Two men, Joel and Jerry, push against a wall. Jerry stops after 10 min, while Joel is able 1) to push for 5.0 min longer. Compare the work they do. A) Both men do positive work, but Joel does 25% more work than Jerry. B) Both men do positive work, but Joel does 75% more work than Jerry. C) Both men do positive work, but Jerry does 50% more work than Joel. D) Both men do positive work, but Joel does 50% more work than Jerry E) Neither of them does any work.

Answers

Answer 1

Answer:

the correct answer is E

Explanation:

Work is defined by the expression

        W = F. d

Where the bold indicates vectors, we can make the dot product explicit

         W = F d cos θ

We can see that this definition of work the two men apply a force, but the wall does not move, so if there is no displacement the work is zero.

When checking the correct answer is E


Related Questions

In order for a protostar to transition to a full fledge star, what must happen? options: A. Nuclear fusion must occur in the protostar B. Planets must form around the protostar
C. The protostar must cool down D. Accretion must occur in the rings around the protostar

Answers

We can see here that in order for a protostar to transition to a full fledge star, A. Nuclear fusion must occur in the protostar

What is protostar?

A protostar is a massive cloud of gas and dust in space that has the potential to become a star and is currently collapsing due to its own gravity. It is the initial stage of a star's development.

The protostar will continue to collapse and get hotter and denser until the conditions are right for nuclear fusion, when it will fuse and turn into a star.

A star gets its energy through nuclear fusion, which is the process of joining atomic nuclei to create heavier atoms. The star is not hot enough or thick enough during the protostar phase for nuclear fusion to take place.

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If Steve throws the football 50 meters in 3 seconds, what is the average speed of the football? Speed = distance / time Question 2 options: A. 16.67 m/s B. 26 m/s C. 5 m/s D. 48.9 m/s

Answers

Answer:

A. 16.67 m/s

Explanation:

Speed or velocity refers to the rate of change in distance over a change in time. That is;

Speed = Distance ÷ time

Where;

Speed is in metre/seconds

Distance is in metre

Time is in seconds.

In this question, Steve throws a football 50 meters in 3 seconds. The average speed can be calculated this:

S = D/t

Where; d = 50m, t = 3s

S = 50/3

S = 16.6666666

S = 16.67m/s

Someone help thanks

Answers

It’s D, I hope it helps!

1. A wave has a wavelength of 5 m and a frequency of 2 Hz. At what speed/velocity does the
wave travel?

2. The speed/velocity of a wave on a guitar string is 100m/s and the frequency is 1,000 Hz. What
is the wavelength of the wave?

3. If the speed/velocity of a wave is 25 m/s and the wavelength is 5 m, what is the frequency of
this wave?

Answers

Answer:

1.10m/s

2.0.1m

3.5Hz

Explanation:

v=velocity, f=frequency and T=wavelength

1.v=ft

v=2x5

=10m

2.v=ft

100=1000T

divide both sides by 1000

T=0.1m

3.v=fT

25=5f

divide both sides by 5

f=5Hz

Please select the word from the list that best fits the definition The skeletons of tiny ocean animals grow together to form ______, structures that are found only in warm, clear ocean water.

Answers

Answer:

coral reef

Explanation:

If you have a fragment of glass that weighs 5 grams and has a volume of 2.4
g/ml, what is the density?
A)12 g/mL.
B)7.4 ml/g
C)2.08 g/ml
D)0.48 ml/g

Answers

Answer:

C)2.08 g/ml

Explanation:

density = [tex]\frac{mass}{vloume\\}[/tex]

             =[tex]\frac{5}{2.4}[/tex]

             =2.08g/ml

The stars in the model below are arrange by.... *

Answers

Answer:

where is the picture of star

A coin falling through a vacuum loses no energy to friction, and yet after it hits the ground it has lost all its potential and kinetic energy. Which statement best explains why the law of conservation of energy is still valid in this case

Answers

Answer:

Explanation:

When coin is at a height and rest, it only has potential energy( by the virtue of its position). While the coin is falling its potential energy changes into kinetic energy. This means that its potential energy is decreasing and kinetic energy increases. just before its hits the ground kinetic energy is maximum and potential energy becomes zero.

When it hits the ground all its kinetic energy is converted into heat.

