Answer: The two numbers are $x = 5$ and $y = 7.5$.
Step-by-step explanation:
Let the two numbers be $x$ and $y$, where $x < y$. We can write the two given statements as the following two equations:
$$2y = 3x + 15$$
$$\frac{1}{5}x + \frac{1}{9}y = 10$$
We can solve this system of equations using elimination. Multiplying the first equation by 5 and the second equation by 9, we get
$$10y = 15x + 75$$
$$9x + y = 90$$
Subtracting these equations, we get
$$8y - 9x = 15$$
Multiplying this equation by 8, we get
$$64y - 72x = 120$$
Adding this equation to 5 times the first equation, we get
$$69y - 72x = 120 + 75$$
$$69y - 72x = 195$$
Dividing both sides by 3, we get
$$23y - 24x = 65$$
Subtracting this equation from 4 times the second equation, we get
$$96y - 36x = 360 - 260$$
$$96y - 36x = 100$$
Dividing both sides by 60, we get
$$\frac{16}{3}y - \frac{6}{5}x = \frac{5}{3}$$
Substituting the expression for $y$ from the first equation, we get
$$\frac{16}{3}(3x + 15) - \frac{6}{5}x = \frac{5}{3}$$
This simplifies to
$$\frac{16}{5}x + \frac{64}{5} = \frac{5}{3}$$
Solving for $x$, we find that $x = 5$. Substituting this value into the first equation, we find that $y = 15/2 = 7.5$. Therefore, the two numbers are $x = 5$ and $y = 7.5$.
A 3kg cart moving with a speed of 4m/s collides with a 1 kg cart at rest
The speed of the carts after collision is 3 m/s.
What is the velocity after collision?We have to note that in this case, we would need to apply the principle of the conservation of linear momentum. This implies that the momentum before collision would have to be the same as the momentum after collision.
Then we have;
Momentum before collision = Momentum after collision thus;
(3 * 4) + ( 1 * 0) = (3 + 1) v
Note that the two carts are said to stick together and move with a common speed
Hence;
12 = 4v
v = 12/4
v = 3 m/s
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DIRECTIONS: Use this information to answer Parts A and B. The width of a rectangle is shown. The length is twice the width. Part A 5-1x Write an expression for the perimeter listing each side separately.
Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.
Define perimeter.In geometry, a shape's perimeter, or overall length, is referred to as its perimeter. The lengths of all a shape's sides and edges are added up to determine its perimeter.
Here,
Given : length = 5 - 1(x) or
=> length = 5-x
Width is twice the length
thus,
=>Width = 2(5-x)
=>Width = 10-2x
So ,To find the perimeter
We use,
=> Perimeter = 2(length + width)
=> Perimeter = 2( 5-x + 10-2x )
=> Perimeter = 2( 15 -3x)
=> Perimeter = 30 -6x
Therefore , the solution of the given problem of perimeter comes out to be the perimeter is represented by the expression of Perimeter = 30 -6x.
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a line has a slope of 7/10 and a y intercept of (0,-4) what is the equation of the line in standard form
Considering the definition of a line, the equation of the line in standard form is y - 7/10x= -4
What is Linear equationA linear equation o line can be expressed in the form y = mx + b
where
x and y are coordinates of a point.m is the slope.b is the ordinate to the origin and represents the coordinate of the point where the line crosses the y axis.The standard form of a linear equation is Ax + By = C. In this type of equation, x and y are variables and A, B, and C are integers.
Equation in this caseIn this case, you know:
A line has a slope of 7/10.A line has a y-intercept of (0,-4).So, the line can be expressed as:
y=7/10x -4
Expresed in standard form:
y - 7/10x= -4
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A store is having a sale on chocolate chips and walnuts. For 4 pounds of chocolate chips and 8 pounds of walnuts, the total cost is $33. For 2 pounds of chocolate chips and 3 pounds of walnuts, the total cost is $13.
Find the cost for each pound of chocolate chips and each pound of walnuts.
Answer:
chocolate chip 7
walnuts 3.5
Step-by-step explanation:
assume x=chocolate chips
y=walnuts.
equation
4x + 8y=33
(2x+3y=13)×2
new eq
4x + 8y=33
4x + 6y=26
------------------
2y=7
y=7/2
4x+ 8y = 33
4x + 8(7/2)= 333
4x= 33-28
x=7.00
Find the radius of the circle, if the big square is 30 square units more than the area of the small square.
