help me plz!!!!
a. Calculate the solution concentration for each of the HCl samples. The first one has been done for you.
b. As the concentration of the HCl solution increased, did the speed of the reaction increase or decrease?
c. Therefore, as the concentration of a reactant increases, does the rate of the reaction increase or decrease?
d. Do your predictions previous to this investigation agree with your results?
e. Make a general rule about the effects of concentration of reactants on reaction rates.
Answer:
From this solution, you can do the a number question answer.
A vehicle is moving with a velocity of 20 m/s.how far does it moves in one hrs
How does the alcohol enter the body? Describe the process. Where does most of the absorption take place?
Explanation: Once swallowed, a drink enters the stomach and small intestine, where small blood vessels carry it to the bloodstream. Approximately 20% of alcohol is absorbed through the stomach and most of the remaining 80% is absorbed through the small intestine.
If an equilibrium system contains gaseous reactants and/or products, a change in volume will cause a change in concentration and pressure. A decrease in volume will cause the system to shift in the direction that produces _____ moles of gas in total, whereas an increase in volume causes a shift in the direction that produces _____ moles of gas in total.
Answer:
Less
More
Explanation:
When a constraint is imposed on a reaction system in equilibrium, the equilibrium position will shift in such a way as to annul the constraint.
When the volume of a reaction system in equilibrium is decreased, the equilibrium position will shift in the direction having less total number of moles.
Similarly, when the volume is increased, the equilibrium position shifts to the direction having a greater total number of moles.
3) The spectrum of the unknown mixture is a mixture of two substances among the five. What are these two substances
Answer:
a. H + d. Na
Explanation:
This is Mixture of H and Na. Because of H and in the emission and Absorption spectrum of H Total 5 lines [Red, Green, Blue and Purple (2)) are present and in the spectrum of Na Two yellow lines are present. In the mixture all this lines are are also 5 + Present. Total lines are 5+2= 7 (H+ Na)
Therefore, the answer is a. H + d. Na
How many cm3 in a L?
calculate the mass of solute in 500cm³ of 1.5mol/dm³ sodium hydroxide solution
Answer: The general formulae for moles is n=m/mr so now we have being given to find the mass so all we have to do is to change subject
Explanation: so we have to change subject in this question to m= n× mr . so in the question below we have being given the mole as 1.5mol/dm³ so all we have to do is to find the molecular relative mass(mr) .
to find the molecular relative mass of sodium hydroxide (NAOH) we add all of the atomic masses of all the atoms present so here we have sodium oxygen and hydrogen atoms present.
NA=23 O=16 H=1 so we add 23+16+1=40 so 40 is our molecular relative mass
now we fix it in our formulae which is m=n× mr
m=1.5× 40 =60 so our mass is 60grams or 60g
HOPE THIS HELPS!!!! if i made a mistake our MAY answer may be wrong feel free to comment
When triglycerides are metabolized, ___ is/are converted to pyruvate or glucose, whereas ____ is/are converted to acetyl CoA.
Answer:
Glycerol;Pyruvate
Explanation:
Metabolism of triglycerides occur through a process known as lipolysis. During triglyceride metabolism, Glycerol is converted to pyruvate or glucose through glycolysis or gluconeogenesis respectively. Glycerol enters these pathways by being converted to glycerol-3-phosphate (reaction catalyzed by glycerol kinase) which can in turn be converted to dihydroxyacetone phosphate (reaction catalyzed by glycerol-3-phosphate dehydrogenase).
NOTE: Dihydroxyacetone phosphate is a compound/substrate found in both glycolysis and gluconeogenesis.
The end product of glycolysis is pyruvate; this pyruvate, under aerobic condition is converted to acetyl coA (reaction catalyzed by pyruvate dehydrogenase complex), an intermediary of the Tricarboxylic acid cycle.
How long would it take Jesse, with an acceleration of -2.50 m/s², to bring his bicycle, with an initial velocity of 13.5 m/s, to a complete stop?
Answer:
i am so sorry. i do not have a answer but i am trying to find questioms i can answer
The elements beryllium, calcium, and strontium are all in group 2. What is the correct relationship of these elements regarding their ionization energy?
Answer: The correct relationship of these elements regarding their ionization energy is Strontium < Calcium < Beryllium.
