Two persons A and B are walking with speed 5 km/h and 6 km/h
respectively in the same direction. Find how far will B be from A after
2 hours.


a 6 km
b 2 km
C 5 km
d 3 km

Answers

Answer 1

Answer:

b

Explanation:

Answer 2

The relative distance can calculate by dividing the time travelled by the speed difference between points A and B. Considering that B is going more quickly than A, we substract A's speed from B's speed.

Relative Speed = Speed of B - Speed of A

Relative Speed = 6 km/h - 5 km/h

Relative Speed = 1 km/h

Now, we can calculate the relative distance traveled by B after 2 hours:

Relative Distance = Relative Speed * Time

Relative Distance = 1 km/h * 2 hours

Relative Distance = 2 km

Therefore, B will be 2 kilometers away from A after 2 hours of walking in the same direction.

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Related Questions

How much does the force increase if each mass is doubled?

Answers

Answer:

The force will also double

Explanation:

The Federalists and Anti-Federalists argued primarily over which issue?

Answers

Both the Federalists and the Anti-Federalists were concerned with the preservation of liberty, however, they disagreed over whether or not a strong national government would preserve or eventually destroy the liberty of the American people
the range of power handed to the national government

A 20 kg fish swimming at 2 m/s swallows a 5 kg fish at rest. What is the speed of the large fish after lunch

Answers

Answer:

1.6m/s

Explanation:

Given parameters:

Mass of the big fish  = 20kg

Mass of small fish = 5kg

Speed of big fish  = 2m/s

Speed of small fish = 0m/s

Unknown:

Speed of the large fish after lunch  = ?

Solution:

The momentum of the big fish before and after feeding is conserved.

    Initial momentum  = Final momentum

    m₁v₁ + m₂v₂  = v (m₁ + m₂)

m₁ is mass of the big fish

v₁ is the speed of the big fish

m₂ is mass of the small fish

v₂ is the speed of the big fish

v is the final speed

 Now insert the parameters and solve;

       20 x 2 + 5(0) = v(20 + 5)

              40 = 25v

                v  = [tex]\frac{40}{25}[/tex]   = 1.6m/s

Two cars, initially 12 meters apart, zip towards one another at the speeds shown. At what point will the collision occur? Explain how you arrived at your answer. Car A: 1.4m/s car B: 2.2m/s

Answers

Answer:

s₁ = 4.67 m from car A

Explanation:

Since, the cars are moving at a constant speed. Hence, we will apply the equation for uniform motion here:

s = vt

where,

s = distance covered

v = velocity

t = time taken

For Car A:

s₁ = (1.4 m/s)t

For Car B:

s₂ = (2.2 m/s)t

Because the time will be same at the collision. At collision the distance covered by Car A and Car B must be 12 m altogether. Hence:

s₁ + s₂ = 12 m

using values:

(1.4 m/s)t + (2.2 m/s)t = 12 m

t = 12 m/3.6 m/s

t = 3.333 s

Substitute this in the equation of s₁:

s₁ = (1.4 m/s)(3.33 s)

s₁ = 4.67 m from car A

You drop a lead fishing weight and a filled water balloon. Which do you expect to fall faster?

Answers

I believe they should fall at the same pace.

A jet plane flies at a velocity of 200 m/s, east in still air. a) If it flies into a 20 m/s wind heading west, what is its velocity relative to the ground? b) If it flies into a 20 m/s wind heading east, what is its velocity relative to the ground?

Answers

Answer:

Explanation:

a) If it flies into a 20 m/s wind heading west

The wind blows against the velocity of plane

resultant velocity = 200 - 20 = 180 m /s

velocity relative to ground = 180 m /s

b ) If it flies into a 20 m/s wind heading east,

wind will support the velocity of plane

resultant velocity = 200 + 20 = 220 m /s .

velocity relative to ground  = 220  m /s .

Answer:

so mas o menos

Explanation:

a) If it flies into a 20 m/s wind heading west

The wind blows against the velocity of plane

resultant velocity = 200 - 20 = 180 m /s

velocity relative to ground = 180 m /s

b ) If it flies into a 20 m/s wind heading east,

wind will support the velocity of plane

resultant velocity = 200 + 20 = 220 m /s .

velocity relative to ground  = 220  m /s .

If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60
m/s^2 for 4 seconds, what will its final velocity be?*

Answers

Answer:

254

Explanation:

use the formula "final Velocity- initial velocity / time = acceleration"

so "X - 14 /4 = 60"

60 x 4 = X - 14

240 +14 = X

X = 254

Answer:

Explanation:Explanation:

6. What is fuel needed for in space?
7. Could a rocket traveling at a speed of
10,000 km/h get into space? Explain.
8. Why is thrust also known as the
reaction force?
9. Why does a rocket not need to burn
fuel to keep moving once it is in space?

