Answer:68.4kg
Explanation:
A toy rocket is launched straight up by using a spring. The rocket is initially pressed down on the spring so that the spring is compressed by 9 cm. If the spring constant is 830 N/m and the mass of the rocket is 50 g, how high will the rocket fly?
Answer:
6.86 meters
Explanation:
Let the compression of the string be represented by x, and the height of projection of the toy rocket be represented by h.
So that;
x = 9 cm = 0.09 m
In its rest position (i.e before the launch), the spring has a stored potential energy which is given as;
PE = [tex]\frac{1}{2}[/tex] K[tex]x^{2}[/tex]
= [tex]\frac{1}{2}[/tex] x 830 x [tex](0.09)^{2}[/tex]
= 415 x 0.0081
= 3.3615
The potential energy in the string = 3.36 Joules
Also,
PE = mgh
where: m is the mass, g is the gravitational force and h the height.
m = 50 g = 0.05 kg, g = 9.8 m[tex]s^{-2}[/tex]
Thus,
PE = 0.05 x 9.8 x h
3.3615 = 0.05 x 9.8 x h
3.3615 = 0.49h
⇒ h = [tex]\frac{3.3615}{0.49}[/tex]
= 6.8602
The height of the toy rocket would be 6.86 meters.
A 56 kg woman climbs the stairs to a height of 5 m. Determine: a) what mechanical work
she performed; b) what work the woman will do when climbing the stairs and carrying a 5 kg load.
Answer:
a) W = 2746.8[J]
b) W = 2992.05 [J]
Explanation:
Work is defined as the product of force by distance. We must bear in mind that the force that performs the work is the one that acts in the same direction of displacement.
For this case, we must calculate the weight of the woman, the weight is defined as the product of mass by gravity.
[tex]w=m*g\\[/tex]
where:
w = weight [N] (units of Newtons]
m = mass = 56 [kg]
g = gravity acceleration = 9.81 [m/s²]
[tex]w=56*9.81\\w=549.36[N][/tex]
a)
[tex]W=F*d[/tex]
where:
F = weight = 549.36[N]
d = distance = 5 [m]
[tex]W = 549.36*5\\W = 2746.8[J][/tex]
b)
The new mass will be the combination of the mass of the woman plus that of the load.
[tex]m_{new} = 56+5\\m_{new}=61[kg][/tex]
[tex]w_{new}=61*9.81\\w_{new}=598.41[N][/tex]
The new work done.
[tex]W =598.41*5\\W=2992.05[J][/tex]
it is rate for any motion to
a. stay the same for very long
b. change quickly
c. increase in velocity
d. decrease in speed
Answer:
a. stay the same for very long
Explanation:
It is rare for any motion to stay the same for a very long time. The force applied on a body causes changes in the magnitude of motion.
For motion to remain constant, there must not be a net force acting on the body All the forces on the body must be balanced. This is very hard to come by. Motion changes very frequently.A local AM radio station broadcasts at a frequency of 627 kHz. Calculate the wavelength at which it is broadcasting. Wavelength
Answer:
Wavelength = 478.46 m
Explanation:
It is given that,
A local AM radio station broadcasts at a frequency of 627 kHz, f = 627000 Hz
We need to find the wavelength at which it is broadcasting. The wavelength is given by :
[tex]\lambda=\dfrac{c}{f}\\\\=\dfrac{3\times 10^8}{627\times 10^3}\\\\=478.46\ m[/tex]
So, the wavelength is 478.46 m.
A car is traveling at 15 m/sm/s . Part A How fast would the car need to go to double its kinetic energy
Answer:
21.21 m/s
Explanation:
Let KE₁ represent the initial kinetic energy.
Let v₁ represent the initial velocity.
Let KE₂ represent the final kinetic energy.
Let v₂ represent the final velocity.
Next, the data obtained from the question:
Initial velocity (v₁) = 15 m/s
Initial kinetic Energy (KE₁) = E
Final final energy (KE₂) = double the initial kinetic energy = 2E
Final velocity (v₂) =?
Thus, the velocity (v₂) with which the car we travel in order to double it's kinetic energy can be obtained as follow:
KE = ½mv²
NOTE: Mass (m) = constant (since we are considering the same car)
KE₁/v₁² = KE₂/v₂²
E /15² = 2E/v₂²
E/225 = 2E/v₂²
Cross multiply
E × v₂² = 225 × 2E
E × v₂² = 450E
Divide both side by E
v₂² = 450E /E
v₂² = 450
Take the square root of both side.
v₂ = √450
v₂ = 21.21 m/s
Therefore, the car will travel at 21.21 m/s in order to double it's kinetic energy.
