Two teams need to raise $100 each for their end-of-the-year field trips. Team A wants to sell popcorn at the Spring Fling Carnival, and Team B wants to sell cotton candy. It costs $15 to rent a popcorn machine and it costs $25 to rent a cotton candy maker. The cost of additional supplies for the popcorn is $0.05 per bag. The additional cost for the cotton candy is $0.10 per stick. Team A will sell the bags of popcorn for $0.50 each. Team B will sell the cotton candy for $0.75 per stick.
What is the least number of items Team A will need to sell to avoid losing money?

Answers

Answer 1

Team A will need to sell at least 256 bags of popcorn to avoid losing money.

What is a linear equation?

When an algebraic equation is graphed, it always results in a straight line since each term in a linear equation has an exponent of 1. For this reason, it is referred to as a "linear equation."

There are both one-variable and two-variable linear equations.

Given total amount to be raised by each team is $100,

Team A wants to sell popcorn,

rent of popcorn machine = $15

total cost to be earned for team B = $100 + $15 = $115

let the number of candies sold be x

cost used in popcorn bag = $0.05 per stick

cost used in x popcorn bag  = $0.05x

the selling price of each popcorn bag  = $0.50

the selling price of x popcorn bag  = $0.50x

total gain = $0.50x - $0.05x

total gain = $0.45x

minimum number of popcorn bags to be sold for no loss

$0.45x = $115

x = 115/0.45

x = 255.55

x = 256

Hence for no loss, at least 256 popcorn bags are to be sold.

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Related Questions

plis help
Is (1, 10) a solution to this system of equations?
y = 9x + 1
y = x + 8

yes or no? ​

Answers

The solution to the system of equations is x = 7/8 and y = 71/8

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equations be represented as A and B

Now , substituting the values in the equation , we get

y = 9x + 1   be equation (1)

y = x + 8   be equation (2)

On simplifying the equations , we get

x + 8 = 9x + 1

Subtracting x on both sides of the equation , we get

8x + 1 = 8

Subtracting 1 on both sides of the equation , we get

8x = 7

Divide by 8 on both sides of the equation , we get

x = 7/8

Substitute the value of x in the equation (2) , we get

y = 7/8 + 8

y = 71/8

Hence , the equations are solved and the solution is ( 7/8 , 71/8 )

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How many ounces per pound ?

Answers

There are 16oz per pound.

16 ounces is equivalent to 1 pound. In other words, 16 ounces per pound.

What is one pound?

A weight measurement unit: The weight of one pound is roughly equal to 454 grams. A kilogram is equivalent to about 2.2 pounds. One pound contains 16 ounces.

One pound is equal to 0.4535 kilograms and is referred to as an imperial unit of mass or weight measurement.

16 ounces = 1 pound

1 pound (lb) equals 16 ounces (oz)

Pounds To Ounces Conversion Table

1 pound = 16 ounces

2 pounds = 32 ounces

3 pounds = 48 ounces

5 pounds = 80 ounces

6 pounds = 96 ounces

7 pounds = 112 ounces

8 pounds = 128 ounces

9 pounds = 144 ounces

10 pounds = 160 ounces

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find the solution of the initial value problem y'' 2y' 5y = 12e^-t cos(2t), y(0) = 10, y'(0) = 0

Answers

The solution to the initial value problem is:y(t) = (10 - (12/7))e^(t) cos(2t) + (12/7)e^(-t) cos(2t).

The characteristic equation of this linear second order ordinary differential equation is:

m^2 - 2m + 5 = 0

The roots of this characteristic equation are m = 1 ± 2i, which means the general solution to the homogeneous equation is:

y(t) = c1e^(t) cos(2t) + c2e^(t) sin(2t)

To find the particular solution, we can use the method of undetermined coefficients and guess that yp(t) = Ae^(-t) cos(2t) + Be^(-t) sin(2t).