Explanation:
The amount of energy required to remove the most loosely bound electron in an atom is called ionization energy.
Larger is the size of an atom, more easily it can lose an electron. Since the size of atoms increases on moving down in a periodic table so ionization energy decreases down the group.
For example, beryllium, calcium, and strontium are elements of group 2. Strontium is the largest in size and beryllium is the smallest in size.
Hence, the ionization energy of group 2 elements in the increasing order is as follows.
Strontium < Calcium < Beryllium
Thus, we can conclude that the correct relationship of these elements regarding their ionization energy is Strontium < Calcium < Beryllium.
necesito que me ayuden a resolver lo de las imágenes por favor ... es urgente
In the experiment "Beer-Lambert’s Law and Spectrophotometry", you prepared a calibration plot similar to the one pictured below. What is the approximate concentration of a solution whose absorbance is 0.35?
Answer:
0.025M
Explanation:
As you must see in your graph, each concentration of the experiment has an absorbance. Following the Beer-Lambert's law that states "The absorbance of a solution is directely proportional to its concentration".
At 0.35 of absorbance, the plot has a concentration of:
0.025MUn medicamento corresponde a una disolución de "nafazolina" (sustancia activa) en agua purificada, en una concentración de 12% V/V. - EXPLICA cuánto soluto hay por cada 100mL del medicamento.
Answer:
12 mL
Explanation:
Según la pregunta;
V / V% concentración del fármaco = 12%
volumen de la solución = 100 ml
De;
V / V% = volumen de fármaco / volumen de solución
volumen de fármaco = V / V% × volumen de solución
volumen de fármaco = 12/100 × 100
= 12 mL
What is the equilibrium constant of pure water at 25°C
For the equilibrium
2H2S(g) ⇋ 2H2(g) + S2(g) Kc = 9 .0X 10-8 at 700°C
the initial concentrations of the three gases are 0.300 M H2S, 0.300 M H2, and 0. 1 50 M S2' Determine the equilibrium concentrations of the gases.
Answer:
Equilibrium concentrations of the gases are
[tex]H_2S=0.596M[/tex]
[tex]H_2=0.004 M[/tex]
[tex]S_2=0.002 M[/tex]
Explanation:
We are given that for the equilibrium
[tex]2H_2S\rightleftharpoons 2H_2(g)+S_2(g)[/tex]
[tex]k_c=9.0\times 10^{-8}[/tex]
Temperature, [tex]T=700^{\circ}C[/tex]
Initial concentration of
[tex]H_2S=0.30M[/tex]
[tex]H_2=0.30 M[/tex]
[tex]S_2=0.150 M[/tex]
We have to find the equilibrium concentration of gases.
After certain time
2x number of moles of reactant reduced and form product
Concentration of
[tex]H_2S=0.30+2x[/tex]
[tex]H_2=0.30-2x[/tex]
[tex]S_2=0.150-x[/tex]
At equilibrium
Equilibrium constant
[tex]K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}[/tex]
Substitute the values
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
[tex]9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}[/tex]
By solving we get
[tex]x\approx 0.148[/tex]
Now, equilibrium concentration of gases
[tex]H_2S=0.30+2(0.148)=0.596M[/tex]
[tex]H_2=0.30-2(0.148)=0.004 M[/tex]
[tex]S_2=0.150-0.148=0.002 M[/tex]
what kind of food preserve for curing
Answer:
bitter leaf soups
Explanation:
because it cures gems out our body system
I am so lost Helppp! step by step would be great and any links would help!
Answer: i dont know
Explanation:
Under which conditions is a reaction spontaneous?Edmentum.
Answer:
When ΔS > 0 and ΔH < 0, the process is always spontaneous as written. When ΔS < 0 and ΔH > 0, the process is never spontaneous, but the reverse process is always spontaneous. When ΔS > 0 and ΔH > 0, the process will be spontaneous at
Explanation:
What are the best conditions to lead towards a spontaneous reaction? high negative enthalpy, high temp, high positive entropy. Your enthalpy is high and negative but your entropy is also negative.
CAN SOMEONE PLEASE ANSWER THIS PAGE ILL GIVE YOU ALL MY POINTS
Answer: the equation for the reaction is NH4Cl (s) --> NH3 (g) + HCl (g)
equation for heat reaction:
ΔH25° = (ΔH25° NH3 + ΔH25° HCl) - ΔH25° NH4Cl)
question 2:
the 1st and 3rd reactions are better ontained through refrence sources and the 2nd and 4th are the easiest and safest to measure in the laboratory. The 1st and rd reaction contains noxious gases this is because there is a (g) in both of the reactions. And the 2nd and 4th does NOT contain noxious gases so i assume its the safest to measure out in the lab
different oil refineries in UAE
Answer:
Petroleum refinery capacity in the UAE 2009-2018
In 2018, the total production capacities of all refineries in the UAE were 1.13 metric barrels per day. Total total production capacity of the al-Ruwais refinery in the United Arab Emirates was approximately 817,000 metric barrels per day.
HELP ASAP!! PLEASE !!
Answer:
8,3, 7,7
Explanation:
Question 1 of 10 What would be a good description of what activating prior knowledge means? O
A. Prior to reading, look at the end of the book or article.
O B. Before you read, recall knowledge you already have about the subject.
O C. Before you read, think about what you hope to learn.
O D. Before reading, find other material that is similar to what you are going to read
Answer:
B
Explanation:
Because activating prior knowledge means getting what you already know on the subject.
From the options provided for each element below, choose the properties that it may have based on its location in the periodic table.
Fluorine (F):
highly reactive nonmetal
shiny
a conductor
Answer:
highly reactive nonmetal
Explanation:
Fluorine is a member of group 7 elements on the periodic table called HALOGENS. Just like other members of its group like chlorine, iodine etc., fluorine is a nonmetallic element. Fluorine is regarded as the most reactive element on the periodic table because of its affinity to accept electrons i.e. most electronegative element.
According to this question, fluorine is an highly reactive nonmetal based on its location on the periodic table.
Answer:
highly reactive nonmetal
Explanation:
edge 21
Why is the amount of gas collected in one of the test tubes in Activity 1.7 double of the amount collected in the other? Name this gas.
For class 10th
Answer:
Water contains two parts of hydrogen and one part oxygen. Therefore, during the electrolysis of water the amount of hydrogen has collected in one of the test tubes is double than that of the oxygen produced and collected in the other last tube.
The structure shown is an example of what kind of molecule?
A) Ether
B) Alkene
C) Polymer
D) Monomer
Answer:
i think its C polymer hope it helps
Automobile airbags inflate due to the formation of nitrogen gas from the chemical reaction 2NaN3(s)—> 3N2(g)+2Na(s) Identify the number of each atom in the reactants and products for this balance reaction.
If the elements W, X, Y, and Z have electronegativity values of 1.0, 2.0, 2.5, and 3.5, respectively, which bond is the least polar
Answer:
XY bond is the least polar
Explanation:
Given
[tex]W = 1.0[/tex]
[tex]X = 2.0[/tex]
[tex]Y = 2.5[/tex]
[tex]Z = 3.5[/tex]
Required
The least polar bond
First, we calculate the difference in the electronegativities
[tex]WX = X - W[/tex]
[tex]WX = 2.0 - 1.0[/tex]
[tex]WX = 1.0[/tex]
[tex]WY = Y - W[/tex]
[tex]WY =2.5 - 1.0[/tex]
[tex]WY =1.5[/tex]
[tex]WZ =Z-W[/tex]
[tex]WZ =3.5 - 1.0[/tex]
[tex]WZ =2.5[/tex]
[tex]XY = Y -X[/tex]
[tex]XY = 2.5 -2.0[/tex]
[tex]XY = 0.5[/tex]
[tex]XZ = Z -X[/tex]
[tex]XZ = 3.5 -2.0[/tex]
[tex]XZ = 1.5[/tex]
[tex]YZ = Z - Y[/tex]
[tex]YZ = 3.5 - 2.5[/tex]
[tex]YZ = 1.0[/tex]
The least of the above calculations will be the least polar.
Hence, XY is the least polar
What are the prefixes for molecular compounds?
Answer:
In nomenclature of simple molecular compounds, the more electropositive atom is written first and the more electronegative element is written last with an -ide suffix.
The Greek prefixes are used to dictate the number of a given element present in a molecular compound.
Prefixes can be shortened when the ending vowel of the prefix “conflicts” with a starting vowel in the compound.
Common exceptions exist for naming molecular compounds, where trivial or common names are used instead of systematic names, such as ammonia (NH3) instead of nitrogen trihydride or water (H2O) instead of dihydrogen monooxide.
Terms
nomenclatureA set of rules used for forming the names or terms in a particular field of arts or sciences.
electronegativeTending to attract electrons within a chemical bond.
electropositiveTending to not attract electrons (repel) within a chemical bond.
Chemical Nomenclature
The primary function of chemical nomenclature is to ensure that a spoken or written chemical name leaves no ambiguity concerning to what chemical compound the name refers. Each chemical name should refer to a single substance. Today, scientists often refer to chemicals by their common names: for example, water is not often called dihydrogen oxide. However, it is important to be able to recognize and name all chemicals in a standardized way. The most widely accepted format for nomenclature has been established by IUPAC.
Molecular compounds are made when two or more elements share electrons in a covalent bond to connect the elements. Typically, non-metals tend to share electrons, make covalent bonds, and thus, form molecular compounds.
Rules for Naming Molecular Compounds:
Remove the ending of the second element, and add “ide” just like in ionic compounds.
When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.
If there is only one of the first element, you can drop the prefix. For example, CO is carbon monoxide, not monocarbon monoxide.
If there are two vowels in a row that sound the same once the prefix is added (they “conflict”), the extra vowel on the end of the prefix is removed. For example, one oxygen would be monooxide, but instead it’s monoxide. The extra o is dropped.
Generally, the more electropositive atom is written first, followed by the more electronegative atom with an appropriate suffix. For example, H2O (water) can be called dihydrogen monoxide (though it’s not usually). Organic molecules (molecules made of C and H along with other elements) do not follow this rule.
Here are the prefixes in naming molecular compounds:
Mono- 1
Di- 2
Tri- 3
Tetra- 4
Penta- 5
Hexa- 6
Hepta- 7
Octa- 8
Nona- 9
Deca- 10
Molecular compounds are named using a systematic approach of prefixes to indicate the number of each element present in the compound.
I hope it helps ●~●
#CarryOnLearningThe true value was 0.120. What was your percent error?
The question is incomplete as the measured value isn't given. However, an hypothesized measured value will be used to explain how to calculate the percentage error.
Answer:
2.5%
Explanation:
Percentage error :
[(measured value - True value)/ True value] * 100%
The measured value is the value obtained during an while using a measuring device.
If the measured value is = 0.123
Then, the percent error will be :
[(0.123 - 0.120) / 0.120] * 100%
(0.003 / 0.120) * 100%
0.025 * 100%
= 2.5%
The percent error is 2.5%. When the true value was 0.120.
Percent error is a measurement used to quantify the discrepancy between an estimated or experimental value and a known or accepted value.
Given information:
The measured value is 0.123
The true value is 0.120
Calculate the percent error using the formula given as below:
Percent Error = (|True Value - Measured Value| / True Value) * 100%
Substituting the given values in the above equation:
Percent Error = (|0.120 - 0.123| / 0.120) × 100%
= (0.003 / 0.120) × 100%
= 0.025 × 100%
= 2.5%
Therefore, the percent error is 2.5%.
To learn more about the percent error, follow the link:
https://brainly.com/question/3105259
#SPJ6
Your question is incomplete, the complete question was:
The true value was 0.120 and the measured value is 0.123. What was your percent error?
To make a sarurated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 k . Find its concentration at this temperature
Answer:
The answer is "[tex]26.47\%[/tex]"
Explanation:
Sodium chloride solute mass[tex]=36 \ g[/tex]
Solvent water mass[tex]=100\ g[/tex]
Calculating the solution mass = Solute mass + solvent mass
[tex]= 36\ g +100\ g\\\\ = 136\ g\\\\[/tex]
Calculating the percentage of concentration:
[tex]= \frac{solute\ mass}{solvent\ mass} \times 100\\\\=\frac{36\ grm}{136\ grm} \times 100\\\\=0.2647 \times 100\\\\=26.47 \%[/tex]