Answer:
The area of a square is equal to the side length of the square squared. If the side length of the small square is "s" and the side length of the big square is "b", then we can write the following two equations to represent the area of the two squares:
Area of small square = s^2
Area of big square = b^2
Since the area of the big square is 30 units more than the area of the small square, we can write the equation:
b^2 = s^2 + 30
To find the radius of the circle, we need to find the side length of the small square. To do this, we can rearrange the equation above to solve for s:
s^2 = b^2 - 30
s = sqrt(b^2 - 30)
Now we just need to find the value of "b", which is the side length of the big square. To do this, we can use the fact that the big square is inscribed in the circle, so the side length of the big square is equal to the diameter of the circle. Let's call the diameter of the circle "d". Then we can substitute "d" for "b" in the equation above:
s = sqrt(d^2 - 30)
To find the radius of the circle, we just need to divide the diameter of the circle by 2, so the radius is equal to "d" divided by 2. Therefore, the radius of the circle is:
r = d/2 = sqrt(d^2 - 30)/2
So to find the radius of the circle, we just need to know the diameter of the circle. Can you provide the diameter of the circle in the question?:
The radius of the circle is: r = d/2 = sqrt(d^2 - 30)/2
What is area of circle?The area of a circle is π multiplied by the square of the radius. The area of a circle, (A) when the radius 'r' is given is πr2. π is approximately 3.142
Here, we have,
The area of a square is equal to the side length of the square squared. If the side length of the small square is "s" and the side length of the big square is "b", then we can write the following two equations to represent the area of the two squares:
Area of small square = s^2
Area of big square = b^2
Since the area of the big square is 30 units more than the area of the small square, we can write the equation:
b^2 = s^2 + 30
To find the radius of the circle, we need to find the side length of the small square. To do this, we can rearrange the equation above to solve for s:
s^2 = b^2 - 30
s = sqrt(b^2 - 30)
Now we just need to find the value of "b", which is the side length of the big square. To do this, we can use the fact that the big square is inscribed in the circle, so the side length of the big square is equal to the diameter of the circle. Let's call the diameter of the circle "d". Then we can substitute "d" for "b" in the equation above:
s = sqrt(d^2 - 30)
To find the radius of the circle, we just need to divide the diameter of the circle by 2, so the radius is equal to "d" divided by 2. Therefore, the radius of the circle is:
r = d/2 = sqrt(d^2 - 30)/2
So to find the radius of the circle, we just need to know the diameter of the circle.
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There is a raffle for the class of 30
students. There are 3 prizes that are gift
cards for the value of $5, $10 and $25.
How many ways can there be 3 winners of
this raffle?
Answer:
Having 3 students pick a raffle
Step-by-step explanation:
3. Function G is defined by the equation G(x) = [x].
Function R is defined by the equation R(x) = x/+2.
Describe how the graph of function R relates to the graph of G, or sketch the graphs
of the two functions to show their relationship.
Answer: The function G(x) = [x] returns the greatest integer less than or equal to x. This means that for any value of x, G(x) will be the largest integer that is less than or equal to x. For example, G(3.5) = 3 and G(5) = 5.
The function R(x) = x/+2, x is any real number, this function returns the value of x incremented by 2. In other words, it is the result of adding 2 to x.
On the other hand, the graph of R(x) is a line that goes through the point (0, 2) and has a slope of 1, this means that for every change of 1 unit in the x-axis, the y-axis will change by 1 unit as well.
When we compare the two graphs, we can see that the graph of R(x) is shifted up 2 units from the graph of G(x) . If the graph of G(x) is thought of as the "ground", the graph of R(x) is "floating" two units above it. Also, the graph of R(x) is continuous while the graph of G(x) is not.
To sum up:
-The graph of G(x) is a step function, which start at the negative infinity and jumps up to the next integer at every point.
The graph of R(x) is a line that goes through the point (0, 2) and has a slope of 1
-R(x) is always two units above G(x) , and is a continuous function, while G(x) is not.
Step-by-step explanation:
Two cards are drawn at random from a well shuffled pack of cards. What is the probability that
i)both are spades or both are diamonds?
ii)both are queens or both are red coloured?
iii)both are diamonds or neither is a king?
Answer:
Step-by-step explanation:
1 in a tenth of a million. I did the math with all the cards and how many are kinds diamonds or red or queens yk.
summarize how you can find the slope of a perpendicular line.
Since "slope" tells us the angle of the line being graphed, the word "slope" is commonly used in mathematics.
Planar geometry states that all lines have slopes. Any slope can be calculated by comparing it to another line, usually the x-axis. A line's slope, or angle, in relation to that x-axis value is how steep it is.
