The area of the isosceles triangle having two sides 12.5 cm and another 20cm is 75cm².
What is a triangle?A triangle is a three-sided closed-plane figure formed by joining three noncolinear points. Based on the side property triangles are of three types they are Equilateral triangle, Scalene triangle, and Isosceles triangle.
We know that an isosceles triangle has two sides having the same length and the third one is different.
We also know that the area of an isosceles triangle is (1/2)×b×√(a² - b²/4),
where b is the value of the third side and a is the value of two similar sides.
Therefore, The area of the isosceles triangle having side lengths of two similar sides is 12.5 cm and the third side is 20 cm is,
= (1/2)×20×√((12.5)²- (20)²/4) cm²,
= 10×√(156.25 - 100) cm².
= 10×√(56.25) cm².
= 10×7.5 cm².
= 75 cm².
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Lenny paid $13 for 4 1/3 pounds of apples.
How many pounds of apples can he buy
for $29?
Answer: 9 2/3
Step-by-step explanation:
you take 29 and divide by 13 to get 2.23076923077 and you then take that times the 4 1/3 to get 9 2/3
Answer:
Step-by-step explanation:
13(X-4 1/3)=29
13X-56.3=29
+56.3 = +56.3
13X=85.3
X=6.56
Can someone please help me? :(
Answer:32 17/18
Step-by-step explanation:
33 + (1/9)(x)
x = -1/2
33 + (1/9)(-1/2) =
33 + -1/18
= 32 17/18
Q14
How can I prove (a)
AE is congruent to CE.We can prove by assuming two triangle in the given diagram and by using SAS rule.
How do you find congruent triangles?If all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle then the two triangles are said to be congruent by SSS rule. In the above-given figure, AB= PQ, BC = QR and AC=PR, hence Δ ABC ≅ Δ PQR.
What is an alternate angle in a triangle?Alternate angles are angles that occur on opposite sides of the transversal line. If two parallel lines are cut by a transversal then the alternate angles are equal.The pair of angles formed on the inner side of the parallel lines but on the opposite sides of the transversal are called alternate interior angles.
Now we have
Given a triangle ABC.Where E is the midpoint of AC. We have to prove that AE is congruent to CE.
In ΔAED and ΔCED
ED=ED (∵Common side are equal)
∠AED=∠CED (∵Alternate angles)
∠A=∠C (∵Alternate angles)
By ASA rule, ΔAED≅ΔCED
By Corresponding Parts of Congruent triangles
AE=EC
Hence, AE is conruent to CE.
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You are running a concession stand at a football game. You are selling snacks and sodas. Each order of nachos costs $2 and each soda costs $1.50. At the end of the night, you made a total of $125. You sold a total of 76 nachos and sodas combined. You must report the number of nachos sold and the number of sodas sold. What equations did you use to solve this
The equations are n + s = 76 and 2n + 1.50 s = 125.
let n = number of Nachos sold
let s = number of sodas sold
Two equations are presented to us, and we can use them together to solve one variable at a time.
Eq. 1: n + s = 76
Eq. 2: 2n + 1.50 s = 125
So, s = 76 - n
Put (76 - n) for s in the second equation
2n + 1.50 (76 - n) = 125
2n + 114 - 1.50 n = 125
2n - 1.50 n + 114 = 125
0.5n + 114 = 125
0.5n = 125 - 114
0.5n = 11
n = 22
s = 76 - 22
s = 54
22 nachos sold and 54 sodas sold.
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Does a parabola have an inverse?
An inverse does not exist for a parabola.
What is a parabola?A parabola is an approximately U-shaped, mirror-symmetrical plane curve in mathematics.
It corresponds to a number of seemingly unrelated mathematical descriptions, all of which can be shown to define the same curves.
An inverse does not exist for a parabola.
One definition of a parabola includes a line and a point (the focus) (the directrix).
The directrix is not the main focus.
