The statements (A) both toy cars will acquire equal but opposite momenta and (C) the massive toy car will acquire least speed are true.
The statement "both toy cars will acquire equal but opposite momenta" is true. This is because momentum is always conserved in a system, and in this case, the initial momentum of the system is zero. When the spring is released, the two toy cars will move in opposite directions, but because they have different masses, they will have different speeds. Therefore, their momenta will be equal but opposite in direction.
The statement "both toy cars will acquire equal kinetic energies" is false. This is because kinetic energy is not conserved in this system, and the two toy cars will have different kinetic energies due to their different masses and speeds.
The statement "the massive toy car will acquire the least speed" is true. This is because the massive toy car has greater inertia than the smaller toy car, meaning it requires more force to move at the same speed. Therefore, it will accelerate more slowly and reach a lower maximum speed than the smaller toy car.
The statement "the smaller toy car will experience an acceleration of the greatest magnitude" is false. This is because acceleration is dependent on both the force applied and the mass of the object. While the smaller toy car may experience a greater force than the larger toy car, it also has less mass, so the acceleration of the two cars will be the same.
Overall, the true statements are A and C, and the false statements are B and D.
The Question was Incomplete, Find the full content below :
Two toy cars with different masses originally at rest are pushed apart by an ideal spring and released. Which of the following statements (s) are TRUE?
(A) both toy cars will acquire equal but opposite momenta
(B) both toy cars will acquire equal kinetic energies
(C) the massive toy car will acquire least speed
(D) the smaller toy car will experience an acceleration of the greatest magnitude
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I need some help with this question
The speed of the ball when it leaves the gun is approximately 17.66 m/s.
Steps
To determine the speed of the ball when it leaves the gun, we can use the principle of conservation of energy. At the moment when the trigger is pulled, the spring has a potential energy equal to:
U = (1/2) k x²
where k is the spring constant and x is the amount by which the spring is compressed from its unstretched length. Using the given values, we have:
U = (1/2) (20 N/m) (0.0125 m)² = 1.5625 mJ
When the spring is released, this potential energy is converted into kinetic energy of the ball, as well as work done against friction. The work done against friction is equal to:
W = f_friction x
where f_friction is the frictional force between the ball and the barrel, and x is the distance that the ball moves along the barrel. Using the given values, we have:
W = (0.02 kg) (9.81 m/s²) (0.20) (0.05 m) = 0.01962 J
The kinetic energy of the ball is equal to the difference between the potential energy of the spring and the work done against friction:
K = U - W = 1.5625 mJ - 0.01962 J = 1.5429 J
The speed of the ball when it leaves the gun is equal to the:
v = sqrt(2K/m)
where m is the mass of the ball. Using the given value of 20 g, we have:
m = 0.02 kg
Substituting the values and evaluating the expression, we get:
v = sqrt(2(1.5429 J)/(0.02 kg)) = 17.66 m/s
Therefore, the speed of the ball when it leaves the gun is approximately 17.66 m/s.
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A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the bottom, and the car’s mass is 1,000 kg What is the power output of the car?
Answer:
the power output of the car is 29.43 kW (rounded to two decimal places).
Explanation:
To find the power output of the car, we need to use the formula:
power = work / time
where work is the change in potential energy of the car as it climbs the hill, which can be calculated using the formula:
work = force x distance
where force is the force required to lift the car against gravity, which is given by:
force = mass x gravity
where mass is the mass of the car, and gravity is the acceleration due to gravity (9.81 m/s^2).
So, the force required to lift the car against gravity is:
force = 1000 kg x 9.81 m/s^2 = 9810 N
The distance the car travels up the hill is 30 m.
Therefore, the work done by the car is:
work = force x distance = 9810 N x 30 m = 294300 J
The time taken by the car to climb the hill is 10 s.
Therefore, the power output of the car is:
power = work / time = 294300 J / 10 s = 29430 W
Three loads are applied attached at B and D. Neglecting the weight of the beam, determine the range of values of Q for which neither cable becomes slack when P = 0. as shown to a light beam supported by cables 7.5 kN Q P С E А В 1.5 m- 0.75 m 0.5 m 0.75 m Fig. P4.9
When[tex]P = 0, Q[/tex]must be in the range between [tex]4.3 kN and 12.9 kN[/tex] to prevent either cable from becoming slack.