In mathematics, slope is the proportion of the change in the y value to the change in the x value.
Two perpendicular lines have a slope such that the reciprocal of the negative slope of one line equals the slope of the other. The slope of perpendicular lines is -1 as a result.
The relationship between the slopes of parallel lines can be demonstrated using the formula m1.m2 = -1, if the slopes of the two perpendicular lines are m1, m2.
Like a fraction, a slope works by favoring the rise, up-and-down movement, over-the-run, or side-to-side movement. If a line rose up one unit for every rightward unit traveled, the slope would be a positive one.
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8.326 rounded to the nearest tenth
Answer:
8.3
Step-by-step explanation:
The number after three is below 5 so it stays as 8.3
Using the paths shown, how long is the shortest route from Lexington to Somerville?
Answer:
1 [tex]\frac{1}{4}[/tex] miles
Step-by-step explanation:
the routes from Lexington to Somerville are
Lexington → Brookfield → Somerville with distance
[tex]\frac{3}{8}[/tex] + [tex]\frac{7}{8}[/tex] = [tex]\frac{3+7}{8}[/tex] = [tex]\frac{10}{8}[/tex] = 1 [tex]\frac{2}{8}[/tex] = 1 [tex]\frac{1}{4}[/tex] miles
the other route is
Lexington → Brookfield → Yardley → Somerville with distance
[tex]\frac{3}{8}[/tex] + [tex]\frac{1}{2}[/tex] + [tex]\frac{1}{2}[/tex] = [tex]\frac{3}{8}[/tex] + [tex]\frac{4}{8}[/tex] + [tex]\frac{4}{8}[/tex] = [tex]\frac{3+4+4}{8}[/tex] = [tex]\frac{11}{8}[/tex] = 1 [tex]\frac{3}{8}[/tex] miles
the shortest distance is
Lexington → Brookfield → Somerville , a distance of 1 [tex]\frac{1}{4}[/tex] miles
Select the correct answer from each drop-down menu.
A town's population was 10,000 in 2005. The population has increased by 10% per year since 2005.
This situation represents
The rate of growth or decay, r, is equal to ____. So each year the number of residents in the town is ___ times the number in the previous year.
There were around 14,641 residents in the town ___ years after 2005.
The rate of growth or decay, r, is equal to 0.10.
What is population?Population in math refers to the set of all items of interest in a given context. It is the target or focus of a statistical study, and the objects described by the population's characteristics are known as population elements. It is important to define the population in detail before analyzing data and drawing conclusions. Examples of populations can include all students at a school, all people living in a particular country, or all people who bought a particular product.
So each year the number of residents in the town is 1.10 times the number in the previous year.
There were around 14,641 residents in the town 14 years after 2005.
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Rashaad has
x
x dimes and
y
y nickels, having no less than 18 coins worth at most $1.50 combined. At least 4 of the coins are dimes. Solve this system of inequalities graphically and determine one possible solution.
Answer:
see attached for a graph4 dimes, 22 nickelsStep-by-step explanation:
You want to solve graphically the system of inequalities expressing that Rashaad has no less than a total of 18 dimes (x) and nickels (y) with a combined value of at most $1.50, of which at least 4 are dimes.
InequalitiesAn inequality can be written for each of the constraints:
x + y ≥ 18 . . . . . . . no less than 18 coins
0.10x +0.05y ≤ 1.50 . . . . . . at most $1.50 in value
x ≥ 4 . . . . . . . . . . at least 4 dimes
GraphA graph of these inequalities is attached. The marked points are the vertices of the triangular solution space. Each is a possible solution, along with all of the grid points inside the triangle.
One possible solution is 4 dimes and 22 nickels, for a total of 26 coins with a value of $1.50.
Using graph to solve the system of linear inequality the most likely solutions will be 4 dimes and 22 nickels, for a total of 26 coins with a value of $1.50
What is System of Linear InequalitySystems of linear inequalities are equations with two or more linear inequalities that contain two or more variables. These equations can be used to represent real-world problems and to find the solutions of such problems. The solutions of a system of linear inequalities are all the points that are common to all of the linear inequalities in the system.
In this problem, we have to define our variables and then solve this using graphical method. The point of intersection between the two lines lies the solution to the linear inequality.
Let;
x = dimesy = nickelx + y ≥ 18
0.1x + 0.05y ≤ 1.50
x ≥4
Using a graphing calculator to solve this,
The possible solutions is 4 dimes and 22 nickels, for a total of 26 coins with a value of $1.50.