For the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
Given the data in the question;
Speed of the car; [tex]v_1 = 15m/s[/tex]
Speed for the car to double its kinetic energy; [tex]v_2 = \ ?[/tex]
Using the expression for kinetic energy:
[tex]K_E = \frac{1}{2}mv^2[/tex]
Where m is the mass and v is the velocity
Now, Initial Kinetic Energy will be;
[tex]K_E_1 = \frac{1}{2}mv_1^2 \\\\K_E_1 = \frac{1}{2}*m*(15)^2\\\\K_E_1 = \frac{1}{2}*m*225\\\\K_E_1 = 112.5*m[/tex]
For the kinetic energy to become double
[tex]K_E_2 = 2 * K_E_1\\\\\frac{1}{2}mv_2^2 = 2 * ( 112.5 * m)\\\\\frac{1}{2}mv_2^2 = 2m( 112.5)\\\\v_2^2 = 4( 112.5)\\\\v_2^2 = 450\\\\v_2 = \sqrt{450}\\\\v_2 = 21.21m/s[/tex]
Therefore, for the car to be able to double its kinetic energy, it would need to travel at a speed of approximately 21.21m/s.
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Can you make predictions about what will happen in a crash when
you know the object's momentuo?
LAB SCIENCE
Which describes an interaction in which organisms work together so that all organisms in the group benefit? cooperation parasitism commensalism competition
Answer:
Cooperation
Explanation:
Cooperation: Both organisms benefit in the relationship.
Parasitism: One organism benefits and the other is harmed in this relationship.
Commensalism: One organism benefits, while the other neither benefits of is harmed.
Competition: Organisms compete for resources.
The option that describes an interaction in which organisms work together so that all organisms in the group benefit is known as Cooperation.
What is Species interaction?Species interaction may be defined as a type of process through which the population of one species interacts with the population of other species that significantly lives in the same locality. This process either benefits or harm the population.
The categories of species interaction are as follows:
Cooperation: It is a type of +,+ interaction where both organisms benefit in the relationship. This is also known as mutualism. Parasitism: It is a type of +,- interaction where one organism benefits and the other is harmed. Commensalism: It is a type of +,0 interaction where one organism benefits, while the other neither benefits nor is harmed.Competition: It is a type of -,- interaction where both organisms are harmed and compete for the same resources.Therefore, the option that describes an interaction in which organisms work together so that all organisms in the group benefit is known as Cooperation.
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I need the answer asap thank you !!!
Answer:
whats the question??????
the pilot of a new stealth helicopter which has a mass of 15000 kg and was traveling 180 m / s accelerated to 250 m / s in six seconds to make sure he could rescue those in need how much force was used to accelerate the helicopter and what was the helicopters final momentum
Answer:
pf = 3750000 kg.m/s
F = 175000 N
Explanation:
Constant Acceleration
An object moves with constant acceleration if its velocity changes uniformly in time.
If we call vo to the initial speed, vf the final speed, and t the time, then the acceleration is calculated as:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
The new stealth helicopter was traveling at vo=180m/s and changed to vf=250 m/s in t=6 seconds, thus the acceleration was:
[tex]\displaystyle a=\frac{250-180}{6}[/tex]
[tex]a=11.67~m/s^2[/tex]
Please note this number is shown rounded to the nearest hundredth, but it was stored in the calculator's memory with full precision. This fact affects the next calculation as will be noted below.
The acceleration must be produced for some net force that can be calculated by:
F = m.a
Where m=15000 Kg is the mass of the helicopter. Thus:
F = 15000 * 11.67
F = 175000 N
The above product would lead to the inaccurate result of 175050 if the acceleration would have not used with its full representation in the calculator's memory.
The momentum of an object of mass m and velocity v is:
p = m. v
The final momentum of the helicopter is:
pf = m.vf = 15000*250 m/s
pf = 3750000 kg.m/s
Note: When performing calculations over intermediate results, it's important to keep them as accurate as possible to preserve the accuracy of the final result.
Each mass in the figure is 3 kg. Find the magnitude and direction of the net gravitational force on mass A due to the other masses.
A. 2.45 × 10–7 N toward B
B. 3.75 × 10–7 N toward C
C. 2.00 × 10–7 N toward D
D. 1.15 × 10–7 N toward D
Answer:
THE ANSER IS B
Explanation:
The magnitude and direction of the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.
The gravitational force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. In this case, all of the masses are equal to 3 kg, and the distance between mass A and mass D is 3 m.
