Two stores sell a certain product. Store A has 45% of the sales, 3% of which are of defective items, and store B has 55% of the sales, 4% of which are of defective items. The difference in defective rates is due to different levels of pre-sale checking of the product. A person receives one of this product as a gift. What is the probability it is defective

Answers

Answer 1

Answer:

[tex]Probability = 0.0355[/tex]

Step-by-step explanation:

Given

Stot A:

[tex]Sales = 45\%[/tex]

Defective = 3%

Store B

[tex]Sales = 55\%[/tex]

Defective = 4%

Required

Determine the probability a product received is defective.

First, we calculate the probability that the defective product is from store A

[tex]Probability = P(Sales) * P(Defective)[/tex]

[tex]P_A = 45\% * 3\%[/tex]

Convert to decimals

[tex]P_A= 0.45 * 0.03[/tex]

[tex]P_A= 0.0135[/tex]  

Next, we calculate the probability that the defective product is from store B

[tex]P_B= 55\% * 4\%[/tex]

[tex]P_B= 0.55 * 0.04[/tex]

[tex]P_B= 0.022[/tex]

The product may come from either stores.

So, the probability of having a defective product is:

[tex]Probability = P_A + P_B[/tex]

[tex]Probability = 0.0135 + 0.022[/tex]

[tex]Probability = 0.0355[/tex]

Answer 2

Answer:

Probability of 0.0355

Step-by-step explanation:


Related Questions

A shop sells apple juice in cartons of two sizes. A 500 ml carton costs $1.30.
a) Work out the cost of 250 ml of this apple juice. A 750 ml carton costs $1.86.
b) Work out the cost of 250 ml of this apple juice.
c) Which carton is better value for money?

Answers

Hi can u pls explain the questions a and b r similar thx

Suppose that in one week in November in St. Louis, the temperature dropped by an average of 4 degrees every day. The temperature at the beginning of the week was 65 degrees. Write an equation that relates the temperature (t) to the number of days that have passed (d). helpppp

Answers

Answer:

t = 65 - 4d

Step-by-step explanation:

Linear Modeling

The temperature in St. Louis dropped by 4 degrees every day in one week.

When d days have passed, the temperature will have dropped by 4d degrees.

We know the temperature t at the beginning of the week was 65 degrees.

Thus, when d days pass, the linear model for the temperature t is:

t = 65 - 4d

Which of the following MUST be true for two negative number?

Answers

Hey, um is there a picture we can look at?

I need help need it done in 20 minutes will give 20 points each

Answers

Answer:

Lets start by isolating for one variable In this case I chose y -7x-2y=14 -2y=14+7x y=-7 -3.5x (1)

Next plug the y into the second equation to solve for x

6x+6(-7 -3.5x) =186x+(-42)+ (-21x) =18 6x-21x= 60 -15x=60x=-4

Now we know x and we can plug into the original equation (1)

x= -4 y= -7 - 3.5× -4 y= 7

Rate brainlist and drop a follow for future help

Answer:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    6*x-6*y-(18)=0  

STEP

1

:

Pulling out like terms

1.1     Pull out like factors :

  6x - 6y - 18  =   6 • (x - y - 3)  

Equation at the end of step

1

:

STEP

2

:

Equations which are never true:

2.1      Solve :    6   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Equation of a Straight Line

2.2     Solve   x-y-3  = 0

Tiger recognizes that we have here an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

Step-by-step explanation:

x= 1 y= 1

hope am right if i am, pls brainliest

The sprit club is making school jackets to sell. The cost c (in dollars) for silkscreening supplies and jackets is c=20x+270, where x is the number of jackets. The club sells each jacket for $35. Write an equation for revenue R in terms of the number of jackets. How many jackets must the club sell to break even?

Answers

Answer:

The club must sell 18 jackets to break even

Step-by-step explanation:

Given:

C = 20x + 270

Where,

x = number of jackets

Equation for revenue R in terms of the number of jackets

Revenue = price × quantity

Price of the jacket = $35

Quantity of the jacket = x

Revenue = price × quantity

= 35 * x

R = 35x

Break even point is the point at which cost is equal to revenue, that is, no gain; no loss.