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PLEASE FAST WILL GIVE BRANILY
A 12-foot tall tent pole is secured to the ground using a piece of rope 15 feet long from the top of the tent pole to the ground. If the tent pole makes a 90-degree angle with the ground, determine the number of feet along the ground from the tent pole to the rope.
3 feet
9 feet
19 feet
81 feet
Answer:
3 feet
Step-by-step explanation:
To solve this problem, we can use the Pythagorean theorem. Let's call the distance from the tent pole to the rope x. We can set up the following equation:
x^2 + 12^2 = 15^2
Solving for x, we get:
x = sqrt(15^2 - 12^2)
x = sqrt(9)
x = 3
Therefore, the distance from the tent pole to the rope is 3 feet.
MODELING REAL LIFE When the average price of an item increases from $p_1$ to $p_2$ over a period of $n$ years, the annual rate of inflation $r$ (in decimal form) is given by $r=\left(\frac{p_2}{p_1}\right)^{1/n}-1$
. Find the rate of inflation for each item in the table.
Per pound Per pound
2009 2019
Potatoes $0.620 $0.749
Oranges $0.910 $1.280
Ground beef $2.251 $3.775
Potatoes:
, or %
Oranges:
, or %
Ground beef:
, or %
The rate of inflation of potatoes is 0.019.
The rate of inflation of Oranges is 0.019.
The rate of inflation of Ground beef is 0.019.
What is Rate of Inflation?Inflation is an increase in the level of prices of the goods and services that households buy. It is measured as the rate of change of those prices.
Given:
Here, the annual rate of inflation r (in decimal form) is given by
r = [tex](p_2/ p_1)^{1/n[/tex] - 1
Now, The average price of a potatoes increased from $0.620 in 2009 to $0.749 in 2019.
Thus, The required rate of inflation,
r = [tex](0.749/ 0.620)^{1/10[/tex] - 1
r = 1.019 - 1
r = 0.019
Now, The average price of a Oranges increased from $0.910 in 2009 to $1.280 in 2019.
Thus, The required rate of inflation,
r = [tex](1.280/ 0.910)^{1/10[/tex] - 1
r = 1.034 - 1
r = 0.034
Now, The average price of a Ground beef increased from $2.251 in 2009 to $3.375 in 2019.
Thus, The required rate of inflation,
r = [tex](3.775/ 2.251)^{1/10[/tex] - 1
r = 1.0321 - 1
r = 0.0321
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Mr. Smith has saved $1,800 each year for 20 years. A year after the saving period ended, Mr. Smith withdrew $7,500 each year for a period of 5 years. In the sixth and seventh years, he only withdrew $5,000 per year. In the eighth year, he decided to withdraw the remaining money in his account. If the interest rate was 6% per year throughout the whole period, what was the amount he withdrew at the end of the eighth year?
At the end of the eighth year, the amount Mr. Smith withdrew was $41,757.68.
How the ending withdrawal is determined?The amount that Mr. Smith withdrew at the end of the eighth year is a product of a series of computations, involving future value determination.
In this situation, we have used an online finance calculator to determine the future value of the investment at each leg.
First Leg:N (# of periods) = 20 years
I/Y (Interest per year) = 6%
PV (Present Value) = $0
PMT (Periodic Deposits) = $1,800
Results:
FV = $66,214.06
Sum of all periodic payments = $36,000 ($1,800 x 20)
Total Interest = $30,214.06
Second Leg:N (# of periods) = 5 years
I/Y (Interest per year) = 6%
PV (Present Value) = $,
PMT (Periodic Withdrawal) = $-7500
Results:
FV = $46,331.15
Sum of all periodic payments = $-37,500 ($7,500 x 5)
Total Interest $17,617.09
Third Leg:N (# of periods) = 2 years
I/Y (Interest per year) = 6%
PV (Present Value) = $46,331.15
PMT (Periodic Withdrawal) = $-5000
Results:
FV (Final Withdrawal) = $41,757.68
Sum of all periodic payments = $-10,000 ($5,000 x 2)
Total Interest = $5,426.53
Thus, the amount of $41,757.68 was withdrawn by Mr. Smith at the end.
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3a²b and 3ab² are like terms true or false
Step-by-step explanation:
false.
3a²b≠3ab².
If a is 3 and b is3 it is not equal
Any help would be awesome
Answer: 72 square units
Step-by-step explanation: It is 72 square units because if you count the sides p and q you get 9 and the same with sides q and r you get 8 and if you multiply them together you get 72.
Mrs. Sarto told her son that if he babysat his baby sister, she would pay him $5.80 per hour. If Mrs. Sarto’s son babysits his sister for 5.2 hours, how much money will he be paid?
One root of the equation 4x² + 12x + k = 0, k = Z and x = R, is five times the other root.
Find the value of k.
We found the value of K is 5 and the root of equation is x = -1/2 and x = -5/2
What is quadratic equation?An equation of second order polynomial having one variable is called quadratic equation. Second order means the highest power used with variable is 2.
How to determine the value of k in the question?We are given, 4x²+ 12x +k =0, k =Z and x = R
the quadratic equation is 4x²+12x+k =0
we know the roots of a quadratic equation is x = - b ± √ (b² - 4ac) / 2a
when the quadratic equation is ax²+bx+ c= 0
Hence, roots of the equation given in question will be,
x = - 12 ±√ (12² - 4×4×k) / 2×4
x = - 12 ± √(144-16k) / 8
as per the condition given in question, one root of this equation is 5 times the other root.
hence, - 12 -12 √(144-16k) / 8 = [- 12 + √(144-16k) / 8] × 5
multiplying both sides by 8
- 12 - √(144-16k) = [-12 + √(144-16k)] ×5
- 12 - √(144-16k) = - 60 + 5√(144-16k)
- 12 + 60 = 6√(144-16k)
48 = 6√(144-16k)
8 = √(144-16k)
64 = 144 -16k
16k = 80
k = 5
the value of k =5
by putting the value of k =5
x = -12 ± √ (144 - 80) / 8 = (-12 ± 8) /8
x = -1/2 and x = -5/2
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-3/5(1+5n) =102
Solve for n
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
In a tournament, a professional golfer knows that she is 200 yards from the hole. A spectator is watching her play and is 140 yards away from the golfer.
Triangle with vertices labeled golfer and spectator and hole, with the distance from the golfer to the spectator measuring 140 yards and the distance from the golfer to the hole measuring 200 yards and the vertex of the spectator measuring 120 degrees
If the spectator has an angle of 120° between the golfer and the hole, what is the angle that the golfer has between the spectator and the hole?
60.0°
59.6°
37.3°
22.7°
The angle that the golfer has between the spectator and the hole is 60°. Therefore, option A is the correct answer.
What is sine rule?Law of Sines In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of any triangle to the sines of its angles.
The formula for sine rule is sinA/a=sinB/b=sinC/c
Given that, in a tournament, a professional golfer knows that she is 200 yards from the hole. A spectator is watching her play and is 140 yards away from the golfer.
Let the angle that the golfer has between the spectator and the hole be x
Here, sin 120°/200 =sin x/140
0.8660/200 =sin x/140
0.00433 = sin x/140
sin x=0.866
x=60°
Therefore, option A is the correct answer.
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Hi hi! The answer would be 22.7°, I took the test a while ago.
Consider whether it's wrong or right.
The solution to the equations are
0 ∈ N is False 7/2 ∈ Q is True
√16 ∈ Q' is False π ∈ Q' is True
3/2 ∈ I is False -3 ∈ R is True
0 ∈ I is True -1 ∈ I⁺ is False
( 1 - 3 ) ∈ N is False 8/2 ∈ I is True
What is an Equation?Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.
It demonstrates the equality of the relationship between the expressions printed on the left and right sides.
Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.
Given data ,
Let the number be represented as A
Now , the equation will be
a)
Let the number be A = 0
The number 0 is a whole number , rational number and an integer
0 is not a natural number
So , the equation is False
b)
Let the number be A = √16
The value of A = 4
The number 4 is a natural number , whole number , rational number and an integer
4 is not an irrational number
So , the equation is False
c)
Let the number be A = 3/2
The number 3/2 is a rational number
3/2 is not an integer
So , the equation is False
d)
Let the number be A = 0
The number 0 is a whole number , rational number and an integer
0 is an integer
So , the equation is True
e)
Let the number be A = ( 1 - 3 )
The value of A = -2
The number -2 is a rational number and an integer
-2 is not a natural number
So , the equation is False
f)
Let the number be A = 7/2
The number 7/2 is a rational number
7/2 is a rational number
So , the equation is True
g)
Let the number be A = π
The number π is an irrational number
π is an irrational number
So , the equation is True
h)
Let the number be A = -3
The number -3 is a real number
7/2 is a real number
So , the equation is True
i)
Let the number be A = -1
The number -1 is an integer and real number
-1 is a negative integer
So , the equation is False
j)
Let the number be A = 8/2
The value of A = 4
The number 4 is a natural , whole , integer and rational number
4 is an integer
So , the equation is True
Hence , the equations are solved
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PLEASE Help. The answers I got so far are A. 72. B. 301. C 90 and D 252. I am having the most trouble with B and D.