We may examine the forces operating on the beam to find the range of values for Q. The sum of the vertical forces must be zero when [tex]P = 0,[/tex]which indicates that the beam is in equilibrium. Our result is the equation:
[tex]Q + 7.5 - 3 - 4 = 0[/tex]
When Q is solved for, we obtain [tex]Q = 0.5 kN to 12.9 kN.[/tex] To prevent either wire from going slack, we must also ensure that both cables are under positive stress. We can accomplish this by searching for the extreme values of Q in each cable's tensions.
[tex]Q = 0.5 kN[/tex]results in a positive 7.5 kN tension in cable AB. However, cable DE's tension is negative[tex](-2.5 kN)[/tex], indicating that cable DE is under tension. is loose.
[tex]Q = 12.9 kN[/tex] results in a positive [tex]3.4 kN[/tex] tension in cable DE. Cable AB, however, has negative tension [tex](-5.4 kN),[/tex] indicating that it is slack.
The range of Q values that satisfy the requirement that neither cable sags when [tex]P = 0 is 4.3 kN to 12.9 kN.[/tex]
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125cm³ of a gas was collected at 15 °C and 755 mm of mercury pressure. Calculate the volume of the gas that will be collected at standard temperature and pressure
Answer:
119,2 см³
Explanation:
по формуле Клопейрона (P1×V1):T1=(P2×V2):T2
если из этой формулы найти V2, ответ будет равен примерно на 119,2 см³
Henry knocked a book off a bookshelf. The book fell to the ground. So did the gravitational energy for that increase, decrease, or stay the same?
Answer:
Explanation:
As the book fell to the ground, its potential energy decreased, and its kinetic energy increased. The total energy (potential energy + kinetic energy) of the book remained constant as per the Law of Conservation of Energy. Therefore, the gravitational potential energy of the book decreased, and the kinetic energy increased, resulting in a transfer of energy from potential to kinetic energy. Therefore, the gravitational energy decreased.
can you please help me ASAP
Answers :-
Atoms contain equal number of protons and electrons so they are neutral.An atoms loses or gains electron to form a species called ions .Cations have positive charge ions , which are formed by loss of electrons . For example Na loses one electron to become Na+ . On the anions are negatively charged species formed by gain of electrons . For example, Cl gains one electron to become Cl- .Ions are formed by loss or gain of electrons. Loss of electrons leads to the formation of cation, whereas gain of electrons leads to the formation of anion .Ions are charged species. They form ionic compounds which have high melting point , also they are insulators .A) Lithium has 1 electron in outer shell so it is relatively easier for lithium to lose one electron rather than gaining 7 electron to complete octet so Lithium forms a cation by losing one electron from its valence shell . B) The charge on its ion will be plus one .C) The ion will be named lithium ion .D) It is represented by symbol [tex]Li^+[/tex]The blanks for question 7 is as follows:-
1st row : Charge of the ion = +3
2nd row : Chemical symbol = I-
3rd row : Name of ion = Magnesium ion and type of ion = cation .
4th row : Chemical symbol = K+ , charge of the ion = +1 and type of ion = cation .
5th row : Name of ion = Nitride ion , charge of the ion = -3 , type of ion = anion .
and we are done!
A tsunami generated off the coast of Chile in 1990 traveled nearly 6500 miles to the coast of Honolulu in 17 hours. Determine the speed in mi/hr and m/s. If the averagewidth of such waves was 22 m, what was the average frequency of such adevastating tsunami? (Given: 1.0 m/s = 2.24 mi/hr)
Answer:
Explanation:
To find the speed of the tsunami:
Speed = Distance / Time
Converting the distance from miles to meters and the time from hours to seconds:
Distance = 6500 miles × 1609.34 m/mile = 10,460,210 m
Time = 17 hours × 3600 s/hour = 61,200 s
Speed = 10,460,210 m / 61,200 s ≈ 171 m/s
To convert the speed to miles per hour:
Speed = 171 m/s × 2.24 mi/hr / 1 m/s ≈ 383 mi/hr
So the speed of the tsunami is approximately 171 m/s or 383 mi/hr.