Substituting this into the differential equation, we get:

2Ae^(-t) cos(2t) - 2Ae^(-t) sin(2t) + 5Ae^(-t) cos(2t) - 5Be^(-t) sin(2t) = 12e^(-t) cos(2t)

Comparing coefficients, we have:

2A - 2A + 5A = 12

7A = 12

A = 12/7

-5B = 0

B = 0

So the particular solution is:

yp(t) = (12/7)e^(-t) cos(2t)

The general solution to the non-homogeneous equation is then:

y(t) = c1e^(t) cos(2t) + c2e^(t) sin(2t) + (12/7)e^(-t) cos(2t)

Using the initial conditions, we can find the values of c1 and c2:

y(0) = 10 = c1 + (12/7)

c1 = 10 - (12/7)

y'(0) = 0 = c2e^(0) sin(0)

c2 = 0

Therefore, the solution to the initial value problem is: y(t) = (10 - (12/7))e^(t) cos(2t) + (12/7)e^(-t) cos(2t)

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solve the equation for x

Answers

Answer:

x = 70 , x = 24

Step-by-step explanation:

the measure of a secant- tangent and a tangent- tangent angle is half the difference of the measures of the intercepted arcs.

9

24 = [tex]\frac{1}{2}[/tex] (118 - x) ← multiply both sides by 2 to clear the fraction

48 = 118 - x ( subtract 118 from both sides )

- 70 = - x ( multiply both sides by - 1 ) , then

x = 70

10

61 = [tex]\frac{1}{2}[/tex] (10x + 1 - (5x - 1) ) ← multiply both sides by 2 to clear the fraction

122 = 10x + 1 - 5x + 1

122 = 5x + 2 ( subtract 2 from both sides )

120 = 5x ( divide both sides by 5 )

24 = x

POINTS AND BRAINLIEST

Answers

Answer:

On Monday, the baker makes 36 blueberry muffins, so the total number of muffins she makes that day is 36/0.4 = 90.

On Tuesday, the baker makes a total of 60 muffins, so the number of blueberry muffins she makes that day is 60*0.4 = 24.

suppose you ask a friend to randomly choose an integer between 1 and 10, inclusive. what is the probability that the number will be more than 7 or odd? (enter your probability as a fraction.)

Answers

The probability that the number will be more than 7 or odd is 7/10.

The number more than 7 or odd is 1, 3, 5, 7, 8, 9, 10

So probability of 7 number is,

P(A) = number of favorable outcomes of an event /  total number of events occurring in a sample

P(A) = 7/10

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about the likelihood of an event happening, or how likely it is. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty. For pupils in Class 10, probability is a crucial subject because it teaches all the fundamental ideas of the subject. One is the probability of every event in a sample space.

The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to determine the mean. When all of the values are organized in ascending order, the Median is the median value of the given data. While the number in the list that is repeated a maximum of times is the mode.

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What i the area of ΔABC given a = 12 in, b = 24 in, and m∠C = 26°? Round the anwer to three decimal place. 63. 125 in2
93. 156 in2
109. 808 in2
129. 426 in2

Answers

Answer: 63.125

Step-by-step explanation: I got it correct ;)

The temperature was -3, 0, 2, -1, and -3 on five consecutive days. What was the average temperature for those five days?

Answers

Answer:

-1 degrees

Step-by-step explanation:

The average = sum of all values/# of values = sum of all temperatures/# of days=

(-3+0+2-1-3)/5=  -1

Someone answer this

Answers

Answer:

I believe the answer is b??

who did more one girls did 42 push ups in 6 mins a other 24 in 3 mins

Answers

Answer:

The girl who completed 42 push-ups in 6 minutes did more push-ups than the girl who completed 24 push-ups in 3 minutes.

Step-by-step explanation:

The girl who did 24 in 3 mins did more because her unit rate in push-ups is 8 in a min and the girl who did 42 in 6 mins did 7 in a min

the marked price of an article is 2080. After allowing d% discount and levying (d-2)% VAT, the cost of the article becomes Rs. 1997.84. Find the discount amount and VAT amount

Answers

The vat rate is 13%

What is  vat rate?

Vat rate is a consumption tax assessed on the value added in each production stage of a good or service.

Given:

MP = 2080

Discount = d%

VAT = (d-2)%

Cost = 1997.84

Apply discount:

2080 - d% = 2080*(1 - 0.01d)

Add VAT:

2080*(1 - 0.01d) + (d - 2)%2080*(1 - 0.01d) * (1 + (d -2)/100)2080*(1 - 0.01d) * (0.98 + 0.01d) = 1997.84(1 - 0.01d)(0.98 + 0.01d) = 1997.84/20800.98 + 0.01d - 0.0098d - 0.0001d² = 0.9605- 0.0001d² + 0.0002d + 0.98- 0.9605 = 00.0001d²- 0.0002d - 0.0195 = 0

d² - 2d + 195 = 0

Solving the quadratic equation we get:

d = 15

Then

VAT rate = 15 - 2 = 13%

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Last year, 80 students were in after-school activities. This year, 160 students participated in after-school activities.
What is the percent of change from last year to this year?

