Answer:
The second option - same change in momentum, different force
Explanation:
They experience the same change in momentum, but the force on car A is greater.
p=m*v
Impulse, or change in p=F*t
We know the cars have the same change in momentum, because they both go from the same initial momentum (p=mv), to zero momentum. Therefore, both experience the same change in momentum. Since the time is different, but the change in momentum is the same, the force has to be different.
For example: if both cars had 200 kg*m/s of momentum at the start, and 0 at rest, the impulse is 200 kg*m/s
So,
p(a)= 200=F(0.3)
p(b)= 200=F(5)
Which force has to be greater to make the equations true? The force for Car A, of course!