of the original price.

Step-by-step explanation:

Ok, so Sam buys 4 boxes in Store A.

We know that in Store A you can get 4 boxes paying only for 3.

If P is the price of a Box, then he got 4 boxes and paid 3*P

then the amount that he paid for each box is equal to the total amount that he paid divided the number of boxes that he received.

this is: 3P/4 = (3/4)*P

Meaning that he paid 3/4 of the original price for each box.

Answer:

26

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

sinH= hypotenuse/opposite = (2.9/6.6)

H = sin^-1 ( 2.9/6.6)

​H=26.065≈26

Answer:

The solution is attached here. Hope it helps ☺️

Answer:

[tex]r = 3.18cm[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

15 is your answer

Step-by-step explanation:

2 x 5 =10

3 x 5 =15

Answer:

a < -1

Step-by-step explanation:

Okay, so we are given this equation:

t(x) = ax^5 + 2

Lets plug in -2 as x and see what happens.. t(x) can be 66..

[tex]a * (-2)^{5} + 2[/tex] = 66

-32a + 2 = 66

-32a = 64

a = -2

A is less than -1,

a < -1

Answer:

b. Use an AD/AS diagram to show how a decrease in the inflation target can keep inflation and short-run output from starting to rise in 2021. Explain your diagram and what it reveals about monetary policy.

Answer:

938583

Step-by-step explanation:

Answer:

4mm.

Step-by-step explanation:

Area of a Square is: [tex]A=s^2[/tex]

's' -side length

We are given the area of 16 square mm.

[tex]16=s^2\\\sqrt{16} =\sqrt{s^2}\\\boxed {4=s}[/tex]

The length of each side of the square is 4mm.

Answer:

4 mm

Step-by-step explanation:

Hope this helps

Answer: 7

Step-by-step explanation: whhhhyyyy

Answer:

the answer is attached to the picture

Answer:

  [tex]\log_{19}{361}=2[/tex]

Step-by-step explanation:

We know that taking logarithms performs the transformation ...

  [tex]b^e=x\\\\e\cdot\log{b}=\log{x}\quad\text{take logs}\\\\e=\dfrac{\log{x}}{\log{b}}\quad\text{divide by $\log{b}$}\\\\\log_b{x}=e\quad\text{use the change of base formula}[/tex]

Then for b=19, e=2, x=361, we have

  [tex]\boxed{\log_{19}{361}=2}[/tex]

Answer:

Step-by-step explanation:

The significant figures of a number that carry meaningful contribution to its measurement resolution

Answer:

s=50*2+1/2*10*2^2=100+20=120 miles

The car travels 120 miles from this point in the next 2 hours, if the acceleration is constant.

There are three equation of motions that can be used when motion of the object is under constant acceleration and on a straight path.

They are listed below as:

[tex]v = u + at\\\\s = ut + \dfrac{1}{2} at^2\\\\v^2 = u^2 + 2as[/tex]

where, the symbols have following meanings:

u = initial velocity of the considered object

v = final velocity of the object

a = acceleration of the object

s = distance traveled by the object in 't' time.

Given; A car is running at a velocity of 50 miles per hour and the driver accelerates the car by 10 miles/hr2.

We are asked that how far the car travels from this point in the next 2 hours, if the acceleration is constant.

s = 50*2 + 1/2*10*2^2

s = 100+20

s = 120 miles

Therefore, the car travels 120 miles from this point in the next 2 hours, if the acceleration is constant.

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Answer:

the radius

Step-by-step explanation:

Answer:

radius

Step-by-step explanation:

Answer:

  5 feet

Step-by-step explanation:

Add 0.25 to both sides of the equation:

  4.75 +0.25 = x - 0.25 +0.25

  5.00 = x

The original height of the water in the pool was 5.00 feet.

Answer:

5 feet

hope this helps

Answer:

The p-value will be "0.0549".

Step-by-step explanation:

The given values are:

Time, t = 15 minutes

Df, σ = 25-1 = 24

Now,

⇒  [tex]H_{0}:\sigma^2\leq 150[/tex]

and,

⇒  [tex]H_{1}:\sigma^2>150[/tex]

As we know,

Chi square = [tex]\frac{(n-1)s^2}{(\sigma^2)}[/tex]

On putting the values in the above formula, we get

⇒                = [tex]\frac{24\times 15^2}{150}[/tex]

⇒                = [tex]\frac{24\times 225}{150}[/tex]

⇒                = [tex]36[/tex]

Therefore, p-value = 0.0549

The p-value determined > 0.05, the null hypothesis also isn't dismissed at point 0.05.

Answer:

Hans deposits $6000 into an account.

=> Principal P = 6000

Simple interest rate 5% per year.

=> Rate R = 5% = 5/100 = 0.05

The formula to calculate the amount of interest after 4 years:

A = P x R x years = 6000 x (5/100) x 4 = 1200$

Hope this helps!

:)

Answer:

-0.06 left-middle

0.28 right-middle

0.03 right-top

0.1 middle-top

0.12 middle-bottom

Step-by-step explanation:

column-row

Answer:

[-2; 1 ] is the new column vector

Step-by-step explanation:

See explanation in the attachment.

