two capacitor, c1 = 6.00 uf and c2 = 11.0 uf, are connected in parallel, and resulting combination is connected to a 9v battery .
(a) What is the equivalent capacitance of the combination?
µF
(b) What is the potential difference across each capacitor?
C1 = V
C2 = V
(c) What is the charge stored on each capacitor?
C1 = µC
C2 = µC

Answer:

Step-by-step explanation:

a) The function f(t) that models the number of bears t years after 2012 can be expressed using exponential decay, as follows:

f(t) = 965 * (0.98)^(t)

Where 0.98 represents the rate of decline of 2% per year. The starting point for t is 0, which corresponds to the year 2012.

b) To find the population of bears predicted to be in 2020, we need to evaluate f(8) since 2020 is 8 years after 2012:

f(8) = 965 * (0.98)^(8)

= 834.84 (rounded to two decimal places)

Therefore, the predicted population of bears in 2020 is approximately 835.

The line integral ∫(2x+4y)ds over the curve C is evaluated.

Given the vector function r(t) = ⟨2t, 3t^2⟩, the curve C is the parametric equation of the path of integration. To find the line integral, we first find the derivative of r(t) with respect to t, which is dr/dt = ⟨2, 6t⟩.

Then, we compute the magnitude of dr/dt as ds/dt = √(2^2 + 6t^2) = 2√(1+9t^2). The limits of integration are determined by the parameter t, where t goes from 0 to 1. Thus, the line integral can be evaluated as ∫(2x+4y)ds = ∫(4t+12t^2)2√(1+9t^2) dt = 32/27(10√10-1).

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The variables can be classified as follows:

i) Distance that a golf ball was hit - CQ (continuous quantitative)

ii) Size of shoe - DQ (discrete quantitative)

iii) Favorite ice cream - C (categorical)

iv) Favorite number - DQ (discrete quantitative)

v) Number of homework problems - DQ (discrete quantitative)

vi) Zip code - C (categorical)

The distance that a golf ball was hit is a continuous quantitative variable, as it can take on any value within a range. The size of shoe, favorite number, and number of homework problems are discrete quantitative variables since they represent distinct, countable values. Favorite ice cream and zip code are categorical variables, as they represent categories or groups rather than numerical values.

A continuous quantitative variable can take on any value within a certain range and can be measured on a continuous scale. In the case of the distance that a golf ball was hit, it can be measured in yards or meters, and it can have any value within that range, making it a continuous quantitative variable.

Discrete quantitative variables represent distinct, countable values. The size of a shoe, favorite number, and number of homework problems are discrete quantitative variables because they can only take on specific whole numbers or values. For example, shoe sizes are typically whole numbers, and the number of homework problems can only be a whole number count.

Categorical variables represent categories or groups. Favorite ice cream and zip code fall under this category. Favorite ice cream represents different flavors or options, which can be classified into categories such as chocolate, vanilla, strawberry, etc. Zip codes are specific codes used to identify geographic areas and are assigned to different regions, making them categorical variables.

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When events A and B are independent.

From the question, we have the following parameters that can be used in our computation:

P(A and B) = P(A) · P(B)

The above rule is used when the events A and B are independent events

This means that

The occurrence of the event A does not influence the occurrence of the event B and vice versa

Using the above as a guide, we have the following:

The correct option is (a)

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Answer: To solve the differential equation yy' - 9e^x = 0, we can use separation of variables:

y * dy/dx = 9e^x

∫ y dy = ∫ 9e^x dx

y^2/2 = 9e^x + C1

y^2 = 18e^x + C2

where C1 and C2 are constants of integration.