Answers

6. fuel is needed in space to power certain things like engines.

7. It couldn't, as the lowest speed acceptable to get into space is 7.9 km per second (28,440 km per hour). This is because to break into the barrier that no longer contains oxygen, you would need to be going at an extremely fast rate.

8. It involves Newton's 3rd law. The movement requires that same thrust to be thrown back, also.

9. There is no gravity. So, basically, you just float.

describe how you would see the apple in the dark.

Answers

You will see the apple after your eyes have had time to adjust to the darkness, but you will not see the red color.

Four forces are exerted on an object as shown below: A square is shown with an arrow pointing up labeled 3 N, an arrow pointing right labeled 2 N, an arrow pointing down labeled 4 N and an arrow pointing left labeled 2 N In which direction will the object move? Up Down Left Right

Answers

Answer:— A square labeled Object B is shown with an arrow pointing up labeled 3 N, an arrow pointing right labeled 2 N, an arrow pointing down labeled 3 N and an arrow pointing left labeled 1 N. In which direction will the objects move? Object A will move down and Object B will move up.

Explanation:

Answer:

The answer is down.

Explanation:

The forces on the left and right sides are balanced forces making the object not move in left or right directions. The force on the object is also shown to be 4N down and 3N up. The object will move toward the side with more force and that is down.

you are flying on an airplane and you overhear two pasengers comment that flight attendants must be very skiled, one says "when the flight attendants pour coffee they must take into account the forward motion of the airplane and pour the coffee in frount of the cup so that it will land in the cup." The other passenger replies, "flight attendants must have to study the laws of motion as part of their training!" What would Isaac Newton say about this conversation? Ik that was long but ill make it worth a lot of points for your trouble.

Answers

How do you get out of a room with only a mirror and a table?

Look in the mirror you see what you saw, use the saw to cut the table, half and half makes a hole, jump in it.

Thought you would like that.

which is the larger value 5 * 10^5 or 3* 10^7

Answers

Explanation:

5x 10^5= 500,000

3x 10^7= 30,000,000

so the second one

Which image below is the best example of an exothermic reaction?

Answers

Answer:

ion

know man sorry

Explanation:

A car runs for about 10 years during its average useful life. If the odometer reads 120,000 miles at the end, what was the average speed of the car in mph

Answers

Answer:

12000 mph

Explanation:

Given that,

Distance read by the odometer = 120,000 miles

Duration of car, t = 10 years

We need to find the average speed of the car. Speed of an object is equal to the total distance covered divided by total time taken. So,

[tex]v=\dfrac{120000}{10}\\\\=12000\ mph[/tex]

So, the average speed of the car is 12000 mph.

Ana vive a 3 km del instituto y María en la misma carretera, 500 m. Más lejos. Todas las mañanas, a las ocho y cuarto, cogen la bici para ir a clase. Ana pedalea a 6 m/s y María a 8 m/s. A) ¿Cuándo y dónde se encuentran? B) A que velocidad tendría que pedalear Ana como mínimo para que María no la alcanzase antes de llegar al instituto

Answers

Answer:

A) Ana y María e encuentran a las 8 hs 19 minutos 10 segundos (250 segundos después).

María y Ana  se encuentran cuando aún faltan 1500 metros para llega al instituto.

B) Ana tendría que pedalear como mínimo para que María no la alcanzase antes de llegar al instituto a una velocidad de 6.857 [tex]\frac{m}{s}[/tex].

Explanation:

A) Un movimiento es rectilíneo cuando un objeto describe una trayectoria recta, y es uniforme cuando su velocidad es constante en el tiempo. En otras palabras, el Movimiento Rectilíneo Uniforme es una trayectoria recta, su velocidad es constante y su aceleración es nula.

Para una posición inicial x0 y una velocidad v que tiene el cuerpo a lo largo del movimiento,  la posición para cualquier tiempo está dada por:

x(t)= x0 + v*t

Estableciendo el origen de referencia en el instituto, se tienen los siguientes valores:

x0ana= 3 km= 3000 mx0maria= 3500 m

Por otro lado, Ana pedalea a 6 m/s y María a 8 m/s.

Entonces, como Ana y María se acercan al origen de referencia, la escuela, se la ecuación del movimiento para cada una de ellas es:

xana= 3000 - 6*txmaria= 3500 - 8*t

Ambas se encuentra cuando la posición de ellas sea la misma, esto es xana=xmaria. Entonces:

3000 -6*t= 3500 - 8*t

Resolviendo:

-6*t + 8*t= 3500 - 3000

2*t= 500

t= 500÷2

t=250 s= 4 minutos 10 segundos

Ana y María se encuentran a las 8 hs 19 minutos 10 segundos (250 segundos después).