Cost = revenue

20x + 270 = 35x

270 = 35x - 20x

270 = 15x

x = 270 / 15

= 18

x = 18 jackets

The club must sell 18 jackets to break even

Answer:

torture

Step-by-step explanation:

I was just working on a prblem like this and I hate it

Triangle ABC has vertices A (2, 4), B(0, -4),
and C(-2,-2). It is dilated about the origin
to form triangle A'B'C' with vertices
A' (12, 24), B (0, -24), and C (-12, -12).
What is the scale factor of the dilation?

Answers

Answer:

k=6

Step-by-step explanation:

To find the scale factor of a triangle, all you have to do is divide the image from the post image

point A

12/2=6

24/4=6

The scale factor is 6

Harper is a salesperson who sells computers at an electronics store. She makes a base pay amount of $100 per day regardless of sales and she earns a commission of 1% of the dollar amount of sales that she makes. Write an equation for P, in terms of x, representing Harper’s total pay on a day which she sells x dollars worth of computers

Answers

Answer:

100x-p*1%

Step-by-step explanation:

Please help me thank you so much I appreciate it

Answers

Answer:

12

Step-by-step explanation:

To find perimeter, add the lengths of each side. 5 + 4 + 3 = 12

Answer:

12

Step-by-step explanation:

5+4+3

find the scale factor of the dilation ​

Answers

Answer:

k=1/2

It is a reduction

Step-by-step explanation:

To the scale factor, you simply divide the length of the post image by the image.

10/20=k

1/2=k

Which expressions represent the distance between-1 and 4? Choose ALL that apply. 14 - 11 | 4 – (-1) HH34 4342 0 3 5 |-1 - 4 |-1 - (-4)​

Answers

|-12| - |-5| = x ==> We start at -12 on the number line. Since we cannot have a negative distance, we must take the absolute value of that number to properly represent the distance from 0 to -12. We only want to know the distance from -5 to -12, so we must get rid of the distance from 0 to -5 by subtracting it from the distance from -12. Again, we must take the absolute value of -5 to represent the distance from 0 to -5.

|-12| - |-5| = 12 - 5 = 7 ==> The absolute value of -12 and -5 are 12 and 5 respectively. Therefore, 12 minus 5 equals 7. The distance from -5 to -12 on the number line is 7.

Indicate the answer choice that best completes the statement or answers the question.
✓ The table shows the cost of long distance calls as a function of the number of minutes used. Is the cost a linear or nonlinear function of the
number of minutes used? Explain.
Number of Minutes 40 180 120 160 1200
Cost (S)
14.00 8.00
16.00 20.00
12.00

Answers

Answer:

The correct answer is:

Option C: Linear; as x increases by 40 minutes and y increases by $4 each time. The rate of change is constant, so this function is linear.

Step-by-step explanation:

Given is the table,

The input is x and output is y.

We can see from the table that the x-values are increasing 40 minutes after each input and the output is increasing by equal amount i.e. $4.

The rate of change remains the same.

Hence,

The correct answer is:

Option C: Linear; as x increases by 40 minutes and y increases by $4 each time. The rate of change is constant, so this function is linear.

Landon bought a tray of plants for $8.15. There were 16 plants in the tray. If Landon only bought 1 plant, about how much would it have cost?

Answers

They are about 50 cents per plant!!

help me answer these questions please 15, 19 and 20 please​

Answers

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Hope watches a movie Friday night that was two and one-half hours long. On Saturday, she watched a documentary half as long as Friday’s movie. How long was the documentary?

Answers

Answer:

1 hour and 15 minutes thats how long the documentary was

Movie friday night was 2 hours and 30 minutes long.

The documentary was half as long as Friday's movie.