To find the particular solution that satisfies the initial condition y(0) = 7, we can substitute x = 0 and y = 7 into the equation y^2 = 18*e^x + C2:

7^2 = 18*e^0 + C2

49 = 18 + C2

C2 = 31

Therefore, the particular solution that satisfies the initial condition y(0) = 7 is:

y^2 = 18*e^x + 31

Taking the square root of both sides gives:

y = ± sqrt(18*e^x + 31)

Since y(0) = 7, we take the positive square root:

y = sqrt(18*e^x + 31)

We can solve this differential equation by using separation of variables. First, we rearrange the equation as:

y' = 9e^x/y

Then, we separate the variables and integrate both sides:

∫ y dy = ∫ 9e^x dx/y

1/2 y^2 = 9e^x + C

where C is an arbitrary constant of integration. To find the particular solution that satisfies the initial condition y(0) = 7, we substitute these values into the equation:

1/2 (7)^2 = 9e^0 + C

C = 49/2 - 9

C = 31/2

Therefore, the particular solution that satisfies the initial condition is:

y^2 = 18e^x + 31

or

y = ±sqrt(18e^x + 31)  (we take ± because the square of a real number is always positive)

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Tracy works at North College as a math teacher. She will be paid $900 for each credit hour she teaches. During the course of her first year of teaching, she would teach a total of 50 credit hours.

The college expects her to work a minimum of 170 days (and less and her salary would be reduced) and 8 hours each day. Her gross monthly income is $12,150.

The total number of hours Tracy works is given by;

Total number of hours Tracy works = Number of days she works in a year x Number of hours per day.

Number of days she works in a year = 170Number of hours per day = 8.

Total number of hours Tracy works = 170 × 8

= 1360.

Each credit hour Tracy teaches is paid for $900.

Therefore, for all the credit hours she teaches in a year, she will be paid for $900 × 50 = $45,000.In order to get Tracy's monthly gross income, we need to divide the total amount of money Tracy will be paid in a year by 12 months.$45,000 ÷ 12 = $3750.

Then, we can calculate the gross monthly income of Tracy by adding her salary per month and her total hourly work salary. The total hourly work salary is equal to the product of the total number of hours Tracy works and the amount she is paid per hour which is $900. Therefore, her monthly gross income will be:$3750 + ($900 × 1360) = $12,150. Answer: $12,150.

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Eli is approximately 329.75 feet away from the base of the Eiffel tower.

Given,The height of the Eiffel Tower is 1063 feet.The angle of elevation from Eli to the top of the tower is 74°.We have to find how far away Eli is from the base of the tower.To find the distance of Eli from the base of the tower, we can use the tangent function of 74°.Let x be the distance from Eli to the base of the tower, then we can find it as follows:Tan 74° = Height of the tower / Distance to the base of the towerx = Height of the tower / Tan 74°= 1063 / Tan 74°≈ 329.75 feet.

Hence, Eli is approximately 329.75 feet away from the base of the Eiffel tower.  The final answer in approximately 150 words:To find how far away Eli is from the base of the tower, we can use the tangent function of 74°. Let x be the distance from Eli to the base of the tower, then we can find it as follows:Tan 74° = Height of the tower / Distance to the base of the tower x = Height of the tower / Tan 74°= 1063 / Tan 74°≈ 329.75 feet Thus, Eli is approximately 329.75 feet away from the base of the Eiffel tower.

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There are 308 more number beef tacos than fish tacos.

Given that the cafeteria made three times as many beef tacos as chicken tacos and 50 more fish tacos than chicken tacos. They made 945 tacos in all.

Let the number of chicken tacos made be x.

Then the number of beef tacos made = 3x (because they made three times as many beef tacos as chicken tacos)

And the number of fish tacos made = x + 50 (because they made 50 more fish tacos than chicken tacos)

The total number of tacos made is 945,

Simplify the equation,

x + 3x + (x + 50)

= 9455x + 50

= 9455x

= 945 - 50

= 895x

= 895/5x

= 179

Therefore, the number of chicken tacos made = x = 179

The number of beef tacos made = 3x

= 3(179)

= 537

The number of fish tacos made = x + 50

= 179 + 50

= 229

The number of more beef tacos than fish tacos = 537 - 229

= 308.

Therefore, there are 308 more beef tacos than fish tacos.

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The evaluation of 2u + v at u = (2, -1, 2) and v = (1, 2, -2) is (5, 0, 2).

(b) The evaluation of u · v at u = (2, -1, 2) and v = (1, 2, -2) is -4.

(c) The vectors u and v make an obtuse angle.

(a) To evaluate 2u + v, where u = (2, -1, 2) and v = (1, 2, -2), we perform vector addition:

2u + v = 2(2, -1, 2) + (1, 2, -2)

      = (4, -2, 4) + (1, 2, -2)

      = (4+1, -2+2, 4+(-2))

      = (5, 0, 2)

Therefore, 2u + v = (5, 0, 2).

(b) To evaluate u.v, we perform the dot product of the vectors u = (2, -1, 2) and v = (1, 2, -2):

u.v = (2)(1) + (-1)(2) + (2)(-2)

   = 2 - 2 - 4

   = -4

Therefore, u.v = -4.

(c) To determine whether the vectors u and v make an acute, right, or obtuse angle, we can examine their dot product.

If the dot product is positive, the angle between the vectors is acute; if it is negative, the angle is obtuse; and if it is zero, the angle is right.

In this case, u.v = -4, which is negative. Hence, the vectors u and v make an obtuse angle.

Therefore, the vectors u and v make an obtuse angle.

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The reasonable prediction for the number of times a yellow paper is drawn is (d) 14

From the question, we have the following parameters that can be used in our computation:

So, we have

Total number of clips = 9 + 7 + 5 + 4

Evaluate

Total number of clips = 25

So, we have the probability of yellow to be

P(yellow) = 7/25

In a selection of 50, the expected number of times is

E(yellow) = 7/25 * 50

Evaluate

E(yellow) = 14

Hence the reasonable prediction for the number of times a yellow paper is drawn is 14

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The 5th quasi-random number in the base-5 low-discrepancy sequence is 0.2 in base-10.(C)0.5)

To determine the 5th quasi-random number in a base-p low-discrepancy sequence with a base of 5, we need to convert the decimal number 5 into base-p and find the 5th digit after the decimal point.

To convert the number 5 into base-p, we divide 5 by p and continue dividing the quotient by p until we obtain a fractional part less than 1. Let's assume that p is 10 for simplicity.

5 / 10 = 0.5

Since the fractional part is less than 1, we have our conversion: 5 in base-10 is equivalent to 0.5 in base-p.

Now, since we are looking for the 5th digit after the decimal point, we can conclude that the answer is:

c) 0.5

Please note that the exact digit in base-p may vary depending on the specific base used and the implementation of the low-discrepancy sequence.

To calculate the 5th quasi-random number in the base-5 low-discrepancy sequence, we can use the Van der Corrupt sequence formula, which is:

V(n, b) = (d_1 / b + d_2 / b^2 + ... + d-k / b^k)

where n is the index of the sequence, b is the base, and d_1, d_2, ..., d-k are the digits of n in base b.

For n = 5 and b = 5, we have k = 1 and d_1 = 1, so:

V(5, 5) = 1 / 5 = 0.2

Therefore, the 5th quasi-random number in the base-5 low-discrepancy sequence is 0.2 in base-10.

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The frequency of heterozygous individuals in the population of piranhas can be calculated using the Hardy-Weinberg equilibrium equation. The dominant allele 'A' occurs with a frequency of 0.8, Assuming that the recessive allele 'a' occurs with a frequency of 0.2 .

According to the Hardy-Weinberg equilibrium, the frequency of heterozygous individuals (Aa) can be determined using the formula 2 xp xq, where p represents the frequency of the dominant allele and q represents the frequency of the recessive allele. In this case, p = 0.8 and q = 0.2. By substituting the values into the equation, we can calculate the frequency of heterozygous individuals as follows: Frequency of heterozygous individuals = 2 x 0.8 x0.2 = 0.32. Therefore, the frequency of heterozygous individuals in the population of piranhas is 0.32, or 32% (rounded to two decimal places). This means that approximately 32% of the individuals in the population carry both the dominant and recessive alleles, while the remaining individuals are either homozygous dominant (AA) or homozygous recessive (aa).

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The focus of the parabola in this problem is given as follows:

B. (3, -1).

The equation of the parabola in this problem is given as follows:

-8(x - 5) = (y + 1)².

Hence the coordinates of the vertex are given as follows:

(5, -1).

The parameter p, used to obtain the coordinates of the focus, are given as follows:

4p = -8

p = -8/4

p = -2.

Hence the coordinates of the focus of the horizontal parabola are given as follows:

(5 - 2, -1) = (3, -1).

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The exact value of cos θ is -5/13. In quadrant III, the cosine function is negative.

In quadrant III, the sine function is negative and given as sin θ = -12/13. Using the Pythagorean identity sin^2θ + cos^2θ = 1, we can find the value of cos θ.

sin^2θ = (-12/13)^2

1 - cos^2θ = (-12/13)^2

cos^2θ = 1 - (-144/169)

cos^2θ = 169/169 + 144/169

cos^2θ = 313/169

Since θ is in quadrant III, where the cosine function is negative, we take the negative square root:

cos θ = -√(313/169)

Rationalizing the denominator:

cos θ = -√(313)/√(169)

cos θ = -√(313)/13

Therefore, the exact value of cos θ is -5/13.

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This expression can be implemented using logic gates such as AND, OR, and NOT gates.

To simplify the given expression using gates, we need to apply the Boolean laws and the distributive property. We can factor out the common terms (in_1) (in_2) and (in_0) (in_1) (in_2) from the expression. Then we can use the distributive property to combine the remaining terms. After simplification, the expression becomes out_0 = (in_1) (in_2) [(in_in_e) + (in_0) (in_) + (in_) (in_) + (in_m)]. Therefore, the simplified expression for out_0 using gates is (in_1) (in_2) [(in_in_e) + (in_0) (in_) + (in_) (in_) + (in_m)]. This expression can be implemented using logic gates such as AND, OR, and NOT gates.

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To correctly identify formatted scientific notation, we need to look for numbers expressed in the form of a × 10^b, where "a" is a number between 1 and 10, and "b" is an integer.

Here are the correctly formatted scientific notations from the options provided:

- 8 × 10^6 (this is equivalent to 8,000,000)
- 6.1 × 10^12 (this is equivalent to 6,100,000,000,000)
- 0.802 × 10^4 (this is equivalent to 8,020)
- 4.532 × 10^-9 (this is equivalent to 0.000000004532)

The other options are not in the correct scientific notation format.

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Hence, the average value of function over the given rectangle is 12.

To find the average value of the function f(x,y) = 4x²y over the rectangle with vertices (-2,0), (-2,3), (2,3), and (2,0), we need to use the formula:

fave = (1/A) * ∬R f(x,y) dA

where A is the area of the rectangle R and the double integral is taken over the region R.

First, we find the area of the rectangle R:

A = (2-(-2))*(3-0)

= 12

Next, we evaluate the double integral:

∬R f(x,y) dA = ∫[-2,2]∫[0,3] 4x²y dy dx

= ∫[-2,2] [2x²y²]0³ dx

= ∫[-2,2] 36x² dx

= 4*36

= 144

Therefore, the average value of f over the rectangle R is:

fave = (1/A) * ∬R f(x,y) dA

= 1/12 * 144

= 12

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The optimal balance of protons and neutrons depends on the specific nuclear species and can be affected by factors such as nuclear spin and nuclear excitation.

The fundamental forces that dominate nuclear structure are the strong force and the electromagnetic force. The strong force is responsible for binding protons and neutrons together in the nucleus, while the electromagnetic force is responsible for the repulsion between protons.

The gravitational force is negligible at the nuclear scale, and the weak force is responsible for nuclear decay processes.

For stable, heavy atomic nuclei, the number of neutrons is typically greater than the number of protons. This relationship occurs because additional neutrons are necessary to counteract the electrostatic repulsion generated by the increasing number of protons.

The strong force is attractive and binds protons and neutrons together, but it has a limited range and becomes weaker as the distance between nucleons increases.

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The fundamental forces that dominate nuclear structure are the strong force and the electromagnetic force.

The strong force is the force that binds protons and neutrons together in the nucleus and is stronger than the electromagnetic force. The electromagnetic force is responsible for the repulsion between the positively charged protons in the nucleus.

For stable, heavy atomic nuclei, the number of neutrons is approximately equal to the number of protons. This relationship occurs because additional neutrons are necessary to counteract the repulsion generated by the number of protons in the nucleus. This is known as the neutron-proton ratio, and it varies for different elements. The neutron-proton ratio affects the stability of the nucleus, and if it is too high or too low, the nucleus may undergo radioactive decay to achieve a more stable configuration.

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The double integral is 1270.5.

To set up a double integral that represents the area of the surface given by z = f(x, y) above the region R, where [tex]f(x, y) = x^2 - 4xy - y^2[/tex] and R = {(x, y): 0 ≤ x ≤ 9, 0 ≤ y ≤ x}.

We can express the area as the double integral of the function f(x, y) over the region R.

The double integral can be written as:

A = ∬R f(x, y) dA

where dA represents the infinitesimal area element.

Since the region R is defined by 0 ≤ x ≤ 9 and 0 ≤ y ≤ x, we can express the limits of integration for x and y accordingly. The integral becomes:

A = ∫₀⁹ ∫₀ˣ (x² - 4xy - y²) dy dx

Here, the outer integral goes from x = 0 to x = 9, and the inner integral goes from y = 0 to y = x.

The double integral to calculate the area above the region R is given by:

A = ∫₀⁹ ∫₀ˣ (x² - 4xy - y²) dy dx

Integrating the inner integral with respect to y first, we get:

A = ∫₀⁹ [x²y - 2xy² - y³/3]₀ˣ dx

Simplifying this expression, we have:

A = ∫₀⁹ (x³ - 2x²y - y³/3) dx

Now, integrating with respect to x, we get:

A = [x⁴/4 - 2x³y/3 - y³x/3]₀⁹

Substituting the limits of integration, we have:

A = (9⁴/4 - 2(9)³(9)/3 - (9)³(9)/3) - (0⁴/4 - 2(0)³(0)/3 - (0)³(0)/3)

Simplifying further, we get:

A = (6561/4 - 2(729)/3 - (729)/3) - (0)

A = 6561/4 - 1458 - 243

A = 5082/4

A = 1270.5

Therefore, the desired result is 1270.5.

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To determine the differential dy for x=1 and dx=0.15, we need to use the formula for the differential of a function: dy = f'(x) dx, where f'(x) is the derivative of the function with respect to x.

In this case, the function is y=7x^2/(x-2), so we need to find its derivative:

y' = (14x(x-2) - 7x^2)/((x-2)^2)

y' = -14x/(x-2)^2

Now, we can substitute x=1 and dx=0.15 into the formula for the differential:

dy = f'(x) dx

dy = (-14(1))/(1-2)^2 (0.15)

dy = 0.735

Rounded to four decimal places, the differential dy is 0.7350.
Hello! I'd be happy to help you with your question. To determine the differential dy, we will first find the derivative of the given equation, and then plug in the values for x and dx. Here's the step-by-step explanation:

1. Given equation: y = 7x * (2/x - 2)
2. Simplify the equation: y = 14 - 14x
3. Find the derivative (dy/dx) of the simplified equation: dy/dx = -14
4. Given values: x = 1 and dx = 0.15
5. Calculate the differential dy: dy = (dy/dx) * dx = (-14) * (0.15)

dy ≈ -2.1

So, the differential dy is approximately -2.1 when x = 1 and dx = 0.15.

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The required answer is (f −1)'(-9) = -2√13/9.

To find (f −1)'(a), we first need to find the inverse function f −1(x).

Using the given function f(x) = x3 + 7x − 1, we can find the inverse function by following these steps:
1. Replace f(x) with y:
y = x3 + 7x − 1
The informal descriptions above of the real numbers are not sufficient for ensuring the correctness of proofs of theorems involving real numbers. The realization that a better definition was needed. Real numbers are completely characterized by their fundamental properties that can be summarized

2. Swap x and y:
x = y3 + 7y − 1
3. Solve for y:
0 = y3 + 7y − x + 1
We need to find the inverse function , Unfortunately, finding the inverse function for f(x) = x^3 + 7x - 1 is not possible algebraically due to the complexity of the function. A number is a mathematical entity that can be used to count, measure, or name things. The quotients or fractions of two integers are rational numbers.