To find the average frequency:
Wave speed = frequency × wavelength
The wavelength is twice the width of the wave:
Wavelength = 2 × 22 m = 44 m
Frequency = wave speed / wavelength
Frequency = 171 m/s / 44 m ≈ 3.9 Hz
So the average frequency of the tsunami is approximately 3.9 Hz.
based on the information in the passage, which of these substances would be most likely to provoke a response similar to the barium dance
The substance that would be most likely to provoke a response similar to the barium dance is c. lead.
What is barium dance?Barium dance is used to describe the movements of the body that can occur when a person is exposed to a high level of barium. Barium is a heavy metal that can be toxic in large amounts, and exposure can occur through ingestion, inhalation, or skin contact.
Other heavy metals such as lead, mercury, can also cause similar symptoms when a person is exposed to high levels. Additionally, exposure to certain chemicals such as pesticides, solvents, and industrial pollutants can also cause neurological symptoms similar to those seen in barium.
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When a person is exposed to high quantities of other heavy metals like lead, mercury, and cadmium, comparable symptoms can also be experienced. Furthermore, neurological symptoms resembling those of barium can also be brought on by exposure to specific substances including insecticides, solvents, and industrial pollutants.
It's critical to remember that any potential exposure to these drugs needs to be taken seriously, and if you think you may have been exposed, you should get medical help right once.
based on the information in the passage, which of these substances would be most likely to provoke a response similar to the barium dance
a. oxygen
b. nitrogen
c. lead
d. sulphur
Use the work energy theorem to rank the final kinetic energy of a ball based on the initial kinetic energy Ki, the magnitude of a constant force F on the ball, the displacement of the ball, d and the angle, theta between the displacement of the ball and the net force on the ball. Rank from greatest kinetic energy (1) to least kinetic energy (4).
a) Ki=150J F=10N d=15m theta=90 degrees
b) Ki=300J F=200N d=1.5m theta=180 degrees
c) Ki=200J F=25N d=4m theta= 0 degrees
d) Ki=450J F=15N d=30m theta=150 degrees
Explanation:
hope its help thank you
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A little boy slides a disc on the floor without tumbling and with an initial velocity of 2.5m/s. If the coefficient of kinetic friction between the disc and the floor is 0.25, determine horizontal distance the disc travels on the floor before coming to rest.
Explanation:
Ff = mg ( .25)
KE = 1/2 m (2.5)^2
Work of friction mg (.25) X (d) must equal the KE for the disc to stop
mg(.25)(d) = 1/2 m ( 2.5)^2 <=== Divide both sides by 'm'
g (.25)(d) = 1/2 ( 2.5)^2
9.81 (.25) d = 1/2 ( 2.5)^2
d = 1.27 m
moving water can be used as an energy source. select all the characteristics of this energy source that apply.
The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.
The following are the characteristics of moving water as an energy source:
It is a renewable energy source. It is a clean energy source. It is available in many different forms. It is the least expensive energy source to generate.Water is an excellent resource for producing electricity since it is clean, renewable, and is available in many different forms. When water moves, it has the potential to generate energy, which can be harnessed in several ways to produce electricity. As a result, moving water is an excellent source of renewable energy, as it is available in many different forms and can be used in a variety of ways.The above-listed characteristics apply to moving water as an energy source. Thus, moving water can be used as an energy source.
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Which option below lists the grades of metamorphism that might be encountered moving west to east from Ohio to the crystalline core of the Appalachians?
low grade, then intermediate grade, then high grade
The sequence of grades of metamorphism that may be encountered moving west to east from Ohio to the crystalline core of the Appalachians is: low grade, then intermediate grade, then high grade.
Metamorphism is the process by which a rock is changed by heat and pressure. When rocks are subjected to increased heat, pressure, and/or chemically active fluids, they undergo metamorphism.
Metamorphic rocks are formed as a result of this process. During metamorphism, the mineral composition and texture of a pre-existing rock are altered.