So it will be: [tex]\frac{2 hours .and. 30 minutes}{2} = 1 hour.and .15 minutes[/tex]

Then solve each problen
Situation 1: A pair of shoes is on sale for 80% of the original price.
The sale price is $60. What was the original price?
food drive

Answers

Answer:

75

a(0.80)=60

a=60/0.80

a=75

A survey of nonprofit organizations showed that online fundraising has increased in the past year. Based on a random sample of 133 nonprofits, the mean one-time gift donation resulting from email outreach in the past year was $85. Assume that the sample standard deviation is $9. Identify the correct 95% confidence interval estimate for the population mean one-time gift donation.

Answers

Answer:

The answer is below

Step-by-step explanation:

Given that:

Confidence interval (C) = 95%, mean (μ) = 85, standard deviation (σ) = 9, sample size (n) = 133

α = 1 - C = 1 - 0.95 = 0.05

α/2 = 0.025

The z score of α/2 (0.025) is the same as the z score of 0.475 (0.5 - 0.025) which is equal to 1.96.

The margin of error (E) is given as:

[tex]E=Z_\frac{\alpha}{2}*\frac{\sigma}{\sqrt{n} } \\\\E=1.96*\frac{9}{\sqrt{133} } \\\\E=1.53[/tex]

The confidence interval = (μ ± E) = (85 ±  1.53) = (83.47, 86.53)

The confidence interval is between 83.47 and 86.53.

Rewrite the equation 8r+62 - 7 = 2 in standard form and Identify a, b, and c



Answers

Answer:

a = 0

b = 8

c = 53

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Algebra I

Standard Form: ax² + bx + c = 0

Step-by-step explanation:

Step 1: Define

8r + 62 - 7 = 2

Step 2: Rewrite

Add:                                        8r + 55 = 2Subtract 2 on both sides:      8r + 53 = 0

Step 3: Identify Variables

a = 0

b = 8

c = 53

A equation of a line in slope intercept form with the given slope and Y-intercept slope: -4, Y-intercept : -9

Answers

Answer:

y = -4x - 9

Step-by-step explanation:

Use slope intercept form, y = mx + b, where m is the slope and b is the y intercept.

Since we are already given the slope and y intercept, we just have to plug them into the equation to find the equation:

y = mx + b

y = -4x - 9

So, y = -4x - 9 is the equation of the line in slope intercept form

What is 82.403 rounded to the nearest whole number​

Answers

Answer: 82

Step-by-step explanation:

Aaliyah is 3 times as old as AJ. 4 years ago, Aaliyah was 7 times as old as AJ. How old is Aaliyah now?

Answers

Answer:

Aaliyah is 18years old now

Step-by-step explanation:

let AJ's age=x

Aaliyah's age=3x

Four years ago,

AJ's age=x-4

Aaliyah's age=3x-4

3x-4=7(x-4)

3x-4=7x-28

3x-7x=-28+4

-4x=-24

x=6

Aaliyah's present age=3x=3×6=18

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question: mona borrowed $6000 for college expenses. After 2 1/2 years she will have paid $750 in interest. What is the interest rate? ______

Answers

Answer:

5250

i hope this is right.

Answer:

5250

Step-by-step explanation:

person on my top got it ^

What postulate/theorem can be used to prove the following triangles congruent?

Answers

Answer: SAS

Step-by-step explanation:

It is given that the two sides are congruent.

The angle between the two congruent sides is also congruent because of the vertical angle theorem.

Since a side, angle, and side are congruent, the theorem is SAS.

Answer this ASAP please. If you can’t see then zoom in. Giving out 25 points and Brainliest to the one who answers correctly. There is a PT2 to this, so you’ll have another chance to answer if you want.
Thank you in advance.

Answers

Answer:

Put 2 feet down for both of them and add 3 extra feet for nate

Step-by-step explanation:

Answer:

add 3 extra feet for Nate and put 2 feet from the both of them

Step-by-step explanation:

Rob did 15 push-ups on Monday, but on Tuesday he did 3 more than on Monday. What was the percent change?​

Answers

Answer:

20%

Step-by-step explanation:

Simplify using the laws of exponets.

Answers

Answer:

2*5

Step-by-step explanation:

when youre dividing with powers you have to subtract them so 2*5-2*4=2*1. When the power is in brackets you multiply the whole power. So 2*1 x 5 = 2*5.