Using the cubic formula, we can solve for y:
y = [(x - 4√13)/2]1/3 - [(x + 4√13)/2]1/3 - 7/3
Therefore, the inverse function is:
f −1(x) = [(x - 4√13)/2]1/3 - [(x + 4√13)/2]1/3 - 7/3
Now we can find (f −1)'(a) by plugging in a = -9:
(f −1)'(-9) = [(−9 - 4√13)/2](-2/3)(1/3) - [(−9 + 4√13)/2](-2/3)(1/3)
(f −1)'(-9) = [(−9 - 4√13)/2](-2/9) - [(−9 + 4√13)/2](-2/9)
(f −1)'(-9) = (4√13 - 9)/9 - (9 + 4√13)/9
(f −1)'(-9) = -2√13/9

Therefore, (f −1)'(-9) = -2√13/9.

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The answer is D. 49,062.50 cubic millimeters vanilla ice cream in one chocolate dip cone holds when filled to be level with the top of the cone.

To calculate the amount of vanilla ice cream that one chocolate dip cone can hold when filled to the top, we need to find the volume of the cone-shaped space inside the cone. The formula for the volume of a cone is V = (1/3)πr^2h, where V is the volume, π is approximately 3.14, r is the radius of the cone's top, and h is the height of the cone.

Given that the radius of the inside of the cone top is 25 millimeters and the height of the inside of the cone is 102 millimeters, we can substitute these values into the volume formula.

V = (1/3) × 3.14 × 25^2 × 102

 = (1/3) × 3.14 × 625 × 102

 = 0.3333 × 3.14 × 625 × 102

 ≈ 49,062.50 cubic millimeters

Therefore, one chocolate dip cone will hold approximately 49,062.50 cubic millimeters of vanilla ice cream when filled to be level with the top of the cone.

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The number more of Michael's friends that like pizza compared to his neighbors are 2 more of his friends.

First, let's calculate how many of Michael's friends and neighbors like pizza:

55% of his 40 friends like pizza, so the number of his friends who like pizza is:

=  55 / 100 x 40

= 22

80% of his 25 neighbors like pizza, so the number of his neighbors who like pizza is :

= 80 / 100 x 25

= 20

Therefore, 2 more of Michael's friends like pizza compared to his neighbors.

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log a 343 is approximately equal to 2.535 using the given approximations of loga7≈0.845 and loga5≈0.699.

To evaluate log a343, we can use the property of logarithms that states log a (x^n) = n log a (x). We know that 343 is equal to 7^3, so we can write log a 343 as 3 log a 7. Using the approximation loga7≈0.845, we can substitute that value in for log a 7:

log a 343 = 3 log a 7
≈ 3(0.845)
≈ 2.535

Therefore, log a 343 is approximately equal to 2.535 using the given approximations of loga7≈0.845 and loga5≈0.699.

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Answer:

There are 9 Nickels & 12 Dimes.

Step-by-step explanation:

Let N = the number of nickels

Let D = the number of dimes

Each nickel is worth 0.05

Each dime is worth 0.10

So let's write some equations.

0.05N + 0.10D = 1.65

N + D = 21

We can solve by substitution.

Rewrite that 2nd equation.

N = 21-D

Now substitute that ^^^ equation into the first equation.

0.05(21-D) + 0.10D = 1.65

1.05-0.05D + 0.10D = 1.65

Combine like terms.

0.05D = 0.6

Divide both sides by 0.05

D = 12

There are 12 Dimes.

N + D = 21

N + 12 = 21

N = 21-12

N = 9

There are 9 Nickels & 12 Dimes.

Check that our answer is correct.

9(.05) + 12(.10) = 0.45 + 1.20 = 1.65

The solution of the function is y(t) = C₁(1 + t) + C₂[tex]e^t + (1/2)t^{2e^{(2t)}}[/tex]

Let's start with the homogeneous part of the equation, which is given by:

ty" − (1 + t)y' + y = 0

A function y(t) is said to be a solution of this homogeneous equation if it satisfies the above equation for all values of t. In other words, we need to plug in y(t) into the equation and check if it reduces to 0.