The value of a-2b as a column vector is [tex]\left[\begin{array}{c}-2&1\end{array}\right][/tex] .

A matrix is an arrangement of numbers, expressions or symbols arranged in rows and columns as a rectangular array. These rows and columns define the size or dimension of a matrix.

For the given situation,

The matrix is

[tex]a=\left[\begin{array}{c}4&5\end{array}\right][/tex] , [tex]b=\left[\begin{array}{c}3&2\end{array}\right][/tex]

The operation is a - 2b. The matrix becomes

⇒ [tex]a-2b=\left[\begin{array}{c}4&5\end{array}\right] -2\left[\begin{array}{c}3&2\end{array}\right][/tex]

⇒ [tex]a-2b=\left[\begin{array}{c}4&5\end{array}\right] -\left[\begin{array}{c}6&4\end{array}\right][/tex]

⇒ [tex]a-2b=\left[\begin{array}{c}-2&1\end{array}\right][/tex]

Hence we can conclude that the value of a-2b as a column vector is [tex]\left[\begin{array}{c}-2&1\end{array}\right][/tex] .

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Answer:

7/6pie. i think

Step-by-step explanation:

1/2 + 2/3 = 3/6 + 4/6 = 7/6 = 1 1/6

Answer:

1 and 1/6

Step-by-step explanation:

1/2 + 2/3 = 3/6 +4/6= 1 1/6

Answer:

Hi there!

To find the volume of the ball, we should follow this formula: 

4/3*pi*r^3

Since the radius is 4, we can just plug the value in:

4/3*3.14*4^3

= 267.946667

Round to the nearest tenth:

= 267.9

Your answer is 267.9. 

Hope this helps!

Answer: c

Step-by-step explanation:

Answer:

C. Rectangle

Step-by-step explanation:

It will result in to a rectangle

Answer:

B, D

Step-by-step explanation:

The product of a sum and a difference results in a difference of squares.

The product must be of the form (a + b)(a - b) to work.

Answer: B, D

Answer:

(w-2.5)(w+2.5) And (-4v-9)(-4v+9)

Step-by-step explanation:

E2020

Answer:

Only Figure 1 and Figure 3 Are Similar.

Step-by-step explanation:

Figure 1 and Figure 3 are proportional by 1:4 while the Figure 2 is not proportional to any of them.

Answer:

314 cm²

Step-by-step explanation:

Area of a circle is A= πr²

pi is 3.14 and radius is 10:

A= 3.14(10)²

A= 314

Answer:

A piece of tape: 15cm =150mm

=> The number of tape 5mm that could be cut: N = 150/5 = 30

Hope this helps!

:)

Answer:

Question 1) $0.08 per oz

Question 2) $0.09 per oz

Step-by-step explanation:

You have to divide the price by how many ounces there are.

$1.92 / 24 = $0.08

$1.35 / 15 = $0.09

Answer:

0.08.

0.09

Step-by-step explanation:

Answer:

Media: 167.88 cm

Mediana:  167.6 cm

Modo: 166.67 cm

Step-by-step explanation:

Hola!

La variable de interés es:

X: estatura de un alumno de noveno año de educación básica.

1)

Primero debes ordenar los datos de menor a mayor y contar cuantos de ellos corresponden dentro de cada intervalo determinado, por ejemplo, el primer intervalo es:

[160;164)

Los intervalos están definidos con el límite inferior cerrado, es decir que incluye el valor de dicho límite, y el límite inferior abierto, es decir, que ese valor no está incluido en el intervalo.

160,160,160,161,162,163,164,165,165,165,165,166,167,167,167,167,168,168,168,169,170, 170, 170,171,173,173,173,175,175,176.

f(1)= 6 (seis valores de estatura corresponden a este intervalo)

La sumatoria de todas las frecuencias absolutas debe dar por resultado el total de observaciones n= 30

Para el segundo intervalo [164;168)

f(2)= 10

2)

hi representa la frecuencia relativa simple y esta se calcula como fi/n

Por ejemplo para el primer intervalo:

h(1)= f(1)/n= 6/30= 0.20

Esta indica la proporción de que las alturas estén entre 160 y 164 cm.

En porcentaje se expresa como hi*100, para el primer intervalo: 0.20*100)= 20%

Para el segundo intervalo h(2)= f(2)/n= 10/30= 0.33 y su porcentaje es 33%

Como indican la proporción de cada categoría de la distribución, la sumatoria de las frecuencias relativas simples de todas las categorías debe ser 1.

3)

Como lo dice su nombre, esta frecuencia es acumulada y se calcula como la sumatoria de las frecuencias absolutas simples, para el primer intervalo, dado que previo a él no hay "nada" es igual a la frecuencia absoluta simple:

F(1)= f(1)

Para el segundo intervalo, es la frecuencia absoluta simple del primer intervalo más la frecuencia relativa simple del segundo intervalo:

F(2)= f(1) + f(2)= 6 + 10= 16

4)

Esta frecuencia también representa la sumatoria de las frecuencias relativas simples.

