Triangle PQR has been dilated to form triangle P'Q'R'. What is the least amount of information needed to determine if the two triangles are similar

Answer:

Answer:

-1/7

Step-by-step explanation:

-3/2(x-2)=45/14

x-2=(45/14)/(-3/2)

x-2=(45/14)(-2/3)

x-2=-90/42

simplify -90/42 into -15/7

x-2=-15/7

x=-15/7+2

x=-15/7+14/7

x=-1/7

Answer:

Perpendicular, CD has a slope of -5/2

Step-by-step explanation:

Parallel lines have the same slope, perpendicular have slopes that are negative reciprocals, or in other words if one slope is m then the other's slope is -1/m and if it is neither fo those then it is neither parallel or perpendicular.  Also,  if two lines have the same slope you have to make sure they are not the same line.  

Now, to find the slope  when you have two points you use the formula (y2 - y1)/(x2 - x1), where the points are (x1, y1) and (x2, y2).  You can make either point point 1 or point 2.  Just make sure x1 and y1 are from one point and x2 and y2 are from the other point.  

So the two lines are AB and CD.  Since the question asks I will start with CD.  The points are (1,8) and (3,3)  So I will call C point 1 and D point 2.  

(y2 - y1)/(x2 - x1)

(3 - 8)/(3 - 1)

-5/2

Thankfully this is lowest terms.

Now for AB.  A will be point 1 and B will be point 2

(y2 - y1)/(x2 - x1)

(4-2)/(5-0)

2/5

So they are not the same, so what if you take negative 1 over one of the slopes.  

well. -1/(2/5) = -5/2

So these are perpendicular.  

If you would like an explanation for how to find the full equation of a line I can explain that.  

Answer:

last option

Step-by-step explanation:

3.9x3 -4.1x2+7.3

Answer:

b) y=sqrt(x) shifted 3 units left

Step-by-step explanation:

3rd line in the attached table:

f(x+3) = sqrt(x+3) horizontal translation left 3 units

Answer: Angles of Elevation and Depression are used in measuring heights and distances in trigonometric applications using right triangles. These angles are made when we look up or down to view objects. Devices are available to measure angles of elevation and depression. These measured angles can be used in measuring heights and distance which are either tedious or impractical to measure, by modelling the situation into right triangles

Answer:

Angles of Elevation and Depression are used in measuring heights and distances in trigonometric applications using right triangles. These angles are made when we look up or down to view objects. Devices are available to measure angles of elevation and depression. These measured angles can be used in measuring heights and distance which are either tedious or impractical to measure, by modelling the situation into right triangles

Step-by-step explanation:

correct on EDGE2021

If “the notation arcsin x represents the inverse function to sine” is true when the sine function is to the interval [ -pi/2, pi/2 ].

The sine function is one of the three primary functions in trigonometry, the others being cosine, and tan functions.

The confusion is compounded by the fact that we use the notation sin⁻¹(x) interchangeably with arcsin(x), and we call it the inverse sine.

Here is a counterexample disproving your given statement:

Let x = π.

The value π is in the domain of sin(x).

arcsin[sin(π)] = arcsin(0) = 0

arcsin[sin(π)] ≠ π

Therefore arcsin(x) is not the inverse of sin(x).

If you restrict the sine function to the interval [ -pi/2, pi/2 ]. Otherwise, arcsin will not be a function.

Hence, If “the notation arcsin x represents the inverse function to sine” is true when the sine function is to the interval [ -pi/2, pi/2 ].

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Respuesta:

12 horas

Explicación paso a paso:

Dado que :

A Mar del Plata = cada 2 horas

A Necochea = cada 4 horas

A San Clemente = cada 6 horas

Número de horas que tardarán los 3 autobuses en salir al mismo tiempo, si ambos salieron ahora;

Tome el mínimo común múltiplo de los 3 autobuses:

Múltiplos de:

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22

4: 4, 8, 12, 16, 20, 24, 28, 32

6: 6, 12, 18, 24, 30, 36, 42

El mínimo común múltiplo de 2 horas, 4 horas y 6 horas es 12;

Por lo tanto, los 3 autobuses saldrán a la misma hora en las próximas 12 horas:

Answer:

It's d or the 4th graph

Step-by-step explanation:

A graph which represents the overall equation (inequality) represented by this scenario.