Answers

Answer:200%

Step-by-step explanation: A different way of saying that a number has doubled is by saying it has increased by 200%.

Let vector a = a1i + a2j + a3k vector b = b1i + b2j + b3k and vector c = c1i + c2j + c3k be three non-zero vectors such that vector c is a unit vector perpendicular to both the vectors a and vector b. If the angle between vector a and vector b is π/6 then |a1 a2 a3 b1 b2 b3 c1 c2 c3|2 is equal toa 0b 1

Answers

The correct option is C) [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

Vectors, in Math's, are objects which have both, magnitude and direction. Magnitude defines the size of the vector.

It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.

According to the given conditions,

[tex]c1^{2}+c2^{2} +c3^{2} = 1, a.c =0, b.c=0[/tex]

and [tex]cos\frac{π}{6} = \frac{\sqrt{3} }{2} =\frac{a1b1+a2b2+a3c3}{\sqrt{a1^{2} +a2^{2} +a3^{2} } \sqrt{x=b1^{2} +b2^{2} +b3^{2} } }[/tex]

thus, a1c1+a2c2+a3c3=0 , b1c1+b2c2=b3c3=0

and [tex]\frac{\sqrt{3} (a1^{2}+a2^{2} +a3^{2} )^{1/2} (b1^{2}+b2^{2} +b3^{2} )^{1/2} }{2}[/tex] = a1b1+a2b2+a3b3

Now,

[tex]\left[\begin{array}{ccc}a1&b1&c1\\a2&b2&c2\\a3&b3&c3\end{array}\right]^{2}[/tex]

= [tex]\left[\begin{array}{ccc}a1&a2&a3\\b1&b2&b3\\c1&c2&c3\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}a1&b1&c1\\a2&b2&c2\\a3&b3&c3\end{array}\right][/tex]

= [tex](a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} ) - (a1b1+a2b2+a3b3)^{2}[/tex]

= [tex](a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} ) -\frac{3}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

= [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

Therefore, The correct option is C) [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

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Rylan earns $200 for working 16 hours this week.
How much does he earn per hour?

Answers

Answer:

Rylan earns $12.50 per hour

Step-by-step explanation:

1. First start by writing the given its always easier when you're able to see the problem.

   $200 = 16 hrs

   $  x    = 1 hr

2. Next divide

        [tex]\frac{200}{16}[/tex] = 12.50

A watch which was bought for R250, was sold for R375. What profit made on the sale? atima has 56 roses, 48 irises and 16 freesias. She wants to cre ouquets using all the flowers. Calculate the highest number ouquets she can make without having any flowers left over Fatima paid R240 for her flowers and sold the bouquets for​

Answers

Solving the provided question, we can say that the highest number bouquets she can make without having any flowers left is calculated by Highest Common Factor so, HCF of 56, 48 and 16 is 8

What is Highest Common Factor?

In mathematics, the highest positive integer that divides the corresponding integers is known as the greatest common divisor of two or more non-zero integers. The greatest common factor (HCF) of two or more numbers is the sum of those two or more numbers. As a result, it is frequently referred to as the largest common divisor (GCF). Take the prime factors of the two (or more) integers and determine the shared prime factors to determine the greatest common divisor. Following that, the sum of common prime factors is the greatest common divisor. A specified number divided by the biggest integer results in the greatest common divisor.

the highest number bouquets she can make without having any flowers left is calculated by Highest Common Factor so, HCF of 56, 48 and 16 is 8

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Does someone mind helping me with this problem? Thank you!

Answers

Answer:

17.6lbs

Step-by-step explanation:

If 1kg equals 2.2 lbs, therefore multiply the number of pounds per kg by 8:

2.2lbs * 8 = [17.6lbs]

illustrate the net force f1 f2 as the geometric addition of the two force vectors. (b) compute the net force, the vector sum of the force vectors.