To summarize, the sequence of grades of metamorphism that may be encountered moving west to east from Ohio to the crystalline core of the Appalachians is low grade, intermediate grade, and then high grade.
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A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?
Answer:
Explanation:
We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.
Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.
When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.
The change in the man's center of gravity is therefore:
Δh = h_final - h_initial
= L - L/2
= 79 cm - 39.5 cm
= 39.5 cm
Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.
determine a formula for velocity, period, and total energy of a hydrogen-like atom of atomic number z
The velocity, period, and total energy of a hydrogen-like atom with atomic number z can be calculated with the following formulas.
Velocity = 2*z²/(z²+1)
Period = 4π²/(z²*(z²+1))
Total Energy = -z²/2
The formula for velocity, period, and total energy of a hydrogen-like atom of atomic number z is given as follows: Velocity: v = Zc/n ... (1)Period: T = 2πa/v ... (2)
Total energy: E = -me^4z^2/8εo^2h^2n^2 ... (3)Where ,v is the velocity of the atom is the principal quantum number T is the period of the atom a is the radius of the orbit E is the total energy of the atom me is the mass of the electronεo is the permittivity of free space h is Planck's constant c is the speed of light.
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For which of the following types of electromagnetic radiation will diffraction most likely occur as the wave passes through a classroom doorway? A) X-rays, because of their high energy. B) Visible light, because that type of electromagnetic radiation is most abundant. C) Radio waves, because of their wavelength. D) Diffraction will occur equally for all electromagnetic waves.
Option C, Because of the wavelength of radio waves and other forms of electromagnetic radiation, diffraction is most likely to occur as the wave travels through a classroom doorway.
Diffraction is the bending of waves around barriers or through apertures that are equivalent to or smaller than the wavelength of the wave.
Because radio waves have longer wavelengths than visible light and X-rays, they are more likely to diffract while passing through a similar-sized aperture, such as a classroom doorway.
Because X-rays have considerably shorter wavelengths and visible light has wavelengths in between, diffraction is less likely to occur in this scenario for these forms of electromagnetic energy. As a result, option C is the right answer.
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FILL IN THE BLANK _____ is a type of measurement error that results in systematically over- or under-measuring the value of a concept.
Systematic error is a type of measurement error that results in systematically over- or under-measuring the value of a concept.
A systematic error is a type of measurement error that results in systematic over- or under-measuring the value of a concept.
A systematic error is one that happens consistently and is caused by a flaw in the measurement system or equipment. It is often caused by calibration problems, instrument drift, or a problem with the environment in which the measurement is taken.
This error can be rectified by improving the measurement system or equipment.Therefore, the correct option is the one which states that the systematic error is a type of measurement error that results in systematically over- or under-measuring the value of a concept.
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TRUE OR FALSE when a laser beam goes from glass out into air it will deviate such that it is further away from the surface normal.
Correct, this is due to the fact that glass has a higher refractive index than air.
What happens when a laser enters a glass surface?We are aware that laser light travels in a straight line, but it bends when it passes through a glass slab. Refraction of light describes the way a laser beam bends as it passes through transparent media.
What transpires to the light beam when it travels from the air to the glass?Light slows down when it enters a material with a higher refractive index, such as glass from air. When facing the straight line, the light sways. When light penetrates a material with a lower refractive index, it moves more quickly.
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A pilot in an air Niugini travelling at 400km/h north sees an airlines aeroplane directly in front of her travelling south at 300 km/h. What is the speed of the airlines aeroplane relative to the pilot in the air Niugini aeroplane?
To find:-
The relative velocity.Answer:-
We are here given that two aeroplanes are travelling in opposite directions to each other that is North and South .
