Una muestra de agua de 250g de agua se caliento desde 10°C hasta 60°C calcula la cantidad de calor absorbido por el agua el calor especifico del agua es de 4186J/Kj.K

Answers

Answer 1

Answer:

Calor absorbido, Q = 52325 Joules

Explanation:

Dados los siguientes datos;

Masa = 250g to kg = 250/1000 = 0.25kg

Temperatura inicial, T1 = 10°C to Kelvin = 273 + 10 = 283K

Temperatura final, T2 = 60°C to Kelvin = 273 + 60 = 333K

Capacidad calorífica específica = 4186 j/kg.K.

Para encontrar la cantidad de calor necesaria;

La capacidad calorífica viene dada por la fórmula;

[tex] Q = mct [/tex]

Dónde;

Q representa la capacidad calorífica o la cantidad de calor.

m representa la masa de un objeto.

c representa la capacidad calorífica específica del agua.

dt representa el cambio de temperatura.

dt = T2 - T1

dt = 333 - 283

dt = 50 K

Sustituyendo en la fórmula, tenemos;

[tex] Q = 0.25*4186*50[/tex]

[tex] Q = 52325 [/tex]

Calor absorbido, Q = 52325 Joules


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Answer:

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Explanation:

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Answers

Answer:

Yes

Explanation:

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Which of these actions does NOT have a vector?
O Swinging from a wire
O Drilling a hole
O Kickig a soccer ball
O Looking to the right

Answers

drilling a hole because it’s a one way movement

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Answers

Answer:

wound disinfectant, to kill fungus, teeth whitener

Explanation:

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Two identical cars, each traveling at the same velocity, and having the same mass come to a stop
Car A stops in 0.3 seconds.
Car B stops in 5 seconds.
Which of the following statements is TRUE?
O Car A has less momentum and experiences less force than Car B.
O Car A has the same change in momentum but experiences more force than Car B.
Car A has the same change in momentum but experiences less force than Car B.
© Car A has the same change in momentum and experiences the same force as Car B.
1 2

Answers

Answer:

The second option - same change in momentum, different force

Explanation:

They experience the same change in momentum, but the force on car A is greater.

p=m*v

Impulse, or change in p=F*t

We know the cars have the same change in momentum, because they both go from the same initial momentum (p=mv), to zero momentum. Therefore, both experience the same change in momentum. Since the time is different, but the change in momentum is the same, the force has to be different.

For example: if both cars had 200 kg*m/s of momentum at the start, and 0 at rest, the impulse is 200 kg*m/s

So,

p(a)=    200=F(0.3)

p(b)=    200=F(5)

Which force has to be greater to make the equations true? The force for Car A, of course!

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