Answers

The magnitude of the net force is 149.33 N.

a) To illustrate the net force F1 + F2 as a geometric addition of the two force vectors, we can use the tail-to-tip method to add the vectors head-to-tail and then connect the tail of the first vector to the tip of the second vector to form the net force vector.

b) To compute the net force as the vector sum of the two force vectors, we can use the components of the two vectors to find the components of the net force. Using the trigonometric relationship between the angle and the components of a force vector, the x and y components of the force vectors can be calculated as follows:

F1x = F1 * cos(30) = 86.6025 N

F1y = F1 * sin(30) = 50 N

F2x = F2 * cos(45) = 35.3553 N

F2y = F2 * sin(45) = 35.3553 N

The x and y components of the net force are found by adding the corresponding components of the individual force vectors:

Fnetx = F1x + F2x = 86.6025 N + 35.3553 N = 122 N

Fnety = F1y + F2y = 50 N + 35.3553 N = 85.3553 N

c) To compute the magnitude of the net force, we use the Pythagorean theorem to find the magnitude from the components:

Fnet = √(Fnetx² + Fnety²) = √(122² + 85.3553²) = 149.33 N

So, the magnitude of the net force is 149.33 N.

Complete Question

Two forces are applied to an object, with magnitudes and directions shown in the image below:

(a) Illustrate the net form F1 + F2 as the geometric addition of the two force vectors.

(b) Compute the net force, the vector sum of the force vectors.

(c) Compute the magnitude of the net force. Include N (newton) for units of force.

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Find the mean of tese numbers 2,9,10,6,8

Answers

Answer:324234

Step-by-step explanation:

Answer:

The mean of the data set is 7.

2 + 9 + 10 + 6 + 8

= 35

35 ÷ 5

= 7

Step-by-step explanation:

You're welcome

For circular motion on a circle of radius r, linear speed equals angular speed divided by r. (T/F)

Answers

For circular motion on a circle of radius r, linear speed equals angular speed divided by r. This statement is false.

What is angular speed?

The definition of angular speed is the rate at which angular displacement changes, and it is written as follows -

ω = θ/t

where θ is the angular displacement, t is the time and ω is the angular speed.

The statement says that for circular motion on a circle of radius r, linear speed equals angular speed divided by r.

Consider that an object moves around a circle of radius r at a constant speed v.

If s is the distance travelled in time t around the circle then linear speed v is defined as v = s/t.

Also if θ is the angle swept out by this object in time t then the angular speed is defined as ω = θ/t.

Thus, there is some relationship between linear speed and angular speed -

Linear speed = v = s/t

= rθ/t = r(θ/t) = rω

where is ω measured in radians per unit time and for a circle of radius r, a central angle of radians subtends an arc whose length s is s = rθ.

Hence, notice that linear speed is equal angular speed multiplied, not divided, by r.

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Remove the outlier from Gretchen’s data set, and recalculate the mean, median, standard deviation, and interquartile range. Use the graphing tool to visualize the data.

Question
Which statements are true about Gretchen’s adjusted data set?

The data set is approximately symmetric.
The center moved closer to the center of Manuel’s data set.
The data set is skewed left.
The spread values are closer to the spread values of Manuel’s data set.
The center moved farther from the center of Manuel’s data set.
The spread values are farther from the spread values of Manuel’s data set.

Answers

The true statements bout Gretchen's adjusted data set are (1), (4), and (5).

What are statistics?

Statistics is a mathematical tool defined as the study of collecting data, analysis, understanding, representation, and organization. Statistics is described as the procedure of collecting data, classifying it, displaying that in a way that makes it easy to understand, and analyzing it even further.

It is given that:

Which statements are true about Gretchen's adjusted data set:

The options are:

The data set is approximately symmetric.

The center moved farther from the center of Manuel's data set.

The center moved closer to the center of Manuel's data set.

The spread values are closer to the spread values of Manuel's data set.

The data set is skewed left.

The spread values are farther from the spread values of Manuel's data set.

As we know,

The spread values are more similar to Manuel's data set's spread values, and the data set is roughly symmetric and tilted to the left.

The true statements are:

The data set is approximately symmetric.

The spread values are closer to the spread values of Manuel's data set.

The data set is skewed left.

Thus, the true statements bout Gretchen's adjusted data set are (1), (4), and (5).

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A restaurant charges `\$10` for each burrito and a `\$5` delivery fee. What is the total cost to have `4` burritos deliver

Answers

Answer:60

Step-by-step explanation:

10+5=15

15x4=60

4. ) Jennifer has a new sister named Chloe. Jennifer's mom, who

is a pediatrician, has been tracking Chloe's growth. Assume that

Chloe's growth rate is constant.



d. Use the information from parts(c) and (d) to write an equation representing Chloes growth rate. Let y= height in cm and x= age in months.


c. Use your equation to predict Choles height at 2 years old

Answers

The equation for Chloe's growth rate would be y = ax + b, where a is the rate of growth in cm/month and b is the height at age 0.