Speed to pilot traveling towards north is ,
[tex]\implies v_N = 400\ km/hr \\[/tex]
Speed of pilot traveling towards south is ,
[tex]\implies v_S = 300\ km/hr \\[/tex]
Since they are traveling opposite directions the relative speed will be the sum of their speeds that is ,
[tex]\implies v_{relative} = 300km/hr + 400 km/hr \\[/tex]
[tex]\implies \underline{\underline{ v_{relative}= 700km/hr}} \\[/tex]
Hence the relative speed is 700km/hr .
and we are done!
problem 1
A train starts at rest, accelerates with constant acceleration a for 5minutes,then travels at constant speed for another 5minutes,and the decelerates with a.suppose it travels a distance of 10km in all find a
problem 2
A ball is dropped from a height of 10m.At the same time, another ball is thrown vertically upwards at an initial speed of 10m/sec.How high above the ground will the two balls collide
problem 3
find the resultant of the two velocity vectors and also, find the angle that the resultant makes with the vector
The constant acceleration of the train is 50/9 m/s².
The two balls will collide at a height of approximately 10.204 meters above the ground.
How to calculate the valueUsing the kinematic equations of motion, we have:
distance = initial velocity * time + 1/2 * acceleration * time^2
For the first phase of acceleration, the initial velocity is zero, the time is 5 minutes = 300 seconds, and the distance traveled is unknown. So we have:
d1 = 0 + 1/2 * a * (300)^2
For the second phase of constant speed, the initial velocity is v, the time is 5 minutes = 300 seconds, and the distance traveled is also unknown. So we have:
d2 = v * 300
For the third phase of deceleration, the initial velocity is v, the time is also 5 minutes = 300 seconds, and the distance traveled is again unknown. So we have:
d3 = v * 300 + 1/2 * (-a) * (300)^2
The total distance traveled is the sum of these three distances:
distance = d1 + d2 + d3 = 1/2 * a * (300)^2 + v * 600 - 1/2 * a * (300)^2 = v * 600
Since the total distance traveled is given as 10 km = 10000 m, we have:
v * 600 = 10000
Solving for v, we get:
v = 10000/600 = 50/3 m/s
Now we can use the second equation above to find a:
d2 = v * 300 = (50/3) * 300 = 5000 m
Therefore, the constant acceleration of the train is:
a = 2 * (5000 - 1/2 * a * (300)^2) / (300)^2 = 50/9 m/s^2
The constant acceleration of the train is 50/9 m/s^2.
Problem 2: The height of the first ball dropped is given as 10m. Let's assume the height of the collision point is h meters above the ground.
Using the kinematic equation for free fall, we have:
h = 10 + 1/2 * g * t^2
where g is the acceleration due to gravity, which is approximately 9.81 m/s^2, and t is the time it takes for the second ball to reach the collision point after being thrown upwards.
The initial upward velocity of the second ball is 10 m/s, and we know that at the collision point, its velocity will be zero, since it will have reached its maximum height and will be momentarily at rest before falling back down.
Using the kinematic equation for motion with constant acceleration, we have:
0 = 10 + (-g) * t
Solving for t, we get:
t = 10/g = 10/9.81 seconds
Substituting this value of t into the first equation, we get:
h = 10 + 1/2 * 9.81 * (10/9.81)^2
Simplifying, we get:
h = 10.204 m
The two balls will collide at a height of approximately 10.204 meters above the ground.
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Two blocks of unequal mass are tied together with a massless string that does not stretch and connected via a frictionless and massless pulley. Mass one, M1, rests on a frictionless table top. Mass two, M2, is released and both blocks begin to move....
The blocks accelerate at the same rate since they are connected. What is the acceleration?
The blocks accelerate at the same charge for the reason that they're linked. The acceleration is a value between zero and g.
Acceleration is a physical concept that refers to the rate of change of an object's velocity with respect to time. When an object's velocity changes, either by speeding up or slowing down, it is said to be accelerating.
Acceleration plays an important role in many aspects of physics, from the motion of celestial bodies to the behavior of particles in a particle accelerator. The magnitude of acceleration is the rate at which an object's velocity changes, and it is measured in units of meters per second squared (m/s^2) in the International System of Units (SI). There are several factors that can cause an object to accelerate, such as a force acting on it, a change in its direction of motion, or a combination of both.
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Help please, view attachments below
Answer: exothermic, chemical bonds between oxygen atoms.
Explanation:
a. what are the physical processes by which atoms rearrange during phase transformations in the solid state (how do atoms rearrange in the solid state)?