Let's first check if y₁(t) = 1 + t is a solution of the homogeneous equation:

ty₁'' − (1 + t)y₁' + y₁ = t[(1 + t) - 1 - t + 1 + t] = t²

Since the left-hand side of the equation is equal to t² and the right-hand side is also equal to t², we can conclude that y₁(t) = 1 + t is indeed a solution of the homogeneous equation.

Similarly, we can check if y₂(t) = [tex]e^t[/tex] is a solution of the homogeneous equation:

ty₂'' − (1 + t)y₂' + y₂ = [tex]te^t - (1 + t)e^t + e^t[/tex] = 0

Since the left-hand side of the equation is equal to 0 and the right-hand side is also equal to 0, we can conclude that y₂(t) = [tex]e^t[/tex] is also a solution of the homogeneous equation.

Now that we have verified that y₁ and y₂ are solutions of the homogeneous equation, we can move on to finding a particular solution of the nonhomogeneous equation.

To do this, we will use the method of undetermined coefficients. We will assume that the particular solution has the form:

[tex]y_p(t) = At^2e^{2t}[/tex]

where A is a constant to be determined.

We can now substitute this particular solution into the nonhomogeneous equation:

[tex]t(A(4e^{2t}) + 4Ate^{2t} + 2Ate^{2t} - (1 + t)(2Ate^{2t} + 2Ae^{2t}) + At^{2e^{2t}} = t^{2e^{(2t)}}[/tex]

Simplifying the above equation, we get:

[tex](At^2 + 2Ate^{2t}) = t^2[/tex]

Comparing coefficients, we get:

A = 1/2

Therefore, the particular solution of the nonhomogeneous equation is:

[tex]y_p(t) = (1/2)t^2e^{2t}[/tex]

And the general solution of the nonhomogeneous equation is:

y(t) = C₁(1 + t) + C₂[tex]e^t + (1/2)t^{2e^{(2t)}}[/tex]

where C₁ and C₂ are constants that can be determined from initial or boundary conditions.

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Complete Question:

Verify that the given functions y₁ and y₂ satisfy the corresponding homogeneous equation. Then find a particular solution of the given nonhomogeneous equation.

ty" − (1 + t)y' + y = t²[tex]e^{2t}[/tex], t > 0;

y₁(t) = 1 + t, y₂(t) = [tex]e^t.[/tex]

the  probability that you will either get a yellow or blue marble is (c) 0.714.

The total number of marbles in the bag is 7 + 8 + 13 = 28.

The probability of getting a yellow marble is 7/28 = 0.25.

The probability of getting a blue marble is 13/28 = 0.464.

The probability of getting either a yellow or a blue marble is the sum of these probabilities:

0.25 + 0.464 = 0.714

what is probability?

Probability is a measure of the likelihood of an event occurring. It is expressed as a number between 0 and 1, where 0 indicates that the event is impossible and 1 indicates that the event is certain to occur. Probability can also be expressed as a percentage, ranging from 0% to 100%.

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The domain of the function is R - {m} and the range of the function is (-∞, ∞).

We are given a function f: R−{n}→R defined by f(x) = (x-n)/(x-m), where m ≠ n.

To find the domain of the function, we need to consider the values of x for which the denominator (x-m) is zero. Since m ≠ n, we have m - n ≠ 0, and therefore the function is defined for all x except x = m.

Therefore, the domain of the function is R - {m}.

To find the range of the function, we can consider the behavior of the function as x approaches infinity and negative infinity. As x approaches infinity, the numerator (x-n) grows without bound, while the denominator (x-m) also grows without bound, but at a slower rate. Therefore, the function approaches positive infinity.

Similarly, as x approaches negative infinity, the numerator (x-n) becomes very negative, while the denominator (x-m) also becomes very negative, but at a slower rate. Therefore, the function approaches negative infinity.

Thus, we can conclude that the range of the function is (-∞, ∞).

In summary, the domain of the function is R - {m} and the range of the function is (-∞, ∞).

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