To predict Chloe's height at two years old, we can plug in x = 24 (representing two years, or 24 months) into the equation.

We would then get y = 24a + b,

Which is Chloe's predicted height at age two. This equation gives us a simple way to predict Chloe's height at any age, as long as we know her rate of growth and her height at age 0.

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Tyler filled up his bathtub, took a bath, and then drained the tub. The function gives the depth of the water, in inches, minutes after Tyler began to fill the bathtub.

Answers

B(0) = 0 Inches of depth are present 0 minutes after filling started, or at time = 0; depth = 0.

B(1) denotes the function one minute into the filling process.

B(9) = 11 shows that 11 inches of water are present in the container 9 minutes after the filling started.

7 minutes after the filling process began, the feature displays the water depth in inches.

A.) B(0)=0

B(0) = 0 indicates that the depth in inches at time = 0 and depth = 0 is 0 minutes after filling started.

B.) B(1) (1) B(1) denotes the function one minute into the filling process.

C.B(9)=11

B(9) = 11 shows that 11 inches of water are present in the container 9 minutes after the filling started.

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function statements are contained within the function ____.

Answers

A function statement is contained within the function block. A function block is a set of instructions within a program that defines what the function should do when it is called.

It is generally surrounded by curly braces and contains one or more lines of code.

A function statement usually contains a formula and calculation. The formula is an expression that specifies the calculation that should be performed when the function is called. The calculation is the result of the formula, which is the value that will be returned when the function is called.

For example, if we have a function that calculates the area of a circle, the formula might be A = πr^2 and the calculation would be A = 3.14 * r^2. The formula describes how the area of a circle is calculated and the calculation is the result of that formula. When the function is called, the calculation will be performed and the result will be returned.

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. using social media in a job search. according to inc, 79% of job seekers used social media in their job search in 2018. many believe this number is inflated by the proportion of 22- to 30-year-old job seekers who use social media in their job search. a survey of 22- to 30-year-old job seekers showed that 310 of the 370 respondents use social media in their job search. in addition, 275 of the 370 respondents indicated they have electronically submitted a resume to an employer. a. conduct a hypothesis test to determine if the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that use social media in their job search. use a 5 .05. b. conduct a hypothesis test to determine if the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer. using a 5 .05, what is your conclusion?

Answers

In case of (a) Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

a. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who use social media in their job search, we need to set up the null and alternative hypotheses:

H0: p = 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is equal to the proportion of the population that use social media in their job search)

Ha: p > 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is greater than the proportion of the population that use social media in their job search)

Where p is the true proportion of 22- to 30-year-old job seekers who use social media.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as: z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 310/370 = 0.838 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.838 - 0.79) / sqrt(0.79 * (1 - 0.79) / 370) = 3.41

Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search.

b. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume, we need to set up the null and alternative hypotheses:

H0: p = 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is equal to 70%)

Ha: p > 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is greater than 70%)

Where p is the true proportion of 22- to 30-year-old job seekers who have electronically submitted a resume.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as:

z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 275/370 = 0.743 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.743 - 0.70) / sqrt(0.70 * (1 - 0.70) / 370) = 2.01

Since 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

Therefore, In case of (a) Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

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In case of (a) Since 3.41 > 1.64485,  job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485,  the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

a. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who use social media in their job search, we need to set up the null and alternative hypotheses:

H0: p = 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is equal to the proportion of the population that use social media in their job search)

Ha: p > 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is greater than the proportion of the population that use social media in their job search)

Where p is the true proportion of 22- to 30-year-old job seekers who use social media.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as: z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 310/370 = 0.838 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.838 - 0.79) / sqrt(0.79 * (1 - 0.79) / 370) = 3.41

Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search.

b. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume, we need to set up the null and alternative hypotheses:

H0: p = 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is equal to 70%)

Ha: p > 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is greater than 70%)

Where p is the true proportion of 22- to 30-year-old job seekers who have electronically submitted a resume.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as:

z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 275/370 = 0.743 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.743 - 0.70) / sqrt(0.70 * (1 - 0.70) / 370) = 2.01

Since 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

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flight 202's arrival time is normally distributed with a mean arrival time of 4:30 p.m. and a standard deviation of 15 minutes. find the probability that a randomly chosen arrival time is within the given time period

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The required probability is 0.953.

