Un compuesto formado por carbono, hidrógeno y oxígeno tiene una masa de 4,6 g. Se hace reaccionar con 9,6 g de oxígeno dando 8,8 g de CO2 y 5,4 g de agua. Si cogemos 9,2 g de un compuesto en un volumen 5,80l en P= 780 mmHg a una temperatura de 90ºC. Calcula la fórmula empírica y molecular.

Answers

Answer 1

Answer:

La fórmula empírica y molecular es: C₂H₆O.

Explanation:

Para calcular la formula empírica y molecular del compuesto debemos primero plantear la reacción:  

[tex] C_{x}H_{y}O_{z} + O_{2} \rightarrow CO_{2} + H_{2}O [/tex]

Necesitamos encontrar "x", "y" y "z". Para ello, tenemos que recordar que la masa de carbono e hidrógeno producida está relacionada con la cantidad de C y H inicial (del compuesto):

Para el H:

CHO → H₂O

y          5,4g

[tex] \frac{2*1 g}{18 g} = \frac{y}{5,4 g} \rightarrow y = 0,6 g [/tex]

Para C:  

CHO → CO₂

 x         8,8g

[tex] \frac{12 g}{44 g} = \frac{x}{8,8 g} \rightarrow x = 2,4 g [/tex]

Para el O:

[tex] z = 4,6 g - 2,4 g - 0,6 g = 1,6 g [/tex]

Ahora mediante el calculo de los moles del C, H y O podemos encontrar la fórmula empírica:

Para el H:

[tex] n_{y} = \frac{m}{Pm} = \frac{0,6 g}{1 g/mol} = 0,6 moles [/tex]

Para el C:

[tex] n_{x} = \frac{m}{Pm} = \frac{2,4 g}{12 g/mol} = 0,2 moles [/tex]

Para el O:

[tex] n_{z} = \frac{m}{Pm} = \frac{1,6 g}{16 g/mol} = 0,1 moles [/tex]

[tex] C_{\frac{n_{x}}{n_{z}}}H_{\frac{n_{y}}{n_{z}}}O_{\frac{n_{z}}{n_{z}}} = C_{\frac{0,2}{0,1}}H_{\frac{0,6}{0,1}}O_{\frac{0,1}{0,1}} = C_{2}H_{6}O_{1} [/tex]

Entonces, la fórmula empírica del commpuesto formado es C₂H₆O.

Ahora para determinar la fórmula molecular podemos usar la siguiente relación:

[tex] \frac{Pm}{Pm_{e}} = n [/tex]

[tex] F_{m} = n*F_{e} [/tex]

[tex] F_{m} = \frac{Pm}{Pm_{e}}*F_{e} [/tex]    

En donde Fm (fórmula molecular) y Fe (fórmula empírica) están relacionadas por n.

El valor de Pm lo obtenemos de la ecuación del gas ideal:

[tex]PV = nRT = \frac{m}{Pm}RT[/tex]

[tex] Pm = \frac{mRT}{PV} = \frac{9,2 g*0,082 L*atm/(K*mol)*(90 + 273 K)}{1.02 atm*5,80 L} = 46,3 g/mol [/tex]

[tex] F_{m} = \frac{46,3 g/mol}{(2*12 + 6*1 + 16)g/mol}*C_{2}H_{6}O_{1} = 1.00*C_{2}H_{6}O_{1} = C_{2}H_{6}O_{1} [/tex]    

Por lo tanto, la fórmula molecular es la misma que la fórmula empírica, a saber C₂H₆O.

Espero que te sea de utilidad!


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At the end of meiosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosomes split between both cells.
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Answers

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Answers

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Answers

Answer:

The answer is 5880 J

Explanation:

The potential energy of a body can be found by using the formula

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where

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Hope this helps you

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Answer:

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GREETINGS!

One mole of a substance is equal to 6.02 × 10²³ units of that substance. The number 6.022 × 10²³ is known as Avogadro's number.

so if one mole of molecule is equal to that number so,

                              for 4 moles of [tex]HNO_{3}[/tex]= 4 x ([tex]6.02x10^{23}[/tex])

so answer is,

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HOPE IT HELPS YOU.