The gravitational force between mass A and mass D is therefore:
F = G * m_A * m_D / r²
= 6.674 × 10⁻¹¹ N m² / kg² * 3 kg * 3 kg / 3 m²
= 1.15 × 10⁻⁷ N
The direction of the gravitational force is towards mass D.
Therefore, the net gravitational force on mass A due to the other masses is 1.15 × 10⁻⁷ N toward D.
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a sample of steam at 15 bar pressure and 400°c temperature is first expanded at a constant enthalpy to 6 bar and then expanded isentropically where the dryness fraction of the steam is 0.90. find the change of enthalpy, the pressure of isentropically expanded steam and change of entropy.
Answer:
Answer.
Explanation:
Explanation.
How should the student change the circuit to give negative values for current and
potential difference?
Answer:
Reversing the polarity of the battery reverses the polarity in the circuit.
Explanation:
In a DC circuit, the polarity of the potential difference and the current is determined by the polarity of the battery or the power source.
Reversing the polarity of the battery reverses the polarity in the circuit.
In the case of current, the direction of the movement of the electrons is reversed and in the case of the potential difference, this is measured with respect to a minimum fly in general taken as zero.
Freida wants to model the way atoms move when a substance changes its state. To do this, Freida makes a pyramid of marshmallows. Then, she knocked down the pyramid causing the marshmallows to fall. If the marshmallows represent the atoms in the substance, which change of state is Freida modeling?
Answer:melting 2020 edge
Explanation:
:)
Answer:
Melting
Explanation:
A film of soapy water ( n= 1.33 ) on top of a plastic cutting board has a thickness of 233 nm. What color is most strongly reflected if it is illuminated perpendicular to its surface?
Answer:
620nm
Explanation:
According to the question,
Refractive index, n = 1.33Thickness, t = 233 nmAs we know,
→ [tex]t = \frac{\lambda}{2n}[/tex]
or,
→ [tex]\lambda = 2tn[/tex]
By putting the values, we get
[tex]= 2\times 233\times 10^{-9}\times 1.33[/tex]
[tex]= 620 \ nm[/tex]
Thus the above response is correct.
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What is the approximate efficiency of the engine?
A heat engine has a temperature of 1800 K. Some of the
heat from the engine flows to the surroundings, which
are at a temperature of 160 K.
0 16%
O 91%
O 103%
O 109%
Answer:91% I think
Explanation:
The typical engine efficiency for a modern petrol combustion engine is from 20 to 30 percent. The remaining 70 to 80 percent of the heat energy of the petrol is released from the engine as friction loss, mechanical sound energy, or exhaust heat. Thus, option B is correct.
What approximate efficiency of the engine?An engine's efficiency is measured by the heat produced divided by the amount of useful work done. Is the task complete. Is the task finished. Please be aware that the phrase “work done” refers to the force applied to the clutch or driveshaft.
Utilizing the following formula, efficiency may be represented as a ratio: output input. Output, often called work output, is the entire quantity of productive work completed, excluding waste and spoilage.
You may determine the efficiency by figuring out what proportion of the energy input results in the desired output: Efficiency is defined as Energy Out/Energy In 100%.
Therefore, This implies that the work produced by thermodynamic expansion is reduced by the friction and other losses.
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A loop of radius r = 3.0 cm is placed parallel to the xy-plane in a uniform magnetic fieldB= 0.75 Tˆk. The resistance of the loop is 18 Ω. Starting at t = 0, the magnitude of thefield decreases uniformly to zero in 0.15 seconds. What is the magnitude of the electric currentproduced in the loop during that time?
This question is incomplete, the complete question is;
A loop of radius r = 3.0 cm is placed parallel to the xy-plane in a uniform magnetic field B = 0.75 Tˆk.
The resistance of the loop is 18 Ω. Starting at t = 0, the magnitude of the field decreases uniformly to zero in 0.15 seconds.
What is the magnitude of the electric current produced in the loop during that time?
Answer
a 2.1 mA
b 0.79 mA
c 1.7 mA
d 0.20 mA
e 3.9 mA
Answer: option (b) 0.79 mA is the correct answer
Explanation:
Given that;
radius r = 3 cm = 0.03 m
Magnetic field B = 0.75
Resistance R = 18
time t = 0.15s
Area A = πr² = π(0.03)² = 0.002827 m²
we know that
Induced EMF ∈ = -BA / T
and ∈ is also = IR
so, IR = -BA/t
I = -BA / Rt
we substitute our values into the equation
I = [- (-0.75 × 0.002827)] / [18 × 0.15]
= 0.002120 / 2.7
= 0.0007851 A ≈ 0.00079 A ≈ 0.79 mA ( milliamperes )
Therefore option (b) 0.79 mA is the correct answer
Why would a baseball traveling at 20 m/s have more kinetic energy than a baseball traveling at 5 m/s?