A graph can be defined as a type of chart that is commonly used for the graphical representation of data points on both the horizontal and vertical lines of a cartesian coordinate, which are the x-coordinate (x-axis) and y-coordinate (y-axis).

Let the variable x represent the total number of guests.

Let the variable y represent the amount of meat

Next, we would write an inequality that represents an amount of meat that must be 2 pounds fewer than one-third (1/3) the total number of guests. Since the customer decides they want at least that amount of meat, the inequality symbol that must be used is greater than (>).

y > 1/3(x) + 2

y > x/3 + 2

In conclusion, the y-value for this inequality graph (see attachment) intersects the x-axis at 0 and 6 with the boundary line shaded upward and dashed to indicate that it is not part of the solution, which must be represented with a greater than (>) inequality symbol.

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Answer:

x = 16

Step-by-step explanation:

Since the numbers are in ascending order, x is the number with the highest value here.

From the arrangement, we can see that the median (the middle number) is the third number which is 9

The mean is the sum of the numbers divided by their count. So we set up the mean and equate to the median

We have this as;

(1 + 9 + 9 + 10 + x)/5 = 9

29 + x = 5(9)

29 + x = 45

x = 45-29

x = 16

Answer:

3

Step-by-step explanation:

A = [tex]\frac{base1 + base2}{2}[/tex] x h     Formula

[tex]\frac{base1 + 5}{2}[/tex] x 20 = 80      Substitution

[tex]\frac{base1 + 5}{2}[/tex] = 4                 Work  (divide by 20, multiply by 2, subtract 5)

base1 + 5 = 8

base1 = 3                  Solution

Answer:

Solution given:

Let there be a point P(x, y) equidistant from

A(-3, 2) and B(0,4),

so PA = PB,

[tex]\sqrt{(x+3)²+(y-2)²}=\sqrt{(x-0)²+(y-4)²}[/tex]

squaring both side

[tex](\sqrt{(x+3)²+(y-2)²})^{2}=(\sqrt{(x-0)²+(y-4)²})²[/tex]

x²+6x+9+y²-4y+4=x²+y²-8y+16

x²+6x+y²-4y-x²-y²+8y=16-4-9

6x-4y+8y=3

6x-4y=3 is a required locus

Actually:

A locus is a curve or other figure formed by all the points satisfying a particular equation of the relation between coordinates, or by a point, line, or surface moving according to mathematically defined conditions.

Answer:

:

Example Question #1:

Step-by-step explanation:

Which of the following is the equation of a line that is parallel to the line 4x – y = 22 and passes through the origin?

Possible Answers:

4x – y = 0

(1/4)x + y = 0

4x + 8y = 0

4x = 8y

y – 4x = 22

Correct answer:

4x – y = 0

Explanation:

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4x – 22

Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4x – y = 0 we can rearrange to get y = 4x. This fulfills both requirements.

', .

Step-by-step explanation:

hope it helps thank you❤

Answer: The question is not complete. the figure is attached below.

The polygon is a rectangle.

Step-by-step explanation:

Line 1 goes through (-2, 3)

hence the slope of line 1 = -3/2

Line 2 goes through (0, 3) (2, 0)

hence the slope of line 2 = -3/2

Line 3 goes through (0, 1) (-3, 1)

hence the slope of line 3 = 2/3

Line 4 goes through (3, 0) (0, -2)

Hence the slope of line 4 = 2/3

therefore -3/2 * 2/3 = -1

Line1 + Line3      Line1 + Line4       Line2 + Line3        Line2+Line4

because, the distance between Line1 and Line2 is not equal to that Line3 and Line4.

The polygon is a rectangle polygon.