Use the information below to answer the following questions.

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Further explanation

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Answers

Answer:

61.75 °C

Explanation:

According to the law of conservation of energy,

Qtin = - (Qliquid)

(m×c×∆T)tin = -(m×c×∆T) ethylene glycol

Where; m = mass

c = specific heat capacity

∆T = change in temperature

According to the information given in this question;

For tin: m= 10.04g, c= 0.213 J/g °C, initial temperature= 14.77 °C, final temperature=?

For ethylene glycol: m= 24.11g, c= 2.36 J/g °C, initial temperature= 63.52 °C, final temperature=?

Hence; (m×c×∆T)tin = -(m×c×∆T) ethylene glycol

10.04 × 0.213 × (T - 14.77) = - {24.11 × 2.36 × (T - 63.52)}

2.139 (T - 14.77) = - {56.899 (T - 63.52)}

2.139T - 31.59 = -56.899T + 3614.225

2.139T + 56.899T = 31.59 + 3614.225

59.038T = 3645.815

T = 3645.815/59.038

T = 61.75 °C

The final temperature of tin and ethylene glycol is 61.75 °C

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Answers

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Answers

A neutral iron atom (Fe)

Mn-1 (a manganese that has gained one electron)

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Explanation:

The atomic number of an atom is equal to the number of protonsAn atom is neutral, it has an equal number of electrons and protons.Element with atomic number 26 is Iron, Fe.A neutral atom of iron has an equal number of protons and electrons.Cobalt has an atomic number of 27.A neutral atom of cobalt has an equal number of protons and electrons.Cobalt has 27 electrons and by losing one electron it will form a cobalt (I) ion with 26 electrons.The cobalt (I) ion has 26 electrons, [tex]Co^+[/tex].Nickel has an atomic number of 28.A neutral atom of nickel has an equal number of protons and electrons.Nickel has 28 electrons and by losing two electrons it will form a nickel(II) ion with 26 electrons.The nickel (II) ion has 26 electrons,[tex]Ni^{2+}[/tex].

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Learn more about ions here:

brainly.com/question/238050?referrer=searchResults

brainly.com/question/491497?referrer=searchResults

equatinal by elimination melha
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Answers

Answer:

x = 3 and y= 2

Explanation:

Given equations:

           8x - 3y  = 18  - ---- (I)

           5x + 6y = 27 -------(II)

Solve this problem by elimination;

  In the elimination method, we simply find a common term that can make one of the variables in the two equation the same. Then we either add or subtract to remove the variable.

 Mulitply equation (i) by 5 to give equation III

 Mulitply equation (II) by 8 to give equation IV

     5(8x - 3y) = 5(18) ------- III

     8(5x + 6y) = 8(27) ------- IV

   40x - 15y = 90------- III

   40x + 48y = 216  ------- IV

Subtract  equation III and IV;

        -15y - 48y = 90 - 216

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                y = 2

Solve for x;

      40x - 15y = 90;

       40x - 15(2) = 90

         40x - 30 = 90

           40x = 90 + 30

              40x = 120

                 x = 3

Based on the article "Will the real atomic model please stand up?," describe what Dalton's theory states about a molecule of water. Dalton's theory about compounds tells us that all water molecules have different kinds of atoms, two hydrogen atoms for every one oxygen atom.

Answers

Answer:

Follows are the solution to this question:

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The characterization with water molecules would be that light waves are made up of 2 different types of atoms (2 hydrogen and 1 oxygen atoms), as per the Dalton theory. There are many multiple times as many atoms of hydrogen as oxygen atoms in each water molecules. For every two hydrogen atoms, all water molecules have one oxygen atom.

Answer:

Sample Response: Dalton’s theory about compounds tells us that all water molecules have different kinds of atoms, two hydrogen atoms for every one oxygen atom.

Explanation:

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