The locus of points in that plane that are equally spaced apart from the directrix and the focus is known as the parabola.
A right circular conical surface and a plane parallel to another plane that is tangential to the conical surface intersect to form a parabola, which is also known as a conic section.
Therefore, an inverse does not exist for a parabola.
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18. Solve for b:
3 (23-2b) + 3b = 48
A. 10
B. 13
C. 7
D. -10
Answer:
Step-by-step explanation:
3(23-2b) + 3b = 48
1. Use the distributive property and distribute the 3 before the parenthesis
3(23-2b) (make sure you read the (-) as part of the 2b so it's -2b
69 - 6b
2. 69 - 6b +3b = 48 (combine like terms...the bs: -6b + 3b)
69 -3b=48
3. 69 - 3b = 48 (subtract 69 from both sides)
-69 -69
4. -3b = -21 (divide both sides by negative three...we want the b to be +
/-3 /-3
Answer: b = 7
So, C is your answer
what is the area of the shaded part, in square meters, below?
Check the picture below.
[tex]\stackrel{\textit{\LARGE Areas}}{\stackrel{rectangle}{(4)(20)}~~ + ~~\stackrel{triangle}{\cfrac{1}{2}(\underset{b}{5})(\underset{h}{20})}}\implies 80+50\implies \text{\LARGE 130}~m^2[/tex]
Write the equation of a line that is perpendicular to y=14x - 4 and passes through the point (28, 16)
The equation of the line perpendicular to {y = 14x - 4} and passes through the point (28, 16) is y = - (1/14)x + 18.
What is the general equation of a straight line?The general equation of a straight line is -
y = mx + c
{m} - slope.
{c} - intercept along the y - axis.
Given is the equation of the line as -
y = 14x - 4
The given equation of line is -
y = 14x - 4
Slope of the line perpendicular to the given line is -
m{p} = -1/14
The equation of this line will be -
y = -(1/14)x + c
For the point (28, 16), we can write -
16 = -(1/14) x 28 + c
c = 16 + 2
c = 18
So, the equation will be -
y = - (1/14)x + 18
Therefore, the equation of the line perpendicular to {y = 14x - 4} and passes through the point (28, 16) is y = - (1/14)x + 18.
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Tamicca bought a Computer for $1200 and made 12 monthly payments of $115.
What was the finance charge that she paid? Round your answer to the nearest cent.
Answer:
Tamicca made 12 monthly payments of $115, for a total payment of 12*$115 = $<<12*115=1380>>1380.
She bought a computer for $1200, so the finance charge that she paid is $1380-$1200 = $<<1380-1200=180>>180.
Therefore, the finance charge that Tamicca paid was $180, rounded to the nearest cent.
Step-by-step explanation:
In Lewis County , there were 2 , 277 student athletes competing in spring sports in 2014 . That was 110% of the number from 2013, which was 90% of the number from the year before. How many student athletes signed up for a spring sport in 2012
In the spring of 2012, 2300 student athletes participated in a sport.
How do I calculate a percentage?The value must be divided by the entire value, and the resulting number must then be multiplied by 100 to get the percentage.
In 2014, there were 2277 student athletes participating in spring sports.
Suppose there were x contestants in 2013.
The answer was 2277, which was 110 percent more pupils competing in 2014 than in 2013. So,
[tex]$110 \%$ of $\mathrm{x}=2277$$\frac{110}{100} \times \mathrm{x}=2277$$\mathrm{x}=\frac{2277 \times 100}{110}$$\mathrm{x}=2070$[/tex]
2070 pupils therefore competed in 2013.
Let y be the student who will be vying in 2012.
Now, the number of pupils competing in 2070 was 90% that of the year 2012's.
So,
[tex]$90 \%$ of $y=2070$$$\begin{aligned}& \frac{90}{100} \times y=2070 \\& y=\frac{2070 \times 100}{90} \\& y=2300\end{aligned}$$[/tex]
As a result, 2300 students competed in the 2012 competition.