Answer:
because formula of kinetic energy is K=1/2mv^2 that means more the velocity then more kinetic energy
A dog walks 24 steps north and then walks 55 steps west to bury a bone. If the dog walks back to the starting point in a straight line, how many steps will the dog take and in which direction will the dog walk? On paper, use the graphical method to find the magnitude of the net displacement.
Answer:
The dog should walk 60 steps to the southeast to return to its starting point.
Explanation:
To solve the present mathematical problem, we must use the Pythagorean theorem. This establishes that in right triangles the sum of their squared legs is equal to the hypotenuse squared, that is:
A ^ 2 + B ^ 2 = X ^ 2
Thus, in the case, the calculation would be the following:
24 ^ 2 + 55 ^ 2 = X ^ 2
576 + 3,025 = X ^ 2
√3,601 = X
60 = X
Therefore, the dog should walk 60 steps to the southeast to return to its starting point.
From the 1780s to the late 1800s, people thought the amount of land and resources in the West was limited
Answer:true
Explanation:
A bag of groceries has a weight of 44 Newton’s. Find it’s mass in kilograms
Answer:
It's mass would be 4.486768kg..
A Young's double-slit experiment is performed using light that has a wavelength of 631 nm. The separation between the slits is 5.25E-5 m. Calculate the angle that locates the first-order bright fringes on the screen.
Answer:
θ = 1.21 10⁻² rad
Explanation:
The double slit experiment is described for constructive interference
d sin θ = m λ
where d is the separation between the slits, λ the wavelength used, m a stereo that represents the order of interference
The first order of interference corresponds to m = 1 and the separation of the slits is d = 5.2 10⁻⁵ m
sin θ = m λ / d
θ = sin⁻¹ (m λ / d)
let's calculate
θ = sin⁻¹ (1 631 10⁻⁹ / 5.2 10⁻⁵)
θ = 1.21 10⁻² rad
The earth rotates every 86,160 seconds. What is the tangential speed (in m/s) at Livermore (Latitude 37.6819° measured up from equator, Longitude 121.
Answer:
The tangential speed at Livermore is approximately 284.001 meters per second.
Explanation:
Let suppose that the Earth rotates at constant speed, the tangential speed ([tex]v[/tex]), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:
[tex]v = \left(\frac{2\pi}{\Delta t}\right)\cdot R \cdot \sin \phi[/tex] (1)
Where:
[tex]\Delta t[/tex] - Rotation time, measured in seconds.
[tex]R[/tex] - Radius of the Earth, measured in meters.
[tex]\phi[/tex] - Latitude of the city above the Equator, measured in sexagesimal degrees.
If we know that [tex]\Delta t = 86160\,s[/tex], [tex]R = 6.371\times 10^{6}\,m[/tex] and [tex]\phi = 37.6819^{\circ}[/tex], then the tangential speed at Livermore is:
[tex]v = \left(\frac{2\pi}{86160\,s} \right)\cdot (6.371\times 10^{6}\,m)\cdot \sin 37.6819^{\circ}[/tex]
[tex]v\approx 284.001\,\frac{m}{s}[/tex]
The tangential speed at Livermore is approximately 284.001 meters per second.
I'm not quite sure how the formula works. I thought it was
55*6*9.81 = N
Weight * acceleration * gravity = N
My answer was wrong. Could anyone help me understand this question, please?
"When landing after a spectacular somersault, a 55.0 kg gymnast decelerates by pushing straight down on the mat. Calculate the force (in N) she must exert if her deceleration is 6.00 times the acceleration of gravity."
Answer:
See the explanation below.
Explanation:
Of course yes, after my explanation you will understand very well how to analyze this type of problems.
First, we must differentiate the weight of the mass, the mass has units of kilograms or pounds, while the weight is the product of the mass by gravitational acceleration. In this way, we have the following formula for the weight of anybody.
w = m*g
where:
w = weight [N] (units of Newtons]
m = mass [kg]
g = gravity acceleration = 9.81 [m/s²]
When we have the product of these units [kg]*[m/s²], We are always going to get as a result the units of Newtons [N], The Newton is a unit of force.
Now, to solve this problem we must use Newton's second law, which tells us that the sum of forces on a body must be equal to the product of mass by acceleration.