Suppose the spark plug on a heat engine is not functioning properly which statement best explains how this will affect the engine?

Answers

Answer:

B. Burned gas...

Explanation:

The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed.

What is RNA polymerase?

RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.

Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.

Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed.

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A ball is thrown directly downward at 4 m/s from the edge of a high cliff. If needed, use g = 10 m/s2. With zero air resistance, the distance the ball falls during its third second of fall is most nearly

28 m
4 m
29 m
12 m
57 m

Answers

Answer:

57 meters

Explanation:

Let's see what variables we have in this problem:

[tex]v_i \ \ \ \ \ \ \ t \\ v_f \ \ \ \ \ \ \triangle x \\ a[/tex]

Let's set the upwards direction to be positive and the downwards direction to be negative.

We are given the initial velocity, 4 m/s. Since the ball is thrown directly downward, we can say that the initial velocity = -4 m/s.

We are also given the acceleration due to gravity, and since the acceleration is pointing downwards, we can say that a = -10 m/s².

The time is also given to us; the question wants to know the vertical displacement at time = 3 seconds, so we can plug in 3 seconds for t.

Since we are solving for vertical displacement, we can use [tex]\triangle x[/tex] as one of our variables.

Now we have all of the variables except for the final velocity, [tex]v_f[/tex].

Since we are dealing with constant acceleration, we can use this constant acceleration equation:

[tex]x_f=x_i+v_it+\frac{1}{2}at^2[/tex]

Subtract [tex]x_i[/tex] from both sides to get [tex]\triangle x[/tex].

[tex]\triangle x =v_it+\frac{1}{2}at^2[/tex]

Substitute in the known values:

[tex]\triangle x = (-4\frac{m}{s})(3s) + \frac{1}{2}(-10\frac{m}{s^2})(3s)^2[/tex]

Get rid of the units to make the equation more readable.

[tex]\triangle x = (-4)(3) + \frac{1}{2} (-10)(3)^2[/tex]

Simplify the equation and solve for delta x.

[tex]\triangle x=(-12) -5(9)[/tex] [tex]\triangle x =-12-45[/tex] [tex]\triangle x = -57[/tex]

The vertical displacement is -57 meters, so we can say that the distance the ball falls in 3 seconds is most nearly 57 meters.

A balloon of diameter 20.0 cm is filled with helium gas at 30°C at 1.00 atm. How
many atoms of helium gas fill a balloon having a diameter of 20.0 cm at 30.0°C
at 1.00 atm?​

Answers

Answer:

N = 3.54 * 10²³ atoms

Explanation:

The formula to apply here is the idea gas law;

PV = nRT  where ;

P= pressure of the gas= 1.013 * 10⁵ Pa

V= volume of the gas = 4/3 * 3.14 *0.15³= 0.01414 m³

n= amount of a substance = ?

R= ideal gas constant= 8.314

T= temperature= 293 K

Applying the values to the formula;

PV = nRT

1.013 * 10⁵ * 0.01414 = n * 8.314*293

n= 1.013 * 10⁵ * 0.01414 / 8.314*293

n= 0.588 moles

1 mole = 6.022 * 10²⁷ atoms/ mole

0.588 moles = 0.588 * 6.022 * 10²⁷

N = 3.54 * 10²³ atoms

A 5000 kg open train car is rolling on frictionless rails at 22 m/s when it starts pouring rain. A few minutes later, the car’s speed is 20 m/s. What mass of water has collected in the car?

Answers

Answer:

500 kg

Explanation:

It is given that,

The mass of a open train car, M = 5000 kg

Speed of open train car, V = 22 m/s

A few minutes later, the car’s speed is 20 m/s

We need to find the mass of water collected in the car. It is based on the conservation of momentum as follows :

initial momentum = final momentum

Let m is final mass

MV=mv

[tex]m=\dfrac{MV}{v}\\\\m=\dfrac{5000\times 22}{20}\\\\=5500\ kg[/tex]

Water collected = After mass of train - before mass of train

= 5500 - 5000

= 500 kg

So, 500 kg of water has collected in the car.

The mass of the  water collected in the car due to the rain is 500 kg.