Therefore, the answer is 2300.
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Could someone please help me?
[tex]\textit{area of the rectangle}\\\\ A=Lw \begin{cases} L=length\\ w=width\\[-0.5em] \hrulefill\\ L=5\\ w=6 \end{cases}\implies A=(5)(6)\qquad \begin{cases} \textit{tripling the sides}\\[-0.5em] \hrulefill\\ L=3\cdot 5\\ w=3\cdot 6 \end{cases} \\\\\\ A=(3\cdot 5)(3\cdot 6)\implies (3\cdot 3)(5)(6)\implies 9(5)(6)\leftarrow \begin{array}{llll} \textit{new area is 9 times}\\ \textit{the old one}\\ \textit{a ratio of 9 : 1} \end{array}[/tex]
Blake uses 2 gallons of gas to drive 34.6 miles in his car. Find the rate of change.
Answer:
17.3 miles / gallon
Step-by-step explanation:
RatesRates can be represented in different forms, such as speed (meters per second) or water flow rate (liters per minute or second)
SolutionGiven information from the question,
2 gallons = 34.6 miles
1 gallon = 34.6 ÷ 2 = 17.3 miles / gallon
How do you find the 3 side of a triangle?
Answer:
by using sine rule and cosine rule.
A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed, what range of weights would 99.7% of the dogs have
With standard deviation of 2 pounds, the range of weight 99.7% of dogs have will be approximately 24–36 pounds.
How to interpret a standard deviation?The term "standard deviation" (or "σ") refers to a measurement of the data's dispersion from the mean. A low standard deviation indicates that the data are grouped around the mean, whereas a high standard deviation shows that the data are more dispersed.
We have given,
Mean weight of Eskimo dogs is μ = 30 pound
Standard deviation of Eskimo dogs is σ = 2 pound
The range of weights would 99.7% of the dogs have,
R = μ ± 3σ
R = 30 ± 3*2
R = 30 ± 6
R = (30 - 6) , (30 + 6 )
R = 24, 36
With standard deviation of 2 pounds, the range of weight 99.7% of dogs have will be approximately 24–36 pounds.
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Mattie is twice as old as Pat. Jon is twice as old as Mattie. In 4 years the sum of their ages will be 61. How old is each person?
Answer:
Let's mark Pat's age is x. Then Mattie's age is 2x and Jon's age is 4x.
So (x + 4) + (2x + 4) + (4x + 4) = 61.
7x + 12 = 61 => 7x = 49 => x = 7.
So the answer is
Pat = 7
Mattie = 14
Jon = 28
The ages of Pat, Mattie, and Jon are as follows: 7 years, 14 years & 28 years.
If we take Pat's age as = 'x' years,
so, Mattie's age will be = '2x' years.
and then, Jon would be = 2(2x)
= '4x' years.
Now, the sum of their ages after 4 years =
=> (x+4) + (2x+4) + (4x+4) = 61
=> 7x+12 = 61
=> 7x= 61-12
=> 7x= 49
=> x= 49/7
=> x = 7
Therefore, Pat's age is = 7 years.
Mattie's age is = 14 years (2×7).
Jon's age is = 28 years (4×7).
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HELP THIS IS URGENT!!!! During a sale, a store offered a 35% discount on a camera that originally sold for $750. After the sale, the discounted price of the camera was marked up by 35%. To the nearest whole number, what percent of the original price was the price after markup?