H(1)= h(1)= 0.20 como previo al primer intervalo no existe distribución definida, la frecuencia relativa acumulada es igual a la frecuencia relativa simple.

Para el segundo intervalo la frecuencia relativa acumulada es:

H(2)= h(1)+h(2)?= 0.20+0.33= 0.57

Adjunta a la respuesta encontrarás la tabla completa.

5)

Como no específica medidas de tendencia central requeridas, voy a calcular la media, mediana y modo utilizando la tabla.

Media

X[barra]= (∑x'fi)/n= ∑x'*hi

Dónde x' representa la marca de clase de cada intervalo. Para calcular la marca de clase de los intervalos debes realizar un promedio entre sus límites y su valor siempre debe encontrarse dentro de los límites del intervalo. Si no es así, has cometido un error de cálculos:

(Limite inferior + Limite superior)/2

1. [160;164)  x₁'= (160+164)/2= 162

2. [164;168)  x₂'= 166

3. [168;172)  x₃'= 170

4. [172;176)  x₄'= 174

Una vez que calculaste las marcas de clase, puedes calcular la media:

X[barra]= ∑x'*hi= (162*0.20)+(166*0.33)+(170*0.27)+(174*0.20)= 167.88 cm

Mediana:

La mediana es el valor de la variable que divide a la muestra en dos (50%-50%).

Para poder calcularla primero debes identificar su posición, en este tipo de presentación, debes identificar el intervalo en el que se encuentra incluida la mediana.

Para muestras pares, la posición de la mediana se calcula como:

PosMe= n/2= 30/2= 15

Esto significa que la mediana corresponde a la 15va observación de la muestra, observando la columna de las frecuencias absolutas (simples o acumuladas) debes identificar cual es el intervalo de la mediana:

Al segundo intervalo se corresponde una frecuencia acumulada de 16, lo que significa que la posición de la mediana está incluida en este intervalo:

[164;168)

Entonces puedes calcular la mediana como:

[tex]Me= Li + c [\frac{PosMe-F_{(i-1)}}{f_i} ][/tex]

Dónde

Li: es el límite inferior del intervalo de mediana.

c: es la amplitud del intervalo

F₍i₋₁₎: frecuencia absoluta acumulada del intervalo anterior al intervalo mediana

fi: frecuencia absoluta del intervalo mediana

[tex]Me= 164 + 4 [\frac{15-6}{10} ]= 167.6[/tex]

Me= 167.6 cm, como puedes notar, el valor de la mediana se encuentra entre los límites del intervalo.

Modo o Moda:

El modo o la moda de una distribución corresponde al valor más observado, es decir, al valor con mayor frecuencia absoluta simple. Al igual que la media, para calcular el modo primero debes identificar el intervalo que lo contiene. En este caso, el intervalo modal será aquel con la mayor frecuencia absoluta simple.

[164;168)

La fórmula para calcular el modo es:

[tex]Md= Li + c[\frac{(f_{max}-f_{ant})}{(f_{max}-f_{ant})+(f_{max}-f_{post})} ][/tex]

Li: es el límite inferior del intervalo modal

c: es la amplitud del intervalo

[tex]f_{max}[/tex]: es la frecuencia absoluta simple del intervalo modal.

[tex]f_{ant}[/tex]: es la frecuencia absoluta simple del intervalo anterior al intervalo modal.

[tex]f_{post}[/tex]: es la frecuencia absoluta simple del intervalo posterior al intervalo modal.

[tex]Md= 164 + 4[\frac{10-6)}{(10-6)+(10-8)} ]= 164+4[\frac{4}{4+2} ]= 166.67[/tex]

Md= 166.67 cm

¡Espero que tengas un buen día!

Answer:

64 * b * b * b * b * b * b

Step-by-step explanation:

Apply exponent to number first, then expand the variable's exponent into repeated multiplication.

An exponent is a symbol that is written above and to the right of a mathematical expression to indicate the operation of raising a power.

The value of (2b²)³ without the exponents is 8 x b x b x b x b x b x b.

A symbol that is written above and to the right of a mathematical expression to indicate the operation of raising to a power.

a², b³

a and b are base.

2 and 3 are exponents.

We have,

(2b²)³

This can be written as:

= 2³ x [tex]b^{2\times3}[/tex]

[ 2 x 2 x 2 = 2³ = 8 ], [ a². a³ = [tex]a^{2\times3}[/tex] ] and [ (a²)³ = [tex]a^{2\times3}[/tex] ]

= 8 x [tex]b^{6}[/tex]

Since we have to write without the exponents we have,

= 8 x b x b x b x b x b x b

Thus the value of (2b²)³ without the exponents is 8 x b x b x b x b x b x b.

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Answer:

Larry’s graph is incorrect.He should used a closed circle at -5

Step-by-step explanation:

Answer:

A)Larry’s graph is incorrect. He should have used a closed circle at –5.

Step-by-step explanation: