Answer:
a) The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Explanation:
Let consider the bottom of the first floor in a building as the zero reference ([tex]z = 0\,m[/tex]). The change in potential energy experimented by a particle ([tex]\Delta U_{g}[/tex]), measured in joules, is:
[tex]\Delta U_{g} = m\cdot g\cdot (z_{f}-z_{o})[/tex] (1)
Where:
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Initial and final height with respect to zero reference, measured in meters.
Please notice that [tex]m\cdot g[/tex] is the weight of the particle, measured in newtons.
a) If we know that [tex]m = 3\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex] and [tex]z_{f} = 4.1\,m[/tex], then the change in potential energy is:
[tex]\Delta U_{g} = (3\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (4.1\,m-0\,m)[/tex]
[tex]\Delta U_{g} = 120.626\,J[/tex]
The change in potential energy of a 3.0 kilograms backpack carried up the stairs.
b) If we know that [tex]m\cdot g = 650\,N[/tex], [tex]z_{o} = 4.1\,m[/tex] and [tex]z_{f} = 0\,m[/tex], then the change in potential energy is:
[tex]\Delta U_{g} = (650\,N)\cdot (0\,m-4.1\,m)[/tex]
[tex]\Delta U_{g} = -2665\,J[/tex]
The change in potential energy of a persona with weight 650 newtons that descends the stairs is -2665 joules.
Ignoring mass and weight contributed by fuel, what happens when the space shuttle takes off and moves away from earth?
Answer:
Its mass increases and weight decreases. Its mass remains constant and weight decreases.
A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volume of the block. Then, use that answer to determine the density of the block. *
Answer:
6g/cm³
Explanation:
Given parameters;
Mass = 600g
Dimension = 2cm wide, 2cm tall and 25cm long
Unknown:
Density = ?
Solution
Density is the mass per unit volume of any substance. To solve this problem:
Density = [tex]\frac{mass}{volume}[/tex]
Since mass = 600g
Let us find the volume;
Volume = length x width x height
Volume = 25cm x 2cm x 2cm = 100cm³
Therefore;
Density = [tex]\frac{600}{100}[/tex] = 6g/cm³
a small glass or plastic tube that contains a piece of wire is called a circuit breaker
T or F?
Answer:
False, it is a fuse.
Explanation:
In electronics and electrical engineering, a fuse is an electrical safety device that operates to provide overcurrent protection of an electrical circuit. Its essential component is a metal wire or strip that melts when too much current flows through it, thereby stopping or interrupting the current. It is a sacrificial device; once a fuse has operated it is an open circuit, and must be replaced or rewired, depending on its type.
Fuses have been used as essential safety devices from the early days of electrical engineering. Today there are thousands of different fuse designs which have specific current and voltage ratings, breaking capacity and response times, depending on the application. The time and current operating characteristics of fuses are chosen to provide adequate protection without needless interruption. Wiring regulations usually define a maximum fuse current rating for particular circuits. Short circuits, overloading, mismatched loads, or device failure are the prime or some of the reasons for fuse operation.
A fuse is an automatic means of removing power from a faulty system; often abbreviated to ADS (Automatic Disconnection of Supply). Circuit breakers can be used as an alternative to fuses, but have significantly different characteristics.
Source: https://en.wikipedia.org/wiki/Fuse_(electrical)
A fuse is a small glass or plastic tube that contains a piece of wire. That wire is carefully calibrated so that it will only allow a certain level of current to pass through it. Any more, and the wire will melt from the heat, breaking the circuit. This means that if a power surge comes into your home, a circuit will be broken before it causes damage to your appliances.
A circuit breaker achieves the same thing, but by a different method. A circuit breaker also disconnects the circuits in your home if the current gets too large but does it using electromagnets. If the current gets high enough, then the electromagnet will become powerful enough to attract a contact and break the circuit that way.
Both circuit breakers and fuses can be used to help with another situation. If you have an appliance with a metal case and that appliance comes in contact with a live wire, it can cause you to electrocute yourself. But if that metal case is connected to a ground wire (the third pin in some plugs), then the electricity will flow through the ground wire, through the circuit breaker or fuse box, and break the circuit, stopping you from potentially getting electrocuted.
Source: https://study.com/academy/lesson/the-differences-between-fuses-circuit-breakers.html
PLEASE NEED HELP ASAP
Answer:
My youngins heartless, so they ain't playin' no games
We really want 'em dead, he got hit up close range
He fuc__ked up in the head, he wanna see some more brains
On that corner, I couldn't stay up out that do_0pe game
My cousin got indicted dealin' coc__aine
She an Insta>:gram addict, she want more fame
I used to starve, now I'm blowing up like pro__pane
Told my inner self, "I promise you I won't change"
Explanation:
Q2. Point D is located at 49.3 m above the ground. The speed of the roller
coaster at point D is 0.49 m/s. Find the speed of the roller coaster at A, B, C
and E, located at the following heights above the ground:
A - 12.4 m
B-3.2 m
C-41.8 m
E-35.3 m
HELP ME PLEASE, I'M BEING TIMED FAST
Answer:
A) Energy is tranferred from Joey to the water. The temperature of the water increases.
Explanation:
At first Joey jumps and gains a height above the water level of the pool, this way has an energy potential initial, as Joey falls into the water his speed is increased that is to say its energy potential is transformed into kinetic energy, and at the moment of impact with the water, this energy kinetic is transformed into heat which is transferred to the water. Therefore the temperature increment.
Note: This is one of the reasons why space agencies are studying spatial asteroids that are directed toward the earth, as these come with great kinetic energy, and great potential energy, if these are of a considerable size can cause catastrophic damage, even if they fall into the ocean, due to the large amount of energy which can cause the instantaneous evaporation of large amounts of water and collateral damage in other areas.
Squamous cells are basically clear, dead cells, filled with an ingredient of keratin
called eleidin.
True
False
Squamous cells, which are tiny, flat cells that resemble fish scales, are present in the tissue that makes up the skin's surface, and the lining of the digestive and respiratory systems.
What are the characteristics of Squamous cells?Simple squamous epithelial cells serve as filtration and diffusion mediators. They enable facile transmembrane transit of tiny molecules (i.e., across the membrane and through the cell) because of their straightforward and thin construction.
The centre of squamous epithelial cells, which are big, flattened cells loaded with cytoplasm, is a small, spherical nucleus. They are spherical and unevenly flat.
Therefore, The lumen is a free area that is surrounded by simple squamous epithelium. Simple squamous cells join together to produce a layered structure.
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When the 5.0 kg cylinder fell 100 m, the final temperature of the water was °C and the change in temperature was °C.
When the 5.0 kg cylinder fell 500 m, the final temperature of the water was °C and the change in temperature was °C.
Answer:
26.17
1.17
30.86
5.86
Explanation:
said they were correct on my assignment
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near . Calculate the frequency of these radio waves.
This question is not complete, the complete question is;
Amateur radio operators in the United States can transmit on several bands. One of those bands consists of radio waves with a wavelength near 20 m . Calculate the frequency of these radio waves.
Answer: frequency of the radio waves is 15 MHz
Explanation:
Given that;
wavelength λ = 20 m
we know that; Speed of light C = 3 × 10⁸ m/s
frequency f = ?
we know that;
frequency f = Speed of light C / wavelength λ
so we substitute
frequency f = (3 × 10⁸m/s) / (20m)
frequency f = 15 × 10⁶ Hz
we also know that 1 Hertz = 0.000001 Megahertz
so
frequency f = 15 × 10⁶ Hz × 0.000001
frequency f = 15 MHz
Therefore frequency of the radio waves is 15 MHz
Imagine you are ice skating with your BFF. Both of you are at rest in the middle of the ice, when you shove your BFF away from you. You have a mass of 70 kg and your BFF has a mass of 60kg. When you shove off, you are moving with a velocity of 2.5 m/s.
What should the total net momentum be after the push?
Answer:
The total net momentum after the push is 0.
Explanation:
The total net momentum is given by:
[tex] p_{f} = p_{1_{f}} + p_{2_{f}} = m_{1}v_{1} + m_{2}v_{2} [/tex]
Where:
m₁: is the mass of 70 kg
m₂: is the mass of 60 kg
v₁: is the speed of 2.5 m/s
v₂:?
To find the final momentum first we need to find the speed v₂:
[tex]m_{1}v_{1} + m_{2}v_{2} = p_{i}[/tex]
Where [tex]p_{i}[/tex] is the initial momentum = 0 (they are at rest)
[tex] v_{2} = -\frac{m_{1}v_{1}}{m_{2}} = -\frac{70 kg*2.5 m/s}{60 kg} = -2.92 m/s [/tex]
The minus sign is because the second person is moving in the opposite direction to the first person.
Now, the total net momentum is:
[tex] p_{f} = m_{1}v_{1} + m_{2}v_{2} = 70 kg*2.5 m/s + 60 kg*(-2.92 m/s) = 0 [/tex]
The final total momentum (after the push) should be zero because of momentum conservation.
Therefore, the total net momentum after the push is 0.
I hope it helps you!
Help please..................
is prey abiotic or biotic?
Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing
Answer:
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
Explanation:
From the question we are told that
Voltage decreases at [tex]\frac{dv}{dt} =-0.03volts/sec[/tex]
Resistance increase at [tex]\frac{dR}{dt}=0.02ohms /sec[/tex]
Resistance at [tex]R=100ohms[/tex]
Current at [tex]I=0.02amps[/tex]
Generally the equation for ohms law is mathematically represented as
[tex]V=IR[/tex]
Therefore
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
Generally making [tex]\frac{dI}{dt}[/tex] subject of the formula in the above equation mathematically gives
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
[tex]R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}[/tex]
[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})[/tex]
Therefore
[tex]\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))[/tex]
Generally it is given that the change in current is
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
Water falls without splashing at a rate of 0.200 L/s from a height of 3.60 m into a 0.730 kg bucket on a scale. If the bucket is originally empty, what does the scale read (in newtons) 3.20 s after water starts to accumulate in it
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
[tex]W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N[/tex]
The mass of the water accumulated in the bucket after 3.20s is:
[tex]m_w= (0.20 \ L/s) ( 3.20)s[/tex]
[tex]m _w=0.64 \ kg[/tex]
To determine the weight of the water accumulated in the bucket, we have:
[tex]W_w = m_w g[/tex]
[tex]W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)[/tex]
[tex]W_w = 6.272 \ N[/tex]
For the speed of the water before hitting the bucket; we have:
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}[/tex]
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
[tex]F = v ( \dfrac {dm}{dt} )[/tex]
[tex]F = (8.4 \ m/s)( 0.200 \ L/s)[/tex]
F = 1.68 N
Finally, the reading scale is:
[tex]F_{scale[/tex] = 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
F_scale ≈ 15.12 N
Explanation:
We are given;
Mass flow rate; m' = 0.2 l/s
Time; t = 3.2 s
Mass of bucket; m_b = 0.730 kg
Height; h = 3.6 m
Now, mass of water is;
m_w = 0.2 l/s × 3.2 s
m_w = 0.64 l
From conversion, 1 litre = 1 kg
Thus: m_w = 0.64 kg
Now, let's calculate final velocity from Newton's third equation of motion.
v² = u² + 2gh
Initial velocity is 0. Thus;
v² = 0 + 2(9.8 × 3.6)
v² = 70.56
v = √70.56
v = 8.4 m/s
Now, total mass of water and bucket is;
m_t = m_w + m_b = 0.64 + 0.73
m_t = 1.37 kg
Force on the scale is calculated from;
F_scale = (m_t)g + (m_w)v/t
F_scale = (1.37 × 9.81) + (0.64 × 8.4/3.2)
F_scale ≈ 15.12 N
To move the Center of Gravity (CG) forward, you could do which of the following?
Add clay to the nose.
Increase the density of the nose material.
Decrease the volume of the horizontal and vertical stabilizer material.
All of the above.
its not Increase the density of the nose material bc i tried that so help pleasee
Answer:
I think it's no. 3
Decrease the volume of the horizontal and vertical stabilizer material.
Explanation:
Lemme know if it's correct
Answer:
all of the above
Explanation:
On a sunny day, a family decided to take sail on a nearby lake. During sailing the wind applies a force of 25N north on the sails of the sailboat. The
water however exerts a force of 20 N east. If the total mass of both the sailboat and the crew (family on board) is 20kg, what is the magnutude and
direction of the acceleration produced?
Answer:
its n
Explanation:
The acceleration of the boat is obtained as 1.6 ms-2.
We have to obtain the resultant force acting on the boat in order to obtain the acceleration of the boat.
Resultant force on the boat = √(25)^2 + (20)^2 = √625 + 400 = 32 N
Now recall that from Newton's laws; F = ma
m= mass of the body
a = acceleration of the body
32 N = 20Kg × a
a = 32 N/20Kg
a = 1.6 ms-2
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In the first 2 seconds of a race, an athlete accelerates constantly from 0 m/s and reaches a
speed of 9 m/s.
Calculate the acceleration of the athlete. You do not need to state the unit here.
Given :
Initial speed, u = 0 m/s.
Final speed, v = 9 m/s.
Time taken to reach that speed, t = 2 sec.
To Find :
The acceleration of the athlete.
Solution :
We know, in uniform acceleration motion :
[tex]v= u+at\\\\a = \dfrac{v-u}{t}\\\\a = \dfrac{9-0}{2}\ m/s\\\\a = 4.5 \ m/s^2[/tex]
Therefore, acceleration of the athlete is 4.5 m/s².
Yeah, so, my teacher finna kill me if I don't turn this in today..