Answer:

3x - y +5=0

Step-by-step explanation:

Slope:-

=> m = 2-8/-1-1 = -6/-2

=> m = 3

Using point slope form :-

=> y - 2 = 3 ( x - (-1))

=> y - 2 = 3x + 3

=> 3x - y +5 = 0

Answer:

y=3x+5

Step-by-step explanation:

first find the gradient

m=y2-y1/x2-x1

from the coordinates you are given x one is -1,x two is1,y one is 2,y two is 8

8-2/1-(-1)

=3

therefore the gradient is 3

after finding the gradient use the equation

y-y1=m(x-x1)

substitute x1,y1 and the gradient..y and x are constant

y-2=3(x-(-1))

y-2=3x+3

y=3x+3+2

y=3x+5

Answer:

The tank is 10cm high

Step-by-step explanation:

Given

[tex]L=60cm[/tex] -- length

[tex]W=60cm[/tex] -- width

[tex]x = \frac{1}{5}[/tex] --- water lever

[tex]Addition = 24L[/tex]

Required

The height of the tank

Let y represents the remaining fraction before water is added.

So:

[tex]y + x = 1[/tex]

Make y the subject

[tex]y = 1 - x[/tex]

[tex]y = 1 - \frac{1}{5}[/tex]

Solve

[tex]y = \frac{5 - 1}{5}[/tex]

[tex]y = \frac{4}{5}[/tex]

Represent the volume of the tank with v

So:

[tex]y * v = 24L[/tex]

Make v the subject

[tex]v = \frac{24L}{y}[/tex]

Substitute: [tex]y = \frac{4}{5}[/tex]

[tex]v = \frac{24L}{4/5}[/tex]

[tex]v = 30L[/tex]

Represent the height of the tank with h;

So, the volume of the tank is:

[tex]v = lwh[/tex]

Make h the subject

[tex]h = \frac{v}{lw}[/tex]

Substitute values for v, l and w

[tex]h = \frac{30L}{60cm * 50cm}[/tex]

Convert 30L to cm^3

[tex]h = \frac{30*1000cm^3}{60cm * 50cm}[/tex]

[tex]h = \frac{30000cm^3}{3000cm^2}[/tex]

[tex]h = 10cm[/tex]

Answer:

143

Step-by-step explanation:

to find the area we multiply half of the sum of the bases with height

(18+8)/2*11 = 143

Answer:

17

Step-by-step explanation:

Answer:y=-5+1

Step-by-step explanation:

Answer:

1) -4(3-5x) >= –6x+9

–12+20x >= -6x+9

The choose (D)

2 ) The choose (A)

3) The choose (A) step 1

4) 1/2(n-4)-3=3-(2n+3)

n=2

The choose ( B)

5) 2.5 (5x-4)=10+4(1.5+0.5x)

x=2

The choose (C)

1. -12 + 20 > -6x + 9

2. simplify by combining like terms

3. step 1

4. n=2

5. 2

Complete question is;

Given a circle with (4. -3) and (2, 1) as the endpoints of the diameter.​ Write the equation of the circle.

Answer:

x² + y² - 6x + 2y + 5 = 0

Step-by-step explanation:

The end points of the diameter are;

(4. -3) and (2, 1).

Thus, the centre coordinates will be the midpoint of the diameter endpoints.

Thus;

Centre coordinates = ((4 + 2)/2), ((-3 + 1)/2) = (3, -1)

Diameter;

d = √(1 - (-3))² + (2 - 4)²)

d = √20

d = 2√5

Radius = ½ × diameter

Thus;

r = ½ × 2√5

r = √5

Equation of a circle is;

(x - a)² + (y - b)² = r²

Where;

(a, b) are coordinates of the centre of the circle

r is radius.

Thus;

(x - 3)² + (y - (-1))² = (√5)²

x² - 6x + 9 + y² + 2y + 1 = 5

x² + y² - 6x + 2y + 10 = 5

x² + y² - 6x + 2y + 10 - 5 = 0

x² + y² - 6x + 2y + 5 = 0

Given:

The graph of system of inequalities.