Answer:
the percentage is 62%
Step-by-step explanation:
Exercise: Use the method of mathematical induction to prove that if n is a positive integer: 1²+ 2² + 3² + ... +n² = 1/6n(n+1)(2n+1)
if n is a positive integer: 1²+ 2² + 3² + ... +n² = 1/6n(n+1)(2n+1) IS 1
What is meant by integer?An integer, which is pronounced "IN-tuh-jer," is a whole number that can be positive, negative, or zero and is not a fraction. Examples of integers include: -5, 1, 5, 8, 97, and 3,043. 1.43, 1 3/4, 3.14, and other numbers that are not integers are examples. The set of whole numbers and their antipodes is known as the integers. The set of integers excludes fractions and decimals. For instance, 2,5,0,12,244,15, and 8 are all numbers. Any positive or negative number that does not contain fractions or decimal places is known as an integer, often known as a "round number" or "whole number." For instance, the numbers 3, -10, and 1,025 are all integers, whereas the numbers 2.76 (decimal), 1.5 (decimal), and 3 12 (fraction) are not.P(n) :
1²+ 2² + 3² + … +n² = 1/6n(n+1)(2n+1)
P(1) :
[tex]1^2=\frac{1(1+1)(2(1)+1)}{6}[/tex]
[tex]1=\frac{6}{6}=1[/tex]
∴ LHS = RHS
Assume P(k) is true
P(k):
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after a party there are parts of three pizzas remaining. there is 3/4 of a pepperoni pizza remaining 5/8 of a cheese pizza remaining and 11/12 of a sausage pizza remaining. the 5 friends who organized the party split the remaining pizza equally. What fraction of a whole pizza does each person get?
Adding all of the remaining pizzas, and dividing the total pizza into 5 equal fractions, the fraction of pizza that each person gets would be 11/24
What is a mixed number and how is it different from an improper fraction?A mixed number is a combination of a whole number and a fraction. For example, 3 1/2 is a mixed number. It is different from an improper fraction, which is a fraction where the numerator is greater than or equal to the denominator. For example, 7/4 is an improper fraction.
How do you convert a mixed number to an improper fraction?To convert a mixed number to an improper fraction, you must first multiply the whole number by the denominator of the fraction. Then add the result to the numerator. Finally, place the sum over the denominator. For example, to convert 3 1/2 to an improper fraction, you would first multiply 3 by 2 (the denominator of the fraction 1/2) to get 6, then add 1 (the numerator of the fraction 1/2) to get 7. So 3 1/2 is equivalent to 7/2 as an improper fraction.
So to find out the fraction of a whole pizza that each person gets out of the different remaining pizzas, first we need to all the remaining pizzas as shown below,
3/4 of pepperoni + 5/8 of cheese + 11/12 of sausage = 55/24
Now to equally divide this into 5 person, we need to divide this fraction by 5,
i.e 55/(24*5) = 11/24
Therefore, each person gets 11/24 of the whole pizza.
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What happens when a function tries to assign or change a value of a variable that has been defined at the module level
When Python constructs a function, it also generates a temporary variable with the same name, and only the function can access the value of that variable.
What is Using a temporary variable?Using a temp variable is the quickest and easiest way to switch the values of two variables. Using the formula temp = a, the first variable's value is stored in the temp variables. By doing this, you can change the values of the two variables so that a = b before assigning the value of temp to the second variable.Tuple packing and sequence unpacking are two additional methods for changing the values of two variables without the usage of a temporary variable. Using commas to divide up the pieces in a tuple is one method of creating a tuple. Additionally, Python examines a task's right side before its left. As a result, the variables are packed into a tuple on the right side of the statement by using commas to separate them, and they are unpacked on the left side using the same number of target variables separated by commas.As long as the statement has the same number of variables on both sides as there are variables, this approach of variable swapping and permutation can be applied to more than two variables.To Learn more About temporary variable Refer To:
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3x-y=2 and 12x-4y=4 parellel or perpendicular line
Answer:
They are parallel line.
What is the product of 2x 3y )( 2x 3y )? *?