Para conocer la posición en la que se encuentran debes sustituir el tiempo en la ecuación del movimiento de alguna de ellas:

xana=3000 - 6*250

xana= 1500 m

Es decir, María y Ana  se encuentran cuando aún faltan 1500 metros para llega al instituto.

B) Para que esto ocurra Ana y María deben llegar al instituto al mismo tiempo. Entonces, el tiempo que tarda María en llegar a al origen de referencia, la escuela, es:

0= 3500 - 8*t

Resolviendo:

3500=8*t

3500÷8= t

437.5 segundos= t

Así que, si Ana 437.5 segundos o menos, María no la alcanzaría. Siendo la velocidad la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello, entonces la velocidad de Ana se calcula como:

[tex]velocidad=\frac{distancia}{tiempo}[/tex]

[tex]velocidad=\frac{3000 metros}{437.5 segundos}[/tex]

velocidad= 6.857 [tex]\frac{m}{s}[/tex]

Ana tendría que pedalear como mínimo para que María no la alcanzase antes de llegar al instituto a una velocidad de 6.857 [tex]\frac{m}{s}[/tex].

ANSWER QUICK PLS!!

(04.02 MC)

Pam observed many small earthworms in the backyard of her house after a heavy rain. What most likely formed the earthworms?

Select one:
a. Rainwater that fell on stones
b. Wet mud in the backyard
c. Eggs of earthworms
d. Mixing of air and water

Answers

Answer:

c. Eggs of earthworms

Explanation:

The actual formation of earthworms is by existing earthworms laying eggs.

The other answers are all separate from earthworms, though they are all found in the area with the earthworms.  

Answer:

C. eggs or earth worms!

Explanation:

I hope this helps and this is Correct!

please help!!!!

What are the mass and weight of a 50 kg stone on planet Earth?

Answers

Answer:

500 Newtons

Explanation:

Mass of the stone = 50 kg

Acceleration caused due to gravity on Earth (g) = 9.81 m/s^2 = 10 m/s^2

We know that,

F=ma

Hence,

W=mg

So,

The weight of the stone on Earth = 50 * 10 = 500 Newtons

Hallar la fuerza eletrica ejercida entre 2 cargas iguales de magnitud 1c separado en el aire una distancia de 1km Cual es el resultado? 1. (2,3*10^-8new) 2. (8,1*10^-6new) 3. (3,2*10^-8new)

Answers

Answer:

La fuerza eléctrica ejercida entre 2 cargas iguales de magnitud 1 C separado en el aire una distancia de 1 km es 9,000 N.

Explanation:

La ley de Coulomb se utiliza para calcular la fuerza eléctrica que actúa entre dos cargas en reposo. Es decir, esta ley permite predecir la fuerza electrostática de atracción o repulsión existente entre dos partículas según su carga eléctrica y la distancia entre ellas.

La fuerza eléctrica con la que dos cargas puntuales son atraídas o repelidas en reposo es directamente proporcional a su producto e inversamente proporcional al cuadrado de la distancia que las separa, expresada como:

[tex]F=k*\frac{q1*q2}{d^{2} }[/tex]

donde:

F es la fuerza eléctrica de atracción o repulsión. En el S.I. se mide en Newtons (N). q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C). d es el valor de la distancia que las separa. En el S.I. se mide en metros (m). k es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. En concreto para el vacío k es aproximadamente 9*10⁹ N·m²/C² utilizando unidades en el S.I.

En este caso:

q1= 1 Cq2= 1 Cd= 1 km= 1,000 m

Reemplazando:

[tex]F=9*10^{9} \frac{N*m^{2} }{C^{2} } *\frac{1 C* 1 C}{(1,000 m)^{2} }[/tex]

Resolviendo obtenes:

F= 9,000 N

La fuerza eléctrica ejercida entre 2 cargas iguales de magnitud 1 C separado en el aire una distancia de 1 km es 9,000 N.

A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground. What is the displacement of the plane?

Answers

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) =  1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a  c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

While traveling along a highway a driver slows from 34 m/s to 15 m/s in 12 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.