To find:

The system of inequalities.

Solution:

From the given graph it is clear that the shaded region is lies below the line y=10 and the boundary line y=10 is a solid line. So, the sign of inequality must be [tex]\leq[/tex].

[tex]y\leq 10[/tex].

The shaded region lies on the right side of the y-axis. So, [tex]x\geq 0[/tex].

Another boundary line passes through the point (0,1) and (1,2). So, the equation of the line is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-1=\dfrac{2-1}{1-0}(x-0)[/tex]

[tex]y=1(x)+1[/tex]

[tex]y=x+1[/tex]

The boundary line [tex]y=x+1[/tex] is a dotted line and the shaded region lies above the boundary line, so the sign of inequality must be [tex]>[/tex].

[tex]y> x+1[/tex]

So, the required system of inequalities is:

[tex]y> x+1[/tex]

[tex]y\leq 10[/tex]

[tex]x\geq 0[/tex]

Therefore, the correct option is B.

Answer:

SA=BA+LA and SA=BA+ph

Step-by-step explanation:

I just looked it up

The correct formulas to find the surface area of a right prism are:

SA = BA + LA and SA = BA + ph.

Options (A), and (D) are the correct answer.

A prism is a three-dimensional object.

There are triangular prism and rectangular prism.

We have,

The correct formulas to find the surface area of a right prism are:

1)

SA = BA + LA, where SA is the total surface area, BA is the area of the two identical bases, and LA is the lateral area (the sum of the areas of all the rectangular sides).

2)

SA = BA + ph, where SA is the total surface area, B is the area of one base, p is the perimeter of the base, h is the height of the prism, and ph is the area of all the rectangular sides (the lateral area).

Therefore,

The correct formulas to find the surface area of a right prism are:

SA = BA + LA and SA = BA + ph.

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Answer:

[tex]x=15[/tex]°

Step-by-step explanation:

The sum of degree measures in a full angle (a circle) is (360) degrees. This means that the sum of all of the angles in this diagram is (360) degrees, as the angles form a full arc. Therefore, one can form an equation by adding up all of the angles and setting the equation equal to (360) degrees. Then one can substitute each angle value with the equation that is used to represent it, simplify, and use inverse operations to solve for the value of (x).

[tex](m<AMB)+(m<BMC)+(m<CMD)+(m<AMD)=(360)[/tex]

Substitute,

[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]

Simplify,

[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]

[tex]21x+45=360[/tex]

Inverse operations,

[tex]21x+45=360[/tex]

[tex]21x=315[/tex]

[tex]x=15[/tex]

Answer:

Because it is a right triangle one angle is obviously 90°. The other two are approximately 36.87° and 53.13°.

hope it helps you

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Answer:

4

Step-by-step explanation:

For this, you need to find the scale factor of two sides that are already given to you.

So, we will have to use the hypotenuse and one of the legs to make sure there is an accurate scale factor.

Hypotenuse:

15 / 5 = 3

Leg:

6 / 2 = 3

____________

So the scale factor is 3.

Using the leg (with the x) we need to divide 12 by the scale factor (3) to give us what x is equal to.

12 / 3 = 4

So, the answer is 4.

Answer:

[tex]perimetro = \dfrac{(3 + \sqrt{3})m}{2}[/tex]

Step-by-step explanation:

triángulo 30°-60°-90°

[tex] 1~:~\sqrt{3}~:~2 [/tex]

[tex] 1m~:~m\sqrt{3}~:~2m [/tex]

[tex] \dfrac{m}{2}~:~\dfrac{m\sqrt{3}}{2}~:~m [/tex]

[tex]perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + m[/tex]

[tex]perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + \dfrac{2m}{2}[/tex]

[tex]perimetro = \dfrac{m + m\sqrt{3} + 2m}{2}[/tex]

[tex]perimetro = \dfrac{3m + m\sqrt{3}}{2}[/tex]

[tex]perimetro = \dfrac{(3 + \sqrt{3})m}{2}[/tex]