The product of (2x-3y)(2x+3y) is 4x^2-9y^2
Product= (2x-3y)(2x+3y)
Let the product of (2x-3y)(2x+3y) be P
P=2x(2x+3y)-3y(2x+3y)
P= 2x(2x)+2x(3y)-3y(2x)-3y(3y) {using distributive property of multiplication}
This property states that multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together. The multiplication of (a-b)(a+b) is equal to a^2 - b^2. This result is used as an identity.
P= 4x^2 +6xy - 6xy -9y^2
solving 6xy-6xy=0
P= 4x^2 - 9y^2
4x^2-9y^2 is the product of (2x-3y)(2x+3y).
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Six cars pull up to a red light, one at a time. At the light, there are three lanes, one left-turn lane, one straight-going lane, and one right-turn lane. How many ways can the cars stack up so that all three lanes are occupied
According to the probability, there are 540 arrangements that can the cars stack up so that all three lanes are occupied.
How is card probability determined?Mathematicians use addition and division as well as counting to calculate probability.
There are three partitions of six using digits 1-3.
(4,1,1), (3,2,1), (2,2,2) (2,2,2)
These could be dispersed between the lanes in order that
(3) Possible solutions to (4,1,1)
There are six possible ways to solve the equation (3,2,1).
There is only one possible solution to the equation (2,2,2).
Cars must now move in the lanes in proper order.
The arrangements for (4,1,1) will be 6C4 * 2C1 = 30. Six cars are chosen, sorted, and placed in the appropriate lanes. then decide on 1 of the 2 surviving vehicles.
then place it in a lane.
The arrangements for (3,2,1) will be 6C3 * 3C2 = 60.
There will be 6C2 * 4C2 = 90 arrangements for (2,2,2).
Consequently, there will be 540 arrangements (3*30 + 6*60 + 1*90 = 90+360 + 90).
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HELP ASAP PLS 50!!!!
Identify or mark the missing side or angle that would make triangle ABC a congruent to triangle PDF by SAS
Answer:
AC = PF
Step-by-step explanation:
will mark u brainliest
Answer:
( - 7, - 1, 1, 4 )
Step-by-step explanation:
( x, y )
where,
x is Domain
y is Range
Hence,
Domain is ( - 7, - 1, 1, 4 )
Help needed! ASAP please!
Answer:
x = - 1 or x = - [tex]\frac{2}{3}[/tex]
Step-by-step explanation:
to find the zeros let f(x) = 0 , that is
3x² + 5x + 2 = 0 ← in standard form
consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 3 × 2 = 6 and sum = + 5
the factors are 3 and 2
use these factors to split the x- term
3x² + 3x + 2x + 2 = 0 ( factor the first/second and third/fourth terms )
3x(x + 1) + 2(x + 1) = 0 ← factor out (x + 1) from each term
(x + 1)(3x + 2) = 0 ← in factored form
equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
3x + 2 = 0 ⇒ 3x = - 2 ⇒ x = - [tex]\frac{2}{3}[/tex]
The table shows information about the masses of some dogs.
a) Work out the minimum number of dogs that could have a mass of more than
27 kg
b) Work out the maximum number of dogs that could have a mass of more than
27 kg
a) The minimum number of dogs that could have a mass of more than 27 kg is 6.
b) The maximum number of dogs that could have a mass of more than 27 kg is 18.
We have a table which shows information about the masses of some dogs.
Now , we need to determine the minimum number of dogs could have a mass more than 27 kg . Let us see dogs with mass of more than 27 kg present in the following intervals , 20≤x<30 and 30≤x<40 with 12 and 6 respectively.
But we wants minimum of 12 and 6 is 6 .
so, the minimum number of dogs with mass more than 27 kg is 6.
b) We need to determine maximum number of dogs with mass more than 27 kg ,so Maximum is equals to sum of number of dogs present in interval 20≤x<30 and in interval 30≤x<40 = 12+6 = 18. So, required maximum number of dogs are 18.