The Fnet = m • a equation is often used in algebraic problem solving. The table below can be filled by substituting into the equation and solving for the unknown quantity. Try it yourself and then use the click on the buttons to view the answers. To get a (acceleration) by itself, you must divide net Force by mass.
Answer:
Blank 1: 10
Blank 2: 4
Blank 3: 10
Blank 4: 5
Blank 5: 5
I think about you all day and at night I watch the stars shoot
I know love is not a game but I can't control what my heart do
I messed up so many times, I know you thinking I don't want you
I never tell you lies, I'm always giving you the hard truth
Remember we was way more than friends, I just wonder, "Would you love me again?"
I'm always having spaceship vibes, sometimes I think that I'm an alien
What is this song?
Answer:
Spaceship Vibes
Explanation:
Song written by NoCap
Describe what determines magnetism and how an electromagnet works.
Answer:
Magnetism is the force exerted by magnets when they attract or repel each other
hope it helps you:)
Assess It! Question #2: Which of the following statements about the Law
of Acceleration is true?
5 points
A: Increasing an object's mass decreases the amount of force required to move it
B: Decreasing the mass of an object increases its acceleration while force is
constant
C: Increasing the force applied to an object does not change its acceleration while
mass is constant
D: Decreasing the force applied to an object increases its acceleration while mass is
constant
Answer:
Statement B is the only true statement
"Decreasing the mass of an object increases its acceleration while force is constant."
Explanation:
Recall that Newton's 2nd Law states:
F = m * a
Therefore, if the force (F) is constant, and the mass (m) decreases, the acceleration (a) of the object must increase.
This agrees with the statement labeled as B: "Decreasing the mass of an object increases its acceleration while force is constant."
The true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.
NEWTON'S LAW:
The relationship between the force, mass and acceleration has been explained by Newton in his law. The equation is as follows:Force = mass × accelerationAccording to the equation, the mass is inversely proportional to the acceleration. This means that as the mass increases, the acceleration decreases and vice versa. Therefore, the true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.Learn more at: https://brainly.com/question/25116504?referrer=searchResults
Free association and dream analysis are techniques used in psychoanalysis to discover a person’s unconscious urges.
Please select the best answer from the choices provided
True or False?
Answer:
T on edge
Explanation:
Answer:
true
Explanation:
A ball is thrown upward and reaches a maximum height of 20 meters and then returns back to where it was launched. What is the displacement of the ball?
Answer: 0
Explanation: because when it return total displacement is 0
A bat with a force of 50 N hits a softball with a mass of 0.5 kg. What will the softball's acceleration rate be?
Answer:
100m/s²
Explanation:
F=ma
50=0.5a
a=50/0.5
a=100
What is the approximate momentum of a car with a mass of 1200 kg and a
velocity of 30.0 km/h? *
A. 13.0 N.S
B. 40.0 N.S
C.3.60 104 N.S
D. 5.40 x 104 N.S
an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a
Answer:
force; distance; energy.
Explanation:
An impulse can be defined as the net force acting an object for a very short period of time.
Mathematically, impulse is given by the formula;
[tex] Impulse = force * time[/tex]
An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.
Mathematically, work done is given by the formula;
[tex] Work done = force * distance [/tex]
Need help fast pls thanks
Answer:
We need the question
Explanation:
The answer is the first choice.
When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory
Answer:
A circle.
Explanation:
When a charged particle moves perpendicularly to a uniform magnetic field, what best describes its trajectory is a circle.
This ultimately implies that, a charged particle moving perpendicularly to a uniform magnetic field would undergo or experience a uniform circular motion and this simply, describes its trajectory.
Additionally, the frequency would be directly proportional to the mass of the charged particle.
what is work? how do we solve for work?
Answer: Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
Answer:Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.
Explanation:
Two rope tows operate on the same ski slope. Tow A with a heavier load pulls as fast as Tow B. Which does the most work? Which has the most power?
Answer:
tow a has the most power but tow b does the most work
Explanation:
Tow A with a heavier load pulls as fast as Tow B, Then A does The most work, and A also has more power.
What is power?It is defined as the Rate of work done or the ratio of work done and time.
If the amount of work(W) is down over a time interval of (t) then the power is given by,
P=W/t
Where W=is work done by a force is known as a product of force and distance.
t= time interval in s.
Force
F= force which is known as the rate of momentum.=mv/t
where m= mass of the body in kg.
v= velocity in m/s.
Here in the question, given that A pulls heavier weight than B that means A applied more force which results in more work.
When more work is done by A than by B then the power of an also greater than B because they move at the same velocity.
Hence, The Work done as well as the power of A is more.
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