We know that the mean μ is:

μ = 4:30 p.m.

The standard deviation  is:

σ = 0:15 minutes

The Z-score is: Z = (x-μ)/σ

We seek to find probability P(4:00 p.m. < x < 5:00 p.m.)

The Z-score is:

Z = (x-μ)/σ = 4:00 - 4:30/0:15 = -2

The score of Z =-2 means that 4:00 p.m. is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35% and

Z = (x-μ)/σ = 5:00 - 4:30/0:15 = 2

The score of Z =2 means that 11:00 p.m. is 2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%.

∴ P(4:00 p.m. < x < 5:00 p.m.) = 100% - 2.35% - 2.35%

= 95.3% = 0.953

Thus, the required probability is 0.953.

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The required probability is 0.953.

We know that the mean μ is:

μ = 4:30 p.m.

The standard deviation  is:

σ = 0:15 minutes

The Z-score is: Z = (x-μ)/σ

We seek to find probability P(4:00 p.m. < x < 5:00 p.m.)

The Z-score is:

Z = (x-μ)/σ = 4:00 - 4:30/0:15 = -2

The score of Z =-2 means that 4:00 p.m. is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35% and

Z = (x-μ)/σ = 5:00 - 4:30/0:15 = 2

The score of Z =2 means that 11:00 p.m. is 2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%.

∴ P(4:00 p.m. < x < 5:00 p.m.) = 100% - 2.35% - 2.35%

= 95.3% = 0.953

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when you are looking at a figure, when can you say on average? why?

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When talking about a figure, you can say "on average" when you are discussing a measure of central tendencies, such as the mean, median, or mode.

This is because these measures represent the "average" point in the data set. For example, if you are looking at a figure that consists of the average monthly temperatures for a given region, the mean would be the average temperature (on average) for that region.

Similarly, if you are looking at a figure that consists of the average daily prices of a certain stock, the mean would be the average daily price (on average) for that stock. In either case, the mean is the "average" point in the data set.

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parallel, perpendicular,
or neither.
2. AB formed by (3, 7) and (-6, 1)
CD formed by (-6, -5) and (0, -1)

Answers

Answer: ez, the answer is Parallel

Step-by-step explanation:

because ab and cd are parallel lines
AB is formed by (3,7) and (-6, 1)
CD is formed by (-6,-5) and (0,-1)
testing the two lines are parallel or perpendicular or neither, is done by determining their gradients
Triangle AB = Gradient of AB = Triangle Y over triangle X = 1-7 over -6-3 = -6 over -9 = 2/3
Triangle CD = Gradient of Triangle CD = Triangle Y over Triangle X = -1 - -5 over 0 - -6 = 1 + 5 over 0 + 6 = 4 over 6 = 2/3

So the two lines AB and CD  have the same gradient and thus the two lines are PARALLEL to each other.

For the subspace below, (a) find a basis for the subspace, and (b) state the dimension. P-2q 9p +2r -2q +4r -6p 12r p, q, rin R

Answers

a) basis is  [ p , q , r . r ]

b) the dimension. P-2q 9p +2r -2q +4r -6p 12r p, q, rin R is 3 for subspace

since the two given equation are in three variable and constants

2q -r= p -----(1)

r= q -s -----(2)

p= q +2r -----(3)

From (2):

r +s= q (+s on both sides)

s= q -r -----(4) (-r on both sides)

Substitute. (3) into (1):

2q -r= q +2r

2q -q= 2r +r

q= 3r -----(5)

Substitute (5) into (4):

s= 3r -r

s= 2r (proved)

hence subspace is [ p , q , r . r ]

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Two sides of the triangle abc has side ab = 22 cm and side ac = 8 cm. Compute the probable perimeter of the triangle.

Answers

The perimeter of the triangle is (30+x) cm

What is perimeter of a triangle?

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon.

Perimeter is the distance around the edge of a shape.

To find the perimeter of a triangle , we add all the sides together.

Two sides are 22 cm and 8cm

Represent the other sides of the triangle by x

therefore the perimeter will be calculated as:

22+8+x

P = (30+x)cm

therefore the perimeter of the triangle is( 30+x)cm for any value of x

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