A store is having a sale. All items for sale are discounted 15%. If the regular price of a bedspread is $45, what is the sale price?

(I NEED THIS QUICK)

Answers

Answer:

$38.25

Step-by-step explanation:

45 × 0.15 = 6.75

45 - 6.75 = 38.25

The sale price of the item will be $38.25

What is the percentage?

The percentage is defined as representing any number with respect to 100. It is denoted by the sign %. The percentage stands for "out of 100." Imagine any measurement or object being divided into 100 equal bits.

Given that a store is having a sale. All items for sale are discounted by 15%. the regular price of a bedspread is $45,

The discounted price will be calculated as:-

45 × 0.15 = 6.75

45 - 6.75 = $38.25


Therefore, the sale price of the item will be $38.25

To know more about percentages follow

https://brainly.com/question/24304697

#SPJ2

I will give you brainliest if you answer this right.

Answers

The answers are in order:
1/10
1/6
2/3
3/5

Kate Sanders, a researcher in the department of biology at PFW University, studied the effect of agricultural contaminants on the stream fish population in northeastern Indiana (April 2012). Specially designed traps collected samples of fish at each of four stream locations. A research question was: did the differences in agricultural contaminants found at the four locations alter the proportion of the fish population by gender

Answers

Full question attached

Answer and explanation:

Null hypothesis : all population proportions are equal, p1=p2=p3=p4

Alternative hypothesis : Not all population proportions are equal

To find our p-value using chi Square method, we first find expected frequencies from observed frequencies above

Expected Frequencies:

Gender A. B. C. D

Male. 46.81 46.81 44.21 43.17

Female 43.19. 43.19 40.79 39.83

Total = 348

chi Square for table = (observed frequency - expected frequency)²/expected frequency

Gender. A. B. C. D

Male. 0.10 0.17 0.52 0.40

Female 0.11 0.18 0.56 0.44

x²= 2.49

Degrees of freedom(df)= k – 1 = (4 – 1) = 3

Using the chi Square table with degree of freedom = 3, 2 and x²= 2.49 shows, the p –value = 0.4771 therefore we do not reject null hypothesis since p value is greater than significance level 0.08

We do not reject the null hypothesis

b. There is no evidence of differences in proportion

A sailboat is 175 feet from the base of a lighthouse. If the angle of elevation to the top of the lighthouse is 23°, find the height of the lighthouse, to the nearest hundredth of a foot.

Answers

9514 1404 393

Answer:

  74.28 ft

Step-by-step explanation:

The tangent of the angle is the ratio of opposite side (lighthouse height) to adjacent side (distance from lighthouse).

  tan(23°) = height/(175 ft)

  height = (175 ft)·tan(23°) ≈ 74.28 ft

Integrate the following problem:
[tex]\int {e^{-x} \cdot cos(2x)} \, dx[/tex]

P.S:
Have fun Lauren (and possibly Kelvy)!

Answers

Answer:

[tex]\displaystyle \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex]

Step-by-step explanation:

The integration by parts formula is: [tex]\displaystyle \int udv = uv - \int vdu[/tex]

Let's find u, du, dv, and v for [tex]\displaystyle \int e^-^x \cdot cos2x \ dx[/tex] .

[tex]u=e^-^x[/tex][tex]du=-e^-^x dx[/tex] [tex]dv=cos2x \ dx[/tex] [tex]v= \frac{sin2x}{2}[/tex]

Plug these values into the IBP formula:

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = e^-^x \cdot \frac{sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex] [tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex]

Now let's evaluate the integral [tex]\displaystyle \int \frac{sin2x}{2} \cdot -e^-^x dx[/tex].

Let's find u, du, dv, and v for this integral:

[tex]u=-e^-^x[/tex] [tex]du=e^-^x dx[/tex] [tex]dv=\frac{sin2x}{2} dx[/tex] [tex]v=\frac{-cos2x}{4}[/tex]  

Plug these values into the IBP formula:

[tex]\displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} - \int \frac{-cos2x}{4}\cdot e^-^x dx[/tex]

Factor 1/4 out of the integral and we are left with the exact same integral from the question.