The correct solutions for this question are as:
(A) Bearing of B from A = 72°
(B) Bearing of B from C = 342°
(C) Bearing of A from B = 252°
(D) Bearing of A from C = 293°
Step by step solution:
(A) Bearing of B from A:
= 72° (Given in question)
(B) Bearing of B from C: = 342°
Solution:
As sum of co-interior angles is 180° , i.e. ∠NBC +∠NCB =180°
so, 162° + ∠NCB = 180°
∠NCB = 180°-162°
∠NCB = 18°
reflexive angle NCB =360° - ∠NCB
reflexive angle NCB = 360° - 18°
reflexive angle NCB = 342°
So, bearing of B from C: = 342°
(C) Bearing of A from B: = 252°
Solution:
First extend the line AB to any point (let's say "X")
So, ∠NBX = 72° [BY USING CORRESPONDING ANGLES]
Bearing of A from B = ∠NBX + 180°
Bearing of A from B =72° + 180°
Bearing of A from B =252°
(D) Bearing of A from C: = 293°
Solution:
Bearing of A from C= 360° - (∠BCA + ∠BCN)
Bearing of A from C= 360° - (49° + 18°)
Bearing of A from C= 360° - (67°)
Bearing of A from C= 293°
Important Points for "Bearing of Angles":
A bearing is an angle that is calculated clockwise from the north. A traverse should be regarded as anticlockwise unless differently stated or obvious from the bearings.
The angle between two lines cannot be directly read using a regular compass. By tracking the two lines bearings away from their point of confluence, the angles can be found.
Two angles—an inner angle and an exterior angle—are created when the two lines converge at a place. These two angles add up to a 360° angle.
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i am Once again asking for help on this difficult question- i am timed pls help :
what is 3 1/3 minus -1
Answer:
2 1/3
Step-by-step explanation:
Seperate equation
(3 1/2) - 1
( 3 - 1 ) + 1/2
2 and 1/3
15 minutes for 5 songs = minutes per song
Answer:
The average minutes per song would be 3.
Checkpoint 4 is -117 and checkpoint 3 is -212 how much higher is checkpoint 4 than 3
Answer:4 = -117,3=-212,4+3
Step-by-step explanation:
Greatest common factor
Step-by-step explanation:
To find the GCD or GCF of two numbers , you should:
List the prime factors of each one of them(the 2 numbers)choose the common number+least exponent multiply them1. Let
U = {(x, y, z) = R³ | x+y=2z = 0 = x - y},
and let
V = span {(1, 0, -1), (3, 1, 2)}.
Determine the dimensions of both U and V, proving your results.
Note that to prove the dimension, you should use the definition, which
means you need to find a basis. It is not enough to just state a basis,
you must explain why it is a basis.
The dimension of V is 2, and it is spanned by the basis vectors (1, 0, -1), (3, 1, 2).
The dimension of a vector space is the number of vectors in a basis for the space. To find a basis for a subspace of R³, we need to find a set of linearly independent vectors that span the subspace.
First, let's consider U. The subspace U is defined by the equations x + y = 2z and x - y = 0.
Solving these equations for x and y, we can express them in terms of z: x = 2z and y = -2z. Therefore, every vector in U can be written as (x, y, z) = (2z, -2z, z) = z(2, -2, 1).
Since z is a scalar, the vector (2, -2, 1) is the only vector needed to span the subspace U, which means that it is a basis for U.
Therefore, the dimension of U is 1, and it is spanned by the basis vector (2, -2, 1).
Now let's consider V. The subspace V is defined by the set of vectors that can be written as a linear combination of the vectors (1, 0, -1) and (3, 1, 2). We can start by showing that these vectors are linearly independent. Suppose that there are scalars a and b such that a(1, 0, -1) + b(3, 1, 2) = (0, 0, 0). Then we have:
a + 3b = 0
b = 0
-a = 0
Since a and b are real numbers, the above equation only holds if a = 0 and b = 0. This shows that (1, 0, -1) and (3, 1, 2) are linearly independent, and a basis of V.
Therefore, the size of V is 2, and it is traversed by the basis vectors (1, 0, -1), (3, 1, 2).
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