The given parameters;

mass of the car, m = 5000 kgvelocity of the car, u = 22 m/sfinal speed of the car, v = 20 m/s

The mass of water collected in the car is determined by applying the principle of conservation of linear momentum as shown below;

[tex]m_cu_c = v(m_c + m_w)\\\\5000 \times 22 = 20(5000 + m_w)\\\\110,000 = 100,000 + 20m_w\\\\20m_w = 10,000\\\\m_w = \frac{10,000}{20} \\\\m_w = 500 \ kg[/tex]

Thus, the mass of the  water collected in the car due to the rain is 500 kg.

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what is the formula to calculate net force

Answers

Answer:

If N is the number of forces acting on a body, the net force formula is given by, FNet = F1 + F2 + F3

Explanation:

If N is the number of forces acting on a body, the net force formula is given by, FNet = F1 + F2 + F3…. + FN.

You pass 633 nm laser light through a narrow single slit of width 0.24 mm and observe the diffraction pattern on a screen 6.0 m away. If the intensity at the central bright is Io , what is the intensity at a point on the screen 3.0 mm from the center of the pattern?

Answers

Answer:

The intensity is  [tex] I  = 0.0175I_o [/tex]

Explanation:

From the question we are told that

   The wavelength is  [tex]\lambda = 633 \ nm = 633*10^{-9} \ m[/tex]

   The width of the slit is [tex]d = 0.24 \ mm = 0.00024 \ m[/tex]

   The distance from the screen is  [tex]D = 6.0 \ m[/tex]

   The distance of the position considered from the center is [tex]y = 3.0 \ mm = 0.003 \ m[/tex]

  Generally the intensity from at a point on the screen 3.0 mm from the center of the pattern is

       [tex]I = I_o * \frac{sin^2 [\frac{\pi d * y}{ \lambda D } ]}{[\frac{\pi d * y }{\lambda D} ]^2}[/tex]

 Here  [tex]I_o[/tex] is the intensity of the central bright fringe

=>    [tex] I  = I_o *  \frac{sin^2 [\frac{3.142  * 0.00024 * 0.003}{ 633*10^{-9} * 6 } ]}{[\frac{3.142*0.00024  * 0.003 }{633*10^{-9} * 6} ]^2}[/tex]

=>    [tex] I  = 0.0175I_o [/tex]        

What were the three topographical climate factors we talked about?

Group of answer choices


B.Grasslands, Tundra, Mountains


C.Dry Arid, Grasslands, Tundra


D.Dry Arid, Coastal, Mountains


A.Coastal, Dry Arid, Grasslands

Answers

Answer:

Dry Arid, Coastal, Mountains

Explanation:

Took the text

The 4.00 kg block is attached to a vertical rod by means of two strings. When the system rotates about the axis of the rod, the strings are extended as shown in the (Figure 1) and the tension in the upper string is 76.0 N.

Find the number of revolutions per minute at which the lower cord just goes slack.

Answers

Answer:

Let theta be angle of upper string with rod.

This a 3-4-5 triangle where R is distance of block from rod. (.75 - 1 - 1.25)

Fc = m w^2 R    where Fc the centripetal force and w the angular velocity

Fc = T sin theta = T * .75 / 1.25 = .6 T = 45.6 N

w^2 = 45.6 / (4 * .75)

w = 3.90 /sec

RPM = 3.90 / sec * 60 sec / min / (2 * pi) = 37.2 RPM      (2 pi rad / rev)

The number of revolutions per minute at which the lower cord just goes slack is 45.36 RPM.

The given parameters;

mass of the block, m = 4 kgthe tension on the upper string, T₁ = 76 N

The following triangle can be formed from the given diagram;

     |

     | 1 m

     |---------x--------(θ)  4.00 kg

The hypotenuse of this triangle = 1.25 m

The height of the triangle = 1 m

The base of the triangle is calculated as;

[tex]x^2 = 1.25^2 - 1^2\\\\x^2 = 0.5625\\\\x = \sqrt{0.5625} \\\\x = 0.75 \ m[/tex]

Resolving the vertical component of the force;