[tex]\displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx[/tex]

Let's substitute this back into the first IBP equation.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ][/tex]  

Simplify inside the brackets.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ \frac{e^-^x \cdot cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ][/tex]

Distribute the negative sign into the parentheses.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4} - \frac{1}{4} \int cos2x \cdot e^-^x dx[/tex]

Add the like term to the left side.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx + \frac{1}{4} \int cos2x \cdot e^-^x dx= \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4}[/tex]  [tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \frac{e^-^x \cdot cos2x}{4}[/tex]  

Make the fractions have common denominators.

[tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x}{4} - \frac{e^-^x \cdot cos2x}{4}[/tex]

Simplify this equation.

[tex]\displaystyle \frac{5}{4} \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4}[/tex]

Multiply the right side by the reciprocal of 5/4.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4} \cdot \frac{4}{5}[/tex]

The 4's cancel out and we are left with:

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{5}[/tex]

Factor [tex]e^-^x[/tex] out of the numerator.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x(2 \cdot sin2x-cos2x)}{5}[/tex]

Simplify this by using exponential properties.

[tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x}[/tex]

The final answer is [tex]\displaystyle \int e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x} + C[/tex].

Answer:

[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]

Step-by-step explanation:

We would like to integrate the following integral:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx[/tex]

Since this is a product of two functions, we can consider using Integration by Parts given by:

[tex]\displaystyle \int u\, dv =uv-\int v\, du[/tex]

So, let’s choose our u and dv. We can choose u base on the following guidelines: LIATE; or, logarithmic, inverse trig., algebraic, trigonometric, and exponential.

Since trigonometric comes before exponential, we will let:

[tex]u=\cos(2x)\text{ and } dv=e^{-x}\, dx[/tex]

By finding the differential of the left and integrating the right, we acquire:

[tex]du=-2\sin(2x)\text{ and } v=-e^{-x}[/tex]

So, our integral becomes:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=(\cos(2x))(-e^{-x})-\int (-e^{-x})(-2\sin(2x))\, dx[/tex]

Simplify:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\int e^{-x}\sin(2x)\, dx[/tex]

Since we ended up with another integral of a product of two functions, we can apply integration by parts again. Using the above guidelines, we get that:

[tex]u=\sin(2x)\text{ and } dv=e^{-x}\, dx[/tex]

By finding the differential of the left and integrating the right, we acquire:

[tex]du=2\cos(2x)\, dx\text{ and } v=-e^{-x}[/tex]

This yields:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[(\sin(2x))(-e^{-x})-\int (-e^{-x})(2\sin(2x))\, dx\Big][/tex]

Simplify:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)-2\Big[-e^{-x}\sin(2x)+2\int e^{-x}\cos(2x)\, dx\Big][/tex]

We can distribute:

[tex]\displaystyle \int e^{-x}\cdot \cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)-4\int e^{-x}\cos(2x)\, dx[/tex]

The integral on the right is the same as our original integral. So, we can isolate it:

[tex]\displaystyle \Big(\int e^{-x}\cos(2x)\, dx\Big)+4\Big(\int e^{-x}\cos(2x)\, dx)\Big)=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]

Combine like integrals:

[tex]\displaystyle 5 \int e^{-x}\cos(2x)\, dx=-e^{-x}\cos(2x)+2e^{-x}\sin(2x)[/tex]

We can factor out an e⁻ˣ from the right:

[tex]\displaystyle 5\int e^{-x}\cos(2x)\, dx=e^{-x}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]

Dividing both sides by 5 yields:

[tex]\displaystyle \int e^{-x}\cos(2x)\, dx=\frac{e^{-x}}{5}\Big(-\cos(2x)+2\sin(2x)\Big)[/tex]

Rewrite. We of course also need the constant of integration. Therefore, our final answer is:

[tex]\displaystyle\int e^{-x}\cos(2x)\, dx=\frac{2\sin(2x)-\cos(2x)}{5e^x}+C[/tex]

Other Questions
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