ΣF = m*a
where:
ΣF = forces acting over the gymnast [N]
m = mass = 55 [kg]
a = desacceleration = 6*9.81 = 58.86 [m/²]
Now we have two forces acting over the gymnast the first one is his or her weight (the mass by the gravity acceleration) and the second force is the one made it by his or her legs upwards in order to be standing. Let's take as positive signs the movements and forces upwards and negative downwards
- (m*g) + Fl = m*a
where:
Fl = force made it by the legs [N]
As the deceleration is upward because it prevents the person from continuing to go down, it is taken as a positive sign.
- (55*9.81) + Fl = (55*58.86)
Fl = (55*58.86) + (55*9.81)
Fl = 3776.85 [N]
I hope you can understand :)
Now write a short paragraph comparing "fast" to "speeding up quickly" and "slow" to "speeding up slowly".
Answer:ok yes
Explanation:yes of course
How much energy is transported across a 1.25 cm2 area per hour by an EM wave whose E field has an rms strength of 38.5 mV/m
Answer:
The energy transported per hour is 4.92 x 10⁻¹⁰ J.
Explanation:
Given;
root mean square strength of the field, [tex]E_{rms}[/tex] = 38.5 mV/m
area per hour, A = 1.25 cm²/hr = 1.25 x 10⁻⁴ m²/hr
The peak strength of the field is given by;
E₀ = [tex]E_{rms}[/tex]√2
E₀ = (38.5 mV)√2
E₀ = 54.45 mV
the average intensity is given by;
[tex]I_{avg} = \frac{c\epsilon E_o^2}{2}\\\\ I_{avg} = \frac{(3*10^8)(8.85*10^{-12})(54.45*10^{-3})^2}{2}\\\\I_{avg} = 3.936*10^{-6} \ W/m^2[/tex]
Energy transported per hour is given by;
[tex]E = \frac{P}{t} = \frac{I*A}{t} = (\frac{A}{t})(I)\\\\E = (1.25*10^{-4} \ \frac{m^2}{hr} )(3.936*10^{-6} \ \frac{W}{m^2} )\\\\E = 4.92*10^{-10} \ J[/tex]
Therefore, the energy transported per hour is 4.92 x 10⁻¹⁰ J.
What is the ratio of the radii of curvature for a proton and an an electron traveling through this apparatus
Answer:
hello your question is incomplete below is the missing part of the question
Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.55 T.
answer : ≈ 42
Explanation:
Ratio of the Radii of curvature for a proton and an electron travelling through this apparatus
= [tex]\frac{Rp}{Re}[/tex] = 0.025 m / 5.94 * 10^-4 m = 42.08
Rp = 0.025 m ( calculated )
Re = 5.94 * 10^-4 ( calculated )
One particle has mass m and a second particle has mass 2m. The second particle is moving with speed v and the first with speed 2v. How do their kinetic energies compare?
Answer:
Explanation:
The formula for kinetic energy to be used here is 1/2mv².
If the first particle is "particle a" and the second particle is "particle n"; there kinetic energies (K.E) will be
K.Eₐ = 1/2.m2v² = mv²
K.Eₙ = 1/2.2mv² = mv²
From the above, it can be said that there kinetic energies are the same.
NOTE that the m and v used in the question means mass and velocity respectively.
5. A man has a weight of 100 Newtons. How much work is done if he climbs 4 meters up a ladder? Plug numbers under the equation. Solve and circle your answer. Include the proper units.
Answer:
400 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 100 × 4
We have the final answer as
400 JHope this helps you
When Danny Diver who weighs 500 N steps off a diving board 10 m above the water, he hits the water with kinetic energy of
Answer:
5000 J
Explanation:
Given that,
Weight of Danny Diver, F = 500 N
He steps off a diving board 10 m above the water
We need to find the kinetic energy of the water with which it hits. Let its is K. It is given by :
E = mgh
Where g is acceleration due to gravity
[tex]E=500\ N\times 10\ m\\\\=5000\ J[/tex]
So, he hits the water with kinetic energy of 5000 J.
in the one pulley system when you move the Mass from The 20-centimeter Mark to the 15 centimeter mark it moves to my 5cm how far did you pull the string?
5 cm
10cm
15cm
20cm
Answer:
5 cm
Explanation:
Remember that in the pulley system the rope moves the same distance in both ends of the pulley, what the pulley system does is creating a mechanical advantage which basically means that it takes less effort to pull than the actual effort it would take, so for example if you have to lift a box that is 800 N, with a pulley system and the mechanical advantage you'd have to pull with less force.