Tension at the upper = Tension at the lower string

[tex]T_1 sin(\theta) = T_2 sin(\theta) + mg\\\\76 \times \frac{1}{1.25} = T_2 \times \frac{1}{1.25} + (4\times 9.8)\\\\76 = T_2 + 39.2\\\\T_2 = 76 - 39.2\\\\T_2 = 36.8 \ N[/tex]

Resolving the horizontal component of the force;

[tex]T_1cos(\theta) + T_2cos(\theta) = F_c\\\\T_1cos(\theta) + T_2cos(\theta) = mr\omega^2 \\\\76\times \frac{0.75}{1.25} \ + \ 36.8\times \frac{0.75}{1.25}= 4\times 0.75\tmes (\frac{2\pi N}{60} )^2\\\\67.68 = 0.0329N^2\\\\N^2 = \frac{67.68}{0.0329} \\\\N^2 = 2057.14\\\\N = \sqrt{2057.14} \\\\N = 45.36 \ rpm[/tex]

Thus, the number of revolutions per minute at which the lower cord just goes slack is 45.36 RPM.

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A racecar accelerates uniformly from 18.5 mil to 46.1 m/s in 2.47 seconds.
What is the acceleration of the car?*

Answers

Answer:

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

Explanation:

Uniformly Accelerated Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Following the definition above, the acceleration is defined as:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The racecar goes from vo=18.5 m/s to vf=46.1 m/s in t=2.47 seconds, thus the acceleration is:

[tex]\displaystyle a=\frac{46.1-18.5}{2.47}[/tex]

[tex]\displaystyle a=\frac{27.6}{2.47}[/tex]

[tex]a = 11.17~m/s^2[/tex]

The acceleration of the racecar is [tex]\mathbf{11.17~m/s^2}[/tex]

A truck with the mass of 8 ton travels at a velocity of 60km/h and collides
with a truck with a mass of 5 tons travelling in the same direction at 40km/h.
After the collision the two trucks move together.
Calculate the final common velocity if the TWO trucks in m/s after the
collision?

Answers

Answer:

52 km/h

Explanation:

When the two trucks move together after collision, the momentum of the system is conserved. The kinetic energy is not conserved. This is inelastic collision

The formula to apply here is :

m₁v₁ + m₂v₂ = {m₁+ m₂} *vf

Given that ;

m₁ = 8 ton ----convert to kg [ multiply by 907.185] =7258 kg

v₁ = 60 km/h

m₂ = 5 tons ------4536 kg

v₂ = 40 km/h

vf = final velocity

Using the values given;

m₁v₁ + m₂v₂ = {m₁+ m₂} *vf

8*60 + 5*40 = {8+5} * vf

480 + 200 = 13 * vf

680 = 13vf

680/13 = vf

52 km/h = vf

what sphere on earth includes mountains

Answers

I believe it is lithosphere

Should we use less energy because it is
harming the planet?

Answers

Answer:

Yes - si.

Explanation:

Answer:

yes we should use less energy

24. Which of the following is true for a generator?
A. It transforms thermal energy to electrical energy.
B. It transforms mechanical energy into electrical energy.
C. It transforms electrical energy into mechanical energy.
D. It transforms solar energy into electrical energy.

Answers

B. it transforms mechanical energy into electrical energy

Answer:

The answer is b: mechanical to electrical

The trunk of a elephant may extend up to 2.2 m. It acts much like an organ pipe only open at one end when the elephant blows air through it. 1) Calculate the fundamental frequency of the sound the elephant can create with its trunk.2) If the elephant blows even harder, the next harmonic may be sounded. What is the frequency of the first overtone?

Answers

Answer:

1) f = 38.63 Hz , 2)   f = 115.9 Hz

Explanation:

The elephant's trunk can be approximated by a tube with a closed end, in pipes the closed ends correspond to nodes and the open ends to antinodes or bellies.

The expression for the wavelengths of this system is

             4L = n λ

              n = 1, 3, 5, 7 ...

               

also let's use the relationship between frequency and wavelength and wave speed

            v = λ f

             f = v / λ

             f = v n / 4L

             f = v / 4L n

1) the fundamental frequency occurs for n = 1

            f = 340/4 2.2 1

            f = 38.63 Hz

2) The first harmonic

           n = 3

            f = 340/4 2.2  3

           f = 115.9 Hz

A car is traveling 60 km/h and accelerates at a rate of 4 m/s^2 how long does it take the car to get to 90 km/h? ( please show work)

Answers

Answer:

Vf = 90km/h

      (90*1000)/3600 ==>

      (90*10)36

Vf = 25m/s

, Vi = 60km/h

         (60*1000)/3600

          16.666m/s =>16.7m/s

          , a = 4m/s^2

t = ?

