Two teams of nine members each engage in a tug of war. Each of the first team's members has an average mass of 64 kg and exerts an average force of 1350 N horizontally. Each of the second team's members has an average mass of 69 kg and exerts an average force of 1367 N horizontally. (a) What is the acceleration (in m/s2 in the direction the heavy team is pulling) of the two teams

Answer:

Wavelength = 1.04 meters

Explanation:

Given the following data;

Speed = 509m/s

Frequency = 491Hz

To find the wavelength;

Wavelength = speed/frequency

Wavelength = 509/491

Wavelength = 1.04 meters

Therefore, the guitar player should shorten the length of the string to 1.04 meters.

Answer: 0.52

Explanation:

Answer:

ω = 7.27 x 10⁻⁵ rad/s

v = 467.99 m/s

Explanation:

First, we will find the angular velocity of the person:

[tex]Angular\ Velocity = \omega = \frac{Angular\ Distance}{Time}[/tex]

Angular distance covered = 1 rotation = 2π radians

Time = (24 h)(3600 s/ 1 h) = 86400 s

Therefore,

[tex]\omega = \frac{2\pi\ rad}{86400\ s}[/tex]

ω = 7.27 x 10⁻⁵ rad/s

Now, for the linear velocity:

[tex]v = r\omega[/tex]

where,

v = linear velocity = ?

r = radius of earth = (4000 miles)(1609.34 m/1 mile) = 6437360 m

Therefore,

[tex]v = (6437360\ m)(7.27\ x\ 10^{-5}\ rad/s)[/tex]

v = 467.99 m/s

Answer:

R1=3.333 Ohms

R2=10 Ohms

R3=16.666 Ohms

Explanation:

30 total

30=R1+R2R3

30=1(x):3(x):5(x)

x=3.3333

R1=3.333 Ohms

R2=10 Ohms

R3=16.666 Ohms

Answer:

Troposphere, stratosphere, mesosphere and thermosphere. The next region is the exosphere, but that region is 500+ km from the Earth's surface.

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Atmosphere.

The four layers of Atmosphere starting from bottom are as follows:

1.) Troposphere - The troposphere is the lowest layer of our atmosphere. Starting at ground level, it extends upward to about 10 km (6.2 miles or about 33,000 feet) above sea level.

2.) Stratosphere - The next layer up is called the stratosphere. The stratosphere extends from the top of the troposphere to about 50 km (31 miles) above the ground.

3.) Mesosphere - Above the stratosphere is the mesosphere. It extends upward to a height of about 85 km (53 miles) above our planet. Most meteors burn up in the mesosphere.

4.) Thermosphere - The layer of very rare air above the mesosphere is called the thermosphere. High-energy X-rays and UV radiation from the Sun are absorbed in the thermosphere, raising its temperature to hundreds or at times thousands of degrees.

Answer:

towards the north.

Explanation:

Answer:

Sunlight is the greatest source of UV radiation. Man-made ultraviolet sources include several types of UV lamps, arc welding, and mercury vapour lamps.

Explanation:

Answer:

In classical mechanics, impulse (symbolized by J or Imp) is the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity. ... A resultant force causes acceleration and a change in the velocity of the body for as long as it acts.

Answer:

It is expensive to generate conditions for a fast reaction

Explanation:

Answer:

2 A

Explanation:

From the question,

Q = it..................... Equation 1

Where Q = Quantity of charge, i = cudrrent, t = time.

Make i the subject of the equation

i = Q/t.......................... Equation 2

Given: Q = 20 C, t = 10 seconds.

Substitute these values into equation equation 2

i = 20/10

i = 2 A.

Hence the current is 2A

Given values are:

As we know,

→ [tex]Current = \frac{Charge}{Time}[/tex]

or,

→ [tex]i = \frac{Q}{t}[/tex]

BY substituting the values, we get

      [tex]= \frac{20}{10}[/tex]

      [tex]= 2 \ A[/tex]

Thus the answer above is right.

Learn more about current here:

https://brainly.com/question/19668907

During the "waxing" phases, the two weeks immediately following the New Moon.

New Moon ==> waxing crescent ==> First Quarter ==> waxing gibbous ==> Full Moon

The phase of the moon decides the moon's visibility. The sequence of phases does the moon's visibility increases is; the waxing crescent, first quarter, waxing gibbous, full Moon.