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Complete question:
The above table shows information about the masses of some dogs.
a) Work out the minimum number of dogs that could have a mass of more than 27 kg
b) Work out the maximum number of dogs that could have a mass of more than 27 kg
Use the function f(x) = 4x2 + 8x − 5 to answer the questions.
Part A: Completely factor f(x).
Part B: What are the x-intercepts of the graph of f(x)? Show your work.
Part C: Describe the end behavior of the graph of f(x). Explain.
Part D: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part B and Part C to draw the graph.
a) The quadratic function is factored as follows: f(x) = 4(x - 0.5)(x + 2.5).
b) The x-intercepts of the quadratic function are given as follows: x = -2.5 and x = 0.5.
c) The end behavior of the quadratic function is given as follows: as x -> ± ∞, f(x) -> ∞.
d) The graph is constructed at the end of the answer, considering the x-intercepts, the y-intercept, the end behavior and the vertex.
How to graph the quadratic function?The quadratic function for this problem is defined as follows:
f(x) = 4x² + 8x - 5.
Hence the coefficients are given as follows:
a = 4, b = 8, c = -5.
The discriminant is given as follows:
D = 8² - 4 x 4 x (-5)
D = 144.
Hence the x-intercepts are given as follows:
x = (-8 + square root (144))/8 = 0.5.x = (-8 - square root (144))/8 = -2.5.Considering the intercepts and the leading coefficient of a = 4, the function is factored as follows:
f(x) = 4(x - 0.5)(x + 2.5).
As the leading coefficient is positive, the parabola is concave up, meaning that the end behavior is that the function increases to infinity both at the left tail and at the right tail.
The y-intercept is given as follows:
f(0) = 4(0)² + 8(0) - 5
f(0) = -5.
The coordinates of the vertex are given as follows:
x = -b/2a = -8/8 = -1.y = -D/4a = -144/16 = -9.More can be learned about quadratic functions at https://brainly.com/question/24737967
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From midnight to 2:00 am, the temperature dropped 1.4 °c each hour. If the temperature at 2:00am was 11.2 °c, what was the temperature at midnight
The temperature at midnight as required to ve determined in the task content is; 14°C.
What is the temperature at midnight as required to be determined from the given information.According to the task content; the temperature was 11.2°C at 2 : 00am.
However, since the temperature dropped 1.4 °c each hour; we have that;
In the two hours between midnight and 2:00am, the total temperature drop is; 2 × 1.4°C = 2.8°C.
On this note, the temperature at midnight can be evaluated as; 11.2°C + 2.8°C = 14°C.
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expand the polynomial (x+1)(x+2)(y-3)
Answer: X^2y + 3xy + 2y -3x^2 -9x -6
explanation
1. Foil (x+2)(x+1)
X^2 +2x + x + 2
2. Simplify
X^2 + 3x + 2
3. Distribute x^2 + 3x +2 (y-3)
X^2y + 3xy + 2y -3x^2 -9x -6
In ΔDEF, f = 5 cm, m∠E=79° and m∠F=75°. Find the length of d, to the nearest 10th of a centimeter.
Using sine and cosine rule, the length of d in the triangle is equal to 4.5cm
What is Sine RuleThe sine rule is a mathematical formula used to calculate the lengths of the sides and angles of any triangle when given two angles and one side or two sides and one angle. It is also known as the law of sines.
To find the length of d, we have to find the length of E.
Using sine rule;
f / sin F = e / sin E
5 / sin 75 = e / sin 79
e = 5sin79 / sin 75
e = 5.7cm
To find the length of d, we have to find the angle D by using the sum of angle theorem.
m∠ E + m∠ F + m∠ D = 180°
79 + 75 + m∠ D = 180
m∠ D = 180 - 154
m∠ D = 26°
Using cosine rule
d² = e² + f² - 2efCosD
d² = 5.7² + 5² - 2(5.7)(5)cos26
d² = 20.615598
d = √20.615598
d = 4.5cm
The length of side d is 4.5cm
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