Answers

Answer:

a=-1.58 m/s^2

Explanation:

Vo=34m/s

Vf=15m/s

t=12s

a= dV/dt = (Vf-Vo) /t = (15-34)/12

= - 19/12 = - 1.58m/s2

what is the weight of a 75 kg sack of flour on Earth

Answers

75*9.8= 735
Sometimes people say it’s 10 instead of 9.8 so you can say it’s 750 N as well

We have that the weight of a 75 kg sack of flour on Earth is

[tex]W=735.75N[/tex]

From the Question we are told that

Mass =75kg

Generally

The Gravitational pull on earth is approximately

g=9.81

Generally the equation for Weight  is mathematically given as

[tex]W=Mass * gravity[/tex]

[tex]W=735.75N[/tex]

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A farmer is walking through a field at a
velocity of +0.5 meters per second (m/s)
relative to the ground. At the same time, he
is throwing seeds in front of him at a
velocity of +2.1 m/s relative to himself.
What is the velocity of the seeds relative to
the ground as they travel through the air?

Answers

Answer:

The velocity of the seeds relative to the ground as they travel through the air is V = +2.6 m/s

Explanation:

Let V be the velocity of the seeds relative to the ground, v be the velocity of the seeds relative to the farmer and v' be the velocity of the farmer relative to the ground.

By vector addition, V = v + v'

Since  v = the velocity of the seeds relative to the farmer = +2.1 m/s and

v' = the velocity of the farmer relative to the ground = +0.5 m/s

Then,

V = v + v'

V = +2.1 m/s + (+0.5 m/s)

V = +2.6 m/s

So, the velocity of the seeds relative to the ground as they travel through the air is V = +2.6 m/s


When the cornea and lens of the eye do not properly focus
light onto the retina, corrective lenses are needed. When are concave lenses
appropriate for vision correction?

Answers

Answer:

When there is nearsightedness or myopia

Explanation:

As, in myopia the image is formed in front of the retina.

Which makes things looking at things near very easy, but looking at far away things very difficult.

So concave lens makes things look bigger, so therefore, it is used during myopia, to make things look bigger when they are far away

which substance can be separated by physical means and it is not the same throughout.
A.a compound
B.a heterogeneous mixture
C.an element
D.a homogeneous solution

Answers

Answer:

B. heterogenous mixture

Explanation:

The substance that can be separated by physical means include heterogenous mixtures, where the components forms separate faces. They can be easily separated using methods based on their physical properties.

What is heterogenous mixtures?

Mixtures are combination of two or more individual components mixed physically or through chemical bonds. There are both homogenous and heterogenous mixtures.

In homogenous mixtures all the components are forms a single phase and appear to be one system. For example, salt solution, sugar solution etc. are homogenous mixtures.

In heterogenous mixtures, the components forms different phases which appears to be separated components. They are just physically mixture components and can be easily separated using physical methods.

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PLEASE HELP!! ILL MARK BRAINLYEST!!

New substances are produced in a chemical change.


True
False

Answers

The Answer is true hope this helps

The equation F = M x a represents

A. Newton’s third law
B. Newton’s first law
C. Newton’s second law

Answers

Answer:

it C

Explanation:

and have a good day :)))

Answer : (c) Newton's second law

The formula (F = m x a) comes under Newton's second law of motion, which revolves around the concept of momentum and force.

This equation shows the reaction that occurs when calcium carbonate
decomposes. what type of reaction is it? CaCO3 + energy – CaO + CO2

a. endothermic
b. synthesis
c. replacement
d. exothermic

ADD ANSWER
+6 PTS

Answers

Answer:

a. endothermic

Explanation:

The reaction shown is an endothermic reaction. In such reaction, they require an input of energy.

Endothermic changes involves absorption of heat from the surrounding. The surrounding becomes colder at the end of the reaction. When heat is on the reactant side, it suggests a reaction that requires a considerable input of energy.

Whats the cell that’s based on that persons sex

Answers

Answer:

gamete i think

1 pts
Question 13
Which statement best describes the consequences of a plant's leaf cells suddenly losing their
chloroplasts?
The leaf cells would divide rapidly.
The leaf cells would evolve into animal cells.
The leaf cells wouldaccumulate too much food and convert it to starch.
The leaf cells would be unable to convert the sun's energy to make food.
Question 14
1 pts

Answers

Answer:

The leaf cells would be unable to convert the sun's energy to make food.

Explanation:

The chloroplast in the leaf are used to make food for the plant. If the leaf loses its chloroplast, the leaf with not be able to use solar energy to manufacture their food.

During photosynthesis, green plants manufacture their food. They use sunlight to cause a reaction between carbon dioxide and water. The sunlight is trapped using chlorophyll present in the leaf. In the absence of the chlorophyll contained in the chloroplast, no solar energy would be generated to cause the reaction to take place.

Can somebody help me with this carbon nuclides question please?

Answers

Answer:

isotopes

Explanation:

because all of them have the same proton number which is the atom of the same element

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