The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.

Only the side of the moon facing the sun can reflect this light and seem bright. The opposite side appears black. this is a full moon.

We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.

Following are the sequence of phases does the moon's visibility increase is;

1. Waxing crescent

2. First Quarter

3. Waxing gibbous

4. Full Moon

The phase of the moon decides the moon's visibility. Hence the visibility changes with the change in the phase of the moon.

To learn more about the moon's phase refer to the link;

https://brainly.com/question/2285324

Answer:

9m/s^2

Explanation:

F=ma

a=F/m

a=63/7

a=9m/s^2

Answer:

608kg

Explanation:

Formula : Kinetic energy

½ ×mass x speed²

47500

½×12.5²

=608 Kg

Answer:

Low pressure systems typically arrive with storms and clouds. Air motion is usually upwards, as heated are is less dense and more buoyant than cooler air. A high pressure system is typically cooler than its counter-part, and skies are usually clear. Low pressure systems carry more water vapor due to rising hot air cooling and condensing.

Answer:

 Δt = 5.85 s

Explanation:

For this exercise let's use Faraday's Law

           emf = [tex]- \frac{d \phi}{dt}[/tex] -  d fi / dt

           [tex]\phi[/tex] = B. A

           \phi = B A cos θ

The bold are vectors. It indicates that the area of the body is A = 0.046 m², the magnetic field B = 1.4 T, also iindicate that the normal to the area is parallel to the field, therefore the angle θ = 0 and cos 0 =1.

suppose a linear change of the magnetic field

            emf = - A [tex]\frac{B_f - B_o}{ \Delta t}[/tex]

             Dt = - A  [tex]\frac{B_f - B_o}{emf}[/tex]

the final field before a fault is zero

let's calculate

            Δt = - 0.046 (0- 1.4) / 0.011

            Δt = 5.85 s

We are to calculate the acceleration.

Answer:

-9.8 m/s²

Explanation:

Since the egg is in a free fall, it means that the force due to gravity will be equal to the normal force.

Now,

Force due to gravity: F_g = mg

Normal force; F_n = ma

Thus;

mg = ma

m will cancel out to get

g = a

Since it is a free fall motion, then gravity is negative;

-g = a

g has a constant value of 9.8 m/s². Thus;

a = -9.8 m/s²

Answer: yes

Explanation:

Answer: A flower pot falling

Explanation:

The car on the curve (its direction is changing) and the falling flower pot (its speed is changing) are both undergoing acceleration.

You Forgot To Add The Pictures

Answer:

coefficient of viscosity of 8.4 poison denotes that the tangential frictional force acting per unit area when divided by the velocity gradient as a result of streamline flow conditions gives 8.4.

Explanation:

Viscosity is defined as the extent to which a fluid can resist flow when a force is applied to it.

Now, coefficient of viscosity is the term in which viscosity is calculated. It is basically the tangential frictional force acting per unit area which is divided by the velocity gradient as a result of streamline flow conditions.

Thus, coefficient of viscosity of 8.4 poison denotes that the tangential frictional force acting per unit area when divided by the velocity gradient as a result of streamline flow conditions gives 8.4.

Answer:

Bowling ball

Explanation:

Answer:

D because the line isn't changing which means constant speed it's going at the same rate so yea it's D

Answer:

D.

Hope that helps!?

Explanation:

Answer:

Materials that can lose or gain electrons in this way are called triboelectric, according to Northwestern University. One common example of this would be shuffling your feet across carpet, particularly in low humidity which makes the air less conductive and increases the effect.

Explanation:

Hope that helps :)

Answer:

86.7 m/s²

Explanation:

Given that

Radius of the circle, r = 0.3 m

Height of the plane above the ground, = 1 m

Distance at which the ball lands, d = 2.3 m

To solve this question, we would use one of the principles of projectile motion.

v = ut + 1/2at²

-1 = 0 + 1/2 * -9.8 * t²

-1 = -4.9 t²

t² = 1/4.9

t² = 0.204

t = √0.204

t = 0.45 s

Then again, it's constant horizontal speed is

v(x) = x/t

v(x) = 2.3 / 0.45

v(x) = 5.1 m/s

And finally, the centripetal acceleration is gotten using the formula

a = v²/r

a = 5.1² / 0.3

a = 26.01 / 0.3

a = 86.7 m/s²