Explanation:

Vf = Vi + at

25m/s = 16.7m/s +4m/s^2(t)

25m/s - 16.7m/s = 4m/s^2(t)

8.3m/s = 4m/s^2(t)

8.3m/s/4m/s^2 = t

2.075s = t => 2.1s

A penny was thrown downward at 2.4 m/s and falls under the influence of
gravity for 5 s. What is the final velocity of the penny?

Answers

Answer:

v = 51.4 m/s

Explanation:

Given that,

Initial velocity of a penny, u = 2.4 m/s

It fall under the influence of gravity for 5 s.

We need to find the final velocity of the penny. Let v is its final velocity. It can be calculated using first equation of motion as follows :

[tex]v=u+at[/tex]

a = g

[tex]v=2.4+9.8(5)\\\\=51.4\ m/s[/tex]

So, the final velocity of the penny is 51.4 m/s.

Use the drop-down menus to complete each statement.


In the mitochondria small molecules combine with to produce and carbon dioxide.
This process releases a large amount of .

Answers

Answer:

oxygen, water , energy

Explanation:

i took the instruction where this is from

Answer:

oxygen/water/energy

Explanation:

edge2020

God Bless You<3

If a pendulum makes 10 oscillations in 5 seconds, what is its oscillation frequency?​

Answers

Answer:

[tex] \boxed{ \rm{Frequency = 2 hertz}}[/tex]

Explanation:

We know that,

"Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second."

According to Question,

⇒ 5 seconds = 10 oscillations

⇒ 1 second = 10/5 oscillations

⇒ 1 second = 2 oscillations

In one second, there are 2 oscillations or cycles. The unit of frequency is Hertz. Hence, the frequency is 2 Hertz.

A 0.54 kg bullfrog is sitting at rest on a level log. How large is the normal force of the log on the bullfrog?

Answers

Answer:

5.3N

Explanation:

Step one:

given data

mass of bullfrog= 0.54kg

Step two:

Required

The force F in Newton

From newton first law

F=mg

The acceleration due to gravity acting on the frog is 9.81m/s^2

hence

F=0.54*9.81

F=5.3N

The normal force is 5.3N

what is mass? what is mass ?

Answers

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter. ... It is, in effect, the resistance that a body of matter offers to a change in its speed or position upon the application of a force. The greater the mass of a body, the smaller the change produced by an applied force.

Explanation:

AnsA

Explanation:

The amount of matter in an object

Which statement did Kepler’s investigations of the movement of the planets explain?


Jupiter has more moons than earth.


Gravity acts on all objects in the universe.


The sun is more massive than earth.


Earth is not the center of the universe.

Answers

Answer:

earth is not the center of the universe

Explanation:

i just took the test

Kepler's laws allow us to find that the correct answer, the basis is these is

 d) Earth is not the center of the universe.

Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws

Kepler's first law. Says the planets move elliptically Kepler's second law. Establish that the vector from the sun to the planet sweeps equal area in equal time intervals Kepler's third law. It is an application of Newton's second law to the movement of the planets around the sun, it gives a relationship between the period of the orbit and the semi-major axis of the ellipse.

                [tex]T^2 = ( \frac{4\pi ^2}{G M_s} ) \ a^3[/tex]

Where T is the period, a the major axis, G the universal gravitational constant and [tex]M_s[/tex] the most of the sun.

 

When analyzing these Kepler's laws in all the sun is the center of movement.

Let's analyze the different claims;

a) False. The laws are not on a specific planet

b) False. Gravity is not in Kepler's laws

c) False. A ratio of the masses between planets and the sun is not established

d) True. In the laws the sun is the center of movement, therefore the earth is not the center of the universe.

In conclusion using Kepler's laws we can find that the correct answer for the bases of these is:

 d) Earth is not the center of the universe.

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what's the answers for all of the questions ?///

Answers

More energy, colour and I think less bright
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