The physical processes by which atoms rearrange during phase transformations in the solid state involve changes in the arrangement of the atoms in the lattice, which can be caused by changes in temperature, pressure, or both.
The physical processes by which atoms rearrange during phase transformations in the solid state involve changes in the arrangement of the atoms in the lattice.
This is typically done by changing the number of nearest neighbours of each atom or by introducing new lattice points in the solid structure. In some cases, atoms may even have to move from one position to another.
Common examples of phase transformations in the solid state include melting, recrystallization, and solidification.
Melting occurs when the thermal energy of the solid is increased and the atoms become mobile enough to break the bonds between them. This causes the solid to transition into a liquid phase.
Recrystallization occurs when the thermal energy of the solid is decreased, causing the atoms to return to their original positions and form a new, more ordered lattice.
Lastly, solidification is the reverse process of melting, where thermal energy is removed and the atoms return to their original positions in the lattice.
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Which of the following energy resources are replaceable through biogeochemical cycles and also provide clean energy?
a. Geothermal energy
b. Biomass energy
c. Nuclear power
d. Hydropower
Biomass energy refers to energy that is derived from organic matter, such as wood, crop residues, and even municipal solid waste. This organic matter can be replenished through biogeochemical cycles.
What is organic ?Organic products, such as fruits, vegetables, meat, and dairy, are grown or raised without the use of synthetic chemicals, fertilizers, or hormones. Organic certification is granted by regulatory bodies that ensure that the products meet strict organic standards.
In addition to its benefits for the environment and personal health, organic farming and food production also promote animal welfare and sustainable agriculture practices. However, organic products may be more expensive than conventionally grown products due to the increased cost of production and certification.
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true/false. A nuclear family includes a pair of adults, their children, and any grandparents who live in the family.
The nuclear family is considered the most essential family unit because it is the family unit with the most fundamental relationships. that's why the Given statement is False.
In a nuclear family, parents and their children live in a household. A nuclear family is a type of family structure that consists of a pair of adults and their children, but not grandparents who live in the family.
It is also called the traditional family, and it is considered to be the basic family unit.A nuclear family is a small family consisting of two parents and their children.
A nuclear family is often known as the basic family unit since it is a family structure consisting of two parents and their children. It is also considered the most prevalent family structure in many countries around the world.
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Please do help me. Nonsense answers will be reported.
An object is thrown horizontally with a speed of 30 m/s from the top of a building. Complete the table below for the indicated time interval. Use g≈ 10 m/s²)
The time that was taken for the movement of the item is observed as 3 seconds.
How do you use the equations of motion?The equations of motion describe the motion of objects in terms of their position, velocity, acceleration, and time.
For the equation;
v = u + at
This equation relates the final velocity (v) of an object to its initial velocity (u), acceleration (a), and time (t). If three of these variables are known, the equation can be rearranged to solve for the unknown variable.
We know that;
v = u - gt
We know that the object would come to rest after being thrown.
0 = 30 - 10t
-30 = - 10t
t = 3 seconds
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What type of electromagnetic wave is sent as a signal by a cell phone to the
nearest cell tower?
A. Gamma rays
B. Microwaves
C. X-rays
D Ultraviolet
Answer:B. Microwaves
Explanation:
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Constants I Periodic Table Suppose two parallel-plate capacitors have the same charge Q, but the area of capacitor 1 is A and the area of capacitor 2 is 2A
Two parallel-plate capacitors with the same charge Q but different areas (A and 2A) can be compared by looking at the capacitance. The capacitance of the second capacitor is double that of the first due to the increase in area.
Two parallel-plate capacitors with the same charge Q but different areas (A and 2A) can be compared by looking at the capacitance, which is defined as the ratio of the charge stored on the capacitor to the voltage applied across the plates. The capacitance C of a capacitor is given by the equation C=Q/V. Therefore, the capacitance of the first capacitor, C1, is C1=Q/V, and the capacitance of the second capacitor, C2, is C2=(2Q)/V. It is seen that the capacitance of the second capacitor is double that of the first. This is because the area of the second capacitor is double that of the first. Therefore, the same charge Q stored on the first capacitor is distributed over twice the area in the second capacitor, resulting in the capacitance being double. This can be mathematically expressed as C2 = 2C1. Thus, two parallel-plate capacitors with the same charge Q but different areas (A and 2A) can be compared by looking at the capacitance. The capacitance of the second capacitor is double that of the first due to the increase in area.
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diagram below shows some of the forces acting on a car of mass 800 kg.
a. State the size of the total drag force when the car is travelling at constant speed.
b. The driving force is increased to 3200 N.
i. Find the resultant force on the car at this instant.
ii. Write down, in words, the equation connecting mass, force and acceleration.
iii. Calculate the initial acceleration of the car.
c. Explain why the car will eventually reach a new higher constant speed.
Answer:
Without a diagram or image, it's difficult to answer this question accurately. However, I can provide a general answer based on the information given.
a. When a car is traveling at constant speed, the net force acting on the car is zero. Therefore, the total drag force acting on the car must be equal in magnitude to the driving force provided by the engine.
b. i. The resultant force on the car when the driving force is increased to 3200 N can be calculated as follows:
Resultant force = Driving force - Drag force
Since the drag force is still equal in magnitude to the driving force (as the car is still moving at a constant speed), the resultant force is zero.
Resultant force = 3200 N - 3200 N = 0 N
ii. The equation connecting mass, force, and acceleration is:
Force = mass x acceleration
This can be rearranged to find acceleration:
Acceleration = Force / mass
iii. To calculate the initial acceleration of the car, we can use the equation above:
Acceleration = 3200 N / 800 kg = 4 m/s²
c. The car will eventually reach a new, higher constant speed because the driving force provided by the engine is now greater than the drag force acting on the car. This means there is a net force acting on the car, causing it to accelerate. As the car accelerates, its speed increases and the drag force acting on the car increases as well. Eventually, the drag force will once again be equal in magnitude to the driving force, and the car will reach a new, higher constant speed where the net force acting on the car is once again zero.
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b) what is the probability that an average of 22 shields will absorb more than 17.1 j/kg? use 4 decimal places.
The probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
where X is the random variable representing the energy absorbed per kilogram of the shield.
To calculate this probability, we need to know the distribution of X.
From the given information, we know that X follows a normal distribution with mean μ = 16.8 J/kg and standard deviation σ = 0.6 J/kg.
Thus, we can standardize X as follows:
Z = (X - μ)/σZ ~ N(0, 1)
P(X > 17.1) = P((X - μ)/σ > (17.1 - μ)/σ)
= P(Z > (17.1 - 16.8)/0.6)
= P(Z > 0.5)
Using a standard normal table, we can find the probability that Z > 0.5 to be 0.3085 (rounded to 4 decimal places).
Therefore, the probability that an average of 22 shields will absorb more than 17.1 J/kg is approximately 0.3085.
for such more question on probability
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Determine the linear velocity of blood in the aorta with a radis of 1.5 cm, if the duration of systole is 0.25 s, the stroke volume is 60 ml.
Answer:
The linear velocity of blood in the aorta can be calculated using the equation:
v = Q / A
where v is the linear velocity, Q is the volume flow rate, and A is the cross-sectional area of the vessel.
The volume flow rate Q can be calculated using the equation:
Q = SV / t
where SV is the stroke volume and t is the duration of systole.
The cross-sectional area of the aorta can be calculated using the equation:
A = πr^2
where r is the radius of the aorta.
Given that the radius of the aorta is 1.5 cm, the stroke volume is 60 ml, and the duration of systole is 0.25 s, we can calculate the volume flow rate Q:
Q = SV / t = 60 ml / 0.25 s = 240 ml/s
Converting the units of Q to cm^3/s:
Q = 240 ml/s × 1 cm^3/1 ml = 240 cm^3/s
We can then calculate the cross-sectional area of the aorta:
A = πr^2 = π × (1.5 cm)^2 = 7.07 cm^2
Finally, we can calculate the linear velocity of blood in the aorta:
v = Q / A = 240 cm^3/s / 7.07 cm^2 = 33.9 cm/s
Therefore, the linear velocity of blood in the aorta is 33.9 cm/s.